Josie walks 15 meters north down the freshman hallway. She then walks 25 meters east. Lastly, she walks 15 meters south. What is Josie's displacement? *

When a speaker is lowered into water, the wavelength of the sound decreases.

When a speaker is lowered into water, the speed of sound changes, as the density and compressiblility of water are different from that of air.

In general, the speed of sound in water is higher than the speed of sound in air.

The wavelength of a sound wave is related to its speed and frequency by the equation:

wavelength = speed/frequency

Since the speed of sound increases when the speaker is lowered into water, but the frequency of the sound remains the same, the wavelength of the sound must decrease.

This means that the distance between adjacent peaks or troughs of the sound wave decreases as the speaker is lowered into water.

In other words, when a speaker is lowered into water, the wavelength of the sound decreases

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Six examples in which Physics has been used in daily life include:

Physics plays a major role in transportation, from the design of cars and airplanes to the operation of trains and buses. Physics is also used in communications, from the design of telephone networks to the operation of the internet.

Physics is used to generate energy from various sources, such as fossil fuels, nuclear power, hydroelectric power, and wind power. Physics is used in medical imaging, such as X-rays, CT scans, and MRI.

Physics plays a major role in construction, from the design of buildings and bridges to the materials used in construction.  Physics is also used in entertainment, from the design of amusement park rides to the operation of video games.

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The discrete radii and energy states of atoms were first explained by electrons circling the atom in an integral number of "quantum" or "quantized" levels.

The concept of quantized energy levels was proposed by Niels Bohr in 1913 as part of his atomic model, which explained how electrons are distributed around the nucleus.

According to Bohr's model, electrons occupy specific energy levels or orbits, and they can jump between these levels by absorbing or emitting energy in discrete packets called photons.

These energy levels are quantized, meaning that only certain specific energy values are allowed for the electrons. This quantization of energy is a fundamental aspect of quantum mechanics and has been verified through experimental observations.

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Decrease

The mathematical relationship between heat, internal energy and work done by the system is given as:

△U = Q + W

where △U is the change in the internal energy

W is the workdone by the system

Q is the heat energy in the system

Since the workdone by the system is negative, when a system does work, there is a depletion in the amount of energy possessed by the system.

Due to this loss of energy by the system as a result of the workdone, the internal energy decreases.

The acceleration (α) of the center of the hoop: α = (mg * sin(θ)) / (2m) = (g * sin(θ)) / 2

The minimum coefficient of static friction (μmin) needed for the hoop to roll without slipping: μmin = α / (g * cos(θ)) = (g * sin(θ) / 2) / (g * cos(θ)) = tan(θ) / 2

The acceleration (α) of the center of the circular hoop can be determined by applying Newton's second law and the principle of conservation of angular momentum. Considering gravitational force (mg), normal force (N), and friction force (f) acting on the hoop, we can write:

mg * sin(θ) - f = m * α (1) (linear motion) and f * r = I * α/r (2) (angular motion)

For a hoop, the moment of inertia (I) is given by I = m * r^2. Substituting this into equation (2) and solving for f, we get:

f = m * α (3)

Now, substitute equation (3) into equation (1):

mg * sin(θ) - m * α = m * α

Rearranging the terms, we get the acceleration (α) of the center of the hoop:

α = (mg * sin(θ)) / (2m) = (g * sin(θ)) / 2

For the hoop to roll without slipping, the static friction (f) must be equal to the torque acting on the hoop. The minimum coefficient of static friction (μmin) can be determined using the frictional force equation:

f = μmin * N

Since the normal force (N) equals mg * cos(θ), the frictional force can be written as:

f = μmin * mg * cos(θ)

Now, substituting f = m * α from equation (3) into this equation, we get:

m * α = μmin * mg * cos(θ)

Rearranging the terms, we find the minimum coefficient of static friction (μmin) needed for the hoop to roll without slipping:

μmin = α / (g * cos(θ)) = (g * sin(θ) / 2) / (g * cos(θ)) = tan(θ) / 2

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The distance the bus travelled in 20 seconds is 12.75 m

The first step is to write out parameters given in the question

Final velocity= 15

Initial velocity= 5

Time= 20

Distance= ?

V² + U²= 2as

15² + 5²= 2(9.8)s

225+25= 19.6s

250= 19.6s

s= 250/19.6

= 12.75

Hence the distance the bus travelled in 20 seconds is 12.75 m

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The current through the 2Ω resistor is 9.5A

The terminal voltage is 10.8 V

a) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V

the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A

the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A

voltage across 20Ω is V = I*R = 0.75*20 = 15 V

the source voltage is Vs = V8 + V20 = 4+15 = 19 V

therefore the current through 2Ω resistor is

I = V/R = 19/2 = 9.5 A

b) The terminal voltage is

Vterminal = VR = I*R = 0.450*24 = 10.8 V

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Answer:

(a) 1.5 nF, 1.2 nF, 1 nF

(b) 0.4 nF

Explanation:

V = 150 V

V' = 40 V, V'' = 50 V, V''' = 60 V, q = 6 x 10^-8 C

(a) C' = q/V' = 6 x 10^-8 / 40  = 1.5 x 10^-9  F

C'' = q/V'' = 6 x 10^-8 / 50 = 1.2 x 10^-9 F

C''' = q/V''' = 6 x 10^-8 / 60 = 1 x 10^-9 F

(b) The effective capacitance is

\(\frac{1}{C}=\frac{1}{C'}+\frac{1}{C''}+\frac{1}{C'''}\\\\\frac{1}{C}=\frac{10^9}{1.5}+\frac{10^9}{1.2}+\frac{10^9}{1}\\\\C = 0.4\times 10^{-9} F\)  

Energy absorbed by the radiologist is 1.775*10^-6J.

To find the answer, we have to know about the radiation.

           \(D=\frac{E}{m}\)

where; E is the energy absorbed and m is the mass of the body.

         \(E=D*m=2.5*10^{-6}J/kg*71kg=1.775*10^{-4}J\)

Thus, we can conclude that, the Energy absorbed by the radiologist is 1.775*10^-6J.

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This is true because the process of dry ice sublimating and the puddle freezing both involve chemical bonds breaking.

In the case of dry ice (solid CO2), the sublimation process occurs when the CO2 molecules absorb enough energy to break the bonds holding them together in a solid state. This energy is supplied by the surrounding air, causing the CO2 to transition directly from a solid to a gas.

In the case of the puddle freezing, the water molecules lose energy and slow down, allowing hydrogen bonds to form between the molecules. As more and more bonds form, the liquid transitions to a solid (ice). The breaking of hydrogen bonds in the liquid and the formation of new bonds in the solid are chemical processes that represent a breaking and forming of chemical bonds.

"

Complete and correct question

I dry ice sublimating and becoming a ga and a puddle freezing into ice on a clod night both involve chemical bond breaking

True or false

"

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Answer:

The amount of moisture air can hold is dependent on its temperature and pressure. The warmer the air the greater the quantity of water vapour it can contain. The air temperature is measured with a normal thermometer this is the Dry-Bulb reading. The actual amount of moisture known as the mixing ratio is measured in grams of water per kilogram of dry air. When air at a certain temperature is saturated it cannot hold any more moisture. The relative humidity of the air is the ratio of the actual amount of moisture in the air to the fully saturated amount.

We can use evaporation to measure the amount of moisture in the air. A wet cloth is placed over the bulb of a thermometer and then air is blown over the cloth causing the water to evaporate. Since evaporation takes up heat, the thermometer will cool to a lower temperature than a thermometer with a dry bulb at the same time and place. The depression in Wet-Bulb temperature allows the humidity to be calculated. If the air is fully saturated (100% relative humidity) the water cannot evaporate, so both the wet and dry bulb temperatures are the same. If the dry and wet bulb temperatures are set to the same value the calculator will show the saturation mixing ratio the amount of water in saturated air at that temperature.

If partly saturated air is cooled without changing its pressure or amount of water vapour, a point is reached when it becomes saturated. The moisture will be given up as dew or ice crystals. This temperature is the Dew Point. This is why condensation will form on a bottle of cold beer, as the air in the vicinity of the bottle is cooled below its dew point. Meteorological reports usually quote the temperature and dew point as well as the station pressure. Moisture content and relative humidity can be calculated from these figures.

The Psychrometer is the name of a device containing both a wet and dry bulb thermometer. This can be a fixed device for meteorology or a handheld sling psychrometer that is often used in air conditioning applications.

Explanation:

Ultraviolet light exhibits shorter wavelengths compared to visible light, infrared waves, or radio waves.

A wavelength is a measure of the distance between two corresponding points on a wave. Ultraviolet light is a type of electromagnetic radiation with wavelengths shorter than visible light but longer than X-rays. Visible light is the portion of the electromagnetic spectrum that is visible to the human eye and has wavelengths between approximately 400 and 700 nanometers. Infrared waves are longer than visible light and have wavelengths between approximately 700 nanometers and 1 millimeter. Radio waves have the longest wavelengths in the electromagnetic spectrum, ranging from about 1 millimeter to more than 100 kilometers.

Visible light is the portion of the electromagnetic spectrum that is visible to the human eye. It ranges in wavelength from approximately 400 to 700 nanometers and is responsible for the colors we see in the world around us. When white light passes through a prism or water droplets, it is separated into the various colors of the visible spectrum: red, orange, yellow, green, blue, indigo, and violet.

Therefore, Compared to radio waves, infrared waves, or visible light, ultraviolet light has shorter wavelengths.

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Answer:  An effect of continental drift is causing tectonic plates resting upon the convecting mantle to move which results in natural disasters like earthquakes, volcanic eruptions, and more.

Answer:

A. Mountains on different continents match up.

Explanation:

Due to the drifting/ moving apart of the continents, land masses is split therefore in case of a mountain that split, it matches the other part in another continent.

The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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The period of the pendulum on the surface of Mars, where g = 3.71m/s², would be the same as the period on Earth, 1.70s.  The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

A basic pendulum's period is determined by the equation T = 2(L/g), where T is the period, L is the pendulum's length, and g is the acceleration brought on by gravity.

L = (T/(2))2g can be solved for on Earth with a period of 1.70s by rearranging the equation.

Using the same equation and the Mars surface gravity, g = 3.71m/s2, we can now get the period on Mars' surface: T\(_{mars}\) = 2(L/g\(_{mars}\)).

The equation T\(_{mars}\) = 2(((T/(2))2g)/(g\(_{mars}\))) is obtained by substituting the expression for L and the surface gravity of Mars.

T\(_{mars}\) = T(g/g_Mars), to simplify the formula.

T\(_{mars}\) = 1.70s(9.81m/s2 / 3.71m/s) is the result of plugging in the data. The pendulum on the surface of Mars has a period of roughly 3.31 seconds, according to our calculation of this expression.

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To solve this problem, we need to use the thin lens equation: 1/f = 1/di + 1/do. Where f is the focal length of the lens, di is the image distance, and do is the object distance.

For the converging lens, f = 5.2 cm, do = -10.2 cm (since the object is to the left of the lens), and di is unknown. Solving for di, we get:

1/5.2 = 1/di + 1/-10.2

di = -3.4 cm

The negative sign for di indicates that the image is formed on the same side of the lens as the object, which means it is a virtual image.

Now, the diverging lens is located 24.7 cm to the right of the converging lens, so the virtual image formed by the converging lens acts as the object for the diverging lens.  Using the same thin lens equation, we can find the final image distance:

1/-14.5 = 1/di + 1/3.4

di = -4.9 cm

Again, the negative sign indicates that the image is virtual, which means it is located on the same side of the lens as the object. The final image is located 4.9 cm to the left of the diverging lens.

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The primary rationale for the technician's precautions about radiation exposure is to protect their health. Ionizing radiation can cause damage to the body's cells and the risk increases with increased exposure.

The technician wants to minimize their exposure to radiation to reduce their risk of developing cancer or any other health issues that may arise from over exposure to radiation. Even though the levels of radiation used in contemporary radiologic imaging are relatively low, it is important for the technician to take precautions to protect their health.

This includes standing behind protective shields, wearing protective clothing and avoiding long-term exposure to the radiation source.

Additionally, the technician should ensure that any equipment they use is regularly tested to ensure it is working properly and is providing the lowest possible dose of radiation. By following these safety precautions, the technician can ensure their safety and reduce their long-term risk of developing any health issues from radiation exposure.

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The coefficient of static friction between the mass and the plane is 0.52.

Then coefficient of static friction is the value that must be overcomed when two surfaces are in contact. This value depends on the nature of the surfaces in contact.

In the given question, since the two surfaces are rough, frictional force will act in opposite direction of the motion.

Given that;

F = μR

where F is the force applied to the mass and R is its reaction.

F = 250 N

R = mgCos θ

  = 50 x 10 Cos 15

  = 483 N

So that;

μ = F/R

  = 250/483

μ = 0.52

The coefficient of static friction between the mass and the plane is 0.52.

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Answer:

\(10 \: m.\)

Explanation:

\(his \: position \:is \: his \: distance \: from \: the \: \\ point \: of \: motion \: and \: is \: given \: by : \\ v = \frac{s}{t} \\ s = vt =2 \times 5 \\ s = 10 \: m.\)

The magnitude of the net force of A and B on object C which is stated as resultant force is 85.12 N.

The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force. When the object is at rest or moving at the same speed as the object, the resulting force is zero. Since all forces are acting in the same direction, the combined force should be equal for all forces.

Combining forces applied to the same body component might result in the same outcome. Combining forces with various points of application while maintaining the same effect on the body is not conceivable. By moving the forces to the same point of application and computing the associated torques, a system of forces operating on a rigid body is combined. These forces and torques are added to produce the final force and torque.

We have two forces as,

A = 25.6 sin 26.5 = 11.42

B = 99.7 cos 32.2 = 84.36

R = \(\sqrt{A^2+B^2}\) = \(\sqrt{11.42^2+84.36^2}\) = \(\sqrt{7247.026}\) = 85.12 N

Therefore, the magnitude of force on C is 85.12 N.

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Answer:

6.25 m/s

Explanation:

The average speed of an object is the ratio of the total distance traveled by the object and the total time taken to cover the distance. Mathematically,

Average speed = total distance traveled/total time taken.

In this case;

Total distance traveled = 650 + 850 = 1500 m

Total time = 240 s

Average speed = 1500/240 = 6.25 m/s

The average speed of the man is, therefore, 6.25 m/s.

Answer:

Balanced forces acting on a stationary object cause the object to remain at rest. True: Forces can give energy to an object it acts on causing the object to change it state of motion. If forces acting on an object are balanced, they do not cause a change in motion.

Answer:

False

Explanation:

It is NOT possible for just three forces to be acting upon an object and they still balance each other. A free-falling object experiences a balance of forces.

Answer:

A

Explanation:

Explanation:

Hope it helps my lady.......

Answer:

Option B

Explanation:

Looking at the 3 galvanometer readings given above, for galvanometer A, the reading is -2 mA.

For galvanometer B, the reading is 4 mA.

While for galvanometer C, the reading is -5 MA

Thus, option B is correct.

Answer:

B, the second picture

Explanation:

edge 2022

Answer: Limiting reactant

Explanation:

The limiting reactant is a reactant will get completely consumed up in the reaction. This reactant being in low concentration will lead to the formation of limited amount of product.

In the given situation, since the butter cakes are required to be 3 sticks for making 3 cakes but only 2 cakes are available thus the butter stick is the limiting reactant.

When a sound source produces waves, the frequency of the waves determines the pitch of the sound. In this scenario, the sound source is producing 1.20-khz waves. However, the sound source is also moving towards a stationary listener at one-half the speed of sound. This means that the waves will be compressed as they travel towards the listener, resulting in a higher frequency.

To calculate the frequency that the listener will hear, we can use the formula:

f' = f (v +/- v_observer) / (v +/- v_source)

Where:
f = frequency of the sound source (1.20 kHz in this case)
v = speed of sound in air (approximately 343 m/s)
v_observer = speed of the observer (0 m/s since they are stationary)
v_source = speed of the source (one-half the speed of sound, or approximately 171.5 m/s)

Plugging in the values, we get:

f' = 1.20 kHz * (343 m/s + 0 m/s) / (343 m/s - 171.5 m/s)
f' = 2.14 kHz

Therefore, the listener will hear a frequency of 2.14 kHz instead of 1.20 kHz. This is because the sound waves are compressed as they travel towards the listener due to the motion of the sound source.

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Explanation:

Domestic wiring is house wiring were phase/live wire,neutral wire,earth wire is used that functions in giving the electricity to our home except in case of neutral wire