Linda built a games board in industrial arts class. The top was a rectangle of 60cm by 48cm. What was the largest size of identical felt squares she could use to cover the top exactly?

Answers

Answer 1

The largest size of identical felt squares that can be used to cover the top of rectangle is 5 squares of side 24cm.

The rectangle is a 2-dimensional figure with length and breadth which may or may not be same. A square is also a 2-dimensional figure with equal length of its sides.

When the dimensions of rectangle are given, it's are is given as the product of the sides of the rectangle which is given as:

Area of rectangle = Length × Breadth = 60 × 48 = 2880 cm square

The length of the square that entirely covers up the top side i.e., rectangular top can be determined by hit and trial mechanism starting from the lowest whole number in order to determine the length of largest squares of equal dimensions. Then comparing the area of the rectangular top and product of number of squares needed and area of each square, we can find the largest size of the square.

Area of square = length × length = l²

Since, Area of rectangular top = No. of squares × Area of 1 square

Therefore, 2880 = N (l²)

Putting N =1, 2, 3, 4, 5 and so on, we find that when N = 5, the value of square root of l is a perfect whole number.

Hence, 2880 = 5 × (l²)

l = √576 = 24

Thus, 5 squares of side 24cm will be used to cover the rectangular top entirely.

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Related Questions

Replace the values of A, b, x, and y to write an exponential equation that represents the number of cells present at h hours.

Replace the values of A, b, x, and y to write an exponential equation that represents the number of cells

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

Given the table

Time, x(hours)             Number of Cells, y

0                                   100

1                                     200

2                                    400

h                                     6400

We know that the exponential function is of the form

A(b)ˣ = y

substituting x = 0 and y  = 100

A(b)⁰ = 100

A×1 = 100           ∵ (b)⁰ = 1

substituting x = 1 and y = 200

A(b)¹ = 200

Ab = 200

plug in A = 100

100×b = 200

b = 200/100

b = 2

So, the values of A and b are:

A = 100b = 2

Thus, the equation of the exponential function becomes:

A(b)ˣ = y

substituting A = 100 and b = 2

100(2)ˣ = y

Thus, the equation of the exponential function becomes:

100(2)ˣ = y

Given that we have to determine the value of 'h' hours at y = 6400

so substituting y = 6400

100(2)ˣ = y

100(2)ˣ = 6400

divide both sides by 100

\(\frac{100\cdot \:2^x}{100}=\frac{6400}{100}\)

Simplify

\(2^x=64\)

\(\:2^x=2^6\)              ∵ 2⁶ = 64

\(x=6\)

Therefore, in 6 hours i.e. x = 6 h, the number of cells present will be 6400.

Can anyone please simplify this?:
(7^3)^6

Answers

Answer:

7^18

Step-by-step explanation:

When you have an exponent to another exponent, you can multiply the exponents.

(7^3)^6

3*6 = 18

7^18

What is the solution to 0.3(12x-16)= 0.4(12-3x) ?

Answers

Answer:

Step-by-step explanation:

2

Answer:

x = 2

Step-by-step explanation:

0.3(12x-16)= 0.4(12-3x) take the x's and put them into.

Find the area of the figure and type your result in the empty box.
3 m
2 m
4 m

Find the area of the figure and type your result in the empty box.3 m2 m4 m

Answers

Answer:

14m^2

Step-by-step explanation:

area of triangle = 1/2bh

= 1/2(3)(4) = 6

area of rectangle = bw

=(4)(2) = 8

6+8 = 14

Answer:

14m²

Step-by-step explanation:

rectangle area= 4*2=8

triangle area= 1/2*3*4=6

total area=14

Need help with this question

Need help with this question

Answers

Answer:

B.

Step-by-step explanation:

you know that (a+b+c)/d is the same as a/d + b/d + c/d.

and (a×b)/(c×d) is the same as (a/c)×(b/d).

and the powers of variables subtract when the variables are divided, and the powers add when the variables are multiplied.

14a⁸y³ / 7a⁴y

14/7 = 2

a⁸/a⁴ = a⁴

y³/y = y²

=> 2a⁴y² is the first part. that eliminates already all other answer options. only B can be right.

but let's practice and look at the second part :

-7a⁴y⁵ / 7a⁴y

-7/7 = -1

a⁴/a⁴ = 1

y⁵/y = y⁴

=> -y⁴ is the second part. B is still confirmed.

the third part :

28a¹²y² / 7a⁴y

28/7 = 4

a¹²/a⁴ = a⁸

y²/y = y

=> + 4a⁸y is the third part. B confirmed.

Which way will water move in this example shown below?








The water will not move

Water will move into the cell

The water will evaporate

The water will move out of the cell

Which way will water move in this example shown below?The water will not moveWater will move into the

Answers

Answer: it will move down.

Step-by-step explanation:

because of gravity.

Twelve squares are placed in a row forming the grid below. Each square is to be filled with an integer. After the third square, each integer in a square is the sum of the previous three integers. If we know the third integer is 6, the sixth integer is 11, and the eleventh integer is 14, determine all of the integers in the grid.

Twelve squares are placed in a row forming the grid below. Each square is to be filled with an integer.

Answers

The integers in the grid are 1, 2, 6, 45, 53, 11, 109, 169, 322, 600, 14, and 1042.

We can start by filling in the third, sixth, and eleventh squares with the given values:

_   _   6   _   _   11  _   _   _   _   14  _

Now we can use the rule that each integer is the sum of the previous three integers to fill in the rest of the grid. We can work from left to right, filling in one square at a time.

For the fourth square, we know that it must be the sum of the first three squares, which are currently unknown. However, we know that the product of the three unknown integers is 84, so we can use this information to find the possible combinations of integers:

1 × 2 × 42

1 × 3 × 28

1 × 4 × 21

1 × 6 × 14

2 × 3 × 14

2 × 4 × 7

3 × 4 × 7

Since the digits are increasing from left to right, the only possible combination is 1, 2, 42. Therefore, the fourth square is 45.

Continuing in this way, we can fill in the rest of the squares:

1   2   6   45  53  11  109 169  322 600  14  1042

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Exercise #1: A rectangular, right prism (or box) has a length of 8 inches, a width of 4 inches, and a height of 5
inches.
= 1 in
(a) What is the area of the base of the box? Use appropriate units.
(b) What is the volume of the box? Use appropriate units. How can
you use your answer to part (a) to determine the volume?

Answers

Step-by-step explanation:

(a) What is the area of the base of the box? Use appropriate units.

A=lw

A=8(4)

A=32 inches

(b) What is the volume of the box? Use appropriate units. How can

you use your answer to part (a) to determine the volume?

V=lwh

V=8(4)(5)

V=160 inches

For a random bit string of length n find the expected value of a random function X that counts the number of pairs of consecutive zeroes. For example X(00100) = 2, X(00000) = 4, X(10101) = 0, X(00010) = 2.

Answers

To find the expected value of X, we need to first determine the probability of having a pair of consecutive zeroes in a given bit string of length n. Let P be the probability of having a pair of consecutive zeroes in any given position of the bit string.

We can calculate P by considering the possible pairs of consecutive zeroes that can occur in a bit string of length n. There are n-1 pairs of adjacent bits in the bit string, so the probability of a given pair being two zeroes is 1/4 (since there are four possible pairs: 00, 01, 10, 11). However, if the first bit is 0 or the last bit is 0, then there are only n-2 pairs, and the probability of a given pair being two zeroes is 1/2. Therefore, the probability of having a pair of consecutive zeroes in a bit string of length n is:

P = [(n-2)/n * 1/4] + [1/n * 1/2] + [1/n * 1/2] + [(n-2)/n * 1/4]
 = (n-3)/2n + 1/n

Now, let Xi be the random variable that counts the number of pairs of consecutive zeroes that start at position i in the bit string (where 1 <= i <= n-1). Then X = X1 + X2 + ... + Xn-1 is the total number of pairs of consecutive zeroes in the bit string.

To find the expected value of X, we use linearity of expectation:

E[X] = E[X1] + E[X2] + ... + E[Xn-1]

We can calculate E[Xi] for any i by considering the probability of having a pair of consecutive zeroes starting at position i. If the i-th and (i+1)-th bits are both 0, then there is one pair of consecutive zeroes starting at position i. The probability of this occurring is P. If the i-th bit is 0 and the (i+1)-th bit is 1, then there are no pairs of consecutive zeroes starting at position i. The probability of this occurring is 1-P. Therefore, we have:

E[Xi] = P * 1 + (1-P) * 0
      = P

Finally, we substitute our expression for P into the formula for E[X] to get:

E[X] = (n-3)/2n + 1/n * (n-1)
    = (n-3)/2n + 1

So the expected value of X for a random bit string of length n is (n-3)/2n + 1.
To find the expected value of a random function X that counts the number of pairs of consecutive zeroes in a random bit string of length n, we can follow these steps:

1. Calculate the total number of possible bit strings of length n. There are 2^n possible bit strings since each position can be either a 0 or a 1.

2. Find the probability of each pair of consecutive zeroes occurring in the bit string. Since there are 2 possible values for each bit (0 or 1), the probability of a specific pair of consecutive zeroes is 1/4 (0.25).

3. Determine the maximum number of pairs of consecutive zeroes in a bit string of length n. The maximum number is n - 1 since the first n - 1 bits can form pairs with the bits that follow them.

4. Calculate the expected value by multiplying the probability of each pair of consecutive zeroes by the number of pairs that can occur, and sum the results. The expected value E(X) can be calculated using the formula:

E(X) = Sum(P(i) * i) for i from 0 to n - 1, where P(i) is the probability of i pairs of consecutive zeroes occurring.

To simplify the calculation, consider that each position has a 1/4 chance of forming a consecutive zero pair with the following position, and there are n - 1 such positions:

E(X) = (1/4) * (n - 1)

So, the expected value of a random function X that counts the number of pairs of consecutive zeroes in a random bit string of length n is (1/4) * (n - 1).

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-
1.) -x + 5y = 49
X =
X - 4y = - 39
-
=

Answers

Answer: (1,10)

Step-by-step explanation:

Assuming these are the correctly written equations:

-x + 5y = 49, and

x - 4y = -39

I'll rewrite them:

5y = x + 49

y = (1/5)x + (49/5)

-4y = -x -39

y = (1/4)x + (39/4)

=====

I'll assume the question is to find the point these two lines intersect (?).

See the attached graph.  They intersect at (1,10).

-1.) -x + 5y = 49X =X - 4y = - 39-=

AAAAAAAAAAHHHHHHHHHHHH​

AAAAAAAAAAHHHHHHHHHHHH

Answers

Answer:

\( \sqrt{45 {x}^{2} } + \sqrt{5 {x}^{2} } + 4x \sqrt{5} \\ = 3 \sqrt{5} x + \sqrt{5} x + 4x \sqrt{5} \\ = 8x \sqrt{5} \\ thank \: you\)

Generally, which one of the following is the least appropriate measure of central tendency for a data set that contains outliers? a. mean b. median c. 2nd quartile d. 50th percentile

Answers

The least appropriate measure of central tendency for a data set that contains outliers is the mean. This is because the mean is calculated by taking the sum of all the values in the data set and dividing it by the number of values. This means that the mean is heavily influenced by outliers, as they are included in the calculation.

The median, 2nd quartile, and 50th percentile are all more appropriate measures of central tendency for a data set that contains outliers, as they are not affected by the presence of outliers. The median is calculated by taking the middle value of the data set, the 2nd quartile is calculated by taking the median of the upper half of the data set, and the 50th percentile is calculated by taking the value at the 50th percentile of the data set.

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Find the absolute minimum and maximum values of the function f: R2 + R on the set D, where f(x, y) =1+xy – X – Y, and D is the region in R2 that is bounded by the parabola y = x2 and the line y = 4.

Answers

The absolute minimum and maximum values of the function f(x,y) = 1+xy – x – y on the region D, bounded by the parabola y = x^2 and the line y = 4, we can follow these steps:

Find the critical points of f(x,y) by setting the partial derivatives of f equal to zero:

fx = y - 1 = 0

fy = x - 1 = 0

Solving these equations simultaneously gives the critical point (1,1).

Check the boundary of region D, which is composed of two curves: y = x^2 and y = 4.

2.1. Along the curve y = x^2:

Substituting y = x^2 into f(x,y), we obtain a function of one variable:

g(x) = f(x, x^2) = 1 + x^3 - 2x^2

Taking the derivative of g(x) and setting it equal to zero to find its critical points:

g'(x) = 3x^2 - 4x = 0

x(3x - 4) = 0

Solving for x, we get x = 0 and x = 4/3. Plugging these values into g(x), we find that g(0) = 1 and g(4/3) = -1/27.

Therefore, the minimum value of f(x,y) along the curve y = x^2 is g(4/3) = -1/27, and the maximum value is g(0) = 1.

2.2. Along the line y = 4:

Substituting y = 4 into f(x,y), we obtain a function of one variable:

h(x) = f(x, 4) = 1 + 4x - x - 4

Simplifying, we get h(x) = 3x - 3.

Taking the derivative of h(x) and setting it equal to zero to find its critical point:

h'(x) = 3 = 0

Since h'(x) is never zero, there are no critical points along the line y = 4. We only need to check the endpoints of the line segment that lies within D.

At the endpoint (4/2, 4), we have f(2, 4) = -2, and at the endpoint (-2, 4), we have f(-2, 4) = 9.

Therefore, the minimum value of f(x,y) along the line y = 4 is f(2,4) = -2, and the maximum value is f(-2,4) = 9.

Compare the values obtained in steps 1 and 2 to find the absolute minimum and maximum values of f(x,y) on D.

The values of f at the critical point (1,1), along the curve y = x^2, and along the line y = 4 are:

f(1,1) = -1

g(4/3) = -1/27

g(0) = 1

f(2,4) = -2

f(-2,4) = 9

Therefore, the absolute minimum value of f(x,y) on D is f(-2,4) = 9, and the absolute maximum value is f(0) = 1.

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An airplane is flying from nyc to la. The distance it travels in miles,d, is related to the to the time in seconds, t, by the equation d=0.15t

Answers

Answer:

It will cover 4.5 miles in 30 seconds.

Step-by-step explanation:

An airplane is flying from nyc to la.

The distance it travels in miles,d, is related to the to the time in seconds, t, by the equation :

d=0.15t ...(1)

Let us assume we need to find the distance at t = 30 s.

Put t = 30 s in equation (1).

d=0.15 × 30

d = 4.5 miles

Hence, it will cover 4.5 miles in 30 seconds.



Solve the following equation.

-p/12 =6

Answers

The solution to the equation is p = -72.

The equation, we need to isolate the variable 'p' on one side of the equation. Let's go through the steps:

-p/12 = 6

To get rid of the fraction, we can multiply both sides of the equation by 12:

12 * (-p/12) = 12 * 6

This simplifies to:

-p = 72

To isolate 'p,' we can multiply both sides of the equation by -1:

(-1) * (-p) = (-1) * 72

This gives us:

p = -72

Therefore, the solution to the equation is p = -72.

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Based on this graph, is the relationship between number of rows and number of chairs a proportional relationship?

Based on this graph, is the relationship between number of rows and number of chairs a proportional relationship?

Answers

Answer:

Yes

Step-by-step explanation:

As the number of rows increases the number of chairs also increases according to the graph

Find the distance in units between 5/8 and 1/4 on a number line.

Answers

Answer:

3/8

Step-by-step explanation:

convert 1/4 to 2/8 and then subtract and that would equal the distance. distance of 3/8 hope this helps

The distance in units between 5/8 and 1/4 on a number line is 3/8.

Here,

We have to find,

The distance in units between 5/8 and 1/4 on a number line.

What is Number line?

Number line is a line in which all types off numbers are show like the negative number the positive numbers and fraction.

Now,

Distance between the 5/8 and 1/4 is find as,

\(\frac{5}{8} - \frac{1}{4} = \frac{5}{8} - \frac{2}{8} = \frac{3}{8}\)

Hence, The distance in units between 5/8 and 1/4 on a number line is 3/8.

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the total amount of fiber (in grams) in a package containing x apples and y oranges is given by the equation 5x 10y

Answers

The equation given, 5x + 10y, does not represent the total amount of fiber in a package containing x apples and y oranges.

To calculate the total amount of fiber in a package containing x apples and y oranges, you would need to know the amount of fiber in each apple and orange and the number of apples and oranges in the package.

For example, if each apple contains 3 grams of fiber and each orange contains 2 grams of fiber, and there are x apples and y oranges in the package, the total amount of fiber in the package would be:

Total fiber = (3 grams of fiber per apple)(x apples) + (2 grams of fiber per orange)(y oranges)

Total fiber = 3x + 2y grams

what is number?

A number is a mathematical concept used to represent quantity or magnitude. Numbers can be used to count objects, measure distances or sizes, perform calculations, and describe various other mathematical concepts. The most basic types of numbers are the natural numbers, which include all positive integers (1, 2, 3, ...), and sometimes zero (0) as well. Other types of numbers include fractions, decimals, negative numbers, complex numbers, irrational numbers, and more. Numbers are a fundamental concept in mathematics and are used extensively in many fields, including science, engineering, economics, and finance.

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Yasmin purchased 6 heads of cabbage that each weighed 2 and StartFraction 3 over 8 EndFraction pounds. How much did the cabbage weigh all together?

Answers

Answer:

14 and 1/4

Step-by-step explanation:

So the equation would be-

6 x 2 and 3/8

I would break this up, so

6 x 2 = 12

6 x 3/8 = 18/8

Simplify

18/8 = 9/4 = 2 and 1/4

12 + 2 and 1/4 = 14 and 1/4

Answer:

14 and 1/4

Step-by-step explanation:

tape<33333333333333333333333333333333333333333333
:) :) :) :) :) :) :) :) :) :) :) :) :) :0 :) :) :) :) :) :) :) :) :) :) :) :) : ): : )

Answers

I like tape because tape is tape

Answer:

tape

Step-by-step explanation:

tape is tape

5x + 15 = 2x +3
x = what

Answers

X=-4



My answer need to be 20 characters long

Answer:

Step-by-step explanation:

5x + 15 = 2x + 3

5x + 15 - 15 = 2x + 3 - 15

5x = 2x + 3 - 15

5x - 2x = 2x - 2x + 3 - 15

5x - 2x = 3 - 15

3x = 3 - 15

3x = -12  ( divide both sides by 3)

x= -4

Hello can you help me with problem one under section C?

Hello can you help me with problem one under section C?

Answers

Answer:so for i the answer is f(t) = 6t/3 +3t - 43t/2

Step-by-step explanation:

Ok this is for i 6t/3 + 3t -43t/2

answers for the 2 boxes please ​

answers for the 2 boxes please

Answers

Answer:

(2, 12)

Step-by-step explanation:

x + 10 = 4x + 4

   - 4           - 4

x + 6 =  4x

- x         - x

6 = 3x

divide 3 on each side

2 = x

then plug 2 in either equation

ei) y = 2 + 10

    y = 12

find the solutions of the quadratic equation.-x^2+7x-14=0

Answers

Answer:

Step-by-step explanation:

x =(-7+√-7)/-2=(7-i√ 7 )/2= 3.5000+1.3229i

 or:

x =(-7-√-7)/-2=(7+i√ 7 )/2= 3.5000-1.3229i

Find the area of a circle with a radius of 5 feet. Round your answer to the nearest tenth. Find the area of a circle with a diameter of 56 millimeters. Round your answer to the nearest hundredth.

Answers

Case 1 :

Radius, r = 5 feet.

Area,

\(A=\pi r^2\\\\A = 3.14\times 5^2\ feet^2\\\\A = 78.5\ feet^2\)

Case 2 :

Diameter, d = 56 mm.

So, radius, r = d/2 = 28 mm.

Area,

\(A = 3.14\times 28^2\ mm^2\\\\A = 2461.76\ mm^2\)

Hence, this is the required solution.

A circular oil slick is expanding at a rate of 3m/min. How fast is the area of the oil slick changing when the diameter is 48 meters?

Answers

Answer:

\( 48\pi \:m/min\)

Step-by-step explanation:

Diameter = 48 m

Therefore radius r = 48/2 = 24 m

\(Area \: of \: circular \: oil \: slick \\ A = \pi {r}^{2} \\ differentiating \: w \: r \: to \: t \: on \: \\ both \: sides \\ \\ \frac{dA}{dt} = \frac{d}{dt} (\pi {r}^{2} )\\ \\ \frac{dA}{dt} =\pi \frac{d}{dt} {r}^{2} \\ \\ \frac{dA}{dt} =\pi \times 2{r}\\ \\ \frac{dA}{dt} =2\pi {r} \\ \\ \bigg(\frac{dA}{dt} \bigg)_{r=24} =2\pi \times {24} \\ \\ \bigg(\frac{dA}{dt} \bigg)_{r=24} =48\pi \: m \: per \: min\)

UCL and LCL PLease ( 2 sigma X chart)
The overall average on a process you are attempting to monitor is \( 55.0 \) units. The process population standard deviation is \( 1.84 \). Sample size is given to be \( 16 . \) a) Determine the 3 -s

Answers

Given the information:

Overall average (μ) = 55.0 units

Process population standard deviation (σ) = 1.84

Sample size (n) = 16

To determine the 3-sigma UCL (Upper Control Limit) and LCL (Lower Control Limit) for a 2-sigma X chart, we can use the following formulas:

UCL = μ + 3 * (σ / √n)

LCL = μ - 3 * (σ / √n)

Plugging in the values:

UCL = 55.0 + 3 * (1.84 / √16)

LCL = 55.0 - 3 * (1.84 / √16)

Calculating the values:

UCL = 55.0 + 3 * (1.84 / 4)

LCL = 55.0 - 3 * (1.84 / 4)

UCL = 55.46

LCL = 54.54

Therefore, the 3-sigma UCL for the 2-sigma X chart is 55.46 units, and the LCL is 54.54 units.

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find the particular solution that satisfies the differential equation and the initial condition. f '(x) = 6x2; f(0) = −9

Answers

This is the required solution that satisfies the given differential equation and initial condition.

The given differential equation is f '(x) = 6x², where the initial condition is given as f(0) = −9.

We can start with integration and find the particular solution: ∫f '(x) dx = ∫6x² dx ⟹ f(x) = 2x³ + C, where C is the constant of integration.

To find the constant C, we will use the initial condition given as

f(0) = −9f(0) = 2(0)³ + C = C = -9

Therefore, the particular solution is:f(x) = 2x³ - 9

Hence, this is the required solution that satisfies the given differential equation and initial condition.

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the fractiions 3/k,4/k ,dand 5/k are in lowest terms. what could be the value of k if the numbers are 48,49,50,51,52?

Answers

The value of k could be 48, 49, 50, 51, or 52, as these all result in the fractions being in lowest terms.

What could be the value of k if the numbers are 48,49,50,51,52?

To further explain, let's look at each of the possible values of k and see how they result in the fractions being in lowest terms:

If k = 48, then the fractions are 3/48, 4/48, and 5/48. These can all be simplified to 1/16, 1/12, and 1/9.6, respectively, which are in lowest terms.If k = 49, then the fractions are 3/49, 4/49, and 5/49. These cannot be simplified further, so they are already in lowest terms.If k = 50, then the fractions are 3/50, 4/50, and 5/50. These can all be simplified to 1/16.666..., 1/12.5, and 1/10, respectively, which are in lowest terms.If k = 51, then the fractions are 3/51, 4/51, and 5/51. These can all be simplified to 1/17, 1/12.75, and 1/10.2, respectively, which are in lowest terms.If k = 52, then the fractions are 3/52, 4/52, and 5/52. These can all be simplified to 1/17.333..., 1/13, and 1/10.4, respectively, which are in lowest terms.

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A point S is 54 km due east of point T. The bearings of an electricity pole from S and Tare N28°W and N70°E, respectively. Calculate the distance of the electricity pole from T.​

Answers

The distance of the electricity pole from T is 53 km

Given that;

The ST is 54 kilometer long

(180 - 28) + (180 - 70) = 262 degree is the angle PST,

which is the product of the angles at S and T.

S has a 62 degree angle.

The law of sines can be written as:

sin(62)/SP = sin(262/ST)

To find SP, we can rearrange this equation as follows:

SP = sin(62)/sin(262)x(ST)

When we enter the values we are aware of, we obtain:

SP = sin(62)/sin(262)*54 km

We can evaluate this expression to determine that:

SP ≈ 53.5 km Consequently, 53.5 kilometer or so separate T from the electricity pole.

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