let x be the number of rolls of a die needed for all 6 numbers to turn up. calculate both the expected value and the variance of x.

Answer:

Q = 636.48 J

Explanation:

Given that,

The mass of gold, m = 0.052 kg

The temperature increase from 30°C to 120°C.

The specific heat of gold is 136  J/kg °C.

We need to find the heat needed to warm the gold. The formula for heat needed is given by :

\(Q=mc\Delta T\\\\Q=0.052\times 136\times (120-30)\\\\Q=636.48\ J\)

So, 636.48 J of heat is needed to warm gold.

E = sigma/2 * epselon naught

E = 300 * 10^-9/(2 * 8.854 * 10^-12)

E = 1.7 * 10^4 N/C

Assuming that the electric field is uniform all across the surface:

Then, Electric flux = E * A

Electrix flux = 1.7 * 10^4 * 15 = 2.5 x 10^5 Nm^2/C

It should be b)

The electric flux through the given area of the conductor is

2.26 x 10³ Nm²/C.

Surface charge density of the conductor, σ = 300 x 10⁻⁹ C/m²

Area of the conductor, A = 15 m²

The equation for surface charge density is,

σ = q/A    where q is the charge in the conductor.

So,

Charge, q = σ A

q =  300 x 10⁻⁹/15

q = 2 x 10⁻⁸C

Therefore,

Electric flux through the conductor, Φ = q/ε₀

Φ = 2 x 10⁻⁸/8.85 x 10⁻¹²

Φ = 2.26 x 10³ Nm²/C

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Answer:

1.2 meter because the equa

Answer:

1.) 2 seconds

2.) 4.5 hertz

3.) it will become one third its original value

4.) 5.9 seconds

5.) 0.87 meters

Explanation:

just took the connexus quick check

Answer:

the car movves briefly as you ran, however, it stops again after you ran in to the wall

Explanation:

Our net total linear momentum was zero at the time both the train and the boy was at rest. As there is no pressure, the train and boy system's linear momentum can be conserved provided no external forces are working on it that might shift its momentum.

If the boy runs inside of the train with a velocity V1 in the forward direction, the train would have a velocity V2 in the reverse direction to V1 to conserve the system's momentum, resulting in Final momentum.

i.e

\(m \times V_1 + M \times V_2 = 0\)  --- (1)

here;

m = mass of the boy

M = mass of the train

Thus;

\(m \times V_1 =- M \times V_2\) --- (2)

As the boy crashes into the train's wall, a pair of equal and opposing force F intervene on both the train and the boy. This force F causes the boy traveling with momentum m× V1 to come to a halt; its momentum remains zero. As the train moves with about the same momentum as the boy as seen in (2) and is subjected to the same force F, its momentum will be diminished to zero, and it will come to a halt.

Answer:

The distance travel during race is 13 m.

Explanation:

Given that,

Initial speed = 0

Final speed = 13 m/s

Unit time = 1 sec

We need to calculate the distance travel during race

Using formula of distance

\(d=vt\)

Where, d = distance

v = velocity

t = time

Put the value into the formula

\(d=13\times1\)

\(d=13\ m\)

Hence, The distance travel during race is 13 m.

Answer:

c

Explanation:

search it up

Answer:

Option A.

Explanation:

Because this is a lunar eclipse it normally happens 2 times a year.  This is a decently rare phenomenon due to the positions they have to be in to make a lunar eclipse.  Therefore, it is option A.

Answer:

In an ionic bond the valence electrons are transferred from the metal

Explanation:

Answer:

true

Explanation:

Answer: No.

Explanation:

Radiometer dating is used on igneous rocks.

Unlike the other two rock types, sedimentary annd metamorphisis, all igneous rocks possess one specific age/ time of origin.

At maximum height, velocity is zero and kinetic energy will be zero.

K.E(A) = 0

P.E(A) = mgh = 200 x 9.8 x 30 = 58,800 J

K.E(B) = P.E(A) - P.E(B)

K.E(B) = 58,800 J - (200 x 9.8 x 25)

K.E(B) = 58,800 J - 49,000 J

K.E(B) = 9,800 J

K.E = ¹/₂mv²

v² = 2K.E/m

v² = (2 x 9800)/(200)

v² = 98

v = √98

v = 9.9 m/s

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All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.

In terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.

In conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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Answer:

Transition Metals

Explanation:

__________________________

Answer: Solubility; decreasing

Explanation:

Answer:

1.pulley,screw,inclined plane

2.using simple machine properly with right way and precautions

Explanation:

3.cuz if they are not used properly they can cause injuries to organs

The first user who answer is correct :)

The index of refraction for the material is 1.612.

The index of refraction (n) of a material can be calculated using the formula:

n = c / v

where c is the speed of light in vacuum and v is the speed of light in the material.

Given that the speed of light in the material is 1.862x\(10^8\) m/s, we can substitute the values into the formula:

n = (3.00x\(10^8 m/s) / (1.862x10^8 m/s\))

Simplifying the expression:

n = 1.612

Therefore, the index of refraction for the material is approximately 1.612.

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Divide the distance traveled by the time it took:

(100 m) / (4.2 s) ≈ 23.8 m/s

The time taken to get up and out of the way before you and the child collide is 2.82 s.

The time taken to get up and out of the way before you and the child collide is calculated as follows;

s = v + ¹/₂at²

s = v + ¹/₂(g sin (31)t²

where;

The time taken to get up is calculated as;

20 = 0 +  ¹/₂(9.8 sin (31)t²

20 = 2.524t²

t² = 20/2.524

t² = 7.925

t = 2.82 s

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The resistance of a platinum resistance thermometer is 200 Ω at 0°C and 255.8 Ω at the melting point. Using the resistance-temperature relationship and calculations, the estimated melting point is approximately 19.93°C.

The resistance of a platinum resistance thermometer is 200 Ω when placed in a 0°C ice bath and 255.8 Ω when immersed in a crucible containing a melting substance. To determine the melting point of the substance, we need to calculate the temperature at which the resistance reaches 255.8 Ω.

First, we find the temperature coefficient of resistance (α) using the formula α = (R - R₀) / (R₀ * T), where R is the resistance at the melting point, R₀ is the resistance at 0°C, and T is the temperature at the melting point.

Substituting the given values, we have α = (255.8 - 200) / (200 * T₀), where T₀ is the known room temperature of 20°C.

Calculating α, we find α ≈ 0.014.

Next, we use the resistance-temperature relationship equation R = R₀(1 + αT) to solve for the melting point temperature (T). Substituting the known values, we have 255.8 = 200(1 + 0.014 * T).

Simplifying the equation, we find 1.279 = 1 + 0.014T.

Solving for T, we get T ≈ 19.93°C.

Therefore, based on the given data, the estimated melting point of the substance is approximately 19.93°C.

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Answer:

incorporators and it is the one you for the delay to get it for now that the new to me to the same as last week to week in my opinion of your

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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The average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.

Room temperature refers to the typical temperature range that is comfortable for humans in an indoor environment. It is generally considered to be between 68°F (20°C) and 77°F (25°C). However, the exact definition of room temperature can vary depending on the context and the standards of a particular region or industry. In scientific experiments or industrial settings, room temperature may be defined more precisely and may range from 20°C to 25°C, or even narrower ranges such as 22°C to 24°C.

To calculate the average time it took for the tablet pieces to dissolve in room temperature water, we need to add up the times from all three trials and divide by the number of trials (3):

(41.00 + 44.00 + 41.00) / 3 = 42.00 seconds

Therefore, the average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.

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the rope wouldnt move, the force of both dogs pulling us also called tension

Answer:

15mm

Explanation:

We know that for circular holes first dark spot is given by

sin စ = 1.22 λ/D

Also we know that at the same time

tan စ = r/L

So

r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))

= 0.0073 m = 7.3 mm

However since the size is twice that so 14.6 mm which is approx 15mm

Answer:

a) The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. ... It allows hydrophobic molecules and small polar molecules diffuse through the lipid layer, but does not allow ions and large polar molecules cannot diffuse through the membrane

b) Plastids are present in the cells of plants. They are characterised by the presence of pigments. ... Chloroplasts contain chlorophyll and carotenoid pigments responsible for capturing the light energy that is necessary for photosynthesis. The chloroplasts are therefore known as the kitchen of the cell.

c) Lysosomes are known as the suicidal bag of the cell because it is capable of destroying its own cell in which it is present. It contains many hydrolytic enzymes which are responsible for the destruction process. This happens when either the cell is aged or gets infected by foreign agents like any bacteria or virus.

d) Mitochondria are often called the “powerhouses” or “energy factories” of a cell because they are responsible for making adenosine triphosphate (ATP), the cell's main energy-carrying molecule. ... In mitochondria, this process uses oxygen and produces carbon dioxide as a waste product.

e) In Hydra, the cells are arranged in two germinal layers—outer ectoderm and inner endoderm. Between these two layers is a layer of undifferentiated cells called mesoglea. Such kind of pattern of embryonic layers is seen in diploblastic animals. Hence, Hydra is a diploblastic animal.

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Answer:

1.43m

Explanation:

Given data

m1= 50kg

m2=70kg

We are told that Sally m1= 50 sat at one end which is 2m from the center

Hence, the summation of clockwise moment = summation of anticlockwise moment

See the attached image for your reference

50*2= 70*x

100= 70x

x= 100/70

x=1.43m

Hence the mass m2 will be at the 1.43m mark for the net torque to be zero

Answer:

a)  t = 3.027 10⁻⁹ s ,  b)   y = 2.25 10⁻² m

Explanation:

We can solve this problem using the kinematic relations

a) as on the x-axis there is no relationship

          vₓ = x / t

          t = x / vₓ

We reduce the magnitudes to the SI system

          x = 5.6 cm (1m / 100 vm) = 0.056 m

we calculate

          t = 0.056 / 1.85 10⁷

          t = 3.027 10⁻⁹ s

b) the time is the same for the two movements, on the y axis

         y = v₀t + ½ a t²

as the beam leaves horizontal there is no initial vertical velocity

         y = ½ a t²

let's calculate

         y = ½  5.45 10¹⁵ (3.027 10⁻⁹)²

         y = 2.25 10⁻² m

Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

\(v_{f} =v_{i} +(a*t)\\where:\)

Vf = final velocity = 20[m/s]

Vi = initial velocity = 10 [m/s]

a = aceleration = 15 [m/s^2]

Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]