Maggie spent $18. 00 Of $30. 00 In her wallet which decimal represents the fraction of the $30. 00 Maggie spent

Answer:

11.85

Step-by-step explanation:

Tan 28 = opposite / adjacent

Answer:

the distance from the pole is 11.85 ft.

Step-by-step explanation:

Given;

the elevation to the top of the pole, θ = 28⁰

height of the pole, h = 6.3 ft

let the distance from the pole = x

If a sketch of a right triangle is made as follows, it will be observed that the base of the triangle forms the adjacent side of the triangle, which is equal to x.

                                ↑

                                ↑ h = 6.3 ft

                                ↑

         28⁰ ---------------

                       x

\(tan(28) = \frac{6.3}{x} \\\\x = \frac{6.3}{tan(28)} \\\\x = 11.85 \ ft\)

Therefore, the distance from the pole is 11.85 ft.

Expressions represent the number of squares in step n are 1st, 2nd and 5th options.

An equation is a mathematical statement that indicates the equality of two expressions. It contains variables, constants, and mathematical operators such as addition, subtraction, multiplication, and division. Equations can be used to model and solve a wide range of problems in various fields, including physics, engineering, economics, and chemistry.

Step 1: analyze the pattern

If number of squares in each step is expressed as , f(n) then you can see the following results1

The number of squares in 1st step is, f(1)=8........(1)

In second step number of squares is increased by a number of 3. that is, f(2)=f(1) + 3...................(2)

Again in 3rd step, the number of squares increased by 3, that is,

f(3)= f(2) + 3...............(3)

    = (f(1) +3) + 3

    = f(1) + 2 × 3f(3)

    = f(1)+ 2 × 3............(4)

Step 2: make the recurrence relation

Now, from (1), (2) and (3) we can generalize the pattern for a step n such that,

f(1)=8........(1)  f(1) + 3...................(2) f(2) + 3...............(3)

f(n)= f(n-1) + 3 for n≥2

Thus, the 2nd option from the top is correct.

Step 3: find the form of f(n)

Now, from (1), (2) and (4) we can find the number of squares , for a step n such that,

f(1)=8+0×3f(2)= 8+1×3f(3)=8+2×3f(n)= 8+(n-1)×3 for n≥1

or

f(n)=8+3(n-1) for n≥1

Thus, 1st option is correct

f(n)=3n+5 for n ≥1

Thus, 5th option is also correct

Thus, 1st, 2nd and 5th options are the correct answer.

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|| ▼ Answer ▼ ||

Option (A) 4 x + 89.95 = 628.35; x = 134 dollars and 60 cents

|| ✪ Solution ✪ ||

Total cost of the trip was $628.35, Anja paid $89.95 as a flat fee, and paid extra for the four tooth fillings, the equation that represents this situation is:

\(4x+89.95=628.35-- > (1)\)

The solution to equation (1) is as follows:

\(4x=628.35-89.95=538.4\)

\(x=\frac{538.4}{4} =134.6\)

\(x=134.6\)

x = $134 and 60 cents

Conclusion: The answer is Option (a).

Hope this helps!

If you have any queries please ask.



A) Mean = 5.8

Median = 5.5

mode = 5

B) Mean = 127.5

Median = 28

mode = 11 -12 scores

3, 4, 5, 5, 5,6,6, 7, 8,9

A) Mean = 3+ 4+ 5+ 5+ 5+ 6+ 6+ 7 + 8 + 9

                                   10

Mean = 58/10

         =   5.8

3, 4, 5, 5, 5,6,6, 7, 8,9

Median = 5 + 6

                  2

Median = 11/2

             = 5.5

3, 4, 5, 5, 5,6,6, 7, 8,9

mode = 5

B) Scores           1 -10, 11- 20, 21 -30, 31-40, 41 -50

   Mid- scores    5.5,   15.5  ,  25.5  ,35.5 ,  45.5

  Frequencies    8     ,   14   ,  12     ,   9     ,  7

Mean of group data = Sum of (Interval midpoint * Freq )

                                         Total Frequency

Mean of group data =  5.5 +  15.5 + 25.5 + 35.5 + 45.5

                                                    50

Mean of group data =  127.5

Median = Calculate a running total of the frequencies - the first interval that is above half the total contains the median.

Median =  50 - ( 8 + 14)

Median = 50 - 22

            = 28

Mode = The largest frequency and the corresponding value is the modal value or modal class.

Mode = 11 -12 scores

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The complete table is

x -12 -6 3 15

y -6 5 15 15

The domain is given as:

Domain = {-12, -6, 3, 15}.

The incomplete table is given as

x

y -6 5 15 15

Enter the domain in the x values

x -12 -6 3 15

y -6 5 15 15

Hence, the complete table is

x -12 -6 3 15

y -6 5 15 15

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Jennifer needs to sample at least 151 vets to achieve a standard error of the mean of 3.42 years or less.

The variability or uncertainty of a sample statistic, like the mean or proportion, is measured by standard error. It represents the sample distribution's standard deviation for that statistic. In other words, it calculates the amount by which chance is likely to cause the sample statistic to deviate from the actual population parameter.

The calculation of the standard error is based on the particular statistic being produced as well as the characteristics of the sampled population. For instance, the population's standard deviation is divided by the square root of the sample size to determine the standard error of the mean. If p is the estimated proportion based on the sample, then the standard error of a proportion is determined as (p * (1 - p)) divided by the square root of the sample size.

A population parameter estimate that has a lower standard error is more accurate. Inferential statistics frequently employ the standard error to compute confidence intervals and test population parameter-related hypotheses.

The formula for the standard error of the mean can be used to get the approximate number of veterans Jennifer needs to sample:

\(SE = / \sqrt{n}\)

where n: sample size, delta: age standard deviation, and SE: standard error of the mean.

In this instance, we are aware that = 22 years and SE = 3.42 years. As we solve for n, we obtain:

\(n = (delta / SE)^2 n = (22 / 3.42)^2 \sn = 150.39\)

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Answer:

answer is in the photo

Step-by-step explanation:

good luck!

Let *-*-) W = ye

R³: xy + z = 0, prove that W has the stated property or use a counterexample to show that the property fails.i) W is closed under vector addition. To prove that W is closed under vector addition, we need to prove that if (x1, y1, z1) and (x2, y2, z2) belong to W, then their sum belongs to W.

This is written as (x1, y1, z1) + (x2, y2, z2) = (x1 + x2, y1 + y2, z1 + z2)To see if this vector belongs to W, we need to check if xy + z = 0.(x1 + x2) (y1 + y2) + (z1 + z2) = x1y1 + x2y2 + x1y2 + x2y1 + z1 + z2After rearranging, we get(x1y1 + x1y2 + z1) + (x2y1 + x2y2 + z2)This is the sum of two elements that are in W, so their sum belongs to W as well. Hence, W is closed under vector addition.ii) W is closed under scalar multiplication.

To prove that W is closed under scalar multiplication, we need to prove that if (x1, y1, z1) belongs to W and a is any scalar, then a (x1, y1, z1) belongs to W. This is written as a (x1, y1, z1) = (ax1, ay1, az1)To see if this vector belongs to W, we need to check if xy + z = 0. This is written as a

(x1y1) + a(z1) = a(x1y1 + z1)We need to check if this equals to 0. This is equivalent to checking if (x1y1 + z1) equals 0. But this is true, since (x1, y1, z1) belongs to W and hence satisfies xy + z = 0. Therefore, W is closed under scalar multiplication.Since W is closed under vector addition and scalar multiplication, W is a subspace of R³.

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Step-by-step explanation:

there is a (V.O.A) which is vertically opposite angle

and in the given part he himself said that there is two = angles

so there for the two third angles are equal

so we can say they are similar

A) The measure of central tendency that best describes the data for time spent on the internet (min/day) is the median.

The median is the middle value in a set of data when the data is arranged in numerical order. In this case, the data arranged in numerical order is 38, 43, 48, 52, 65, 75, 120. The median value is 52, which is the middle value in the data set.

B) The measure of central tendency that best describes the data for the weight of books (oz) is the mode. The mode is the value that occurs most frequently in a data set. In this case, the data is 12, 10, 9, 15, 16, 10. The mode is 10, as it occurs twice in the data set and is the most frequent value.

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Part 1: Kate should buy 100 coats to maximize profits.Part 2: The probability that the coats sell out is 0.25 (25%), and the probability that they do not sell out is 0.75 (75%).

To maximize profits, Kate should consider the scenario where she sells all the coats without any left over at the end of the season.

Since the sales are uniformly distributed between 100 and 400, buying 100 coats ensures that she meets the minimum expected sales of 100. Purchasing more than 100 coats would increase costs without a guarantee of higher sales, potentially leading to excess inventory and lower profits.

Given that the sales are uniformly distributed between 100 and 400 coats, Kate's purchase of 100 coats covers the minimum expected sales.

The probability of selling out can be calculated by finding the proportion of the range covered by the desired sales (100 out of 300). Therefore, the probability of selling out is 100/300 = 0.25 or 25%. The probability of not selling out is the complement, which is 1 - 0.25 = 0.75 or 75%.

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The correct answer is c. Learning curves are important for estimating performance improvement as workers become experienced.

Learning curves are often used in project management to estimating the time, effort, and resources required to complete a task or project. They help to estimate how long it will take for a worker or team to become proficient at a task or process, based on the amount of time and effort that they have put into it.

This can be helpful in estimating performance improvement as workers become more experienced and efficient in their work. The concept of a learning curve is a curved line that represents the rate of improvement over time, which is why the term "curve" is relevant. While learning curves do involve some math, they are not primarily focused on helping new PMs understand required math, nor are they used for visualization of curved mechanical parts or estimating cost improvement as parts become "broken in."
Learning curves are important for:
c. estimating performance improvement as workers become experienced.
Learning curves represent the progress made in a skill or job over time, whereas a curve illustrates the relationship between experience and efficiency. As workers become more experienced, their performance typically improves, which can be estimated using a learning curve in various industries and tasks.

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To paint 70 ornaments, he will need 70 bottles of paint.

To find the total surface area of one ornament, we need to find the lateral area of each cone and add them together.

The lateral area of a cone can be found using the formula:

L = πrℓ

where L is the lateral area, r is the radius, and ℓ is the slant height.

Since the two cones are identical, we only need to find the lateral area of one cone and then multiply it by two.

For each cone, we have:

r = 3.9 cm

ℓ = 8.4 cm

Using the formula, we get:

L = π(3.9)(8.4) ≈ 103.45 cm²

So the lateral area of both cones is:

2L = 2(103.45) = 206.9 cm²

The total surface area of one ornament is the sum of the lateral area and the area of the circular base:

A = πr² + 2L

A = π(3.9)² + 2(103.45)

A ≈ 235 cm²

Since one bottle of paint covers an area of 235 cm², Tim will need one bottle of paint for each ornament.

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The complete question is given in the attached image.

The equation of the plane passing P (1,2,1) and orthogonal to the two planes: x-y-z-10 = 0, x-2y + z-2=0 is -3x-2y-z+8=0.

Equation of plane passing through (x1,y1,z1) is given by

A(x-x1)+B(y-y1)+C(z-z1)=0

where, A, B, and C are direction ratios

In the question, it is given that the plane passes through (1,2,1)

So, the equation of the plane will be in the form,

A(x-1)+B(y-2)+C(z-1)=0

It is also given that the plane is perpendicular to give 2 planes.

So, their normal to the plane would be perpendicular to the normal of both planes.

So, the required normal is a cross-product of the normals of planes

x-y-z-10=0 and x-2y+z-2=0

i.e,

-3i-2j-k=0

so, the direction ratios,

A=-3, B=-2, C=-1

putting the direction ratios in the previous equation of the plane,

-3(x-1)-2(y-2)-1(z-1)=0

-3x+3-2y+4-z+1=0

-3x-2y-z+8=0

is the required equation of the plane

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The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated for different data sets, as specified in the given values.

The UCL and LCL are statistical control limits used in process control to determine if a process is in a stable and predictable state. These limits define the range within which data points should fall if the process is under control.

In each case provided (A, B, C, D, E), the UCL and LCL values are given. These values represent the calculated control limits for the respective data sets.

To calculate the control limits, a specific statistical method such as the ± 3σ (sigma) method may have been used. This method sets the UCL and LCL at three standard deviations above and below the mean.

The UCL represents the upper threshold or upper boundary, while the LCL represents the lower threshold or lower boundary. These limits help identify any potential deviations or out-of-control situations in the data.

By applying the given values, the corresponding UCL and LCL for each data set can be calculated. These limits are important for quality control and process monitoring, ensuring that the data falls within acceptable ranges.

To calculate the UCL and LCL using ±3σ limits, we use the following formulas:

UCL = Mean + 3σ
LCL = Mean - 3σ

Here, σ represents the standard deviation of the data set. The ±3σ limits provide a range that encompasses most of the data points in a normal distribution, with approximately 99.7% of the data falling within this range.
A) For data set A:
UCL = 7.437
LCL = -2.237

B) For data set B:
UCL = 7.82
LCL = 0

C) For data set C:
UCL = 8.382
LCL = 0

D) For data set D:
UCL = 7.82
LCL = -2.22

E) For data set E:
UCL = 9.112
LCL = 0

The ±3σ limits are derived from the standard deviation (σ) of the data set. Unfortunately, the standard deviation is not provided in the given information. If you have the standard deviation available, we can proceed to calculate the UCL and LCL using the formulas UCL = Mean + 3σ and LCL = Mean - 3σ.

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Question - What are the upper control limit (UCL) and lower control limit (LCL) using a ±3σ limit for the given data sets?

A) For data set A, the UCL is 7.437 and the LCL is -2.237.
B) For data set B, the UCL is 7.82 and the LCL is 0.
C) For data set C, the UCL is 8.382 and the LCL is 0.
D) For data set D, the UCL is 7.82 and the LCL is -2.22.
E) For data set E, the UCL is 9.112 and the LCL is 0.

Considering the linear equation in slope-intercept form:

The y-intercept of the line is the constant of the equation, in this case, the y-intercept is -1.

The slope of the line corresponds to the coefficient of the x-term, i.e. the value that multiplies x. For this line, the slope is equal to 11.2

The factor form of the cubic equation y = x³ + 3 · x² + x + 3 is y = (x² + 1) · (x + 3).

In this problem we find a cubic equation, that is, a polynomial of the form:

y = a · x³ + b · x² + c · x + d

Where a, b, c, d are the real coefficients of the polynomial. Herein we must use algebra properties to find the factor form of the expression:

y = a · Π (x - rₙ) for n = {1, 2, 3, ..., m - 1, m}

Where:

First, write the entire equation:

y = x³ + 3 · x² + x + 3

Second, use distributive property of real mumbers:

y = x² · (x + 3) + 1 · (x + 3)

Third, use distributive property of real numbers once again:

y = (x² + 1) · (x + 3)

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The scale of the map can be written as:

1cm to 20km

We want to find the distance that 1 cm in the map representes in the real world.

We know the relation:

3cm = 60km

We want to get a 1 in the left side, then we can divide both sides by 3 to get:

1cm = 60km/3

1cm = 20km

Then the scale of the map is 1cm to 20km

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Answer:

D. The function has no intercepts.

Step-by-step explanation:

There are vertical and horizontal asymptotes on both the x and y-axis (meaning nothing can touch them), so it is impossible for there to be any intercepts.

The probability that a participant selected at random will require no less than 500 hours to complete the program is 0.5000 or 50%.

To calculate the probability that a participant selected at random will require no less than 500 hours to complete the program, we can use the properties of a normal distribution.

Given that the average time spent by line supervisors on the program is 500 hours with a standard deviation of 100 hours, we can model this as a normal distribution with a mean (μ) of 500 and a standard deviation (σ) of 100.

To find the probability that a participant will require no less than 500 hours, we need to find the area under the normal curve to the right of 500 hours. This represents the probability of observing a value greater than or equal to 500.

To calculate this probability, we can use the z-score formula:

z = (x - μ) / σ

where:

x is the value we want to calculate the probability for,

μ is the mean of the distribution, and

σ is the standard deviation of the distribution.

In this case, x = 500, μ = 500, and σ = 100. Plugging these values into the formula, we get:

z = (500 - 500) / 100

z = 0

Next, we need to find the cumulative probability for this z-score using a standard normal distribution table or a statistical calculator. The cumulative probability represents the area under the normal curve up to a certain z-score.

Since our z-score is 0, the cumulative probability to the right of this point is equal to 1 minus the cumulative probability to the left. In other words, we want to find P(Z > 0).

Using a standard normal distribution table, we can look up the cumulative probability for a z-score of 0, which is 0.5000. Since we want the probability to the right, we subtract this value from 1:

P(Z > 0) = 1 - 0.5000

P(Z > 0) = 0.5000

Therefore, the probability that a participant selected at random will require no less than 500 hours to complete the program is 0.5000 or 50%.

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We need to identifying whether or not if this is a function

So, we will apply the vertical line test , we will graph a vertical line

If the vertical intersects withe the given graph at more than one point , so, the graph will not be a function

show the following image :

as shown : the vertical line at x = -6 intersects with the graph at two points

So, The graph is not a function

So, the answer is No

​

Answer:

The answer is x = \(\frac{-5}{3}\).

Step-by-step explanation:

First, we expand the brackets. Therefore:

\(2x+6 = -4x+(-4)\)

\(2x+6 = -4x -4\)

Then, we separate the like terms:

\(2x+4x = -4-6\)

Then we add the like terms up and solve for x:

\(6x = -10\)

Therefore:

\(x = \frac{-10}{6}\)

which, simplified, is:

\(x = \frac{-5}{3}\).

No, this rule for a relation is not a function because the input variable (domain) are not uniquely mapped to an output variable (range).

In Mathematics, a function is a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair.

This ultimately implies that, a function is typically used in mathematics for uniquely mapping an input variable (domain) to an output variable (range).

When x = -2, the range (output) of this function is given by:

y = (x + 1)²

y = (-2 + 1)²

y = (-1)²

y = 1.

When x = -1, the range (output) of this function is given by:

y = (x + 1)²

y = (-1 + 1)²

y = (0)²

y = 0.

When x = 0, the range (output) of this function is given by:

y = (x + 1)²

y = (0 + 1)²

y = (1)²

y = 1.

Based on the integers shown above, we can reasonably infer and logically deduce that this rule for a relation does not represent a function because the value of "1" is mapped to more than one domain element i.e -2 and 0.

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Answer:

1,9

Step-by-step explanation:

Answer:

-2+4=2, 1+8=9

Hope I helped

The decimal expansion of the given fraction is 0.0208. Therefore, the correct answer is option D.

The given fraction is 13/625.

Decimals are one of the types of numbers, which has a whole number and the fractional part separated by a decimal point.

Here, the decimal expansion is 13/625 = 0.0208

So, the number of places of decimal are 4.

Therefore, the correct answer is option D.

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Answer: Carlos is right

Step-by-step explanation:

why because in dilation, the image and the original are similar, in that they are the same shape but not necessarily the same size. They are not congruent because that requires them to be the same shape and the same size, which they are not (unless the scale factor happens to be 1.0).

Diya is wrong because the picture is the not the same size && the image is going to stay the same

Your question is incomplete. Please read below to find the missing content.

Carlos is right because, in dilation, the image and the original are similar, in that they are the same shape but not necessarily the same size. They are not congruent because that requires them to be the same shape and the same size, which they are not (unless the scale factor happens to be 1.0).

A word problem in maths is a maths question written as one sentence or more that requires children to apply their maths knowledge to a 'real-life' scenario.

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Answer:

2100

Step-by-step explanation:

2000+400= 2400

2400-300= 2100

Answer:

answer is a

Step-by-step explanation:

zeros are x intercepts

Answer:

A

Step-by-step explanation:

(2x+1)(x+2)

so

2x=-1

x=-1/2

x=-2

A

Answer:

a. +34 b. +46 c. +45 d. +31

Step-by-step explanation: use a number line