L'atomo è composto da protoni,neutroni ed elettroni

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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a) In the reaction \(H_2CO_3 + CN^- = HCN + HCO^{3-}\), \(H_2CO_3\) acts as an acid by donating a proton (\(H^+\)) to \(CN^-\).

b) In the reaction \(F^- + HSO_4^{-} = HF + SO_4^{2-}\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(F^-\).

c) In the reaction \(HSO_4^- + H_2O = H_3O^+ + SO_4^{2-\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(H_2O\).

a) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

b) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

c) The acid is a Bronsted-Lowry acid (donates a proton to a base) but not an Arrhenius acid because it does not produce \(H^+\) ions in water. However, the \(H_3O^+\) ion that is formed can be considered an Arrhenius acid because it produces \(H^+\) ions in water.

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Answer:

In this simulation, you will be able to “see” several different forms of energy and the changes(transfers) that can occur between them.You are also able to work with a system where you canmanipulate the energy input, observe the process of electrical energy generation and manipulatethe output.Click on the “Energy Systems” tab.We will do all of our work here. Be sure to clickthe “Energy Symbols” box so the different types of energy will be visible throughout the process

We have that for the Question "Which energy output objects work with the solar panels" it can be said that  the energy output object that works with the solar panels is the

From the question we are told

Which energy output objects work with the solar panels?

Generally

Inverter

A Inverter is a device used in a solar installation system,with its primary work being conversion from DC(Direct current) to AC(Alternating Current)

Therefore

the energy output object that works with the solar panels is the

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Answer:Many nocturnal animals have a mirror-like layer, called the tapetum, behind the retina, which helps them make the most of small amounts of light.

Explanation:

Answer:

The correct option C. 25.0%. The percentage by mass of cesium Cs in the sample is found as 25%.

Mass percent = mass of solute/ mass of solution

mass percent = mass of solute/ mass of solution * 100 %

mass percent = 100/ 400 *100%

mass percent = 25%

Thus,  the percentage by mass of cesium Cs in the sample is found as 25%.

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Batteries, natural gas, and coal are all chemical energy

The Rutherford experiment rose above Thompson's Model 1911 with his gold-foil experiment. He designed an experiment to use the alpha particles created by a radioactive element as probes. Hope this helps you.

The unit cell volume of the crystal is \(V_c = 9.9084*10^-^2^3 cm^3 / unit cell\) and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Data;

The unit cell volume can be calculated as

\(V_c = 6R^2c\sqrt{3}\\\)

let's substitute the values into the formula

\(V_c = 6 * (1.445*10^-^8)^2 * 1.58 8 * a * \sqrt{3} \\a = 2R\\V_c = 6 * (1.445*10^-^8)^2 * 1.58* 2 * 1.445*10^-^8 * \sqrt{3}\\ V_c = 9.984*10^-^2^3 cm^3 / unit cell\)

The unit cell volume of the crystal is \(V_c = 9.9084*10^-^2^3 cm^3 / unit cell\)

The density of titanium can be calculated as

\(\rho = \frac{nA}{V_c N_a}\)

let's substitute the values into the formula

\(\rho = \frac{nA}{V_c Na}\\ \rho = \frac{6*46.88}{9.9084*10^-^2^3* 6.023*10^2^3} \\\rho = 4.71 g/cm^3\)

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

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A water bath can be used to keep the temperature of the conical flask and its contents at a temperature .

This is a laboratory equipment which contains a heated source and  is used to incubate samples in water at a constant temperature over a period of time.

This is why water bath will be best used to keep the temperature of the conical flask and its contents at a temperature of 45 °C throughout the reaction.

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Answer:

No. of moles \(\approx\) 0.020

Explanation:

To calculate the number of moles of a substance in a solution given its concentration and volume, we use the following formula:

\(\boxed{\mathrm{No. \ of \ moles = Concentration \times Volume}}\),

where concentration is in mol/dm³ (or M) and volume is in L.

In the question, we are told that the volume of the solution is 0.085 L and that its concentration is 0.23 M. Substituting these values into the formula above, we get:

No. of moles = 0.23 × 0.085

                     = 0.01955

                     \(\approx\) 0.020 mol  (3 s.f.)

Therefore, there are 0.020 moles of NH₄NO₃ in the solution.

Explanation:

Using a calorimeter with the highest possible accuracy to measure the heat of reaction.

In the following experiment, a coffee-cup calorimeter containing 100 mL of \(H_{ 2} O\) is used. The initial temperature of the calorimeter is 23.0 ∘C. If 6.60 g of \(CaCl_{2}\) is added to the calorimeter, Final temperature of the solution in the calorimeter = 11.

The first step in solving this problem is to calculate the number of moles of \(CaCl_{2}\\\) added to the calorimeter.

Moles of \(CaCl_{2}\) = mass of \(CaCl_{2}\) / molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 6.60 g / 110.98 g/mol (molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 0.0594 mol

We can use the equation for heat transfer to find the change in temperature of the solution. q = mCsΔT, where q is the heat transferred, m is the mass of the solution, Cs is the specific heat of the solution, and ΔT is the change in temperature.

We know that the initial temperature of the calorimeter is 23.0 ∘C and the mass of the solution is 100 g (since the density of water is 1 g/mL). We can solve for ΔT: ΔT = q / mCs

To find q, we can use the enthalpy change of solution (ΔHsoln) and the number of moles of\(CaCl_{2}\)added: q = ΔHsoln x moles of\(CaCl_{2}\)

q = -82.8 kJ/mol x 0.0594 mol

q = -4.92 kJ

Now we can solve for ΔT: ΔT = (-4.92 kJ) / (100 g x 4.184 J/g⋅∘C)

ΔT = -11.8 ∘C

We can find the final temperature of the solution by adding the change in temperature to the initial temperature: Final temperature = 23.0 ∘C - 11.8 ∘C =11 ∘C.

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(a) The empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) The molecular formula of the compound is approximately \(C_{8}H_{118}O_{3}\)

To determine the empirical formula of the organic compound, we need to find the simplest whole-number ratio of the elements present.

(a) The given percentages of carbon, hydrogen, and oxygen can be converted into moles by dividing them by their respective atomic masses:

Carbon: 0.624 g / 12.01 g/mol = 0.052 mol

Hydrogen: 0.065 g / 1.008 g/mol = 0.064 mol

Oxygen: 0.028 g / 16.00 g/mol = 0.0018 mol

Next, we divide each of the mole values by the smallest mole value (0.0018 mol in this case) to obtain the mole ratio:

Carbon: 0.052 mol / 0.0018 mol ≈ 29

Hydrogen: 0.064 mol / 0.0018 mol ≈ 36

Oxygen: 0.0018 mol / 0.0018 mol = 1

Therefore, the empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) To find the molecular formula, we need the relative molecular mass of the compound, which is given as 1940 g/mol. The empirical formula mass can be calculated by summing the atomic masses in the empirical formula:

Empirical formula mass: (29 × 12.01 g/mol) + (36 × 1.008 g/mol) + (1 × 16.00 g/mol) = 588.94 g/mol

To find the multiplier, we divide the relative molecular mass by the empirical formula mass:

Multiplier: 1940 g/mol / 588.94 g/mol ≈ 3.29

Rounding to the nearest whole number, the molecular formula of the compound is approximately 3 times the empirical formula, resulting in \(C_{8}H_{118}O_{3}\).

In summary, the empirical formula of the compound is\(C_{29}H_ {36}O\), and the molecular formula is approximately \(C_{8}H_{118}O_{3}\).

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Answer:

If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?

Answer:

5)A &D 6)B

Explanation:

Mass of Fe is 55.845 u

Mass of Cl is 35.453 u

And their sum is 91.298 u

Answer:

The answer is

Explanation:

To find the number of entities or particles given the number of moles of a substance we use the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.4 mol

We have

N = 3.4 × 6.02 × 10²³

We have the final answer as

Hope this helps you

Answer:

there are 6 MOLES of zinc nitrate in 145 g

Answer:

74.87% Carbon

Explanation:

The molecular mass of CH4 is 16.042 g/ mole.

X=(100 × 12.01) / 16.042= 74.87%  

Answer:

\(\boxed {\boxed {\sf 74.87 \% \ C}}\)

Explanation:

We want to find the mass percent composition of carbon in methane: CH₄

First, we must calculate the gram formula mass, also called the molar mass. Use the values for mass found on the Periodic Table. Look for carbon and hydrogen.

There is no subscript after C, so there is just 1 atom. There is a subscript of 4 after H, so there are 4 atoms of hydrogen. We must multiply hydrogen's mass by 4.

Calculate the percent composition.

\(\frac {mass \ of \ part}{mass \ of \ whole} *100\)

The part is the carbon, or 12.011 grams.

The whole is the entire compound, CH₄, or 16.043 grams.

\(\frac { 12.011 \ g }{ 16.043 \ g} *100\)

\(0.748675435*100\\74.8675435\)

Let's round to the nearest hundredth. The 7 in the thousandth place tells us to round the 6 to a 7.

\(74.87 \% \ C\)

The mass percent of carbon is 74.87%

Answer:

I think u willl get the answer fast in......

Answer:

this is because when a salt dissolves, its dissociated ions can move freely in solution, allowing a charge to flow. The resulting solution will conduct electricity because it contains ions.

Explanation:

Answer:

compound

Explanation:

it is calcium oxide, also known as quicklime

The water molecule is formed by the covalent bonding between oxygen and hydrogen atoms. Therefore, option C is correct.

Covalent bonding is a type of chemical bonding that involves the sharing of electrons between two atoms. In covalent bonding, the two atoms share a pair of electrons to fill their outermost electron shell and form a stable molecule.

This type of bonding usually occurs between non-metal atoms, which have a high electronegativity and tend to attract electrons strongly. In a covalent bond, the shared electrons are attracted to the positively charged nuclei of both atoms, creating a strong bond.

The strength of the bond depends on the number of shared electrons and the distance between the nuclei. Covalent bonds can be either polar or nonpolar, depending on the electronegativity difference between the two atoms.

In water the bond is formed between oxygen atom and two hydrogen atoms. Hence, C is correct.

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The desired reaction is 2Al(s) + 3CO2 from Al2O3(s) + 3CO(g) (g) The reactions include 2 Al(s), 3/2 O2(g), and Al2O3(s), with H = 1675.7kJ. ————————— (1) CO(g) = CO2 + 1/2 O2(g) (g).

As a result, the enthalpies of a reactants and products are added together, and the result is used to compute the enthalpy of a reaction. This endothermic process generates and absorbs environmental heat if H is positive. This reaction is exothermic so emits heat into the environment if H is negative.

A negative H indicates that heat is transferred from the a system towards its surroundings, whereas a positive H indicates that heat is transferred from the surroundings into the system. An enthalpy of reaction (Hrxn) for a chemical reaction is the difference of enthalpy between the products and reactants; Hrxn is measured in kilojoules per mole.

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Answer:

B. Metals are malleable, ductile, and can carry an electric current.

Explanation:

According to the article, deep-sea mineral extraction a controversial practice because it destruct the natural land wildlife

Deep sea mining is the process of retrieving mineral deposited from deep seabed and there are many environmental problems created by deep ocean mines which level the ocean floor to extract the minerals and the most direct impacts at mining sites are destruction of natural land forms and the wildlife they host compaction of the sea floor and creation of sediment plumes that disrupt aquatic life and deep sea contain many different resources such as silver, gold, copper, manganese, cobalt, and zinc

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Answer:

radius = 16 in ; height = 27 in

Answer:

the first element on the table is Hydrogen