Line BD is tangent to a circle with diameter AB. Explain why the measure of angle BCA must equal the measure of angle ABD.

The value of x , y and z in the parallel line is 50 degrees.

When parallel lines are crossed by a transversal line, angle relationships are formed such as vertically opposite angles, alternate interior angles, alternate exterior angles, adjacent angles, corresponding angles etc.

Therefore, let's use the angle relationships to find the angle, x, y and z as follows:

Therefore,

x = 360 - 310(sum of angles in a point)

x = 50 degrees

Therefore,

x = y(alternate interior angles)

Alternate interior angles are congruent.

Hence,

y = 50 degrees

Therefore,

x = z(alternate interior angles)

z = 50 degrees.

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The Area of the composite figure = area of the rectangle + area of the triangle = 148.5 cm².

The figure formed by the arrow can be decomposed into a rectangle and a triangle.

The area of the composite figure = area of the rectangle + area of the triangle.

Find the area of the rectangle:

Length = 12 cm

Width = 11 cm

Area of the rectangle = (length)(width) = (12)(11)

Area of the rectangle = 132 cm²

Find the area of the triangle

Base = 11 cm

Height = 15 - 12 = 3 cm

Area of the triangle = 1/2(b)(h) = 1/2(11)(3)

Area of the triangle = 16.5 cm²

Area of the composite figure = area of the rectangle + area of the triangle = 132 + 16.5 = 148.5 cm².

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Answer:

Step-by-step explanation:

Answer:

35000

Step-by-step explanation:

Since all numbers above 50 round to a hundred, we see that the number 34,971.22 has the tens digit over 5. We can then round this to 35,000.

Answer:

1840 = 2x, where  x = jazz tickets

Step-by-step explanation:

Since twice as many rock concert tickets were sold, and 1840 were sold, that means that 1840 is equal to twice the number of jazz concert tickets.

Step-by-step explanation:

like they don't know, and so we don't know and so what do we do when ask that question as overtime and somewhere else

Answer:

a) 7³

b) \(11^{20}\)

c) \(4^{8}\)

d) \(6^9\)

e) \(12^{14}\)

f) \(3^9\)

g) \((0.173)^{11}\)

h) 0.87²

i) (\(\frac{5}{2}\\\))²

Step-by-step explanation:

The exponents are subtracted when they are dividing, are summed when it's multiplication, and are multiplied when it's between parenthesis.

Answer:

Follow the steps below

Step-by-step explanation:

a. When dividing with the same base, (7 in this case), subtract the exponents. So, 7^6 / 7^2 = 7^6-2 = 7^4

b. (11^4)^5 becomes 11^4*5 = 11^20

c. Once again, same base (4 this time), so add the exponents. 4^2 * 4^6 = 4^2+6 = 4^8

d. So, 6 is technically 6^1, so 6 * 6^8 = 6^1 * 6^8 = 6^9

e. (12^2)^7 is 12^2*7 = 12^14

f. (3^10) / 3 = 3^10 / 3^1 = 3^10-1 = 3^9

g. (0.173)^9 * (0.173)^2 = 0.173^9+2 = 0.173^11

h. (0.87^5) / (0.87^3) = 0.87^5-3 = 0.87^2

i. (5/2)^8 / (5/2)^6 = (5/2)^8-6 = (5/2)^2

1. The limit of h(x) + f(x) as x approaches a is 4., 2. The limit of h(x) - f(x) as x approaches a is 4., 3. The limit of h(x) * g(x) as x approaches a is -4., 4. The limit of f(x) / h(x) as x approaches a is 0., 5. The limit of g(a) as x approaches a is -1., 6. The limit of h(x) as x approaches a is 4., 7. The limit of (f(a))^2 as x approaches a is 0., 8. The limit of f(a) as x approaches a is 0., 9. The limit of f(x) - g(x) as x approaches a is 1.

1. The limit of h(x) as x approaches a is 4, and the limit of f(x) as x approaches a is 0. Therefore, the limit of h(x) + f(x) as x approaches a can be found by evaluating each limit separately and then adding them together. The limit of h(x) as x approaches a is 4, and the limit of f(x) as x approaches a is 0. So, the answer to the first question is 4 + 0 = 4.

2. The limit of h(x) as x approaches a is 4, and the limit of f(x) as x approaches a is 0. Therefore, the limit of h(x) - f(x) as x approaches a can be found by evaluating each limit separately and then subtracting them. The limit of h(x) as x approaches a is 4, and the limit of f(x) as x approaches a is 0. So, the answer to the second question is 4 - 0 = 4.

3. The limit of h(x) as x approaches a is 4, and the limit of g(x) as x approaches a is -1. Therefore, the limit of h(x) * g(x) as x approaches a can be found by evaluating each limit separately and then multiplying them. The limit of h(x) as x approaches a is 4, and the limit of g(x) as x approaches a is -1. So, the answer to the third question is 4 * -1 = -4.

4. The limit of f(x) as x approaches a is 0, and the limit of h(x) as x approaches a is 4. Therefore, the limit of f(x) / h(x) as x approaches a can be found by evaluating each limit separately and then dividing them. The limit of f(x) as x approaches a is 0, and the limit of h(x) as x approaches a is 4. So, the answer to the fourth question is 0 / 4 = 0.

5. The limit of g(x) as x approaches a is -1. Therefore, the limit of g(a) as x approaches a is simply -1, as it is evaluating g(x) at the specific value x = a. So, the answer to the fifth question is -1.

6. The limit of h(x) as x approaches a is 4. Therefore, the limit of h(x) as x approaches a is simply 4, as it is evaluating h(x) at the specific value x = a. So, the answer to the sixth question is 4.

7. The limit of f(x) as x approaches a is 0. Therefore, the limit of (f(a))^2 as x approaches a is simply (0)^2 = 0, as it is evaluating f(x) at the specific value x = a and squaring the result. So, the answer to the seventh question is 0.

8. The limit of f(x) as x approaches a is 0. Therefore, the limit of f(a) as x approaches a is simply 0, as it is evaluating f(x) at the specific value x = a. So, the answer to the eighth question is 0.

9. The limit of f(x) as x approaches a is 0, and the limit of g(x) as x approaches a is -1. Therefore, the limit of f(x) - g(x) as x approaches a can be found by evaluating each limit separately and then subtracting them. The limit of f(x) as x approaches a is 0, and the limit of g(x) as x approaches a is -1. So, the answer to the ninth question is 0 - (-1) = 1.

In summary:
1. The limit of h(x) + f(x) as x approaches a is 4.
2. The limit of h(x) - f(x) as x approaches a is 4.
3. The limit of h(x) * g(x) as x approaches a is -4.
4. The limit of f(x) / h(x) as x approaches a is 0.
5. The limit of g(a) as x approaches a is -1.
6. The limit of h(x) as x approaches a is 4.
7. The limit of (f(a))^2 as x approaches a is 0.
8. The limit of f(a) as x approaches a is 0.
9. The limit of f(x) - g(x) as x approaches a is 1.

Please note that if the given limits do not exist or if the functions are undefined at x = a, then the respective limits will be marked as DNE.

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An expression involving division that is equivalent to the expression 2/9 x 3/4 is 1/6.

An algebraic expression is a mathematical expression that consists of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. In algebraic expressions, variables are typically represented by letters, and they can take on any value. Constants, on the other hand, are fixed values that do not change.

Algebraic expressions can be simple or complex, depending on the number of terms and the complexity of the operations involved. For example, a simple algebraic expression might be 2x + 3, where x is a variable and 2 and 3 are constants. A more complex expression might be (2x + 3y) / (x - y), which involves two variables and both addition and division operations.

To find an expression equivalent to the expression 2/9 x 3/4, we can simply multiply the two fractions together and simplify the result:

2/9 x 3/4 = (2 x 3) / (9 x 4) = 6/36

We can further simplify this fraction by dividing both the numerator and the denominator by their greatest common factor, which is 6:

6/36 = (6 ÷ 6) / (36 ÷ 6) = 1/6

Therefore, an expression involving division that is equivalent to the expression 2/9 x 3/4 is 1/6.

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Answer: Its C and E on engenuity

Step-by-step explanation:

The radius is half the diameter.

The volume of the sphere is two-thirds the volume of a cylinder with the same radius and height.

Answer: C, E

Step-by-step explanation: Got it right on edge

The optimal allocation is x = -1/2, y = 3/2, with a shadow price of 1.50.

To maximize profit, the firm needs to determine the optimal allocation of inputs x and y within the budget constraint of $100.

Let's assume the firm uses 'a' units of input x and 'b' units of input y. Since each unit of x costs $2 and each unit of y costs $3, the total cost constraint can be expressed as:

2a + 3b ≤ 100

To maximize profit, we need to differentiate the profit function P(x, y) with respect to both inputs and set the derivatives equal to zero:

∂P/∂x = 2y - 3 = 0 ---> y = 3/2

∂P/∂y = 2x + 1 = 0 ---> x = -1/2

However, x and y cannot have negative values, so these values are not feasible. To find the feasible values, we can substitute the values of x and y into the cost constraint:

2(-1/2) + 3(3/2) = 0 + 9/2 = 9/2 ≤ 100

This constraint is satisfied, so the feasible allocation is x = -1/2 and y = 3/2.

To find the shadow price, we need to determine the rate at which the maximum profit would change with respect to a one-unit increase in the budget constraint. We can do this by finding the derivative of the profit function with respect to the cost constraint:

∂P/∂(2a + 3b) = λ

Where λ represents the shadow price or the marginal value of an additional dollar in the budget. In this case, λ is the shadow price.

Taking the derivative of the profit function with respect to the cost constraint:

∂P/∂(2a + 3b) = ∂(2xy - 3x + y)/∂(2a + 3b) = 0

2y - 3 = 0 ---> y = 3/2

Thus, the shadow price (λ) is 3/2 or 1.50 when rounded to two decimal places.

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Answer:

1 1/6

Step-by-step explanation:

2+5/6=7/6 but it is an improper fraction so you turn it into a mixed fraction which is one whole number one over six

Answer:

7/6

Step-by-step explanation:

because the denominator are the same we add the numerator

Answer:

x=3

Step-by-step explanation:

6(8−2x)=4x

Step 1: Simplify both sides of the equation.

6(8−2x)=4x

(6)(8)+(6)(−2x)=4x(Distribute)

48+−12x=4x

−12x+48=4x

Step 2: Subtract 4x from both sides.

−12x+48−4x=4x−4x

−16x+48=0

Step 3: Subtract 48 from both sides.

−16x+48−48=0−48

−16x=−48

Step 4: Divide both sides by -16.

−16x/−16=−48/−16

Answer:

Yeah i don't get it i have the same problem

Answer:

It is not (−2,3).

Step-by-step explanation:

Step-by-step explanation:

the middle one has to be the same for both part ratios.

the best here is to bring the ratio element of B in the first part ratio to 10. we need to double the B element there

for that (as a ratio is a fraction) we also have to adapt the A element in the same way.

so, we get

4×2 : 5×2 : 9 =

= 8 : 10 : 9

and that is also shown in the graphic.

Answer:

X:Y:Z= 8:10:9

Step-by-step explanation:

Let x be the number of students in class A

Let y be the number of students in class B

Let z be the number of students in class C

x:y = 4:5

y:z= 10: 9

x:y:z = ?

Find the LCM of the y terms (5 and 10 ) which is 10

Divide 10 by the first y term (5) = 2

Divide 10 by the second y term(10) = 1

X: y = (4 x 2) :(5 x 2)= 8:10

y:z =(10 x 1) : (9:1)= 10:9

x:y:z= 8:10:9

Raven bought 1/3 kg of turkey ham, and Chisa bought 2/9 kg less. The total amount of turkey ham they bought together is 1/3 + 1/9 = 3/9 + 1/9 = 4/9 kg. Together, they bought a total of 4/9 kg of turkey ham.

A fraction is a mathematical symbol that represents a portion of a whole or a component of a number. It is made up of two numbers divided by a horizontal line, with the number above the line (numerator) indicating the portion under consideration and the number below the line (denominator) indicating the entire or the total number of equal parts in the whole.

From the given information, we know that Raven bought 1/3 kg of turkey ham, and Chisa bought 2/9 kg less than Raven. This means that Chisa bought:

1/3 kg - 2/9 kg = 3/9 kg - 2/9 kg = 1/9 kg

Now we can find the total amount of turkey ham they bought together by adding Raven's purchase and Chisa's purchase:

1/3 kg + 1/9 kg = 3/9 kg + 1/9 kg = 4/9 kg

Therefore, Raven and Chisa bought a total of 4/9 kg of turkey ham together.

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Answer:

Problem 2): \(\left \{x\, |\,0\leq x\leq 240\,\,\right \}\)

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\(\left \{x\, |\,0\leq x\leq 240\,\right \}\)

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

Answer:

2

Step-by-step explanation:

The standard matrix for t is [ 2 0 -8 ] [ 0 8 -1 ]. To find the standard matrix for the linear transformation t, we need to find the images of the standard basis vectors of R^3 under t.

The standard basis vectors of R^3 are e1 = (1, 0, 0), e2 = (0, 1, 0), and e3 = (0, 0, 1).

t(e1) = (2(1) - 8(0), 8(0) - 0) = (2, 0)
t(e2) = (2(0) - 8(0), 8(1) - 0) = (0, 8)
t(e3) = (2(0) - 8(1), 8(0) - 1) = (-8, -1)

The standard matrix for t is the matrix whose columns are the images of the standard basis vectors of R^3 under t.

Therefore, the standard matrix for t is

[ 2  0 -8 ]
[ 0  8 -1 ]

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Answer:

BAC and DAE are two acronyms for BAC and DAE, respectively. Since they are angles at a point, an arc measuring 204 degrees is 360 degrees. BAC is measured at 11 degrees. 5(11)° = 55° is the measure of DAE.

Step-by-step explanation:

Answer:

27.43% of the students scored 83 or more in the exam.

Step-by-step explanation:

We can use the Z-score formula to find the percentage of students scoring 83 or more:

Z = (X - μ) / σ

where X is the test score, μ is the mean test score, and σ is the standard deviation.

Substituting the given values, we get:

Z = (83 - 80) / 5 = 0.6

Using a Z-score table or calculator, we can find the percentage of students scoring 83 or more:

P(Z > 0.6) = 1 - P(Z < 0.6) = 1 - 0.7257 ≈ 0.274

27.43% of the students scored 83 or more in the exam.

OR. USING PROPERTIES OF NORMAL DISTRIBUTION

convert the raw score of 83 into a standardized score, also known as a z-score.

The formula for calculating the z-score is:

z = (x - μ) / σ

Where:

x = raw score

μ = mean

σ = standard deviation

Substituting the values given in the question, we get:

z = (83 - 80) / 5

z = 0.6

This means that a student who scored 83 on the exam has a z-score of 0.6.

Next, we need to find the area under the normal distribution curve to the right of this z-score. We can use a standard normal distribution table or calculator for this purpose.

Using a standard normal distribution table, we find that the area to the right of z = 0.6 is approximately 0.2743.

Therefore, the percentage of students scoring 83 or more in the exam is approximately:

0.2743 x 100% = 27.43%

So, about 27.43% of students scored 83 or higher on the exam.

Answer:

10/52 or when reduced, is 5 over 26 (5/26) and if they want it as a percent, its 19% (.19)

Answer:

5/26

Step-by-step explanation:

Answer:

hmmm cant tell if this is a serious question Lol considering you seem pretty smart but if so answer is 23

Step-by-step explanation:

Answer: 21

Step-by-step explanation:

If those are absolute value bars the value is 21

Answer:

Q is not a function

Step-by-step explanation:

Answer:

The answer is 8.75<3

Answer:

the correct answer is 7.50

Step-by-step explanation:

because they are telling to measure how much will 6lbs will scost them in the chart when you look at six and go up to the line it lines up with 7.50

The centre line of a control chart is calculated by computing the average (mean) of the data for every period.

In control chart analysis, the centre line represents the central tendency or average value of the process being monitored. It is typically obtained by calculating the mean of the data points collected over a specific period. The purpose of the centre line is to provide a reference point against which the process performance can be compared. Any data points falling within acceptable limits around the centre line indicate that the process is stable and under control.

The calculation of the centre line involves summing up the values of the data points and dividing it by the number of data points. This average is then plotted on the control chart as the centre line. By monitoring subsequent data points and their distance from the centre line, deviations and trends in the process can be identified. Deviations beyond the control limits may indicate special causes of variation that require investigation and corrective action. Therefore, the centre line is a critical element in control chart analysis for understanding the baseline performance of a process and detecting any shifts or changes over time.

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Answer:

24.8

Step-by-step explanation:

sin75 = 24/x

x = 24/sin75 = 24.8466 = 24.8 (nearest tenth)