M A neutron in a nuclear reactor makes an elastic, head-on collision with the nucleus of a carbon atom initially at rest. (b) The initial kinetic energy of the neutron is 1.60 ×10⁻¹³J . Find its final kinetic energy and the kinetic energy of the carbon nucleus after the collision. (The mass of the carbon nucleus is nearly 12.0 times the mass of the neutron.)

Answers

Answer 1

In the head-on elastic collision between a neutron and a carbon nucleus in a nuclear reactor, with the neutron initially having a kinetic energy of 1.60 × 10⁻¹³J, the final kinetic energy of the neutron remains the same. The kinetic energy of the carbon nucleus after the collision is approximately 1.33 × 10⁻¹³J.

In an elastic collision, both momentum and kinetic energy are conserved. Let's denote the initial kinetic energy of the neutron as KE_neutron_initial, and its final kinetic energy after the collision as KE_neutron_final. Similarly, we'll use KE_carbon_initial and KE_carbon_final to represent the initial and final kinetic energies of the carbon nucleus, respectively.

Given the mass of the carbon nucleus is nearly 12.0 times the mass of the neutron (let's assume the neutron's mass is "m"), the carbon nucleus's mass is approximately 12m.

Since the collision is head-on, the initial momentum of the neutron is p_neutron_initial = √(2 * m * KE_neutron_initial), and the initial momentum of the carbon nucleus is p_carbon_initial = 0 (as it is initially at rest).

By conservation of momentum, the final momentum of the neutron is equal to the final momentum of the carbon nucleus, which can be expressed as:

p_neutron_final = p_carbon_final

√(2 * m * KE_neutron_final) = √(2 * (12m) * KE_carbon_final)

Since the mass "m" of the neutron is canceled out, we find:

√(KE_neutron_final) = √(12 * KE_carbon_final)

Squaring both sides to solve for KE_neutron_final:

KE_neutron_final = 12 * KE_carbon_final

Now, since kinetic energy is conserved, we can write:

KE_neutron_initial = KE_neutron_final + KE_carbon_final

Substitute the expression for KE_neutron_final:

1.60 × 10⁻¹³J = 12 * KE_carbon_final + KE_carbon_final

Solving for KE_carbon_final:

13 * KE_carbon_final = 1.60 × 10⁻¹³J

KE_carbon_final = (1.60 × 10⁻¹³J) / 13 ≈ 1.33 × 10⁻¹³J

Therefore, the final kinetic energy of the neutron remains the same, while the kinetic energy of the carbon nucleus after the collision is approximately 1.33 × 10⁻¹³J.

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Related Questions

At sea level, water boils at 100 degrees Celsius and methane boils at -161 degrees Celsius. Which of these has a stronger force of attraction between its particles? Explain your reasoning.

Answers

Water has a stronger force of attraction between its particles than methane.

To justify this we have to remember that temperature is a measure of the kinetic energy of the particles (atoms and molecules) in a given system. As temperature increase the kinetic energy increases as well; now larger molecules will have more electron and nucleis that attract with each other, then they will need more kinetic energy (temperature) to boil.

The lines of action of all the forces in the system pass through a common point and lie in the same plane. This type of force system is classified as:
Spatial force system
Concurrent coplanar force system
Concurrent noncoplanar force system
Non current coplanar force system

Answers

The type of force system described in the question is known as a Concurrent Coplanar Force System. This classification of force systems refers to a situation in which multiple forces are acting on a single point, and all of these forces have the same plane of action. Option B)

The type of force system described in the question is known as a Concurrent Coplanar Force System. This classification of force systems refers to a situation in which multiple forces are acting on a single point, and all of these forces have the same plane of action. Additionally, the lines of action for all of the forces intersect at a common point. In a Concurrent Coplanar Force System, the forces can be either balanced or unbalanced, meaning that they can either cancel each other out or result in a net force acting on the point in question. This type of force system is commonly used in engineering and physics applications, as it can be useful for analyzing the behavior of objects under the influence of multiple forces. One important consideration when working with a Concurrent Coplanar Force System is to ensure that the forces are being properly resolved. This means that the forces need to be broken down into their individual components in order to determine their overall effect on the point in question. By properly resolving the forces in a Concurrent Coplanar Force System, engineers and physicists can accurately predict how an object will move or behave under the influence of multiple forces. Therefore option B) is correct.

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Which of the following is an example of Newton’s 1 st Law? a. Using a force to push a box b. Pulling back an arrow to shoot it forward c. A table remains motionless in a classroom d. None of the above

Answers

Answer:

C.

Explanation:

Newton's 1st law states that an object at rest will stay at rest until acted upon by an external force.

Answer:

C is the answer for the question

Which statement accurately describes the use of radioactive decay?

Technetium-99 is used as a radioactive tracer because it remains in the body for a long time.
Some types of cancer cells are killed by directing alpha rays at the tumor from outside the body.
Plants utilize radioisotopes in the same way they use nonradioisotopes because they are chemically identical.
Geologists and archaeologists use different dating processes to determine the age of rocks, fossils, and ancient artifacts.

Answers

Answer:

O. Geologists and archaeologists use different dating processes to determine the age of rocks, fossils, and ancient artifacts.

Explanation:

Redioactive decay is the process whereby the radioactive materials reduces in quantity through the decay of its materials.

For example, if there where 100g of polonium today, and 5 years later, it has reduced to 30g, then, radioactive decay has taken place over the long period of time.

One of its major use is in the determination of the ages of rocks, fossils, and ancient artifiacts through its cabon dating inorder to determining the radioactive decay of those materials over the past few decades.

please help



A cannonball is launched diagonally with an initial velocity of 56.0m/s. Label the

hypotenuse, opposite side and adjacent side, and determine all unknowns.

At what angle was the cannonball launched?

Answers

The hypotenuse is the initial velocity of the cannonball (56.0m/s). The opposite side is the vertical component of the velocity and the adjacent side is the horizontal component of the velocity.

To determine the unknowns, we need to use trigonometry. Let's use theta to represent the angle at which the cannonball was launched. The vertical component of the initial velocity can be found using the equation:
Vsin(theta) = opposite side
Vsin(theta) = (56.0m/s)sin(theta)
The horizontal component of the velocity can be found using the equation:
Vcos(theta) = adjacent side
Vcos(theta) = (56.0m/s)cos(theta)
We can use these equations to solve for the unknowns. For example, if we wanted to find the angle at which the cannonball was launched, we could set the two equations equal to each other and solve for theta:
Vsin(theta) = Vcos(theta)
tan(theta) = opposite side/adjacent side
tan(theta) = (56.0m/s)sin(theta)/(56.0m/s)cos(theta)
tan(theta) = sin(theta)/cos(theta)
theta = tan^-1(sin(theta)/cos(theta))
Using a calculator, we find that theta is approximately 51.3 degrees. Therefore, the cannonball was launched at an angle of 51.3 degrees.  While the ultimate velocity of an object thrown upward will be zero, the final velocity of an object thrown downward will be twice as fast as the initial velocity. Due to the forces of gravity, when an object is thrown both upward and downward with the same initial velocity, the ultimate velocities will differ. The object thrown upward will have a negative ultimate velocity, while the thing thrown downhill will have a positive end velocity.

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your car is skidding to a stop from a high speed. part a identify all forces acting on the object. check all that apply. identify all forces acting on the object.check all that apply. kinetic friction force, f⃗ k normal force, n⃗ thrust, f⃗ thrust weight, w⃗ tension, t⃗

Answers

Your car is skidding to a stop from a high speed. All the force acting on the object are Kinetic friction force, Normal force and Weight.

The forces acting on the car while it is skidding to a stop include:

1. Kinetic friction force (f⃗k): This force acts opposite to the direction of motion and is responsible for slowing down the car.

2. Normal force (n⃗): This force is perpendicular to the surface and acts to support the weight of the car.

3. Weight (w⃗): This force is the gravitational force acting on the car due to its mass and acts vertically downward.

Therefore, the correct forces acting on the car are:

- Kinetic friction force (f⃗k)

- Normal force (n⃗)

- Weight (w⃗)

The forces "thrust" and "tension" are not applicable in this context as they are typically associated with the motion of objects propelled by engines or connected by ropes or strings, which do not apply to a skidding car scenario.

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T/F the main asteroid belt environment is an active and chaotic part of the solar system where frequent collisions occur between rocky masse

Answers

True. The main asteroid belt is an active and chaotic part of the solar system where frequent collisions occur between rocky masses.

The asteroid belt is located between Mars and Jupiter and consists of millions of asteroids, ranging in size from small pebbles to several hundred kilometers in diameter.

These asteroids are constantly colliding with each other, sometimes resulting in the formation of smaller asteroids or the destruction of larger ones.

This collisional environment is due to the gravitational interactions between the asteroids and Jupiter, which perturbs their orbits and causes them to cross paths.

Despite the frequent collisions, the asteroid belt is relatively sparse, with the average distance between asteroids being several kilometers. Nonetheless, the asteroid belt remains an important area of study for astronomers, as it provides insight into the formation and evolution of the solar system.

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Rank the four fundamental forces from strongest to weakest

Answers

1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity

Answer:gravitational, weak nuclear, electromagnetic, strong

Explanation:

A steel railroad track has a length of 21 m when the temperature is 0 C. what is the increase in the length of the rail on a hot day when the temperature is 32 C? the linear expansion coefficient of steel is 11*10-6(C)-1

Answers

The increase in the length of the rail on a hot day is 0.007392 m.

Length calculation.

To solve this problem, we can use the formula for linear expansion:

ΔL = αLΔT

Where:

ΔL = change in length

α = linear expansion coefficient

L = original length

ΔT = change in temperature

We are given:

L = 21 m

ΔT = 32°C - 0°C = 32°C

α = 11×10^(-6) (°C)^(-1)

Substituting the values into the formula, we get:

ΔL = (11×10^(-6) (°C)^(-1)) × (21 m) × (32°C)

ΔL = 7.392 m × 10^(-3)

ΔL = 0.007392 m

Therefore, the increase in the length of the rail on a hot day is 0.007392 m.

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Eric has a mass of 19.0 kg on the earth. What is Eric's weight on earth? What is Eric's weight on Mars? where the acceleration of gravity is approximately 0.381 of that of Earth's? ________.

Answers

Answer:

Weight on Earth = We = 186.2 N

Weight on Mars = Wm = 70.94 N

Explanation:

The weight of an object is defined as the force applied on the object by the gravitational field. The magnitude of weight is given by the following formula:

W = mg

were,

W= Weight of Eric

m = mass of Eric

g = acceleration due to gravity

ON EARTH:

W = We = Eric's Weight on Earth = ?

m = Eric's Mass on Earth = 19 kg

ge = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

We = (19 kg)(9.8 m/s²)

We = 186.2 N

ON MARS:

W = Wm = Eric's Weight on Mars = ?

m = Eric's Mass on Mars = 19 kg

gm = acceleration due to gravity on Mars = 0.381(ge) = (0.381)9.8 m/s² = 3.733 m/s²

Therefore,

Wm = (19 kg)(3.733 m/s²)

Wm = 70.94 N

The electric potential at a point in space is -890 V. If a 0.0285 C charge is placed there, what will its potential energy U be? Include the sign, + or - (Unit = J)​

Answers

Answer: -25.4

Explanation:

Acellus don’t forget the negative sign

Answer:

-25.4

Explanation:

Acellus

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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.

Answers

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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18. After chemical weathering, what is true about the chemical makeup of the weathered rock?
A. It is different than that of the original rock.
B. It is the same as the original rock.
C. It is more affected by mechanical weathering.
D. It could either be changed or stay the same.

Answers

The true statement is  about the chemical makeup of the weathered rock is "It is different than that of the original rock.

option A.

What is chemical weathering?

Chemical weathering is a process that involves the breakdown of rocks and minerals through chemical reactions with the surrounding environment. This process occurs due to the interaction of rock minerals with water, atmospheric gases, and organic acids, which can lead to the breakdown of the mineral structure of the rock.

Chemical weathering involves the breakdown of rocks and minerals through chemical reactions with water, oxygen, and other substances in the environment. As a result of these reactions, the chemical makeup of the weathered rock can be altered, and it may have different physical and chemical properties than the original rock.

Therefore, option A is the correct answer.

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an 1,810 w toaster, a 1,440 w electric frying pan, and a 60 w lamp are plugged into the same outlet in a 15 a, 120 v circuit. (the three devices are in parallel when plugged into the same socket.) (a) what current (in a) is drawn by each device?

Answers

Explanation:

Watts =  amp * volts

watts/ volts = amps

1810 w / 120 v =  15.5 A

1440 w / 120 v = 12 A

60 w/ 120 v = .5 A

In reality, they are probably drawing ZERO amps     as the circuit breaker (15 Amps as given)  will likely trip or the wires will burn !

The current drawn by each device in a parallel circuit is determined by the resistance of each device.

Since the toaster has the highest resistance, it will draw the least amount of current, while the electric frying pan with the lowest resistance will draw the highest current. The lamp, being a light bulb, will draw a medium amount of current.

Using Ohm's law, the current drawn by each device can be calculated as follows:

Toaster:  1,810 W ÷ 120 V = 15.08 A

Electric Frying Pan: 1,440 W ÷ 120 V = 12 A

Lamp: 60 W ÷ 120 V = 0.5 A

Since all three devices are connected in parallel, the total current drawn from the outlet will be the sum of the individual currents drawn by each device, which is 15.58 A. This is below the maximum current rating of the circuit (15 A), so the circuit is safe.

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Distance between gas molecules in the case of:
-Increase in temperature
-Decrease in temperature
-Increase in volume
-Decrease in volume
-Increase in pressure
-Decrease in pressure

Answers

Answer:

-Increase in temperature: increase

-Decrease in temperature: decrease

-Increase in volume: increase

-Decrease in volume: decrease

-Increase in pressure: increase

-Decrease in pressure: decrease

Explanation:

-Increase in temperature:

● Molecules gain kinetic energy and move fast thus increasing distance

-Decrease in temperature:

● Kinetic energy of molecules decrease so they have smaller distance

-Increase in volume:

● Molecules have more space to move around so distance increase

-Decrease in volume:

● Less space, molecules collide with each other because of decreased distance thus increasing pressure

-Increase in pressure

● Molecules collide with each other and the walls of container increasing pressure so molecules move faster and it increases distance

-Decrease in pressure:

● Molecules collide with each other and walls of container less frequently so distance between molecules decrease

Se lanza una piedra de 3.00 N verticalmente hacia arriba desde el suelo. Se observa que, cuando está 15.0 m sobre el suelo, viaja a 25.0 m/s hacia arriba. Use el teorema trabajo-energía para determinar a) su rapidez en el momento de ser lanzada. b) su altura máxima

Answers

Answer:

(a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

Explanation:

Given that,

Weight of stone = 3.00 N

Height = 15 m

Speed = 25.0 m/s

(a). We need to calculate the speed at the moment of being thrown

Using work energy theorem

\(W=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)

\(-mg\times d=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)\)

Put the value into the formula

\(-9.8\times15=\dfrac{1}{2}\times(v_{2}^2-v_{1}^2)\)

\(-2\times9.8\times15=25^2-v_{1}^2\)

\(-v_{1}^2=-300-25^2\)

\(v_{1}=\sqrt{925}\)

\(v_{1}=30.41\ m/s\)

(b). We need to calculate the maximum height

Using work energy theorem

\(\(W=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)

\(mg\times d=\dfrac{1}{2}mv_{2}^2-\dfrac{1}{2}mv_{1}^2\)

Here, \(\dfrac{1}{2}mv_{2}^2\)=0

\(-(mg)\times d=\dfrac{1}{2}mv_{1}^2\)

\(d=\dfrac{v_{1}^2}{2g}\)

Put the value into the formula

\(d=\dfrac{30.41^2}{2\times9.8}\)

\(d=47.18\ m\)

Hence, (a). The speed at the moment of being thrown is 30.41 m/s.

(b). The maximum height is 47.18 m.

The rarest type of stars are A. stars that are about 1 solar mass. B. stars that are more than 50 solar masses. C. stars that are about 10 solar masses. D. stars that are about 0.5 solar mass.

Answers

The rarest type of stars is those that are more than 50 solar masses.

How are stars categorized?

Stars are categorized on the basis of mass, spectral behavior, and temperature.

There are 7 spectral types of stars:

O-type (Blue) stars have more than 50 times the solar mass of the sun and are the rarest main sequence stars present in the universe. Their abundance is merely 0.000001% of known stars.

B-type (Blue) stars have 10 times the solar mass of the sun with a surface temperature of over 20,000 K and their abundance is 0.1% of known stars.

A-type (Blue) stars have 2 times the solar mass of the sun with a surface temperature of 8500 K. Their abundance is 0.7% of known stars.

F-type (Blue/white) stars have 1.5 times the solar mass of the sun with a surface temperature of 6500 K. Their abundance is 2% of known stars.

G-type (White/yellow) stars have 1 times the solar mass of the sun with a surface temperature of 5700 K. Their abundance is 3.5% of known stars.

K-type (Orange/red) stars have 0.7 times the solar mass of the sun with a surface temperature of 4500 K. Their abundance is 8% of known stars.

M-type (Red) stars have 0.2 times the solar mass of the sun with a surface temperature of 3200 K. Their abundance is 80% of known stars.

Thus, the rarest type of stars are the O-type stars that have more than 50 times the solar mass of the sun.

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please help me guys please please please​

please help me guys please please please

Answers

Answer:

Mass = 2154 grams

Explanation:

Given the following data;

Acceleration = 520m/s²

Force = 11.2N

To find the mass;

Force = mass * acceleration

Mass = force/acceleration

Substituting into the equation, we have;

Mass = 11.2/520

Mass = 2.154 kg

Therefore, the value of mass in grams;

1000 grams = 1 kilograms

x grams = 2.154 kilograms

Cross-multiplying, we have;

2.154 * 1000 = 2154 grams.

Mass = 2154 grams.

Therefore, the mass of the model rocket is equal to 2154 grams.

how does Newton's third law of motion give a property of process​

Answers

Answer:

Newton's third law explains the generation of thrust by a rocket engine. In a rocket engine, hot exhaust gas is produced through the combustion of a fuel with an oxidizer. The hot exhaust gas flows through the rocket nozzle and is accelerated to the rear of the rocket. In re-action, a thrusting force is produced on the engine mount.

Explanation:

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a 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor.

Answers

(A) the original charge of the system is 21,250 μC. (B)  the final potential difference across the capacitor is 850 V. (C) The final energy of the system is 11,740,750 μJ.

To compute the original charge of the system, we can use the formula;

Q = C × V

where Q will be the charge, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor charged to 850 V;

Q₁ = C₁ × V₁

= (25.0 μF) × (850 V)

Q1 = 21,250 μC

Therefore, the original charge of the system is 21,250 μC.

When the charged capacitor is connected in parallel to the uncharged capacitor, the potential difference across both capacitors becomes equal. This means the final potential difference across the capacitors will be the same as the initial potential difference of the charged capacitor, which is 850 V.

Therefore, the final potential difference across the capacitor is 850 V.

The energy stored in a capacitor can be calculated using the formula:

E = 0.5 × C × V₂

where E will be the energy, C will be the capacitance, and V will be the potential difference.

For the 25.0 μF capacitor with a potential difference of 850 V:

E₁ = 0.5 × C1 × V1²

= 0.5 × (25.0 μF) × (850 V)²

E₁ = 9,018,750 μJ

For the 8.00 μF capacitor with a potential difference of 850 V:

E₂ = 0.5 × C₂ × V2²

= 0.5 × (8.00 μF) × (850 V)²

E2 = 2,722,000 μJ

The final energy of the system is the sum of the energies of both capacitors;

E_final = E₁ + E₂

= 9,018,750 μJ + 2,722,000 μJ

E_final = 11,740,750 μJ

Therefore, the final energy of the system is 11,740,750 μJ.

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--The given question is incomplete, the complete question is

"A 25.0 μf capacitor is charged to a potential difference of 850 v . the terminals of the charged capacitor are then connected to those of an uncharged 8.00 μf capacitor. A) compute the original charge of the system B)compute the final potential difference across the capacitor C)compute the final energy of the system."--

The half life of
40
K is approximately 1.3 billion years, and it decays to
40
Ar, which is trapped in igneous rocks as
40
K decays. If we find a sample of granite in which the ratio of
40
Ar/
40
K is 3/1, then how old is the sample?

Answers

The half-life of 40K is approximately 1.3 billion years. Given a ratio of 40Ar/40K as 3/1 in a granite sample, we can estimate the age of the sample by understanding the decay process.  Based on the given 40Ar/40K ratio, the age of the sample is approximately 650 million years.

Since the half-life of 40K is 1.3 billion years, this means that after each half-life, half of the 40K atoms will have decayed into 40Ar. Therefore, if the ratio of 40Ar/40K is 3/1, it suggests that three-quarters (or 75%) of the original 40K atoms have decayed into 40Ar.

To determine the age, we can calculate the number of half-lives that have occurred based on the remaining 25% of 40K. Since each half-life is 1.3 billion years, dividing the remaining 25% by 50% (half) gives us 0.5. Thus, the sample has undergone 0.5 half-lives.

Multiplying 0.5 by the half-life of 1.3 billion years gives us an estimated age of 0.65 billion years, or 650 million years, for the granite sample.

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free fall is possible on lunar but not on earth surface.Why?

Answers

Answer:

The earth has more gravity so that means if you jump out of a plane without a parachute u will die. But the moon has less gravity so u will not die when hit ground. But someone can probally explain it better than me.

More gravity equals more speed in some cases like falling

ASAP HELP!! Showing the entire question for information I only need the data and conclusion. Please hurry!
Electromagnetic Spectrum Lab Report
Instructions: In this virtual lab, you will use a virtual spectrometer to analyze astronomical bodies in space. Record your hypothesis and spectrometric results in the lab report below. You will submit your completed report to your instructor.

Procedure:
Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.


Data:
Record the elements present in each unknown astronomical object. Be sure to indicate “yes” or “no” for each element.

Hydrogen Helium Lithium Sodium Carbon Nitrogen
Moon One




Moon Two



Planet One



Planet Two


Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

Using two to three sentences, summarize what you investigated and observed in this lab.
Astronomers use a wide variety of technology to explore space and the electromagnetic spectrum; why do you believe it is essential to use many types of equipment when studying space?
If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to Earth? Explain why. (Hint: Think about the carbon cycle.)
We know that the electromagnetic spectrum uses wavelengths and frequencies to determine a lot about outer space. How does it help us find out the make-up of stars?
Why might it be useful to determine the elements that a planet or moon is made up of?

Answers

Answer:

In this lab, we used a virtual spectrometer to analyze the elements present in unknown astronomical objects. We observed that Moon One had hydrogen, helium, and carbon present, while Moon Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present. Planet One had hydrogen, helium, lithium, sodium, and carbon present, while Planet Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present.

It is essential to use many types of equipment when studying space because the electromagnetic spectrum is made up of many different wavelengths and frequencies, and each one provides different information. If carbon was the most common element found in the moons and planets, oxygen would be missing, which is necessary for the carbon cycle to occur. The electromagnetic spectrum helps us find out the make-up of stars by allowing us to detect the different wavelengths and frequencies of light they emit, which can tell us the elements they are composed of.

It is useful to determine the elements that a planet or moon is made up of because it can provide insight into the planet's atmosphere, climate, and potential for life. Knowing the elements present can also help us understand the history of the planet or moon, such as how it was formed and how it has evolved over time.

Assuming a thermal to electric efficiency of 30% we want to run a 100 W light bult for a year a. Using 235U, how much mass would be consumed in that year? (1 point) b. How much coal would be required given a thermal output of 25 GJ/ton). (1 point)

Answers

The thermal to electric efficiency of 30%, to run 100W bulb for a year.

a) Mass consumed in a year is 1.67 × 10⁻³⁷ g.

b) Coal required will be 180 kg.

a. Using 235U, the mass that would be consumed in one year.

we have a thermal to electric efficiency of 30% and we want to run a 100 W light bulb is:0.1 W = (235U energy/mass consumed) × 0.30Using the equation above; we can deduce that:

Mass consumed = 0.1 W / [(235U energy/mass consumed) × 0.30]

To determine the mass of 235U consumed in that year, we will first have to calculate its energy as follows:

Using 235U, we know that;

1 atom of 235U = 7 × 10¹³ J

By Avogadro's number, the number of atoms in 235g of 235U will be;

Nₐ = 6.02 × 10²³/ mole

The molar mass of 235U is 235g/mol

Therefore, the number of moles of 235U is:

moles of 235U = mass of 235U / molar mass of 235U

= 235g / 235g/mol

= 1 mol

Therefore, the total number of atoms in 235g of 235U is:

Nₐ = 1 mol ×6.02 × 10²³/ mole = 6.02 × 10²³ atoms of 235U

To find the total energy in 235g of 235U, we multiply the number of atoms by the energy of one atom:

The total energy of 235g of 235U = 7 ×  10¹³ J/atom × 6.02 × 10²³ atoms ⇒ 4.22 × 10³⁷ J

To get the mass of 235U consumed per year, we would substitute this value into the equation we had derived earlier:

m = 0.1 W / [(4.22 × 10³⁷ J) / (235g)] × 0.30 ⇒ 1.67 × 10⁻³⁷ g

b.How much coal would be required given a thermal output of 25 GJ/ton)?

To calculate how much coal would be required given a thermal output of 25 GJ/ton:

1 GJ = 10⁹ J (Joules)

The energy required to run a 100 W light bulb in a year = 100 W × 24 hours × 365 days

⇒ 876000 Wh

⇒ 876000 × 3600 J

⇒ 3.1536 × 10⁹ J

Thermal efficiency is 30%

Hence, electric efficiency = 100% - 30% ⇒ 70%

To calculate the coal consumption, we need to know the amount of energy required to produce 1 ton of coal. We will assume that the energy needed to produce coal is the same as its thermal energy content.

The energy content of 1 ton of coal = 25 GJ/ton

Therefore, the amount of coal required can be calculated as follows:

mass of coal = 3.1536 × 10⁹ J / (25 × 10⁹ J/ton × 0.70)

⇒ 0.1802057 ton

⇒ 180 kg (approximately)

Thus, to run a 100 W light bulb for a year, we would need approximately 3.36 × 10⁻¹⁰ grams of 235U or 180kg of coal.

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Iron is made up of atoms. The thermal expansion of solid iron is caused by ___.

A. increasing the amplitude of vibration of the iron atoms

B. increasing the distance between equilibrium positions for the vibrating iron atoms

C. the breaking of bonds between the iron atoms

Answers

Iron is made up of atoms, the thermal expansion of solid iron is caused by C. the breaking of bonds between the iron atoms.

What is thermal expansion?

Thermal expansion  can be described as the tendency of matter to change in shape, volume, and area in response to a change in temperature.

It should be noted that the temperature  can be seen as a monotonic function of the average molecular kinetic energy of a substance , however When a substance is heated, the Kinetic energy that is present in the molecules will increases then they can start to vibrating more and usually maintain a greater average separation and this process will result to expoansion because bond will be broken.

Therefore, option C is correct.

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the maximum displacement of a particle by a wave is called

Answers

The answer is amplitude

based on its location on the periodic table which element is a metal

Answers

Answer:

i found this i thinks its Boron

Explanation:

In the periodic table, you can see a stair-stepped line starting at Boron (B), atomic number 5, and going all the way down to Polonium (Po), atomic number 84. Except for Germanium (Ge) and Antimony (Sb), all the elements to the left of that line can be classified as metals.

Answer:

Metal are on the left side and down(excepts Hydrogen)

Explanation:

If you look the periodic the left side and down is metal whereas boron metalloids so the right side would be nonmetal starting from carbon.

(a) is it possible for the magnetic force on a charge moving in a magnetic field to be zero? (b) is it possible for the electric force on a charge moving in an electric field to be zero? (c) is it possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero?

Answers

a)It is possible for the magnetic force on a charge moving in a magnetic field to be zero. The force acting on the charge is zero when a charge is moving in the same or opposite direction of the magnetic field.  When a is charge moving parallel in the same direction of the magnetic field, then the magnetic force  is zero.

b)It is not possible for the electric force on a charge moving in an electric field to be zero. If there's a charged particle in a magnetic field, it's impossible for this force to become zero.

c)It is not possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero. The magnetic force can be zero but the electric force cannot be zero because it is not affected by the motion of the particles.

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A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will its final velocity be in m/s, after two seconds.

Answers

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + (13 x 2)

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

An engine using 1 mol of an ideal gas initially at 18.5 L and 358 K performs a cycle
consisting of four steps:
1) an isothermal expansion at 358 K from
18.5 L to 39.1 L ;
2) cooling at constant volume to 180 K ;
3) an isothermal compression to its original
volume of 18.5 L; and
4) heating at constant volume to its original
temperature of 358 K .
Find its efficiency. Assume that the
heat capacity is 21 J/K and the universal gas constant is 0.08206 L · atm/mol/K =
8.314 J/mol/K.

Answers

The efficiency of the engine is 83.4% assuming  that the

heat capacity is 21 J/K and the universal gas constant is 0.08206 L · atm/mol/K =8.314 J/mol/K.

What is efficiency?

Efficiency is described as the often measurable ability to avoid wasting materials, energy, efforts, money, and time while performing a task.

The efficiency of the engine is given by:

E = W/Q

where;

W = the work done in the four steps,

Q = the energy input

Since there at four steps in a cycle:

E = w1+ w2 +w3+ w4/ q1+ q2+q3+q4

We calculate that the work done in the first step (isothermal expansion)

n= 1 mole, T1 = 402 K, V2 = 41.2 L, V1 = 18.5 L

We also solve for Steps 2 and 4 are constant volume processes,

We also calculate  work done in the third step (isothermal expansion) is

where;

n = 1 mol, T3 = 273 K, V4 = 41.2 L, V3 = 18.5 L

We notice that Heat enters the system only during steps (1) and (4).

The internal energy of the gas increases in step 4 but no work is done, while the internal energy is constant change in step 1 but work is done by the gas.

Cv =21 J/K, T3 = 273 K, T4 = 402 K

We Solve  for efficiency, ɛ:

ɛ = 2676.01  +0 +0 + 1879.29/ 2676.01  +0 +0 + 2709 = 83.4%.

Therefore, the efficiency of the engine is 83.4%.

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