To estimate the number of ladybugs in the entire garden, Ajoy needs the dimension of the garden.
What is a dimension?Dimensions in mathematics are the measure of the size or distance of an object or region or space in one direction.
Dimensional measurement is of fundamental importance for interchangeability and global trade.
Hence, to estimate the number of ladybugs in the entire garden, Ajoy needs the dimension of the garden.
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he scientist had a 35% saline solution that he mixed with 10 milliliters of a 75% saline solution to get a 40% saline solution. How many milliliters of the 35% solution were used? a) 30 milliliters b) 40 milliliters c) 50 milliliters d) 60 milliliters e) 70 milliliters
The answer is (e) 70 milliliters.
Let's assume that x milliliters of the 35% saline solution were used.
The total amount of saline in the solution can be calculated as follows:
Saline in 35% solution = 0.35 * x
Saline in 75% solution = 0.75 * 10 (since 10 milliliters of the 75% solution were used)
The total amount of saline in the resulting 40% solution can be calculated as:
Saline in 40% solution = 0.40 * (x + 10)
Since the saline is being mixed, the total saline in the resulting solution is equal to the sum of the saline in the individual solutions:
0.35 * x + 0.75 * 10 = 0.40 * (x + 10)
Simplifying the equation:
0.35x + 7.5 = 0.40x + 4
Subtracting 0.35x and 4 from both sides:
7.5 - 4 = 0.40x - 0.35x
3.5 = 0.05x
Dividing both sides by 0.05:
x = 3.5 / 0.05
x = 70
Therefore, 70 milliliters of the 35% saline solution were used. The answer is (e) 70 milliliters.
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The "roasting" of 48.7 g of ZnS at constant pressure gives off 220. kJ of heat. Calculate the ΔH for this reaction.2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g)a. −110 kJ/mol rxnb. −293 kJ/mol rxnc. −440. kJ/mol rxnd. −881 kJ/mol rxne. +440. kJ/mol rxn
The answer is -440 kJ/mol rxn. This means that 440 kJ of heat is released for every mole of ZnS reacted in the roasting process.
The given problem requires us to calculate the enthalpy change (ΔH) for the reaction of roasting ZnS. The reaction can be represented as follows:
2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g)
To calculate ΔH, we use the formula:
ΔH = q / n
where q is the amount of heat released or absorbed in the reaction, and n is the number of moles of the limiting reactant.
In this case, 48.7 g of ZnS is the limiting reactant. To calculate the number of moles of ZnS, we need to use its molar mass, which is 97.45 g/mol. Thus,
n = m / M = 48.7 g / 97.45 g/mol = 0.499 mol
Now, we can calculate ΔH:
ΔH = -220 kJ / 0.499 mol = -440 kJ/mol
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The bowl of fruit has a mass of 2.2 kg.
What net force must act on the bowl of fruit to make it accelerate to the right
at a rate of 4.4 m/s2? (Hint: Use F = ma.)
A. F = 9.68 N right
B. F = 9.68 N left
C. F = 6.60 N left
D. F= 6.60 N right
Taking into account the Newton's second law, the correct answer is option A. F = 9.68 N right
In first place, acceleration in a body occurs when a force acts on a body.
Newton's second law states that a force will change the speed of an object because the speed and/or direction will change. These changes in velocity are called acceleration.
So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object
Mathematically, Newton's second law is expressed as:
F= m×a
where:
F = Force [N] m = Mass [kg] a = Acceleration [m/s²]In this case, you know:
F= ? m= 2.2 kg a= 4.4 m/s²Replacing in Newton's second law:
F= 2.2 kg× 4.4 m/s²
Solving:
F= 9.68 N
Finally, As the bowl of fruit accelerates to the right, the correct answer is option A. F = 9.68 N right
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Which parts must be balanced in a chemical equation?
The reactants and products parts of a chemical equation must be balanced.
What is a balanced equation?A chemical reaction is said to be balanced when the number of atoms of each element on both sides of the equation are the same.
A chemical equation consists of the reactants and the products, hence, the number of atoms on both sides must be equal for the equation to be balanced.
Therefore, the reactants and products parts of a chemical equation must be balanced.
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How does a balanced chemical equation demonstrate the Law of Conservation of Mass?
(1 point)
A. It shows that all compounds remain bonded after the reaction
B. It shows that no atoms have been gained or lost during the reaction
C. It shows that the properties of the elements stay the same after the reaction
D. It shows that only physical changes follow the Law of Conservation of Mass
Thank you If you help!
Write formulas and other symbols for these substances.
a. Sulfur trioxide (SO3) gas
b. Potassium nitrate (KNO3) dissolved in water
c. Heat supplied to a chemical reaction
d. Metallic copper
e. Liquid mercury
f. Zinc chloride (ZnCl2) as a catalyst
The chemical formula of mentioned substances is as follows 1) SO₃ 2) K\(^+\) and NO₃\(^-\) 3) ΔH 4) Cu 5) Hg (l) 6)ZnCl₂.
What is chemical formula?Chemical formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols of elements. It also makes use of brackets and subscripts.
Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form is called empirical formula.
It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.
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Na(s) +2 H2O (l) ➔ 2NaOH (aq) + H2 (g)
Suppose that 10.0 g of sodium reacts completely with 1.00 L of water and the final solution volume is 1.00L. What is the molarity of the NaOH solution formed by this reaction?
To find the molarity of the NaOH solution formed by the reaction, we first need to determine the number of moles of NaOH produced.
The balanced equation shows that 1 mole of Na reacts to form 2 moles of NaOH. Therefore, if 10.0 g of Na reacts completely, we can calculate the moles of NaOH produced as follows:
Molar mass of NaOH = 22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 39.99 g/mol
Moles of NaOH = (10.0 g Na) / (39.99 g/mol) = 0.250 mol NaOH
Since the final solution volume is 1.00 L, the molarity (M) of the NaOH solution can be calculated using the formula:
Molarity (M) = Moles of solute / Volume of solution in liters
Molarity (M) = 0.250 mol NaOH / 1.00 L = 0.250 M
Therefore, the molarity of the NaOH solution formed by the reaction is 0.250 M.
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Consider the chemical equation.
CuCl2 + 2NaNO3 Right arrow. Cu(NO3)2 + 2NaCl
What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?
Use Percent yield equals StartFraction actual yield over theoretical yield EndFraction times 100..
49.7%
58.4%
63.6%
78.7%
Percent yield = 78.7% , the correct answer is D) 78.7%, which represents the percent yield of NaCl in the reaction.
To calculate the percent yield of NaCl in the given chemical equation, we need to compare the actual yield of NaCl with the theoretical yield. The theoretical yield is the amount of NaCl that would be produced if the reaction went to completion based on stoichiometry.
First, we need to determine the theoretical yield of NaCl. By examining the balanced equation, we can see that the stoichiometric ratio between CuCl2 and NaCl is 1:2. This means that for every 1 mole of CuCl2, 2 moles of NaCl are produced.
Step 1: Convert the mass of CuCl2 to moles using its molar mass.
Molar mass of CuCl2 = 63.55 g/mol (atomic mass of Cu) + 2 × 35.45 g/mol (atomic mass of Cl)
Molar mass of CuCl2 = 134.45 g/mol
Moles of CuCl2 = 31.0 g / 134.45 g/mol ≈ 0.231 mol
Step 2: Use the stoichiometry to calculate the theoretical yield of NaCl.
Since the stoichiometric ratio between CuCl2 and NaCl is 1:2, the moles of NaCl produced will be twice the moles of CuCl2.
Moles of NaCl (theoretical) = 2 × 0.231 mol = 0.462 mol
Step 3: Convert the moles of NaCl to grams using its molar mass.
Molar mass of NaCl = 22.99 g/mol (atomic mass of Na) + 35.45 g/mol (atomic mass of Cl)
Molar mass of NaCl = 58.44 g/mol
Theoretical yield of NaCl = 0.462 mol × 58.44 g/mol ≈ 26.96 g
Now, we can calculate the percent yield using the formula:
Percent yield = (Actual yield / Theoretical yield) × 100
Percent yield = (21.2 g / 26.96 g) × 100 ≈ 78.7%
Option D
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Which of the following is an oxidation-reduction reaction?
Answer:
last choice
Explanation:
oxidation and reduction can be defined in terms of adding or removing oxygen to a compound
oxidation is gaining oxygen
reduction is to loss oxygen
If 60 mL of 0.04 M NaOH solution is required to neutralize exactly 37 mL of HCL, what is the concentration of the acid?
According to molar concentration, the concentration of the acid is 0.064 M.
Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.In case of 2 solutions it is calculated as, M₁V₁=M₂V₂ which on substitution gives M₂=0.04×60/37=0.064 M.
Thus, the concentration of the acid is 0.064 M.
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This chemical equation is not balanced. Which element is not conserved?
AgNO3 + CaCl2 → AgCl + CaNO3
Answer:
D. CI
Explanation:
a p e x
Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\). The correct option is option D.
What is balanced chemical equation?An equation per a chemical reaction is said to be balanced if both the reactants as well as the products have the same number of atoms and total charge for each component of the reaction. In a nutshell, the two components of the reaction have an equal balance of mass and charge.
The components and byproducts of a chemical reaction are listed in an imbalanced chemical equation, but the amounts necessary to meet the conservation of mass are not specified. Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\).
Therefore, Chlorine is the element which is not conserved in the given chemical equation AgNO\(_3\) + CaCl\(_2\) → AgCl + CaNO\(_3\). The correct option is option D.
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For the night yet balanced equation, No + CuCl2 —> Cu + NiCl3, if you started with 12.00 g of nickel and 42.00 g of CuCl2, how much Copper would you expect to produce Perdue
Answer:
19.45g of Cu are expect to be produced
Explanation:
Based on the reaction:
2Ni + 3CuCl2 → 3Cu + 2NiCl3
2 moles of Ni react with 3 moles of CuCl2 to produce 3 moles of Cu
To solve this question we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of Cu produced and the mass as follows:
Moles Ni -Molar mass: 58.6934g/mol-
12.00g * (1mol / 58.6934g) = 0.204 moles Ni
Moles CuCl2 -Molar mass: 134.45g/mol-
42.00g * (1mol / 134.45g) = 0.312 moles CuCl2
For a complete reaction of 0.204 moles of Ni are required:
0.204 moles Ni * (3 moles CuCl2 / 2 moles Ni) = 0.306 moles of CuCl2
As there are 0.312 moles, CuCl2 is the excess reactant and Ni is limiting reactant.
Moles Cu:
0.204 moles Ni * (3moles Cu / 2 moles Ni) = 0.306 moles of Cu are produced
Mass Cu:
0.306 moles of Cu * (63.546g / mol) =
19.45g of Cu are expect to be producedExplain the volume of ideal gasses as related to the molar concept.
Answer:
n = Initial volume/22.4L
Explanation:
The molar concept is simply one that is used to find the Number of moles and explain the relationship it has with avogadro's number, molecular mass, molar mass e.t.c.
Now, in terms of molar mass, number of moles is given by the formula;
n = mass of the sample/molar mass
In terms of avogadro's number, number of moles is;
1 mole = avogadro's number = 6.02 × 10^(23)
Now, when dealing with ideal gases, the molar volume of an ideal gas is 22.4 L.
Now the relationship between this volume and the mole concept is that the number of moles is gotten by dividing the initial volume by this molar volume.
Thus;
n = Initial volume/22.4L
1. Use Models: How does the GPS determine its distance from each satellite?
(SCIENCE) HURRY HELP!!
Anabolic steroids are especially dangerous for teenagers whose bones are still growing.
true or false
Answer:
True
Explanation:
Generally makes sense.
Calculate the empirical formula of a compound that has a composition of 5.9% (by mass) hydrogen and 94.1% (by mass) oxygen.
Answer:
The empirical formula is the simplest form;
Given:
Oxygen O at 94.1% and
H at 5.9%
Assume 100grams.
94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O
5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H
There is one mole of O for each mole of H so the empirical formula is \(O_1H_1\)
and written as OH.
Explanation:
\(given \: that \: oxygen \: by \: 94.1\% (.941)\\ hydrogen \: by5.9\%(.059) \\ in \: 100gram \: \\ oxygen = 100 g\times .941 = 94.1 \times \frac{1(mol)}{16g} \\ = 5.88moles \: of \: oxygen \\ in \: hydrogen \: = .059\times 100 = 5.9 \times \frac{1mol}{1.002gram} \\ = 5.88mole \: of \: hydrogen \\ \: so \: here \: \: both \: oxygen \: andhydrogen = 5.88 \\their \: ratio = 1 \: 1 \\ so \: emparical \: formula = oh \\ thank \: you\)
can you solve this for me?
Answer:
b...............................
Answer:
b
Explanation:
can you solve this for me?
a scientist wants to test how much of a base can be added to a solution before the ph of a solution cahgnes
The scientist can conduct an experiment to determine the amount of base that can be added to a solution before the pH changes.
Here's a step-by-step approach:
1. Prepare a solution with a known pH.
2. Add a small amount of base to the solution and measure the pH using a pH meter.
3. Gradually increase the amount of base added while recording the pH at each step.
4. Observe the point at which the pH starts to change significantly.
5. Repeat the experiment multiple times to ensure accuracy and consistency.
6. Calculate the average amount of base required to cause a noticeable change in pH.
7. This average value will indicate the approximate amount of base that can be added before the pH changes significantly.
For example, if the scientist starts with a solution of pH 7 and notices a significant pH change when 10 mL of base is added, then they can conclude that around 10 mL of base is the threshold before the pH changes.
Remember, the experiment can be repeated with different solutions or bases to gather more data and ensure reliable results. The scientist should also consider using appropriate safety measures and equipment during the experiment.
Overall, this experiment will help the scientist understand the relationship between the amount of base added and the resulting pH change in a solution.
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a gas measured a volume 100 mL under pressure of 740 mmHg. What would the volume be under a pressure of 780 mmHg with constant temperature
Answer:
94.87 mLExplanation:
The new volume can be found by using the formula for Boyle's law which is
\(P_1V_1 = P_2V_2\)
Since we're finding the new volume
\(V_2 = \frac{P_1V_1}{P_2} \\\)
We have
\(V_2 = \frac{100 \times 740}{780} = \frac{74000}{780} \\ = 94.8717...\)
We have the final answer as
94.87 mLHope this helps you
Please help and right down each step!!
The mass of \(Ag_2CrO_4\) that would be formed will be 2.69 grams.
Stoichiometric problemMole of 2.5 grams silver nitrate = 2.5/143.32 = 0.017 mol
Mole of 18.0 mL, 0.450 M sodium chromate = 18/1000 x 0.450 = 0.0081
From the balanced equation of the reaction, the mole ratio of silver nitrate to sodium chromate is 2:1. In other words, the sodium chromate is a bit limiting.
The mole ratio of sodium chromate and \(Ag_2CrO_4\) is 1:1. Hence, the equivalent mole of \(Ag_2CrO_4\) formed would also be 0.0081 mol.
Mass of 0.0081 mol \(Ag_2CrO_4\) = 0.0081 x 331.73
= 2.69 grams
In other words, the mass of \(Ag_2CrO_4\) formed from the reaction would be 2.68 grams.
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A burner in a gas stove breaks propane and oxygen up to form carbon dioxide and water, thereby heating a home. Which part is the source of the activation energy required, and is this reactionendothermic or exothermic? (1 point)O The flame from the burner provides the energy to perform the reaction. The reaction is exothermic.O The burning propane gas provides the energy to perform the reaction. The reaction is endothermic.O The burning propane gas provides the energy to perform the reaction. The reaction is exothermic.O The flame from the burner provides the energy to perform the reaction. The reaction is endothermic.
Answer:
The third option is correct
brass has a density of 88.25 g/cm3 and a specific heat of 0.362 j/gc. A cube of brass 22 mm on an edge is heated in a bunsen burner flame to a temperature of 95 degrees celsius. It is then immersed in 20 ml of water (d=1g/ml, c=4.18 j/gc) at 22c in an insulated container. Assuming no heat loss, what is the final temperature of the water?
I found the mass of the brass, but I am confused about how to set up the equation because we don't know the initial temp of the brass.
The final temperature of the water, given that the cube of brass heated to 95 degrees celsius was immersed in it is 80.6 °C
How do i determine the final temperature of the water?First, we shall determine the mass of the brass. Details below:
Edge length (L) = 22 mm = 22 / 10 = 2.2 cmVolume = L³ = 2.2 = 10.684 cm³Density = 88.25 g/cm³Mass of brass =?Mass = density × volume
Mass of brass = 88.25 × 10.684
Mass of brass = 939.686 g
Finally, we shall determine the equilibrium temperature in order to obtain the final temperature of the water. Details below:
Mass of brass (M) = 939.686 gTemperature of brass (T) = 95 °CSpecific heat capacity of brass = 0.362 J/gºC Volume of water = 20 mLDensity of water = 1 g/mLMass of water (Mᵥᵥ) = 1 × 20 = 20 gTemperature of water (Tᵥᵥ) = 22 °CSpecific heat capacity of the water = 4.18 J/gºC Equilibrium temperature (Tₑ) =?Heat loss by brass = Heat gain water
MC(T - Tₑ) = MᵥᵥCᵥᵥ(Tₑ - Tᵥᵥ)
939.686 × 0.362 (95 - Tₑ) = 20 × 4.18(Tₑ - 22)
340.166332(95 - Tₑ) = 83.6 (Tₑ - 22)
Clear bracket
32315.80154 - 340.166332Tₑ = 83.6Tₑ - 1839.2
Collect like terms
32315.80154 + 1839.2 = 83.6Tₑ + 340.166332ₑ
34155.00154 = 423.766332Tₑ
Divide both side by 423.766332
Tₑ = 34155.00154 / 423.766332
Tₑ = 80.6 °C
Now, the equilibrium temperature is 80.6 °C
Thus, we can conclude that the final temperature of the water is 80.6 °C
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in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet, the water in the kettle gained only 5.95×10^2 J of thermal energy. determine the percent efficiency of the electrical element in heating the kettle of water
Answer:
The percentage efficiency of the electrical element is approximately 82.186%
Explanation:
The given parameters are;
The thermal energy provided by the stove element, \(H_{supplied}\) = 3.34 × 10³ J
The amount thermal energy gained by the kettle, \(H_{absorbed}\) = 5.95 × 10² J
The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;
\(\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}} \times 100\)
Therefore, we get;
\(\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3} \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%\)
The percentage efficiency of the electrical element, η% ≈ 82.186%.
Please answer it in 1 hour Write explanation if it needed I’ll give you upvote immediately Don’t use excel to solve this question i In a bond amortization schedule, what does the book value mean?Describe in words. (ii) Consider a n-period coupon bond where the redemption amount, C may not be the same as the face amount, F. Using j and g to represent the yield rate per period and modified coupon rate per period respectively, show that,for k = 01,2,n, the book value at time k,B is B=C+Cg-jan-kj and the amortized amount at time k is ii Let K = Cu. The Makeham formula to compute the price of a bond is given by A verbal interpretation for K would be that K is the present value of the redemption value C.Provide a verbal interpretation for(C-K)
Answer:
(i) In a bond amortization schedule, the book value represents the remaining amount of the bond principal that hasn't been paid off at a given point in time. When a bond is first issued, its book value equals its face value. As payments are made over the life of the bond, a portion of these payments reduces the book value. By the end of the bond's life, its book value will be zero, as the entire principal will have been paid off.
(ii) The formula for the book value B at time k, where k is the number of periods elapsed, is B = C + Cg - jan-kj.
Here:
- C is the redemption amount,
- g is the modified coupon rate per period,
- j is the yield rate per period, and
- a_n-kj is the present value of an annuity immediate with n - k periods at the yield rate j.
This formula states that the book value at any time k is the redemption amount plus the present value of the future coupon payments (Cg), minus the present value of the annuity that represents the repayments of the bond (jan-kj).
The amortized amount at time k is the change in the book value from time k-1 to time k, plus the coupon payment at time k. It represents the portion of the bond's principal (and interest) that has been repaid up to time k.
(iii) If K is defined as the present value of the redemption value C, according to the Makeham formula, (C-K) would represent the difference between the redemption value of the bond and its present value. This difference is the amount of interest that will accumulate over the life of the bond. In other words, (C-K) can be interpreted as the total interest that the bondholder will earn from holding the bond until redemption, assuming that all coupon payments are reinvested at the yield rate j.
Explanation:
In the formula XS04, the symbol X could represent the element*
O (1) AI
O (2) Ar
O (3) Mg
0 (4) Na
When a cold front is collied and a warm front is the same this occurs during a ? front
When a cold front and a warm front collide, it is called an occluded front. This weather phenomenon occurs when a cold front catches up to and overtakes a slower-moving warm front, pushing it upwards.
As the two fronts meet, the warm air is lifted, causing it to cool and condense, leading to the formation of clouds and precipitation. The type of precipitation that occurs during an occluded front can vary depending on the temperature and moisture content of the air masses involved. Generally, it is common to see rain or snowfall during an occluded front, and the intensity of the precipitation can be moderate to heavy. During an occluded front, the temperature can also change rapidly as the warm air mass is lifted and replaced by cooler air. If the air behind the occluded front is colder than the air ahead of it, the temperature will drop, leading to a sudden chill. However, if the air behind the occluded front is warmer, the temperature will rise, creating a sudden warmth.
In conclusion, an occluded front is a weather phenomenon that occurs when a cold front overtakes and lifts a slower-moving warm front, resulting in precipitation and sudden temperature changes. It is a unique weather event that requires careful monitoring by meteorologists to ensure the safety of people and property.
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Give one example of each of the following, that happens to us in our everyday life: Explain a bit about the science behind it, so for example, for melting you can say ice cream melting in your hand, which turns from a solid to a liquid, which is melting. If you are unsure please do not answer, though if you are confident please be free to do so! Have a wonderful day or night!
a) Melting:
b) Freezing:
c) Condensation:
d) Evaporation:
e) Sublimation.
a) Melting: An example of melting that occurs in our everyday life is when we heat butter on a stovetop.
b) Freezing: Freezing is the process in which a liquid transforms into a solid upon cooling.
c) Condensation: One example of condensation that we encounter regularly is when water droplets form on the surface of a cold drink on a hot day.
d) Evaporation: Evaporation is the process by which a liquid transforms into a gas or vapor.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state.
a) Melting: Butter is a solid at room temperature, but when heat is applied, it melts into a liquid. This change is a result of the increase in temperature, which provides enough energy to overcome the intermolecular forces holding the butter molecules together.
b) Freezing:Eventually, the temperature reaches the freezing point of water (0°C or 32°F), at which the water molecules slow down and arrange themselves into a regular, crystalline structure. This transformation from a liquid to a solid state is accompanied by the release of heat energy.
c) Condensation: As the temperature decreases, the air's capacity to hold moisture decreases, causing the water vapor in the air to condense into liquid water droplets. This process occurs due to the transfer of heat energy from the warm air to the cold surface, leading to the saturation of the air and the conversion of water vapor into liquid form.
d) Evaporation: As the sun's heat energy is absorbed by the water molecules on the clothes' surface, their kinetic energy increases, causing them to break free from the liquid phase and escape into the surrounding air as water vapor. This process occurs because the molecules at the liquid surface with sufficient energy can overcome the attractive forces within the liquid and enter the gas phase.
e) Sublimation: Sublimation refers to the transformation of a substance directly from a solid to a gas without passing through the liquid state. An example of sublimation is the process of dry ice (solid carbon dioxide) converting into carbon dioxide gas.
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Why the planets are arranged as they are in our solar system.
Answer:
The order and arrangement of the planets and other bodies in our solar system is due to the way the solar system formed. Nearest the Sun, only rocky material could withstand the heat when the solar system was young. For this reason, the first four planets—Mercury, Venus, Earth and Mars—are terrestrial planets.
Explanation:
9. Which mass measurement contains a total of three
significant figures?
A) 22.0 g
C) 220 g
B) 22.00 g
D) 2200 g
Answer:
A
Explanation:
2 has 4, 3 and 4 both have 2.
(if 3 had a decimal point it would have 3 sig figs)
The mass measurement contains a total of three significant figures is 22.0 g. Thus option A is correct.
What is mass?Mass is defined as the inertia, a fundamental feature of all stuff, is quantified.
It is also defined as a dimensionless quantity that represents the mass of a particle or object.
Mass can be expressed as
Mass = density x volume
Significant figure is defined as a number in positional notation is a set of digits that may be relied on to signify the quantity of anything.
It can also be defined as the amount of significant single digits from 0 to 9 in the coefficient of the expression that accurately conveys the meaning.
Thus, the mass measurement contains a total of three significant figures is 22.0 g. Thus option A is correct.
To learn more about mass, refer to the link below:
https://brainly.com/question/19694949
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Isotopes of an element cannot have just any number of neutrons. If there are too many or too few, the nucleus will split apart. This is called ____________
Answer:
beta decay
Explanation: