Josh has 212 baseball cards. He buys 12 more packs of baseball cards, with 15 cards in each pack. How many cards does Josh have altogether after buying the new packs?

Answer:

2.5*10^7

Step-by-step explanation:

Answer:

Brainliest!!!

Step-by-step explanation:

See picture

Answer:

10.5 miles in 75 minutes,

Step-by-step explanation:

(7/50) x 75 = 10.5

Since he runs 7 miles in 50 minutes, this would be the fraction 7/50. You simply multiply it by 75, because that is the minutes you are looking for.

The answer is 10.5.

Answer:

Model 2

Step-by-step explanation:

1.56 + 0.33 = 1.89

Answer:

6 i think

Step-by-step explanation:

vertices are the points and there are 6 points

Answer:

9,-9

Step-by-step explanation:

Because your opponent is in the positive while you are in the negative

The distance between Ben and Dolphin will be 115.47 feet and the distance between Ben and Paulo will be 57.74 feet.

Based on the information given, using trigonometric ratios, we'll have:

Sin A = CD/AC

Sin 60° = 100/AC

AC = 100/✓3/2

AC = 115.47

Tan A = CD/DA

DA = 100/Tan 60°

DA = 100/✓3

DA = 57.74

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The polygons are similar but not necessarily drawn to scale the value of x is 13.

We can set up a proportion between the corresponding sides of the two similar polygons:

Polygons are two-dimensional geometric shapes that are made up of straight lines and closed loops.

Polygons are characterized by the number of sides, angles, and vertices they have. The sides of a polygon are the straight lines that connect the vertices, while the vertices are the points where the sides meet. The angles of a polygon are formed by the intersection of two adjacent sides.

(x - 3) / 2.5 = 8 / 2

=> 16 / 4

Simplifying each side of the equation:

(x - 3) / 2.5 = 4

Multiplying both sides by 2.5 to isolate x:

x - 3 = 10

Adding 3 to both sides:

x = 13

Therefore, the value of x is 13.

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Note: The full question is

The polygons are similar but not necessarily drawn to scale, find the value of x.

Bigger polygon has x - 3, 8, and 16

Smaller has 2.5, 2, 4

The side a = 5.12 approximately to two decimal places using the cosine rule.

In trigonometry, the cosines rule relates the lengths of the sides of a triangle to the cosine of one of its angles.

Considering the ∆ABC, line a is calculated with cosine rule as follows;

a² = b² + c² - 2(b)(c)cosA

a² = 7² + 9² - 2(7)(9)cos35°

a² = 49 + 81 - 126(0.8192)

a² = 130 - 103.2132

a² = 26.7868 {take square root of both sides}

a = 5.1756

With proper application of the cosine rule, we can conclude the value of the side a of the triangle ABC is approximately 5.12 to 2 decimal place.

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Answer:

Step-by-step explanation:

To identify the conditions of continuity that are not satisfied if a function has any discontinuities, we need to consider the three conditions for continuity:

1. The function must be defined at the point of interest.

2. The limit of the function as it approaches the point of interest must exist.

3. The value of the function at the point of interest must equal the limit.

If any of these conditions are not met, the function will have a discontinuity at that point.

There are different types of discontinuities, including removable, jump, infinite, and oscillating. Let's briefly discuss the conditions of continuity that are not satisfied for each type:

1. Removable Discontinuity: In this case, the function is undefined at the point of interest. However, the limit exists, and if the value of the function is redefined or removed at that point, the function can become continuous.

2. Jump Discontinuity: The function is defined at the point of interest, and the limit exists from both sides, but the value of the function at the point is different from the limit. There is a sudden "jump" in the function's value.

3. Infinite Discontinuity: The function is defined at the point, but the limit diverges to positive or negative infinity as it approaches the point. There is a vertical asymptote or a vertical gap in the function.

4. Oscillating Discontinuity: The function oscillates or fluctuates infinitely as it approaches the point, failing to approach a specific value. The limit does not exist.

By analyzing the behavior of the function and checking if these continuity conditions are satisfied, we can identify the specific condition(s) that are not met and determine the type of discontinuity present.

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Answer:

website na para sa di marunong mag math haha cutting study value of c is vintamin C = Glox C

The SIR model is a mathematical model that is used to study the spread of infectious diseases in a population. It consists of three compartments: susceptible (S), infectious (I), and recovered (R). The equilibrium solutions of the SIR model can be found by setting the derivatives of the three compartments to zero. There are two equilibrium solutions: the disease-free equilibrium, where the number of infectious individuals is zero, and the endemic equilibrium, where the disease is present in the population. The disease-free equilibrium is stable, meaning that if the initial number of infectious individuals is zero, it will remain zero. The endemic equilibrium is unstable, meaning that if the initial number of infectious individuals is not zero, it will eventually converge to the disease-free equilibrium. Therefore, the equilibrium solutions of the SIR model are important in understanding the dynamics of infectious diseases in a population.

To find the equilibrium solutions of the SIR Model, we need to consider the system of equations representing the model:
1. dS/dt = -βSI
2. dI/dt = βSI - γI
3. dR/dt = γI

At equilibrium, the rates of change are zero, so we have:
dS/dt = 0
dI/dt = 0
dR/dt = 0

From these equations, we can find the equilibrium solutions:
1. -βSI = 0
2. βSI - γI = 0
3. γI = 0

From equation 1, either S=0 or I=0. Similarly, from equation 3, either I=0 or R=0. Now, consider equation 2:
- If I=0, then βSI - γI = 0 simplifies to 0, which is an equilibrium solution (no infection).
- If I≠0, we can divide by I and get βS - γ = 0. Solving for S gives S = γ/β. In this case, the equilibrium solution is when the susceptible and infected populations balance, resulting in a constant rate of infection.

In summary, the SIR Model has two equilibrium solutions:
1. I=0 (no infection)
2. S=γ/β (balance between susceptible and infected populations)

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Answer:

Step-by-step explanation:

y(xy+1)

Answer:

xy^2+y = y(xy + 1)

Step-by-step explanation:

Answer:

There are 9 horses and 7 crows.

2c + 2 = 16 is the equation that represents the situation

Step-by-step explanation:

H for Horses, C for Crows

H = C + 2

C + (C + 2) = 16

2C + 2 = 16

2C = 14

C = 7

H = 7 + 2

H = 9

For the first question, we just need to find how many letters are delivered incorrectly. Since we know that 80% of the letters are delivered to the correct location, it means the the remaining 20% of the letters are delivered to a wrong location.

With this, we can solve for the number of letters that were delivered to the incorrect location through multiplying the total number of letters by 20% or 0.20.

Let x be the number of letters that were delivered incorrectly

There were 86 letters that are delivered to the wrong location on Monday.

For the second part, we need to know the total number of letters delivered given that 80% of it, which is 500 letters, were delivered to the correct location. Since we know that in order to find the percentage of the letters, we need to divide number of delivered letters to the correct location by the total amount of letters.

Let N be the total amount of letters delivered.

Therefore, there was a total of 625 letters delivered on Tuesday.

If the confidence level were increased to 99%, the width of the confidence interval increases, when decreased to 80%, the width of the confidence interval decreases.

A confidence interval provides a range of estimated values for a population parameter's real value. A confidence level is connected to confidence intervals. The width of the confidence interval grows as the confidence level increases. The width of the confidence interval reduces as the confidence level goes down.

Since the margin of error grows as the confidence level does as well, the confidence interval will be bigger. Hence it increases for 99% and decreases for 80%.

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Answer:

-10 is the opposite of 10

Step-by-step explanation:

-10 is the opposite of 10 ,because The sum of a number and its opposite equals to zero.

Step-by-step explanation:

answer is d because in d it is not given a fixed value so d is the answer

Answer: B and D

Step-by-step explanation:

I'm gonna say be because "The highest temperature over three days." has a variable of days. Also D because how much the car weighs can be changed.

The length of a track cant really be changed and 5 feet tall is given.

Answer:

10

Step-by-step explanation:

10×10×10 = 1000

(10³ = 1000)

The slope of the line that divides the region bounded by the parabola \(y=5x-3x^2\)and the x-axis into two regions with equal area is 5.

To find the slope of the line that divides the region into two equal areas, we need to determine the point of intersection between the parabola and the x-axis. Since the line passes through the origin, its equation will be y = mx, where m represents the slope.

Setting the equation of the parabola equal to zero, we find the x-values where the parabola intersects the x-axis. By solving the equation\(5x - 3x^2 = 0\), we get x = 0 and x = 5/3.

To divide the region into two equal areas, the line must pass through the midpoint between these x-values, which is x = 5/6. Plugging this value into the equation of the line, we have y = (5/6)m.

Since the areas on both sides of the line need to be equal, we can set up an equation using definite integrals. By integrating the equation of the parabola from 0 to 5/6 and setting it equal to the integral of the line from 0 to 5/6, we can solve for m. After performing the integration, we find that m = 5.

Therefore, the slope of the line that divides the region into two equal areas is 5.

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Answer:

x = 7

Step-by-step explanation:

QY = 5x

YZ = 18

QZ = 53

Thus:

QY + YZ = QZ (segment addition postulate)

5x + 18 = 53

5x = 53 - 18 (subtraction property of equality)

5x = 35

Divide both sides by 5

x = 7

If we know the parameters a, b, and c in the first equation, we can find the equivalent parameters A, B, and C in the second equation by using the above relationships.

What is the logarithmic equation?

A logarithmic equation is an equation that involves the logarithm of an expression containing a variable. To solve exponential equations, first, see whether you can write both sides of the equation as powers of the same number.

The parameters in the two equations are related as follows:

A = log10(Psat/kPa) / ln(10)

B = b * ln(10)

C = c

T = t + 273.15 (to convert from Celsius to Kelvin)

Therefore, the relationship between the parameters in the two equations is:

A = log10(Psat/kPa) / ln(10)

B = b * ln(10)

C = c

T = t + 273.15

Hence, if we know the parameters a, b, and c in the first equation, we can find the equivalent parameters A, B, and C in the second equation by using the above relationships.

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The trigonometric ratios are given as follows:

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

5 is the hypotenuse length, while for angle A, we have that the sides are given as follows:

Hence the ratios are given as follows:

For angle B, we have that 4 is now the adjacent side, while 3 is the opposite side, hence:

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The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1.

To construct a schedule using the Earliest Deadline First (EDF) scheduling algorithm, we need to consider the execution time, period, and deadline of each task and assign them priorities based on their deadlines. The task with the earliest deadline will be scheduled first. Let's create a schedule for the given task set:

Task T1: Execution time (e) = 2 ns, Period (P) = 5 ns, Deadline (D) = 5 ns

Task T2: Execution time (e) = 4 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

Task T3: Execution time (e) = 7 ns, Period (P) = 7 ns, Deadline (D) = 7 ns

We have a period of 22 ns, and we need to schedule these tasks within that period. Let's start with the task with the earliest deadline:

At time 0 ns: Execute T1 (2 ns)

At time 2 ns: Execute T2 (4 ns)

At time 6 ns: Execute T1 (2 ns)

At time 8 ns: Execute T3 (7 ns)

At time 15 ns: Execute T1 (2 ns)

At time 17 ns: Execute T2 (4 ns)

At time 21 ns: Execute T1 (2 ns)

This completes the execution of all tasks within the given period of 22 ns. The schedule is as follows:

T1 -> T2 -> T1 -> T3 -> T1 -> T2 -> T1

In this schedule, we have followed the EDF algorithm by selecting tasks based on their deadlines. The task with the earliest deadline is always scheduled first to meet the timing requirements of the system.

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To transform the regression equation, you would divide both sides of the equation by the square root of Var(ut), which is σ√(zt). This transformation helps in obtaining the transformed regression coefficients and standard errors that account for the heteroscedasticity in the error term.

When the variance of the error term (ut) is related to a known variable (zt), it implies the presence of heteroscedasticity in the regression model. Heteroscedasticity means that the variability of the error term is not constant across different levels of the independent variables.

To address this issue, we can transform the regression equation by dividing both sides by the square root of the variance of the error term, which is σ√(zt). This transformation is known as the weighted least squares (WLS) estimation.

By dividing both sides of the equation, we can obtain the transformed regression equation with the error term divided by its standard deviation. This transformation accounts for the heteroscedasticity by giving different weights to the observations based on the variability of the error term. It allows for a more appropriate estimation of the regression coefficients and standard errors, as it gives more weight to observations with smaller error variances and less weight to observations with larger error variances.

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Answer:

distance: 77760 meters

Step-by-step explanation:

24 min = 24*60 sec = 1440 sec

54m/s * 1440 s = 77760 m

Answer:

the bus went 77760 m/s in 24 minutes

Step-by-step explanation:

convert 24 minutes to seconds

24 min= 1440 seconds

54x1440= 77760

(i hope this is what you're asking)

The probability of getting Round after spinning a dreidel three times is 0.0156.

To calculate the probability, we need to consider the total number of possible outcomes and the number of favorable outcomes. In this case, since the dreidel has four sides, there are four possible outcomes for each spin. Since we are spinning the dreidel three times, the total number of possible outcomes is 4³ = 64.

To determine the number of favorable outcomes, we need to calculate the number of ways we can get Round in three spins. Since each spin is independent, the probability of getting Round on each spin is 1/4. Therefore, the number of favorable outcomes is 1/4 * 1/4 * 1/4 = 1/64.

Finally, we divide the number of favorable outcomes by the total number of possible outcomes to obtain the probability: 1/64 / 64 = 1/4096 ≈ 0.000244. Rounded to four decimal places, the probability of getting Round after spinning a dreidel three times is 0.0156.

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a)r = R * 〈cos(theta), sin(theta), 0〉where R is the length of the pedal crank. b) F = 〈0, -F₀, 0〉 (downward force). So, the torque τ(theta) = R * F₀ * sin(theta) * k, where k is the unit vector along the rotation axis of the gear. 5a) The z-component of r is always 0, the z-component of the resulting torque vector should also be 0 to maximize the effective torque.

5b) Using this parameterization and the torque formula, the effective torque τ(ϕ, theta) = R * F₀ * sin(theta) * sin(ϕ) * k.
5c) The force vector that yields maximal effective torque is F_max = F₀ * 〈0, sin(θ), 0〉.

To answer your question, let's start with the basic principle of riding a bike. The rider applies force to the pedal, which turns a gear and sets the bike in motion. This situation is governed by three vectors: the force applied by the rider's foot to the pedal, the radius vector from the gear's center to the point on the pedal where the force is being applied, and a unit vector along the rotation axis of the gear.

Now, when riding a bicycle, the pedal crank does not stay in the same position. To express this changing nature, we define theta to be the angle that the pedal crank makes with the vertical, measured clockwise. We need to find two things related to theta:

a) We need to find the effective torque when the pedal crank is at an angle of theta from the vertical.

b) We need to find the effective torque as a function of theta using the same force as in (2).

To compute the effective torque, we can use the formula:

τ = r × F

where τ is the torque, r is the radius vector from the gear's center to the point on the pedal where the force is being applied, and F is the force vector.

Now, we want to determine what direction a force of constant magnitude should be pointed in if we want to maximize the effective torque. To do this, we need to compute the effective torque using an arbitrary force vector F = 〈x, y, z〉 and the unit vector u that we found earlier in (3).

After computing the effective torque, we can conclude that one of the variables x, y, or z must be 0 if we are to maximize the effective torque.

Next, we can use the assumption that the force vector has a constant magnitude of F to parameterize the vector in terms of a variable t. Using this parameterization, we can write the effective torque as a function of t and theta.

Finally, we can use differential calculus to determine what value(s) of t will give us the maximum effective torque. This value of t should be a function of theta. We can write an expression for the force vector that will yield maximal effective torque in terms of t and theta.

In summary, to ride a bike, you need to apply force to the pedal, which turns a gear and sets the bike in motion. The situation is governed by three vectors: the force applied by the rider's foot to the pedal, the radius vector from the gear's center to the point on the pedal where the force is being applied, and a unit vector along the rotation axis of the gear. We can use these vectors to compute the effective torque and determine what direction a force of constant magnitude should be pointed in to maximize the effective torque. We can write an expression for the force vector that will yield maximal effective torque in terms of t and theta.

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