Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 14 g of hexane is mixed with 88. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answer:

The correct answer is - 75 grams.

Explanation:

Half-life is the amount of time that is used by the given amount of substance or element to make it half of the initial amount of a particular radioactive substance.

Equation for alpha decay for radon

\(^222_{86}Rn\Rightarrow^{218}_{84}Po  \)

we need to calculate the left amount of radon after given time

using formula half life

\(N(t)=N_{0}e^{-\lambda t}\)

\(\lambda =\dfrac{0.693}{3.82}\)

\(\lambda=0.1814\)

\(N(3.82)=150\times e^{-0.1814\times3.82}\)

\(N(3.82)=75.0\ g\)

Thus, the left amount of radon is - 75 grams.

By diluting the acid during the titration, the concentration of the acid will be lower than intended, leading to an underestimated value of Ka.

What is titration and why is it performed?

Titration is a laboratory technique used to determine the concentration of a substance in a solution by reacting it with a known concentration of another substance (known as the titrant) of known volume. Titration is commonly used to determine the concentration of an unknown substance in a solution.

If you titrated a weak acid and left a significant amount of water in the buret, it would dilute the acid and affect the concentration of the acid used in the titration. This, in turn, would impact the calculated value of the acid's dissociation constant (Ka).

The dissociation constant (Ka) is a measure of the extent to which an acid dissociates or ionizes in water. It is determined by the equilibrium concentration of the acid and its conjugate base. By diluting the acid during the titration, the concentration of the acid will be lower than intended, leading to an underestimated value of Ka.

Therefore, by diluting the acid during the titration, the concentration of the acid will be lower than intended, leading to an underestimated value of Ka.

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The maximum possible potential difference between the two ends of the tether is approximately 2.06 × 10³ V. Thus, the correct answer is 2.06 × 10³ V.

The maximum possible potential difference (V) between the two ends of the tether can be calculated using the formula:

V = B * L * v

where B is the magnetic field strength, L is the length of the wire, and v is the velocity of the wire.

In this case, we have the following values:

B = 1.31 × 10⁻⁵ T (magnetic field strength)

L = 20.0 km = 20,000 m (length of the wire)

v = 7.86 × 10³ m/s (velocity of the wire)

Plugging these values into the formula, we can calculate the potential difference:

V = (1.31 × 10⁻⁵ T) * (20,000 m) * (7.86 × 10³ m/s)

Calculating this value:

V ≈ 2.06 × 10³ V

Therefore, the maximum possible potential difference between the two ends of the tether is approximately 2.06 × 10³ V. Thus, the correct answer is 2.06 × 10³ V.

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Answer:

h20

Explanation:

hay una cosa llamada google usarlo dummby!

Answer:

4

Explanation:

none of them

they are compounds and mixtures

Answer:

4. none of them

Explanation:

Water is a compound.

Air is a mixture.

Soil is a mixture.

None of them are elements.

Answer:

Zero

Explanation:

The oxidation state of an element that is not involved in bonding is zero. An atom in its free and uncombined state has zero oxidation number.

The extent of oxidation of each atom of the elements in a molecular formula or formula unit or an ionic radical is given by the oxidation number.

Answer:

I do not know. I think there is .as we are the living creatures in this earth. maybe aliens are creatures of other planet or galaxies. I am not scientists to prove it.sorry.

Answer:

don't know just supporting u

Answer:

Its electrical to thermal energy

Explanation:

Answer:

Carbon atoms each form four strong bonds. The bonds are covalent (atoms share electrons). This gives graphite its characteristic properties such as high melting and boiling points, good electrical conductivity, and softness. Use as pencil 'lead', as a lubricant in oil, furnace linings, electrodes, neutron moderators in nuclear power stations.

Diamond atoms each form three strong covalent bonds in the same layer and one weak bond to an atom in another layer.  Diamonds have a high level of hardness, thermal conductivity, and optical dispersion. It is used for jewellery, oil-well drills, abrasives and cutting tools.

Explanation:

Structure of Graphite and Diamond (attached below):

Answer:

C. 1,500 kg · m/s

Answer: False

Explanation: The stronger oxidizing agent, and stronger reducing agent are the reactants.

The given statement is false , for a spontaneous redox reaction, the reactants are stronger oxidizing and reducing agents than the products.

Redox reactions comprise of two parts a reduced part and an oxidized part, which occur simultaneously . The part which is reduced gain electrons and hence there is a increase in oxidation state of the species.

While, the part which is oxidized looses electrons and hence there is a decrease in oxidation state of the species.During redox reactions, there is no net change in the number of electrons . Electrons which are given off in oxidation are used up in reduction.

The ion or molecule which accepts electrons is called as oxidizing agent while the ion or molecule which donates electrons is called as a reducing agent.

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The ionic substance strontium oxide, SrO, forms from the reaction of strontium metal with molecular oxygen.

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Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.

Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)

The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).

HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1

= 1.0x10⁻⁷,

Ka2 = 1.0x10⁻¹⁹

To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.

It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.

To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0Change -x +x +x

Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹

= x² / (6.89x10⁻² - x)

Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)

Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]

x = 2.31x10⁻¹¹ M

Thus, [S²⁻] = 2.31x10⁻¹¹ M

To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0

Change -x +x +x

Equilibrium (6.89x10⁻² - x) x x

Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷

= x(6.89x10⁻² - x) / (6.89x10⁻²)

Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)

Thus: x = 1.66x10⁻⁸ M[H₃O⁺]

= 1.66x10⁻⁸ M

Then, pH = -log[H₃O⁺]

= -log(1.66x10⁻⁸)

= 7.78 (rounded to two decimal places)

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Foliar burn is a plant condition caused by the application of fertilizer in excess. It appears as a leaf-tip or marginal burn, with the burning and dying of plant tissues, and the leaves will also display the formation of necrotic tissue and spots.

This happens because of the process by which particles of fertilizer can cause foliar burn.Foliar burn occurs when a fertilizer solution is applied to the plant’s foliage, and the solution stays on the leaves for too long. The particles of fertilizer can create an osmotic pressure difference across the leaf membrane, which leads to an imbalance of water between the leaf cells and the external environment.

This imbalance causes the plant cells to leak out, leading to cell death. As the plant cells die, the leaves start to turn brown and become brittle. In some cases, the leaves will fall off entirely.A long answer to your question can be: The process by which particles of fertilizer can cause foliar burn is the imbalanced water between the leaf cells and the external environment.

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In a face-centered cubic (fcc) unit cell, there are four atoms located at the corners of the unit cell and an additional atom located at the center of the unit cell.

These atoms are arranged in such a way that the [111] direction passes through the center of each face of the unit cell. Therefore, there are four atoms that are centered on the [111] direction within the fcc unit cell. This arrangement of atoms is characteristic of the fcc crystal structure, which is commonly found in metals such as aluminum, copper, and gold.

The [111] direction is an important crystallographic direction in fcc materials as it is the direction of densest packing of atoms and is often used as a reference direction in materials science.

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Ideal gas law is valid only for ideal gas not for vanderwaal gas. Combined Boyle's and Charles' gas law is used here. The  new temperature of gas is 79.3°C.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically,

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

P₁V₁/T₁ = P₂V₂/T₂

{ (752 mmHg) (8.29 L )} ÷296K ={ ( 358 mmHg) (11.39 L)} ÷T₂

T₂ = 79.3°C

Therefore the new temperature of  gas is79.3°C.

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The pH of the 0.400 M sodium formate solution is approximately 1.90, which is closest to option (A) 2.07.

The condition for the separation of formic corrosive (HCHO₂) is:

HCHO₂ + H₂O ↔ H₃O⁺ + CHO²⁻

The balance steady articulation for this response is:

Ka = [ H₃O⁺][CHO²⁻]/[HCHO₂]

From the given data, we realize that the Ka of formic corrosive is 1.8 x 10^-4. We likewise know that sodium formate (NaCHO₂) is a salt of formic corrosive and it will separate totally in water to shape Na+ and CHO²⁻particles. The CHO²⁻ particle will respond with water to frame HCHO₂ and Goodness particles.

NaCHO₂(s) ↔ Na+(aq) + CHO²⁻(aq)

CHO²⁻(aq) + H2O(l) ↔ HCHO₂(aq) + Gracious (aq)

Since NaCHO₂ totally separates in water, we can expect that [CHO²⁻] = [NaCHO₂] = 0.4 M.

Let x be the centralization of  H₃O⁺ particles shaped in the response. Then, [OH-] = \(1.0 x 10^-14/x\).

Utilizing the harmony consistent articulation, we can compose:

\(1.8 x 10^-4 = x^2/(0.4 - x)\)

Since x << 0.4, we can surmised (0.4 - x) to be 0.4.

\(1.8 x 10^-4 = x^2/0.4\)

\(x = sqrt(1.8 x 10^-4 x 0.4) = 0.0126 M\)

pH = - log[H3O+] = - log(0.0126) = 1.90

Consequently, the pH of the 0.400 M sodium formate arrangement is roughly 1.90, which is nearest to choice (A) 2.07.

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Answer:

Condensation is the change of the physical state of matter from the gas phase into the liquid phase.

Answer:

the conversion of a vapour or gas to a liquid is defined as condensation.

When air surfaces the earth, the density of the air warms up. This is because the earth surface heats up the air by the process of convection. As the sun's radiation reaches the earth, the earth's surface absorbs it and in turn, heats the surrounding air molecules.

These molecules then rise as they become less dense than the cooler air around them. This warm air then moves upwards and away from the surface of the earth, allowing cooler air to take its place.The heating of the air surface affects the air density, which causes the air to expand. When the air is warmed up, it becomes less dense, and its molecules move farther apart. The opposite happens when the air cools down, and its density increases. As the air becomes less dense, it rises, and the cooler, denser air flows in to replace it.

The warming up of the earth's air surface due to the sun's radiation has a significant effect on weather patterns and global climate change. It is one of the reasons why the earth's temperature is increasing, and this increase in temperature has a range of implications, including rising sea levels, melting ice caps, and more frequent extreme weather events.

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1) The substances present before the reaction has occurred.

2) The substances formed after the reaction has occurred.

3) A negatively charged ion, typically non-metal, that gains electrons to become stable.

4) A positively charged ion, typically metal, that losses electrons to become stable.

5) A chemical reaction in which the reactants absorb heat energy from the surroundings to form products.

6) A chemical reaction in which the reactants release heat energy into the surroundings to form products.

The skateboarder will have the most kinetic energy at point X and Y.

The energy an object possesses as a result of its motion is known as kinetic energy. With a decrease in object speed, the kinetic energy drops.

K.E = ¹/₂mv²

The skateboard will be moving at its fastest at points X and Y in the following diagram. Speed and kinetic energy are inversely correlated.

The skateboarder will therefore have the greatest kinetic energy at points X and Y, we can deduce.

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

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Answer:

X and Y

Explanation:

Edge said so

The mass of AI needed to react with 72 g of HCI is 54 g.

To determine the mass of AI needed to react with 72 g of HCI, we can use the stoichiometry of the balanced chemical equation you provided:

2AI + 6HCI --> 2AICI3 + 3H

From the equation, we can see that 2 moles of AI react with 6 moles of HCI to produce 2 moles of AICI3.

This means that the mole ratio between AI and HCI is 2:6 or 1:3.

Given the molar mass of HCI is 36 g/mol, we can calculate the number of moles of HCI in 72 g of HCI by dividing 72 g by the molar mass of HCI:

Number of moles of HCI = mass of HCI / molar mass of HCI

Number of moles of HCI = 72 g / 36 g/mol

Number of moles of HCI = 2 moles

Since the mole ratio between AI and HCI is 1:3, the number of moles of AI needed to react with 2 moles of HCI is also 2 moles.

Now, we can use the molar mass of AI, which is 27 g/mol, to calculate the mass of AI needed to react with 2 moles of HCI:

Mass of AI = number of moles of AI × molar mass of AI

Mass of AI = 2 moles × 27 g/mol

Mass of AI = 54 g

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Boyle's law: Inverse relationship between P and V. Charles's law: Direct relationship between V and T. Ideal gas law: Linear relationship between P and T. Moles and volume are directly proportional.

Here are the labelled graphs for the variation of different properties of an ideal gas:

(a) The variation of P (pressure) with V (volume):

In an ideal gas, when the volume decreases, the pressure increases, and vice versa. This relationship is known as Boyle's law. The graph of pressure (P) versus volume (V) is inversely proportional and can be represented as follows:

```

    P

    |        o

    |       /

    |      /

    |     /

    |    /

    |   /

    |  /

    | /

    |/

------------------- V

```

(b) The variation of V (volume) with T (temperature):

According to Charles's law, the volume of an ideal gas is directly proportional to its absolute temperature. The graph of volume (V) versus temperature (T) is a straight line passing through the origin:

```

V

|

|

|

|         o

|        /

|       /

|      /

|     /

|    /

|   /

|  /

| /

|/

------------------- T

```

(c) The variation of P (pressure) with T (temperature):

The relationship between pressure and temperature in an ideal gas is described by the ideal gas law. When temperature increases, the pressure of an ideal gas also increases, assuming constant volume. The graph of pressure (P) versus temperature (T) is a linear relationship:

```

 P

 |

 |

 |         o

 |        /

 |       /

 |      /

 |     /

 |    /

 |   /

 |  /

 | /

 |/

------------------- T

```

(d) The variation of n (number of moles) with V (volume):

In an ideal gas, the number of moles is directly proportional to the volume, assuming constant pressure and temperature. The graph of the number of moles (n) versus volume (V) is a straight line passing through the origin:

```

n

|

|

|

|         o

|        /

|       /

|      /

|     /

|    /

|   /

|  /

| /

|/

------------------- V

```

These graphs represent the relationships described by Boyle's law, Charles's law, the ideal gas law, and the direct proportionality between moles and volume in an ideal gas.

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Gas chromatography can be used to tentatively identify a compound from its retention time. D. Retention time.

What is chromatography? Chromatography is a method of separating out chemicals from a mixture by moving them through a material. Chromatography is a popular method for identifying and separating different chemical components in a complex mixture. The working principle of Chromatography is that the components of a mixture are separated based on their ability to adhere to a surface, i.e. the stationary phase, and their capacity to move across that surface, i.e. the mobile phase.

Gas chromatography is a powerful analytical method for the separation and quantitation of organic compounds based on their molecular characteristics. Gas chromatography is an essential method used in analytical chemistry for the qualitative and quantitative analysis of mixtures of substances. In gas chromatography, the components in a mixture are vaporized and then separated based on their distribution between a stationary liquid phase and a mobile gas phase that passes through the stationary phase. Each component is identified based on its retention time, which is the amount of time it takes for the component to travel through the column and reach the detector. Therefore, a compound can tentatively be identified by gas chromatography from its retention time. Answer: D. Retention time.

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The velocity of electron from odium is 6.86 × 10 ⁻¹⁹ and from potassium is 7.35 × 10⁵ .

hf = φ₀ + Eₓ

where h is planks constant , f is frequecy of light , φ₀ is ionisation potential

and  Eₓ is kinetic energy of emitted electron

f = c/λ

where c is speed of light and λ is wavelength of radiation

so Eₓ = hc/λ -  φ₀

h=6.63×10⁻³⁴  joule/hertz

so  hc/λ = (6.63×10⁻³⁴×3×10⁸)/(290×10⁻⁹)

=> (19.89× 10⁻²⁶)/(2.9 × 10⁻⁷)

=> 19.89/2.9 × 10 ⁻¹⁹

=> 6.86 × 10 ⁻¹⁹

Eₓ = 1/2×m×v²

=> v = √2Eₓ/m

where m= mass of electron and v is velocity of electorn

for velocity of elctron in odium we have:

Eₓ = 6.86 × 10 ⁻¹⁹ - 3.68 × 10 ⁻¹⁹

=> 3.18 × 10 ⁻¹⁹

so v = √2Eₓ/m

m = 9.1 × 10⁻³¹

so v = √2×3.18 × 10 ⁻¹⁹/9.1 × 10⁻³¹

=> v = √ 0.7 × 10¹²

=> v = √ 70 × 10¹⁰

=> 8.36 × 10⁵ m/s

so velocity of electron from odium is  8.36 × 10⁵ m/s

(ii) we need to find speed of electron from potasium

Eₓ = 6.86 × 10 ⁻¹⁹ - 4.41 × 10 ⁻¹⁹

=> 2.45 × 10 ⁻¹⁹

so v = √2Eₓ/m  

m = 9.1 × 10⁻³¹

so v = √2×2.45 × 10 ⁻¹⁹/9.1 × 10⁻³¹

=> v = √ 0.54 × 10¹²

=> v = √ 54 × 10¹⁰

=> 7.35 × 10⁵ m/s

so velocity of electron from potaium is  7.35 × 10⁵ m/s

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Answer:

Basically, a variable is any factor that can be controlled, changed, or measured in an experiment. It's anything that can be changed in the experiment.

Explanation:

Scientific experiments have several types of variables. The independent and dependent variables are the ones usually plotted on a chart or graph, but there are other types of variables you may encounter. The presence/absence of the chemical is the independent variable. The health of the (ex:)rat (whether it lives and can reproduce) is the dependent variable.

Answer:

1. The budgeted sales for July are $1,540,000.

To find the budgeted sales for July, we look at the given information. The budgeted unit sales for July are 22,000 units. The budgeted selling price per unit is $70.

To calculate the budgeted sales for July, we multiply the budgeted unit sales by the selling price per unit:

Budgeted sales for July = Budgeted unit sales for July * Selling price per unit

Budgeted sales for July = 22,000 units * $70

Budgeted sales for July = $1,540,000

2.  The expected cash collections for July are $616,000 (in the month of the sale) and $924,000 (in the following month).

To find the expected cash collections for July, we need to consider the information provided.

Forty percent of credit sales are collected in the month of the sale, and 60% are collected in the following month.

We know the budgeted sales for July is $1,540,000.

To calculate the expected cash collections for July, we need to determine the cash collected in the month of the sale and the cash collected in the following month.

Cash collected in the month of the sale

= 40% of budgeted sales for July

= 40/100 * $1,540,000

= $616,000

Cash collected in the following month = 60% of budgeted sales for July

= 60/100 * $1,540,000

= $924,000

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