Kelly works two jobs. She usually works at a retail store for 8 hours during the day and is paid $12.90 per hour by the store. In the evening she works at a restaurant as a manager for 4 hours and is paid $12.20 per hour. How much does she make on average per hour for the day?

Based on the provided question, it seems like you are asking about the most efficient evaluation method, either by hand or using a computer. To determine which method is the most suitable, you need to consider the complexity of the evaluation process and the number of alternatives.

Using a computer is generally faster and more accurate when dealing with large datasets or complex calculations. On the other hand, evaluating by hand may be more suitable for smaller datasets or simpler calculations. It can provide a more hands-on approach, allowing for a deeper understanding of the evaluation process. However, this method is generally more time-consuming and prone to human error.

To select the most appropriate evaluation method, consider the complexity of the task and the available resources. If the evaluation involves a large amount of data or complex calculations, using a computer would likely be the most efficient choice. However, if the task is relatively simple or involves a smaller dataset, evaluating by hand may suffice. In conclusion, the choice between evaluating by hand or using a computer depends on the complexity of the task and the available resources. Consider these factors to determine the most suitable method.

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The statement "dispersion models are selected based on the phase of the material being modeled in a release scenario" is true as Different dispersion models are needed for different phases (gas, liquid, solid) due to differences in behavior and transport mechanisms.

Dispersion models are used to predict the spread of pollutants, and they depend on the physical and chemical properties of the material being released.

Generally, different models are used for each phase of the material, such as the Gaussian plume model for gases, the plume rise model for heated gases, and the particle dispersion model for particles.

Each of these models is based on different characteristics and equations which allow for the most accurate prediction of the dispersion of pollutants.

For example, the Gaussian plume model considers the wind velocity, turbulence, and buoyancy of the released material, whereas the plume rise model considers the momentum, thermal expansion, and buoyancy of the released material.

Therefore, dispersion models are selected based on the phase of the material being modeled in a release scenario.

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Its speed is closest to 414m/s

given that

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10-9 m, or angstroms (), which are units of 10-10 m, for infrared (IR), visible light (UV), and gamma radiation ().

Frequency, which is defined as the quantity of wave cycles per second, and wavelength have an inverse relationship. The wavelength of the signal decreases with increasing signal frequency.

a wave has a wavelength = 25.4cm

a frequency = 1.63khz

now, we need to find speed of the wave

speed = wavelength × frequency

speed = 25.4 × 16.3

           = 414m/s

speed = 414m/s

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From the given resistivities, the largest and the smallest will be as follows:

ρ2>ρ3>ρ1=ρ5>ρ4.

The resistance of a wire is given as,

R= ρL/A

Here, p is the resistivity of the wire, L is the length of the wire, and A is the area of the wire.

Rearrange the equation R = ρL/A in terms of ρ.

ρ=RA/L

Let R be the resistance of each wire.

The resistivity of the wire 1 is,

\(p_{1}=\frac{A_{1} }{L_{1} } *R\)

ρ1= π\(r^{2}\)\(\frac{R}{L}\)

The resistivity of the wire 2 is,

\(p_{2}=\frac{A_{2} }{L_{2} } *R\)

ρ2= 4(π\(r^{2}\)\(\frac{R}{L}\))

The resistivity of the wire 3 is,

\(p_{3}=\frac{A_{3} }{L_{3} } *R\)

ρ3= 2(π\(r^{2}\)\(\frac{R}{L}\))

The resistivity of the wire 4 is,

\(p_{4}=\frac{A_{4} }{L_{4} } *R\)

ρ3= 0.5(π\(r^{2}\)\(\frac{R}{L}\))

The resistivity of the wire 5 is,

\(p_{5}=\frac{A_{5} }{L_{5} } *R\)

ρ5= (π\(r^{2}\)\(\frac{R}{L}\))

Therefore from the above equations, we come to get the resistivities of ρ1 to ρ5. They are: ρ2>ρ3>ρ1=ρ5>ρ4.

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Answer:

the answer of v is -4.6 of the question

Answer:

Your question has already being answered.

I am just here to ask for brainliest please.

sorry for the interruption

Answer:

The 64 fl oz for 4 dollars

Step-by-step explanation:

That can hold up for about 5 or 4 weeks

Answer:

x = 6

General Formulas and Concepts:

Pre-Algebra

Geometry

Step-by-step explanation:

Step 1: Set up equation

8x + 2 + 70 + 60 = 180

Step 2: Solve for x

And we have our final answer!

Step-by-step explanation:

\(2 \times 14 \times 13 +12 \times 10 + 14 \times 10 = \\ = 624\)

Multiply the taxable income by the tax rate.

800.98 x 0.14 = 112.14

The answer is B. $112.14

2003: 1000

2004: 1100

2005: 1210

2006: 1331

Predict the SAT score for Brookstone seniors in 2007.​

2007: 1464.1

The answer is the score in 2006 *110%=1464.1

Answer: 5

Step-by-step explanation:

  8-2b=-2

8-2b-8=-2-8

    -2b=-10

-2b/-2=-10/-2

       b=5

We have 95% confidence in our interval, instead of 100%.because we need to account for the fact that a) the sample may not be truly random.

Strictly speaking, a 95% confidence interval means that if we were to take 100 different samples and calculate a 95% confidence interval for each sample, then approximately 95 of the 100 confidence intervals will contain the true mean (μ). In practice, however, we take one random sample and generate one confidence interval, which may or may not contain the true mean. The observed interval may overestimate or underestimate μ. Consequently, the 95% CI is the likely range of the true, unknown parameter. A confidence interval does not reflect the variability in the unknown parameter. Rather, it reflects the amount of random error in the sample and provides a range of values ​​that are likely to include the unknown parameter. Another way of thinking about a confidence interval is that it is a range of possible values ​​of a parameter (defined as a point estimate + margin of error) with a specified confidence level (which is similar to a probability).

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The ball traveled approximately \(26.27\) units in total.

To calculate the distance the ball traveled, we can use the distance formula between two points in a Cartesian coordinate system.

Distance = \(\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1} )^{2} }\)

Let's calculate the distance between Player A and Player B first:

Distance_AB =

\(\sqrt{((16-2)^{2}+(9-4)^{2}) }\)

\(= \sqrt{(14^{2}+5^{2} ) } \\= \sqrt{(196 +25)} \\= \sqrt{221} \\= 14.87\)

Now, let's calculate the distance between Player B and Player C:

Distance_BC =

\(\sqrt{ ((25 - 16)^2 + (16 - 9)^2)}\\= \sqrt{ (9^2 + 7^2)}\\= \sqrt{(81 + 49)}\\= \sqrt{130}\\=11.40\)

Finally, we can calculate the total distance traveled by adding the distances AB and BC:

Total distance = Distance_AB + Distance_BC

\(= 14.87 + 11.40 \\= 26.27\)

Starting from Player A at \((2, 4),\) it was thrown to Player B at \((16, 9),\) covering a distance of about \(14.87\) units. From Player B, the ball was then thrown to Player C at \((25, 16),\) covering an additional distance of approximately \(11.40\) units.

Combining these distances, the total distance the ball traveled was approximately \(26.27\) units.

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Answer:57.6

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

According to the given question.

Total number of shirts, n = 12

Number of shirts to be selected, r = 3

As we know, the total number of ways of selection of r objects from n objects at a time without replacement is given by

C(n, r) = n!/r!(n - r)!

Answer:

  A.  60 ft·lb

Step-by-step explanation:

You want the work done lifting a 15-lb flower pot to a height of 4 ft.

Work is the product of force and distance. When the pot is raised 4 ft, the work done is ...

  W = F·d

  W = (15 lb)(4 ft) = 60 ft·lb

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According to the study, economists are not more self-centered than persons in other classes because 51% of the envelopes returned from economics classes and 36% from other classes.

Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.

At one classroom for economics and another for other topics, they dumped 122 stamped envelopes with addresses and $20 bills inside each.

Let the money returned = R

economics classes = E

other classes = O

a). The following gives the probability statement for the overall percentage of the money returned: 100.P (R)

b). The probability statement that the percentage of money recovered from economics classes is 100.P(R|E)

c). The probability statement that displays the percentage of money returned from the other classes is 100.P(R|O).

d). No, because P(R) is not equal to P(R|E), the money returned is not independent of the classes.

e).  According to the study, economists are not more self-centered than persons in other classes because 51% of the envelopes returned from economics classes and 36% from other classes.

The complete question is:

Three professors at George Washington University did an experiment to determine if economists are more selfish than other people. They dropped 122 stamped, addressed envelopes with $20 cash in two different classrooms (one economics, one not) on the George Washington campus. Of these, 42% were returned overall. From the economics class 51% of the envelopes were returned. From the other class 36% were returned.

From

the business, psychology, and history classes 31% were returned.

Let: R = money returned; E = economics classes; O = other classes

a. Write a probability statement for the overall percent of money returned.

b. Write a probability statement for the percent of money returned out of the economics classes.

c. Write a probability statement for the percent of money returned out of the other classes.

d. Is money being returned independent of the class? Justify your answer numerically and explain it.

e. Based upon this study, do you think that economists are more selfish than other people? Explain why or why not. Include numbers to justify your answer.

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The dimensions of the box that minimize the cost of materials are a length of 4 ft, a width of 2 ft, and a height of 2 ft.

Let's denote the length, width, and height of the box as L, W, and H, respectively. The volume of the box is given as V = LWH = 16 ft^3.

To minimize the cost of materials, we need to minimize the surface area of the box. The surface area is given by A = 2(LW + LH + WH).

We can rewrite the volume equation in terms of one variable, L, by solving for H: H = 16 / (LW).

A = 2(LW + L(16 / (LW)) + (16 / (LW))W).

A = 2(LW + 16 / L + 16W / L).

To find the minimum cost of materials, we take the derivative of A with respect to L, set it equal to zero, and solve for L.

Differentiating A with respect to L, we get: dA/dL = 2W - 16 / L^2 + 16W / L^2.

Setting dA/dL equal to zero, we have: 2W - 16 / L^2 + 16W / L^2 = 0.

Simplifying, we get: W = 8 / L.

8 / L = 16 / (LW).

8 = 16 / L.

L = 2 ft.

Substituting this value of L into the equation W = 8 / L, we get W = 4 ft.

Finally, substituting the values of L and W into the volume equation, we find H = 2 ft.

Therefore, The optimal dimensions for reducing material costs in the box are a length of 4 feet, a width of 2 feet, and a height of 2 feet..

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(a) Using the distributive property ( x + 7 )² is equal to x² + 14x + 49.

(b) When x = 3, the expressions  ( x + 7 )² and x² + 14x + 49 are equal.

Consider the expression ( x + 7 ),

Now when we square the expression we get,

( x + 7 )²  = ( x + 7 ) ( x + 7 )

Using the distributive property,

( x + 7 )²  = x( x + 7 ) + 7( x + 7 )

Again by using distributive property,

( x + 7 )²  = x² + 7x + 7x + 49

( x + 7 )²  = x² + 14x + 49

(b) For the expressions ( x + 7 )² and x² + 14x + 49,

When x = 3,

( x + 7 )² = ( 3 + 7 )²

( x + 7 )² = 10²

(x + 7 )² = 100

When x = 3,

x² + 14x + 49 = 3² + 14 × 3 + 49

x² + 14x + 49 = 9 + 42 + 49

x² + 14x + 49 = 100

Hence, the expressions (x+7)² and  x² + 14x + 49 are equal when x = 3.

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Answer:

120 degrees

Step-by-step explanation:

There are 120 degrees in a third of a full turn. To determine this, you need to start with a full turn which is 360 degrees.

Answer:

120⁰ is the answer. Hope it helps have a nice day also ;)

Answer:

if this is 4.88/16 then the answer is 0.305.

Answer:

The sorted inputs in order from least to greatest is:

0.27 < 35% < 27 < 35

Step-by-step explanation:

Given the data

0.27, 27, 35%, 35

as

so Rewriting these inputs as decimals:

0.27, 27, 0.35, 35

Sorting this table by decimal values in order from least to greatest:

0.27    35%        27       35

0.27  <  0.35    <  27  <   35

Thus, the sorted inputs in order from least to greatest is:

0.27 < 35% < 27 < 35

Answer:

A

Step-by-step explanation:

0.27

2/7 = .28

35% = 0.35

3/5 = 0.6

Answer:

6

Step-by-step explanation:

that is because 6 is x and y is -3

Answer:

4.5%

Step-by-step explanation:

Francis made an error in writing the explicit formula. The correct formula should be an = 4 * (1/4)⁽ⁿ⁻¹⁾, not an = 4 * (1/4)ⁿ⁻¹. The exponent should be (n-1), not just n, to correctly represent the sequence where the second term is 8 and the fourth term is 2.

To determine the error in Francis' formula, we need to apply it to the known terms of the sequence and see if it produces the correct values. For example, for the second term, n = 2, so using Francis' formula:

an = 4 * (1/4)⁽ⁿ⁻¹⁾ = 4 * (1/4)¹ = 4 * 1/4 = 1

But the second term of the sequence is 8, not 1. So the formula is incorrect.

Similarly, for the fourth term, n = 4, so using Francis' formula:

an = 4 * (1/4)⁽ⁿ⁻¹⁾ = 4 * (1/4)³ = 4 * 1/64 = 1/16

But the fourth term of the sequence is 2, not 1/16. So the formula is still incorrect.

Therefore, we can conclude that the formula written by Francis is not correct and needs to be corrected to accurately describe the sequence.

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In order to completely delta hedge 480 shares of ABC company with an option delta of 0.6, you would need 3 call options.

To completely delta hedge your holdings of 480 shares of ABC company, you would need to calculate the number of call options required based on the delta of the option. The delta represents the change in the option price relative to the change in the underlying stock price. In this case, since the delta is given as 0.6, it means that for every $1 increase in the stock price, the option price will increase by $0.6.

To calculate the number of call options needed for delta hedging, you can use the following formula:

Number of call options = (Delta * Number of shares) / 100

Plugging in the given values, we have:

Number of call options = (0.6 * 480) / 100

Number of call options = 2.88

Since you cannot have a fractional number of options, you would need to round up to the nearest whole number. Therefore, you would need 3 call options to hedge your 480 shares of ABC company.

In summary, to completely delta hedge 480 shares of ABC company with an option delta of 0.6, you would need to acquire 3 call options.

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The given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants.

Mutually exclusive and exhaustive variables: A variable is mutually exclusive and exhaustive if it includes all possible outcomes and each outcome can only be assigned to one variable category.a. Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday - Mutually exclusive and exhaustiveb. Days: Weekday and Weekend - Mutually exclusive and exhaustive c. Letters: Vowels and Consonants - Mutually exclusive and exhaustive. Letters: Alphabets and Consonants - Not mutually exclusive and exhaustiveThe given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants. Hence, the options a and c are correct.

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The exact trigonometric ratios for the angle x is second quadrant.

Given Radian equals to θ = 27π / 4, we need to find all the Trigonometric ratios for the same -

Lets calculate the value of θ first.

We know π equals 180 degree angle and 2π equals 360 degree, hence with each 2π the radian moves back to zero degree. Which means

θ = 27π / 4 can be reduced to θ = 3π / 4

Hence θ = 135 degree which can be represented as below -

As This lies in second quadrant, hence  on x-axis (Value of base , needs to be taken as -1)

sin θ = 1/√2                            cosec θ = √2

cos θ = -1/√2                          sec θ = - √2

tan θ = -1                               cot θ = - 1

Trigonometric ratios are based on the value of the ratio of sides of a right-angled triangle and contain the values of all trigonometric functions. The trigonometric ratios of a given acute angle are the ratios of the sides of a right-angled triangle with respect to that angle.

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95% confidence interval for the population mean is 170.2 to 189.8, option d is correct.

We are given the following information:

- Sample size (n) = 225
- Standard deviation (σ) = 75
- Sample mean (x) = 180
- Confidence level = 95%

We need to calculate the 95% confidence interval for the population mean (μ). To do this, we will use the formula:

Confidence interval = x ± (z × σ/√n)

First, we need to find the z-score that corresponds to a 95% confidence level. For a 95% confidence interval, the z-score is 1.96 (you can find this value in a standard z-score table).

Now, we can plug in the values we have:

Confidence interval = 180 ± (1.96 × 75/√225)

Calculate the standard error (σ/√n):

Standard error = 75/√225 = 5

Now, calculate the margin of error (z * standard error):

Margin of error = 1.96 × 5 = 9.8

Finally, calculate the confidence interval:

Confidence interval = 180 ± 9.8 = (170.2, 189.8)

So, the 95% confidence interval for the population mean is 170.2 to 189.8, which corresponds to option d.

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the interval of time between when a vector takes an infectious meal, and when it begins to transmit the pathogen, is referred to as the extrinsic incubation period.

The incubation period refers to the duration of time between the invasion by an infectious pathogen and the start (first appearance) of symptoms of the disease in question. The host enters the symptomatic phase after the incubation period is over. Additionally, after infection, the host develops the ability to spread infections to other people, or they become infectious or communicable. The host person may or may not be contagious throughout the incubation phase, depending on the disease. The dynamics of disease transmission depend on the incubation period since it establishes the timing of case detection in relation to infection. This aids in assessing the success of symptomatic surveillance-based control methods.

the interval of time between when a vector takes an infectious meal, and when it begins to transmit the pathogen, is referred to as the extrinsic incubation period.

The complete question is-

The interval of time between when a vector takes an infectious meal, and when it begins to transmit the pathogen, is referred to as the: (a) vectorial capacity; (b) intrinsic incubation period; (c) vectorial competence; (d) extrinsic incubation period.

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