Rebounds did Mark have is x = 21
The Option C is correct.
Mark and Gary had a basketball game Saturday.
and, Mark had three times as many rebounds as Gary.
Together they had 28 rebounds.
To find the how many rebounds did Mark have?
Now, According to the question:
Based on the given conditions:
Let x be the rebounds mark
Mark had three times rebounds as Gary
then, formulate ;
x × (1 + 3)÷ 3 = 28
Solve the equation:
[x × (1 + 3)] / 3 = 28
(x × 4) / 3 = 28
x = 28 × \(\frac{3}{4}\)
x = 21
Hence, Rebounds did Mark have is x = 21
The Option C is correct.
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Solve the equation using a graphical method.
t/3-1/2=t+3/9
Answer:
-1.25
Step-by-step explanation:
t÷3-1÷2 = t÷1+3÷9
2t-3÷6 = 9t+3=9
18t - 27 = 54 + 18
18t -54t = 18 + 27
-36t = 45
Divide through by -36
t = -1.25
Each of the following functions f,g,h, and h represents the amount of money in a bank account in dollars as a function of time x, in years they are each written in form m(x)= a•b
Answer:
f(x) : exponential growth
g(x); exponential growth
h(x): exponential growth
j(x): exponential decay
Step-by-step explanation:
In an exponential function such as
\(m(x) = a \cdot b^x\)
the factor that determines whether it is a growth or decay function depends entirely on the value of b since x cannot be negative
If b > 1, it is a growth function
If b < 1 then it is a decay function
If b = 1 neither growth or decay function values are constant
In this context
f(x) has b = 2 > 1 . Hence it is a growth function
g(x) has b = 3 > 1 hence growth function
h(x) has be = 3/2 > 1; hence growth function
j(x) has be = 0.5 < 1 hence decay function
Answer:
O f(x) : exponential growth
O g(x); exponential growth
O h(x): exponential growth
O j(x): exponential decay
Step-by-step explanation: I used to do this before :)
-1000 2/3 is not real fraction. True or false
True, While "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.
The statement "-1000 2/3 is not a real fraction" is true. A real fraction is a mathematical expression that represents a ratio of two real numbers. In a fraction, the numerator and denominator are both real numbers, and they can be positive, negative, or zero.
In the given statement, "-1000 2/3" is not a valid representation of a fraction. The presence of a space between "-1000" and "2/3" suggests that they are separate entities rather than being part of a single fraction.
To represent a mixed number (a whole number combined with a fraction), a space or a plus sign is typically used between the whole number and the fraction. For example, a valid representation of a mixed number would be "-1000 2/3" or "-1000 + 2/3". However, without the proper formatting, "-1000 2/3" is not considered a real fraction.
It's important to note that "-1000 2/3" can still be expressed as an improper fraction. To convert it into an improper fraction, we multiply the whole number (-1000) by the denominator of the fraction (3) and add the numerator (2). The result would be (-1000 * 3 + 2) / 3 = (-3000 + 2) / 3 = -2998/3.
In conclusion, while "-1000 2/3" is not a real fraction, it can be represented as the improper fraction -2998/3.
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the 3rd and 6th term in fibonacci sequence are 7 and 31 respectively find the 1st and 2nd terms of the sequence
Answer:
Step-by-step explanation:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,144,233,377,610,987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, ... Can you figure out the next few numbers?
Trina has a credit card that uses the adjusted balance method. For the first 10
days of one of her 30-day billing cycles, her balance was $780. She then
made a purchase for $170, so her balance jumped to $950, and it remained
that amount for the next 10 days. Trina then made a payment of $210, so her
balance for the last 10 days of the billing cycle was $740. If her credit card's
APR is 17%, which of these expressions could be used to calculate the
amount Trina was charged in interest for the billing cycle?
OA. (30)($780)
365
B.
O C.
D.
0.17
365
0.17
365
0.17
365
30
30
(10 $780+10 $950 +10 $210)
30
10
$780+10$950+10 $740
30
•30) ($570)
The expression that could be used to calculate the amount Trina was charged in interest for the billing cycle is (APR / 365) x 30 days x adjusted balance.
What is the adjusted balance method?The adjusted balance method is one of the methods for computing the finance charge (interest and other fees) for credit cards.
The adjusted balance is the ending balance determined after adjusting the opening balance with purchases and payments.
Credit card interest method = adjusted balance method
Beginning balance = $780
Purchase = $170
Payment = $210
Adjusted balance, AB = $740 ($780 + $170 - $210)
APR = 17% = 0.17 (17/100)
The interest charged = (APR / 365) x 30 days x adjusted balance
= $10.34 [(0.17/365) x 30 x $740]
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LOOK AT ATTACHED IMAGIE! Make a two-column proof showing statements and reasons to prove that triangle ABD is similar to triangle ACB.
If map=1, Prove that
1+
It man
Itntpt 1tpam
+
Answer:
hi I didn't understand the question
can you please help me to understand.
I will try to give my best
the price has changed from $120 to $75. by how many percent did it chnage
A parabola can be represented by the equation y2=12x which equation represents directrix?
Answer:
x=-3
Step-by-step explanation:
The equation of the directrix is x = -3
Given the general equation of a parabola expressed as
(y-y0)² = 4a(x-x0) ... 1
Equation of the directrix will be expressed as x = x0 - a
From the equation given;
y² = 12x ... 2
Comparing 1 and 2;
x - x0 = x
-x0 = x - x
-x0 = 0
x0 = 0
Similarly;
y-y0 = y
-y0 = y - y
-y0 = 0
y0 = 0
Also;
4a = 12
a = 12/4
a = 3
Substituting x0 =0, y0 = 0 and a = 3 into the equation of the dirrectrix above, we will have;
x = x0 - a
x = 0 - 3
x = -3
Hence the equation of the directrix is x = -3
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Choose the graph of the following function: f(x) = -2 cos(0.5x)
Answer:
The answer is Graph B. you could also plug it in demos and it will give you the answer.
#5 I need help ASAPPP !!
Cheese and baloney sandwich
The table below represents a frequency distribution for the age (in years) of employees at a particular company.
Age (in years) Frequency
23-29
25
30-36
41
37-43
37
Use the table to answer the following questions.
Your answers should be exact numerical values
The class width used for the frequency distribution is
The class midpoint for the class 23-29 is
The class midpoint for the class 30-36 is
The class midpoint for the class 37-43 is
Check
The class width used for the frequency distribution is 6.
The class midpoint for the class 23-29 is 26.
The class midpoint for the class 30-36 is 33.
The class midpoint for the class 37-43 is 40.
To find the class width of the frequency distribution, we need to determine the range of each age class. The range is the difference between the upper and lower boundaries of each class. Looking at the table, we can see that the class boundaries are as follows:
23-29
30-36
37-43
For the class 23-29, the lower boundary is 23 and the upper boundary is 29. To find the class width, we subtract the lower boundary from the upper boundary:
Class width = 29 - 23 = 6
So, the class width for the frequency distribution is 6.
To find the class midpoint for each class, we take the average of the lower and upper boundaries of each class.
For the class 23-29:
Class midpoint = (23 + 29) / 2 = 52 / 2 = 26
For the class 30-36:
Class midpoint = (30 + 36) / 2 = 66 / 2 = 33
For the class 37-43:
Class midpoint = (37 + 43) / 2 = 80 / 2 = 40
So, the class midpoint for the class 23-29 is 26, for the class 30-36 is 33, and for the class 37-43 is 40.
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At a supermarket, there are 118 customers. If 45 have purchased shirts, 59 have
purchased pants, and 40 have purchased neither, how many purchased both shirts and
pants?
Using the Venn Diagram principles, the number of customers at the supermarket who purchased both shirts and pants is 26.
What is a Venn Diagram?A Venn Diagram shows a pictorial or graphical representation of the relationship (similarities and differences) between data sets.
In a Venn Diagram, overlapping circles or other shapes can be used to depict the logical relationships between two or more data sets or items.
The total number of customers at a supermarket = 118
The number of customers who purchased shirts, n(A) = 45
The number of customers who purchased pants, n(B) = 59
The number of customers who purchased neither shirts nor pants = 40
Let the number of customers who purchased both shirts and pants = n(A ∩ B)
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
n(A) = 45 n(B) = 59 n(A ∪ B) = 118 - 40 = 78
Substituting values:
78 = 45 + 59 - n(A ∩ B)
Solving for n(A ∩ B), we get:
n(A ∩ B) = 45 + 59 - 78 n(A ∩ B) = 26
Thus, using the formula of Venn Diagram, we can conclude that at this supermarket with 118 customers, 26 customers purchased both shirts and pants.
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what is the solution to the equation m/m plus 4 plus 4/4-m = m^2/m^2-16?
Answer:
m= -1
Step-by-step explanation:
Given:
m/m plus 4 plus 4/4-m = m^2/m^2-16
interpreted as
m / ((m+4)(4-m)) = m^2/(m^2-16)
Solution
m / ((m+4)(4-m)) = m^2/(m^2-16)
rearrage and expand
-m / ((m+4)(m-4)) = m^2 / ((m+4)(m-4))
if m does not equal 0, we can cancel terms in numerator
-1 / ((m+4)(m-4)) = m / ((m+4)(m-4))
if m does not equal +4 nor -4, we can cancel terms in denomnator
-1 = m
Hence m=-1 if m does not equal 0, -4 or +4, which is valid.
What is the probability that either event will occur?
A
30
8
B
7
P(A or B) = P(A) + P(B)
P(A or B) = [?]
Enter as a decimal rounded to the nearest hundredth.
The probability that either event will occur is 0.33
What is the probability that either event will occur?From the question, we have the following parameters that can be used in our computation:
Event A = 8Event B = 7Other Events = 30Using the above as a guide, we have the following:
Total = A + B + C
So, we have
Total = 8 + 7 + 30
Evaluate
Total = 45
So, we have
P(A) = 8/45
P(B) = 7/45
For either events, we have
P(A or B) = 8/45 + 7/45
P(A or B) = 15/45
Evaluate
P(A or B) = 0.33
Hence, the probability that either event will occur is 0.33
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Paula has 5 dimes, 2 pennies, and 3 nickels in her pocket. Without looking, she selects 2 coins in a row. What is the probability that the first coin is a dime and the second coin is a penny?
Answer:
Step-by-step explanation:
She has 5 dimes, 2 pennies, and 3 nickels in her pocket.
So 5+2+3 = 10 coins total.
For the first coin is a dime, the probability = number of dimes/total number of coins
= 5/10
= 1/2
After that, 9 coins are left with 4 dimes, 2 pennies and 3 nickels.
For the second coin is a penny, the probability = number of penny / total number of coins
= 2/9
Combining the above, probability that the first coin is a dime and the second coin is a penny
= 1/2 * 2/9
= 1/9
It rained all day on Father's Day and the temperature dropped ten and seven tenth degrees. The next day the rain
stopped and the temperature rose twelve and six tenths degrees. If the temperature at the beginning of Father's Day
was sixty five and eight tenths degrees, what was the temperature at the end of the day after Father's Day?
Write numerical answer only (no sentences, no units)
BEER
Activate
Go to Settings
p. 10 of 19
Answer:
67.7
Step-by-step explanation:
Temperature at beginning of Father's Day = 65.8 degrees
Drop in temperature because of rain = 10.7 degrees
Rise in temperature after the rain the next day = 12.6 degrees
Therefore, temperature at the end of the day after the Father's Day
= Temperature at beginning of Father's Day minus Drop in temperature because of rain plus Rise in temperature after the rain the next day
= 65.8 - 10.7 + 12.6
= 67.7 degrees
NB: The answer was written as only 67.7 as requested by the questioner.
Can someone please help me with this??
The solution to the given simultaneous equations using Cramer's rule is x = -1, y = -4.92, z = -1.03.
How to Solve Simultaneous Equation Using Crammer's RuleTo solve the given simultaneous equations using Cramer's rule, we need to find the determinants of various matrices.
Given the set of equation:
3x-3y+ 5z = 5
9x - 8y + 13z = 14
-3x+4y- 7z=-7
We start by finding the determinant of the coefficient matrix, which is denoted as D.
D = \(\left[\begin{array}{ccc}3&-3&5\\9&-8&13\\-3&4&-7\end{array}\right]\)
To calculate D, we use the formula:
D = (3 * (-8) * (-7) + (-3) * 13 * (-3) + 5 * 9 * 4) - ((-3) * (-8) * 5 + 3 * 13 * 4 + (-3) * 9 * (-7))
D = (-168 + 117 + 180) - (120 - 156 + 189)
D = 129 - 165
D = -36
Next, we need to find the determinants of the matrices obtained by replacing the columns of the coefficient matrix with the constant terms. These determinants are denoted as Dx, Dy, and Dz, respectively.
Dx = \(\left[\begin{array}{ccc}5&-3&5\\14&-8&13\\-7&4&-7\end{array}\right]\)
Dx = (-40 - 65 + 20) - (-70 - 60 + 189) = -85 - (-121) = -85 + 121
Dx= 36
Dy = \(\left[\begin{array}{ccc}3&5&5\\9&14&13\\-3&-7&-7\end{array}\right]\)
Dy = (21 + 75 + 35) - (-21 - 130 + 105) = 131 - (-46) = 131 + 46
Dy = 177
Dz = \(\left[\begin{array}{ccc}3&-3&5\\9&-8&14\\-3&4&-7\end{array}\right]\)
Dz = (39 - 39 + 0) - (-27 + 84 + 20) = 0 - (-37) = 0 + 37
Dz = 37
Finally, we can find the values of x, y, and z using the formulas:
x = Dx / D
y = Dy / D
z = Dz / D
Plugging in the values, we have:
x = 36 / -36 = -1
y = 177 / -36 ≈ -4.92
z = 37 / -36 ≈ -1.03
Therefore, the solution to the given simultaneous equations using Cramer's rule is x = -1, y ≈ -4.92, z ≈ -1.03.
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Y=2X squared -12 X +20 for quadratic formula
x = (12 ± √(-16)) / 4,The solutions would be complex numbers.
What is the quadratic formula?To solve quadratic equations of the form ax2 + bx + c = 0, use the quadratic formula. For this situation, your condition is as of now as a quadratic condition, with a = 2, b = - 12, and c = 20.
The quadratic formula is:
x = (-b ± √\((b^2 - 4ac)\)) / 2a
Plugging in the values for a, b, and c, we get:
x = (-(-12) ± √\(((-12)^2 - 4(2)(20)))\) / 2(2)
Simplifying the expression inside the square root:
x = (12 ± √\((144 - 160)\)) / 4
x = (12 ± √(-16)) / 4
Since the square foundation of a negative number is definitely not a genuine number, this condition has no genuine arrangements. Complex numbers would provide the answers.
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Pls pls help I’ll mark u brainliesttt
Answer:
89.44
Step-by-step explanation:
\(120^2-80^2=8000\)
\(\sqrt{8000} = 89.44\)
Peter, Gordon and Gavin share £36 in a ratio 2:1:1. How much money does each person get?
Answer:
Peter gets 18£
Gordon and Gavin each get 9£
Answer:
peter = 18 Gordon = 9 Gavin = 9
Step-by-step explanation:
2+1+1 = 4
36 div 4 = 9
2 times 9 = 18
1 times 9 = 9
Name
Parker is making a quilt. The table shows the cost
of some of the items she needs to make the quilt.
1. Parker needs 3 yards of Fabric A, 5 yards
of Fabric B, and 9 yards of Fabric C. She
estimates the cost of the fabrics before she
goes to the store.
23-25-6.8²
1.319
Part A
920
292,5
3.21.95
Estimate the cost for each type of fabric. Then
find the total estimated cost.
67
21.95 29:2
21.00
Topic 4
Performance Task
Item
Fabric A, per yard
Fabric B, per yard
Fabric C, per yard
Batting, per package
Thread, per spool
2100 Template plastic, per sheet
Noc
Cost
$6.89
$4.39
$3.25
$17.50
$2.10
$3.35
$1.35
1. Using the multiplication of unit cost and quantity, the cost for each type of fabric is as follows:
Fabric A = $20.67Fabric B = $21.95Fabric C = $29.25.2. Using the addition operation, the total estimated cost required by Parker to make the quilt is $96.17.
What are mathematical operations?Mathematical operations include multiplication, division, addition, and subtraction.
These basic mathematical operations can be used to determine solutions to mathematical problems.
While the costs for the fabrics are determined using multiplication, the total estimated costs for the quilt are the addition of all the different material costs.
Unit Cost Units Total Cost
Fabric A, per yard $6.89 3 $20.67 ($6.89 x 3)
Fabric B, per yard $4.39 5 21.95 ($4.39 x 5)
Fabric C, per yard $3.25 9 29.25 ($3.25 x 9)
Batting, per package $17.50 1 17.50
Thread, per spool $2.10 1 2.10
Template plastic, per sheet $3.35 1 3.35
Needles, per package $1.35 1 1.35
Total estimated costs $96.17
Thus, in this situation, we have applied mathematical operations to determine the different costs.
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4. Maria also wants to study the relationship between the weight of puppies at birth
and their adult weight (at two years old). She collected data from five randomly
selected small-breed dogs and displayed the data in the table.
Birth weightAdult weight
(pounds) (pounds)
1.5 10
317
18
2.5 14
Birth weight Adult weight
(pounds) (pounds)
0.75 5
Part A. Use the data in the table to create a scatterplot. (5 points)
Part A.
(5 points)
Dog Birth and Adult Weights
Answer:
y = 4.87x + 2.28 Is the answer
Step-by-step explanation:
( i see a little bit of part b but do not see the FULL QUESTION which is a problem and i cannot answer.. )
using a:
THE ULTIMATE LINEAR REGRESSION CACLAULTOR
yes it is the epic i get:
y = 4.87x + 2.28
Nothing more noting less ikr
y = 4.87x + 2.28 Being the answer
Find the median: 86, 24, 65, 65, 24, 24 *
Answer:
24 or uhm 44.6? i.d.k.
Step-by-step explanation:
The median of the given set {86, 24, 65, 65, 24, 24} is 44.5.
To find the median of the given set of numbers: 86, 24, 65, 65, 24, 24, we need to first arrange the numbers in ascending order:
24, 24, 24, 65, 65, 86
Now, there are six numbers in the set. Since there is an even number of data points, the median is the average of the two middlemost values.
The two middlemost values are 24 and 65.
Median = (24 + 65) / 2 = 89 / 2 = 44.5
So, the median of the given set is 44.5.
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Which graph represents the function f(x) = 2x-1 +2
Answer: Graph A
Step-by-step explanation:
Graph A. If you find the y-intercept by plugging in 0 for x, you get 2.5 = y, so therefore graph A is correct.
pls simplify these two problems:
Answer:
Step-by-step explanation:
1 )
\(\frac{2}{5}( \frac{5x}{4} - \frac{10}{3})-\frac{4x}{3} \\\frac{x}{2} - \frac{4}{3} - \frac{4x}{3}\\ \frac{-5x}{6}-\frac{4}{3}\)
2 )
\(\frac{17x}{8}+\frac{3x}{4}+\frac{1}{6}-\frac{7x}{12}+\frac{17}{3}\\ \frac{51x}{24}+\frac{18x}{24}-\frac{14x}{24}+\frac{35}{6}\\\frac{55x}{24}+\frac{35}{6}\)
Can someone help me answer this
The two relations that are also functions are:
S = { (-1, 0), (3, 2), (5, 4), (8, 9), (15, 12)}R = {(0, -1), (2, 1), (5, 4), (7, 9), (14, 12)}Which of the following relations represent functions?A relation is a function if and only if each point in the domain is mapped into a single value of the range.
So for example, the following relation:
{ (a, b), (a, c), (d, f)}
The input a is mapped into two different outputs, thus, this is not a function.
Then from the given options the ones that can be functions are:
S = { (-1, 0), (3, 2), (5, 4), (8, 9), (15, 12)}
R = {(0, -1), (2, 1), (5, 4), (7, 9), (14, 12)}
In all the other relations we can see inputs mapped into more than one output.
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Evaluate the expression when m=-3
m + 7m+1
__________________________________________________________
In this question, you are solving the expression by plugging in the value "-3" to all of the "m" variables in the expression.
__________________________________________________________
Solve:
Expression: m + 7m + 1
Plug "-3" into the "m" variables and solve.
-3 + 7(-3) + 1
-3 - 21 + 1
-24 + 1
-23
Your final answer should be: -23
__________________________________________________________
Answer: -23
__________________________________________________________
Answer:
m+7m+1 = -23
Step-by-step explanation:
To solve the given equation we will follow the PEDMAS rule.
PEDMAS stands for :
\(\purple\star\) P = Parentheses \(\purple\star\) E = Exponents \(\purple\star\) M = Multiplication \(\purple\star\) D = Division \(\purple\star\) A = Addition \(\purple\star\) S = Subtraction To solve the given equation we will follow the PEDMAS rule.Substituting the value of m = 3 to evaluate the expression :
\(\begin{gathered} \qquad{\twoheadrightarrow{\sf{m + 7m + 1}}}\\\\\qquad{\twoheadrightarrow{\sf{( - 3) + (7 \times - 3) + 1}}}\\\\\qquad{\twoheadrightarrow{\sf{ - 3 - 21+ 1}}}\\\\\qquad{\twoheadrightarrow{\sf{ - 24+ 1}}}\\\\\qquad{\twoheadrightarrow{\sf{ - 23}}} \\\\\qquad{\star{\underline{\boxed{\sf{\red{ - 23}}}}}}\end{gathered}\)
Hence, the answer is -23.
\(\rule{300}{2.5}\)
Which inequality is shown on the graph?
Answer:
y <= -2x + 1
Step-by-step explanation:
The one that is selected is correct.
Solve for the unknown. q- 5/6=1 5/6
Answer:
q=8/3
Step-by-step explanation:
First, add 5/6 to both sides to get rid of -5/6 to get q=16/6 then simplify to q=8/3.
Answer:
\(q=2\frac{2}{3}\)
Step-by-step explanation:
The given equation consists of a fraction and a mixed number.
First, convert the mixed number into an improper fraction by multiplying the whole number by the denominator of the fraction, adding this to the numerator of the fraction, and placing the answer over the denominator:
\(q-\dfrac{5}{6}=1 \frac{5}{6}\)
\(q-\dfrac{5}{6}=\dfrac{1 \cdot 6+5}{6}\)
\(q-\dfrac{5}{6}=\dfrac{11}{6}\)
Now, add 5/6 to both sides of the equation to isolate q:
\(q-\dfrac{5}{6}+\dfrac{5}{6}=\dfrac{11}{6}+\dfrac{5}{6}\)
\(q=\dfrac{11}{6}+\dfrac{5}{6}\)
As the fractions have the same denominator, we can carry out the addition by simply adding the numerators:
\(q=\dfrac{11+5}{6}\)
\(q=\dfrac{16}{6}\)
Reduce the improper fraction to its simplest form by dividing the numerator and denominator by the greatest common factor (GCF).
The GCF of 16 and 6 is 2, therefore:
\(q=\dfrac{16\div 2}{6 \div 2}\)
\(q=\dfrac{8}{3}\)
Finally, convert the improper fraction into a mixed number by dividing the numerator by the denominator:
\(q=2 \; \textsf{remainder}\;2\)
The mixed number answer is the whole number and the remainder divided by the denominator:
\(q=2\frac{2}{3}\)