Lions eat antelopes. Antelopes eat plants.
A lion is eating an antelope.
Which of these statements correctly describes what is happening when a lion eats an antelope?
A carnivore is eating its prey
B herbivore is eating its prey
C predator is eating a carnivore
D prey is eating a herbivore

First we need to calculate the number of moles of K₂SO₄ (potassium sulfate) in 25.0 mL of 0.255 M solution.

a) 0.255 moles K₂SO₄ / 1 L solution * 0.0250 L solution = 0.006375 moles K₂SO₄

Therefore, there are 0.006375 moles of K₂SO₄ present in 25.0 mL of this solution.

b) To calculate the volume of 0.255 M K₂SO₄ required to supply 0.0600 mol of K₂SO₄:

0.0600 moles K₂SO₄ / 0.255 moles per L = 0.235 L

0.235 L * 1000 mL/L = 235 mL

Therefore, 235 mL of this solution are required to supply 0.0600 mol of K₂SO₄.

(c) To prepare a 0.800 M K₂SO₄ solution from 1.50 L of 0.255 M K₂SO₄ solution:

Let x be the mass of K₂SO₄ required in grams. We can use the formula:

M₁V₁ = M₂V₂

where M₁ will represent initial concentration, V₁ will represent  the initial volume, M₂ will represent  the final concentration, and V₂ will represent the final volume.

0.255 M * 1.50 L = 0.800 M * 1.50 L + x grams / (174.26 g/mol)

x = (0.255 M * 1.50 L - 0.800 M * 1.50 L) * 174.26 g/mol = 34.90 g

Therefore, 34.90 grams of K₂SO₄ are needed to prepare 1.50 L of a 0.800 M K₂SO₄ solution.

(d) To calculate the molarity of the diluted solution:

M₁V₁ = M₂V₂

The initial volume is 40.0 mL, and the final volume is 135 mL, which means that the dilution factor is:

V₂/V₁ = 135 mL / 40.0 mL = 3.375

The final concentration can be calculated as:

M₂ = M₁ / (V1/V2) = 0.255 M / 3.375 = 0.0754 M

Therefore, the molarity of the diluted solution is 0.0754 M.

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Answer:

2.8 moles

Explanation:

The number of water needed to react with 8.4 moles of NO₂ is equal to 4.2 moles.

A mole can be defined as a scientific unit that is used to determine a large number of atoms, molecules, and ions. The mass of 1 mole of any chemical element is atomic mass and that of any chemical compound is molar mass.

The number of particles in one mole is equal to 6.023 × 10 ²³ which is known as Avogadro’s constant.

The balanced chemical equation of water and nitrogen dioxide NO₂ is:

\(H_2O + 2NO_2\longrightarrow HNO_3 +HNO_2\)

From the equation, we can say that two moles of nitrogen dioxide (NO₂) react with one mole of water.

8.4 moles of nitrogen dioxide react with water = 8/4/2 = 4.2 mol

Therefore, 4.2 moles of water are needed to react with 8.4 moles of nitrogen dioxide NO₂.

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The question pertains to solubility equilibrium and involves the determination of the solubility product constant for cobalt(II) hydroxide based on the measured concentration of hydroxide ions in a saturated aqueous solution.

Solubility product constants (Ksp) are equilibrium constants that describe the degree to which a sparingly soluble ionic compound dissociates in a solution. Cobalt(II) hydroxide is a sparingly soluble ionic compound that forms a precipitate in water. The Ksp for cobalt(II) hydroxide can be calculated using the measured concentration of hydroxide ions in a saturated solution and the stoichiometry of the reaction.

The Ksp represents the product of the concentrations of the dissociated ions at equilibrium, and its value can be used to predict the extent of precipitation or dissolution of the compound under different conditions. Understanding solubility equilibria is important in many areas of chemistry, including environmental chemistry, materials science, and geochemistry, as it allows for the prediction of the solubility and precipitation behavior of ionic compounds in natural and man-made systems.

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The solubility product constant for cobalt(II) hydroxide is approximately 2.67×10-14.

To determine the solubility product constant (Ksp) for cobalt(II) hydroxide using the given OH- concentration, we will follow these steps:

1. Write the balanced chemical equation for the dissolution of cobalt(II) hydroxide:
Co(OH)2(s) ⇌ Co2+(aq) + 2OH-(aq)

2. Determine the stoichiometric relationship between Co2+ and OH- ions:
1 mole of Co(OH)2 produces 1 mole of Co2+ ions and 2 moles of OH- ions.

3. Calculate the concentration of Co2+ ions in the solution:
Since the concentration of OH- ions is 8.10×10-6 M, and the stoichiometric ratio is 1:2, we can determine the Co2+ concentration by dividing the OH- concentration by 2:
Co2+ concentration = (8.10×10-6 M) / 2 = 4.05×10-6 M

4. Calculate the solubility product constant (Ksp):
Ksp = [Co2+][OH-]^2
Ksp = (4.05×10-6)(8.10×10-6)^2
Ksp ≈ 2.67×10-14

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Answer

D

Explanation:

They take up usable forms of nitrogen found in soil

Answer:

d

Explanation:

i took the test

Answer:

D

Explanation:

The cell wall

All reactions that work to hydrolyze large biochemical substances into smaller subcomponents is referred to as catabolism.

Metabolism is the sum of all chemical reactions that is occurring in an organism. A metabolic pathway is a sequence of reactions that is used to produce a particular product. Metabolic pathways are usually mediated by enzymes, which help speed the rate of reaction of each step by lowering the activation energy.

The process of breaking down large molecules into smaller ones is called catabolism. Catabolism breaks bonds and releases energy. Anabolism, on the other hand, is the term that describes the process of building larger molecules from the smaller ones. Anabolism forms new bonds and also requires the input of energy.

Anabolic and catabolic pathways are often coupled to make the overall energetics of a process to be favorable.

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Increased water temperature is most likely occur downstream after logging.

When the tree roots are no longer holding the soil in place, soil erosion will increase. The stream's turbidity will rise as a result, and the temperature will rise as well.

Due to soil compaction and decreased transpiration, clear-cutting frequently lowers soil water-holding capacity and root strength. In addition, the loss of the forest cover leaves the soil surface vulnerable to intense precipitation and wide temperature changes.

When trees are destroyed through burning, cutting, or other means, they release carbon rather than absorbing it. 15% of all greenhouse gas emissions are attributable to deforestation and forest degradation.

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The correct abbreviation for each metric unit is:

Kilogram - kg, Milliliter - ml, Kilometer- Km, Meter- m, Millimeter - mm, Centimeter - cm, Gram - g,  Liter - L, and Milligram - mg.

The metric system can be described as a system of measurement that succeeded the decimalized system based on the meter.  Each of the fundamental dimensions can be expressed by a single base unit of measure.

For quantities derived from the base units of the system, units derived from the base units are used such as the square meter being the derived unit for the area, a quantity derived from length.

Metric units can be described as units based on the meter, gram, or second and decimal multiples or sub-multiples of these. The units of the International System of Units (SI). By extension, they involve units of electromagnetism from the CGS units and SI units systems.

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Answer:

its carbon

Explanation:

iron oxide + carbon = iron + carbon dioxide

as coke(mainly carbon) is a raw material gone into a blast furnace displaces iron.

The melting point of the impure substance is lower than the melting point of a pure substances.

Pure substances are made up of single type of atoms. Impure substances are made up of different type of atoms. The substances are comprised of two types of chemical composition. one is homogeneous composition and other is heterogeneous composition. pure substances have homogeneous chemical composition. Impure substances have  heterogeneous chemical composition.  Pure substances cannot be broken down to simpler substances. Impure substances can be broken down into purer forms by using separation or purification techniques, like filtration, sublimation. The pure substances have fixed structure and impure substances don't have any fixed structure. The melting point of pure substances have higher than the impure substances.

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The change in freezing point when the same solute is dissolved in water instead of stearic acid would be 1.45°C.

To determine the change in freezing point of the solution when the same solute is dissolved in water instead of stearic acid, we can use the freezing point depression equation:

ΔTf = Kf x m

Where ΔTf is the change in freezing point, Kf is the freezing point depression constant, and m is the molality of the solution.

Given that the freezing point depression of the solute in stearic acid is 3.5°C, we can rearrange the equation to solve for the molality:

m = ΔTf / Kf

m = 3.5°C / 4.5°C/molal

m = 0.78 molal

Now, we can use this molality and the freezing point depression constant for water (1.86°C/molal) to determine the change in freezing point when the same solute is dissolved in water:

ΔTf = Kf x m

ΔTf = 1.86°C/molal x 0.78 molal

ΔTf = 1.45°C

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A cell membrane is more flexible than a brick wall. Why might many cells benefit from a flexible cell membrane because it allows them to survive in and out of the cell.

The cell is surrounded by a membrane called as cell membrane . cell membrane is a semipermeable membrane. semipermeable membrane is the type of membrane which allows solvent particles to pass through it . or some molecules or ion . Therefore , many cells benefited by cell membrane as they can pass through it.

Thus, A cell membrane is more flexible than a brick wall. Why might many cells benefit from a flexible cell membrane because it allows them to survive in and out of the cell.

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The radius of an atom of a chemical element is a measure of the atom's size. The meaning of it is said to be the typical distance, which is from the center of the nucleus to the boundary of the atom, which is surrounding the electrons.

Explanation :

To arrange the following in order of increasing radius: O2-, F-, Ne, Rb, and Br-, follow these steps:

1. Determine the number of protons and electrons for each species.
2. Compare their positions on the periodic table.

Here's a breakdown of the species with their protons and electrons:
- O2-: 8 protons, 10 electrons
- F-: 9 protons, 10 electrons
- Ne: 10 protons, 10 electrons
- Rb: 37 protons, 37 electrons
- Br-: 35 protons, 36 electrons

Now, let's compare their positions on the periodic table:
- O2-, F-, and Ne are all in the same period (row), so we'll compare their atomic numbers (protons) to determine their size. As we move across a period from left to right, the atomic radius decreases, so the order will be O2- > F- > Ne.
- Rb and Br- are in the same group (column). Going down a group, the atomic radius increases, so Rb > Br-.

Finally, we can combine these orders to get the overall order of increasing radius: O2- < F- < Ne < Br- < Rb.

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Answer:

Final temperature, T2 = 381.28°C

Explanation:

Given the following data;

Mass = 6.23 g

Initial temperature = 30.4°C

Heat capacity = 282 J

Specific heat capacity = 0.129 J/g°C

To find the final temperature;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

\( dt = \frac {Q}{mc} \)

Substituting into the equation, we have;

\( dt = \frac {282}{6.23*0.129} \)

\( dt = \frac {282}{0.8037} \)

dt = 350.88°C

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 350.88 + 30.4

Final temperature, T2 = 381.28°C

Answer:

75,900 g

Explanation:

m=d×v

(1.38g/cm^3) × (55,000)

Among the given options, the most likely to contain trans fatty acids would be partially hydrogenated vegetable oil.

Trans fatty acids are commonly found in processed foods that use partially hydrogenated oils as an ingredient. Partial hydrogenation is a process that converts liquid vegetable oils into solid or semi-solid fats, thereby increasing their shelf life and stability.

However, this process also generates trans fatty acids as a byproduct. Trans fats have been linked to various health issues, including heart disease. To make healthier choices, it is advisable to avoid products that list partially hydrogenated vegetable oil on their food labels.

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Answer:

two hydroxide ions

Explanation:

Ba(OH)2 in aqueous solution can provide two hydroxide ions per molecule.

There are 1.392 x \(10^{24\) hydroxide ions in 198g of barium hydroxide.

Step 1: Calculate the molar mass of \(Ba(OH)_2\).

Ba (barium) has a molar mass of 137.33 g/mol.

O (oxygen) has a molar mass of 16.00 g/mol.

H (hydrogen) has a molar mass of 1.01 g/mol.

Molar mass of \(Ba(OH)_2\) = (137.33 g/mol) + 2 * (1.01 g/mol) + 2 * (16.00 g/mol)

= 171.33 g/mol

Step 2: Calculate the number of moles of \({\text}Ba(OH)_2\).

Number of moles = Mass (in grams) / Molar mass

                             = 198 g / 171.33 g/mol

                             = 1.157 moles

Step 3: Consider the stoichiometry of \({\text}Ba(OH)_2\).

The chemical formula of barium hydroxide is \({\text}Ba(OH)_2\), which means that for each mole of \({\text}Ba(OH)_2\), there are two moles of hydroxide ions (OH^-).

Step 4: Calculate the number of hydroxide ions.

Number of hydroxide ions = Number of moles of \({\text}Ba(OH)_2\) * 2

                                            = 1.157 moles * 2

                                            = 2.314 moles

Now, Actual number of hydroxide ions

= 2.314 moles * 6.022 x \(10^{23\) ions/mol

= 1.392 x \(10^{24\) hydroxide ions

So, 1.392 x \(10^{24\) hydroxide ions in 198g of barium hydroxide.

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The density of the metal is 1.167 g/ml.

The density of the metal can be calculated using the formula for density, ρ:

ρ = m /v

where ρ is the density, m is the mass, and v is the volume.

In this case, the mass of the metal is 31.5g and the volume can be determined by subtracting the initial volume (51mL) from the final volume (78mL) of water in the graduated cylinder. Thus, the volume of the metal is 27mL.

Using the formula, the density of the metal is then:

ρ = 31.5 g / 27mL

ρ = 1.167 g/ml

This means that 1 mL of the metal has a mass of 1.167g. Density is an important property of materials, as it affects other properties such as buoyancy. Generally, materials with a higher density will sink in a liquid, while those with a lower density will float.

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Answer:

. Increasing the volume of the container

Explanation:

Answer:

BY : EDLYN MORENO

(b) false

It is not ok to pour it back in the bottle

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Answer:

\( \frac{(179.6g) \times (1mol)}{63g} = 2.8 \approx3 \: mol \: HNO_3\\ \frac{4 mol H_2O \times 3}{8 mol HNO_3}=1.5 mol\\ H_2O\\1.5 mol H2O × 175.6g H_2O / 1 mol H_2O = 263. 4g H_2O \)

Answer:

Compounds are substances composed of two or more elements chemically combined that can be separated into simpler substances only by chemical means. Water, for example, is a compound because pure water is composed of only H2O molecules.

Pls choose me as brainliest!

Answer:

oxygen and glucose

Explanation:

science

Answer:

the correct answer is B. far left

Explanation:

i just got it right on edge 2020 :p

Answer: conjugate base of a weak acid

Explanation: If the anion is a conjugate base of a weak acid, the solution would be basic. This is because weak acids do not produce enough hydrogen ions in the solution so does not really affect the acidity, so the conjugate base can react with water in the solution to produce a basic solution.

The element is Neon
The protons is the same as the atomic number (10 protons)
The electrons are the same as the number of protons in a neutral atom (10 electrons)
The neutrons can be found by subtracting the protons from the atomic mass (22-10=12 neutrons)

To recover all of the copper in analytically pure form. This experiment is intended to provide a quantitative assessment of your unique laboratory proficiency in performing some of these processes.

It is ductile and malleable, as well as a good conductor of heat and electricity. It is softer than zinc and can be highly polished. It is in the same periodic table family as silver and gold. Copper has no chemical activity.

Metathesis reactions and redox reactions You will recover the copper sample by using these reactions.

When two ionic compounds' pieces are exchanged, two new compounds are formed. Double replacement reactions, double displacement reactions, exchange reactions, and metathesis reactions are all examples of these reactions.

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