Let X=Zthe set of inters and Int.A be the set of all singletons of X tben A)- LA PIX) d) None of the shove d b a c

We found that the value of a if the line represented by2y - 3x = 5 is the same as the line represented by By - ax = 20, where a is a constant, is -6.

In the given problem, we are required to find the value of a if the line represented by2y - 3x = 5 is the same as the line represented by By - ax = 20, where a is a constant.

Let's try to find the value of a.

Let's write the equation of the line represented by2y - 3x = 5 in the slope-intercept form:y = (3/2)x + 5/2 (Adding 3x/2 to both sides)

Let's write the equation of the line represented by By - ax = 20 in the slope-intercept form:y = (a/B)x + 20/B (Dividing both sides by B)

As both the lines are same, we get:(3/2)x + 5/2 = (a/B)x + 20/B.

SComparing the constants on both sides, we get:5/2 = 20/BSo, B = 8.

Putting the value of B in the equation obtained in step 3, we get:(3/2)x + 5/2 = (a/8)x + 20/8=> (3/2)x - (a/8)x = 15/8=> (24- a)/16 = 15/8=> a = -6Therefore, the value of a is -6.

We found that the value of a if the line represented by2y - 3x = 5 is the same as the line represented by By - ax = 20, where a is a constant, is -6.

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Answer:

B = 19

Step-by-step explanation:

Answer:

b=19

Step-by-step explanation:

We find this by plugging in numbers that would match the answer so    thats what i did and got the equasion:

19+14=33

Answer:

=6

Step-by-step explanation:

(4√5)i

Step-by-step explanation:

Complex number is a number in the form a + bi, where both a and b are real numbers. A complex number has two parts, the first part a is the real part of the complex number and the second part b is the imaginary part of the complex number. Also, i = √(-1), hence i² = -1.

Complex numbers can also be graphed on the complex plane.

√(-80) = √(-1) × √(80)

But since √(-1) = i

√(-80) = i × √80 = i × √16 × √5 = i × 4 × √5 = (4√5)i

√(-80) = (4√5)i

Answer:

A

Step-by-step explanation:

edge 2020

Answer:

\(x = \frac{y}{3} - 1\)

Step-by-step explanation:

\(1. \: 4y - 8 - 4 = 12x \\ 2. \: 4y - 12 = 12x \\ 3. \: \frac{4y - 12}{12} = x \\ 4. \: \frac{4(y - 3)}{12} = x \\ 5. \: \frac{y - 3}{3} = x \\ 6. \: - 1 + \frac{y}{3} = x \\ 7. \: \frac{y}{3} -1 = x \\ 8. \: x = \frac{y}{3}-1\)

Answer:

\(\\\sf7x^3 - 2x^2 - 5\)

Step-by-step explanation:

\(\\\sf(6x^3 + 3x^2 - 2) + (x^3 - 5x^2 - 3)\)

Remove parenthesis.

6x^3 + 3x^2 - 2 + x^3 - 5x^2 - 3

Rearrange:

6x^3 + x^3 + 3x^2 - 5x^2 - 2 - 3

Combine like terms to get:

----------------------------------------

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Hope this helps! :)

Answer:

7x³ - 2x² - 5

Step-by-step explanation:

(6x³ + 3x² - 2) + (x³ - 5x² - 3)

Remove the round brackets.

= 6x³ + 3x² - 2 + x³ - 5x² - 3

Put like terms together.

= 6x³ + x³ + 3x² - 5x² - 2 - 3

Do the operations.

= 7x³ - 2x² - 5

____________

hope this helps!

Yes, the connection between the semimajor axis and an orbit's period varies as the eccentricity of the orbit changes.

In geometry, the eccentric definition is the distance from any point on a conic section to the focus divided by the perpendicular distance from that point to the nearest directrix. In general, eccentricity aids in determining the curvature of a form. The eccentricity grows as the curvature lowers.

Here,

In general, an orbit's period is proportional to the square root of the semimajor axis multiplied by three. This connection, however, is only valid for circular orbits with zero eccentricity. When the eccentricity is larger than zero, the period of the orbit is still determined by the magnitude of the semimajor axis, but it is also determined by the form of the orbit as given by the eccentricity. The relationship between the semimajor axis and the period in this situation is not as straightforward as a proportionate relationship.

As a result, modifying an orbit's eccentricity modifies the connection between the semimajor axis and the period.

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The utility function is u(x₁, x₂) = x₁ + x₂, and two budget constraints are given: (p₁, p₂, m) = (1, 2, 30) and (p₁', p₂, m) = (3, 2, 30).

To compute the total effect, substitution effect, and income effect, we compare the initial equilibrium bundle (x₁, x₂) to the new equilibrium bundle after the price change.

The total effect measures the change in utility when both the price and income change simultaneously. In this case, the price of good 1 changes from p₁ to p₁' while the income remains the same. By calculating the utility at the initial and new equilibrium, we can determine the total effect.

The substitution effect measures the change in utility due to the price change while holding utility constant. To isolate the substitution effect, we adjust the income to keep utility unchanged. We calculate the utility at the new equilibrium with the adjusted income, assuming the original price remains unchanged.

The income effect measures the change in utility due to the change in income while holding prices constant. We adjust the income to the new value while keeping prices constant and calculate the utility at the new equilibrium.

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Out of the given figures, namely, a square, triangle, a trapezoid, a regular pentagon, and a rhombus, a test would require selecting a figure among these figures.

However, we can understand the nature of each of these figures, their characteristics, properties, and formulas related to them, and determine how to select a figure for the test.The square has four sides and four right angles, with all sides of equal length.

Its formula for area is A = s²,

where s is the length of the sides.

The triangle is a polygon with three sides, with its area calculated as A = (1/2)bh,

where b is the base and h is the height of the triangle.A trapezoid is a quadrilateral with only one pair of parallel sides. Its formula for area is A = [(b1+b2)/2]h,

where b1 and b2 are the lengths of the parallel sides, and h is the height of the trapezoid.

A regular pentagon is a polygon with five sides, with all sides of equal length. Its area formula is A = (1/4)s²√(25+10√5), where s is the length of the sides.

The rhombus has four equal sides, with opposite angles being equal.

Its area formula is A = (1/2) d1d2, where d1 and d2 are the lengths of the diagonals.

Depending on the nature and level of the test, the selection of any of the figures can vary. For example, if the test is related to the calculation of areas, the selection of square, triangle, trapezoid, and rhombus would be more appropriate, while the selection of a regular pentagon can be suitable for a more advanced test.

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Answer:

dont post stuff like this on brainly, it is for homework only

Step-by-step explanation:

Answer:

The equation of this line is

\(y = 18x\)

Answer:

x = number of hours to train plan a clients

x = 0.55 hour

y = number of hours to train plan b clients

y = 0.87 hours

Step-by-step explanation:

Friday

Plan a = 8 clients

Plan b = 3 clients

Total hours = 7

Saturday

Plan a = 3 clients

Plan b = 5 clients

Total hours = 6

Let

x = number of hours to train plan a clients

y = number of hours to train plan b clients

8x + 3y = 7 (1)

3x + 5y = 6 (2)

Multiply (1) by 5 and (2) by (3)

40x + 15y = 35 (3)

9x + 15y = 18 (4)

Subtract (4) from (3)

40x - 9x = 35 - 18

31x = 17

Divide both sides by 31

x = 17 / 31

= 0.548 hour

Approximately

x = 0.55 hour

Substitute x = 0.55 hour into (1)

8x + 3y = 7

8(.55) + 3y = 7

4.4 + 3y = 7

3y = 7 - 4.4

3y = 2.6

Divide both sides by 3

y = 2.6 / 3

= 0.867 hours

Approximately

y = 0.87 hours

x = number of hours to train plan a clients

x = 0.55 hour

y = number of hours to train plan b clients

y = 0.87 hours

The input and the output of a function are key components in understanding how a function operates. The input refers to the value or values that are given to the function as an argument, while the output refers to the result or results that the function returns after processing the input.

In other words, the input is what you provide to the function, and the output is what you get in return. The input can be a single value or a set of values, depending on the requirements of the function. The output can also be a single value or a collection of values, again depending on the function's purpose.

It's important to note that the input and output of a function are not always the same. The function may perform calculations or transformations on the input, and the output may be different from the input. This transformation is what gives functions their ability to perform specific tasks and solve problems.

In summary, the input is what you give to a function, and the output is what you get in return after the function processes the input.

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I believe the difference is 5 degrees Fahrenheit.

Answer:

\(x=\frac{125}{6},\\y=11\)

Step-by-step explanation:

The angles marked \(7x-15\) and \(5x-5y\) are co-interior angles. Since all co-interior angles are supplementary (add up to 180 degrees), we have the following equation:

\(7x-15+5x-5y=180\)

The two angles marked \(4x+4y\) and \(2x+y\) are also co-interior angles, thus must also add to 180 degrees.

Therefore, we have the following system of equations:

\(\begin{cases}7x-15+5x-5y=180,\\4x+4y+2x+y=180\end{cases}\)

Combine like terms:

\(\begin{cases}12x-5y-15=180,\\6x+5y=180\end{cases}\)

Divide the first equation by -2 and add both equations to get rid of \(x\):

\(\begin{cases}-6x+2.5y=-97.5,\\6x+5y=180\end{cases},\\-6x+6x+2.5y+5y=82.5,\\7.5=82.5,\\y=\boxed{11}\)

Now substitute \(y=11\) into any equation with \(x\):

\(6x+5y=180,\\6x+5(11)=180,\\6x+55=180,\\6x=125,\\x=\boxed{\frac{125}{6}}\)

Verify that these two solutions work:

\((7(\frac{125}{6})-15)+(5(\frac{125}{6})-5(11))=180\:\checkmark,\\\\(4(\frac{125}{6})+4(11))+(2(\frac{125}{6})+11)=180\:\checkmark\)

The frequency distribution of lottery winners of age between 19 and 40 is 7, and 3.32% of lottery winners are 70 years or older.

To find the frequency of lottery winners of age between 19 and 40, we need to add the frequencies of the age groups [20,29] and [30,39].

Frequency of lottery winners between 20 and 29 years old = 2

Frequency of lottery winners between 30 and 39 years old = 5

Frequency of lottery winners between 19 and 40 years old = 2 + 5 = 7

Therefore, the frequency of lottery winners of age between 19 and 40 is 7.

To find the percentage of lottery winners who are 70 years or older, we can use the cumulative relative frequency. We know that the cumulative relative frequency for the age group [70,79] is 0.9668, which means that 96.68% of the lottery winners are 70 years old or younger. Therefore, the percentage of lottery winners who are 70 years or older is:

100% - 96.68% = 3.32%

So, 3.32% of lottery winners are 70 years or older.

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The coordinates of the y-intercept of the line is (0, 17)

Defining y-intercept before working out the coordinates for the equation. The y-intercept is the point where the line will intersect the y-axis on graph. Since the line intersects at y-axis, there will be no x-axis coordinate.

Hence, for calculation, the value of x will be zero. Keeping the value to find y-intercept.

y = 3×0 + 17

Performing multiplication on Right Hand Side

y = 0 + 17

Performing addition on Right Hand Side

y = 17

So, the coordinates are (0, 17).

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Answer:

Hypotenuse = 10 Cm

Step-by-step explanation:

Given:

θ = 60°

Base = 5 cm

Hypotenuse = x cm

Find:

Hypotenuse

Computation:

Cos θ = Base / Hypotenuse

Cos 60° = 5 / Hypotenuse

0.5 = 5 / Hypotenuse

Hypotenuse = 10 Cm

1 (a) Proof that every nice tree with n vertices has n - 1 edges:

Let G = (V, E) be an undirected graph with n vertices and T = (V, T) be a nice tree of G. To prove that T has n - 1 edges, we can use the concept of tree properties:

T is connected: By definition, T is a connected subset of edges. Since it is a nice tree, it must connect all vertices in V.

T is acyclic: Again, by definition, T is an acyclic subset of edges. There are no cycles within T.

Each edge in T adds exactly one new connection between two vertices without creating a cycle. Therefore, every nice tree of a graph with n vertices has n - 1 edges.

(b) Proof that if T is a subset of n-1 edges, where n = |V|, then the graph (V, T) is connected if and only if it is acyclic:

First, let's prove that if the graph (V, T) is connected, then it is acyclic:

Assume that (V, T) is connected. If there exists a cycle in (V, T), we can remove one edge from the cycle. However, this contradicts the assumption that (V, T) is connected. Therefore, if (V, T) is connected, it must be acyclic .

Now, let's prove that if the graph (V, T) is acyclic, then it is connected:

Assume that (V, T) is acyclic. We will prove it is connected by contradiction. Since (V, T) is acyclic, there must be at least one edge connecting A and B, which contradicts the assumption. Therefore, if (V, T) is acyclic, it must be connected.

2. To prove the equivalence between every edge of a nice tree T of a graph G with all edge costs being distinct satisfies the bottleneck property and T is a minimal nice tree, we need to show both directions.

Direction 1: If every edge of T satisfies the bottleneck property, then T is a minimal nice tree. Assume that every edge of T satisfies the bottleneck property. We will prove that T is a minimal nice tree by contradiction.

Direction 2: If T is a minimal nice tree, then every edge of T satisfies the bottleneck property.

By proving both directions, we have shown that every edge of a nice tree T of a graph G with all edge costs being distinct satisfies the bottleneck property if and only if T is a minimal nice tree.

3. To prove that if an edge e is the cheapest edge crossing a cut (A, B), then e belongs to every minimal nice tree of G, we need to show that e is a necessary edge for every minimal nice tree.

Suppose there exists a minimal nice tree T that does not contain the edge e. We will show that by adding e to T, we can create a new nice tree T' with a lower sum of costs, which contradicts the minimality of T.

Since e is the cheapest edge crossing the cut (A, B), its cost is lower than any other edge that could be part of the path p in T. Therefore, the sum of costs in T' is lower than the sum of costs in T.

Hence, our assumption that there exists a minimal nice tree T without the edge e is false. Therefore, e belongs to every minimal nice tree of G.

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Answer:

344

Step-by-step explanation:

Number of coins added per day in the collection = 9

Number of coins in the collection after 22 days = 218

To find:

Number of coins in the collection after 36 days.

Solution:

First of all, let us find how many coins did he have initially.

Let the number of coins present initially with Wil = \(x\)

Number of coins added per day = 9

Number of coins added after 22 days = 22 \(\times\) 9 = 198

Therefore,

\(x + 198 = 218\\\Rightarrow x = \bold{20}\)

Number of coins present with Wil initially = 20

Number of coins added after 36 days = 36 \(\times\) 9 = 324

Total number of coins after 36 days = Number of coins present initially with Will + Number of coins added = 324 + 20 = 344

Answer:

To answer the questions regarding Mokoena's and his brother's ages, we'll use the given information:

Mokoena is p years old.

His brother is twice his age.

2.1 How old is his brother?

Since his brother is twice Mokoena's age, his brother's age would be 2p.

2.2 How old will Mokoena be in 10 years?

To find Mokoena's age in 10 years, we add 10 to his current age: p + 10.

2.3 How old was his brother 3 years ago?

To find his brother's age 3 years ago, we subtract 3 from his brother's current age: 2p - 3.

2.4 What will their combined age be in q years' time?

To find their combined age in q years' time, we add q to the sum of their current ages: p + 2p + q = 3p + q.

Therefore, the answers are:

2.1 His brother's age is 2p.

2.2 Mokoena will be p + 10 years old in 10 years.

2.3 His brother was 2p - 3 years old 3 years ago.

2.4 Their combined age in q years' time will be 3p + q.

Step-by-step explanation:

Answer:

92

Step-by-step explanation:

1,374 ÷ 15 = 91.6

you can't have .6 of a box so you add an extra one to make 92

9514 1404 393

Answer:

  D)  When 10 movies are streamed in a month; the total price that month is $28.

Step-by-step explanation:

Using the function definition, put 10 where you find m, then evaluate:

  p(10) = 2(10) +8 = 20 +8

  p(10) = 28

The function definition tells you this (28) is the price of streaming 10 movies in a month.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is closest to a. a is 0.1056.

The proportion of scores in a standard Normal Distribution that are greater than 1.25 is:

\(P(Z > 1.25) = 1 - P(Z < 1.25)\)

Using a standard normal distribution table or a calculator.

The area to the left of 1.25 is 0.8944, so:

\(P(Z > 1.25) = 1 - P(Z < 1.25) = 1 - 0.8944 = 0.1056\)

The closest answer choice is (a) 0.1056.

The percentage of scores in a normal distribution with a standard deviation larger than 1.25 is:

either a calculator or a normal distribution standard table.

0.8944 is the region to the left of 1.25, so:

The nearest possible response is (a) 0.1056.

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Answer:

=18/7

=−4/7

Step-by-step explanation:

Divide both sides by -7

−7|−1|=−11

The negatives are canceled.

Simplify

|−1|=11/7

Split the problem into two cases: one positive and one negative

=18/7

=−4/7

Answer:

1552

Step-by-step explanation:

Probably anyway

Tricia has a total of $6.35. The answer is D.

Tricia has 10 quarters, which is equivalent to $2.50 (since 1 quarter is $0.25).

She also has 17 dimes, which is equivalent to $1.70 (since 1 dime is $0.10).

Tricia has 40 nickels, which is equivalent to $2.00 (since 1 nickel is $0.05).

Finally, she has 15 pennies, which is equivalent to $0.15 (since 1 penny is $0.01).

To find the total amount of money Tricia has, we can add up the values of each coin:

$2.50 + $1.70 + $2.00 + $0.15 = $6.35

Therefore, Tricia has a total of $6.35. The answer is option D.

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