Many opera singers (and some pop singers) have a range of about 212 octaves or even greater. Suppose a soprano's range extends from A below middle C (frequency 220 Hz ) up to E-flat above high C (frequency 1244 Hz ). Although the vocal tract is quite complicated, we can model it as a resonating air column, like an organ pipe, that is open at the top and closed at the bottom. The column extends from the mouth down to the diaphragm in the chest cavity, and we can also assume that the lowest note is the fundamental. How long is this column of air if v=354 m/s ? Does your result seem reasonable on the basis of observations of your own body?

Answers

Answer 1

The length of a closed-end resonant tube for the above question is 21.3 cm.

Resonating air column:

Many opera singers (and some pop singers) have a range of about 2–12 octaves or even greater. Suppose a soprano's range extends from A below middle C (frequency 220 Hz ) up to E-flat above high C (frequency 1244 Hz ). Although the vocal tract is quite complicated, we can model it as a resonating air column, like an organ pipe, that is open at the top and closed at the bottom. The column extends from the mouth down to the diaphragm in the chest cavity, and we can also assume that the lowest note is fundamental.

How long is this column of air if v=354 m/s?

Given: Frequency of A below middle C, f₁ = 220 HzFrequency of E-flat above high C, f₂ = 1244 Hz. Speed of sound, v = 354 m/s. To find: Length of the column of air, assuming that the lowest note is fundamental, we know that the frequency of the second overtone is three times the frequency of the fundamental or first harmonic. Hence, we have f₂ = 3f₁=> f₁ = f₂/3=> f₁ = 1244/3 = 414.67 Hz.

Now, we can use the formula for the length of a closed-end resonant tube (or pipe): l = v/4f₁= 354/(4 × 414.67)= 0.213 m = 21.3 cm length of the column of air in the resonating vocal tract of the soprano is 21.3 cm, given that the speed of sound is 354 m/s. This result is reasonable, as the human vocal tract is about 17-20 cm long on average, which is within the range of our calculated value.

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Related Questions

. Draw the position vs. time graph for a person walking at a
constant speed of 1 m/s for 10 seconds. On the same axes, draw
the graph for a person running at a constant speed of 4 m/s.

Answers

The slope of position versus time graph represent the velocity.

position vs. time graph attached below.

In a position-time graph, the velocity of the moving object is represented by the slope of the graph line.

So, the position vs. time graph for a person walking at a  constant speed of 1 m/s for 10 seconds will be a straight line having slope of 1 in the interval of 0 to 10 seconds.

Similarly,  the position vs. time graph for a person walking at a  constant speed of 4 m/s for 10 seconds will be a straight line having slope of 4 in the interval of 0 to 10 seconds.

Graph attached below.

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. Draw the position vs. time graph for a person walking at aconstant speed of 1 m/s for 10 seconds. On

a 12-cm-long spring is attached to the ceiling. when a 2.4 kg mass is hung from it, the spring stretches to a length of 15 cm .
(a) What is the spring constant k?

Answers

The spring constant (k) is approximately 784 N/m when a 2.4 kg mass stretches a 12 cm long spring to a length of 15 cm.

To find the spring constant (k), we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position.

Hooke's Law can be expressed as F = -kx, where F is the force applied to the spring, k is the spring constant, and x is the displacement from the equilibrium position.

In this case, the displacement is the change in length of the spring, which is given as 15 cm - 12 cm = 3 cm = 0.03 m.

The force applied to the spring can be calculated using the formula F = mg, where m is the mass and g is the acceleration due to gravity (approximately 9.8 m/s^2).

F = (2.4 kg) * (9.8 m/s^2) = 23.52 N

Now we can use Hooke's Law to find the spring constant:

23.52 N = -k * 0.03 m

Solving for k:

k = -23.52 N / 0.03 m

k ≈ 784 N/m

Therefore, the spring constant (k) is approximately 784 N/m.

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a.) Review the graphical data above and create a data table that reflects the graph (10
pts.)

Answers

no shushhhhhhhhhhhhhhhhhhh

Silver has a density of 10.5g/cm3 and gold has a density of 19.3g/cm3. Which would have a greater mass, 5cm3 of silver or 5cm3 of gold ?

Answers

Silver has a density of 10.5 g/ \(cm^3\) and gold has a density of 19.3 g/ \(cm^3\), so out of 5  \(cm^3\) of silver or 5  \(cm^3\) of gold, the 5  \(cm^3\) of gold would have a greater mass as the mass of gold is 96.5 g while the mass of silver is 52.5 g.

What is the relationship between density and mass?

The mass of an object is equal to its density multiplied by its volume, so here is the calculation,

For 5 \(cm^3\) of silver, the mass is,

mass = density x volume

mass = 10.5 g/ \(cm^3\)x 5 \(cm^3\)= 52.5 g

For 5  \(cm^3\) of gold, the mass is

mass = density x volume

mass = 19.3 g/ \(cm^3\)x 5  \(cm^3\)

mass = 96.5 g

Hence, silver has a density of 10.5 g/ \(cm^3\) and gold has a density of 19.3 g/ \(cm^3\), so out of 5  \(cm^3\) of silver or 5  \(cm^3\) of gold, the 5  \(cm^3\) of gold would have a greater mass as the mass of gold is 96.5 g while the mass of silver is 52.5 g.

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John travels 250 miles North, but then 105 miles South to pick up a friend. What is his total distance and displacement? 355 miles total distance and 355 miles South displacement 145 miles total distance and 355 miles North displacement 145 miles total distance and 145 miles South displacement 355 miles total distance and 145 miles North displacement

Answers

Answer:

The displacement is 145 m in the north direction and the distance is 355 miles.

Explanation:

The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In other words, distance refers to the space traveled by an object during its movement. It is calculated as the sum of all the distances traveled. In this case:

250 miles + 105 miles= 355 miles

On the other hand, displacement refers to the distance from a start position to an end position regardless of the travel. That is, like distance, displacement is a measure of length. Instead, the displacement is a vector quantity that depends on the direction, so it is described from the magnitude and the direction.

Mathematically, the displacement d is calculated as:

d = df - di

where df is the final position and di is the initial position of the object.

In this case:

displacement= 250 miles - 105 miles= 145 miles

Since the north distance is greater than the south distance, then the displacement is 145 m in the north direction and the distance is 355 miles.

an 82-kg stunt man falls off the top of a large building. after falling for 65 meters he has a speed of 22 m/s. assuming he was initially at rest, what was the average force of air resistance exerted on the stunt man during his fall?

Answers

The average drag force on the stuntman during a fall is 305.29 N. force is a push or a pull.

.

Start by collecting the kinetic energy of the stuntman.

Mass (m) = 82 kg

Velocity (v) = 22 m/s

Kinetic Energy (KE) =?

KE = 19844 J

Finally, determine the average drag applied to the stunt. This is obtained as follows:

Distance = 65 meters

Energy = 19844 J

Average force =?

Energy = Work

Work (W) = Force (F) × Displacement (d)

W = Fd

So

E = W = Fd

19844 = F × 65

Divide both sides 65

F = 19844 / 65

F = 305.29 N

So, from the above calculation we can conclude that the average force is 305.29 N

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.

Calculate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2.

Answers

After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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A car starts from rest and speeds up to 30 m/s in a total of 6 s.
What is the acceleration?
1. 5m/s2
2. 30 m/s
3. 24 m/s2
4. 5 m/s

Answers

5 m/s^2, acceleration is always in m/s^2

One of the most fundamental techniques used to determine distances is triangulation. This same method is used to detect a star's parallax and corresponding distance. Triangulation involves observing the same object from two vantage points, so that the object, along with the two vantage points, forms a triangle in space. In the figure, label the essential components used to triangulate the distance to a building located on the opposite side of an empty lot.

Answers

A prime mechanism for calculating distances, such as those between stars, is triangulation.

A key method for calculating distances, such as those between stars, is triangulation. Three elements are needed: the thing itself, two vantage points, and one. The building on the other side of the lot is the item in the illustration, which also shows two viewpoints labelled as P1 and P2.

The separation among points P1 and P2 is known, and the three points together form a triangle in space. The distance from P1 or P2 to the building can then be calculated using complex trigonometric calculations. Since it may be performed from a distance and does not require close proximity to an object, triangulation is a useful method for determining distances.

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the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s.

Answers

The unstretched length so that it does not allow the block to leave the surface until θ= 60° is L = 4.574 ft.

Given:

The weight of the block W = 2 lb

The initial velocity of the block v_i = 0

The stiffness of the spring k = 2 lb/ft

The radius of the cylindrical surface r = 2 ft

Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.

= F_n = m X a_n

Where, a_n is the centripetal acceleration or normal component of acceleration as follows:

= a_n = v²_2 / r

Substitute:

= F_n = m*v²2 / r

Where, F_n normal force acting on block by the surface is:

= F_n = W X cos(θ)

Substitute:

W*cos(θ) = m*v^2_2 / r

v_2 = sqrt ( r*g*cos(θ) )

Plug in the values:

v²_2 = 2 X 32.2 X cos(60)

v²_2 = 32.2 (ft/s)²

Apply the conservation of energy between points A and B where θ= 60° :

T_A + V_A = T_B + V_B

Where,

T_A : Kinetic energy of the block at initial position = 0

V_A: potential energy of the block initial position

V_A = 0.5 X k X x_A²

x_A = 2 X π- L           ( L is the original length )

V_A = 0.5X 2 X (2 X πi - L)² =

= (2 X pi - L)²

T_B = 0.5 X W/g X v_2² =

= 0.5 X 2 / 32.2 X 32.2 = 1

V_B = 0.5 X k X x_B² + W X 2 X cos(60)

and, x_B = 2 X 0.75 X π - L             ( L is the original length )

V_B = 0.5 X 2 X (1.5 X π - L)² + 2 X 1

= 2 + ( 1.5 X π- L )²

Input the respective energies back in to the conservation expression:

= 0 + (2π - L)² = 1 + 2 + ( 1.5π - L )²

= 4π² - 4πL + L² = 3 + 2.25π² - 3πL + L²

= πL = 1.75π² - 3

= L = 4.574 ft

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The complete question;

the 2-lb brick slides down a smooth roof, such that when it is at a it has a velocity of 5 ft/s. The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a stiffness k = 2 lb/ft. Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.

Consider the reaction, H2 + Br2 => 2 HI , which is found to be first order in Br2. Which step of the proposed mechanism must be slow in order to agree with this rate law?
Br2 => 2 Br
Br + H2 => H2Br
H2Br + Br => 2 HBr
A. 1
B. 2
C. Either 2 or 3
D. 3

Answers

Consider the H2 + Br2 => 2 HI reaction, which is first order in Br2 the correct option is A.

The reaction's rate law, which reads rate = k[Br2], reveals that it is first order in Br2. This demonstrates that the rate of the reaction is solely dependent on the Br2 concentration.

The equation should then be balanced, which requires that each component of the equation contain the same number of each element. For example, if you enter 2 for both NaBr and Na, the equation will be balanced

The first step, Br2 => 2 Br, has to be the slow step for the suggested mechanism to accord with this rate law. This is so because the reaction mechanism's slow step controls the overall rate law. The pace of the reaction will only be influenced by the concentration of Br2 if the first step is slow, as shown by the rate law.

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A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field created by the positive test charge also specify the direction of the electric field with respect to the force

Answers

Explanation:

direction of electric field is same as that of force experienced by the test charge

A positive test charge of 8.5 10 negative 7 Columbus experiences a force of 4.1 10 negative 1 N calculate

Answer:

Comments/Reasoning                                               Calculations/Results

I used the equation for calculating electric field strength. E = F/q

I substituted the values of F and q in the equation to get

this value of E                                                              E= (4.1 x10-1)/(8.5 x10-7)                                                                                                                  

The electric field strength is                                4.8 × 105 newtons/coulomb

Explanation:

edmentum sample answer

Using no more than 3 sentences, explain how a motor and generator are related.

Answers

The Electric Motor and Generator are differentiated on various factors like the main principle of working or function of the motor and generator. Consumption or production of electricity, its driven element, the existence of the current in the winding. Fleming’s rule followed by the motor and generator.

An increase in what property of an object causes an its inertia to increase?
A. velocity
B. acceleration
C. volume
D. mass

Answers

D. mass ,because inertia and mass are directly related, which means an increase in mass will increase inertia

Mass ,because inertia and mass are directly related, which means an increase in mass will increase inertia.

What is Inertia?

The concept of inertia states that an object will maintain its current motion unless a force changes its speed or direction.

The Latin word iners, which means idle or sluggish, is where the word "inertia" originates. The resistance of any physical object to a change in velocity can also be referred to as inertia.

The propensity of things to continue traveling straight ahead at a constant speed in the absence of external pressures is one element of this feature.

Therefore, Mass ,because inertia and mass are directly related, which means an increase in mass will increase inertia.

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In Fig. 25-28, find the equivalent capacitance of the combination. Assume that C1 is 10.0 mF, C2 is 5.00 mF, and C3 is 4.00 mF.

Answers

Use NGSS-aligned activities, movies, and articles to learn high school physics. Review the principles of electromagnetic radiation, kinematics, forces, and fields.

The electromagnetic spectrum is what?

The electromagnetic spectrum is introduced. Waves of electromagnetic energy can range in length from very long radio signals to very brief gamma rays. Only a small fraction of this spectrum, known as visible light, is visible to the human eye.

What does the term "electromagnetism" mean?

Electromagnetism. The electromagnetism that exists between particles with electrical charge is the subject of the branch of physics known as electromagnetism. One of the four primary forces, the electromagnetic force, manifests electromagnetic fields like earth's magnetic field, electric fields, and photons. It is the fundamental cause of electron binding.

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An aircraft A is flying at a constant speed of 270 m/s at a constant height of100 m above the surface of the earthThe aircraft directs a radar beam of wavelength 1.0 cm at a target T on the Earth's surface. After 90 us, an echo from the target is detected on the aircraft the frequency of the radar waves is 3 x 10^10Hz, find

(a) the speed of the radar waves
(b) the distance AT between aircraft and target
(c) the time which elapses before A is vertically above T.

An aircraft A is flying at a constant speed of 270 m/s at a constant height of100 m above the surface

Answers

A)  The speed of the radar waves = 3 x 10^8 m/s

B)  The distance between the aircraft and the target is 27 km.

C) It takes 100 seconds for the aircraft to be vertically above the target.

Radar wave speed, distance and time

(a) The speed of the radar waves can be found using the formula:

speed of light = frequency x wavelength

Since radar waves are a type of electromagnetic waves and travel at the speed of light, we can use the above formula to find the speed of the radar waves:

speed of radar waves = speed of light = 3 x 10^8 m/s

(b) To find the distance AT between the aircraft and the target, we can use the formula:

distance = (speed x time) / 2

where speed is the speed of the radar waves (which we found to be 3 x 10^8 m/s), and time is the time taken for the radar waves to travel to the target and back (which is twice the time it took for the echo to be detected on the aircraft).

time taken for radar waves to travel to target and back = 2 x 90 us = 180 us = 1.8 x 10^-4 s

So, the distance between the aircraft and the target can be calculated as:

distance AT = (speed of radar waves x time taken for radar waves to travel to target and back) / 2

= (3 x 10^8 m/s x 1.8 x 10^-4 s) / 2

= 27 km

Therefore, the distance between the aircraft and the target is 27 km.

(c) To find the time which elapses before A is vertically above T, we can use the formula:

time = distance / speed

where distance is the horizontal distance between the aircraft and the target (which we found to be 27 km), and speed is the speed of the aircraft (which we were not given, but we can assume is constant).

Since the aircraft is flying at a constant speed, the time it takes to travel the horizontal distance between the aircraft and the target is the same as the time it takes for the aircraft to be vertically above the target. Therefore, the time which elapses before A is vertically above T is:

time = distance / speed

= 27 km / (270 m/s)

= 100 s

Therefore, it takes 100 seconds for the aircraft to be vertically above the target.

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Compare and contrast the reproduction and death stage of a cicada and ladybug.

Answers

Answer:

Larva and pupa is present in complete metamorphosis while nymph is present instead of larva and pupa in incomplete metamorphosis.

Explanation:

Complete metamorphosis has four stages i. e. egg, larva, pupa, and adult while the incomplete metamorphosis has three stages i. e. egg, nymph, and adult. Grasshopper, dragonfly, cicada and cockroach have incomplete metamorphosis while ladybug , housefly, butterfly  and honeybee have complete metamorphosis. Both type of insects lay eggs and after hatching a baby insect comes out called larva. After sometime this larva transforms from immature to mature, this stage is known as pupa. After pupa, the insect converts into an adult which is ready for reproduction. Nymph is a stage that comes in place of larva and pupa in incomplete metamorphosis. in this stage, the insect is small in size and lack of wings but in adult stage the wings appear.

Light is incident upon the surface of the water in a level, flat-bottomed glass dish(see fifure, emailed). at what angle does the light emerge from the bottom of the dish?

Answers

Light will emerge at the same angle as it incidence on the medium.

It doesn't matter how many mediums through which light passes it will always emerge at the same angle as it is incident. As the flat bottomed glass slab will act as a glass slab and will laterally displace the light ray without changing the angle of the emergence.

When a light ray passes from a rarer to a denser medium it will bend towards normal, when a light ray passes from a denser to a rarer medium it will bend away from normal. How much the ray will bend depends on the refractive index of the material. In the case of a glass slab the amount of deviation at the point when the ray touches the dish and the deviation at the point where the ray leaves the slab nullifies each other. hence the emerging ray is parallel or latterally displaced as compared to the incident ray

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If a beam of radiation containing 1000 x-rays is spread out over a square field that measures 10 inches long and 10 inches wide, what is the concentration of x-rays per square inch?
a. 1 x-ray/in squared
b. 10 x-rays/in squared
c. 100 x-rays/in squared
d. 1000 x-rays/in squared
e. 10,000 x-rays/in squared

Answers

The concentration of x-rays in a given area can be calculated by dividing the total number of x-rays by the area. In this answer, we will determine the concentration of x-rays per square inch in a beam of radiation containing 1000 x-rays spread out over a square field that measures 10 inches long and 10 inches wide.

First, we need to calculate the total area of the square field. To do this, we multiply the length by the width, which gives us 10 inches * 10 inches = 100 square inches. Next, we divide the total number of x-rays by the total area to find the concentration of x-rays per square inch. In this case, 1000 x-rays / 100 square inches = 10 x-rays per square inch.

So, the answer is (c) 100 x-rays per square inch. It is important to note that the concentration of x-rays in a given area will vary based on the number of x-rays and the size of the area being considered. The above calculation assumes a uniform distribution of x-rays, but in real-world scenarios, the distribution may not be uniform and the concentration of x-rays may vary based on factors such as the angle of the beam, the distance from the source, and the presence of any obstructions.

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When cars travel around a banked (curved) road at the optimum angle,the normal reaction force (n) can provide the necessary centripetal force without the need for a friction force. (a)Describe whar would happen to Optimum banking angle when radius doubles? (b)Describe what would happen to optimum angle when speed doubles? (c)A car negotiate a turn of radius 80cm.What is the optimum banking angle for this curve if the speed is to be equal to 12m/s?​

Answers

Answer:

(a) The optimum banking Decreases

(b) The optimum banking Increases

(c) The optimum banking is approximately 86.88°

Explanation:

(a) The equation of motion on a banked road is given as follows;

\(v = \sqrt{R \cdot g \times \left(\dfrac{tan (\theta) + \mu}{1 - \mu \cdot tan (\theta) }\right) }\)

For no friction, we have;

v = √(R·g·tan(θ))

Where;

R₁ = The radius of the road

g = The acceleration due to gravity ≈ 9.81 m/s² = Constant

θ₁ = The bank angle

μ = The coefficient pf friction = Constant

v = The vehicle's speed

If the radius doubles, for no friction, we have;

v² = R·g·(tan(θ))

tan(θ) = v²/(R·g)

Therefore, when the radius doubles, tan(θ) becomes smaller and therefore, the optimum banking angle θ decreases (becomes smaller)

(b) When the speed doubles, we have;

v₁ = 2·v

∴ tan(θ₁) = (v₁)²/(R·g) = 4·(v)²/(R·g) = 4·tan(θ)

When the speed doubles, tan(θ) increases and therefore, the optimum banking angle θ increases increases

(c) The radius negotiated by the car, R = 80 cm = 0.8 m

The speed of the car, v = 12 m/s

From tan(θ) = v²/(R·g), we have;

tan(θ) = 12²/(0.8 × 9.81) ≈ 18.349

θ ≈ arctan(18.349°) ≈ 86.88°

which is a harmful role of bacteria of bacteria?

Answers

Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

What type of radiation is emitted by planets and star-forming clouds?.

Answers

Infrared radiation is emitted by planets and star-forming clouds.

Infrared radiation is a type of electromagnetic radiation with a longer wavelength than visible light, but shorter than radio waves. It is emitted by all objects with a temperature above absolute zero, including planets and star-forming clouds. This type of radiation is useful for observing astronomical objects because it can penetrate through dust and gas clouds that block visible light.

Infrared radiation is emitted by planets due to their thermal energy. The planets absorb radiation from the Sun and re-emit it as infrared radiation. Observing the infrared radiation from a planet can reveal information about its temperature, composition, and surface features.

Star-forming clouds also emit infrared radiation due to the heat generated by the formation of new stars. As these clouds collapse and fragment, they heat up and emit radiation across the electromagnetic spectrum, including in the infrared region. This allows astronomers to study the early stages of star formation and the physical conditions within these clouds.

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How does a fuse differ from a circuit breaker?
O A. A fuse must be replaced after use, but a circuit breaker can be
reset.
OB. A fuse works by flipping open, while a circuit breaker melts.
O C. A fuse opens the circuit to stop current, but a circuit breaker
closes the circuit.
O D. A fuse works when it detects a high resistance, but a circuit
breaker works when it detects a high voltage.​

Answers

Answer:

A.  A fuse must be replaced after use, but a circuit breaker can be

reset.

Explanation:

A fuse works by actually melting, so there is physical damage that interrupts conduction of current due to lack of conductive material.

The circuit breaker is a switch operated automatically when there is excess flow of current. It interrupts that way the flow of current, but can simply get reset (back to its original close position) once the problem that caused the overflow of current in the circuit is found.

This better agrees with answer A in the list of possible choices.

You would like to confirm Netwon's second law by running an experiment. You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude?
Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
There is some other force present. This additional force is different for the two objects and accounts for the fact that the objects land at different times.
Newton's second law is not relevant in determining when an object will land on the ground.
One object must be heavier than the other and must therefore experience a greater gravitational acceleration.

Answers

Answer:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

Explanation:

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.

what is the speed of a wave with a frequency of 2 Hertz and a wavelength of 87 m?

0.023 m/s
43.5 m/s
89 m/s
174 m/s

Answers

Answer:

The answer to your problem is, D. 174 m/s

Explanation:

Formula:

wave speed = frequency * wavelength

Speed of wave = 2Hz × 87m ( Look at question for the numbers )

Speed of wave = 174m/s

Simple math..

Thus the answer to your problem is, 174m/s

Which of these objects are malleable? Check all that apply.

tin fork and knife from a camping set
antique ceramic vase
steel pole fence post
marble sculpture
glass tabletop
copper coin

Answers

Answer:

The tin fork and knife, the copper coin, and the steel fence pole.

Explanation:

Those are both what people would call soft metals so they are malleable to the extent of probably not needing heavy duty equipment. It depends on you description of malleable because the steel fence pole could be malleable with the correct equipment and not snap in half if bent slowly enough.

The definition of malleable: (of a metal or other material) able to be hammered or pressed permanently out of shape without breaking or cracking.

But the glass table, marble sculpture and antique ceramic vase are nowhere near malleable because if you tried bending them they wouldn't bend but would shatter and break into pieces.

The tin fork and knife, the copper coin, and the steel fence pole are malleable, the correct option is A, C, and F.

What are malleable objects?

A malleable material is one that can be easily formed into a thin sheet by hammering. The most malleable metal is gold. In contrast, ductility is a solid material's ability to deform under tensile stress.

Metals are malleable because when a force is applied, layers of ions can slide over each other. Metallic bonding allows metal to change shape without breaking.

Gold, iron, aluminum, copper, silver, and lead are examples of malleable metals. Ductility and malleability do not always correlate; for example, gold is both ductile and malleable, whereas lead is only malleable.

Tin fork and knife, copper coin, and steel fence pole are all malleable.

Thus, the correct options are A, C, and F.

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If at some point along the straight line directly between two charges the strength of the electric field at that point is found to be zero what can we say for sure about those two charges?.

Answers

Answer: The charges must be like charges (both positive or both negative).

Explanation:

What happens to the acceleration of an object that has low mass and a large force applied to it?

Answers

Answer:

states that the acceleration of an object increases with increased force and decreases with increased mass. ... Notice how mass and force affect acceleration. Newton's second law. The acceleration of an object increases with increased force, decreases with increased mass, and is in the same direction as the force.

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The coetticient of friction between a block and the surface it slides across is 0.360. The block has a mass of 150 kg

What force is required to accelerate the block 0.5 m/a^2.

Answers

The friction between the b;ock and surface is given by mass and accelerartion.

Force = mass * acceleration

Imagine you throw a ball upward. After you release it, the ball would rise upward getting further from the earth and it's speed with decreased as it does so. Complete the G/R energy diagram and statement of conservation of energy on the next page for this situation. (We know the ball would eventually fall back down, but for this question consider the ball while it is rising upward and decreasing in speed.)

Answers

In the given situation, as the ball is thrown upward, it gains gravitational potential energy (GPE) while losing kinetic energy (KE). The energy diagram and statement of conservation of energy can be represented as follows: The picture is given below.

Conservation of Energy Statement:

The total mechanical energy of the ball, which is the sum of its gravitational potential energy (GPE) and kinetic energy (KE), remains constant as long as no external forces (such as air resistance) are acting on the ball. Therefore, the decrease in kinetic energy as the ball rises is equal to the increase in gravitational potential energy.

Mathematically, the conservation of energy can be expressed as:

Initial Energy (at release) = Final Energy (at highest point)

KE(initial) + GPE(initial) = KE(final) + GPE(final)

Since the ball is rising upward and its speed is decreasing, the initial kinetic energy is higher than the final kinetic energy. At the same time, the initial gravitational potential energy is lower than the final gravitational potential energy. This conservation principle ensures that the total energy of the ball is conserved throughout its motion.

To know more about gravitational potential energy (GPE)

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Imagine you throw a ball upward. After you release it, the ball would rise upward getting further from
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