Mai is visiting a city to see a tall land mark. They are 80 feet away when they spot it. To see the top they have to look up at an angle of 85. 66 degrees. How tall is the land mark?

Answer:

x= -3

Step-by-step explanation:

3(x-4)= -21

x - 4 = -7( to get this divide both sides of the equation by 3 )

x = -7 + 4 ( add 4 to both sides of the equation)

x = -3 ( then add -7 and 4 to get -3)

So clearly x = -3

HOPE THIS HELPED

Answer:

$ 21

Step-by-step explanation:

Money spent = (2/5) * 60 + (1/4) * 60

                      = 2*12 + 1*15

                      = 24 + 15

                      = $ 39

Money save = 60 - 39 = $ 21

True, Reinforcement Learning (RL) with linear function approximation may not work effectively on environments having a continuous state space.

The reason behind this is the complexity and high dimensionality of continuous state spaces, which often makes it difficult for a linear function to capture the underlying structure of the environment accurately.
Linear function approximation involves using a linear combination of features to estimate the value function or the optimal policy in RL. While this approach works well for discrete state spaces and simple problems, it struggles to handle continuous state spaces where the relationships between states and actions are more complex and nonlinear.
In such environments, a more sophisticated function approximation technique, such as neural networks or kernel-based methods, might be required to learn and generalize from continuous state spaces effectively. These methods can capture nonlinear relationships, enabling better performance in challenging environments.
In summary, although RL with linear function approximation can work in some cases, it might not be effective in environments with continuous state spaces due to the complexity and high dimensionality involved. More advanced function approximation techniques are typically necessary for successful learning in such situations.

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A correlation score of 0.75 between two variables such as symptoms of anxiety and symptoms of depression indicates a strong positive relationship between these variables.

This means that as the level of symptoms of anxiety increase, there is a high likelihood that the level of symptoms of depression will also increase. Conversely, as the level of symptoms of anxiety decreases, the level of symptoms of depression is likely to decrease as well.

It's important to note that correlation does not imply causation, meaning that just because there is a strong positive correlation between two variables, it doesn't necessarily mean that one variable causes the other. Further research would be needed to establish any causal relationship between symptoms of anxiety and symptoms of depression.

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Answer:

C. Log base b (a) - Log base b (d)

Step-by-step explanation:

In logarithm, log means index or exponent. It can be explained with following example. Consider 2^5 = 32

here index = log = 5 so you can write the log of 32 = 5

Consider 64/16 = 4

now 64 = 2^6 and 16 = 2^4

We can write log 2(64) = 6 and log2(16)=4

Now log 64/16= log 4= 2

Also log2(64)-log2(16)=6-4=2

Therefore

Log base b (a/d) = Log base b (a) - Log base b (d)

To complete 4 whole numbers using the fractions 2/3 and 13/7, a total of 31/21 is needed.

To determine how much is needed to complete 4 whole numbers using the fractions 2/3 and 13/7, we need to find the sum of these fractions and subtract it from 4.

First, we need to find a common denominator for the fractions. In this case, the least common multiple (LCM) of 3 and 7 is 21.

We convert the fractions to have the same denominator:

(2/3) x (7/7) = 14/21

(13/7) x (3/3) = 39/21

Now we add the fractions:

14/21 + 39/21 = 53/21

We subtract this sum from 4 whole numbers:

4 - 53/21

To perform this subtraction, we need to have the same denominator:

4 = (4/1) x (21/21) = 84/21

We subtract the fractions:

84/21 - 53/21 = 31/21

Therefore, to complete 4 whole numbers using the fractions 2/3 and 13/7, a total of 31/21 is needed.

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Reason:

If (x^2-c)/(x-b) = x+b, then we can rearrange things into this:

x^2-c = (x-b)(x+b)  = x^2-b^2

I'm using the difference of squares rule.

Comparing terms, we see that b^2 = c.

If b is an integer, then c is a perfect square.

Of the answer choices listed, only 4 is a perfect square.

Answer:

Step-by-step explanation:

If the figure is a parallelogram then the angles opposite one another are equal

2x - 30 = x + 40                    Subtract x from both sides.

2x - x - 30 = x - x + 40         Combine

x - 30 = 40                             Add 30 to both sides

x - 30 + 30 = 40 + 30           Combine

x = 70

The probability that an employee has an MBA and gets a promotion as decribed is; 0.34.

According to the question;

The problem statements means that the employee not only has an MBA, but gets a promotion too.

Hence, The required probability is given as;

P = 0.34

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The solutions to the quadratic equation f(x) = x² + 10x - 1 are x = -5 + √26 and x = -5 - √26

To solve the quadratic equation f(x) = x² + 10x - 1

we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, a = 1, b = 10, and c = -1.

Substituting these values into the quadratic formula:

x = (-(10) ± √((10)² - 4(1)(-1))) / (2(1))

= (-10 ± √(100 + 4)) / 2

= (-10 ± √104) / 2

Simplifying further:

x = (-10 ± 2√26) / 2

= -5 ± √26

Therefore, the solutions to the quadratic equation f(x) = x² + 10x - 1 are:

x = -5 + √26 and x = -5 - √26

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Answer:

1) y=2x-4

2) y=1/4x+2

The value of tan A is equal to 4/3.

In order to determine the magnitude of tan A, we would apply the law of tangent because the given side lengths represent the adjacent side and opposite side of a right-angled triangle.

tan(θ) = Opp/Adj

Where:

Based on the information provided in the image, we can logically deduce the following parameters:

Adj = 3 units.

Opp = 4 units.

Substituting the parameters into the tangent ratio formula, we have the following;

TanA = 4/3

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Step-by-step explanation:

impossible event or a probablity of 0

Answer:

0.20

Step-by-step explanation:

add them all up figure out how much is left till you get to 1.00

There are 26 automobiles and 13 vans available for the field excursion.

An algebraic equation, also known as a polynomial equation, is a mathematical equation of the form P=0, where P is a polynomial with coefficients in some field, most commonly the field of rational numbers. A mathematical statement that expresses the connection between two values is simply characterized as an equation. In an equation, the two values are usually equated by an equal sign. Linear equations are first-order equations. Lines in the coordinate system are determined by linear equations. A linear equation in one variable is defined as an equation with a homogeneous variable of degree 1 (i.e. only one variable). A linear equation can include several variables.

Here,

If c represents the number of cars and v represents the number of vans,

5c+8v=234

c=2v

10v+8v=234

v=234/18

v=13 vans

c=26 cars

The number of cars for field trip is 26 and number of vans is 13.

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The total number of plates of bagel Mr.Coretti will have is 7 and would need two more bagels to fill the last one up.

We have 8 dozen bagels, or 8×12=96 bagels.  

Each plate can hold 14 bagels, so we have enough bagels to fill ⇒96/14=about 6.86 plates.

However, we cannot have a fraction of a plate, so we round up to have a total of seven plates.

 To fill all seven plates fully, 7×14=98 bagels would be needed, which is two more than we have.

To summarize, Mr. Corsetti has seven plates of bagels, and would need two more bagels to fill the last one up.

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The Matlab & Simulink model consists of a Clock block to generate a time signal, a Gain block to multiply the time signal by 2, and a Differential Equation block to solve the given differential equation. The Scope block is used to visualize the behavior of the variable x over time.

To construct a Matlab & Simulink model for the given mathematical model, we can use Simulink's Differential Equation block and a Clock and Gain block. Here's a step-by-step guide:

1. Open Simulink in Matlab.

2. Drag and drop a Clock block from the Simulink Library Browser into the model.

3. Drag and drop a Gain block from the Simulink Library Browser into the model.

4. Double-click on the Gain block and set the Gain value to 2.

5. Drag and drop a Differential Equation block from the Simulink Library Browser into the model.

6. Double-click on the Differential Equation block and enter the equation `d²x + 3 + 4*x + 6 = 5*cos(2*t)`.

7. Connect the output of the Clock block to the input of the Gain block, and the output of the Gain block to the input of the Differential Equation block.

8. Connect the output of the Differential Equation block to a Scope block from the Simulink Library Browser.

9. Run the simulation.

The Scope block will show the behavior of the value of x over time according to the given mathematical model.

In conclusion, The Clock block provides the independent variable t, and the Differential Equation block evaluates the given equation to compute the value of x. The simulation shows the dynamic response of x as influenced by the equation and the time signal.

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Answer:

sinA = 3/5 cosA = 4/5 tanA =3/4

Step-by-step explanation:

SinA = Opposite/Hypotenuse

CosA= Adjacent/Hypotenuse

TanA = Opposite/Hypotenuse

soh, cah, toa.

We have the next numbers on the spinner:

1,2,3,4

Now, the prime numbers are:

2,3

Hence, the probability to get a primer number is:

P( prime number) = # of prime numbers/ total # on the spinner.

Then,

P( prime number) = 2/4 = 1/2

Now, the divisor of 14:

1,2

Hence, the probability to get a divisor of 14 is:

P( divisor of 14) = # of divisor / total # on the spinner.

Replacing:

P( divisor of 14) = 2/4 = 1/2

P(prime and divisor of 14) = 1/4

Finally, we need to find the probability of:

P( prime or divisor of 14) = P( prime number)+ P( divisor of 14) - P(prime and divisor of 14) = 1/2 +1/2 -1/4= 3/4 =0.75*100 = 75%

Hence, the P( prime or divisor of 14) is 75%.

Answer:

4^6 number of horses

Step-by-step explanation:

(4^2)^3x 4^o

4^6*4^0

4^6*1

4^6

Answer:

0 20

Step-by-step explanation:

x2 + y2 = r2 , and this is the equation of a circle of radius r whose centre is the origin O(0, 0). The equation of a circle of radius r and centre the origin is x2 + y2 = r2 .

The value of determinant of the matrix det (AB) is 15.

Given matrices A and B are 3 by 3 matrices with

det (A) = 3 and

det (b) = 5.

We need to find the value of det (AB).

Writing the given matrices into the augmented matrix form gives [A | I] and [B | I] respectively.

By multiplying A and B, we get AB. Similarly, by multiplying I and I, we get I. We can then write AB into an augmented matrix form as [AB | I].

Therefore, we can solve the augmented matrix [AB | I] by row reducing [A | I] and [B | I] simultaneously using elementary row operations as shown below.


The determinant of AB can be calculated as det(AB) = det(A) × det(B)

= 3 × 5

= 15.

Conclusion: The value of det (AB) is 15.

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We need to find the value of determinant det(AB), using the formula: det(AB) = det(A)det(B)

=> det(AB) = 3 × 5

=> det(AB) = 15.

Hence, the value of det(AB) is 15.

The given matrices are A and B. Here, we need to determine the value of det(AB). To calculate the determinant of the product of two matrices, we can follow this rule:

det(AB) = det(A)det(B).

Given that: det(A) = 3

det(B) = 5

Now, let C = AB be the matrix product. Then,

det(C) = det(AB).

To evaluate det(C), we have to compute C first. We can use the following method to solve the augmented matrix by elementary row operations.

Given matrices A and B are: Matrix A and B:

[A|B] = [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0][A|B]

= [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0].

We can see that the coefficient matrix is an identity matrix. So, we can directly evaluate the determinant of A to be 3.

det(A) = 3.

Therefore, det(AB) = det(A)det(B)

= 3 × 5

= 15.

Conclusion: Therefore, the value of det(AB) is 15.

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According to the question the absolute minimum of \(\( f(x, y) \)\) is 2, and the absolute maximum is 16.

To find the absolute minimum and maximum of the function \(\( f(x, y) = x^2 - xy + y^2 - 4x + 4y \)\) over the region \(\( x^2 + y^2 \leq 16 \),\) we need to consider the critical points and the boundary of the region.

First, let's find the critical points by taking the partial derivatives of \(\( f(x, y) \)\) with respect to \(\( x \) and \( y \)\) and setting them equal to zero:

\(\(\frac{\partial f}{\partial x} = 2x - y - 4 = 0\)\)

\(\(\frac{\partial f}{\partial y} = -x + 2y + 4 = 0\)\)

Solving these equations simultaneously, we find that the critical point is \(\((x, y) = (2, -2)\).\)

Next, we need to examine the boundary of the region \(\( x^2 + y^2 \leq 16 \),\) which is the circle centered at the origin with a radius of 4. We can parameterize the boundary of this circle as follows:

\(\(x = 4\cos(t)\)\)

\(\(y = 4\sin(t)\)\)

where \(\(0 \leq t \leq 2\pi\).\)

Substituting these expressions into \(\(f(x, y)\),\) we get:

\(\(f(t) = (4\cos(t))^2 - (4\cos(t))(4\sin(t)) + (4\sin(t))^2 - 4(4\cos(t)) + 4(4\sin(t))\)\)

Simplifying further:

\(\(f(t) = 16\cos^2(t) - 16\cos(t)\sin(t) + 16\sin^2(t) - 16\cos(t) + 16\sin(t)\)\)

We can now find the maximum and minimum values of \(\(f(t)\)\) by evaluating it at the critical point \(\((2, -2)\)\) and the endpoints of the parameterization \(\(t = 0\) and \(t = 2\pi\).\)

Evaluating \(\(f(2, -2)\),\) we get:

\(\(f(2, -2) = 2^2 - 2(-2) + (-2)^2 - 4(2) + 4(-2) = 2\)\)

Next, let's evaluate \(\(f(t)\) at \(t = 0\):\)

\(\(f(0) = 16\cos^2(0) - 16\cos(0)\sin(0) + 16\sin^2(0) - 16\cos(0) + 16\sin(0) = 16\)\)

And finally, let's evaluate \(\(f(t)\) at \(t = 2\pi\):\)

\(\(f(2\pi) = 16\cos^2(2\pi) - 16\cos(2\pi)\sin(2\pi) + 16\sin^2(2\pi) - 16\cos(2\pi) + 16\sin(2\pi) = 16\)\)

Therefore, the absolute minimum of \(\(f(x, y)\)\) is 2, and the absolute maximum is 16.

Hence, the absolute minimum of \(\( f(x, y) \)\) is 2, and the absolute maximum is 16.

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15/19 + 14/19 = 29/19

Step-by-step explanation:

Add the number of balls in the basket together.

Subtract the number of white balls from the sample space ( the total amount of balls) your answer is written over the sample space and the same process is done for the green ball

We have shown that the expression is equal to 0.

To show that the given expression is equal to 0, we can simplify it algebraically. First, we can substitute 0 for the value of sin(θ0) in the expression. This results in:

0 sin θ0 √(0 sin θ0 )^2 2ℎ

Next, we can simplify the expression under the square root by squaring 0 sin(θ0), which results in:

0 sin θ0 √0 2ℎ

The square root of 0 is equal to 0, so the entire expression becomes:

0 * sin(θ0) * 0 / 2ℎ = 0

Therefore, we have shown that the expression is equal to 0. This result indicates that there is no contribution to the value of the expression from the terms in the numerator and denominator, and it is entirely dependent on the constant value of 0.

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Answer:

\(10 \sqrt{5} \ x^2y^3\sqrt{y}\)

Step-by-step explanation:

simplify \(2\sqrt{125x^4y^7}\)

Apply radical rule \(\sqrt{ab} =\sqrt{a} \sqrt{b}\):

\(\implies 2\sqrt{125}\sqrt{x^4}\sqrt{y^7}\)

\(\implies 2 \cdot 5 \sqrt{5}\sqrt{x^4}\sqrt{y^7}\)

\(\implies 10 \sqrt{5}\sqrt{x^4}\sqrt{y^7}\)

Apply radical rule \(\sqrt[n]{a^m} =a^{\frac{m}{n}}\):

\(\implies 10 \sqrt{5} \ x^{\frac42}y^{\frac72}\)

\(\implies 10 \sqrt{5} \ x^2y^3\sqrt{y}\)

Answer:

\(7x^{2}\sqrt{5y^{7} }\)

Step-by-step explanation:

First, we'll start by simplifying \(\sqrt{125}\).  2 factors of 125 are 5 and 25, and since 25 is a perfect square, that can be taken out of the radicand and added to the 2 that's already outside of it, creating \(7\sqrt{5x^{4}y^{7}}\).

x to the power of 4 can be simplified to x squared and taken out of the radicand along with that 7, so:

\(7x^{2}\sqrt{5y^{7} }\)

y to the power of 7 is a bit trickier to solve, so I left it like this, because I think it's the simplest version, but if this isn't an option then simplify further by working on the y.  

I hope this helps :)  

Answer:

A

Step-by-step explanation:

root of 49 is 7

as we know 7 * 7 is 49

also -7 * -7 is 49

so yeah that's the r8 answer

The number of centimetres in the 1 yard will be 9.144 cm.

Multiplication or division by a numerical factor, selection of the correct number of significant figures, and unit conversion are all steps in a multi-step procedure.

Given that:-

Metric System Units

1 inch = 2.54 centimetres

1 foot = 0.3048 meters

1 mile = 1.61 kilometres

1 yard = 3 feet

1 yard = 36 inches

First, we will calculate 1 yard to feet.

1 yard = 3 feet

1 feet = 0.3048 meters

1 feet = 3.048 centimeters

1 yard = 3 x 3.048 centimeters

1 yard = 9.144 centimeters

Hence, the length of 1 yard in cm is 9.144 cm.

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By using the vertex of the quadratic equation, we will get the equation:

y = -2*(x + 6)^2

For a quadratic equation with a leading coefficient "A" and a vertex (h, k), the equation can be written as:

y = A*(x - h)^2 + k

Here we can see that the vertex is (-6, 0), so we have:

y = A*(x + 6)^2

We also can see that the parabola passes through the point (-4, -8), replacing these values above we will get:

-8 = A*(-4 + 6)^2

-8 = A*(2)^2

-8 = 4A

-8/4 = A

-2 = A

Then the quadratic equation is:

y = -2*(x + 6)^2

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The statement “there exists a function f such that f(x) < 0, f’(x) > 0, and f”(x) < 0 for all x” is false.

To understand why this statement is false, we must first understand what the symbols mean. The symbol f(x) refers to a function of x, and the symbols f’(x) and f”(x) refer to the first and second derivatives of the function, respectively.

The statement is saying that for all x, the function f(x) will be less than 0, the first derivative f’(x) will be greater than 0, and the second derivative f”(x) will be less than 0.

To show that this statement is false, we need to find an example of a function where this is not the case. Let’s consider the function f(x) = x³. At x = 0, this function is equal to 0, and so f(x) < 0 is not true. Additionally, the first derivative at x = 0 is f’(0) = 0, which is not greater than 0. Thus, the statement is false.

We can also show that this statement is false by looking at the graph of the function f(x). A function with the properties given in the statement would have a graph that looks like a “U” shape, with a minimum point at the origin. However, this is not the case for the function f(x) = x³. The graph of this function is a parabola, which does not have the desired shape.

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