m^ -3 ^2 n^2 ×n over 9 mxn^4​

Answer:

The answer is C

Step-by-step explanation:

Answer:

31/16 = 1.9375 lbs

Step-by-step explanation:

The oz to pound conversion is (oz/16) = lbs

So, 31oz/16 = 1.9375 lbs

Start at the corner of the right angle and walk along the line that connects two of the corners of the right angle until you reach the line which is the longest side of the right angle (the hypotenuse).

The playground of Hank School has a large right angle painted on the ground. A right angle is a type of angle that is exactly 90°. It is made up of two perpendicular lines that intersect at a corner. To walk along an angle bisector, you must start at one of the corners of the right angle and walk along the line that connects two of the corners. This line is the angle bisector, which is the line that bisects (divides) the two angles of the right angle into two equal parts. When you reach the line which is the longest side of the right angle (the hypotenuse), you will have reached the opposite side. The hypotenuse is the longest side of a right triangle, and it is always opposite the 90° angle. Walking along the angle bisector of the right angle is a great way to explore the geometry of the playground.

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Answer:

435 degrees

Step-by-step explanation:

Using unit circle, you move back 5/12 of the circle and add 360 degrees to it to get 360 + 75 = 435 degrees :)

make me brainliest if i helped

nxhudkdodisuhaiioavsbos

Answer:

there's no picture of the shape but a rectangular shape  maybe

Step-by-step explanation:

if you ask the question again with the picture of the shape attached I will help you

Answer:

shapes that have 4 edges are called quadrilaterals. Quadrilateral shapes include squares, rectangles, trapezoids, rhombus, parallelogram, diamonds, and kites.

Step-by-step explanation:

It is given that PG grading requirement is met if the values of S(t) are between -3.2 and +3.2. As all the calculated values of S(t) lie within this range, the asphalt meets PG grading requirement.

Given data: Bending rheometer: 0.4mm, 0.5mm, 0.65mm, 0.82mm, 0.98mm, and 1.3mm for t = 15s, 30s, 45s, 60s, 75s, and 90s.

We are supposed to calculate the values of S(t) and m to check if the asphalt meets PG grading requirement.

Calculation of m:

Mean wheel track rut depth = (0.4+0.5+0.65+0.82+0.98+1.3)/6

= 0.7933mm

Calculation of S(t)

S(t) = (x - m)/0.3

Where, x = 0.4mm, 0.5mm, 0.65mm, 0.82mm, 0.98mm, and 1.3mm

Given, m = 0.7933mm

Substituting these values into the formula above:

S(15s) = (0.4 - 0.7933)/0.3

= -1.311S(30s)

= (0.5 - 0.7933)/0.3

= -0.9777S(45s)

= (0.65 - 0.7933)/0.3

= -0.4777S(60s)

= (0.82 - 0.7933)/0.3

= 0.128S(75s)

= (0.98 - 0.7933)/0.3

= 0.62S(90s)

= (1.3 - 0.7933)/0.3

= 1.521

It is given that PG grading requirement is met if the values of S(t) are between -3.2 and +3.2. As all the calculated values of S(t) lie within this range, the asphalt meets PG grading requirement.

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Answer:

36

Step-by-step explanation:

The two terms in the t-test are the numerator and denominator degrees of freedom. The numerator represents the number of independent variables in the test, while the denominator represents the sample size minus the number of independent variables.

In a one-sample t-test, the numerator is typically the difference between the sample mean and the null hypothesis mean, while the denominator is the sample standard deviation divided by the square root of the sample size.

In a two-sample t-test, the numerator is typically the difference between the means of two samples, while the denominator is a pooled estimate of the standard deviation of the two samples, also divided by the square root of the sample size.

The degrees of freedom are important in calculating the critical t-value, which is used to determine whether the test statistic is statistically significant. As the degrees of freedom increase, the critical t-value decreases, meaning that it becomes more difficult to reject the null hypothesis.

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Answer:

the answer is one cup of oil for each cup of water. hope this helps!

Answer:

15x -45y +180

Step-by-step explanation:

5(3x)= 15x

5(26)= 130

5(-9y)= -45y

5(10)= 50

combine like terms:

15x - 45y +180

Answer:

15 and 270

Step-by-step explanation:

using the property of radicals

(\(\sqrt{x}\) )² = x and (\(\sqrt[3]{x}\) )³ = x

then

(\(\sqrt{5}\) )² × (\(\sqrt{3}\) )² = 5 × 3 = 15

(\(\sqrt[3]{9}\) )³ × (\(\sqrt{30}\) )² = 9 × 30 = 270

Answer: Everyone would get about 7 pizzas

Step-by-step explanation:

I did 212 divided by 30 which is 7.06666666667 which is closest to 7 then 8 so the answer would be 7. I know this is about right because 7 times 30 is 210 which is closest to 212 then 8*30 which is 240.

Events A and C as well as events B and D are independent.

Two events A and B are independent if the occurrence or non-occurrence of one event does not affect the probability of the other event.

In the given events, it is not explicitly mentioned how the events are related. However, based on typical assumptions about burrito ingredients and customer preferences, we can make some assumptions:

Assuming that the choice of meat (chicken or carne asada) and the choice of beans (black beans or pinto beans) are independent of each other, we can conclude that events A (The burrito is a chicken burrito) and C (The customer requested black beans) are independent. The choice of chicken meat in the burrito does not affect the probability of the customer requesting black beans.

Similarly, events B (The burrito is a carne asada burrito) and D (The customer requested pinto beans) are independent. The choice of carne asada meat in the burrito does not affect the probability of the customer requesting pinto beans.

So, based on these assumptions, events A and C as well as events B and D are independent.

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The mass of the water can be determined using the formula for heat transfer, which states that heat transferred (in calories) is equal to the mass of the substance (in grams) multiplied by the specific heat capacity of the substance (in calories/gram°C) multiplied by the change in temperature (in °C). By rearranging the formula, we can find that the mass of water is equal to the heat transferred divided by the product of the specific heat capacity and the temperature change.

Given:

Initial temperature (T1) = 45°C

Final temperature (T2) = 25°C

Heat transferred (Q) = 20 calories

Specific heat capacity of water (C) = 1 calorie/gram°C

We can use the formula for heat transfer:

Q = m * C * ΔT

Where:

Q is the heat transferred,

m is the mass of the substance,

C is the specific heat capacity of the substance, and

ΔT is the change in temperature.

Rearranging the formula, we have:

m = Q / (C * ΔT)

Substituting the given values:

m = 20 calories / (1 calorie/gram°C * (45°C - 25°C))

Simplifying the equation:

m = 20 calories / (1 calorie/gram°C * 20°C)

m = 20 grams

Therefore, the mass of water is 20 grams.

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Answer:

10

Step-by-step explanation:

ll

Answer:

he used 4 1/6 cup of flour for each loaf I think

Step-by-step explanation:

Answer:

the place of 2 is tenth thousands

Answer: $41

work out what one ticket is:

$57.40/7=$8.20

and then multiply by 5

$8.20*5=41

Answer:

$41

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

Sea level elevation is defined as 0 ft.

Answer:

Your location doesn't matter, because all over the world, see level is at an elevation of 0 feet. Sea level is the "building block of elevation" as my math teacher used to say.

Answer:

A.\(2(3^{\frac{1}{3}})-\sqrt[3]{18}\)

Step-by-step explanation:

We are given that

\(\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})\)

We have to find the quotient.

\(\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})\)

\(\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})\)

\(2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})\)

Using the property

\((ab)^n=a^n\cdot b^n\)

\(2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})\)

Using the property

\(\frac{a^x}{a^y}=a^{x-y}\)

\(2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})\)

\(2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}\)

\(2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}\)

\(2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}\)

\(2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}\)

\(2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}\)

\(2(3^{\frac{1}{3}})-\sqrt[3]{18}\)

Hence, the quotient of \(\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})\) is given by

\(2(3^{\frac{1}{3}})-\sqrt[3]{18}\)

Option A is correct.

Answer:

A

Step-by-step explanation:

Answer:

x=6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

x = 6

Step-by-step explanation:

In this equation, we are told to solve for the value of x. Thus, we must isolate the variable x (poor x... we're always trying to isolate it).

3 - 2x = -1.5x

(I'm going to swap sides to make it easier for me to solve. This doesn't change anything mathematically due to the associative laws. It's purely cosmetic.)

-1.5x = 3 - 2x

First, we can add 2x to both sides of the equation to get all algebraic expressions containing the variable x on one side of the equation alone.

0.5x = 3

For our next part here, let's convert 0.5 to a fraction to make life easier for us.

\(\frac{1}{2}\)x = 3

When isolating x in this, we are trying to get rid of 1/2. How can we do this? We can multiply is by 2!

\(\frac{1}{2}\)x · \(\frac{2}{1}\) = 1x (or simply x)

What we do to one side we must do to another.

x = 3 · 2

x = 6

Our answer is x = 6. Woo!

To calculate the finance charge we need to apply the simple interest formula, which can be seen below:

Where "M" is the interest value, "C" is the value on which the interest should be calculated, "r" is the interest rate and "t" is the elapsed time in years. Pam paid $50 in advance, therefore the interest should be calculated on the $700 there is left to be paid. We have:

The finance charged 252 in interest.

In linear equation, 256.28 is the cost of her ticket .

What is the most effective way to explain linear equations?

An x-y linear relationship, or two variables in which the value of one of them (often y) relies on the value of the other one, is what is known as a linear equation in two variables (usually x).

                          In this scenario, y is referred to as the dependent variable because it depends on the independent variable, x. A linear equation is an algebraic equation of the form y=mx+b.

=  149 * .72

= 107.28

= 149 + 107.28

= 256.28

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According to given information, the value of  x = 22/3.

To find x in the equation below.

log 10 (x + 6) - log 10 (x - 6) = 1

Solution:

We have the equation:

log 10 (x + 6) - log 10 (x - 6) = 1

Since the bases of the two logarithms are the same, we can apply the quotient rule of logarithms, which states that if we subtract two logarithms with the same base, we can simply divide the numbers inside the parentheses, so we have:

log 10 [(x + 6)/(x - 6)] = 1

We can convert this logarithmic equation to an exponential equation as follows:

10¹ = (x + 6)/(x - 6)

10(x - 6) = x + 6

Now we can expand the left side: 10x - 60 = x + 6

Subtracting x from both sides: 9x - 60 = 6

Adding 60 to both sides: 9x = 66

Dividing by 9: x = 66/9 or x = 22/3

Answer: x = 22/3.

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Answer:

B) 67°C.

Step-by-step explanation:

Newton's Law of Cooling is given by:

\(\displaystyle \frac{dT}{dt}=k(T-A)\)

Where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.

We are given that the coffee cools from 100°C to 90°C in one minute at a room temperature A of 25°C.

And we want to find the temperature of the coffee after four minutes.

First, solve the differential equation. Multiply both sides by dt and divide both sides by (T - A). Hence:

\(\displaystyle \frac{dT}{T-A}=k\, dt\)

Take the integral of both sides:

\(\displaystyle \int \frac{dT}{T-A}=\int k\, dt\)

Integrate:

\(\displaystyle \ln\left|T-A\right| = kt+C\)

Raise both sides to e:

\(|T-A|=e^{kt+C}=Ce^{kt}\)

The temperature of the coffee T will always be greater than or equal to the room temperature A. Thus, we can remove the absolute value:

\(\displaystyle T=Ce^{kt}+A\)

We are given that A = 25. Hence:

\(\displaystyle T=Ce^{kt}+25\)

Since the coffee cools from 100°C to 90°C, the initial temperature of the coffee was 100°C. Thus, when t = 0,T = 100:

\(100=Ce^{k(0)}+25\Rightarrow C=75\)

Hence:

\(T=75e^{kt}+25\)

We are given that the coffee cools from 100°C to 90°C after one minute at a room temperature of 25°C.

So, T = 90 given that t = 1. Substitute:

\(90=75e^{k(1)}+25\)

Solve for k:

\(\displaystyle e^k=\frac{13}{15}\Rightarrow k=\ln\left(\frac{13}{15}\right)\)

Therefore:

\(\displaystyle T=75e^{\ln({}^{13}\! /\!{}_{15})t}+25\)

Then after four minutes, the temperature of the coffee will be:

\(\displaystyle \begin{aligned} \displaystyle T&=75e^{\ln({}^{13}\! /\!{}_{15})(4)}+25\\\\&\approx 67^\circ\text{C}\end{aligned}\)

Hence, our answer is B.

The given indefinite integral evaluates to ∫(2√2 + #de) = (4/3) (2\(^3^/^2\)) + e + C.

The given indefinite integral is: ∫(2√2 + #de).

We know that the integral of √x is (2/3) x\(^3^/^2\)

The given integral can be re-written as follows: ∫(2√2 + #de) = 2∫√2 #de + ∫#de.

Since the integral of a constant term is just the product of the constant and the variable, the second integral is given by: ∫#de = e + C, where C is the constant of integration.

On the other hand, the first integral can be calculated using the integral of √x, which is given by: (2/3) x\(^3^/^2\)+ C.

Putting this back into the original integral, we have:

∫(2√2 + #de) = 2∫√2 #de + ∫#de

= 2(2/3) (2\(^3^/^2\)) + e + C

= (4/3) (2\(^3^/^2\))) + e + C.

In summary, the given indefinite integral evaluates to ∫(2√2 + #de) = (4/3) (2\(^3^/^2\)) + e + C.

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SOLUTION

The given graph is shown

From the graph the lengths AC and CB are equal.

Hence the triangle is Isosceles.