Answer:
Step-by-step explanation:
7n<84
(7n)/7<84/7
n<12
A package of 8-count AA batteries costs $6.24. A package of 20-count Of batteries costs $15.80. Which statement about the unit prices is true?
A) The 20-count pack of AA batteries has a lower unit price of $0.78 per battery.
B) The 8-count pack of AA batteries has a lower unit prices of $0.78 per battery.
C) The 20-count pack of AA batteries has a lower unit price of $0.79 per battery.
D) The 8-count pack of AA batteries has a lower unit price of $0.79 per battery.
The 8-count pack of AA batteries has a lower unit prices of $0.78 per battery.
Option B is correct.
What is division?Division in mathematics is the process of breaking a number up into equal parts, and finding out how many equal parts can be made. For example, dividing 15 by 3 means splitting 15 into 3 equal groups of 5.
According to the question
Unit price of 8 AA batteries
= 6.24 ÷ 8
= 0.78
Unit price of 20 AA batteries
= 15.8 ÷ 20
= 0.79
Since, 0.78 < 0.79
Therefore, the unit price of 8 AA batteries is low.
Option B is correct.
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23 points see attachment below
Answer:
-3
Step-by-step explanation:
The top left box on the x axis is negitive 3
(6) A t-shirt originally priced at $16 was reduced after a sale. After a coupon had been applied, James paid $11.20 for a new t-shirt. By what percent was the shirt discounted?
Answer: The shirt was discounted at 30%
Step-by-step explanation:
1- Find how many dollars you saved (16-11.20=4.8$)
2-
4.8/16
?/100
?= 100x4.8÷16
?=30
Joey’s math average in the first quarter was an 83. In the second quarter, his average was 93. What was the approximate percent increase in his math average?
The approximate percent increase in his math average is 12%
How to find the approximate percent increase in his math average?
A percentage is defined as the ratio that can be expressed as a fraction of 100.
percent increase in math average = (difference in average/initial average) * 100
percent increase in math average = (93 - 83)/83 * 100
percent increase in math average = 10/83 * 100
percent increase in math average = 12%
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In ΔUVW, the measure of ∠W=90°, UW = 39, WV = 80, and VU = 89. What is the value of the sine of ∠V to the nearest hundredth?
Answer:
In ΔUVW, the measure of ∠W=90°, WV = 39, UW = 80, and VU = 89. What ratio represents the cosine of ∠U? Therefore, the ratio that represents the cosine of ∠U is 39/81.
Step-by-step explanation: hope this helps
3 3/5 divided by 1/6?
Answer:
10.8
Step-by-step explanation:
3 3/5 divided by 1/6
(3(3/5))/(1/6)
(9/5)/(1/6)
54/5
10(4/5)
10.8
3 6 9 12 15 18 21 24 27 30 is odd or even numbers?
Answer: Half of them are even and half of them are odd.
Step-by-step explanation:
The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.
The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.
Therefore, out of the given numbers, half of them are even and half of them are odd.
________________________________________________________
Hi please help me no links thank you
Step-by-step explanation: (I'm not gonna' do it all for you tho)
to convert from percent to fraction:
70% = \(\frac{70}{100} =\frac{7}{10}\)
to convert from fraction to percent:
\(\frac{11}{20}=\frac{55}{100}\) = 55%
to convert from fraction to decimal:
\(\frac{3}{25} =\frac{12}{100} =0.12\)
to convert from decimal to fraction:
\(1.25=\frac{125}{100} =1\frac{25}{100} =1\frac{1}{4}\)
to convert from percent to decimal:
0.2% = \(\frac{0.2}{100} =0.002\)
to convert from decimal to percent:
\(0.4= (0.4*100)\)% = 40%
With that, you can solve the rest on your own
I need to know how to do this problem please
Answer: Total expenses if 3 widgets are produced is $11,018.00
Step-by-step explanation: The variable cost per unit is given by the coefficient of q in the expense function. In this case, the variable cost is $6.00 per widget. To find the variable costs to produce 2 widgets, we simply multiply the variable cost per unit by the number of units produced: Variable costs for 2 widgets = 2 x $6.00 = $12.00 Therefore, the variable costs to produce 2 widgets is $12.00. To find the variable costs to produce q widgets, we simply multiply the variable cost per unit by the number of units produced: Variable costs for q widgets = q x $6.00 = $6q Therefore, the variable costs to produce q widgets is $6q. To find the total expenses if 3 widgets are produced, we can use the expense function and substitute q = 3:E = 6.00 q + 11,000
E = 6.00 (3) + 11,000
E = 18.00 + 11,000
E = 11,018.00 Therefore, the total expenses if 3 widgets are produced is $11,018.00.
A phone company offers two monthly plans. Plan A costs $10 plus an additional $0.15 for each minute of calls. Plan B costs $19 plus and additional $0.10 for each minute of calls.
For what amount of calling do the two plants cost the same?
What is the cost when the tow plans cost the same?
Answer:
Step-by-step explanation:
A phone company offers two monthly plans. Plan A costs $10 plus an additional $0.15 for each minute of calls. Plan B costs $19 plus and additional $0.10 for each minute of calls.
For what amount of calling do the two plants cost the same?
50 students in the fourth grade class list of their hair and eye colors in the table below are the events green eyes and brown hair independent
Answer:
câu này là 500 nhen
The table below represents a frequency distribution for the age (in years) of employees at a particular company.
Age (in years) Frequency
23-29
25
30-36
41
37-43
37
Use the table to answer the following questions.
Your answers should be exact numerical values
The class width used for the frequency distribution is
The class midpoint for the class 23-29 is
The class midpoint for the class 30-36 is
The class midpoint for the class 37-43 is
Check
The class width used for the frequency distribution is 6.
The class midpoint for the class 23-29 is 26.
The class midpoint for the class 30-36 is 33.
The class midpoint for the class 37-43 is 40.
To find the class width of the frequency distribution, we need to determine the range of each age class. The range is the difference between the upper and lower boundaries of each class. Looking at the table, we can see that the class boundaries are as follows:
23-29
30-36
37-43
For the class 23-29, the lower boundary is 23 and the upper boundary is 29. To find the class width, we subtract the lower boundary from the upper boundary:
Class width = 29 - 23 = 6
So, the class width for the frequency distribution is 6.
To find the class midpoint for each class, we take the average of the lower and upper boundaries of each class.
For the class 23-29:
Class midpoint = (23 + 29) / 2 = 52 / 2 = 26
For the class 30-36:
Class midpoint = (30 + 36) / 2 = 66 / 2 = 33
For the class 37-43:
Class midpoint = (37 + 43) / 2 = 80 / 2 = 40
So, the class midpoint for the class 23-29 is 26, for the class 30-36 is 33, and for the class 37-43 is 40.
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Can it be concluded that the given parallelogram is either a rhombus, a rectangle, or a square? Explain.
Can it be concluded that the given parallelogram is either a rhombus, a rectangle, or a square?
(Picture, and answer options below)
1 From the given information, no determination can be made as to whether the parallelogram is a rhombus, a rectangle, or a square.
2 The reason for the determination made in the previous step is A. From the given information, no determination can be made as to whether the parallelogram is a rhombus, a rectangle, or a square.
How to explain the parallelogramThe diagonals of a parallelogram bisect each other, but this is true for all parallelograms, regardless of whether they are squares, rectangles, or rhombuses.
Therefore, the given information is not sufficient to determine whether the parallelogram is a rhombus, a rectangle, or a square.
In conclusion, from the given information, no determination can be made as to whether the parallelogram is a rhombus, a rectangle, or a square.
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What is the meaning of "all free variables of a formula ϕ(u1, . . . , un) are among u1, . . . , un"?
The phrase "all free variables of a formula ϕ(u1, . . . , un) are among u1, . . . , un" refers to a property of a logical formula ϕ with variables u1, u2, ..., un. In logic and formal systems, variables are used to represent unspecified elements or objects.
What does the phrase imply?When a variable is considered "free" in a formula, it means that it is not bound by any quantifiers or other logical operators in the formula. In other words, it is a variable that is not restricted in any way within the formula.
The given statement implies that all the free variables in the formula ϕ(u1, . . . , un) are explicitly listed among the variables u1, u2, ..., un. In other words, the formula ϕ does not contain any additional free variables beyond the ones explicitly mentioned.
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Joshua and Amahle are selling boxes of fruit for a Habitat for Humanity fundraiser. Customers can buy small
boxes of fruit and large boxes of fruit. Joshua sold 15 small boxes of fruit and 15 large boxes of fruit for a
total of $390.00. Amahle sold 20 small boxes of fruit and 25 large boxes of fruit for a total of $592.50. Find the cost of one small box of fruit and the cost of one large box of fruit.
Cost of small box: $
Cost of large box: $
The cost of one small box of fruit and the cost of one large box of fruit is $11.5 and $14.5 respectively.
What is the cost of small and large box?Let
cost of one small box of fruit = x
cost of one large box of fruit = y
15x + 15y = 390
20x + 25y = 592.50
From (1)
x + y = 26
x = 26 - y
Substitute x = 26 - y into (2)
20x + 25y = 592.50
20(26 - y) + 25y = 592.50
520 - 20y + 25y = 592.50
- 20y + 25y = 592.50 - 520
5y = 72.50
divide both sides by 5
y = 72.50/5
y = 14.5
Substitute y = 14.5 into
15x + 15y = 390
15x + 15(14.5) = 390
15x + 217.5 = 390
15x = 390 - 217.5
15x = 172.5
divide both sides by 15
x = 172.5/15
x = 11.5
Therefore, small box cost $11.5 and large box cost $14.5
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The fraction of PKR 1 is 50 paisas
The fraction that represents the rate between PKR and Paisas is given as follows:
1/50.
What is a fraction?A fraction is a numerical representation of the division of the two terms x and y, as follows:
Fraction = x/y.
As the rate is PKR 1 = 50 paisas, we have that the fraction that represents the rate between PKR and Paisas is given as follows:
1/50.
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Michael's dog ate 6 cans of dog food this week. Each can contained 48.6 grams of protein. How much protein was this in all?
Answer:
291.6 g
Step-by-step explanation:
Hi there!
What we know:
There were 6 cans of dog foodEach can contained 48.6 g of proteinTo find the total grams of protein that Michael's dog ate, multiply 48.6 g by 6 cans:
48.6 × 6 = 291.6
Therefore, Michael's dog ate 291.6 g of protein altogether.
I hope this helps!
Work out the volume of the prism height of 12 4 and five
The calculated volume of the prism is 702 cubic cm
Finding the volume of the prismFrom the question, we have the following parameters that can be used in our computation
The trapezoidal prism (see attachment)
The formula of the volume of a trapezoidal prism is
Volume = Base area * Height
Where we have
Base area = 1/2 * (8 + 10) * 6
Evaluate the sum of 8 and 10
Base area = 1/2 * 18 * 6
Evaluate the products of 1/2, 18 and 6
Base area = 54
Also, we have
Height = 13
So, the volume is calculated as
volume = 13 * 54
Evaluate
volume = 702
Hence, the volume of the prism is 702 cubic cm
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help there a man walkibg around in my hosue and it late and everyone sleep help!!
Answer: throw something at it maybe
Step-by-step explanation:
What is the explicit formula for this sequence?
60, 30, 15, 7.5, ...
A. an = 60.
(9)
OB. an= = (1.60
OC. an = 60.
• (+)-
OD. an=3.2(n-1)
60(n-1)
(n-1)
i beilive this is unknown
What is the equation of the line that is perpendicular to -x+y=7 and passes through (-1,-1)?
a.-x+y=2
b.-x-y=2
c.x-y=2
d.-x-y=0
e. x+y=0
Answer:
\(-x - y = 2\).
Step-by-step explanation:
If the slope of a line in a plane is \(m\) and the \(y\)-intercept of that line is \(b\), the slope-intercept equation of that line would be \(y = m\, x + b\).
Rearrange the equation of the given line \(-x + y = 7\) in the slope-intercept form to find the slope of this line:
\(-x + y = 7\).
\(x -x + y = x + 7\).
\(y = x + 7\).
Notice that in the slope-intercept equation of this given line, the coefficient of \(x\) is \(1\). Thus, the slope of the given line would be \(m_{1} = 1\).
Two lines in a plane are perpendicular to one another if the product of their slopes is \((-1)\). In other words, if \(m_{1}\) and \(m_{2}\) are the slopes of two lines perpendicular to each other, then \(m_{1}\, m_{2} = (-1)\).
Since \(m_{1} = 1\) for the given line, the slope of the line perpendicular to this given line would be:
\(m_{2} = (-1) / m_{1} = (-1) / 1 = -1\).
If the slope of a line in a plane is \(m\), and that line goes through the point \((x_{0},\, y_{0})\), the equation of that line in point-slope form would be:
\(y - y_{0} = m\, (x - x_{0})\).
The slope of the line in question is \(m = (-1)\). It is given that this line goes through the point \((-1,\, -1)\), where \(x_{0} = (-1)\) and \(y_{0} = (-1)\). Thus, the equation of this line in point-slope form would be:
\(y - y_{0} = m\, (x - x_{0})\).
\(y - (-1) = (-1)\, (x - (-1))\).
\(y + 1 = -(x + 1)\).
Rearrange this equation to match the format of the choices:
\(y + 1 = -x - 1\).
\(x + y = -2\).
\(-x - y = 2\).
Help meeee please or I'm going to fail school
Christopher tosses a coin three times. Each toss could be heads or tails. Which outcome would be included in the compound event "at least two heads"? First toss He Second Third Sample space toss toss outcomes
H HHH HHT HTH HTT THH THT TTH H H T
A. THH
B. HTT
C. TTH
D. THT
Answer: The is THH, or A.
Step-by-step explanation: The question directly ask for “at least two heads”, which no other answer contains two heads. Therefore, the answer is A.
Brittany has 50 beads. 70% of the beads are gold. How many beads are gold?
What is 2+x=4 please help
Answer:
2+x=4
x = 4 - 2
x = 2
Step-by-step explanation:
........
Evaluate the line integral, where C is the given curve. (x 9y) dx x2 dy, C C consists of line segments from (0, 0) to (9, 1) and from (9, 1) to (10, 0)
You have some missing symbols, so I'm guessing that the integral reads
\(\displaystyle \int_C (x-9y) \, dx - x^2 \, dy\)
where C is composed of the two line segments,
• C₁ = {(9t, t) : 0 ≤ t ≤ 1}
• C₂ = {(9 + t, 1 - t) : 0 ≤ t ≤ 1}
The integrals over each path are
\(\displaystyle \int_{C_1} (x-9y) \, dx - x^2 \, dy = \int_0^1 (9t - 9\cdot t) (9 \, dt) - (9t)^2 \, dt\)
\(\displaystyle \cdots = -81 \int_0^1 t^2 \, dt\)
\(\displaystyle \cdots = -\frac{81}3 (1^3 - 0^3) = -27\)
and
\(\displaystyle \int_{C_2} (x-9y) \, dx - x^2 \, dy = \int_0^1 ((9 + t) - 9(1 - t)) \, dt - (9 + t)^2 (-dt)\)
\(\displaystyle \cdots = \int_0^1 (81 + 28t + t^2) \, dt\)
\(\displaystyle \cdots = 81 (1 - 0) + 14 (1^2 - 0^2) + \frac13 (1^3 - 0^3) = \frac{286}3\)
Then the overall line integral has a value of
\(\displaystyle \int_C (x-9y) \, dx - x^2 \, dy = -27 + \frac{286}3 = \boxed{\frac{205}3}\)
16 lakh students in India use Khan Academy today. The number of users is expected to grow by 50% every year. How many students in India will be using Khan Academy two years from now?
Answer: Let's first calculate the number of users after one year:
Number of users after one year = 16 lakh + 50% of 16 lakh
= 16 lakh + 8 lakh
= 24 lakh
Now, we can calculate the number of users after two years by applying the same growth rate:
Number of users after two years = 24 lakh + 50% of 24 lakh
= 24 lakh + 12 lakh
= 36 lakh
Therefore, two years from now, it is expected that 36 lakh (3.6 million) students in India will be using Khan Academy.
Step-by-step explanation:
Answer:
36 Iakh Students
Step-by-step explanation:
Find the absolute value. |1 - i|
Answer: 2
I couldn't find the answer on here so if anyone needs it here it is
HELP PLEASE 50 POINTS
The cost of producing n items is £(950+63n). The items can be sold for £(280-5n) per item. How many items can be produced and sold in order to make a profit? Give your answer in the form M<=n<=N where M and N are both integers.
Items that can be produced and sold in order to make a profit is
\(5\leq n\leq 38\)
Given :
The cost of producing n items is (950+63n). The items can be sold for (280-5n) per item
Cost price = \(950+63n\)
Selling price is 280-5n for one item
Selling price of 'n' items
\(n \cdot (280-5n)\\280n-5n^2\)
We know that , profit = selling price for n items - cost price for n items
We make profit only when selling price - cost price >=0
Lets replace the expressions
\(280n-5n^2 - (950+63n)\geq 0\\280n-5n^2 - 950-63n\geq 0\\\\-5n^2+217n-950\geq 0\)
Solve the inequality for n
Apply the quadratic formula to solve for n
\(-5n^2+217n-950=0\\n=\frac{-217\pm \sqrt{217^2-4\left(-5\right)\left(-950\right)}}{2\left(-5\right)}\\n=\frac{-217\pm \:3\sqrt{3121}}{2\left(-5\right)}\\n=\frac{-217+3\sqrt{3121}}{2\left(-5\right)},\:n=\frac{-217-3\sqrt{3121}}{2\left(-5\right)}\\n=4.94022 ,\:n=38.45977\)
Now we check the inequality
lets pick a number before 4.9 , n=4
\(-5n^2+217n-950\:\geq 0\\-162\geq 0 false\\\\Pick, n=10\\-5\left(10\right)^2+217\left(10\right)-950\geq 0\\720\geq 0 true\\\\Pick, n=40\\-5\left(40\right)^2+217\left(40\right)-950\geq 0\\-270\geq 0 false\\\)
n=40 satisfies our inequality
40 lies between n=4.9 and n=38
So, \(5\leq n\leq 38\) items can be produced and sold in order to make a profit
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On a map, the scale shown is 1 inch : 5 miles. If
a wildlife refuge is 50 square miles, what is the
area of the refuge on the map?
Use the proportion to solve for x.
1 in. 2
25 mi2
x in. ²
50 mi²
Cross
multiplication
can help!
=
The area of the wildlife refuge is [?] square
inches on the map.
Enter
Answer:
Step-by-step explanation:
6
A 17 feet ladder is placed against a building. The bottom of the ladder is 15 feet away from the building. How many feet high is the top of the ladder?
7 feet
12 feet
8 feet
15 feet
Answer:
\(8 \ feet\)
Step-by-step explanation:
In this situation, one is given the following information. A ladder is leaning against a wall and has a measure of (17) feet. The bottom of the ladder is (15) feet away from the wall. One can infer that the wall forms a right angle with the ground. Thus, the triangle formed between the ground, ladder, and wall is a right triangle. Therefore, one can use the Pythagorean theorem. The Pythagorean theorem states the following,
\(a^2+b^2=c^2\)
Where (a) and (b) are the legs or the sides adjacent to the right angle of the right triangle. The parameter (c) represents the hypotenuse or the side opposite the right angle. In this case, the legs are the ground and wall, and the hypotenuse is the ladder. Substitute this into the formula a solve for the height of the wall.
\(a^2+b^2=c^2\)
Substitute,
\((ground)^2+(wall)^2=(ladder)^2\\\\(15)^2+(wall)^2=(17)^2\\\)
Simplify,
\((15)^2+(wall)^2=(17)^2\\\\225+(wall)^2=289\)
Inverse operations,
\(225+(wall)^2=289\\\\(wall)^2=64\\\\wall=8\)