Joni worked 14 hours more than Dominic last month. If Joni worked 7 hours for every 3 hours that Dominic worked, how many hours did they each work?

The degree of the polynomial is 14

The polynomial is given as:

y^2+7x^14-10x^2

Here, we assume that the variable of the polynomial is x

The highest power of x in the polynomial y^2+7x^14-10x^2 is 14

Hence, the degree of the polynomial is 14

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Answer:

-4/3

Step-by-step explanation:

you do change in y over change in x which is -1-3 over -3-(-6)

when you do the calculations you get -4/3

The zeros of the polynomial function are x = -1 and x = 5

From the question, we have the following parameters that can be used in our computation:

y = x⁴ - 4x³ - 4x² - 4x - 5

To calculate the zeros of the polynomial function, we create a graph of the polynomial

The point where the graph intersect with the x-axis are the zeros of the polynomial function

using the above as a guide, we have the following:

Zeros: x = -1 and x = 5

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Answer:eu naõ so grigo não xara

Step-by-step explanation:

The ordered pairs (a, m) that satisfy all the constraints are:

(3, 4)

(4, 4)

(5, 4)

These are the possible combinations of magazine and radio ads that the dog food manufacturer can use to advertise its products within the given budget and constraints.

Here, we have to break down the problem step by step to find the possible combinations of magazine and radio ads that meet the given criteria:

Cost Constraints:

Magazine ad cost: $60 per ad

Radio ad cost: $150 per commercial minute

Total advertising budget: $900

The cost constraint can be represented by the inequality:

60a + 150m ≤ 900

Quantity Constraints:

Magazine ads reach 12,000 people each

Radio ads reach 16,000 people each

The quantity constraint can be represented by the inequality:

12,000a + 16,000m ≤ Total target audience

Minimum Purchase Requirements:

The magazine requires the purchase of at least three ads (a ≥ 3)

The radio station requires the purchase of at least four minutes (m ≥ 4)

Now, let's calculate the target audience reached by each advertising medium:

Target audience reached by magazine ads = 12,000a

Target audience reached by radio ads = 16,000m

To maximize the reach, we want to find the highest possible values of a and m that meet all the constraints.

Let's start by finding the possible values of a and m (integers) that satisfy the minimum purchase requirements:

a = 3, 4, 5, ...

m = 4, 5, 6, ...

Now, we'll check each combination to see if it meets the cost constraint and find the total target audience for each combination. We'll also list the ordered pairs (a, m) that satisfy the constraints:

a = 3, m = 4

Cost: 60(3) + 150(4) = 780 (within the budget)

Total target audience: 12,000(3) + 16,000(4) = 92,000

Ordered pair: (3, 4)

a = 3, m = 5

Cost: 60(3) + 150(5) = 930 (exceeds the budget)

Total target audience: 12,000(3) + 16,000(5) = 116,000

a = 4, m = 4

Cost: 60(4) + 150(4) = 840 (within the budget)

Total target audience: 12,000(4) + 16,000(4) = 112,000

Ordered pair: (4, 4)

a = 4, m = 5

Cost: 60(4) + 150(5) = 990 (exceeds the budget)

Total target audience: 12,000(4) + 16,000(5) = 128,000

a = 5, m = 4

Cost: 60(5) + 150(4) = 900 (within the budget)

Total target audience: 12,000(5) + 16,000(4) = 124,000

Ordered pair: (5, 4)

a = 5, m = 5

Cost: 60(5) + 150(5) = 1050 (exceeds the budget)

Total target audience: 12,000(5) + 16,000(5) = 140,000

Based on the calculations, the ordered pairs (a, m) that satisfy all the constraints are:

(3, 4)

(4, 4)

(5, 4)

These are the possible combinations of magazine and radio ads that the dog food manufacturer can use to advertise its products within the given budget and constraints.

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Answer:

she will be recivining $24.06

Step-by-step explanation:

4x3.99=15.96

2x4.99=9.98

15.96+9.98=25.94

50-25.94=24.06

Of course with out taxes

Answer:

Step-by-step explanation:

18 - 7x = -20.5

18 + 20.5 = 7X

38.5 = 7X

X = 38.5/7

X = 5.5

Answer:

C

Step-by-step explanation:

Step-by-step explanation:

Given the function

f(x, y) = 5 + x ln(xy − 9) at the point (5, 2)

For the function to be differentiable at the given point, the differential of the function with respect to x and y must be continuous at the point.

Fx is the differential of the function with respect to x.

Using product rule to get f(x):

fx = 0 + x(1/(xy-9)y) + ln(xy-9)

fx = xy(1/(xy-9)) + ln(xy-9)

Substitute point (5, 2) into fx

fx = 5(2)(1/5(2)-9) + ln(5(2)-9)

fx = 10(1/(10-9)) + ln(10-9)

fx = 10(1/1) + ln1

fx = 10 + 0

fx = 10

For fy:

fy = 0 + x²(1/(xy-9))+ 0

fy = x²(1/(xy-9))

Substitute point (5, 2) into fy

fy = 5²(1/(5(2)-9))

fy = 25(1/10-9)

fy = 25(1/1)

fy = 25

Next is to calculate f(5,2)

f(5,2) = 5 + 5 ln(2(5) − 9)

f(5,2) = 5 + 5 ln(10− 9)

f(5,2) = 5 + 5 ln1

f(5,2) = 5 + 5(0)

f(5,2) = 5

Since fx ≠ fy, hence the function is not differentiable at the given point

Answer:

Step-by-step explanation:

f(4)=-3(4+3)

do distributive i think, and if that doesnt work then add 4+3 first and then multiply by -3

Answer:

-21

Step-by-step explanation:

4 plus 3 equals 7. 7 times -3 is -21. I could be wrong but I believe it is the correct answer.

Answer:

answer is c

Step-by-step explanation:

Just did it make me brainliest

The value of x is 6.

What is system of linear equations?

A collection of one or more linear equations involving the same variables is known as a system of linear equations in mathematics. For instance, the system of three equations 3x + 2y - z = 1, 2x - 2y + 4z = -2, -x + y - z = 0 has the three variables x, y, and z.

A collection of one or more linear equations involving the same variables is known as a system of linear equations (or linear system) in mathematics.

Graphically, a system of linear equations that has no solution indicates two parallel lines-that is, two lines that have the same slope but different y-intercepts.

To have the same slope, the x-and y-coefficient must be the same.

To get from -2/3 to -8 you multiply by 12, so multiply  -1/2x by 12 as well to yield 6x.

Because the other x-coefficient is a, it must be that a = 6  and (D) is correct.

Note that, even though it is more work, you could also write each equation in slope-intercept form and set the slopes equal to each other to solve for a.

Hence, the value of x is 6.

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The result of  the expression 2 + 5^3 is 127.

To solve the expression 2 + 5^3, you need to follow the order of operations, which is often remembered using the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

In this case, the exponentiation should be performed first.

Step 1: Calculate 5^3

5^3 means raising 5 to the power of 3, which is equivalent to multiplying 5 by itself three times: 5 * 5 * 5 = 125.

Step 2: Add 2 to the result from Step 1.

2 + 125 = 127.

Therefore, the result of 2 + 5^3 is 127.

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Answer:

Given

a=-5

b=2

c=1

i) b - a + c

= 2 -(-5) + 1

=2 + 5 + 1

=8.

ii)2b + 6c

= 2(2) + 6(1)

=4 + 6

=10.

iii) abc = (-5)(2)(1)

= -10.

iv) -2ab/c

= -2(-5)(2)/1

= 20.

Answer:

Use inequalities.

At certain x values.

Step-by-step explanation:

\(3 \leqslant x \leqslant 6\)

\( - \infty < x < \infty \)

\(x = 6\)

The people that would not be sampled would be:

We have to do this by considering the people that would be seen present in the roster of the school. The people that are dropouts as well as homeschooled cannot appear in a school register because they are not students.

The students that are sick and on the trip are all students of the high school so they can be included in the sampling that is being done by the school.

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Given: A room measures 675 sq feet.

Required: To determine how many sq yards of flooring is required for the room.

Explanation: Since 3 feet is equivalent to 1 yard. Hence 9 square feet will be equivalent to 1 square yard.

Thus, in 675 square feet, we have-

Answer:

\(BC=5.1\)

\(B=23^{\circ}\)

\(C=116^{\circ}\)

Step-by-step explanation:

The diagram shows triangle ABC, with two side measures and the included angle.

To find the measure of the third side, we can use the Law of Cosines.

\(\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}\)

In this case, A is the angle, and BC is the side opposite angle A, so:

\(BC^2=AB^2+AC^2-2(AB)(AC) \cos A\)

Substitute the given side lengths and angle in the formula, and solve for BC:

\(BC^2=7^2+3^2-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-42\cos 41^{\circ}\)

\(BC^2=58-42\cos 41^{\circ}\)

\(BC=\sqrt{58-42\cos 41^{\circ}}\)

\(BC=5.12856682...\)

\(BC=5.1\; \sf (nearest\;tenth)\)

Now we have the length of all three sides of the triangle and one of the interior angles, we can use the Law of Sines to find the measures of angles B and C.

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c} $\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

In this case, side BC is opposite angle A, side AC is opposite angle B, and side AB is opposite angle C. Therefore:

\(\dfrac{\sin A}{BC}=\dfrac{\sin B}{AC}=\dfrac{\sin C}{AB}\)

Substitute the values of the sides and angle A into the formula and solve for the remaining angles.

\(\dfrac{\sin 41^{\circ}}{5.12856682...}=\dfrac{\sin B}{3}=\dfrac{\sin C}{7}\)

Therefore:

\(\dfrac{\sin B}{3}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin B=\dfrac{3\sin 41^{\circ}}{5.12856682...}\)

\(B=\sin^{-1}\left(\dfrac{3\sin 41^{\circ}}{5.12856682...}\right)\)

\(B=22.5672442...^{\circ}\)

\(B=23^{\circ}\)

From the diagram, we can see that angle C is obtuse (it measures more than 90° but less than 180°). Therefore, we need to use sin(180° - C):

\(\dfrac{\sin (180^{\circ}-C)}{7}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin (180^{\circ}-C)=\dfrac{7\sin 41^{\circ}}{5.12856682...}\)

\(180^{\circ}-C=\sin^{-1}\left(\dfrac{7\sin 41^{\circ}}{5.12856682...}\right)\)

\(180^{\circ}-C=63.5672442...^{\circ}\)

\(C=180^{\circ}-63.5672442...^{\circ}\)

\(C=116.432755...^{\circ}\)

\(C=116^{\circ}\)

\(\hrulefill\)

Additional notes:

I have used the exact measure of side BC in my calculations for angles B and C. However, the results will be the same (when rounded to the nearest degree), if you use the rounded measure of BC in your angle calculations.

Step-by-step explanation:

0.17039244908......

when 343 is divided by 2013

the answer is

5.86888....

We need a work of 294210 watts to pump the water over the top. \(\blacksquare\)

Since the cross section area of the trough (\(A\)), in square meters, varies with the height of the water (\(h\)), in meters, and considering that pumping system extracts water at constant rate, then the work needed to pump all the water (\(W\)), in joules, is:

\(W = \int\limits^{V_{max}}_0 {p} \, dV\) (1)

Where:

The infinitesimal volume is equivalent to the following expression:

\(dV = A\, dh\) (2)

Since the area is directly proportional to the height of the water, we have the following expression:

\(A = \frac{A_{max}}{H_{max}}\cdot h\) (3)

Where:

In addition, we know that pressure of the water is entirely hydrostatic:

\(p = \rho \cdot g \cdot h\) (4)

Where:

By (2), (3) and (4) in (1):

\(W = \frac{\rho\cdot g\cdot W_{max}\cdot L_{max}}{H_{max}} \int\limits^{H_{max}}_{0} {h^{2}} \, dh\)   (5)

Where:

The resulting expression is:

\(W = \frac{\rho\cdot g\cdot W_{max}\cdot L_{max}\cdot H_{max}^{2}}{3}\)   (5b)

If we know that \(\rho = 1000\,\frac{kg}{m^{3}}\), \(g = 9.807\,\frac{m}{s^{2}}\), \(W_{max} = 2\,m\), \(L_{max} = 5\,m\) and \(H_{max} = 3\,m\), then the work needed to pump the water is:

\(W = \frac{(1000)\cdot (9.807)\cdot (2)\cdot (5)\cdot (3)^{2}}{3}\)

\(W = 294210\,W\)

We need a work of 294210 watts to pump the water over the top. \(\blacksquare\)

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The set of positive integers less than 1000 that are:

a)Divisible by 7 are 142

b)Divisible by 7 but not by 11 are 130

c)Divisible by both 7 and 11 are 12

d)Divisible by either 7 or 11 are 220

e)Divisible by exactly one of 7 and 11 are 220

f)Divisible by neither 7 nor 11 are 780

g)Having distinct digits are 576

h)Having distinct digits and even are 337

We have,

A whole number that is greater than zero is known as positive integer

a)The positive numbers below 1000 that are divisible by 7 are 7, 14, 21, 28,..., 994.

Total terms: 994, divided by 7, plus (n-1)

There are 142 total terms below 1000 that are divisible by 7.

b) The numbers 77, 154, 231, 308, 385, 462, 539, 616, 693, 770, 847, and 924 are all divisible by both 7 and 11.

The total number of integers below 1000 that are divisible by 7 but not 11 therefore equals 142 - (total number of integers divisible by 7 and 11), which means that the total number of integers that fall into this category is 130.

c) The total amount of integers that can be divided by both 7 and 11 equals the total amount of integers that can be divided by 77.

There are 12 total integers below 1000 that can be divided by 77.

d) The total number of integers that can be divided by either 7 or 11 is equal to the sum of the numbers that can be divided by each of those numbers and the number that can be divided by 77.

The total number of integers below 1000 that are divisible by 11 is (11,22,33,...,990). 990 = 11 + (n-1) 11, which equals 90 integers.

Total integers that may be divided by both 7 and 11 are equal to 142 + 90 - 12 = 220.

e) The total number of integers that may be divided by either 7 or 11 perfectly is equal to 142 + 90 - 12 = 220 numbers.

f) The total number of integers that cannot be divided by either 7 or 11 is 1000 - (The total number of integers that can be divided by either 7 or 11), which is 1000 - 220 = 780 numbers.

g)Distinct digits from 1 to 100 = 100 - Total number of integers below 1000 with distinct digits = 1000 - (non-distinct digits) ( 11,22,33,44,55,66,77,88,99,100),

=> Unique digits from 1 to 100 equal 90.

=> The distinct numerals 101 to 200 equal 100. (101,110,111,112,113,114,115,116,117,118,119,121,122,131,133,141,144,151,155,161,166,171,177,181,188,191,199,200),

=> Unique digits from 101 to 200 are: 100 to 28, 72.

=> Unique numbers between 201 and 1000 = 72 x 8 = 576.

h)Different digits and even values equal to 337

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Answer:

24

Step-by-step explanation:

just MultiplMultiply 8 times 3 and 24

Answer:

Step-by-step explanation:

Given ,

Sum of 3 times m = 3m

And 4 times m = 4m

Hence,

Sum is = 3m + 4m = 7m (Ans)

Step-by-step explanation:

850 calls

1000:100=10

1%=10

10×85=850

Discount is the reduction in value. The total number of calls not answered this is 150 calls

Given the following

Total number of calls = 1000 calls

If 15% of those calls were not answered, the total calls that were not answered is given as:

Total call not answered . = 0.15 * 1000

Total call not answered = 150 calls

Hence the total number of calls not answered this is 150 calls

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Answer:

\(x^\frac{8}{3} y^\frac{16}{3}\)

Step-by-step explanation:

Given the expression \((x^4y^8)^\frac{2}{3}\), to simplify the expression using the rational exponents;

Applying one of the law of indices to simplify the expression;

\((a^m)^n = a^{mn}\)

\((x^4y^8)^\frac{2}{3}\\\\= (x^4)^\frac{2}{3} * (y^8)^\frac{2}{3}\\\\= x^{4*\frac{2}{3} } * y^{8*\frac{2}{3} }\\\\= x^\frac{8}{3} * y^\frac{16}{3}\\ \\The \ final \ expression \ will \ be \ x^\frac{8}{3} y^\frac{16}{3}\)

Answer:

It would have to be 3x or 3(x)

0.06 is 10 times 0.006; 0.06 = 10 * 0.006

You can find this by solving 0.06/10 = 0.006

The correct answer is C. It is the graph of f(x) translated 11 units to the left.

The correct answer is:

C. It is the graph of f(x) translated 11 units to the left.

When we have a function of the form g(x) = f(x - a), it represents a horizontal translation of the graph of f(x) by 'a' units to the right if 'a' is positive and to the left if 'a' is negative.

In this case, g(x) = f(x - 11), which means that the graph of f(x) is being translated 11 units to the right. However, the answer options do not include this specific transformation. The closest option is option C, which states that the graph of g(x) is translated 11 units to the left.

The graph of f(x) = x is a straight line passing through the origin with a slope of 1. If we apply the transformation g(x) = f(x - 11), it means that we are shifting the graph of f(x) 11 units to the right. This results in a new function g(x) that has the same shape and slope as f(x), but is shifted to the right by 11 units.

Therefore, the correct answer is C. It is the graph of f(x) translated 11 units to the left.

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The velocity of the particle at times t = a, t = 1, t = 2, and t = 3 are:

a) 4/a^2 m/s, 4 m/s, 1 m/s, 4/9 m/s.

b) The instantaneous velocity of the particle when t=1 is 4 m/s.

To find the velocity, we need to take the derivative of the displacement function with respect to time. The derivative of s = 4/t^2 is ds/dt = -8/t^3. So, the velocity of the particle at time t is given by v = ds/dt = -8/t^3.

For t = a, the velocity is v = -8/a^3 m/s. For t = 1, the velocity is v = -8 m/s. For t = 2, the velocity is v = -2 m/s. For t = 3, the velocity is v = -8/27 m/s.

To find the average velocity during the time period [1, 2], we need to find the displacement at t = 2 and t = 1, then calculate the change in displacement divided by the time interval: (4/4 - 4/1)/1 = 0 cm/s. To find the average velocity during the time period [1, 1.1], we need to find the displacement at t = 1.1 and t = 1, then calculate the change in displacement divided by the time interval: (4/1.1^2 - 4/1)/0.1 = -19.60 cm/s.

To estimate the instantaneous velocity of the particle at t = 1, we can plug in t = 1 to the derivative we found earlier: v = -8/1^3 = -8 m/s. Therefore, the instantaneous velocity of the particle when t = 1 is 4 m/s.

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