Juanita earns 8.75 per hour. How much will she earn next week if she works 23 hours?

Suppose that triangles ABC and DFE are similar. Therefore, the ratio between their corresponding sides is constant. Let x and y be

Then,

Triangle DFE is impossible, the lengths of its sides are impossible to construct in such a manner that the result is a right triangle whose hypotenuse is 3. DFE is an impossible triangle, the hypotenuse of a right triangle is always its largest side.

However, we can algebraically find x and y, although it would not make any sense geometrically speaking.

Solving for x,

Similarly, solving for y,

Answer:

2100

Step-by-step explanation:

60%=0.6

35%=0.35

0.6*0.35=0.21

0.21*10000=2100

Answer:

The answer is "\(1\frac{1}{2}\)"

Step-by-step explanation:

Please find the graph file of the question in the attachment.

Its first step is the lightest and heaviest evil. \(4 \frac{1}{4}\) is the lightest bag, and \(5 \frac34\) is the heaviest bag. To remove it now, it is not permissible to remove it as a mixed fraction, therefore convert each fraction into an improper fraction by multiplying the whole integer to the numerator, then adding a numerator to this amount, multiplied by the numerator. Follow those steps to find out \(4 \frac{1}{4}\)  is the wrong part.

\((4\times 4+1=17) \ so\ 4\frac14=\frac{17}{4}.\) The process is the same for \(5 \frac34 (5\times 4+3=23) \ so \ 5 \frac34= \frac{23}{4}.\)

You now deduce the numerator but just not the negative, to deduct both. You subtract, as the question is raised far as\(\frac{23}{4}-\frac{17}{4} =\frac{6}{4}\) is involved. The last stage is that this is transformed into blended families, dividing its count by the denominator, 6 divided by 4 is identical to 1.5. 1 is a full amount so you don't modify it, but you do need to change the 5 decimals to \(1.5=1 \frac{5}{10}\) and the last step is \(1\frac{1}{2}\)to reduce.

The quartile values for the distribution are 1.96, 3.44 and 4.76 for the first, second and third quartiles respectively.

Given the data :

0.76, 1.08, 1.32, 1.55, 1.83, 2.09, 2.57, 2.83, 3.01, 3.25, 3.63, 3.78, 4.09, 4.32, 4.64, 4.93, 5.23, 5.34, 5.44, 5.73

Q1 = 1/4(n+1)th term

Q1 = 1/4(21)th term

Q1 = 5.25th term

Q1 = (1.83+2.09)/2 = 1.96

Hence, the value of Q1 is 1.96

Q2 = 1/2(n+1)th term

Q2 = 1/2(21)th term

Q2 = 10.5th term

Q2 = (3.25+3.63)/2 = 3.44

Hence, the value of Q2 is 3.44

Q3 = 3/4(n+1)th term

Q3 = 3/4(21)th term

Q3 = 15.75th term

Q3 = (4.64+4.93)/2 = 4.76

Hence, the value of Q3 is 4.76

Therefore, 1.96, 3.44 and 4.76 are the first, second and third quartile values respectively.

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The values of p and q are found to be 0 using the substitution method. Therefore, p = 0 and q = 0.

Given: 6p = q  and 15p² = q²

To find: The values of p and q.

We know that

q = 6p

substitute it in the 2nd equation to get:

15p² = (6p)²

15p² = 36p²

15p² - 36p² = 0

   -21p² = 0

  p² = 0/21

p² = 0

p = 0/√21

p = 0

Since we have the value of p, we can find the value of q by using any of the given equations; let's use the first one.

6p = q6(0)

q = 0

Therefore, the value of p is 0, and the value of q is also 0. The given two equations are

6p = q and 15p² = q², and the task is to find the value of p and q. The values of p and q are found to be 0 after solving the equations using substitution and simplification.

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To determine a value of that allows the given system of equations to be solved by Cramer's method, we need to check if the determinant of the coefficient matrix is non-zero.

If the determinant is non-zero, Cramer's method can be used to find a unique solution. The coefficient matrix for the given system is:

| 1 (a - 1) 0 1 |

| (a - 2) -a 0 -2 |

| 1 (a - 1) a 1 |

| a (a - 1) (a + 4) 1 |

We can calculate the determinant of this matrix and set it equal to zero:

Det = 1 * (-a * (a + 4) - 1 * (a - 1) * 1) - (a - 1) * ((a - 1) * (a + 4) - a * 1)

= -a^2 - 4a - a + 1 - (a^2 - 2a + 1 - a)

= -a^2 - 4a + 1 - a^2 + 2a - 1 + a

= -2a^2 - 2a

To find the value of a that allows Cramer's method to be used, we set the determinant equal to zero:

-2a^2 - 2a = 0

Simplifying the equation:

a^2 + a = 0

Factoring out a common factor:

a(a + 1) = 0

Setting each factor equal to zero:

a = 0 or a + 1 = 0

So, the possible values that allow Cramer's method to be used are a = 0 or a = -1.

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It becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

Logarithms arise in problems of exponential growth

and decay because they are inverses of exponential functions. Because of the Laws of Logarithms, they also turn out to be useful in the measurement of the loudness of sounds, the intensity of earthquakes, and other processes that occur in nature

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by P(t) = A (2)^t

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So

P(t) = 100000 (2)^t

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore

P(-5) = 100000 (2)^-5 =100000*(1/32) =3125

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

P(t) = A (2)^t

After 5 days, we reach the 100,000 population. So, when t = 5, P(t) = 100000:

100000 =A\(2^5\)

And solving for A, we acquire     :\(\frac{100000}{2^5}\)

                                                      =3125

So, our function in terms of the original day is:

P(t) = 3125 (2)^t

So, it becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

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The research team determined the normal range for BUN levels using a sample of 16 employees.

The research team at the hospital conducted a study to determine the normal range of BUN (blood urea nitrogen) levels in a healthy population. They randomly selected 16 employees and measured their BUN levels.

The average BUN level in the sample was found to be 16 mg/dl, with a standard deviation of 6.5 mg/dl. Using this data, the research team aimed to estimate the range of normal values for the entire healthy population.

To construct the range of normal values, the team considered the average BUN level of 16 mg/dl as the central value. They then used the standard deviation of 6.5 mg/dl to establish the spread of values around the average. In a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. Therefore, the research team might have determined the range of normal BUN levels to be around 9.5 mg/dl to 22.5 mg/dl (16 mg/dl ± 6.5 mg/dl).

It's important to note that the determination of normal ranges may vary depending on the specific context and criteria used. In this case, the team based their estimation on a sample of 16 employees, which might not represent the entire healthy population. Further studies involving a larger and more diverse sample would provide a more accurate and reliable estimation of the normal range for BUN levels.

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Given a figure of a circle:

As shown, the radius of the circle = r = 9 miles

The shown sector bounded by a 60-degree arc

We need to find the area of the shown sector

as we know the area of the circle =

The area of the sector represents 60/360 of the area of the circle

So, the area of the sector =

so, the answer will be the area of the shown sector = 42.4115 square miles

We will write the area in terms of pi and fractions as follow:

So, the answer will be:

Answer:

16 11/2

Step-by-step explanation:

ezz

Answer:

Step-by-step explanation:

D. supplementaryAn exterior angle is an angle that is supplementary when any of its side-extended with an interior angle of a triangle. In other words, when you extend one side of a triangle, you create an exterior angle that is adjacent to and supplementary (adds up to 180 degrees) with the interior angle next to it. This property is true for all triangles.

The given table represents a discrete probability distribution.

To determine whether the table represents a discrete probability distribution, we need to check if it satisfies two conditions: the sum of probabilities equals 1 and all probabilities are non-negative.

In the given table, the sum of probabilities is 0.3 + 0.3 + 0.1 + 0.3 = 1, which satisfies the first condition.

Additionally, all probabilities in the table are non-negative, as each value of p(x) is greater than or equal to 0. This satisfies the second condition.

Therefore, since the table satisfies both conditions, it represents a discrete probability distribution. It provides the probabilities for each value of x, indicating the likelihood of each outcome occurring in a discrete random variable scenario.

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Answer:

C orB looks like it

Step-by-step explanation:

To determine the average rate of change in weight of the plankton from week 8 to week 12, we need to find the difference in weight between these two weeks and divide it by the number of weeks that have passed. Looking at the table below, we can see that the average weight of the plankton was 3.5 mg in week 8 and 4.2 mg in week 12, so the difference is 0.7 mg.

Week  |  Weight (mg)  
------|--------------
 1   |     1.2    
 2   |     1.8    
 3   |     2.4    
 4   |     2.9    
 5   |     3.2    
 6   |     3.3    
 7   |     3.4    
 8   |     3.5    
 9   |     3.8    
 10  |     4.0    
 11  |     4.1    
 12  |     4.2    

Next, we need to divide this difference by the number of weeks between week 8 and week 12, which is 4. Therefore, the average rate of change in weight of the plankton from week 8 to week 12 is 0.7 mg / 4 weeks = 0.175 mg/week.

In other words, on average, the weight of the plankton increased by 0.175 mg per week from week 8 to week 12. This rate of change can be useful information for researchers studying the growth and development of these plankton, and can also provide insight into the health of the ecosystem they are a part of.

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a) The median number of hours per week these Year 12 students spend doing homework is 4 hours.

b) If 10% of Year 12 students spend more than k hours per week doing homework, then the value of k is 5.75 hours.

The median is a central value or a middle value in a distribution. The number of values in a dataset is an important factor that determines the calculation of the median. It is a value that cuts the data set into two equal parts.

The data set consists of 20 Year 12 students. Sort the data in ascending order (or descending order) and find the middle value. Then, use the formula for calculating the median. 

a)The number of hours per week the Year 12 students spend doing homework is given as:

3, 3, 3, 3, 3, 3, 3.5, 3.5, 4, 4, 4, 4, 4.5, 5, 5, 5.5, 6, 7, 8, 8.5

Arrange the data in ascending order:

3, 3, 3, 3, 3, 3, 3.5, 3.5, 4, 4, 4, 4, 4.5, 5, 5, 5.5, 6, 7, 8, 8.5

Now count the data, which gives us 20 numbers. The middle value is the 10th and the 11th numbers, which are both 4.

So the median of the number of hours per week Year 12 students spend doing homework is 4 hours.

b) If 10% of Year 12 students spend more than k hours per week doing homework, then the value of k can be found using the following formula:

100% - 10% = 90%

So, 90% of students study for k hours or less.

So, the value of k can be found using the median. The median value is 4 hours, and 90% of students are studying for k hours or less. Therefore, 10% of students study for more than k hours.

k = 10% more than the value of the 90th percentile value, which is given by: k = 5.5 + ((8-5.5)/10)*1 = 5.5 + 0.25 = 5.75 hours.

Therefore, 10% of Year 12 students spend more than 5.75 hours per week doing homework.

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Answer:

330

Step-by-step explanation:

15 crates × 22 books each = 330 books

Therefore, the librarian has 330 books to sort.

to get the equation of any straight line all we need is two points from it, let's use those ones in the picture.

\((\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{0}}}\implies \cfrac{2}{3}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}(x-\stackrel{x_1}{0})\implies y=\cfrac{2}{3}x+1\)

Answer:

52/79

Step-by-step explanation:

One costume = 156 (This is our numerator.)

All visitors = 156 + 58 + 23 = 237 (This is our denominator.)

156/237

Find the GCF to simplify (sneak peek it's 3)

156/3 = 52

237/3 = 79

52/79 (tada!)

Answer: 0.41

Step-by-step explanation:

Mary's average workday for the past week was approximately 6.6 hours. This is calculated by dividing the total hours worked (16 1/2) by the number of workdays (5).

To calculate the average workday, we divide the total hours worked by the number of workdays. In this case, Mary worked a total of 16 1/2 hours over 5 days in the past week.

To find the average workday, we divide 16 1/2 hours by 5 days.

Converting the mixed number to an improper fraction, 16 1/2 is equal to 33/2.

Dividing 33/2 by 5, we can simplify the fraction to find the average workday.

The result is 6 3/5 hours per day, or approximately 6.6 hours per day.

Therefore, Mary's average workday for the past week was 6.6 hours.

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To find the partial derivatives of the function f(x, y) = x³e^y + y³sec(√√x) with respect to x and y, we'll take the derivative of each term separately and apply the chain rule where necessary.

First, let's find the partial derivative with respect to x, denoted as ∂f/∂x:

∂f/∂x = ∂/∂x (x³e^y) + ∂/∂x (y³sec(√√x))

Differentiating the first term, x³e^y, with respect to x:

∂/∂x (x³e^y) = 3x²e^y

For the second term, y³sec(√√x), we need to use the chain rule. Let's define a new function u = √√x:

∂/∂x (y³sec(√√x)) = ∂/∂u (y³sec(u)) * ∂u/∂x

Differentiating y³sec(u) with respect to u:

∂/∂u (y³sec(u)) = y³ * sec(u) * tan(u)

Now, let's find ∂u/∂x:

u = √√x

Taking the derivative of both sides with respect to x:

du/dx = (1/2) * (1/√x) * (1/2) * x^(-3/2) = 1/(4√x) * x^(-3/2) = 1/(4x√x)

Substituting the values back into ∂/∂x (y³sec(√√x)):

∂/∂x (y³sec(√√x)) = ∂/∂u (y³sec(u)) * ∂u/∂x

= y³ * sec(u) * tan(u) * 1/(4x√x)

= (y³ * sec(√√x) * tan(√√x))/(4x√x)

Therefore, the partial derivative of f(x, y) with respect to x is:

∂f/∂x = 3x²e^y + (y³ * sec(√√x) * tan(√√x))/(4x√x)

Now, let's find the partial derivative with respect to y, denoted as ∂f/∂y:

∂f/∂y = ∂/∂y (x³e^y) + ∂/∂y (y³sec(√√x))

Differentiating the first term, x³e^y, with respect to y:

∂/∂y (x³e^y) = x³e^y

For the second term, y³sec(√√x), the derivative with respect to y is simply the derivative of y³, which is 3y²:

∂/∂y (y³sec(√√x)) = 3y²

Therefore, the partial derivative of f(x, y) with respect to y is:

∂f/∂y = x³e^y + 3y²

In summary:

f(x, y) = x³e^y + y³sec(√√x)

∂f/∂x = 3x²e^y + (y³ * sec(√√x) * tan(√√x))/(4x√x)

∂f/∂y = x³e^y + 3y²

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Answer:

The distance from A to B is 19

Step-by-step explanation:

So the total of a triangle is 180 degrees

So all we have to do is add 117 + 44 = 161

And 180 - 161 = 19

Sorry if I am wrong But

Hope this helps ;)

Answer:

125

Step-by-step explanation:

hyp^2 = base^2 + hyp^2

hpy^2 = 44^2 + 117^2

hyp= 125

By applying the subtraction formula for trigonometric function cosine, we can express the given expression as cos(6°).

To express the expression cos(12°) cos(18°) − sin(12°) sin(18°) as a trigonometric function of one number, we can use the subtraction formula for cosine. The subtraction formula states that cos(A - B) = cos(A) cos(B) + sin(A) sin(B). By applying this formula, we have:

cos(12°) cos(18°) − sin(12°) sin(18°)

= cos(12° - 18°) (using the subtraction formula)

= cos(-6°)

= cos(6°) (since the cosine function is an even function)

Thus, the expression cos(12°) cos(18°) − sin(12°) sin(18°) can be written as cos(6°), which is a trigonometric function of the single number 6°.

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The polynomial (x)/(9) consists of a single term. The coefficient of the term is (1/9).A polynomial is an algebraic expression consisting of one or more terms, where each term consists of a coefficient multiplied by one or more variables raised to non-negative integer exponents.

In the given expression, (x)/(9), we have only one term since there is no addition or subtraction involved.The term in the polynomial is (x)/(9), where x is the variable and 9 is the constant denominator. The coefficient of the term is the number multiplied by the variable, which in this case is (1/9). The coefficient represents the scaling factor of the variable.

In summary, the given polynomial (x)/(9) has a single term, and the coefficient of that term is (1/9). The coefficient indicates that the variable x is scaled down by a factor of 1/9.

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The answer of the number simplified in scientific notation is 1 × 10¹.

Scientific notation is a way of expressing very large or very small numbers using powers of 10. In scientific notation, a number is written as a coefficient multiplied by 10 raised to an exponent.

(2 × 10⁻³)/(2 × 10⁻⁴) = 2¹⁻¹ × 10⁻³⁻⁽⁻⁴⁾

(2 × 10⁻³)/(2 × 10⁻⁴) = 2¹⁻¹ × 10⁻³⁺⁴

(2 × 10⁻³)/(2 × 10⁻⁴) = 2⁰ × 10¹

(2 × 10⁻³)/(2 × 10⁻⁴) = 1 × 10¹ {numbers to the power of zero is equal to 1}

Therefore, the answer of the number simplified in scientific notation is 1 × 10¹.

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Spanish: Siento algo que me mueve

Un ritmo que me hace bailar

Tomen todos su pareja

Todos vamos a gozar

Baila, baila esta cumbia

Mueve, mueve la cintura

Todos, las manos en alto

Y griten, griten con locura

Baila, baila esta cumbia

Un ritmo, ritmo sin igual

Nadie se quede sentado

Todos vamos a bailar

Siento algo que me mueve

Un ritmo que me hace bailar

Tomen todos su pareja

Todos vamos a gozar

Baila, baila esta cumbia

Mueve, mueve la cintura

Todos, las manos en alto

Y griten, griten con locura

¡Hey!, ¡hey!, ¡hey!, ¡hey!

¡Hey!, ¡hey!, ¡hey!, ¡hey!

¡Hey!

Baila, baila esta cumbia

Un ritmo, ritmo sin igual

Nadie se quede sentado

Todos vamos a bailar

Baila, baila esta cumbia

Un ritmo, ritmo sin igual

Nadie se quede sentado

Todos vamos a bailar

Baila, baila esta cumbia (baila esta cumbia conmigo)

Un ritmo, ritmo sin igual

Nadie se quede sentado (mueve la cintura)

Todos vamos a bailar

Baila, baila esta cumbia

Un ritmo, ritmo sin igual

Nadie se quede sentado (baila esta cumbia conmigo)

Todos vamos a bailar

Baila, baila esta cumbia (mueve la cintura)

Un ritmo, ritmo sin igual

Englis:I feel something that moves me

A rhythm that makes me dance

Take all your partner

We are all going to enjoy

Dance, dance this cumbia

Move, move your waist

Everyone, hands up

And scream, scream with madness

Dance, dance this cumbia

A rhythm, rhythm like no other

No one stay seated

We are all going to dance

I feel something that moves me

A rhythm that makes me dance

Take all your partner

We are all going to enjoy

Dance, dance this cumbia

Move, move your waist

Everyone, hands up

And scream, scream with madness

Hey! Hey! Hey! Hey!

Hey! Hey! Hey! Hey!

Hey!

Dance, dance this cumbia

A rhythm, rhythm like no other

No one stay seated

We are all going to dance

Dance, dance this cumbia

A rhythm, rhythm like no other

No one stay seated

We are all going to dance

Dance, dance this cumbia (dance this cumbia with me)

A rhythm, rhythm like no other

Nobody stay seated (move the waist)

We are all going to dance

Dance, dance this cumbia

A rhythm, rhythm like no other

Nobody stay seated (dance this cumbia with me)

We are all going to dance

Dance, dance this cumbia (move your waist)

A rhythm, rhythm like no other

Answer:

d>0

Step-by-step explanation:

brainliest please

Answer:

did you get the answer yet I have the same question

Answer: a. 8 feet

the first question in part b is 1 and the second part is 9. ( or you could just put 1,9) c. 1 foot taller d. -2 and 4

Step-by-step explanation: you get answer A by looking at the C- value of the equation( in this case it’s 8)

you get the first answer to B by using the axis of symmetry formula -b/2(a) and that equals 1. You get the second answer to B by plugging in 1 into the equation..solve and get 9. So your answers in total should be (1,9)

For part C all you do is subtract the top of the ramp.. which is 8 from your vertex. in other words you do 9-8 and get 1 as your answer for C

Lastly, for D you use the quadratic formula ( or use photo math) and get answers -2 and 4.

If you’re also having problems on part E .. all you have to do is place a dot at point -2, place dot at point 4, place a dot at 8 on the Y AXIS, then place a dot at point (1,9) lastly, connect the dots with a line and the graph should look like an upside down U or V( whatever you think it looks like)

I hope this helped you guys!!

Answer:

0.1

Step-by-step explanation:

Just take 24/24 which is 1 and move the decimal one place to the left because there is an extra 0 on the denominator

Answer:

To convert 2 Bigha into Kattha:

If 1 Bigha = 20 Kattha:

2 Bigha = 2 * 20 Kattha = 40 Kattha

If 1 Bigha = 16 Kattha:

2 Bigha = 2 * 16 Kattha = 32 Kattha