We will decrease the wavelength of light in order to cause electrons to be ejected from the surface of this metal.
We have a Light of a given wavelength that is used to illuminate the surface of a metal, however, no photoelectrons are emitted.
We have to find out what can we do in order to cause electrons to be ejected from the surface of this metal.
What is Photoelectric Effect ?The emission of electrons from the surface of the metal when the light of specific frequency (greater than the threshold frequency) falls over it is called photoelectric effect.
Light consists of photons. The energy associated with the photons is used to emit out the electrons from the surface of metal. We know that - Energy can neither be created nor be destroyed and it can only be transferred from one body to another. Hence, the energy of these moving photons is used to emit electrons from the metal surface. The energy associated with the photon is given by -
E = hμ
Where - μ is the frequency of light an h is Planck's constant.
Now, we can see that the energy of the photon is directly proportional to the frequency of light. The minimum frequency required to eject the electron from the metal surface is called Threshold frequency. Thus, we can emit the electron from the metal surface by using the light of frequency greater than threshold frequency.
Hence, we will increase the frequency of light in order to cause electrons to be ejected from the surface of this metal
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What happens when you call someone using your cell phone?
A. Microwaves travel from your cell phone directly to the cell phone
of the person you are calling.
B. Microwaves reach a cell tower, then fiber optic cables send the
signal to a cell tower near the person you are calling.
C. A system of satellites orbiting Earth receives the microwave
signals and sends them to the person you are calling.
D. Sound waves reach a cell tower, then fiber optic cables send the
signal to a cell tower near the person you are calling.
Answer: B, Microwaves reach a cell tower, then fiber optic cables send the signal to a cell tower near the person you are calling.
Explanation:
Answer:D. Sound waves reach a cell tower, then fiber optic cables send the
signal to a cell tower near the person you are calling.
Explanation: just got it right
Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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what is the relationship between harmonics and resonance frequency in a piano
There is direct relationship between harmonics and resonance frequency.
A harmonic is a wave with a frequency that is a positive integer multiple of the frequency of the original wave whereas, resonance frequency is the frequency at which the oscillation reaches to its maximum point. The lowest resonant frequency is known as the fundamental, while on the other hand, the higher resonant frequencies are called overtones. All resonant frequencies are multiples of the fundamental, and are called harmonics. So we can conclude that there is a direct relationship between harmonics and resonance frequency.Learn more about harmonic here: https://brainly.com/question/17315536
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So this is physics any suggestions?
Answer:
8. GPE
9. KE
Explanation:
GPE=mgh
KE=(1/2)mv^2
Neutrons are also known as____
neutrinos
photons
alpha particles
beta particles
Answer:
Beta Particles
Explanation:
A 25 kg box on a horizontal frictionless surface is moving to the right at a speed of +2.0 m/s. The box hits and remains attached to one end of a spring of negligible mass whose other end is attached to a wall. As a result, the spring compresses a maximum distance of 0.50 m, and the box then sticks to the spring and oscillates back and forth.
a. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maximum compression. Calculate the magnitude of the work done by the spring.
b. Calculate the spring constant of the spring.
c. Calculate the frequency of the oscillation of the box.
d. Let x = 0 be the point where the box makes contact with the spring, with positive x directed toward the right. On the axes below, sketch the velocity a of the oscillating box as a function of position x for the range x = -0.50 m to x = +0.50 m.
a. The work done by the spring on the box is equal to the change in kinetic energy of the box as it comes to a stop and then compresses the spring. The initial kinetic energy of the box is:
KEi = (1/2)mv² = (1/2)(25 kg)(2.0 m/s)² = 50 J
At maximum compression, all of the kinetic energy of the box has been converted to potential energy stored in the compressed spring. Therefore, the work done by the spring is:
W = KEi = 50 J
b. The potential energy stored in a spring is given by:
PE = (1/2)kx²
where k is the spring constant and x is the displacement from the equilibrium position. At maximum compression, x = -0.50 m and the potential energy stored in the spring is equal to the initial kinetic energy of the box:
PE = KEi = 50 J
Substituting the given values:
(1/2)k(-0.50 m)² = 50 J
Solving for k:
k = (2)(50 J) / (0.50 m)² = 800 N/m
c. The frequency of oscillation of the box is given by:
f = (1/2π)√(k/m)
Substituting the given values:
f = (1/2π)√(800 N/m / 25 kg) = 2.54 Hz
d. The velocity of the box as a function of position x can be sketched as follows:
At the equilibrium position (x = 0), the box has zero velocity. As it moves to the right, it begins to compress the spring, which slows it down until it reaches maximum compression at x = -0.50 m. At this point, the box has zero velocity again and begins to move back to the right. As it moves away from the spring, it gains speed until it reaches the equilibrium position, where it has maximum velocity. It continues to move to the right and compress the spring again, repeating the cycle. The graph of velocity versus position is a sinusoidal wave, with the maximum velocity at x = 0 and the minimum velocity at x = ±0.50 m.
Our Solar System What is the region that is located between Mars and Jupiter and is labeled A in the illustration? Solar System A
A. The terrestrial belt
B. The comet belt
C. The asteroid belt
D. The Kuiper belt
Answer:
asteroid belt
Explanation:
The asteroid belt is a torus-shaped region in the Solar System, located roughly between the orbits of the planets Jupiter and Mars, that is occupied by a great many solid, irregularly shaped bodies, of many sizes but much smaller than planets, called asteroids or minor planets.
The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s. What is the acceleration of the particle at 3 s?
The acceleration of the particle at 3s is [tex]a = 6 \beta \)
\(v = \alpha + \beta {t}^{2} \)
How to calculate acceleration\(a = \frac{dv}{dt} \\ v = \alpha + \beta {t}^{2} \\ \frac{dv}{dt} = 0 + 2 \beta t \\ \)
if Time is given as 3s
therefore, Acceleration is
\(a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times \beta \times 3 \\ a = 6 \beta \)
Acceleration is
\(a = 6 \beta \)
What is acceleration and velocity?This is the change in velocity with respect to time.
Velocity is a vector quantity that denotes the rate of change of position with respect to time, or a speed with the directional component.
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Thermal energy transfer portfolio 1
A thermal energy transfer portfolio would be an excellent way for students to showcase their knowledge and understanding of this important scientific concept.
Thermal energy transfer is the energy transfer between two or more objects that have different temperatures. This energy transfer can take place in three different ways: conduction, convection, and radiation. A portfolio is a collection of documents or pieces of work that demonstrate a person's skills, abilities, and achievements in a particular area.
Therefore, a thermal energy transfer portfolio would be a collection of documents or pieces of work that demonstrate a person's skills, abilities, and achievements related to thermal energy transfer. This portfolio could include lab reports, experimental data, diagrams, and explanations of the various ways thermal energy can be transferred.
For example, a student's thermal energy transfer portfolio might include:
1. A lab report detailing an experiment they conducted to measure the rate of heat transfer through different materials using conduction.
2. A diagram showing the process of heat transfer through convection in a fluid, such as air or water.
3. A written explanation of the concept of radiation and how it relates to thermal energy transfer.
4. A spreadsheet of data showing the temperature changes in a system as heat is transferred through it.
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is a person believes that dreams have hidden meaning how or she would agree with Freud's ideas about _ content?
A. manifest
B. latent
C. hidden
D. lucid
Answer:B ez
Explanation:
the half-life of sodium-24 is 14.96 hours. if a sample contains 320 mg, how many mg will remain after 150 hours?
The half-life of a radioactive isotope is the time it takes for half of the initial amount to decay. So 0.31 mg will remain after 150 hours.
For sodium-24, the half-life is 14.96 hours. To determine the amount of sodium-24 that remains after 150 hours, we need to calculate the number of half-lives that have occurred during that time. We can do this by dividing the total elapsed time by the half-life of the isotope:
150 hours / 14.96 hours = 10.07 half-lives
Since each half-life reduces the amount of the isotope by half, after 10 half-lives, we would expect the amount to be reduced by a factor of \(2^{10}\) = 1024. So, the amount of sodium-24 that remains after 150 hours would be:
320 mg × (1/1024) = 0.31 mg
This is the theoretical minimum amount of sodium-24 that would remain after 150 hours. In practice, other factors such as environmental conditions and decay products can affect the actual amount remaining.
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The pairs of forces described by Newton's third law must be _________
1) the same type of force
2) exerted on the same object
3) different types of forces
4) different magnitudes
Newton's third law states that to every action, there is an equal and opposite reaction.
For a flat mirror, when there’s a ray that travels parallel to the surface where the object sits and it hits the surface of the mirror, the ray will then be reflected back in the opposite direction like the following diagram. Why can’t it be the same for a concave or convex mirror when the light ray travels parallel to the principle axis?
When a light ray travels parallel to the principal axis of a curved mirror, the ray will not be reflected back in the opposite direction like in the case of a flat mirror.
What is a ray diagram?The reason why this does not occur is because the surface of a curved mirror is not a flat surface and it has a varying curvature, which causes the reflected rays to behave differently compared to the flat mirror.
In the case of a concave mirror, when a light ray travels parallel to the principal axis and strikes the mirror, it is reflected back towards the focus of the mirror. This is because the concave mirror surface curves inward, causing the reflected light rays to converge towards the focus.
In the case of a convex mirror, when a light ray travels parallel to the principal axis and strikes the mirror, it is reflected back in a direction away from the focus of the mirror. This is because the convex mirror surface curves outward, causing the reflected light rays to diverge away from the focus.
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Define measurement with 10 points
Answer:
the process of comparing unknown quantities with known standards quantities are known as measurement
3. You are standing on a scale in an elevator. You have a mass of 75kg. Determine what a scale would
show as your "apparent" weight if...
a. the elevator starts to accelerate upwards at 3.0m/s².
b. the elevator starts to accelerate downwards at 4.0m/s²
a) The scale would show an apparent weight of 961.0N ; b) Scale would show an apparent weight of 435.8N.
What is acceleration?Rate at which velocity of any object changes with time is called acceleration and it is vector quantity.
a. When the elevator starts to accelerate upwards at 3.0m/s², apparent weight of the person on scale will be:
Apparent weight = (mass of the person) x (acceleration due to gravity + acceleration of the elevator)
= 75kg x (9.81m/s² + 3.0m/s²)
= 75kg x 12.81m/s²
Apparent weight = 961.0N
Therefore, scale would show an apparent weight of 961.0N.
b. When the elevator starts to accelerate downwards at 4.0m/s², apparent weight of the person on the scale will be:
Apparent weight = (mass of the person) x (acceleration due to gravity - acceleration of the elevator)
= 75kg x (9.81m/s² - 4.0m/s²)
= 75kg x 5.81m/s²
Apparent weight = 435.8N
Therefore, scale would show an apparent weight of 435.8N.
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light waves a. require a medium. c. are caused by a vibrating object. b. cannot travel through solids.
Light waves cannot travel through solid objects. Therefore, the correct answer is option B.
Lightwaves or visible light are a part of electromagnetic waves/radiation that can be perceived by the human eye. It can travel through various types of mediums and even in a vacuum.
When light travels, it interacts with the atoms and molecules in the medium that it is going through. Because of that, light travels fastest in an empty space and travels the slowest in solid objects.
That being said, light can not travel through many kinds of solid objects. It's because solid objects tend to absorb light instead of allowing it to pass through them.
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NEED HELP ASAP What are the lengths of the x and y components of this vector?
Explanation:
the lengths of the x and y components of the vector :
the x- Component:
Vx = 12×cos72° = 12× 0.3090 = 3.708
the y-component:
Vy = 12×sin72° = 12× 0.9510 = 11.412
-
x-component
= 12 . cos 72
= 12 . 0,3090
= 3,708
y component
= 12 . sin 75
= 12 . 0,9510
= 11,412
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if the frequency is doubled to 80 khz and the current is kept the same, what will be the peak out-of-phase voltage?
The peak out of phase voltage also becomes doubled with increase in frequency .
The frequency of the incident light must exceed a particular frequency a for photoemission to occur cut-off frequency .No matter how bright the light is, photoemission would not occur if the frequency were lower than that. If the initial frequency is assumed to be higher than the cut-off frequency, doubling the frequency will also result in photoemission and non-zero photocurrent.The intensity, on the other hand, is a measurement of the quantity of incident photons per second per unit area. If the frequency is greater than the cut-off frequency, which we have already assumed, then doubling its value will also double the probability of collision with atoms. Frequency=80KHz with current constant makes no effect due to independent factor of intensity.To study more about probability of collision -
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A tennis player player wins a match at a stadium and hit a ball into the stands at 30m/s at an angle of 45° above the horizons , on its way down , the ball is caught by a spectator 10m above the point where the ball was hit. What are the magnitude and direction of the balls velocity at impact .
while checking out the front end of a vehicle, the technician grabs the driver’s side tire and steers the wheels manually left and right. while he does this, he notices that the center link moves up and down. what component is most likely at fault?
The worn idler arm is the component that is most likely at fault.
What occurs when a wheel hits a dip or home and moves downward?
When you hit any bump or dip in a road, your vehicle's suspension and springs move so the tire can stay in contact with the road and absorb the energy. The shock absorbers dampen the movement of the springs by converting the spring's kinetic energy into thermal (heat) energy.
What are the symptoms of a bad idler arm?
What are the warning signs of a bad idler arm? If you notice your steering wheel feels loose or has extra play before the tires respond, this may be a sign of an issue with your idler arm or pitman's arm. If these arms fail completely, you will lose all steering in your vehicle.
Can a worn idler arms cause play?
A steering wheel with too much play that shimmies, shakes, or vibrates too loosely can be a symptom of a bad idler arm. Poor steering likely means the ball joints are worn.
How important is an idler arm?
Idler's arms are particularly important for two reasons. First, as mentioned, the idler arm supports the right end of the track rod. Without it, the track rod would not hold the right wheel in place or turn it effectively, if at all. Second, the idler arm maintains proper toe angle.
Thus, a worn idler arm is a correct answer.
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Can anyone please help
a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.
(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.
(c) The position of the object at 5.0 seconds is 0.5 m.
(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.
What is the motion of the object?(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.
(b) The average velocity of the object between 0 and 15 seconds is calculated as;
average velocity = total displacement / total time
average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s
(c) The position of the object at 5.0 seconds is calculated as follows;
at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.
(d) The motion of the object between 30 and 40 seconds is calculated as;
velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s
Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.
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how much heat transfer (in j) occurs from a system if its internal energy decreased by 200 j while it was doing 44.0 j of work? (enter the magnitude.)
Heat transfer (in j) occurs from a system Q = - 156 J.
Briefly:-We use thermodynamics principles in this situation. There are already obtained relationships for intense properties like internal energy (U), heat transfer (Q), and work (W) that were based on differential equations. The formula is
ΔU = Q + W
But since these factors depend on their signs, we must remember to take them into account. Van Ness, Smith, and Abbott assert that declining has a negative sign convention. If work is being done ON the system, the sign is positive; however, if work is being done BY the system, the sign is negative. in this instance,
ΔU = - 200 J\sW = - 44 J
In that case, Q can be found.
-200 J = Q - 44 J
heat transfer (in j) occurs from a system Q = - 156 J.
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Pretend you are explain net force to someone much younger than you. Explain how to calculate net force and how the net force determines the object’s motion.
Answer:
you can tell them it is the amount of "push" on an object then you can explain using a soccer ball being kicked or a cart being pushed
Explanation:
Please this question
Answer:
1. 7
2. Mass
3. (b) Distance
4. (b) Force
5. (a) ML⁻¹T⁻²
6. (c) M⁻¹LT²
7. (c) M⁻¹L³T⁻²
8. (c) Pressure
9. (c) Young's modulus
10. (b) zero
11. (c) Infinite
12. (d) 1:4
13. (b) 0.6 J
14. (c) 45 N
15. (a) 0.4 cc
16. (a) 176.7 °F
17. (a) 10°C
18. (c) 50 K
19. b. H
Explanation:
15. Whereby the compressibility = 4 × 10⁻⁵ Pa⁻¹
The compression ratio for 100 Pa = 4 × 10⁻⁵ × 100 = 4 × 10⁻³
The Change for 100 cc = 4 × 10⁻³ × 100 cc = 0.4cc
a particular violin string plays at a frequency 300hz. if the tension doubles what will be the new frequency
The new frequency of a particular violin string that plays at a frequency 300hz when the tension is doubled is 424.26 Hz.
Frequency is directly proportional to the square root of the tension. So, if the tension doubles, the frequency will increase by a factor of the square root of 2, or approximately 1.414.
To calculate the new frequency, we can use the following formula:
new frequency = old frequency x √(new tension / old tension)
In this case, the old frequency is 300 Hz and the new tension is double the old tension, so we can plug these values into the formula:
new frequency = 300 x √(2 / 1) = 300 x 1.414 = 424.26 Hz
So, the new frequency of the violin string will be 424.26 Hz when the tension doubles.
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this is actually physical science but there isn’t a tag for that☹︎
the continued existence of a star in any phase of its evolution is a balance between the inward force of
The continued existence of a star in any phase of its evolution depends on a balance between the inward force of gravity and the outward pressure of hot gas.
The inward force of gravity tries to collapse the star, while the outward pressure of hot gas, resulting from nuclear fusion in the core, resists this collapse. This balance of forces is known as hydrostatic equilibrium and is essential for the star to maintain a stable size and temperature. The exact balance between these forces depends on the star's mass, age, and other factors. When this balance is disturbed, it can cause changes in the star's structure, such as expansion or contraction, and may even lead to the star's eventual death.
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Full Question
the continued existence of a star in any phase of its evolution depends on a balance between the inward force of _______ and the outward _______ of hot gas
A proton is moving at 0.950 c. Calculate:
a) its energy at rest
b) its energy total
c) its kinetic energy. (data: mp = 1.6726x10-27 Kg).
A proton is moving at \(0.950 c\). We have to determine its energy at rest, energy total, and kinetic energy.
We know that the mass of a proton is
\(m\)\(p = 1.6726x10^(-27) kg.\)
The speed of light,
\(c = 3 × 10^8 m/s.\)
The rest energy of a proton is given by the equation:
\(Er = mc²\)
Therefore,
\(Er = (1.6726x10^(-27) kg) × (3 × 10^8 m/s)²\)
\(Er = 1.5058x10^(-10) J\)
Now we will calculate the total energy of the proton.
\(Total energy, E = mc²/√(1 - v²/c²)²\)
We have
\(mp = 1.6726x10^(-27) kg, c = 3 × 10^8 m/s, v = 0.950 c.\)
Therefore,
\(E = 1.6726x10^(-27) × 3 × 10^8² / √(1 - 0.950²)²\)
\(E = 3.4683x10^(-10) J\)
The kinetic energy is given by the equation:
\(K.E = E - Er\)
\(K.E = 3.4683x10^(-10) J - 1.5058x10^(-10) J\)
\(= 1.9625x10^(-10) J\)
Therefore, the energy at rest is \(1.5058x10^(-10) J\), the total energy is \(3.4683x10^(-10) J\), and the kinetic energy is \(1.9625x10^(-10) J.\)
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Please help, asap!
Will mark as brainliest!
Answer:
a1)gravity
not sure on others
Explanation:
cause the gravity force pulls u down
Answer:
a) i) Gravitational force
ii) Air resistance
b) (I cannot understand what is the question saying but the unit of acceleration is m/\(s^{2}\) or \(ms^{-2}\))
ii) Because when the parachutist is falling, the gravitational force is pulling him down. But the air resistance is pushing him upwards acting against the gravitational force resulting in a decreasing acceleration.
iii) This is because soon the air resistance catches up with that of the gravitational force and it cancels the gravitational force so he is falling in a constant velocity. This is called terminal velocity when the gravitational force gets cancelled resulting in a free fall where his weight brings him down.
DETAILS MY NOTES Write the nuclear symbols for each of the following. (Enter the mass number in the first raised box, the atomic number in the second lower box, and the element's symbol in the third box.) (a) strontium-90 90 38 Sr (b) xenon-133 133 54 Xe (c) technetium-95 95 To 43 (d) aluminum-25 25 13 Al
(a) The nuclear symbol for strontium-90 is 90 38 Sr.
(b) The nuclear symbol for xenon-133 is 133 54 Xe.
(c) The nuclear symbol for technetium-95 is 95 43 Tc.
(d) The nuclear symbol for aluminum-25 is 25 13 Al.
Here are the nuclear symbols for each of the given elements:
(a) Strontium-90: 90 38 Sr
Strontium has 38 protons in its nucleus. So, the atomic number of strontium is 38. The mass number of strontium-90 is 90. Therefore, the nuclear symbol for strontium-90 is 90 38 Sr.
(b) Xenon-133: 133 54 Xe
Xenon has 54 protons in its nucleus. So, the atomic number of xenon is 54. The mass number of xenon-133 is 133. Therefore, the nuclear symbol for xenon-133 is 133 54 Xe.
(c) Technetium-95: 95 43 Tc
Technetium has 43 protons in its nucleus. So, the atomic number of technetium is 43. The mass number of technetium-95 is 95. Therefore, the nuclear symbol for technetium-95 is 95 43 Tc.
(d) Aluminum-25: 25 13 Al
Aluminum has 13 protons in its nucleus. So, the atomic number of aluminum is 13. The mass number of aluminum-25 is 25. Therefore, the nuclear symbol for aluminum-25 is 25 13 Al.
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