Markovnikov addition of HCl to propene involves:

A. initial attack by a chlorine ion. B. initial attack by a chlorine atom. C. isomerization of 1-chloropropane. D. formation of a propyl cation. E. formation of an isopropyl cation.

The two ways in which the physical state of matter can be changed are melting and freezing.

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The answer to the question is that the number of H+ (or H3O+) ions is 3.61 × 10²¹ ions/L and the number of OH- ions is 6.02 × 10¹⁰ ions/L.

The given solution is that of 0.100 M HCl in 6.0 mL of the solution.

The balanced chemical equation for the ionization of hydrochloric acid in water can be given as follows:

HCl + H₂O → H₃O⁺ + Cl⁻

From the above equation, it can be concluded that for every HCl molecule, one H₃O⁺ ion is produced and one Cl⁻ ion is produced.

Now, we can calculate the number of H₃O⁺ ions produced using the formula for the number of moles of solute (n) using the formula:

n = M × V ÷ 1000

M represents the molarity of the solution and V represents the volume of the solution in mL.

The value of n can be used to calculate the number of moles of H₃O⁺ ions produced since one mole of HCl ionizes to produce one mole of H₃O⁺ ions. The number of moles of H₃O⁺ ions can then be converted into the number of H₃O⁺ ions using Avogadro's number (6.022 × 10²³).

The calculation for the number of H₃O⁺ ions can be given as follows:

n(H₃O⁺) = (0.100 mol/L) × (6.0 mL/1000 mL) = 0.0006 mol[H₃O⁺] = 0.0006 mol/6.0 mL = 0.1 M

Number of H₃O⁺ ions = 6.022 × 10²³ × 0.0006 = 3.61 × 10²¹ ions/L

Similarly, the number of OH⁻ ions can be calculated by taking into consideration the fact that the product of the concentration of H₃O⁺ ions and the concentration of OH⁻ ions in water is a constant (1 × 10⁻¹⁴ M² at 25 °C). Therefore,[H₃O⁺] × [OH⁻] = 1 × 10⁻¹⁴ M²[OH⁻] = 1 × 10⁻¹⁴ M²/[H₃O⁺] = 1 × 10⁻¹⁴ M²/0.1 M = 1 × 10⁻¹³ M

Number of OH⁻ ions = 6.022 × 10²³ × 1 × 10⁻¹³ = 6.02 × 10¹⁰ ions/L

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Answer:

A

No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal.

Hope this helps!

The amount of KNO₃ would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution is 44 g.

To create a saturated solution of KNO₃ in 100g of water at 50 degrees Celsius, the following steps should be taken:

Step 1: Find out the mass of the solvent in the saturated solution.

The solvent is water in this instance. So, using the formula for the mass of a solution, we can calculate the mass of the solvent in the saturated solution as follows:

Mass of solvent = Mass of solution - Mass of solute

= 100 g - Mass of KNO₃

Step 2: Determine the amount of solute that would be dissolved in the solution to make it saturated.

The mass of KNO₃ that would dissolve in 100 g of water at 50°C to create a saturated solution is 56g/100g of water.

Step 3: Calculate the mass of KNO₃ that would dissolve in 100g of water to make a saturated solution.

Mass of KNO₃ = Solubility of KNO₃ × Mass of solvent

Mass of KNO₃ = 56 g/100 g × (100 g - Mass of KNO₃)

Now, let's solve for Mass of KNO₃;

56 = 56g(100-Mass of KNO₃)/100100 - Mass of KNO₃ = 100

Multiply both sides of the equation by 100 to obtain;

5600 - 100 Mass of KNO₃ = 100

Mass of KNO₃ = 5600/10100 - 56

= 44 g

Therefore, 44 g of KNO₃ would dissolve in 100g of water to make a saturated solution.

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The overall balanced redox reaction for nitrite ion oxidizing iodide in acid to form molecular iodine, nitrogen monoxide, and water can be represented as follows:
NO2^- (aq) + 2I^- (aq) + 4H^+ (aq) → I2 (s) + NO (g) + 2H2O (l)

In this reaction, nitrite ion (NO2^-) acts as an oxidizing agent, while iodide ion (I^-) acts as a reducing agent. The reaction takes place in an acidic medium, which provides the protons (H^+) necessary for the reaction to occur.

The products formed are molecular iodine (I2), nitrogen monoxide (NO), and water (H2O).

The reaction is balanced by ensuring that the number of atoms of each element is the same on both sides of the equation and that the charges are balanced.

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Answer:

gravitational potential energy doesnt change srry the other one as in explaining it

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Answer:

Mass of 1 H atom: 1.008 amu x 1.661 x10-24 g/amu = 1.674 x10-24 g. Mass of 1 mole of H atoms: 1.674 x10-24g/H atom x 6.022 x1023H atoms = 1.008 g.

62 pages

Missing: 66 ‎| Must include: 66

Explanation:

Answer:

From my view the answer is

D. Forests

Answer:

400 joules sisisiss

Explanation:

TNT (Trinitrotoluene) has relatively small energy per pound, but it is a very effective explosive due to the following reasons:

1. It is an insensitive explosive: TNT has a high ignition temperature, making it less prone to accidental detonation. TNT can also resist shock and friction, making it a stable explosive.

2. High detonation velocity: TNT is capable of detonating at a speed of 6,900 m/s. This high velocity allows TNT to produce a supersonic shockwave that can cause significant damage to its surroundings.

3. High gas yield: When TNT explodes, it produces a large amount of gases, which further increases the pressure exerted on its surroundings. This high-pressure shockwave causes significant damage to buildings and structures.

4. Easy to manufacture: TNT is relatively easy and cheap to manufacture, making it a popular explosive for military and industrial applications.

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Answer:

It is not possible to accurately determine whether the system or the surroundings performs work in a chemical reaction without more information about the specific reaction and the conditions under which it occurs.

In general, the work done in a chemical reaction can be affected by several factors, including the pressure, volume, and temperature of the system, as well as the nature of the reactants and products. Some reactions may result in the system doing work on the surroundings, such as when gases expand and do work on their surroundings by pushing against a piston or other external object. Other reactions may result in the surroundings doing work on the system, such as when gases are compressed and their surroundings do work on them. Still other reactions may result in essentially no work being performed, such as when the reactants and products are in equilibrium or when the volume of the system remains constant.

Without more information about the specific reaction in question, it is not possible to accurately determine whether the system or the surroundings performs work.

Answer:

Read below

Explanation:

Do a quick conversion: 1 mole CO2 = 44.0095 gram using the molecular weight calculator and the molar mass of CO2. Check the chart for more details.

Answer:

The answer to this question would be electron.

Electron is located on the outer side of the atom and constantly moving in an orbit so its location cannot be accurately determined. The cloud around the center of the atom is drawn to picture the orbit.

Neutron and proton located in the middle of an atom in a part that called nucleus. Nucleus location is kept at the center and it doesn't move.

Explanation:

Answer:

749 grams CO₂

Explanation:

To find the amount of carbon dioxide produced, you need to (1) convert grams C₃H₈ to moles C₃H₈ (via molar mass from periodic table), then (2) convert moles C₃H₈ to moles CO₂ (via mole-to-mole ratio via reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The desired unit should be in the numerator. The final answer should have 3 significant figures because the given value (250. grams) has 3 sig figs.

Molar Mass (C₃H₈): 3(12.01 g/mol) + 8(1.008 g/mol)

Molar Mass (C₃H₈): 44.094 g/mol

1 C₃H₈ + 5 O₂ ---> 3 CO₂ + 4 H₂O

Molar Mass (CO₂): 12.01 g/mol + 2(16.00 g/mol)

Molar Mass (CO₂): 44.01 g/mol

250. g C₃H₈         1 mole C₃H₈           3 moles CO₂              44.01 g
------------------  x  ----------------------  x  ----------------------  x  --------------------  =
                               44.094 g              1 mole C₃H₈            1 mole CO₂

= 749 grams CO₂

Following are the methods to unplug this drain without physically touching the blockage.

1. Pour hot, boiled water down a drain.

If you choose to attempt to clear a grease blockage on your own and you are certain that your plumbing system is made up of metal pipes rather than plastic, you might try flushing it out with hot water. If your pipes are constructed of plastic, we wouldn't recommend trying this because you run the risk of melting or weakening the joints.

2. Hot water and vinegar

A 50:50 solution of hot, boiling water and vinegar performs similarly to the commercial chemical drain cleaner (and is just as effective). The advantage of a homemade vinegar and water solution is that it is non-toxic and substantially less corrosive than commercial drain cleaners. Grease that has accumulated on the inside walls of your pipes is dissolved by warm water and vinegar. Give yourself another dose a few minutes later if the first dose doesn't work.

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Answer:

the mass is of potassium is 88.38 rounded to the nearest hunndred.

Explanation:

Answer:

Same i have headaches daily, maybe from infections such as meningitis or Intracranial pressure that's either too high or too low or id.k.

Answer:

aluminium bromide

Explanation:

This is a synthesis reaction, where 2 individual molecules react to produce a single new compound.

The balanced chemical equation for the synthesis of aluminium metal and bromine gas is thus:

\(\large \textsf{$\rm 2Al_{\,(s)}+3Br_{\,2\,(g)}\rightarrow 2Al\,Br_{\,3\,(g)}$}\)

The product is therefore:

Answer:

Anodizing is an electrochemical process that converts the metal surface into a decorative, durable, corrosion-resistant, anodic oxide finish. ... Anodizing is accomplished by immersing the aluminum into an acid electrolyte bath and passing an electric current through the medium.

Answer:

Anodising is a process of forming a thick oxide layer of aluminium. Aluminium develops a thin oxide layer when exposed to air.  This Aluminium oxide coat makes it resistant to further corrosion. The resistance can be improved further by making the  oxide layer thicker. During anodising, a clean aluminium article is made the anode and is electrolysed with dilute sulphuric acid. The oxygen gas evolved at the anode reacts with aluminium to make a thicker protective oxide layer. This oxide layer can  be dyed easily to give aluminium articles an attractive finish

Answer:

Frequency is 2Hz

Explanation:

Calculate the equilibrium concentrations of N2O4 and NO2 after the extra 1.00 mol NO2 is added to 1.00 L of solution. For given reaction Kc = [NO2]2 / [N2O4] = (2.21)2 / 0.435 = 11.23 From Le-Ch atelier's Principle, if a reaction at equilibrium is subjected to a change in any of the reaction

Le Ch atelier's principle explains the qualitative behavior of a system in thermodynamic equilibrium when there is an externally induced, instantaneous change in one of the system's parameters; it claims that a behavioral shift happens in the system to oppose (partly cancel) the parameter change. The length of adjustment depends on how strongly the original shock was responded to negatively. The second rule of thermodynamics requires that the disequilibrium brought on by an instantaneous shock have a finite half-life, hence the principle is commonly employed to explain closed negative-feedback systems, but it also applies generally to thermodynamically closed and isolated systems in nature.

Le Ch atelier's , which has its roots in chemical equilibrium but may also be applied to mechanical systems, states that a system

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The question is incomplete, the complete question is;

Each sentence describes potential and kinetic energy at various locations on a slide. Complete each statement by selecting the position of the object on the slide.

An object at position has all kinetic energy. A B or C

An object at position has all potential energy. A B or C

An object at position has about half potential energy and half kinetic energy. A B or C

Answer:

An object at position C has all kinetic energy.

An object at position A has all potential energy.

An object at position B has about half potential energy and half kinetic energy.

Explanation:

Lets take a good look at the image.

At position A, the object is stationary and we know that the energy possessed by an an object by virtue of its position is known as potential energy. Hence at A, the energy possessed by the body is all potential.

At position B, the total mechanical energy of the object becomes potential energy + kinetic energy as the object is now in motion.

At position C, the object is still in motion and the energy is all kinetic.

Answer:

C

A

B

Explanation:

The atom that moves at its rms velocity at 100°C with a wavelength of 2.31 * 10 m is : SULPHUR ( s )

To determine the atom we will have to determine the molar mass of the atom

Applying De Broglie equation

λ = h / mv

Vrms = \(\sqrt{\frac{3RT}{M} }\)  ---- ( 1 )

Where : λ  = 2.31 * 10⁻¹¹,  R = 8.314 J / k.mol,  T = 373 K, h = 6.626 * 10⁻³⁴ J.s

From equation ( 1 )

M = ( h² Ua ) / 3RT*λ² --- ( 2 )

where : Ua ( mass of an atom ) = 6.022 * 10²³,  h = 6.626 * 10⁻³⁴,  R = 8.314 J / k.mol, λ  = 2.31 * 10⁻¹¹,    T = 373 K

Insert values into equation ( 2 )

M ( molar mass ) = 32 g/mol

Sulphur has a molar mass of 32 g/mol therefore the atom is sulphur.

Hence we can conclude that The atom that moves at its rms velocity at 100°C with a wavelength of 2.31 * 10 m is : SULPHUR ( s ).

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The fraction of association for the 3.00×10⁻¹ M K(C2H5COO2) solution is 4.5%. and the fraction of association for the 3.00×10⁻¹² M K(C2H5COO2) solution is very close to 100%.

The fraction of association (α) represents the degree to which a weak acid dissociates in a solution. For a weak acid HA, it can be calculated

using the following formula:

α  = (Ka/[HA])^(1/2)

where Ka is the acid dissociation constant for HA, and [HA] is the initial concentration of the acid.

In this case, the weak acid is propanoic acid (C2H5COOH), which dissociates to form the propanoate anion (C2H5COO-) and a hydrogen ion (H+). The propanoate anion can then associate with a potassium ion (K+) to form potassium propionate (K(C2H5COO)2).

For the given solutions of potassium propionate, the initial concentration of propanoic acid can be calculated by multiplying the concentration of potassium propionate by the fraction of the acid that remains undissociated:

[HA] = [K(C2H5COO)2] x (1 - α)

Using the formula above, we can calculate the fraction of association (α) for each solution as follows:

For 3.00×10−1 M K(C2H5COO2):

[HA] = (3.00×10^-1) x (1 - α)

Ka = 1.34×10⁻⁵

α = (Ka/[HA])^(1/2) = (1.34×10⁻⁵ / (3.00×10^-1 x (1 - α)))^(1/2)

Solving this equation gives α = 0.045 or 4.5%.

Therefore, the fraction of association for the 3.00×10^-1 M K(C2H5COO2) solution is 4.5%.

For 3.00×10⁻² M K(C2H5COO2):

[HA] = (3.00×10⁻²) x (1 - α)

Ka = 1.34×10⁻⁵

α = (Ka/[HA])^(1/2) = (1.34×10⁻⁵ / (3.00×10⁻² x (1 - α)))^(1/2)

Solving this equation gives α = 0.31 or 31%.

Therefore, the fraction of association for the 3.00×10⁻² M K(C2H5COO2) solution is 31%.

For 3.00×10⁻¹²M K(C2H5COO2):

[HA] = (3.00×10⁻¹²) x (1 - α)

Ka = 1.34×10⁻⁵

α = (Ka/[HA])^(1/2) = (1.34×10⁻⁵ / (3.00×10⁻¹² x (1 - α)))^(1/2)

Solving this equation gives α = 0.9999999999 or very close to 100%.

Therefore, the fraction of association for the 3.00×10^-12 M K(C2H5COO2) solution is very close to 100%.

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The gravitational potential energy (GPE) of a 1 kg fish positioned 0.5 meters above the ground is 4.9 joules (J).

What is Gravity?

Gravity is a fundamental force of nature that causes objects with mass or energy to be attracted to one another. It is the force that gives weight to physical objects and determines how objects interact with each other due to their mass. Gravity is responsible for the motion of celestial bodies, such as planets, stars, and galaxies, and it plays a crucial role in the structure and evolution of the universe.

GPE = mgh

where:

Given the information provided:

Mass of the fish (m) = 1 kg

Height above ground (h) = 0.5 meters

Acceleration due to gravity (g) = 9.8 m/\(s^{2}\)

Plugging these values into the formula, we get:

GPE = (1 kg) x (9.8 m/\(s^{2}\)) x (0.5 m)

GPE = 4.9 J

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The compound \(C_2H_3O_2K\) is salt because of its reaction with acids bases. Therefore option D is correct.

The potassium acetate is also called potassium ethanoate, which is a hygroscopic solid in state at room temperature. The chemical formula of this potassium acetate is  \(C_2H_3O_2K\). It is formed when a reaction between acid (acetic acid) and a base (potassium hydroxide) reacts.

Salts are compounds that are formed by the neutralization of an acid and a base. In this reaction, the Hydrogen ions from acids will be attached by the cations. In this potassium acetate, potassium (K+) ions will be attracted by the hydrogen ion (H+).

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The complete question is:

which compound is a salt?

a. ch3oh

b. c6h12o6

c. h2c2o4

d. c2h3o2k

Answer:c

Explanation: can someone help me to see if this is true

In the second experiment, it would take 60 minutes to produce the same amount of product (25 mmol).

We can start by using the Michaelis-Menten equation to determine the initial reaction rate in the first experiment, where the substrate concentration is initially a thousand times greater than the KM:

v₀ = Vmax × [S]/(KM + [S])

Since the substrate concentration is initially a thousand times greater than the KM, we can assume that [S] >> KM, and simplify the equation to:

v₀ = Vmax × [S] / KM

The amount of substrate converted to product after 15 minutes is 1% of the initial substrate concentration, so the remaining substrate concentration is 99% of the initial concentration. Let's define [S]0 as the initial substrate concentration, then:

[S] = 0.99 [S]₀

The amount of product formed in 15 minutes is 25 mmol, so we can calculate the initial reaction rate as:

v₀ = (25 mmol / 15 min) / (0.01 mol / mol) = 1666.7 nmol/min

where we have converted the units to nmol/min and used the molecular weight of the product to convert from moles to millimoles.

Now, let's consider the second experiment, where one-fourth as much enzyme and twice as much substrate are used.

Since the amount of product formed is the same in both experiments, we can write:

v₁ × t₁ = v₂ × t₂

where v₁ and t₁ are the initial reaction rate and reaction time in the first experiment, and v₂ and t₂ are the corresponding values in the second experiment.

Let's use the Michaelis-Menten equation to relate the initial reaction rate to the enzyme and substrate concentrations:

v₁ = Vmax × [S]₁ / (KM + [S]₁) × E₁

v₂ = Vmax × [S]₂ / (KM + [S]₂) × E₂

We can rearrange these equations to solve for [S]1 and [S]2 in terms of v1, v₂, E₁, E₂, and KM:

[S]₁ = (v₁ × KM) / (Vmax × E₁) - [S]₂

[S]₂ = (v₂ × KM) / (Vmax × E₂) - [S]₁

Substituting these expressions into the equation for the reaction time, we get:

t₂ = (v₁ × t₁ × Vmax × E₂) / (v₂ × Vmax × E₁ + v₁ × E₂ × KM / (Vmax × E₁) - v₁ × KM / (Vmax × E₁))

Substituting the values from the first experiment, we get:

t₂ = (1666.7 nmol/min × 15 min × 1/4 × 2) / (1666.7 nmol/min × 1/2 × 1/1000 mol/L + 1666.7 nmol/min × 2 × 0.01 mol/L / (1/1000 mol/L) - 1666.7 nmol/min × 0.01 mol/L / (1/1000 mol/L))

Simplifying, we get:

t₂ = 60 min

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Answer:

1. One is more compact than the next hence more density

2. A: 0.67g/cm3 hence will sink

B:0.56g/cm3 hence will sink

C:0.91g/cm3 hence will sink

Explanation:

Use the formula mass/volume to find its density with S.I unit is g/cm3

And to determine weather or not it sink use the relative density formula

Density of substance / Density of water