Mahesh can cut out 16 full circles from the cardboard.
To find the number of full circles that can be cut out from the cardboard, we need to calculate the maximum number of circles that can fit within the dimensions of the cardboard.
First, we convert the dimensions of the cardboard to centimeters and find the area:
Length = 6 1/4 cm = 6.25 cm
Width = 3 3/4 cm = 3.75 cm
Area of cardboard = Length x Width = 23.4375 cm²
Next, we find the area of each circle using the formula A = πr² where r = 3/4 cm:
A = π(3/4)² = 1.767 cm²
Finally, we divide the area of the cardboard by the area of each circle to find the maximum number of circles that can be cut out:
Number of circles = Area of cardboard / Area of each circle = 13.25
Since we can only have whole circles, the maximum number of full circles that can be cut out is 16.
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Scores on the verbal ability portion of the GRE follow a normal distribution with a mean of 600 and standard deviation of 75. 1. Between what two values do the middle 95% of scores fall?
2. If your score is 665, you did better than what percentage of exam takers? 3. What is the probability of a score being between 575 and 620?
2. Tthe probability of a score being between 575 and 620 is approximately 0.2345 or 23.45%.
1. To find the values between which the middle 95% of scores fall, we need to find the z-scores corresponding to the 2.5th and 97.5th percentiles of the standard normal distribution. These percentiles correspond to the critical values that enclose the middle 95% of the distribution.
The z-score corresponding to the 2.5th percentile is -1.96, and the z-score corresponding to the 97.5th percentile is 1.96.
To find the actual score values, we can use the formula:
Score = Mean + (z-score * Standard Deviation)
Lower Score = 600 + (-1.96 * 75)
≈ 450
Upper Score = 600 + (1.96 * 75)
≈ 750
Therefore, the middle 95% of scores fall between approximately 450 and 750.
2. To determine the percentage of exam takers who scored below 665, we need to find the cumulative probability of the z-score corresponding to 665.
Z-score = (Score - Mean) / Standard Deviation
Z-score = (665 - 600) / 75
= 0.8667
Using a standard normal distribution table or a calculator, we can find that the cumulative probability to the left of a z-score of 0.8667 is approximately 0.8078.
Therefore, you did better than approximately 80.78% of exam takers.
3. To find the probability of a score being between 575 and 620, we need to calculate the cumulative probability for both z-scores.
For a score of 575:
Z-score = (575 - 600) / 75
= -0.3333
Cumulative Probability = 0.3707
For a score of 620:
Z-score = (620 - 600) / 75 = 0.2667
Cumulative Probability = 0.6052
To find the probability between the two scores, we subtract the cumulative probability of the lower score from the cumulative probability of the higher score:
Probability = 0.6052 - 0.3707
= 0.2345
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I need help with this please
Answer:
x=21 interior angle =150 exterior angle=210
Step-by-step explanation:
to find the angle rule=(n-2)×180
n is the number of sides in the polygon
(12-2)×180=1800
1800/12=150 (this is the interior angle)
7x+3=150
x=21
exterior angle = 360-150=210
k/3+16 algebraic expression
Answer: -48
Step-by-step explanation:
k/3 + 16
find the roots by factoring
which leads to -48
k/3 + 16
To add or subtract expressions, expand them so their denominators are the same. Multiply 16 by 3/3.
k/3 + 16 × 3/3
Since k/3 and 16 × 3/3 have the same denominator, we join their numerators to add them.
k + 16 × 3/3
We perform the multiplications in k+16×3.
k + 48/3
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an oblique prism has a volume of 144 cubic units. the area of its base is 24 square units. what is the perpendicular height of the prism? a.2 units b.4 units c.units d.8 units
The perpendicular height of the given oblique prism is 6 units. The answer is not one of the options given, but it is closest to option :
(d) 8 units
We can use the formula for the volume of an oblique prism, which is:
V = Bh, where B is the area of the base and h is the perpendicular height.
We are given that the volume is 144 cubic units and the area of the base is 24 square units. Substituting these values into the formula, we get:
144 = 24h
Simplifying, we can divide both sides by 24:
h = 6
Therefore, the perpendicular height of the prism is 6 units. The answer is not one of the options given, but it is closest to option d, which is 8 units.
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Triangle QRS is transformed as shown on the graph. Which rule describes the transformation?
Answer:
270°
Step-by-step explanation:
(x , y) --> (y, -x)
90° clockwise rotation
270° anti-clockwise rotation
Use the frequency distribution to complete parts (a) through (e) a) Determine the total number of observations. b) Determine the width of each class. c) Determine the midpoint of the second class. d) Determine the modal class (or classes). e) Determine the class limits of the next class if an additional class were to be added. Class 6-15 16 - 25 26 - 35 36 - 45 46-55 56 - 65 Frequency 4 8 8 9 3 3 a) The total number of observations is b) The width of each class is c) The midpoint of the second class is (Type an integer or a decimal.) d) The modal class(es) is/are (Use a hyphen to separate the limits of a class. Use a comma to separate answers. Type the classes in order fr Enter your answer in each of the answer boxes.
Using the frequency distribution, a) The total number of observations is 35. b) The width of each class is 9. c) The midpoint of the second class is 20.5. d) The modal classes are class 36-45 and class 26-35. e) The class limits of the next class would be 66-75.
a) To determine the total number of observations, we need to sum up the frequencies of all the classes. In this case, the total number of observations is:
4 + 8 + 8 + 9 + 3 + 3 = 35
Therefore, there are a total of 35 observations.
b) The width of each class can be calculated by taking the difference between the upper and lower class limits. For example, the width of the first class (6-15) is 15-6 = 9.
Similarly, the width of the other classes can be calculated as follows:
Class 6-15 : width = 15-6 = 9
Class 16-25 : width = 25-16 = 9
Class 26-35 : width = 35-26 = 9
Class 36-45 : width = 45-36 = 9
Class 46-55 : width = 55-46 = 9
Class 56-65 : width = 65-56 = 9
Therefore, the width of each class is 9.
c) The midpoint of a class can be calculated by taking the average of the upper and lower class limits. For example, the midpoint of the second class (16-25) can be calculated as:
Midpoint = (16+25)/2 = 20.5
Therefore, the midpoint of the second class is 20.5.
d) The modal class is the class with the highest frequency. In this case, we can see that two classes have the same highest frequency of 9: class 36-45 and class 26-35. Therefore, both of these classes are modal classes.
e) To determine the class limits of the next class if an additional class were to be added, we need to consider the current width of the classes, which is 9.
Therefore, if we want to add a class after the last class (56-65), the lower limit of the next class would be 66, and the upper limit would be 75. Therefore, the class limits of the next class would be 66-75.
In conclusion, frequency distribution is a useful tool to organize and summarize data by grouping them into classes.
It provides information on the total number of observations, width of each class, midpoint of a class, modal class, and can even help in determining the class limits of an additional class.
Understanding frequency distributions can help in making decisions, analyzing trends, and drawing conclusions in various fields such as business, economics, psychology, and more.
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the sides of a triangle are 13ft 15ft and 11 ft find the measure of the angle opposite the longest side
The measure of the angle opposite the longest side is approximately 56.32 degrees.The measure of the angle opposite the longest side of a triangle can be found using the Law of Cosines.
In this case, the sides of the triangle are given as 13 ft, 15 ft, and 11 ft. To find the measure of the angle opposite the longest side, we can apply the Law of Cosines to calculate the cosine of that angle. Then, we can use the inverse cosine function to find the actual measure of the angle.
Using the Law of Cosines, the formula is given as:
\(c^2 = a^2 + b^2 - 2ab * cos(C)\)
Where c is the longest side, a and b are the other two sides, and C is the angle opposite side c.
Substituting the given values, we have:
\(13^2 = 15^2 + 11^2 - 2 * 15 * 11 * cos(C)\)
169 = 225 + 121 - 330 * cos(C)
-177 = -330 * cos(C)
cos(C) = -177 / -330
cos(C) ≈ 0.5364
Using the inverse cosine function, we find:
C ≈ arccos(0.5364) ≈ 56.32 degrees
Therefore, the measure of the angle opposite the longest side is approximately 56.32 degrees.
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The following system of linear equations is shown in the graph.
y=1/4x+5
x-4y=4
How many solutions does the system of linear equations have?
A. No solution
B. Infinitely many solutions
C. One solution at (4,0)
D. One solution at (0,-1)
Answer:
Step-by-step explanation:
The slopes of both those lines are the same so there is no solution. Use slope triangles to find out the slope. They are both 1/4.
A. No solution
y = 1/4x+5
x - 4y = 4
You can simplify the second equation into y = 1/4x - 1
Since these equations both have the same slope, they are parallel. When two lines are parallel, they have no solutions.
HELP WILL MARK AS BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Sandy bought a car for $17,500. Her monthly car payment is $346. The first month the amount applied to the principal is $283 and the interest amount is $63 Assume that each month the amount applied to the principal increases by $1 and the interest amount decrease by $1 Which spreadsheet shows the amount of interest she paid in the six months?
Answer:
I'm not quite sure how to point to which graph exactly, but I will tell you that it is the one that principal increases by one for six months, and interest decreases. It has "Month, Principal, Interest, and Total" written across the top in bold. Down the left-hand side, it has numbers 1-6. On the bottom, the first total is $363, and the second is $2076.
Step-by-step explanation:
There is very limited math involved in this question. The first step is to find a graph where each month, the principal number increases by one dollar and the interest decreases by one dollar. This should go on for six months. We can now eliminate two graphs. For a third, you must remember that the interest starts in the sixty, and the principal payment is in the two hundred eighties. By now, we have our graph. The final step to double-check this is to add up the total interest and principal (which should be on the side). All totals should be $346 as we're basically just trading one number for another (-1+1). You should also go to the bottom and fill in the blank in the principal column. In this box, you should put the total of all principals together.
Hope this helps!
Find the area of the region enclosed by one loop of the curve. r = sin(2θ)
The area of the region enclosed by one loop of the curve r = sin (2θ) is given by 1 square unit.
Given the polar equation is,
r = sin (2θ)
The graph of the given polar equation is given by,
when r = 0 then, sin (2θ) = 0
2θ = 0, π, 2π, 3π, .....
θ = 0, π/2, 2π/2, 3π/2, ..... = 0, π/2, π, 3π/2, ....
So the loop is created for each 0 < θ < π/2.
So the area of the one loop using integration is given by
= \(\int_0^{\frac{\pi}{2}}\) r dθ
= \(\int_0^{\frac{\pi}{2}}\)sin 2θ dθ
= [- cos 2θ/2] from 0 to π/2
= (1/2) [- cos (2 (π/2)) + cos (2*0)]
= (1/2) [- cos π + cos 0]
= (1/2) [- (-1) + 1]
= 1 square units.
Hence the required area is 1 square units.
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Can someone solve 3y − 3 = 2y + 6
step by step
Like the example below
Answer:
y = 9
Step-by-step explanation:
3y − 3 = 2y + 6
3y - 2y = 6 + 3
y = 9
I hope this is detailed enough for you :)
James and Sylvie need to paint the line around the outside of a soccer field. To know how much paint to buy, they must find the perimeter of the field. James claims, “I can calculate the perimeter by using the formula P = 2(l + w) .” Sylvie replied, “That’s not right. The correct formula is
P = 2l + 2w .” Who is correct? Provide evidence to support your answer.
Answer:
Both of them are correct.
The perimeter is found by adding up all four sides. If you notice, one of them is width and one of them is length. A rectangle has four sides, two width and two length.
l= length and w=width so P=2l+2w.
But, we can combine them by factorizing 2l+2w.
Lets see what we can pull out. We can only pull out 2.
2(l+w)=2l+2w.
2(l+w)=P
Both of them are correct.
Hope this helps plz hit the crown :D
can someone help with this one im confused.
Answer:
C
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
what type of graph or chart is used to compare relative parts of a whole?
A pie chart is commonly used to compare relative parts of a whole. It is a circular chart that is divided into sectors, where each sector represents a proportionate part of the whole.
The size of each sector is proportional to the value it represents, and the whole circle represents the total value. Pie charts are frequently used in business, finance, and statistics to show the relative sizes of different categories or data points. They are easy to understand and can quickly convey complex information in a simple visual format. However, it's important to note that pie charts are not always the most effective way to display data and should be used appropriately depending on the type of data being presented.
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A trapezoid has 21 inches base and 5.3 inches base, as well as 39 inches height. What is the area?
Answer:
It is 512.85
Step-by-step explanation:
A = \(\frac{a+b}{2}\)h = \(\frac{21 + 5.3}{2}\).39 = 512.85
It is 512.85
21*5.3*39=512.85
Your mother gave you $15.80 with which
to buy a present. This covered of the
2
3
cost. How much did the present cost?
Answer: it cost 14 dollars
Step-by-step explanation:
For some transformation kinetics that obey the Avrami equation, the parameter n is known to
have a value of 1.2.
a) If it takes 180 seconds for the transformation to go to 90% completion, determine the
parameter, k.
b) Determine the rate of transformation, r.
a) Using the Avrami equation with n = 1.2 and 90% completion in 180 seconds, the parameter k is found to be approximately 0.00397. b) The rate of transformation, r, is approximately 0.0367 per second.
a) The Avrami equation is given by the equation t = k * (1 – exp(-r^n)), where t is the transformation time, k is a parameter, r is the rate of transformation, and n is a constant (in this case, n = 1.2). Given t = 180 seconds and the transformation is 90% complete, we can rearrange the equation to solve for k: k = t / (1 – exp(-r^n)). By substituting the values, we find k ≈ 0.00397.
b) To determine the rate of transformation, we can rearrange the Avrami equation and solve for r: r = (-ln(1 – (t / k)))^(1/n). Plugging in the values t = 180 seconds and k ≈ 0.00397, and n = 1.2, we can calculate r ≈ 0.0367 per second. This represents the rate at which the transformation progresses per unit time.
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Jackie is selling donuts and cookies to raise money for her school trip. The donuts sell for $8 a box and the cookies sell for $6 a box. She needs to raise more than $600. If she wants to sell at least twice as many cookies than donuts, what is the minimum number of cookies she must sell?
Answer:
16$ liam you can get a shout at
Please help with Algebra we are doing elimination using multiplication
Question: Laura and Brent paddled a canoe 6 miles up stream in four hours. The return trip took three hours. Find the rate at which Laura and Brent paddled the canoe in still water.
The answer is supposed to look something like this (x, y)
The rate at which Laura and Brent paddled the canoe in still water is (7/9, 2/3).
Speed is a measure of how quickly an object moves or the rate at which it covers a certain distance in a given amount of time. It is a scalar quantity, meaning it has magnitude but no specific direction unless combined with a vector quantity like velocity.
Speed is a fundamental concept in physics and plays a crucial role in understanding motion, transportation, sports, and various other areas. It helps describe how fast objects move and allows for comparisons of different velocities or rates of motion.
Let the speed of the canoe be x in still water and the speed of the current be y.
When going upstream, the speed of the canoe is x - y. When going downstream, the speed of the canoe is x + y.
Distance = Speed × Time
According to the question,
6 = 4(x - y) 6 = 3(x + y)
Simplifying these equations, we get:
4x - 4y = 3x + 3y x = 7y/6
Multiplying by 2:
12 = 8(x - y) 12 = 6(x + y)
Simplifying these equations, we get:
8x - 8y = 6x + 6y 2x = 7y x = 7y/2
We can equate the two expressions for x to get:
7y/6 = 7y/2 1/6 = 1/2 - y/2 y/2 = 1/3 y = 2/3
Substituting this value of y into x = 7y/6, we get:
x = 7(2/3)/6 = 7/9
Therefore, the rate at which Laura and Brent paddled the canoe in still water is (7/9, 2/3).
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In ABC , sin A = 2/3, sin B = 4/5 and side a = 20. Find side b.
Answer:
Side b = 24
Step-by-step explanation:
Refer to the picture below
Lonell wants to share a box of chocolate chip cookies equally with his study group. He wants to give of the cookies to each member of the group. The box has 27 chocolate chip cookies. Which equation could Lonell use to find how many chocolate chip cookies each member of the study group will get?
Answer:
27÷ x=?
Step-by-step explanation:
if yuu want to share 27 cookies equally you have to kno the number of members in that case that number is "x" nd yuu have to divide
what is an interval notation in math to find the function domain and range
Interval notation is a mathematical notation used to represent intervals or sets of numbers. It is commonly used to describe the domain and range of a function. The interval notation consists of using brackets or parentheses to indicate whether the endpoints are included or excluded, and using commas or union symbols to separate different intervals within a set.
In interval notation, a closed interval is represented by using square brackets [ ], indicating that the endpoints are included. For example, [a, b] represents the interval that includes all numbers from a to b, including both endpoints.
An open interval is represented by using parentheses ( ), indicating that the endpoints are excluded. For example, (a, b) represents the interval that includes all numbers between a and b, excluding both endpoints.
A half-open or half-closed interval includes one endpoint but not the other, and is represented by using one bracket and one parenthesis. For example, [a, b) represents the interval that includes all numbers from a to b, including a but excluding b.
To describe a set of intervals or a range of a function, we can use union symbols (∪) to combine the intervals. For example, (a, b) ∪ [c, d] represents the set that includes all numbers between a and b, excluding both endpoints, as well as all numbers from c to d, including both endpoints.
By using interval notation, we can concisely and precisely represent the domain and range of a function or describe sets of numbers in a clear and compact manner.
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Interval notation is a mathematical notation used to represent intervals or sets of numbers. It is commonly used to describe the domain and range of a function. The interval notation consists of using brackets or parentheses to indicate whether the endpoints are included or excluded, and using commas or union symbols to separate different intervals within a set.
In interval notation, a closed interval is represented by using square brackets [ ], indicating that the endpoints are included. For example, [a, b] represents the interval that includes all numbers from a to b, including both endpoints.
An open interval is represented by using parentheses ( ), indicating that the endpoints are excluded. For example, (a, b) represents the interval that includes all numbers between a and b, excluding both endpoints.
A half-open or half-closed interval includes one endpoint but not the other, and is represented by using one bracket and one parenthesis. For example, [a, b) represents the interval that includes all numbers from a to b, including a but excluding b.
To describe a set of intervals or a range of a function, we can use union symbols (∪) to combine the intervals. For example, (a, b) ∪ [c, d] represents the set that includes all numbers between a and b, excluding both endpoints, as well as all numbers from c to d, including both endpoints.
By using interval notation, we can concisely and precisely represent the domain and range of a function or describe sets of numbers in a clear and compact manner.
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Alice has 14 baseball cards. Jason has twice as many card as Alice. Tom has 6 fewer cards than Alice . How many baseball cards do Alice , Jason , and Tom have altogether.
Answer:
50 cards
Step-by-step explanation:
Alice = 14 cards
Jason = 14 x 2 or 28
Tom = 14 - 6 or 8
Simplify: 1/6x + 42 + 2/5x - 8/3 -19
A: 97/30x + 23
B: 21/10x - 23
C: -21/10x + 23
D: 97/30x - 23
Answer:
A: 97/30x + 23
what is 4 fiths plus one third
Answer:
17/15 or 1 2/15
Step-by-step explanation:
Answer:
\(1 \frac{2}{15}\)
0.85m + 7.5 = 12.6
find m plsss <33
Answer:
m=6
Step-by-step explanation:
0.85m+7.5=12.6
0.85m=12.6-7.5
0.85m=5.1
m=6
Hope this helps!
\( \rm0.85m + 7.5 = 12.6\)
\( \rm0.85m= 12.6 - 7.5\)
\( \rm0.85m= 5.1\)
\( \rm \: m= 6\)
valve guides can be measured for roundness and diameter using what type of tool
Valve guides can be measured for roundness and diameter using a micrometer or a bore gauge. Both of these tools are commonly used in the automotive industry to measure the dimensions of engine parts such as valve guides.
A micrometer is a precision measuring tool that uses a calibrated screw to measure the diameter of an object with high accuracy. It can be used to measure the diameter of the valve guide at different points along its length to check for roundness. A bore gauge, also known as an inside micrometer, is a specialized tool used to measure the inside diameter of a cylinder, such as the bore of an engine block or the valve guide. It consists of a probe that is inserted into the cylinder and expands to take a measurement. A bore gauge is particularly useful for measuring the internal dimensions of complex shapes like valve guides, which can have irregular or non-circular profiles. Both micrometers and bore gauges come in various sizes and types, and the specific tool used will depend on the size and shape of the valve guide being measured.
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Calcula el perímetro y el área de un hexágono de 4 metros de lado y 3.46 m de apotema
Answer:
\(P=24\: m\)
\(A=41.52 \m^{2}\)
Step-by-step explanation:
El perímetro de un hexágono se calcula de la siguiente manera:
\(P=6*l\)
l es el lado del hexágono l = 4 m
Entonces P es:
\(P=6*4=24\: m\)
El área del hexágono puede calcularse de la siguiente manera:
\(A=\frac{P*Ap}{2}\)
P es el perímetro = 24 m
Ap es la apotema = 3.46 m
El Area sera:
\(A=\frac{24*3.46}{2}\)
\(A=41.52 \m^{2}\)
Espero te haya sido de ayuda!
Megan has a dog-sitting business. She charges an initial fee of $10 to watch the dog, plus an hourly fee of $4.
Megan watches Frenchie the bulldog for m hours. She wants to make at least $50. Write an inequality for the number of hours, m, that Megan needs to watch Frenchie for to meet her goal.
Answer:
Below
Step-by-step explanation:
Standard charge = $ 10
plus hourly charge 4 m where 'm = hours
10 + 4m needs to be at LEAST $ 50
10 + 4m ≥ 50 which can be re=arranged Subtract 10 from both sides
4m ≥ 40 now you can divide both sides by 4
m ≥ 10 hours
Expand the expression:
(3a - 2b)^3
Show complete computation.
Answer:
I have solved it and attached in the explanation.
Step-by-step explanation:
Answer:
\(27a^3-54a^2b+36ab^2-8b^3\)
Step-by-step explanation:
To expand the expression (3a - 2b)³, we can use the Perfect Cube Formula.
\(\boxed{\begin{minipage}{6 cm}\underline{Perfect Cube Formula}\\\\$(x-y)^3=x^3-3x^2y+3xy^2-y^3$\\\end{minipage}}\)
Let:
x = 3ay = 2bSubstitute the values into the formula, and use the exponent rule
\(\boxed{(xy)^n=x^n \cdot y^n}\) :
Therefore:
\(\begin{aligned}(3a-2b)^3&=(3a)^3-3(3a)^2(2b)+3(3a)(2b)^2-(2b)^3\\&=3^3 \cdot a^3-3 \cdot 3^2 \cdot a^2 \cdot 2b+3 \cdot 3a \cdot 2^2\cdot b^2-2^3\cdot b^3\\&=27a^3-3 \cdot 9 \cdot a^2 \cdot 2b+9a \cdot 4b^2-8b^3\\&=27a^3-54a^2b+36ab^2-8b^3\end{aligned}\)
So the expression (3a - 2b)³ expanded is 27a³ - 54a²b + 36ab² - 8b³.