Lenz’s Law allows us to find _______.

the direction of the induced current.
the magnitude of the induced emf.
the direction of the induced emf.
the magnitude of the induced current.

Answer:

c heats up cancer cells and weakens them.

Answer:

I think it is C

Explanation:

because

Answer:

Polarization.

Reason being that phenomena verifies the transverse nature of light

A)The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

B).The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J

C) The rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.

D) The mass of the pulley ismp = (1/2)mpr²/R² =(1/2)(0.020 kg)(0.100 m)²/(0.200 m)² = 0.001 kg = 1 g.r = (1/2)R.

The Atwood's machine shown in Figure 1 consists of two masses mA = 6.50 kg and mB = 3.30 kg. The height of mA above the floor is 0.865 m. When mA hits the floor, its velocity is 1.89 m/s. The pulley has a moment of inertia (1/2)mpr². We have to find the total mechanical energy of the two blocks before they are released, the total mechanical energy when mA hits the ground, the rotational kinetic energy of the pulley just before mA hits the ground, and the mass of the pulley. Let's solve these one by one. Part A The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

The equation for gravitational potential energy is mgh. The gravitational potential energy of mA and mB is mAg(h-hB)where h is the height of mA above the floor and hB is the height of mB above the floor. Since the pulley is at the same height as mB, its gravitational potential energy ismBg(h-hB).The gravitational potential energy of mA is6.50 kg × 9.81 m/s² × 0.865 m = 54.33 J.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J.Part BThe total mechanical energy of the two blocks when mA hits the ground can be found by adding the kinetic energy of mA, the kinetic energy of mB, and the rotational kinetic energy of the pulley to the gravitational potential energy of mB and the pulley. The equation for kinetic energy is (1/2)mv². The kinetic energy of mA is(1/2) × 6.50 kg × (1.89 m/s)² = 11.54 J.The kinetic energy of mB is(1/2) × 3.30 kg × 0 m/s² = 0 J, since it is at rest.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω²,where R is the radius of the pulley and ω is its angular velocity just before mA hits the ground. We can use the fact that the linear speed of the rope is the same on both sides of the pulley to find ω. The equation for linear speed is v = Rω. When mA hits the ground, its speed is 1.89 m/s. The speed of mB is zero. Since the rope is inextensible, the speed of the rope is also 1.89 m/s.

Therefore, the speed of the pulley is also 1.89 m/s. We can find the angular velocity of the pulley by dividing the linear velocity by the radius.ω = v/R = 1.89 m/s ÷ (0.200 m/2) = 18.9 rad/s.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω² =(1/4)mpR²ω² =(1/4)mp(0.200 m)²(18.9 rad/s)² =(0.178 mp) J.The total mechanical energy of the two blocks when mA hits the ground is11.54 J + 0 J + 0 J + (0.178 mp) J = 11.72 J + (0.178 mp) J.Part CThe rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.Part DWe can find the mass of the pulley by using the moment of inertia of a disk and the mass of the pulley. The moment of inertia of a disk is (1/2)mr². Therefore,(1/2)mpR² = (1/2)mpr²,where R is the radius of the pulley and r is the radius of gyration of the pulley. The radius of gyration of a disk is (1/2)R.

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The statement shows a case of rotational motion, in which the disc decelerates at constant rate.

i) The angular acceleration of the disc (\(\alpha\)), in revolutions per square second, is found by the following kinematic formula:

\(\alpha = \frac{\omega_{f}-\omega_{o}}{t}\) (1)

Where:

If we know that \(\omega_{o} = \frac{5}{12}\,\frac{rev}{s}\), \(\omega_{f} = 0\,\frac{rev}{s}\) y \(t = 15\,s\), then the angular acceleration of the disc is:

\(\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}\)

\(\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}\)

The angular acceleration of the disc is \(\frac{1}{36}\) radians per square second.

ii) The number of rotations that the disk makes before it stops (\(\Delta \theta\)), in revolutions, is determined by the following formula:

\(\Delta \theta = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha}\) (2)

If we know that \(\omega_{o} = \frac{5}{12}\,\frac{rev}{s}\), \(\omega_{f} = 0\,\frac{rev}{s}\) y \(\alpha = -\frac{1}{36}\,\frac{rev}{s^{2}}\), then the number of rotations done by the disc is:

\(\Delta \theta = 3.125\,rev\)

The disc makes 3.125 revolutions before it stops.

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The vehicle has a 2000kg mass.

Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.

F= ma

m= F/a

m= 50000/25

m= 2000 kg

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.

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Answer:

False.

Explanation:

The sum of two or more vectors is called a resultant.

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

Answer:

the bubble appears DARK

Explanation:

This problem shows the interference by reflection of light on the surface, let's take it into account;

* There is a phase change of 180º on the surface when it stops from a lower medium to a higher index

* Within the film the wavelength changes due to the fraction index

           \(\lambda_n = \frac{\lambda_o}{n}\)

if we plug this into the expression for constructive interference we have

       2tn = (m + ½) λ₀

for destructive interference it is

       2tn = m λ₀

apply these expressions to our case

indicate that the incident wavelength is red λ₀ = 700 nm

Let's find the minimum thickness that the film must have to have a constructive interference

the refractive index of soap is n = 1.4

from the constructive interference equation

            t = (0+ ½) 700 10⁻⁹ / 2 1.4

            t = 1.25 10⁻⁷ m

just before the soap bubble explodes the thickness (t) of the film less than the calculated value there is no possibility of constructive interference, therefore the bubble appears DARK

Answer:

A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

\(M_{before} = M_{after}\)

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

\((m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})\)

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

Now replacing and solving:

(0.5*5) - (0.05*30) = (0.5*v3) + (0.05*34)

1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

The negative sign means that the movement is towards left

Answer:

A. 1.4 m/s to the left

Explanation:

Answer:

The color of the Anthocyanins changes depending on the PH of what they come into contact with, because wine already has acid in its Anthocyanins are red. But as soon as you expose those Anthocyanins to more alkaline factors, it will start to turn blue.

Answer:

\(force = mass \times acceleration \\ 100 = 50 \times a \\ a = 2 \: {ms}^{ - 2} \\ from : \: \: v = u + at \\ 150 = 100 + (2 \times t) \\ 50 = 2t \\ time = 25 \: seconds\)

Answer: A. I,II and III

Explanation:

Let's describe the situation in a simplified way.

First remember, in ambient temperature, the candle is in solid form.

As you light the candle, the region of the candle near the flame suffers an increase in energy, caused by the heat of the flame. As you know, when we give enough heat to a solid, it will change of phase, from solid to liquid, and this is why the candle melts. Now, this change of phase is due to the heat of the flame, so when the liquid phase is away from the flame (because the flame went out, or because the liquid wax fell and now is far from the flame) the wax will cool down, and return to the solid phase.

Then we must have:

Presence of heat to go from solid to liquid.

Absence of heat to go from liquid to solid.

And we have a flame, then we must have presence of oxygen.

Then the correct option is:

A. I,II and III

Answer:

There is no scientific evidence that playing specifically l badminton makes you a better person, but sport and exercise in general release hormones which can make you feel more happy therefore making you nicer to the people around you and 'a better person'.

Answer:

It's true because playing any sport makes a person happy. So a happy person is a better person.

Please Mark as brainliest.

Answer:

However, those astronauts would experience a second spectacle: A solar eclipse caused by the Earth – the Sun disappearing behind the dark disc of the Earth. When Earth inhabitants witness a lunar eclipse, Moon inhabitants would, simultaneously be witnessing a solar eclipse.

The silver would be coolest since it has the lowest heat capacity.

Heat capacity, also known as thermal capacity, is the amount of heat energy required to raise the temperature of a substance by a certain amount. It is expressed as the amount of heat energy per unit temperature change, and is usually measured in joules per kelvin (J/K) or calories per degree Celsius (cal/°C).

Heat capacity is a key property of materials that provides important information about their thermal behavior and is critical for many areas of science and technology.

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(1) The distance of the image formed by the lens is determined as 6 cm.

(2) The image formed is real.

The distance of the image formed by the lens is calculated by applying the following formula as follows;

1/f = 1/v + 1/u

where;

The distance of the image formed by the lens is calculated as;

1/v = 1/f - 1/u

1/v = 1/2 - 1/3

1/v = 1/6

v = 6 cm

Since the sign of the image of the image is positive, the image formed is real.

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The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer: for part A Its A the ANSWER for part B its D

Explanation:

Answer:

a and b

Explanation:

Coal-fired power plants are the major sources of acid rain.

Thus, the correct option is B

Answer:

1,000KG*M/S

Explanation:

P=M*V

100KG*10M/S=1,000KG*M/S

Answer:

if its winter

Explanation:

then we know it will me cold

The mass of the girl is 30 kg  in order for the seesaw to be in equilibrium.

A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.

As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.

Let the  mass of the girl = m kg

In equilibrium;

40 kg × 300 cm = m × 400 cm

⇒ m = 30 kg.

Hence,  the mass of the girl is 30 kg.

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Answer:

the answer is d the world  trade organization

Explanation:

Answer:

1.62 m/s

Explanation:

Wavelength of the water wave= 54 m

The frequency is 0.03 Hz

Therefore the velocity can be calculated as follows

Velocity= frequency × wavelength

= 0.03 × 54

= 1.62 m/s

Answer:

1.152 miles

Explanation:

Given: central angle = 1 minute = \((\frac{1}{60}) ^{o}\)

           radius of the earth = 3960 miles

The length of an arc = \(\frac{\alpha }{360^{o} }\) 2\(\pi\)r

where: \(\alpha\) is the central angle, and r is the radius.

Thus,

Distance along the arc = \(\frac{\alpha }{360^{o} }\) 2\(\pi\)r

Distance along the arc = \(\frac{(\frac{1}{60}) ^{o} }{360^{o} }\) x 2 x \(\frac{22}{7}\) x 3960

                                      = \(\frac{(\frac{1}{60}) ^{o} }{360^{o} }\) x 24891.4286

                                      = 1.1524

The required distance along an arc is 1.152 miles.

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

To create a tragic past for your character, you would have to write a plot that shows a sad ending to a good story.

This refers to a type of story that has negative emotions such as sadness, death, etc.

Hence, we can see that for example, you could write about two lovers and how despite all the struggles they faced, eventually died in mysterious circumstances.

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Answer:

a = 0.1 m/s²

Explanation:

       \(F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)\)

       \(F_{net} = m* a = 300 Kg * a = 30 N (2)\)

        \(a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)\)