Lighter cars are more fuel-efficient than heavier cars. An environmentalist would like to estimate the true mean weight
of all cars. To do so, she selects a random sample of 30 cars and determines the 90% confidence interval for the true
mean weight to be 2.8 to 3.4 tons. Which of these statements is a correct interpretation of the confidence level?
O There is a probability of 0.90 that the confidence
interval (2.8, 3.4) captures the true mean weight of all cars.
O The environmentalist can be 90% confident that the true mean weight of all cars is between 2.8 and 3.4 tons,
O If many random samples of size 30 are selected from the population of all cars, approximately 90% of the sample
means will be between 2.8 and 3.4 tons.
O If many random samples of size 30 are selected from the population of all cars, about 90% of the intervals would
capture the true mean weight of all cars.
Answers
Answer:
The environmentalist can be 90% confident that the true mean weight of all cars is between 2.8 and 3.4 tons.
Step-by-step explanation:
x% confidence interval:
A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.
In this question:
90% confidence interval between 2.8 and 3.4 tons. This means that the environmentalist can be 90% sure that the mean weight of all cars is in this interval, that is:
The environmentalist can be 90% confident that the true mean weight of all cars is between 2.8 and 3.4 tons.
Related Questions
What is the sum of 1 3/4 + 2 1/8
Answers
Answer:
3 \(\frac{7}{8}\)
Step-by-step explanation:
PLEASE ANSWER!! Find EF using Pythagorean theorem. Express answer to one decimal place.
Answers
Answer:
115.5 cm
Step-by-step explanation:
A^2 + B^2 = C^2
41^2 + 108^2 = C^2
C^2 = 13345
C = 115.5 cm
One side of a triangle is 3 times the second side. The third side is 13 feet longer than the second side. The perimeter of a triangle is 68 feet. Find the length of each side.
Answers
Answer:
33, 11, 24 feet
Step-by-step explanation:
Let s represent the length of the second side. Then the length of the first side is 3s and the length of the third side is s+13. The perimeter is the sum of side lengths:
(3s) +(s) +(s +13) = 68
5s = 55 . . . . . subtract 13
s = 11 . . . . . . . divide by 5
The side lengths are ...
33, 11, 24 feet
For many years, businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to less inflation in health care prices and employees paying for a larger portion of health care benefits. A recent survey showed that 62% of employers are likely to require higher employee contributions for health care coverage this year relative to last year. Suppose the survey was based on a sample of 800 companies likely to require higher employee contributions for health care coverage this year relative to last year. At 95% confidence, compute the margin of error for the proportion of companies likely to require higher employee contributions for health care coverage. (Round your answer to four decimal places.) Compute a 95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage. (Round your answers to four decimal places.)
Answers
Answer:
95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage.
(0.5868 , 0.6532)
Step-by-step explanation:
Step(i):-
Given the survey was based on a sample of 800 companies
Given size 'n' = 800
A recent survey showed that 62% of employers are likely to require higher employee contributions for health care coverage this year relative to last year
sample proportion
p⁻ = 0.62
Step(ii):-
The margin of error for the proportion of companies likely to require higher employee contributions for health care coverage.
\(M.E= Z_{0.05} \sqrt{\frac{p^{-} (1-p^{-}) }{n} }\)
\(M.E= 1.96\sqrt{\frac{0.62 (1-0.62 }{800} }\)
M.E = 0.017 X 1.96
M.E = 0.03
Step(iii):-
95% confidence interval for the proportion of companies likely to require higher employee contributions for health care coverage.
\((p^{-} - Z_{0.05} \sqrt{\frac{p^{-} (1-p^{-}) }{n} } , p^{-} +Z_{0.05} \sqrt{\frac{p^{-} (1-p^{-}) }{n} })\)
\((0.62 - 1.96\sqrt{\frac{0.62 (1-0.62 }{800} } ,0.62+1.96\sqrt{\frac{0.62 (1-0.62 }{800} }\)
( 0.62 - 0.0332 , 0.62+0.0332)
(0.5868 , 0.6532)
Find PN and QP.
IMAGE ATTACHED PLS HELP
Answers
Answer:
PN: 15
QP: 15
Step-by-step explanation:
if QN is 30 and P is in the middle of N and Q then the distance from P must be 15
if i have 140 post its and my brother has 120 how has more
Answers
Answer:
you
Step-by-step explanation:
Answer:
You have more lol
Step-by-step explanation:
cus 140 is more than 120
A fruit basket contains 3 mangoes 4 oranges and 3 apples. Another fruit basket contains 5 mangoes, 5 oranges and 5 apples. One basket is selected at random. 1. what is the probabilities that both are mangoes?
Answers
If one basket is selected at random, the probability that both are mangoes is; 1/10
How to find probabilities?
Contents of first basket;
3 mangoes
4 oranges
3 apples
Contents of second basket;
5 mangoes.
5 oranges.
5 apples.
Probability of mango in first basket is = 3/10
Probability of mango in second basket is = 5/15
Thus;
Probability that both are mangoes = (3/10) * (5/15)
Probability that both are mangoes = 1/10
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What is the sum of the first 7 terms of the geometric series:
Answers
Answer:
-15.875
Step-by-step explanation:
First, we can sum up the first 5 terms.
-8 + (-4) = -12
-12 + (-2) = -14
-14 + (-1) = -15
-15 + (-1/2) = -15.5
Next, we can find a pattern in the data. We can tell that the next number is one half of the current number. For example, -4 is one half of -8. To find the next number, we simply multiply our current number by one half. Thus, the sixth number is -1/4 and the seventh is -1/8. Adding these to our current total, we have
-15.5 - 1/4 = -15.75
-15.5 - 1/8 = -15.875 as our answer
4(1-x)<16 solve and graph
Answers
Answer: (x > -3).
Step-by-step explanation:
To solve the inequality 4(1 - x) < 16, we will simplify and solve for x:
4(1 - x) < 16
Distribute the 4:
4 - 4x < 16
Subtract 4 from both sides:
-4x < 12
Divide both sides by -4. Note that when dividing by a negative number, the inequality sign flips:
x > -3
The solution to the inequality is x > -3. This means that x must be greater than -3 for the inequality to hold true.
To graph the solution on a number line, we mark a shaded region to the right of -3, indicating that all values greater than -3 satisfy the inequality:
The open circle at -3 indicates that -3 is not included in the solution since the inequality is strict (x > -3).
here's the graph for 4(1-x)<16
which number line shows the solution to -3-{-1}?
Answers
Answer:
please send the picture of the number line.
Answer:me not know
Step-by-step explanation:
Hehuehuejejejje
Keith receives $25000 salary for working as a account. If keith spends 40% of his salary on expenses each year, then how much money does Keith have to spend on expenses? Round your answer to the nearest whole number if necessary.
Answers
Answer:
$25000 * 40% = 100.000
Step-by-step explanation:
10,000 on expenses. 25000X.40=10,000
Ten percent of the items produced by a machine are defective. Suppose that twenty items are randomly chosen. Use this information to answer the following three questions. What is the probability that exactly 3 of the items are defective
Answers
Answer:
15%
Step-by-step explanation:
if 10% is to 20 then 15% is to 30
Convert 1.4394 to a percent
Answers
Answer: = 143.94%
Step-by-step explanation:
Multiply 1.4394 by 100/100. Since 100/100 = 1, we are only multiplying by 1 and not changing the value of our number.
1.43941×100100=143.94100
143.94/100 is 143.94 over 100 and means 143.94 per 100. 143.94 "per 100" means 143.94 "percent" or 143.94%
Therefore, we have shown that
1.4394 = 143.94%
Answer:
143.94%
It is a whole number so it is 100% plus the 43 so it is 143.94
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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If triangle ABC is reflected across the line y = x, are the pre-image and image congruent? Why, or why not?
OYes, distance and angle measure are preserved
OYes, angle measure is preserved and distance is not
O No, distance is preserved but angle measure is not
O No, neither distance nor angle measure are preserved
Answers
The correct answer is: O Yes, distance and angle measure are preserved.
When a triangle ABC is reflected across the line y = x, the pre-image and image are congruent.
This is because the line y = x is the perpendicular bisector of the segment joining each corresponding point of the pre-image and image.
Reflection across the line y = x is a type of transformation known as an isometry, which preserves both distance and angle measure.
Here's why:
Distance preservation:
When a point is reflected across the line y = x, the distance between the original point and its reflection remains the same.
This holds true for all corresponding points of the triangle.
Therefore, the distance between any two corresponding points in the pre-image and image triangle will be equal, resulting in distance preservation.
Angle preservation: When a line segment is reflected across the line y = x, the angle between the line segment and the line y = x is preserved. This means that the corresponding angles in the pre-image and image triangle will be congruent.
Since both distance and angle measure are preserved during reflection across the line y = x, the pre-image and image triangles are congruent.
It's important to note that congruence under reflection across a line holds only when the line of reflection is the same for both the pre-image and image.
If the line of reflection were different, the triangles would not be congruent.
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Given: a || b
Find the missing angle measures in the diagram. Explain how you find each angle measure. (please explain how you got the answer)
Answers
The angle measure explained in the solution.
Given that, a || b, we need to find the missing angles,
∠1 = 42° [vertically opposite angles]
∠3 = 62° [vertically opposite angles]
∠2 = 180°-(∠1+62°) [angle in a straight line]
∠2 = 76°
∠4 = ∠2 [vertically opposite angle]
∠4 = 76°
∠4 = ∠9 = 76° [alternate angles]
∠9 = ∠12 = 76° [vertically opposite angle]
∠3 = ∠ 6 = 62° [alternate angles]
∠ 6 = ∠7 = 62° [vertically opposite angle]
∠3 + ∠5 = 180° [consecutive angles]
∠5 = 118°
∠5 = ∠8 = 118° [vertically opposite angle]
∠4 + ∠10 = 180° [consecutive angles]
∠10 = 104°
∠10 = ∠11 [vertically opposite angle]
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Answer with step by step details pls
Answers
Answer:
-6x^3 + x^2 - 20
Step-by-step explanation:
First step: write down the problem.
2nd step:
Just lose the first set of parentheses. Write the first four terms exactly the same. Remove also the second set of parentheses but distribute that minus sign to all the last four terms. You get:
-6x^2+4x^3-9x-10-10x^3+7x^2+9x-10
Then combine like terms. Terms with the same exponent can be added or subtracted.
Standard Form means the highest exponent is written first, then the next lower exponent, and then the next lower exponent with a constant (number only) at the end.
So we do the third power first. Then 2nd power. (The x's drop out because -9x and +9x) and constants last.
-6x^3 + x^2 - 20
In how many ways can we stack 10 books?
Answers
The arrangement of items can be done with the use of permutation. The stacking of the number of books in the question can be done in 3,628,800 ways.
The arrangement of a given number of items can be done when definite numbers are to be considered at once by the use of permutation. A permutation is a mathematical method that can be used to determine the number of ways by which given items are to be arranged in a particular order.
Given that 10 books are to be stacked, the number of ways (n) that this can be done can be determined by:
n = 10!
= 10 x 9 x 8 x7 x6 x5 x4 x3 x2x 1
n = 3,628,800
Therefore, the 10 books can be stacked in 3,628,800 ways.
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from a point 1.75 m above the ground and 10 m away from a tower the angle of elevation of a top of a tower is 60 degree calculate the height of the tower
Answers
Answer:
17.32 meters
Step-by-step explanation:
Let’s call the height of the tower H. The distance from the point to the base of the tower is 10 m. The angle of elevation from the point to the top of the tower is 60 degrees.
Using trigonometry, we can calculate that:
tan (60) = H / 10
H = 10 * tan (60)
H = 10 * √3
H = 17.32 m
Therefore, the height of the tower is 17.32 meters.
Let me know if I helped :)
A recipe asks that the following three ingredients be mixed together as follows: add 1/2 of a cup of flour for every 1/2 of a teaspoon of baking soda, and every 1/4 of a teaspoon of salt.
Which of the following rates is a unit rate equivalent to the ratios shown above?
A. 2 teaspoons of salt per 1 cup of flour
B. 1/2 teaspoon of salt per 1 teaspoon of baking soda
C .2 teaspoons of salt per 1 teaspoon of baking soda
D. 1 teaspoon of baking soda per 2 teaspoons of salt
Answers
Answer:
all of the above
Step-by-step explanation:
the ratio between the flour, the baking soda, and the salt would = 1:1:2 (disregarding tsp or cup measurements, since all the units stay the same in the choices)
so really, all the answers are correct
hope this helps!
Answer:
B. 1/2 teaspoon of salt per 1 teaspoon of baking soda.
Step-by-step explanation:
The ratio of cups of flour to tsp. of baking soda to tsp. of salt shown above is:
1/2 : 1/2 : 1/4
An equivalent rate to the ratio of tsp. of salt to tsp. of baking soda is 1/2 : 1 because:
Ratio of tsp. of salt to tsp. of baking soda is:
1/4 : 1/2
If we were to find an equivalent rate to this, it would be 1/2 teaspoon of salt per 1 teaspoon of baking soda for:
Multiply 2 to both terms in the ratio 1/4 : 1/2:
1/4 x 2 = 1/2 (simplified)
1/2 x 2 = 1 (simplified)
The new ratio is 1/2 : 1, which also represents the rate 1/2 teaspoon of salt per 1 teaspoon of baking soda.
Hope this helps!
Please comment back if this was correct.
Laura drinks 1/5 a gallon of water each day. How many days does it take her to drink 3 gallons of water? a. 1/15 b. 15 c. 3/5 d. 5/3
Answers
There are 49 non-fiction books on my shelf. The remaining 75% of
books are novels. How many books are on my shelf?
Answers
Step-by-step explanation:
the answer is in the above image
Solve equation. |x| = 12
Answers
x₁ = - 12
x₂ = + 12
Step-by-step explanation:| x | = 12
x = ± 12
x₁ = - 12
x₂ = + 12
Use the distributive property to find the product
5/6 x 2 2/5
Answers
Answer:
2
Step-by-step explanation:
A bag contains two coins, one for which the probability of heads is equal to 1 and one for which the probability of heads is equal to p. A coin is selected at random, and three independent tosses of this coin result in three heads. What is the probability that a further independent toss of this coin will produce a head?a. p4/1 + p3.b. p3 - p2/1 + p3.c. p3/1 - p.d. 1/1 + p3.e. 1 + p4/1 + p3.
Answers
Answer: Option E is the correct answer; (1 + p⁴) / (1 + p³)
Step-by-step explanation:
P (3 head) = P(first and 3 heads) + P(second coin and 3 heads)
= (1/2)×1³ + (1/2)× p³ = (1/2) × (1 + p³)
therefore P(first coin given 3 heads) = (1/2)×1³/ ((1/2)×(1 + p³))
= 1 / (1 + p³)
Also P( second coin given 3 heads) = p³ /(1 + p³)
therefore P(4th toss in heads given first 3 are heads) will be;
= P(first and 4th toss heads) + P(second and 4th toss heads)
=(1/( 1 + p³ )) × 1 + p³ / (1+p³) × p
= (1 + p⁴) / (1 + p³)
Therefore Option E is the correct answer
The sale price of an item is $105 after a 30% discount is applied. What is the original price of the item?
SHOW WORK PLEASE AND THANKYOU
and be quick please
Answers
Answer:
$150
Step-by-step explanation:
let x be the original price
105 = 0.7x
150 = x
what is 2+2 my brain has been in circles about this
Answers
Answer:
hey welcome to Brainly, and 2 + 2 = 4
Step-by-step explanation:
2+2=4
3+3=6
4+4=8
5+5=10
and so on just keep adding 2
In a pre algebra class containing 43 students, there are 4 freshman, 35 sophomores, and 4 juniors. what fraction of the class are sophomores
Answers
The fraction of the class that is sophomores is \(35/43\).
The fraction of the class that is sophomores, divide the number of sophomores by the total number of students in the class.
Number of sophomores = 35
Total number of students = 43
Fraction of sophomores = (Number of sophomores)/(Total number of students Fraction of sophomores)
Fraction of sophomores \(= 35 / 43\)
Therefore, the fraction of the class that are sophomores is = \(35/43\).
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A large carton of sour cream is 36 ounces. How many cups of sour
cream does the container hold?
Answers
Answer:
4.5 cups
Step-by-step explanation:
20 POINTS!!!! Which best describes the relationship between the successive terns in the sequence shown ? The common difference is -10. The common difference is 10. The common ratio is -9. The common ratio is 9.
Answers
Answer:
B
Step-by-step explanation:
9-(-1)=10
(-1)-(-11)=10
etc...
The common difference(subtraction) between the numbers is 10.