Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

The force of buoyancy acting on the sample is 2.65 N.

If the sample's supporting string is cut, it will float to the surface of the water.

a. The buoyant force acting on the sample can be calculated using the formula Fb = ρVg, where ρ is the density of water, V is the volume of the submerged part of the sample, and g is the acceleration due to gravity. Since the sample is immersed in water, its volume is equal to the volume of water it displaces, which can be calculated using the formula V = l × w × h, where l, w, and h are the dimensions of the submerged part of the sample. Since the sample is cubical, all sides have the same length of 3.0 cm. Thus, the submerged part of the sample has a volume of V = 3.0 cm × 3.0 cm × 3.0 cm = 27.0 cm³ = 0.027 m³. The density of water is ρ = 1000 kg/m³, and the acceleration due to gravity is g = 9.81 m/s². Therefore, the buoyant force acting on the sample is:

Fb = ρVg = 1000 kg/m³ × 0.027 m³ × 9.81 m/s² ≈ 2.65 N

b. The sample will float to the surface of the water if its supporting string is cut. This is because the buoyant force acting on the sample is greater than its weight, which means that there is a net upward force on the sample. This net force causes the sample to accelerate upward, and it will continue to accelerate until it reaches the surface of the water. At the surface, the upward force is balanced by the weight of the sample, and it will float on the water.

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Complete question:

2. Suppose the metal sample in Figure 10.2 is immersed in water, is cubical with side 3.0 cm, and has a mass of 54 g. a. Calculate the buoyant force acting on the sample. b. Describe the behavior of the sample if its supporting string is cut. Explain how you arrive at your answer. balance arm water metal sample water overflow can beaker Figure 10.2 MEASUREMENTS

ANSWER

5.77

EXPLANATION

Given:

• The diameter of the input cylinder, d₁ = 3.2 in

• The input force, F₁ = 485 lb

• The diameter of the output cylinder, d₂ = 9.2 in

• The output force, F₂ = 2800 lb

Find:

• The actual mechanical advantage, AMA

The mechanical advantage is given by,

Replace the known values and solve,

Hence, the actual mechanical advantage of this jack is 5.77, rounded to the nearest hundredth.

In precipitation, Rainwater can fall as either Liquid or Solid.

Precipitation is a part of the water cycle. Precipitation falls to the floor as snow and rain. It subsequently evaporates and rises back into the surroundings as a gas. In clouds, it turns back into a liquid or stable water, and it falls to Earth again

The water cycle shows the non-stop motion of water within the Earth and its surroundings. it's miles a complex system that consists of many one-of-a-kind techniques. Liquid water evaporates into water vapor and condenses.

There are four fundamental ranges in the water cycle. they are evaporation, condensation, precipitation, and collection. permit's examined every one of these ranges. Evaporation: that is whilst warm temperature from the sun causes water from oceans, lakes, streams, ice, and soils to upward push into the air and grow to be water vapor.

Disclaimer: your question is incomplete, please see below for the complete question.

Liquid

Steam cloud

2nd half

Steam

Solid

Cloud

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Answer:

For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

hope it helps :)

Answer: For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

Answer:

1/4πε₀[Hx/ (√x² + b²)^3/2]i.

Explanation:

So, without mincing words let's dive straight into the solution to the question above. There is need to determine the electric field on-axis of a uniformly-charged disk sitting.

The electric field in the x-component, dεₓ = 1/4πε₀[H/ x² + b²] cos .

Thus, the total electric field in the x-component, εₓ = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2.

Therefore, the electric field = 1/4πε₀ [ xdH/ (x^2 + b^2)^3/2i.

Where x=0

Answer:

m = 0.5

Explanation:

Given that,

The length of the blade of scissors = 5 cm

The length of the handle = 2.5 cm

Here, effort arm is 2.5 cm and load arm is 5 cm. The mechanical advantage is the ratio of effort arm to the load arm as follows :

\(m=\dfrac{2.5}{5}\\\\m=0.5\)

So, the ideal mechanical advantage of a pair of scissors is 0.5.

Answer:

c) It decreases.

Explanation:

If you treat this as a case of momentum of the sled while sledding on a friction-less ice, then mass and velocity are directly proportional. This means increasing either mass or velocity , the momentum of the object increases proportionally.

In this question, when the child falls sideways off the sled, the mass reduces, the velocity experiences the same causing a decrease in momentum .

Answer:

A.) Work function = 2.3 eV

B.) Max. K.E observed = 1.1 eV

Explanation:

A.) Millikan observed a maximum kinetic energy of 0.550 eV when electrons were ejected with 433.9-nm light. When light of 253.5 m was used, he observed a maximum kinetic energy of 2.57 eV. 

work function (f) is the minimum energy required to remove an electron from the surface of the material.

hf = Ø + K.E (maximum)

Where

h = Plank constant 6.63 x 10-34 J s

Ø = work function

hc/λ = Ø + K.E (max)

(6.63×10^-34 × 3×10^8)/433.9×10^-9 = Ø + 0.550 × 1.6×10^-19

4.58×10^-19 = Ø + 8.8×10^-20

Ø = 4.58×10^-19 - 8.8×10^-20

Ø = 3.7 × 10^-19 J

Converting Joule to eV

Ø = 3.7 × 10^-19/1.6×10^-19

Ø = 2.3 eV

B.) When light of wavelength 362.4 m is used

The maximum K.E observed = incident light K.E - (the work function).

Incident K.E = hf = hc/λ

Incident K.E =

(6.63×10^-34 × 3×10^8)/362.4

Incident K.E = 5.5 × 10^-28J

Let's convert joule to eV

Incident K.E = 5.5×10^-28/1.6×10^-19

Incident K.E = 3.4 × 10^-9

Max. K.E observed = 3.4 - 2.3

Max. K.E observed = 1.1 eV

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Answer:

A car traveling south with its cruise control set

Explanation:

Turning could cause anything to slow down but going forward could mean that anything could go faster.

The 'feeling' function in one's personality can be effectively developed through empathy, primarily by imagining how others might feel in various situations. This enhances one's ability to connect with others emotionally.

One effective way to develop the 'feeling' function in your personality can be achieved through increased levels of empathy. The best choice among the provided options would be 'C. Imagine how other people might feel in a situation'. This behavior enables you to consider and understand circumstances from the perspectives of other people, thereby enhancing your capabilities to connect with them on an emotional level. It's important to note that this doesn't involve ignoring the consequences of your actions or spending more time alone. In contrast, it's about actively engaging in understanding and empathizing with others and their experiences.

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Answer: 0.28 A

Explanation:

Answer:

.28

Explanation:

Acellus

The period of the pendulum allows to find the result for how much it advances when the length is reduced is:

           Δt = 1550 s

Simple harmonic motion is an oscillatory motion where the restoring force is proportional to the displacement.

In the case of the simple pendulum, this is fulfilled for small angles minus 15º, the angular velocity of the pendulum is

           w = \(\frac{g}{L}\)  

Angular velocity and period are related

           w = \(\frac{2pi}{T}\)

We substitute

            T = \(2\pi \ \frac{L}{g}\)  

They indicate that for the initial length L₀ and the pendulum marks the exact time, how much time changes if the length is  3.97 feet, therefore the initial length is L₀ = 3.90 feet.

            \(T_o^2 = 4 \pi ^2 \ \frac{L_o}{g}\)  

The period for the reduced length is:

           \(T'^2 = 4\pi ^2 \ \frac{L}{g}\)  

The relationship between the periods is:

            \(( \frac{T}{T'}^2 = \frac{L_o}{L} \\T' = \sqrt{\frac{L_o}{L} } \ T\)

Let's calculate

             T ’=  \(T \ \sqrt{\frac{3.97}{3.9} }\)  

             T ’= T 1.01795

In the total time of a day.

             T = 24 hours (3600 s / 2h) = 86 400 s

We calculate

             T ’= 86400 1.01795

              T ’= 87,950 s

Therefore the pendulum moves forward in a time of:

           ΔT = T'- T

           ΔT = 87950 - 86400

           ΔT = 1550 s

In conclusion, using the period of the pendulum we can find the result for how much it advances when the length is change is:

           ΔT = 1550 s

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Answer:

w= p∆v 50000 ( 0.55-0.40) and calculate and you get it

The work done on the system by its environment is 7,500J.

To find the work done, we need to know about the work done on an ideal gas during isobaric process.

When the pressure is remained constant throughout a process, then the process is called isobaric process.

Here, Final volume= 0.55 m³

         Initial volume= 0.40 m³

         Pressure= 50,000 Pa

Work done = 50,000 × (0.55 - 0.40)

                  = 7,500 J

Thus, we can conclude that 7,500 J of  work is done on the system by its environment.

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If the coefficient of kinetic friction between Josh's sled and the snow is 0.08, he slides 6.97 meter from the base of the hill.

To find how far from the base of the hill Josh's sled ends up, we need to first find the speed of the sled at the bottom of the hill using the conservation of energy principle,

mgh = (1/2)mv², plugging in the values given in the problem, we get,

m(9.81 m/s²)(3.5 m) = (1/2)mv²

Simplifying and solving for v, we get,

v = √(2gh)

v = √(2(9.81 m/s²)(3.5 m))

v = 8.29 m/s

Now we can use the kinematic equation,

d = vt - (1/2)at, to find how far the sled slides on the horizontal patch of snow before coming to a stop, where d is the distance traveled, v is the initial velocity (8.29 m/s), a is the acceleration due to friction (-μg), and t is the time it takes to come to a stop (which we can find by setting v = 0 and solving for t),

0 = 8.29 m/s - μg*t

t = 8.29 m/s / μg

Substituting this value of t back into the kinematic equation, we get,

d = (8.29)(8.29/μg) - (1/2)μg(8.29/μg)²

d = 6.97 m

Therefore, Josh's sled ends up 6.97 meters from the base of the hill.

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The gravitational field strength on the surface of Mars is 3.71 m/\(s^{2}\).

What is Mass?

Mass is a fundamental property of matter that measures the amount of substance or material in an object. It is a scalar quantity and is measured in kilograms (kg) or grams (g). Mass is a property that remains constant regardless of the location of an object in the universe, and it is different from weight, which is the force that results from the gravitational attraction between two objects.

The gravitational field strength on the surface of a planet can be calculated using the formula:

g = G * M / \(r^{2}\)

where g is the gravitational field strength, G is the gravitational constant, M is the mass of the planet, and r is the radius of the planet.

Plugging in the values for Mars, we get:

g = (6.6743 × \(10^{-11}\) \(m^{3}\)\(kg^{-1}\)\(s^{-2}\)) * (6.4 × 10^23 kg) / (3.4 × \(10^{6}\) m)

g = 3.71 m/\(s^{2}\)

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\(\qquad \)We know that on the Earth’s surface, gravitational field strength has a constant value of \(\sf \underline{9.81\: N kg^{-1}}\) and outside the Earth’s surface, gravitational field strength is not constant. Gravitational field strength decreases as r increases by a factor of \(\sf 1/r^2\) which is an inverse square law relationship with distance and can be deduced as -

\(\: \:\:\:\:\:\:\star\longrightarrow \boxed{\bold{g = G \:\dfrac{M}{r^2}}}\\\)

Where:-

As per question, we are given -

Now that we have all the required values, so we can put them into the formula and solve for the gravitational field strength of Mass:-

\(\: \:\:\:\:\:\:\star\longrightarrow \bold{g = G \:\dfrac{M}{r^2}}\\\)

\( \:\:\:\:\:\:\longrightarrow \sf g = 6.67\times 10^{-11}\times \dfrac{6.4\times 10^{23}}{\bigg(3.4\times 10^{6}\bigg)^2}\\\)

\( \:\:\:\:\:\:\longrightarrow \sf g = 6.67\times 10^{-11}\times \dfrac{6.4\times 10^{23}}{\bigg(3.4 \bigg)^2 \times 10^{12}}\\\)

\( \:\:\:\:\:\:\longrightarrow \sf g = 6.67 \times \dfrac{6.4}{11.56}\times 10^{-11+23-12}\\\)

\( \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf g = \dfrac{42.68}{11.56}\times 10^{0}\\\)

\( \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf g = 3.69273.....\times 1\\\)

\( \:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf \underline{g = \underline{3.693 \:Nkg^{-1}}}\\\)

it's true because we'll engery and causes of matter work together I think

ANSWER

EXPLANATION

To find the acceleration of the meteoroid, we have to apply the formula for acceleration:

where v1 and v2 are the initial and final velocities, and t is the time taken

Therefore, we have that:

That is the acceleration.

The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.

To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:

Q1 = m1 * c * ΔT1

Where:

m1 = mass of water = 100 g

c = specific heat capacity of water = 4.2 J/g °C

ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C

Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J

Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:

Q2 = m2 * Lf

Where:

m2 = mass of ice = 18 g

Lf = specific latent heat of fusion of ice (to be determined)

Q2 = 18 g * Lf

Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):

-10,500 J = 18 g * Lf

Solving for Lf:

Lf = -10,500 J / 18 g = -583.33 J/g

The negative sign indicates that energy is being released during the process of freezing.

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Answer:

true

Explanation:

because it has magnitude

According to seismic waves, the Earth's interior is made up of a number of concentric shells, including a solid inner core, a liquid outer core, a mantle, and a thin outer crust.

The wave's course will be bent or refracted as it enters the new layer if it moves at a different speed there. The wave will be somewhat curved in the direction of the contact between the two layers if it can move through it more quickly in the new layer.

Therefore, We can learn about just the layers that make up the Earth by understanding how waves behave as they pass through various materials.

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When a person increases their activity level to gain muscle mass, their nutritional needs change.

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Answer:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Explanation:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

Answer:

1168.05 J

Explanation:

The work that the boy does can be calculated as

W = Fdcosθ

Where F is the force, d is the distance and θ is the angle. Replacing F = 41.5 N, d = 32.5 m, and θ = 30 degrees, we get:

W = (41.5 N)(32.5 m)cos(30)

W = 1168.05 J

Therefore, the answer is 1168.05 J

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.

What is a satellite?

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