Answer:
See below
Explanation:
power = work / time = 70 000 j / 16.5 s = 4242 w
An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel: (i) (ii) AM Determine whether or not the ice will melt completely; Calculate the final temperature of the system. [ specific heat capacity of ice = 2100 J kg ¹K-¹, latent heat of fusion of ice = 3.33 x 10³ J K-¹, specific heat capacity of water = 4200 J kg ¹K-¹] [6 marks] and hy convection.
An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).
To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.
(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.
Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature
Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))
Energy required for complete melting = mass of ice × latent warmth of fusion of ice
Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)
If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.
(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.
Energy won by the water = mass of water × unique heat ability of water × trade in temperature
Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)
Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:
Energy gained through the ice = Energy won by the water
Using the equations above, we will installation the following equation:
80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)
Thus, this the final temperature of the system.
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A 2.0-V battery is connected in a circuit with an ammeter and an unknown resistor, P. The current is observed to be 0.70 A. What would be the current in the circuit if a 12-V battery replaces the 2.0-V battery?
Answer:
4.2 A
Explanation:
V=IR
V= voltage
I= Current
R= resistance
so you will find the resistance in the circuit so
R= V/I
R=2V/0.70A
R=2.857 ohms ( TO THE NEAREST THOUSANDTH)
then you will find the current of the 12V battery using the resistance in the circuit
I=V/R
I=12/2.857
I=4.2A (TO THE NEAREST TENTH)
Climbing a tree would
A. decrease your potential energy
B. increase your kinetic energy
C. increase your potential energy
Answer:
C Increase your potential energy
Explanation:
Because if you start falling your potential energy would convert to kinetic energy. So you would get potential energy climbing up a tree
Answer:
I think it's potential energy
Help me please!!!!!!!!!!
The velocity of the ball just before it hits the ground is 14.0 m/s
Let's solve the problem using the given equation:
\(v^2 = u^2 + 2as\)
We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.
Plugging in the given values, we get:
v^2 = 0 + 2(9.81)(10)
v^2 = 196.2
Taking the square root of both sides, we get:
v = sqrt(196.2)
v = 14.0 m/s
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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)
Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--
What is the height of the cliff if it takes 2.35 s for a rock to hit the ground when it thrown up from the cliff with an initial velocity of 8 m/s, and how long would it take to reach the ground if it's thrown straight down with the same speed?
Thrown downward at the same velocity, it will take about 0.717 seconds to hit the ground.
A) \(Y = ut -0.5*gt^2\)
= 8*2.35 - 0.5*9.8*2.35^2
= 8.26m (it comes negative bcz its at a lower point)
For part b, V0 = -8.00m/s instead of 8.00m/s, because the initial velocity is downwards instead of upwards.
The complete height equation should be:
\(y_f - y_i = vi*t - 1/2gt^2\)
yf is the final height and yi is the initial height
We know that the cliff is 8.26m from the ground, so yi should be 8.26m and yf should be 0 (when the rock hits the ground)
So you would get
0 =\(vi*t - 1/2gt^2 + yi\)
vi = -8.00m/s because you are throwing the rock downwards, instead of an upwards 8.00m/s as in part a)
Using the quadratic equation, you can solve for t
\(t = [-vi +or- sqrt(vi^2 + 2g*yi)]/(-g) = [vi -or+ sqrt(vi^2 + 2g*yi)]/g\)
We keep only the +, because vi is negative, so we must add a larger value, sqrt(vi^2 + 2g*yi) to make t positive overall. This is because t doesn't make sense when it is negative in this situation.
So, \(t = [vi + sqrt(vi^2 + 2g*yi)]/g\)
= \([-8.00m/s + sqrt(64.0m^2/s^2 + 19.6m/s^2*8.26)]/9.80m/s^2\)
= 0.717s
In normal use and in kinematics, the rate of an object is the importance of the change of its role over time or the significance of the alternate of its position in keeping with a unit of time; its miles accordingly a scalar amount.
The price of change of function of an object in any path. the pace is measured as the ratio of distance to the time wherein the gap becomes included. the pace is a scalar amount because it has the handiest path and no value. speed is defined because of the rate of trade of distance with time. It has the size of distance by means of time. hence, the SI unit of speed is given because of the aggregate of the primary unit of distance and the primary unit of Time. for this reason, the SI unit of pace is a meter in keeping with the second.
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3. An object released from rest at time t = 0 slides down a frictionless incline a
distance of 1 m during the first second. The distance traveled by the object
during the time interval from t = 2 s to t = 3 s is:
(A) 1 m
(B) 2 m (C) 3 m
(D) 4 m (E) 5 m
The distance traveled by the object during the time interval from t = 2 s to t = 3s is 3m. Option C.
From the formula d = ½ at2 the displacement is proportional to the square of time. If you run twice as far from the rest, the displacement will quadruple (or 4m). Since the object has already moved 1 m in the first second, the remaining 3 m have moved in time intervals from 1 to 2 seconds.
This means that the velocity and net force in the direction normal to the plane must be zero. Assuming the plane is frictionless means that the plane exerts no force on the block parallel to the surface. For angular frictionless tilt, the acceleration is the result of the gravitational acceleration multiplied by the sine of the angle.
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A 12-kg iron ball is dropped onto a pavement from a height of 150 m . Suppose that half of the heat generated goes into warming the ball. What is the temperature increase of the ball. (The specific heat capacity of iron is 450 J/kg ⋅ ∘C. Use 9.8 N/kg for g.).
The temperature increase of the ball will be 1.633 degree.
when the ball comes in contact with the pavement then its kinetic energy will be equal to potential energy of the ball before it was dropped and half of the KE goes to warming or heat generation.
So. heat energy = K.E/2 = mgh/2 (because K.E = P.E before dropping)
= 12 x 9.8 x 150/2
= 8820
Now, As we know that,
Q = m x C ΔT
where Q is the heat energy, m is the mass and C is the specific heat capacity and ΔT is the temperature change.
putting all the values we get
ΔT = 8820/(12 x 450) = 1.633 degree
Hence the temperature increase of the ball is 1.633 degree.
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A girl weighing 45kg is standing on the floor, exerting a downward force of 200N on the floor. The force exerted on her by the floor is ..............
Select one:
a.
No force exerted
b.
Less than 2000N
c.
Equal to 200 N
d.
Greater than 200 N
Answer:
c.
Equal to 200 N..........
Draw the electric field between two equal negative charges.
The two negatively charged particles repel each other. Thus, the electric field lines of both the charges will be moving away from each other.
The electric field lines start from the positive charge and end at the negative charge. Thus, in the given case, the direction of electric field lines from both the charges will be towards the charge itself.
The diagrammatic representation of electric field lines between the two negative charges is,
formula for inertia speed
Answer:
The equation of momentum for a linear system is simply P = mv where P = momentum (kg·m/sec or lb·ft/sec); m = mass (kg or lb); and v = velocity (m/s or ft/sec). ... By reducing her inertia (I = mr2 where r has been decreased) her angular velocity, ω, must increase in order for the angular momentum to remain constant.
https://www.gstatic.com/education/formulas2/355397047/en/moment_of_inertia.svg
hope this helps?
Explanation:
Animals change their feature according to their environment
How does a battery generate electrical energy?
wich of the following are commonly distributed by veterinary assistants in typical veterinary practice?
If an object is accelerating at a rate of 8 m/s^2 what is the mass of the box.
See attached
Answer:
50 kg
Explanation:
fnet=ma
600-200=m8
divide both side by 8 to make m the subject of the formula Thus m=50kg
A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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at what speed is the top of the ladder along w the electrician sliding down the wall at that instant
The given problem can be exemplified in the following diagram:
We are given that a ladder is against a wall. According to the diagram, the ladder, the wall, and the floor form a right triangle, therefore, if "T" is the distance from the top to the floor and "B" is the distance from the bottom to the wall we can apply the Pythagorean theorem and we get:
\(T^2+B^2=14^2\)Now, since we want to know the speed, we will derivate implicitly with respect to time on both sides of the equation:
\(2T\frac{dT}{dt}+2B\frac{dB}{dt}=0\)Now we solve for the value of the speed of the top of the ladder, this is dT/dt:
\(2T\frac{dT}{dt}=-2B\frac{dB}{dt}\)The 2 cancels out:
\(T\frac{dT}{dt}=-B\frac{dB}{dt}\)Now we divide both sides by "T":
\(\frac{dT}{dt}=-\frac{B}{T}\frac{dB}{dt}\)Now, since we determine the value of "T" from the Pythagorean theorem, we get:
\(T^2+B^2=14^2\)Subtracting B squared from both sides:
\(T^2=14^2-B^2\)Taking the square root:
\(T=\sqrt[]{14^2-B^2}\)Now we replace these values in the formula for the velocity:
\(\frac{dT}{dt}=-\frac{B}{\sqrt[]{14^2-B^2}}\frac{dB}{dt}\)Now we have an expression for the velocity of the top of the ladder. Replacing the given values:
\(\frac{dT}{dt}=-\frac{6ft}{\sqrt[]{14^2-(6ft)^2}}(1\frac{ft}{s})\)Solving the operations we get:
\(\frac{dT}{dt}=-0.47\frac{ft}{s}\)Therefore, the speed of the top of the ladder is -0.47 feet per second.
In the park, there are 25 pigeons, 15 squirrels, 5 rabbits, and 5 stray cats. Why
can't you draw a line graph using only this information?
Answer: Line graph should be used to show how one variable changes over time not to show multiple categories or variables are at one specific point in time.
Explanation:
In maths, statistics, and related fields, graphs are used to visually display variables and their values. In the case of line graphs, these are mainly used to display evolution or change of a variable over time. For example, a line graph can show how the number of divorces changed from 1920 to 2010.
In this context, the number of different animals in the park cannot be represented through a line graph because this situation does not imply a variable changing over time. Moreover, this situation includes multiple variables or categories of animals and the data shows only one specific point in time, which can be better represented through a bar graph.
what is climate change?
What Is Climate Change?
Climate change refers to long-term shifts in temperatures and weather patterns. These shifts may be natural, such as through variations in the solar cycle. But since the 1800s, human activities have been the main driver of climate change, primarily due to burning fossil fuels like coal, oil and gas.
Burning fossil fuels generates greenhouse gas emissions that act like a blanket wrapped around the Earth, trapping the sun’s heat and raising temperatures.
Examples of greenhouse gas emissions that are causing climate change include carbon dioxide and methane. These come from using gasoline for driving a car or coal for heating a building, for example. Clearing land and forests can also release carbon dioxide. Landfills for garbage are a major source of methane emissions. Energy, industry, transport, buildings, agriculture and land use are among the main emitters.
The Earth is feeling the heat.
Greenhouse gas concentrations are at their highest levels in 2 million years
And emissions continue to rise. As a result, the Earth is now about 1.1°C warmer than it was in the late 1800s. The last decade (2011-2020) was the warmest on record.
Many people think climate change mainly means warmer temperatures. But temperature rise is only the beginning of the story. Because the Earth is a system, where everything is connected, changes in one area can influence changes in all others.
The consequences of climate change now include, among others, intense droughts, water scarcity, severe fires, rising sea levels, flooding, melting polar ice, catastrophic storms and declining biodiversity.
The Earth is asking for help.
People are experiencing climate change in diverse ways
Climate change can affect our health, ability to grow food, housing, safety and work. Some of us are already more vulnerable to climate impacts, such as people living in small island nations and other developing countries. Conditions like sea-level rise and saltwater intrusion have advanced to the point where whole communities have had to relocate, and protracted droughts are putting people at risk of famine. In the future, the number of “climate refugees” is expected to rise.
Every increase in global warming matters
In a series of UN reports, thousands of scientists and government reviewers agreed that limiting global temperature rise to no more than 1.5°C would help us avoid the worst climate impacts and maintain a livable climate. Yet policies currently in place point to a 2.8°C temperature rise by the end of the century.
The emissions that cause climate change come from every part of the world and affect everyone, but some countries produce much more than others. The 100 least-emitting countries generate 3 per cent of total emissions. The 10 countries with the largest emissions contribute 68 per cent. Everyone must take climate action, but people and countries creating more of the problem have a greater responsibility to act first.
Photocomposition: an image of the world globe looking worried to a thermometer with raising temperatures
We face a huge challenge but already know many solutions
Many climate change solutions can deliver economic benefits while improving our lives and protecting the environment. We also have global frameworks and agreements to guide progress, such as the Sustainable Development Goals, the UN Framework Convention on Climate Change and the Paris Agreement. Three broad categories of action are: cutting emissions, adapting to climate impacts and financing required adjustments.
Switching energy systems from fossil fuels to renewables like solar or wind will reduce the emissions driving climate change. But we have to start right now. While a growing coalition of countries is committing to net zero emissions by 2050, about half of emissions cuts must be in place by 2030 to keep warming below 1.5°C. Fossil fuel production must decline by roughly 6 per cent per year between 2020 and 2030.
Growing coalition
Adapting to climate consequences protects people, homes, businesses, livelihoods, infrastructure and natural ecosystems. It covers current impacts and those likely in the future. Adaptation will be required everywhere, but must be prioritized now for the most vulnerable people with the fewest resources to cope with climate hazards. The rate of return can be high. Early warning systems for disasters, for instance, save lives and property, and can deliver benefits up to 10 times the initial cost.
We can pay the bill now, or pay dearly in the future
Climate action requires significant financial investments by governments and businesses. But climate inaction is vastly more expensive. One critical step is for industrialized countries to fulfil their commitment to provide $100 billion a year to developing countries so they can adapt and move towards greener economies.
Climate finance
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let vector A=2i+3j-k which is anti parallel wit h vector B which has magnitude 6 .find vector B
Let B = b₁ i + b₂ j + b₃ k.
Since A and B are anti-parallel, the angle between them is 180°. Then the dot product of A and B is
A • B = ||A|| ||B|| cos(180°)
⇒ A • B = - ||A|| ||B||
The magnitude of A is
||A|| = √(2² + 3² + (-1)²) = √14
so that
A • B = 2b₁ + 3b₂ - b₃ = -6√14
Because A and B are anti-parallel, their cross product is the zero vector.
A × B = (3b₃ + b₂) i - (2b₃ + b₁) j + (2b₂ - 3b₁) k = 0 i + 0 j + 0 k
⇒ 3b₃ + b₂ = 0, 2b₃ + b₁ = 0, and 2b₂ - 3b₁ = 0
Now,
2b₂ - 3b₁ = 0 ⇒ b₂ = 3/2 b₁
2b₃ + b₁ = 0 ⇒ b₃ = -1/2 b₁
so that
2b₁ + 3/2 b₁ - (-1/2 b₁) = -6√14
7b₁ = -6√14
b₁ = -6/7 √14 = -6 √(2/7)
Similarly,
2b₂ - 3b₁ = 0 ⇒ b₁ = 2/3 b₂
3b₃ + b₂ = 0 ⇒ b₃ = -1/3 b₂
so that
2 (2/3 b₂) + 3b₂ - (-1/3 b₂) = -6√14
14/3 b₂ = -6√14
b₂ = -18/14 √14 = -9 √(2/7)
Finally,
2 (-6 √(2/7)) + 3 (-9 √(2/7)) - b₃ = -6√14
-39 √(2/7) - b₃ = -6√14
b₃ = 6√14 - 39 √(2/7) = 3 √(2/7)
and so the vector B is
B = -6 √(2/7) i - 9 √(2/7) j + 3 √(2/7) k
or equilvalently,
B = -3 √(2/7) (2 i + 3 j - k)
B = -3 √(2/7) A
explain why the length of the pendulum is measured from the lower part of the wooden clamp
The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.
The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.
The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.
As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A body with initial velocity 8.0 m/s moves along a straight line with constant acceleration and travels
640 m in 40 s. For the 40 s interval, find (a) the average velocity, (b) the final velocity, and (c) the
acceleration.
Answer:
(a) The average velocity is 16 m/s
(b) The acceleration is 0.4 m/s^2
(c) The final velocity is 24 m/s
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity (or the speed) of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, final speed is calculated as follows:
\(v_f=v_o+at\qquad\qquad [1]\)
The distance traveled by the object is given by:
\(\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]\)
(a) The average velocity is defined as the total distance traveled divided by the time taken to travel that distance.
We know the distance is x=640 m and the time taken t= 40 s, thus:
\(\displaystyle \bar v=\frac{x}{t}=\frac{640}{40}=16\)
The average velocity is 16 m/s
Using the equation [1] we can solve for a:
\(\displaystyle a=\frac{v_f-v_o}{t}\)
(c) From [2] we can solve for a:
\(\displaystyle a= 2\frac{x-v_ot}{t^2}\)
Since vo=8 m/s, x=640 m, t=40 s:
\(\displaystyle a= 2\frac{640-8\cdot 40}{40^2}=0.4\)
The acceleration is 0.4 m/s^2
(b) The final velocity is calculated by [1]:
\(v_f=8+0.4\cdot 40\)
\(v_f=8+16=24\)
The final velocity is 24 m/s
Astar has a mass of 1.74 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 1.5x 10^4light-years (1 light-year-9.5x 10¹5 m), and the angular speed of the star is 2.9 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?
(a)
In order to calculate the tangential speed, we can use the formula below:
\(\begin{gathered} V=r\omega\\ \\ V=15000\cdot9.5\cdot10^{15}\cdot2.9\cdot10^{-15}\\ \\ V=413250\text{ m/s} \end{gathered}\)(b)
The force that acts on the star to keep it moving around the center is the centripetal force, and it's calculated with the formula below:
\(\begin{gathered} F=\frac{mv^2}{r}\\ \\ F=\frac{1.74\cdot10^{30}\cdot4132.5^2}{15000\cdot9.5\cdot10^{15}}\\ \\ F=208.526\cdot10^{15}\\ \\ F=2.085\cdot10^{17}\text{ N} \end{gathered}\)Help with parts a through part f.
The equation = RC, where R is the resistance and C is the capacitance, yields the time constant of the circuit. We obtain the value = RC = (5.5 k)(4.5 F) = 24.75 ms = 0.02475 s by substituting the above variables.
What is circuit, exactly?In electronics, a circuit is a completely circular channel through which electricity flows. A current source, conductors, and a load make up a straightforward circuit.
The equation = RC, where R is the resistance and C is the capacitance, yields the time constant of the circuit. Inputting the values provided yields:
τ = RC = (5.5 kΩ)(4.5 µF) = 24.75 ms = 0.02475 s
The voltage drop Vc across the capacitor is equal to the voltage of the battery, i.e., Vc = VB = 180 V.
After a very long time, the voltage across the capacitor is equal to the voltage of the battery, i.e., V = VB = 180 V. Substituting the given values, we get:
Q = CV = (4.5 µF)(180 V) = 810 µC = 8.1 × 10⁻⁴ C
The current I in the circuit is equal to the current in the resistor, which is given by Ohm's law as I = V/R, where V is the voltage of the battery. Substituting the given values, we get:
I = V/R = (180 V)/(5.5 kΩ) = 32.73 mA = 3.273 × 10⁻² A
To find the time t when the current through the resistor is one-third of its maximum value, we can set I = (1/3)(VB/R) and solve for t:
(1/3)(VB/R) = (VB/R)e(-t/τ)
e(-t/τ) = 1/3
-t/τ = ln(1/3)
t = τln(3) ≈ 0.867τ
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B. Calculate the total resistance of the circuit below. (4 points)
c. In the circuit diagram above, meters 1 and 2 are connected as shown. Write 2 - 3 sentences identifying each type of meter and how it is connected with the 30.0 Ω resistor in the circuit. (4 points)
d. In the circuit diagram above, predict which resistors (if any) will stop working when the switch is opened. Write 2 - 3 sentences explaining your reasoning. (4 points)
B. The equivalent resistance of the two resistors is 20.0 ohms.
C. The voltmeter will measure the voltage across the 30.0 ohm resistor.
D. The 30.0 ohm resistor will stop working.
How to determine resistance?B. The total resistance of the circuit is 60.0 ohms. This is because the 30.0 ohm resistor and the 60.0 ohm resistor are in parallel, and the equivalent resistance of two resistors in parallel is equal to the product of the resistors divided by the sum of the resistors.
R_T = 1/(1/R_1 + 1/R_2 + ...)
In this case, the product of the resistors is:
30.0 ohms × 60.0 ohms = 1800 ohms,
and the sum of the resistors is:
30.0 ohms + 60.0 ohms = 90.0 ohms.
Therefore, the equivalent resistance of the two resistors is 1800 ohms / 90.0 ohms = 20.0 ohms.
C. Meter 1 is an ammeter, and it is connected in series with the 30.0 ohm resistor. This means that the ammeter will measure the current flowing through the 30.0 ohm resistor.
Meter 2 is a voltmeter, and it is connected in parallel with the 30.0 ohm resistor. This means that the voltmeter will measure the voltage across the 30.0 ohm resistor.
D. When the switch is opened, the 30.0 ohm resistor will stop working. This is because the switch is in series with the 30.0 ohm resistor, and when the switch is opened, the circuit is broken.
The 60.0 ohm resistor will continue to work, because it is in parallel with the switch, and the current will continue to flow through the 60.0 ohm resistor even when the switch is opened.
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What are the three states of water in Earth's system?
Answer:
Solid state: Water in the form of ice or snow.
Liquid state: Water in the form of liquid, such as oceans, rivers, lakes, and groundwater.
Gas state: Water in the form of water vapor, which is an invisible gas that is present in the atmosphere.
Vengo una ves en un minuto dos veces en un momento pero no vengo en diez años Ayudaaaaaaa
Answer:
La letra "m"
Explanation:
HALP I NEED THE ANSWER!!!! Move on to electric force. Blow up the two balloons and knot them. Then tie a thread onto each balloon. Suspend the two balloons using tape so that they’re about six inches apart, and check that they don’t move or interact. Rub both balloons with wool or fur. If wool or fur is not available, rub the balloons on your hair. Do they attract or repel (push away) each other?
Answer:
Attract
Explanation:
The balloons attract each other due to electrons.
Hope this helps :)
when did the story happen of paragraph
Answer:
1. The story happens at Masayahin Senior High School,during his first class in grade 11.
2. The transitional divices are used is At first,then,after a year, in the end.
3. I entered the class and jasper offered me a seat.
4. A story.
5. in chronological orde
A 682-kg elevator starts from rest and moves upward for 3.10 s with constant acceleration until it reaches its cruising speed, 1.80 m/s.
(a) What is the average power of the elevator motor during this period? (Answer in horsepower)
(b) How does this amount of power compare with its power during an upward trip with constant speed? (Give the power during an upward trip with
constant speed.) (answer in horsepower)
a) the average power of the elevator motor during this period is 0.1696 hp
b) The power during an upward trip with constant speed is 16.13 horsepower.
To calculate the average power of the elevator motor during the period of acceleration, we need to find the work done by the motor and divide it by the time taken.
Given:
Mass of the elevator (m) = 682 kg
Acceleration (a) = (1.80 m/s - 0) / 3.10 s = 0.5806 m/s²
Time taken for acceleration (t) = 3.10 s
(a) First, let's calculate the displacement (d) using the formula for uniformly accelerated motion:
d = 0.5 * a * t^2
= 0.5 * 0.5806 m/s² * (3.10 s)^2
= 1.0153 m
Next, we can calculate the work done (W) by the elevator motor:
W = m * a * d
= 682 kg * 0.5806 m/s² * 1.0153 m
= 391.55 J
Now, to find the average power (P), we divide the work done by the time taken:
P = W / t
= 391.55 J / 3.10 s
= 126.36 W
To convert the power to horsepower, we can use the conversion factor: 1 horsepower (hp) = 745.7 watts.
Therefore, the average power of the elevator motor during this period is:
P = 126.36 W / 745.7
= 0.1696 hp
(b) During an upward trip with constant speed, the elevator does not accelerate, so the power required is only to counteract the force of gravity and friction. The power during an upward trip with constant speed is equal to the power required to overcome the force of gravity and friction.
The force of gravity (Fg) can be calculated using:
Fg = m * g
= 682 kg * 9.8 m/s²
= 6683.6 N
The power (P) required is given by the formula:
P = Fg * v
= 6683.6 N * 1.80 m/s
= 12030.5 W
To convert the power to horsepower:
P = 12030.5 W / 745.7
= 16.13 hp
Therefore, the power during an upward trip with constant speed is 16.13 horsepower.
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