Answer:
24:1
Step-by-step explanation:
The ratio is 336:14 to 24:1.
x a a a
[ a x a a ] =?
a a x a
Answer:
nyee he he he
Step-by-step explanation:
heh
paps undertale
A right rectangular container is 10 cm wide and 24 cm long and contains water to a depth of 7cm. A stone is placed in the water and the water rises 2.7 cm. Find the volume of the stone.
Answer:
The volume of the rock is 648 cm^3
Step-by-step explanation:
Likely the only dimension that is free to move is the depth of 7 cm.
Volume of the Rock = L * W * h1
L = 24
W = 10
h1 = 2.7
V = 24 * 10 * 2.7
V = 648 cm^3
Full time tuition at Duke University is $55960 per year. Round this number to the nearest hundred.
No link please
Ergent
Using matrix method solve
the following simulaneous equatin
2x+3y=9
3x-1y=3
Step-by-step explanation:
here are the matrices you were looking for
100 Points! Algebra question. Graph the function. Photo attached. Thank you!
The graph will provide a V-shaped graph with (-1,0) as the vertex when the values are substituted into the function f(x) = |x+1|
The graph consists of two parts: one above the x-axis and one below the x-axis.
For x values greater than or equal to -1, the absolute value of (x + 1) is equal to (x + 1), resulting in a positive y-value. This is represented by the diagonal line starting at (-1, 0) and extending upward to the right.
For x values less than -1, the absolute value of (x + 1) is equal to -(x + 1), resulting in a negative y-value. This is represented by the diagonal line starting at (-1, 0) and extending downward to the left.
The graph is symmetric with respect to the vertical line x = -1. The point (-1, 0) is the vertex of the "V" shape formed by the graph.
The domain of the function is all real numbers, as there are no restrictions on x. The range consists of y-values greater than or equal to 0 for integer values of y and y-values less than 0 for integer values of y.
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Find the equation of a line with given slope and containing the given point. Write the equation in slope-intercept form. Horizontal line containing (4,-1)Y=
Solution
Since,Horizontal line containing (4,-1) then the slope (m) is zero (0)
The equation of the line in Slope-Intercept form is:
\(y=mx+b\)Where "m" is the slope and "b" is the y-intercept.
We know that this is a horizontal line.
This means that: m=0
Knowing that this line contains the point (4,-1) we can substitute this coordinates m=0 into y = mx + b, and then we solve for b
\(\begin{gathered} -1=4(0)+b \\ -1=0+b_{} \\ b=-1 \end{gathered}\)Therefore, b = -1
Therefore, the equation of this line in Slope-intercept form is:
\(\begin{gathered} y=(0)-1 \\ y=-1 \end{gathered}\)The final answer
\(y=-1\)Please answer it....
If \(a\ \textless \ b\), there are three ordered pairs of positive integers \((a,b)\) that satisfy \(a^{2}+b^{2}=10(123)^{2}\) If two of these ordered pairs are \((39,387)\) and \((201,333)\). What is the third such ordered pair?
The third ordered pair that satisfy the given equation is (123, 369).
The given parameters;
\(a^2 + b^2 = 10(123)^2\)First pair of the equation, = (39, 387)Second pair of the equation = (201, 333).The third ordered pair of the equation can be determined by using general equation of a circle;
\(a^2 + b^2 = r^2\\\\a^2 + b^2 = (123\sqrt{10} )^2\\\\a^2 + b^2 = (\sqrt{151290} )^2\\\\a^2 + b^2 = 151290\\\\a^2 = 151290- b^2\\\\ a= \sqrt{151290 - b^2}\)
The radius of the circle is calculated as;
\(r^2 = 151290\\\\r = \sqrt{151290} \\\\r = 388.96\)
The value of a can be obtained by randomly choosing numbers less than the radius as values of b.
\(b < r\\\\b < 388.96\)
\(a = \sqrt{151290 \ - \ (387)^2} \\\\a = 39\\\\(39, \ 387)\\\\a = \sqrt{151290 \ - \ (333)^2}\\\\a = 201\\\\(201, \ 333)\\\\a = \sqrt{151290 \ - \ (369)^2}\\\\a = 123\\\\(123, \ 369)\)
Thus, the third ordered pair that satisfy the given equation is (123, 369).
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After the party, a bag of ice weighs 7/8 pound. Before the party, the bag of ice weighed 3 times as much. How many pounds did the bac
party?
Drag the pointer to its correct location on the number line to show the weight of the bag of ice before the party.
3
4
Weight of Bag of Ice Before Party
2
4
Finish Late
The weight before the party could be any positive number
The weight of the bag of ice after the party was 7/8 pounds. So we can set up an equation:
x - weight used at the party = 7/8
We know that the weight used at the party is the weight before the party minus the weight after the party.
So we can substitute 3x for the weight before the party:
3x - (7/8) = weight used at the party
We don't know the exact weight used at the party, but we do know that it was less than or equal to the weight before the party.
So we can set up another inequality:
weight used at the party ≤ 3x
Putting it all together:
3x - (7/8) ≤ 3x
Simplifying:
-(7/8) ≤ 0
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What is the length of side AB of parallelogram ABCD?
units
A
VX
49-8
B
D
9 +4
Answer:
8
Step-by-step explanation:
If you are driving at a rate of 55 miles per hour, about how many feet per second are you traveling?
290400 feet per second
0.015 feet per second
4840 feet per second
80.67 feet per second
Fide the volume and round to the nearest tenth I will give brainless
Answer:
22.5 I hope this helped
What is the Area and Perimeter??? PLEASE HELP
Answer:for area you times them and for perimiter you add
Step-by-step explanation:
hope you understand
NO LINKS!!!
5. Find the domain and range for the graph
Remember that
For a pair (x,y)
x is domainy is rangeSo
here
Domain:-
[-5,oo)As the function starts from -5 and tends to infinity .
Range:-
[-3,3)As the function starts from -3 but has an asymptote at y=3 .
Answer:
From inspection of the graph, it appears that the curve approaches y = 3 but never crosses it. Therefore, there could be an asymptote at y = 3.
Domain: input values (x-values) → [-5, ∞)
The x-values of the curve start at x = -5 and tends to infinity.
Range: output values (y-values) → [-3, 3)
The y-values of the curve start at y = -3 and appears to tend towards y = 3
How many 2 1/3 m lengths of rope can be cut from a rope of length 21 m?
Pls help with this homework pls
Answer: 480 in²
Step-by-step explanation:
To calculate the surface area, we will find the area of each side and add it together.
Area of the rectangular sides can be found with A = LW:
A = LW
A = (12 in)(10 in)
A = 120 in²
A = LW
A = (12 in)(10 in)
A = 120 in²
A = LW
A = (12 in)(12 in)
A = 144 in²
All the rectangular sides added together:
120 in² + 120 in² + 144 in² = 384 in²
Now, we will find the triangle sides. The formula for a triangle is \(A=\frac{BH}{2}\), but since we have two congruent triangles I will not be dividing by 2.
A = BH
A = (12 in)(8 in)
A = 96 in²
Lastly, I will add them both together:
384 in² + 96 in² = 480 in²
Find the odds against the event rolling a fair die and getting a 3, a 5, a 6 or a 4
The odds against the event rolling a fair die and getting a 3 is \(\frac{5}{6}\) , getting a 5 is \(\frac{5}{6}\) , and getting a 6 or a 4 is \(\frac{2}{3}\).
Probability is finding the odds of occurring or odd against an event occurring. It is described as the ratio of the number of times that event occurs to the total number of events that can occur
In case of a fair die, the outcomes possible are 1, 2, 3, 4, 5, or 6
Thus the number of events that can occur is 6
1. The odds against getting a 3 means that the outcome can either be 1, 2, 4, 5, or 6
Probability = \(\frac{5}{6}\)
2. The odds against getting a 5 means that the outcome can either be 1, 2, 3, 4, or 6
Probability = \(\frac{5}{6}\)
3. The odds against getting a 6 or a 4 means that the outcome can either be 1, 2, 3, or 5.
Probability = \(\frac{4}{6}\) = \(\frac{2}{3}\)
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PLEASE HELP how do you find the thickness of a foil when you’re given the density, mass, length and width? please explain with detail! also how will the units look during the process because my length and width are cm, density is g/cm^3, and mass is g.
Step-by-step explanation:
Density = mass / volume
Volume = width × length × thickness
D = M / V
D = M / (WLT)
Solving for the thickness:
T = M / (WLD)
how oes the relationship between logarithms and exponential functions help us find solutions
The relationship between logarithms and exponential functions is fundamental and provides a powerful tool for finding solutions in various mathematical and scientific contexts.
Logarithms are the inverse functions of exponential functions. They allow us to solve equations and manipulate exponential expressions in a more manageable way. By taking the logarithm of both sides of an exponential equation, we can convert it into a linear equation, which is often easier to solve.
One of the key properties of logarithms is the ability to condense multiplication and division operations into addition and subtraction operations. For example, the logarithm of a product is equal to the sum of the logarithms, and the logarithm of a quotient is equal to the difference of the logarithms.
Logarithms also help us solve equations involving exponential growth or decay. By taking the logarithm of both sides of an exponential growth or decay equation, we can isolate the exponent and solve for the unknown variable.
This is particularly useful in fields such as finance, population modeling, and radioactive decay, where exponential functions are commonly used.
Furthermore, logarithms provide a way to express very large or very small numbers in a more manageable form. The logarithmic scale allows us to compress a wide range of values into a smaller range, making it easier to analyze and compare data.
In summary, the relationship between logarithms and exponential functions enables us to simplify and solve equations involving exponential expressions, model exponential growth or decay, and manipulate large or small numbers more effectively.
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Dorothy organises a charity raffle she sells 800 tickets for £2 each 4% of the tickets win a prize it cost £20 65% of the profit goes to charity A and the rest goes to charity be how much of the money does Dorothy raise for charity day
By using Percentage , Profit distributed to Charity A is £ 624 and Charity B is £ 336
What is Percentage ?A figure or ratio stated as a fraction of 100 is called a percentage. Although the abbreviations "pct.", "pct.", and occasionally "pc" are also used, the percent symbol, "%," is frequently used to indicate it. A % is a number without dimensions and without a standard measurement.
The Latin phrase "per centum," which meaning "by the hundred," was the source of the English word "percentage." Fractions having a denominator of 100 are called percentages. In other words, it is a relationship where the value of the entire is always assumed to be 100.
Finding the percentage of a whole in terms of 100 is what percentage calculation refers to. A percentage can be found in one of two ways:
use the unitary approach.by adjusting the fraction's denominator to 100.It should be noted that when the denominator is not a factor of 100, the second technique of percentage calculation is not applied. In these situations, we employ the unitary technique.Total ticket sold = 800
Cost of each ticket is £ 2
Total fund raised (raw) = 2 * 800 = £1600
4% of the ticket won a prize of £20 each
so total number of tickets winning a prize = 4 % of 800 = 32
Total prize money distributed = 32 * 20 = £ 640
Total amount to distribute to charity = 1600 - 640 = £ 960
Total profit that goes to Charity A is = 65 % of 960 = £624
And rest to charity B is = £ 336
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A gym owner has some red weights and some purple weights. The red weights are 8 kilograms each, and the purple weights are 3 kilograms each. The owner has 10 weights, and they weigh 55 kilograms in all. How many of each color weight does he have?
Answer:
7 red weights and 2 purple
Step-by-step explanation:
Answer:
5 purple weights and 5 red weights
Step-by-step explanation:
Help please asap no links please
So the new coordinates of point C are (1, 2), and the image of Triangle ABC is congruent to the original triangle.
What is triangle?A triangle is a closed, two-dimensional geometric figure with three straight sides and three angles. It is one of the basic shapes in geometry and can be classified based on the length of its sides or the size of its angles. A triangle with all sides of equal length is called an equilateral triangle, while a triangle with two sides of equal length is called an isosceles triangle. A triangle with no sides of equal length is called a scalene triangle. Triangles can also be classified based on the size of their angles, with an acute triangle having all angles less than 90 degrees, a right triangle having one angle equal to 90 degrees, and an obtuse triangle having one angle greater than 90 degrees.
Here,
To find the new coordinates of point C after the rotation and translation, we need to perform each transformation separately and then combine them.
Rotation:
To rotate a point 180° counterclockwise about the origin, we switch the sign of both coordinates. Therefore, the new coordinates of point C after the rotation are (-3, -2).
Translation:
To translate a point to the right 4 and up 4, we add 4 to the x-coordinate and 4 to the y-coordinate. Therefore, the new coordinates of point C after the translation are (1, 2).
To determine if the image of Triangle ABC is similar or congruent to the original triangle, we need to compare the corresponding sides and angles of both triangles.
Since we performed a rotation of 180°, all the angles in the image triangle are congruent to the corresponding angles in the original triangle. Additionally, since we performed a translation, the sides of the image triangle are congruent to the corresponding sides of the original triangle. Therefore, the image triangle is congruent to the original triangle.
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A puzzle has 1080 pieces. How many pieces are 80% of the puzzle?
Answer:
864
Step-by-step explanation:
80/100 simplified is 4/5
so you do 4/5 of 1080
which is 1080 divided by 5 that is 216
and then 216 x 4 which is 864
What is the inverse of f(x) = 2x2 –4?
Answer:
The inverse of the function is
\({ \underline{f {}^{ - 1}(x) = \sqrt{ \frac{x + 4}{2} } }}\)
Step-by-step explanation:
let the inverse of f(x) be m:
\(m = {2x}^{2} - 4 \)
take 4 to the left hand side ( changes sign to positive ):
\(m + 4 = {2x}^{2} \\ \frac{m + 4}{2} = {x}^{2} \)
take a square root on all sides:
\( \sqrt{ \frac{m + 4}{2} } = \sqrt{ {x}^{2} } \\ \\ x = \sqrt{ \frac{m + 4}{2} } \)
substitute x in place of m:
\( {f}^{ - 1} (x) = \sqrt{ \frac{x + 4}{2} } \)
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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find the equation of the perpendicular bisector of segment ab with endpoints a=2,2 and b=-4,6 if the perpendicular bisector intersects the y-axis at point p what are the lengths of pa and pb
Equation of perpendicular bisector is , \(y=\frac{3}{2} x+\frac{11}{2}\)
Length of both pa and pb are \(\sqrt{\frac{65}{4} }\) unit.
Slope of segment ab is, \(\frac{6-2}{-4-2} =-\frac{2}{3}\)
So, slope of perpendicular bisector will be, negative of reciprocal of slope of segment ab.
Therefore, slope of perpendicular bisector is, \(\frac{3}{2}\)
Since, perpendicular bisector passes through the mid point of segment ab.
So, coordinate of mid point of segment ab is,
\((\frac{2-4}{2},\frac{2+6}{2} )=(-1,4)\)
Thus, perpendicular bisector of ab passing through (- 1, 4) and have slope 3/2.
So, equation of angle bisector is,
\(y=\frac{3}{2} x+\frac{11}{2}\)
Since, the perpendicular bisector intersects the y-axis at point p
So, coordinate of point p is (0, 11/2)
By applying distance formula,
\(pa=\sqrt{(2-0)^{2}+(2-11/2)^{2} }\\\\ =\sqrt{4+\frac{49}{4} }\\\\ =\sqrt{\frac{65}{4} }\)
\(pb=\sqrt{(-4-0)^{2}+(6-11/2)^{2} }\\\\ =\sqrt{16+\frac{1}{4} }\\\\ =\sqrt{\frac{65}{4} }\)
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The Venn diagram below shows the events A and B, and the probabilities p, q and r.
It is known that P(A)=0.43 , P(B)=0.62 and P(A∩B)=0.27 .
Calculate the value of p
Calculate the value of q
Calculate the value of r
Find the value of P (A given NOT B)
The value of q is 0.35.
The value of p is 0.16.
The value of r is 0.27.
The value of P(A given NOT B) is approximately 0.4211.
To calculate the values of p, q, and r, we can use the information provided in the Venn diagram and the probabilities of events A and B.
Given:
P(A) = 0.43
P(B) = 0.62
P(A∩B) = 0.27
Calculating the value of p:
The value of p represents the probability of event A occurring without event B. In the Venn diagram, p corresponds to the region inside A but outside B.
We can calculate p by subtracting the probability of the intersection of A and B from the probability of A:
p = P(A) - P(A∩B)
= 0.43 - 0.27
= 0.16
Therefore, the value of p is 0.16.
Calculating the value of q:
The value of q represents the probability of event B occurring without event A. In the Venn diagram, q corresponds to the region inside B but outside A.
We can calculate q by subtracting the probability of the intersection of A and B from the probability of B:
q = P(B) - P(A∩B)
= 0.62 - 0.27
= 0.35
Therefore, the value of q is 0.35.
Calculating the value of r:
The value of r represents the probability of both event A and event B occurring. In the Venn diagram, r corresponds to the intersection of A and B.
We are given that P(A∩B) = 0.27, so the value of r is 0.27.
Therefore, the value of r is 0.27.
Finding the value of P(A given NOT B):
P(A given NOT B) represents the probability of event A occurring given that event B does not occur. In other words, it represents the probability of A happening when B is not happening.
To calculate this, we need to find the probability of A without B and divide it by the probability of NOT B.
P(A given NOT B) = P(A∩(NOT B)) / P(NOT B)
We can calculate the value of P(A given NOT B) using the provided probabilities:
P(A given NOT B) = P(A) - P(A∩B) / (1 - P(B))
= 0.43 - 0.27 / (1 - 0.62)
= 0.16 / 0.38
≈ 0.4211
Therefore, the value of P(A given NOT B) is approximately 0.4211.
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Area of traingle and rectangle
More coming!!
Answer:
20cm2
Step-by-step explanation:
area of triangle :
1/2 x b x h
= 1/2 x 8 x 5
=20 cm 2
6.
Karla is selling jewelry at a fair. She sells each piece of jewelry for $5. She sells 24 pieces
of jewelry in 3 hours. At that rate, how much money will she make from the jewelry sold in
7 hours
Answer:
$280
Step-by-step explanation:
Sell 24 pieces in 3 hours, so 8 pieces in 1 hour
in 7 hours 8*7 = 56 pieces, each for $5
56 piece cost 5^56 = $280
How many dollars are in one cent
Answer:
I think its $0.01?
Step-by-step explanation:
Penny/Cent= €1 = $0.01
I think
We buy these products for $50.00 and then sell them for $67.00
Answer:
$17.00
Step-by-step explanation:
The profit=67-50
=$17