Light of wavelength 200.0 nm is incident on a metal plate with a threshold wavelength of 400.0 nm. What is the energy of the incident photon in electron volts?
a.
2.48 × 105 eV
b.
0.161 eV
c.
6.20 eV
d.
3.10 eV
Answers
The energy of an incident photon in electron volts (eV) can be calculated using the equation: Therefore, the answer is option c. 6.20 eV.
E = h c /λ Where E is the energy of the incident photon, h is the Planck constant, c is the speed of light, and λ is the wavelength of the incident light.
Here, the wavelength of the incident light is 200.0 nm, which is less than the threshold wavelength of the metal plate (400.0 nm).
This means that the incident light has enough energy to eject electrons from the metal surface, and the metal will undergo the photoelectric effect.
The energy of the incident photon can be calculated as:
E = hc/λ
= (6.626 × 10^-34 J s) × (2.998 × 10^8 m/s) / (200.0 × 10^-9 m)
= 9.93 × 10^-19 J
To convert the energy to electron volts, we can use the conversion factor: 1 eV
= 1.602 × 10^-19 J.
Therefore, the energy of the incident photon in eV is:
E/eV
= (9.93 × 10^-19 J) / (1.602 × 10^-19 J/eV)
≈ 6.20 eV
Therefore, the answer is option c. 6.20 eV.
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Related Questions
When an electron in a one-dimensional box makes a transition from the n = 1 energy level to the n = 2 level, it absorbs a photon of wavelength 426 nm. What is the wavelength of that photon when the electron undergoes a transition (a) from the n = 2 to the n = 3 energy level and (b) frorm the n = 1 to the n-3 energy level? (c) What is the width L of the box? [Ans: (a) 256 nm, (b) 160 nm, (c) 0.622 nm]
Answers
The photon's wavelength emitted during the transition from n = 2 to n = 3 is approximately 256 nm. The photon's wavelength emitted during the transition from n = 1 to n = 3 is about 160 nm. The width of the box is approximately 0.622 nm.
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
Let's assume the wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h² / (8× m × L²)) ×(9 - 4)
ΔE = (h²/ (8 × m × L²)) × 5
The energy difference is proportional to the frequency of the emitted photon:
ΔE = h × c / λ
where c is the speed of light.
We can equate the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
Plugging in the given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L² = 0.00047765 m²
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
Following the same steps,
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Simplifying and solving for λ:
λ = (m × L² × c) / h
Plugging in the given values:
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Therefore, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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The wavelength of the photon released during the change from n = 2 to n = 3 is roughly 256 nm. About 160 nm is the wavelength of the photon that is released when n = 1 changes to n = 3. The box has a width of about 0.622 nm.
Given values:
m = mass of the electron = 9.11 x 10⁻³¹ kg
L = width of the box (to be determined)
c = speed of light = 3 x 10⁸ m/s
The energy levels of a particle in a one-dimensional box:
Eₙ = (n² ×h²) / (8 × m × L²)
where:
Eₙ: energy level of the particle
n: quantum number of the energy level
h: Planck's constant
m: mass of the particle
L: width of the box.
Transition from n = 2 to n = 3:
The wavelength of the photon emitted during this transition is λ.
ΔE = E₃ - E₂
ΔE = ((3² × h²) / (8 ×m × L²)) - ((2² × h²) / (8 × m × L²))
ΔE = (h²/ (8 × m × L²)) × 5
The frequency of the photon that was released directly correlates with the energy difference:
ΔE = h × c / λ
,c is the speed of light.
Evaluating the two expressions for ΔE:
(h² / (8 × m × L²)) × 5 = h × c / λ
λ = (8 × m × L² ×c) / (5 × h)
λ = (8 ×(9.11 x 10⁻³¹ kg) × L² × (3 x 10⁸ m/s)) / (5 ×(6.626 x 10⁻³⁴ J·s))
Solving for L
L² = (5 × (6.626 x 10⁻³⁴J·s) × λ) / (8 ×(9.11 x 10⁻³¹kg) × (3 x 10⁸ m/s))
L ≈ 0.021847 m
The wavelength of the photon is given by:
λ = (8 × (9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (5 × (6.626 x 10⁻³⁴J·s))
λ ≈ 256 nm
Transition from n = 1 to n = 3:
ΔE = E₃ - E₁
ΔE = ((3² × h²) / (8 ×m ×L²)) - ((1² × h²) / (8 × m × L²))
ΔE = (h² / (m × L²))
Using ΔE = h × c / λ:
(h² / (m × L²)) = h ×c / λ
Solving for λ:
λ = (m × L² × c) / h
λ = ((9.11 x 10⁻³¹ kg) × (0.021847 m)² × (3 x 10⁸ m/s)) / (6.626 x 10⁻³⁴ J·s)
λ ≈ 160 nm
Width of the box (L):
From the above equations,
L² = (5 × (6.626 x 10⁻³⁴J·s) × (426 nm)) / (8 × (9.11 x 10⁻³¹ kg) × (3 x 10⁸ m/s))
L ≈ 0.000622 m or 160 nm
Thus, the answers are 256 nm, 160 nm, and 0.622 nm respectively.
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If you were to examine the profile of a typical river, you would probably find the fastest flowing water closer to the __.
Answers
If you were to examine the profile of a typical river, you would probably find the fastest flowing water closer to the center or thalweg the deepest part of the channel.
This is because the water flowing along the center of the channel experiences the least amount of friction with the river bed and banks, allowing it to flow more rapidly compared to the water near the edges of the channel which experiences more friction.Experience refers to the accumulation of knowledge, skills, and understanding that an individual gains through their interactions with the world around them. It includes both conscious and unconscious perceptions of sensory information, as well as emotional, cognitive, and social responses to those perceptions.Experience can be divided into two main types: subjective experience and objective experience. Subjective experience refers to the individual's personal interpretation of events and their emotional and cognitive reactions to those events.
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Suppose Alex is navigating using a compass. She starts walking at an angle of 60° north of east and walks a total of 100 m. How far north is she from the starting point? How far east?
Answers
Answer:
\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)
Explanation:
We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:
The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:
\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).
The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:
\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).
What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of
gravity only (9.8m/s²)?
Answers
Answer:
9800N
Explanation:
Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N
A 7.00-kg object accelerates from rest to a final velocity in 55 seconds. If the magnitude of the
net force acting upon the object is 42.0 N, the final velocity reached by the object is
____________m/s.
Answers
Answer:
The final velocity of the object is 330 m/s.
Explanation:
To solve this problem, we first must find the acceleration of the object. We can do this using Newton's Second Law, given by the following equation:
F = ma
If we plug in the values that we are given in the problem, we get:
42 = 7 (a)
To solve for a, we simply divide both sides of the equation by 7.
42/7 = 7a/7
a = 6 m/s^2
Next, we should write out all of the information we have and what we are looking for.
a = 6 m/s^2
v1 = 0 m/s
t = 55 s
v2 = ?
We can use a kinematic equation to solve this problem. We should use:
v2 = v1 + at
If we plug in the values listed above, we should get:
v2 = 0 + (6)(55)
Next, we should solve the problem by performing the multiplication on the right side of the equation.
v2 = 330 m/s
Therefore, the final velocity reached by the object is 330 m/s.
Hope this helps!
Exercise: Translation symmetry in Landau gauge 10 point (graded) With a constant magnetic field, we expect the Hamiltonian for a particle of mass m and charge q to have translational symmetry. But our choice of Landau gauge A = (-By,0) appears to break that symmetry in the y-direction. While [H, P2] = 0, we have [H, Py] =0 Consider a modified momentum operator Py: y = Ôy + Bi. Note that ſý, ] = iħ and ſê, ê,] = 0, as befits a translation operator. Find the value of the constant B so that , commutes with H. Write your answer in terms of q. m, cand B. y B=
Answers
The value of the constant B so that y commutes with H is given by
B = 2m/q
The Hamiltonian for a particle in a constant magnetic field is given by
H = (1/2m) (p^2 + 2qBy)
where p is the momentum operator and B is the magnetic field strength. The momentum operator in the Landau gauge is given by
p = -iħ \frac{\partial}{\partial x} + Bi
where x is the position operator. In order for y to commute with H, we need to have
[y, H] = 0
Substituting the expressions for y, p, and H into this equation, we get
[y, (1/2m) (p^2 + 2qBy)] = 0
Expanding the commutator, we get
[y, p^2] + 2qB[y, B] = 0
Since y and p are both operators, they anticommute, so [y, p^2] = 0. The commutator [y, B] is equal to iħ, so we have
0 = 2qB iħ
Solve for B to get
B = 2m/q
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Pictures A and B show the result when cars model convergent movement. What happens when two cars converge?
Answers
Answer:
bad
Explanation:
A spring gun initially compressed 2 cm fires a 0.01 kg dart straight up into the air. If the dart reaches a height of 5.5 m, determine the spring constant of the dart gun.
Answers
The spring constant of the dart gun compressed by 2 cm is determined as 121.275 N/m.
What is the spring constant?To determine the spring constant of the dart gun, we can use the conservation of energy principle, which states that the initial potential energy stored in the compressed spring is converted to the kinetic energy of the dart and its potential energy due to its position in the gravitational field.
The initial potential energy stored in the compressed spring is given by:
U = (1/2)kx²
where;
k is the spring constant and x is the compression of the spring.In this case, x = 0.02 m.
The kinetic energy of the dart just after it leaves the spring is given by:
K = (1/2)mv²
where;
m is the mass of the dart and v is its initial velocity.Since the dart is fired straight up, its initial velocity is zero.
At the highest point of the dart's trajectory, all of its kinetic energy has been converted to potential energy due to its position in the gravitational field. The potential energy of the dart at this point is given by:
U = mgh
where;
h is the maximum height reached by the dart.Equating the initial potential energy stored in the spring to the final potential energy of the dart, we have:
(1/2)kx² = mgh
Substituting the given values, we get:
(1/2)k(0.02)² = 0.01 * 9.81 * 5.5
Solving for k, we get:
k = (0.01 x 9.81 x 5.5) / (0.02)² = 121.275 N/m
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1. An air track glider of mass m1 = 0. 200kg moving at 0. 750m/s to the right collides with a glider of mass m2 = 0. 400kg at rest. If my rebounds and moves to the left with a speed of 0. 250m/s, what is the speed and direction of m2 after the collision. Direction is indicated by the sign of the velocity Enter your answer in. M/s. 2. For the collision in question 2, calculate the initial kinetic energy of the system before the collision. Enter your answer in Joules. Report your answer with 3 significant figures
Answers
The speed and direction of m2 after the collision can be calculated using conservation of momentum. Since the collision is an isolated system, the total momentum before the collision must be equal to the total momentum after the collision. Using the equation for conservation of momentum, we can find that the speed and direction of m2 after the collision is 0.625 m/s to the right.
To calculate the initial kinetic energy of the system before the collision, we can use the formula for kinetic energy: KE = (1/2)mv^2. The total initial kinetic energy is equal to the sum of the kinetic energy of m1 and m2 before the collision. Plugging in the given values, we can calculate that the initial kinetic energy of the system before the collision is 0.169 J.
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What is the frequency of this wave?
O 1
)2.
O 3
o 4
Answers
Answer:
The frequency, represented by the Greek letter nu (ν), is the number of waves that pass a certain point in a specified amount of time. Typically, frequency is measured in units of cycles per second or waves per second. One wave per second is also called a Hertz (Hz) and in SI units is a reciprocal second (s−1).
A waitress lifts an apple pie 5 meters from the ground floor to the second floor of the restaurant. If the pie is 0.30 kg, what is the Ep gained by the pie? *
Answers
m = 0.30kg h = 5m g = 9.8m/s^2
Ep = m•g•h
Ep = 0.30kg x 9.8m/s^2 x 5m
Ep = 14.7 J
Ep = 15J (rounded)
The potential energy gained by the pie on lifting 5 meters from the ground floor to the second floor of the restaurant is 14.7 J.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components.
Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.
Given that mass of the apple pie: m = 0.30kg
The waitress lifts an apple pie: h = 5m
Acceleration due to gravity: g = 9.8m/s^2
Hence, potential energy gained by the pie: Ep = m•g•h
= 0.30kg x 9.8m/s^2 x 5m
= 14.7 J
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The Sun is 150 million kilometers away from Earth. How long does it take for light to reach Earth from the Sun? (Hint: Light travels at 3 × 10^5 m/s)A. 0.50 secondsB. 5.0 secondsC. 50 secondsD. 500 seconds
Answers
Given
The Sun is d=150 million kilometers away from Earth.
Light travels at v=3 × 10^5 m/s.
To find
How long does it take for light to reach Earth from the Sun?
Explanation
We know
Time taken is given by
\(\begin{gathered} t=\frac{d}{v} \\ \Rightarrow t=\frac{150\times10^6}{3\times10^5} \\ \Rightarrow t=500sec \end{gathered}\)Conclusion
The time taken is D.500 sec
Which of the following statements are TRUE, you can select more than one. * IT
(4 Points)
Chemical reactions always involve changes in energy.
Energy must be taken away to break bonds
Forming bonds releases energy
Energy is released in chemical reactions
Answers
Answer:
Chemical reactions always involve changes in energy.
Energy is released in chemical reactions
Explanation:
Chemical reactions involves the formation and breaking of bonds by the combination of atoms in a system.
Chemical reactions always involve changes in energy which can be exothermic or endothermic in nature. When bonds are broken energy is always released, bond dissociation is an exothermic process. When bonds are formed, energy is used up and this process is an endothermic one.a 60.-kilogram man is pushing a 30.-kilogram lawn mower. compared to the magnitude of the force exerted on the lawn mower by the man, the magnitude of the force exerted on the man by the lawn mower is
Answers
The lawn mover is exerting a force of 30 N on the man.
Given, a man weighing 60 kg is moving a 30 kg lawnmower.
Thus, the lawnmower's force is calculated as 30N - 60N = -30N.
A force is something that pushes or pulls an object. The objects' interactions with one another are what causes push and pull. Force can also be expressed using words like stretch and squeeze.
Force is an external agent that has the power to alter a body's resting or moving state. It has a size and a movement.
The direction of the force is referred to as the force's direction, and the application of force is the point at which the force is applied.
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does anyone have answers to this ;(\
Answers
From the above information provided, the blood type of the individual is O- (O negative) which is found by the reactions of the blood sample with the different antibodies:
Anti-A serum: No reaction
Anti-B serum: No reaction
Anti-Rh serum: No reaction
The individual do not have the A, B, or Rh antigens on their red blood cells, that is corresponding to blood type O-.
What are Rh antigens?Rh antigens, also called Rhesus antigens, are described as transmembrane proteins expressed at the surface of erythrocytes and they appear to be used for the transport of CO2 and/or ammonia across the plasma membrane.
In conclusion, the main Rh antigens on red cells – C, c, D, E, e of which the most important of these is the Rh D.
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part a) as far as energy transformations in this problem go, what forms of energy does he have the moment after he has pushed off the platform?
Answers
The moment after the person has pushed off the platform, the forms of energy they have can include Kinetic energy, Potential energy, Elastic potential energy, and Thermal energy.
1. Kinetic energy: This is the energy of motion. As the person pushes off the platform, they start moving and gain kinetic energy. This energy depends on their mass and velocity.
2. Potential energy: This is the energy an object possesses due to its position or height above the ground. When the person is on the platform, they have potential energy relative to the ground. As they push off and leave the platform, this potential energy is converted into kinetic energy.
3. Elastic potential energy: If the person used a spring-like mechanism to push off the platform, they may also have elastic potential energy. This type of energy is stored in a compressed or stretched object, such as a spring or elastic band. As the person releases the mechanism, the stored energy is converted into kinetic energy.
4. Thermal energy: This energy may also be present to a certain extent due to friction between the person and the platform, or between the person and the air. When there is friction, some of the energy is converted into heat, resulting in a small increase in thermal energy.
It's important to note that the specific forms of energy present will depend on the context and details of the situation described in the problem. These are some of the common forms of energy that can be present after a person pushes off a platform.
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How would we find bond length?
Answers
22.13 .. Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length 5.20 mC>m. What magnitude of force does one line of charge exert o
Answers
Answer:
Two very long uniform lines of charge are parallel and are separated by 0.300 m. Each line of charge has charge per unit length.
Explanation:
Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan
Answers
SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-
They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.
Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.
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Ranjana has average velocity 3.2 m/s
How long does she take to cover a displacement
of 256 m
Answers
Answer:
t= 80 seonds
Explanation:
Given that,
The average velocity of Ranjana, v = 3.2 m/s
We need to find how long does she take to cover a displacement of 256 m. Let she takes t time.
We know that,
Average speed = distance/time
So,
\(t=\dfrac{d}{v}\\\\t=\dfrac{256\ m}{3.2\ m/s}\\\\t=80\ s\)
So, she will take 80 seconds to cover a displacement of 256 m.
Spiderman is standing on a building and notices some shady characters up to no good on the street below. Rather than leap or
jump, Spiderman steps off the building and descends to the street below. Using his spidey-sense, he determines that he fell
for 2.7 seconds. What was the height Ay of the building?
Answers
The height of the building using second equation of motion is 35.721 m
What is the second equation of motion?
In kinematics, equations of motion are referred to as the fundamental principles of an object's motion, including velocity, location, and acceleration that occur at variable time intervals. These three motion equations control motion in all three dimensions of an item.
Second equation of motion: s = ut + a(t^2)/2
where,
s = displacement
u = initial velocity
v = final velocity
a = acceleration
t = time of motion
Given, a = 9.8 m/s/s
t = 2.7 s
Using this equation we find the height of the building,
s = ut + a(t^2)/2
= 0 + 9.8 x 2.7 x 2.7/2
= 71.442/2
= 35.721 m
Hence, the height of the building is 35.721 m
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Question If a force of 2N is used to move a box 1 meter, how much work was done to move the box?
Answers
Answer:
I assume that the force of 2N is applied along the direction of motion and was applied for the whole 1 meter, the formula of work is this; Work = force * distance * cosθ where θ is zero degrees. Plugging in the data to the formula;
Explanation:
Work = 2N * 1m * cos 0º.
Work = 2N * 1m * 1
Work = 2Nm
Work = 2 joules
3. A boy does 15 Joules of work to push a cart covering 2.5 meters. How much force did he use?
Given:
Solve For:
Solution:
Answers
Answer: 6 N
Explanation: W (WORK) = 15 JOULES
S (DISTANCE) = 2.5 m
F (FORCE) = ?
BY USING FORmULA OF WORK DONE
W = F.S
F =W/S
F = 15/2.5
F = 6 N
Gravity obeys an inverse square relation. This statement implies that the force due to gravity between two masses.
Answers
The inverse square relation implies that force resulting from gravity between two masses will decrease as the square of the distance between the two masses increases.
The force of gravity between any two objects is given by,
F = GM₁M₂/R²
Where,
M₁ and M₂ are the masses of the bodies.
R is the distance between them.
We know, if the masses are constant. then the force of gravity will be inversely proportional to the square of the distance between them.
This is what inverse square relation means here.
As the force of gravity and the square of the distance are inversely proportional to each other,
So, when the square of the distance between the masses increases, the force of gravity between the decreases.
Hence of all the options provided, b is the correc0,t which says, the force will decrease on increasing the square of the distance.
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Complete question - Gravity obeys an inverse square relation. This statement implies that the force resulting from gravity between two masses a. will increase as the distance between the two masses increases b. will decrease as the square of the distance between the two masses increases. c. will cause the two masses to move away from each other. d. will cause the two masses to move in a straight line. e. will cause the two masses to orbit each other.
Table C: Average Speeds for Lower Racetrack
Answers
Answer:
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)²)/r
= ((2³.14*50/14.3)²)/50
= 9.64 m/s²
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Explanation:
Highest common factor of 12r and 10
Answers
I think the number 2, not sure
A mass is sliding on a frictionless surface with a speed v. It runs into a linear spring with a spring constant of k, which compresses from position xi to position xf.
a) Write a general expression for the force that the spring exerts on the mass, in term of k and x. Choose the initial position of the front of the spring to be xi=0.
b) Evaluate the relationship in part (b) to arrive at an expression for the work done in terms of known variables.
c) Solve for the numerical value of the work done in Joules given that xi = 0, xf = 58 cm, and k = 55 N/m.
Answers
a) The force exerted by the spring on the mass is given by F = -kx, where F is the force, k is the spring constant, and x is the displacement of the spring from its equilibrium position.
b) The work done by the spring can be calculated using the work-energy principle.
The work done is equal to the change in the spring's potential energy, which is given by the formula W = (1/2)k(xf² - xi²), where W is the work done, k is the spring constant, xf is the final displacement of the spring, and xi is the initial displacement of the spring.
c) Plugging in the given values, xi = 0, xf = 58 cm = 0.58 m, and k = 55 N/m into the formula W = (1/2)k(xf² - xi²), we can calculate the work done as follows:
W = (1/2)(55 N/m)((0.58 m)² - (0 m)²)
W = (1/2)(55 N/m)(0.3364 m²)
W ≈ 9.30 J
Determine the force exert on the mass?a) The force exerted by a spring is proportional to the displacement from its equilibrium position and is given by Hooke's Law as F = -kx, where F is the force, k is the spring constant, and x is the displacement.
Determine the work done?b) The work done by the spring is equal to the change in its potential energy.
Using the formula for the potential energy of a spring, U = (1/2)kx², the work done is given by W = ΔU = (1/2)k(xf² - xi²), where W is the work done, k is the spring constant, and xf and xi are the final and initial displacements of the spring, respectively.
Determine the work done in joule?c) Plugging in the given values, xi = 0 and xf = 0.58 m, and k = 55 N/m into the formula W = (1/2)k(xf² - xi²), we can calculate the work done.
Substituting the values yields W = (1/2)(55 N/m)((0.58 m)² - (0 m)²), which simplifies to W ≈ 9.30 J.
Therefore, the numerical value of the work done by the spring is approximately 9.30 Joules.
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The strength of an object's gravitational force is affected by both____
and____
Answers
Answer:
the answers are "mass" and "distance"
Explanation:
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multiple choice
15) A coiled spring used to help a door close has ________ ________energy when the door is open.
16) After braking, a bicycle's tires increase in temperature as friction causes some of the
mechanical energy to transfer to ________ energy.
Answers
According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.
Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.
The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .
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This waterbottle has a mass of .5 kg. If the net force acting on the bottle is five and to the right what is the bottles acceleration (hint: use formula a=f/m
Answers
Answer:
a = 10/s^2
Explanation:
Answer:
a=10 m/s *2 right
Explanation:
The net force (0.5 kg) divided by the mass (5 N) = 10
The force moved the object to the right.
So you Would put this in the equation a=___ m/s *2 _____
And you would get a=10m/s*2 right
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