Many common liquids have boiling points that are less than 110°C, whereas most metals are solids at room temperature and have much higher boiling points.

The boiling point of iodomethane, , is 42.4°C. What is the equivalent absolute temperature?

Temperature =
K

The boiling point of bismuth is 1833 K. What is the equivalent temperature on the Celsius scale?

Temperature =
°C

The quantity of heat energy released when 543 g of steam condenses is 1,228.5 kJ.

To calculate the quantity of heat energy released when 543 g of steam condenses, we need to use the heat of vaporization of water, which is the amount of energy required to vaporize one mole of water. The heat of vaporization of water is 40.7 kJ/mol at standard conditions.

First, we need to determine how many moles of water are in 543 g of steam. The molar mass of water is 18.015 g/mol, so we can calculate the number of moles as follows:

n = m/M = 543 g / 18.015 g/mol = 30.15 mol

Next, we can calculate the amount of heat energy released by multiplying the number of moles of water by the heat of vaporization of water:

q = nΔHvap = 30.15 mol x 40.7 kJ/mol = 1,228.5 kJ

Therefore, the quantity of heat energy released when 543 g of steam condenses is 1,228.5 kJ.

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Answer:

oxygen and carbon dioxide.

hope this helps you

The specific heat of the metal is 1.1106 J/g°C

Specific heat is the quantity of heat required to raise the temperature of one gram of a substance by one celsius degree

Here given data is

Mass of unknown metal = 23.8g

Temprature = 100°C

Mass of water = 50.0cm³ = 50 g

Temprature of water =  24.0°C

Final temprature of the system = 32.5°C

We have to find specific heat = ?

So first we determine the heat gain by water

Specific heat of water is 4.18 J/g°C

Q = mcΔT

Q =  50 g×8.5°C×4.18 J/g°C

Q = 1776.5 Joules

Then we determine the total heat lost by the unknown metal

Taking the specific heat f the metal to be x

Heat = 23.8g×67.5°C×x

1776.5 Joules = 23.8g×67.5°C×x

1776.5 Joules = 1606.5 J

x =  1606.5 J/1776.5 Joule

x = 1.1106 J/g°C

Specific heat of the metal is  1.1106 J/g°C

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Answer:

9.2375 grams of lithium carbonate is required to prepare 500.0 mL of a 0.250 M Li₂CO₃ solution.

Explanation:

Molarity is a measure of the concentration of a substance and is defined as the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

\(molarity=\frac{number of moles of solute}{volume}\)

Molarity is expressed in units \(\frac{moles}{liter}\).

In this case:

Replacing in the definition of molarity:

\(0.250 M=\frac{number of moles of solute}{0.5 L}\)

Solving

0.250 M*0.5 L = number of moles of solute

0.125 = number of moles of solute

If the molar mass of lithium carbonate is equal to 73.9 g/mol, then the required mass of the compound can be calculated by:

\(73.9 \frac{g}{mol}*0.125 moles= 9.2375 grams\)

9.2375 grams of lithium carbonate is required to prepare 500.0 mL of a 0.250 M Li₂CO₃ solution.

The mass of lithium carbonate required to prepare 500.0 mL of a 0.250 M Li₂CO₃ solution is 9250.0 grams.

The molar mass, also known as the molecular weight, is the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol). The molar mass of a compound is calculated by adding up the atomic masses of all the atoms in its chemical formula.

Given:

Volume = 500.0 mL = 500.0 cm³

Concentration = 0.250 M (moles per liter)

Molar mass of lithium carbonate (Li₂CO₃) = 73.9 g/mol

Use the formula:

Mass = Volume × Concentration × Molar mass

Substitute the values in the above equation:

Mass = 500.0 cm³ × 0.250 mol/L × 73.9 g/mol

= 9250.0 g

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The molarity or molar concentration of a solution is given by the number of moles of solute divided by the volume of solution:

No solute was added when the solution was diluted, so the only terms that change are the concentration and the volume.

So, let 1 denote the situation before the dilution and 2 denote the situation after the dilution.

At first, we have concentration 1, volume 1 and number of moles 1:

After diluting, we have concentration 2, volume 2 and number of moles 2:

However, since no solute was added or removed, the number of moles before and after are the same:

So, if we solve both equations for n, we have:

So:

The initial concentration and volume are:

And it was diluted to 137.6 mL, so this is the final volume:

Solving the equation we have to C2, we have:

So, the resulting molarity is approximately 2.42 M.

The standard reduction potential of the Cr³+/Cr electrode is -0.46V. None of the option is correct.

To determine the standard reduction potential of the Cr³+/Cr electrode, we can use the Nernst equation, which relates the standard reduction potential to the cell potential under non-standard conditions. The Nernst equation is given by:

E = E° - (0.0592/n) * log(Q)

where E is the cell potential, E° is the standard reduction potential, n is the number of electrons transferred in the half-reaction, and Q is the reaction quotient.

In this case, we have the standard potential of the cell as −0.60V. We know that the standard reduction potential of the Sn/Sn²+ electrode is -0.14V. Therefore, the reduction potential of the Cr³+/Cr electrode can be calculated as:

E = -0.60V - (-0.14V)

E = -0.60V + 0.14V

E = -0.46V

Therefore, the standard reduction potential of the Cr³+/Cr electrode is -0.46V.

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We are given the molarity of the solution, the molarity corresponds to the following expression:

That is, in one liter of solution there will be 0.259 moles of calcium sulfate.

We are asked to find the volume to have 4.45g, let's see how many moles are equivalent. To do this we divide the required weight by the molecular weight (MW) of calcium sulfate.

MW of calcium sulfate = 136.1 g/mol

Now we apply a rule of three to know the required volume. In the same operation, we can make the conversion from liters to milliliters, since the answer is asked in milliliters.

So, we will need 126.24 mL to supply 4.45 g from a 0.259M calcium sulfate solution

Answer:

No sound Is not matter Sound and light are not considered matter and was never matter

Explanation:

Hope this hope helps

Answer:

meteor

Explanation:

The most logical identification of a "shooting star" is a meteor. A meteor is basically any material from outerspace that falls to Earth. The main characteristic of a meteor is that from our point of view on the surface of the Earth it looks like a shooting star because we see a streak of light behind it. This light is simply dust and rock from the meteor burning up as it enters the Earth's atmosphere, leaving a "tail" of light behind it. Which to us looks like a shooting star.

Answer:

\(\boxed {\boxed {\sf 0.3 \ mol \ NH_3}}\)

Explanation:

We need to use stiochiometry and a mole to mole conversion to solve this problem.

First, examine the chemical equation. Make sure it is balanced before doing any calculations.

\(N_2+3H_2 \rightarrow 2NH_3\)

It is balanced, so we can also use the coefficients to refer to molar amounts.

So, the equation is also saying that 1 mole of N₂ (no coefficient implies 1) and 3 moles of H₂ react to form 2 moles of NH₃.

\(1 \ mol \ N_2 + 3 \ mol \ H_2 \rightarrow 2 \ mol \ NH_3\)

Now we can use this information to make a ratio. We know that we have 0.45 moles of hydrogen, and we are trying to find the moles of ammonia.

According to the original equation, 3 moles of hydrogen produce 2 moles of ammonia. Let's make a ratio.

\(\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

We have 0.45 moles of hydrogen, so multiply by that number.

\(0.45 \ mol \ H_2 *\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

Flip the ratio so the units of moles of hydrogen cancel.

\(0.45 \ mol \ H_2 *\frac{2 \ mol \ NH_3 }{3 \ mol \ H_2}\)

\(0.45 *\frac{2 \ mol \ NH_3 }{3}\)

\(\frac {0.45 *2 \ }{3} mol \ NH_3\)

\(\frac {0.9 \ }{3} mol \ NH_3\)

\(0.3 \ mol \ NH_3\)

0.3 moles of ammonia are produced when 0.45 moles of hydrogen gas react with nitrogen gas.

Answer:

D 4,3,2

Explanation:

4 Co + 3 O2 ----> 2 Co2O3

Answer:

False

Explanation:

The given statement stating that resistance  is the slowing of the flow of electrons and where some of the electrical energy is converted into heat is true and it is a opposite of conduction.

Conduction is defined as a process as a means of which heat is transferred from the hotter end of the body to it's cooler end.Heat flows spontaneously from a body which is hot to a body which is cold.

In the process of conduction,heat flow is within the body and through itself.In solids the conduction of heat is due to the vibrations and collisions of molecules while in liquids and gases it is due to the random motion of the molecules .

When conduction takes place, heat is usually transferred from one molecule to another as they are in direct contact with each other.There are 2 types of conduction:1) steady state conduction 2) transient conduction.According to the type of energy conduction is of three types:

1) heat conduction

2) electrical conduction

3)sound conduction

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The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.

For carbon:

Mass of carbon = 86.0% × 100.0 g = 86.0 g

For hydrogen:

Mass of hydrogen = 14.0% × 100.0 g = 14.0 g

Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.

First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.

Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol

Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol

Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.

Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939

Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.

Carbon: Hydrogen ≈ 2 : 3.878

Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.

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Answer:

The answer is A.

Explanation:

Answer:

Explanation:

I believe it is a

Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition  for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

The balance that can be used to measure a mass reading of 0.90 g will be a balance with ±0.01 g tolerance.

The mass reading       balance used for measurement

1.230 g                      ±0.001 g tolerance

5.43g                         ±0.01 g tolerance

4.0000g                    ±0.0001 g tolerance

6.539g                       ±0.001 g tolerance

The tolerance of a balance is the number of decimal place values shown on the balance and it is the permissible limitations measured in grams, that a balance can tolerate.

From the given parameters:

The mass reading       balance used for measurement

0.90 g                        ±0.01 g tolerance

1.230 g                      ±0.001 g tolerance

5.43g                         ±0.01 g tolerance

4.0000g                    ±0.0001 g tolerance

6.539g                       ±0.001 g tolerance

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The value of S2 is S₂ = 2.1 g/L.Approximately 2.1 g of the gas will dissolve in 2 L of water at 0.6 ATM, assuming the temperature remains constant.

To determine the amount of gas that will dissolve in 2 L of water at 0.6 ATM, we can use Henry's law, which states that the solubility of a gas is directly proportional to the partial pressure of the gas above the liquid.

According to Henry's law, the solubility of a gas can be represented as:S₁/P₁ = S₂/P₂,,where S₁ and S₂ are the solubilities of the gas at the respective pressures P₁ and P₂.Given that 7 g of the gas dissolves in 1 L of water at 2.0 ATM, we can consider this as our initial condition, denoted by S₁/P₁.

Now, we need to find the solubility at 0.6 ATM in 2 L of water, denoted by S₂/P₂.Since the temperature remains constant, we can assume that the solubility of the gas does not change. Therefore, we can rewrite the equation as:

S₁/P₁ = S₂/P₂,

Substituting the known values, we have:

(7 g/1 L)/(2.0 ATM) = S₂/(0.6 ATM),

Solving for S₂, we get:

S₂ = (7 g/1 L) * (0.6 ATM)/(2.0 ATM),

S₂ = 2.1 g/L.

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

Glossary: Electromagnetic wave. Definition: Electromagnetic radiation is generated by the vibration of electrons or other electrically charged particles

Explanation:

Explanation:

Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

By convention in standard cell notation, the anode is written on the left and the cathode is written on the right. So, in this cell: Zinc is the anode (solid zinc is oxidised). Silver is the cathode (silver ions are reduced).

Answer:

A mixture of ethane and ethene occupies 40 litre at 1.00 atm and at 400 K.The mixture reacts completely with 130 g of O2 to produce CO2 and H2O . Assuming ...

Missing: 32 ‎Br2

The coefficient needed in front of the product potassium to properly balance this chemical equation is 3 (option B).

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, potassium phosphide reacts with aluminum in a single replacement reaction to produce aluminum phosphide and potassium as follows:

K₃P + Al → AlP + 3K

The coefficient in front of pottasium in the balanced equation is 3.

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Taking into account the definition of Avogadro's Number, 2.5959×10²³ particles of PF₅ are present in 0.431 moles of PF₅.

Avogadro's number is the number of constituent particles (usually atoms or molecules) found in one mole amount of substance. Therefore, it is the proportional factor that relates the molar mass of a substance to the mass of a sample.

Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if 1 mole of PF₅ contains 6.023×10²³ particles, 0.431 mole of the compound contains how many particles?

amount of particles= (0.431 moles × 6.023×10²³ particles)÷ 1 mole

amount of particles= 2.5959×10²³ particles

Finally, 2.5959×10²³ particles of PF₅ are present.

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Yes, the three astronauts can safely make the trip back to Earth with only the CO2 absorbers contained in the lunar module.

The Lunar Module (LM) was a spacecraft built by the United States and used in the Apollo program to land humans on the Moon. The LM was designed and built to be used only in the vacuum of space, and it had no capability to operate in the Earth's atmosphere or on the surface of the Moon.

To determine this, we can calculate the amount of glucose needed to sustain the astronauts for the 3-day trip.

We know that each astronaut needs 2500 kilocalories per day, and there are 4 kilocalories per gram of glucose.

Therefore, each astronaut needs 625 grams of glucose per day, or 1875 grams of glucose total for the 3-day trip.

We can then convert this to moles of glucose needed, using the molar mass of glucose (180.156 g/mol).

Therefore, 1875 grams of glucose is equal to 10.4 moles of glucose.

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Answer:

87.6 %

Explanation:

Step 1: Write the balanced equation

LiOH + KCl ⇒ LiCl + KOH

Step 2: Calculate the theoretical yield of LiCl

We will use the following relations:

The theoretical yield of LiCl from 20.0 g of LiOH is:

\(20.0gLiOH \times \frac{1molLiOH}{23.95gLiOH} \times \frac{1molLiCl}{1molLiOH} \times \frac{42.39gLiCl}{1molLiCl} = 35.4gLiCl\)

Step 3: Calculate the percent yield of LiCl.

We will use the following expression.

\(\%yield = \frac{real\ yield}{theoretical\ yield} \times 100\% = \frac{31.0g}{35.4g} \times 100\% = 87.6 \%\)

Answer:

88.6%

Explanation:

Hello,

In this case, considering the given reaction, we notice a 1:1 molar relationship between lithium hydroxide (molar mass=23.95 g/mol) and lithium chloride (molar mass=42.394 g/mol), for that reason, we are able to compute the theoretical yield of lithium chloride by stoichiometry:

\(m_{LiCl}^{theoretical}=20.0gLiOH*\frac{1molLiOH}{23.95gLiOH}*\frac{1molLiCl}{1molLiOH} *\frac{42.394 gLiCl}{1molLiCl}=35.4gLiCl\)

Next, by knowing the actual yield of 31.0 g, we compute the percent yield as:

\(Y=\frac{m_{LiCl}^{actual}}{m_{LiCl}^{theoretical}} *100\%=\frac{31.0g}{35.4g}*100\%\\ \\Y=87.6\%\)

Therefore, among the given, the answer should be 88.6%

Best regards.

Explanation:

List the known and unknown quantities and plan the problem. Change each percent abundance into decimal form by dividing by 100. Multiply this value by the atomic mass of that isotope. Add together for each isotope to get the average atomic mass.

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

x = 7.016

The atomic mass of second isotope is 7.016

____________________________________________________

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Answer:

The correct answer is 18.75 moles X.

Explanation:

We first start with the idea that we have 25.00 moles of D. Next, we must look at the relationships in the balanced equation to find that for every 4 moles of D produced, 3 moles of X are reacted (since it is given that there is excess Y and thus X is the limiting reagent). From this, we can do the following calculation:

25.00 moles D * (3 moles X/4 moles D) = 18.75 moles X

Therefore, your answer is 18.75 moles X.

Hope this helps!

Answer:

You forgot to add a screenshot buddy.

Explanation: