John has 10 quarters 11 nickels, 14 dimes and 159 pennies
his bank? He added that money to the $46.76 he had in his
savings account. How much money does John have in his
account now?

Answers

Answer 1

Answer:

Step-by-step explanation:10 quarters is $2.50

11 nickels is $0.55

14 dimes is $1.40

159 pennies is $1.59

Add the sum of all of those ($6.04) to the money that was originally in the bank acc.

6.04+46.76=52.80

Answer:52.80


Related Questions

If im making 12 a hour and get a 10% increase how much more im making

Answers

Answer:

13.2/hour

Step-by-step explanation:

10% of 12 = 1.2

12+1.2=13.2

Question 1 of 5 Which number line shows the solutions to x < 5? OA. -3 -6 -4 -2 0 2 4 6 8 OB. O C. -8 -6 -4 -2 0 2 4 6 8 -8-6-4-2 0 2 4 6 8 OD. 864 2 0 2 4 6 8​

Answers

The number line that shows the solutions of x < 5

B. O

What is number line?

A number line is a visual representation of the real numbers, ordered from left to right, with zero in the middle. It is typically a straight line that extends infinitely in both directions, with evenly spaced markings that represent specific points along the line.

The solution of x < 5 should consist of number less than 5

The inequality used is less than and hence should have values saying less than

Other options has numbers more than 5 such as 6 except option B

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45 to 60 using percent of change unit.

Answers

Answer:

A change from 45 to 60 represents a positive change (increase) of 33.3333333333%

Step-by-step explanation:

Percent change = 60 - 45

45

× 100 = 33.333333333333 % (increase)

Answer:

33.3% increase

Step-by-step explanation:

Percent of Change =

\( \frac{change}{original} \)

The change would be 15:

60 - 45 = 15

So the percent of change would be:

15/45 = 1/3 = 33.3% increase

Hope this helps! Brainliest would be appreciated!

An investment of R1 500 000, made two years ago, has increased in value to R1 700 000, and has delivered R40 000 worth of dividends over the two years. What is the return on the investment? 1.6% 2.16% 3.28% 4.33%​

Answers

Two years ago, an investment of R1 500000 has increased to R1 700000 and has delivered R40 000 worth of dividends over the two years. Then the return on investment would be 16%.

We can use the following formula to calculate ROI:

ROI = (gain from investment - cost of investment) / cost of investment

where, gain from investment is the total value of the investment (including dividends), and cost of investment is the initial investment.

Using the values given in the question, we can calculate the ROI as:

ROI = ((R1,700,000 + R40,000) - R1,500,000) / R1,500,000 = R240,000 / R1,500,000

ROI = 0.16 or 16%

Therefore, the return on the investment is 16%.

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Let T be the three dimensional solid bounded from above by the half cylinder described by the equation z = √(9 - y) and from below the cy plane for 0 ≤ x ≤ 2 and -3 ≤ y ≤ 3. Let S be the closed surface that completely surrounds T. Let F➜ = (x,y,y+z). Use the Divergence Theorem to calculate ∫∫S F • n dS

Answers

Using the Divergence Theorem, we get the flux of F across the closed surface S is π/2 (27√2 - 27).

To apply the Divergence Theorem, we will first compute the divergence of F as follows -

div(F) = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z

= 1 + 1 + 1

= 3

Now we will calculate the flux of F across the closed surface S that completely surrounds T. By the Divergence Theorem, this is equal to the triple integral of the divergence of F over the region T and is given by -

∫∫S F•n dS = ∭T div(F) dV

We can describe the region T using cylindrical coordinates:

0 ≤ r ≤ 2

-π/2 ≤ θ ≤ π/2

0 ≤ z ≤ √(9 - r sin θ)

The bounds on r and θ come from the fact that the half cylinder is contained within the plane x = 2, and the plane y = ±3. The bounds on z come from the equation of the half cylinder.

Now we can write the triple integral as follows -

∭T div(F) dV = ∫0^2 ∫-π/2^π/2 ∫0^√(9 - r sin θ) 3 r dz dθ dr

Evaluating this integral, we get,

∭T div(F) dV = π/2 (27√2 - 27)

Therefore, the flux of F across the closed surface S is π/2 (27√2 - 27).

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2 3/4 of 500grams in step by step calculator

Answers

Answer:

To calculate 2 3/4 of 500 grams, follow these steps:

1. Convert the mixed number to an improper fraction:

2 3/4 = (2 x 4 + 3)/4 = 11/4

2. Multiply the improper fraction by 500:

11/4 x 500 = (11 x 500)/4 = 2,750/4

3. Simplify the fraction by dividing the numerator and denominator by their greatest common factor, which is 2:

2,750/4 = (2 x 1,375)/(2 x 2) = 1,375/2

Therefore, 2 3/4 of 500 grams is equal to 1,375/2 grams or 687.5 grams.

Step-by-step explanation:

Bryan invests $6500 in two different accounts. The first account paid 11 %, the second account paid 7 % in interest. At the end of the first year he had earned $519 in interest. How much was in each account?

$ at 11 %

$ at 7 %

Answers

Bryan invested $1600 in the first account (earning 11% interest) and $4900 (6500 - 1600) in the second account (earning 7% interest).

Let's assume that Bryan invested an amount of x dollars in the first account, which earns 11% interest, and (6500 - x) dollars in the second account, which earns 7% interest.

The interest earned from the first account can be calculated as 0.11x, and the interest earned from the second account can be calculated as 0.07(6500 - x).

According to the problem, the total interest earned after one year is $519. So we can set up the equation:

0.11x + 0.07(6500 - x) = 519

Simplifying the equation:

0.11x + 455 - 0.07x = 519

0.04x + 455 = 519

0.04x = 64

x = 64 / 0.04

x = 1600

Therefore, Bryan invested $1600 in the first account (earning 11% interest) and $4900 (6500 - 1600) in the second account (earning 7% interest).

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Write an expression for the sequence of operations described below.
raise 3 to the 9th power, then add the result to j
Do not simplify any part of the expression.

Answers

An expression for given sequence of operations is: j + 3^9

In this question, we need to write an expression for the sequence of operations described below.

raise 3 to the 9th power, then add the result to j

Consider the part of given statement,

raise 3 to the 9th power

We write this as: 3^9

then we add this result to j.

So, we get an expression: 3^9 + j

Therefore, an expression for given sequence of operations is: j + 3^9

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Which scale is equivalent iS to 1 cm to 1 km?
1 to 1000
10,000 to
1 to 100,000
100,000 to
1 to 1,000,000

Answers

The scale which is equivalent to 1 cm to 1 km is 1 to 100,000. Hence 3rd option is correct

Cm: The SI prefix centi stands for a factor of 1/100, making a centimetre a length unit that is equal to one-tenth of a metre. In the now-outdated centimetre-gram-second system of units, the centimetre served as the fundamental unit of length.

Km: A kilometre is a measurement unit for both length and distance. It is a metric unit of measurement. Additionally, miles, which are equivalent to one kilometre, can be used to describe the distance. Although miles and kilometres are equivalent in size, they have different values.

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The school sold 300 tickets to the theatre performance. They sold adult tickets for $9 each and student tickets for $6 each. They made a total of $2, 190. How many students were in attendance?
I need help please, I need to show work and it is due tonight.

Answers

Answer:

Your answer is.....

170 students

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

Help me light get brainless ( math )

Help me light get brainless ( math )

Answers

Since a circle measures 360 degrees, 1/360 of it would be one degree, a very "skinny" angle,so it is less than 90 degrees, (B)

A circle, when using degrees, have 360 degrees. 1/360 of a circle can be calculated by multiplying the two numbers.

\(\frac{1}{360}*360=1\)

Therefore, the answer for the question is

1/360 of a circle measure 1 degree

Genesis is older than Dylan. Their ages are consecutive integers. Find Genesis's age if
the product of their ages is 110.

(ill give brainliest )

Answers

Answer:

Dylan is 10 years old, and Genesis is 11.

Step-by-step explanation:

If Genesis and Dylan's age are consecutive integers, and Genesis is older, we can represent their ages as:

Dylan's age: x

Genesis' age: x+1

This would mean Genesis is a year older than Dylan.

The product of their ages is 110.

We can write an equation:

x×(x+1)=110

x²+x=110 (Distribute x)

x²+x-110=0 (Move 110 to the other side)

You can solve this by the quadratic equation, by factoring or by completing the square

I'll solve it by the quadratic equation:

We must first find the coefficients a, b and c, and then plug it into the formula.

\(x = \frac{ - 1 + - \sqrt{ {1}^{2} - 4 \times 1 \times - 110} }{2 \times 1} \\ x = \frac{ - 1 + - \sqrt{1 + 440} }{2} \\ x = \frac{ - 1 + - 21}{2} \)

Since we have a ± symbol, we get 2 real solutions, x1 and x2.

x=-1±21/2

x1=-1+21/2

x1=20/2

x1=10

x2=-1-21/2

x2=-22/2

x2=-11

Since their age can't be negative, x2 can't be a solution, so Dylan's age must be 10, and Genesis' age must be 11.

Hope this helps, and let me know if you need help with another method to solve this problem!

Find the exact value of ..
Х
15
6

Find the exact value of ..156

Answers

Is the answer ur looking for 25

midpoint of (-10,11) and (5,-4)

Answers

Answer:

4

Step-by-step explanation:

3 miles is the same as how many kilometers?
Hint: 1 mi≈ 1.6 km
Round your answer to the nearest tenth.

Answers

Answer: 4.8

Step-by-step explanation:

The sum of two numbers is 40. One number is 4 times as large as the other. What are the numbers?

Answers

Answer:

4x+x=40

5x+40

x=8

8, 32

Step-by-step explanation:

Answer:

8 and 32 are the numbers

Step-by-step explanation:

4x + x = 40

4x + x= 5x

5x + 40

40/5= 8

x= 8

and

40-8= 32

x= 32

Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Test the claim that the book had no effect on their scores.Use α=0.05. Assume that the distribution is normally distributed. Student 1 2 3 4 5 6 7 8 9 Scores before reading book 72 0 86 0 850 88 0 86 0 710 85 0 1200 95 0 Scores after reading book 74 0 86 0 840 92 0 89 0 720 84 0 1240 97 0 Nine students took the SAT. Their scores are listed below. Later on, they read a book on test preparation and retook the SAT. Their new scores are listed below. Test the claim that the book had no effect on their scores. Use α = 0.05. Assume that the distribution is normally distributed. Student 1 2 3 4 5 6 7 8 9 Scores before reading book 72 0 86 0 850 88 0 86 0 710 85 0 1200 95 0 Scores after reading book 74 0 86 0 840 92 0 89 0 720 84 0 1240 97 0

Answers

Answer:

t= 0.4933

t ≥ t ( 0.025 ,8 ) = 2.306

Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0: ud= 0 Ha: ud≠0

The significance level is set at ∝= 0.05

The test statistic under H0 is

t= d`/ sd/√n

which has t distribution with n-1 degrees of freedom

The critical region is t ≥ t ( 0.025 ,8 ) = 2.306

Computations

Student       Scores before      Scores after    Difference           d²

                        reading book                    ( after minus before)

1                          720                   740             20                       400

2                        860                   860              0                           0

3                        850                   840             -10                       100

4                        880                   920             40                       1600

5                        860                   890             30                        900

6                        710                    720              10                         100

7                       850                    840              -10                       100

8                      1200                  1240             40                        1600

9                      950                    970              20                           40

∑                    6930                  8020           140                         4840

d`= ∑d/n= 140/9= 15.566

sd²= 1/8( 4840- 140²/9) = 1/8 (4840 - 2177.778) = 2662.22/8= 332.775

sd= 18.2422

t= 3/ 18.2422/ √9

t= 0.4933

Since the calculated value of t= 0.4933 is less than t ( 0.025 ,8 ) = 2.306 therefore we accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the book had no effect on their scores.

2
1
-1
-2
Determine the period.
2 4
6 8 10 12 14
Acellus

21-1-2Determine the period.2 46 8 10 12 14Acellus

Answers

According to the information we can infer that the period of the graph is 8.

How to determine the period of the graph?

To determine the period of the graph we have to consider that the period of a grah is the distance between rigdes. So, in this case we have to count what is the difference between each rigde.

In this case, the distance between rigdes is 8 units because the first is located in the line 1 an the second is located in the line 9. So we can conclude that the period of the graph is 8.

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A study was conducted to determine if there was a difference in the driving ability of students from West University and East University by sending a survey to a sample of 100 students at both universities. Of the 100 sampled from West University, 15 reported they were involved in a car accident within the past year. Of the 100 randomly sampled students from East University, 12 students reported they were involved in a car accident within the past year. True or False. The difference in driving abilities at the two universities is statistically significant at the .05 significance level.

Answers

Answer:

False

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \(\mu = p\) and standard deviation \(s = \sqrt{\frac{p(1-p)}{n}}\)

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

West University:

15 out of 100, so:

\(p_W = \frac{15}{100} = 0.15\)

\(s_W = \sqrt{\frac{0.15*0.85}{100}} = 0.0357\)

East University:

12 out of 100, so:

\(p_E = \frac{12}{100} = 0.12\)

\(s_E = \sqrt{\frac{0.12*0.88}{100}} = 0.0325\)

Test the difference in driving abilities at the two universities:

At the null hypothesis we test if there is no difference, that is, the subtraction of the proportions is 0, so:

\(H_0: p_W - p_E = 0\)

At the alternative hypothesis, we test if there is a difference, that is, if the subtraction of the proportions is different of 0. So

\(H_1: p_W - p_E \neq 0\)

The test statistic is:

\(z = \frac{X - \mu}{s}\)

In which X is the sample mean, \(\mu\) is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that \(\mu = 0\)

From the two samples:

\(X = p_W - p_E = 0.15 - 0.12 = 0.03\)

\(s = \sqrt{s_W^2+s_E^2} = \sqrt{0.0357^2+0.0325^2} = 0.0483\)

Value of the test statistic:

\(z = \frac{X - \mu}{s}\)

\(z = \frac{0.03 - 0}{0.0483}\)

\(z = 0.62\)

P-value of the test and decision:

The p-value of the test is the probability that the proportions differ by at least 0.03, which is P(|z| > 0.62), that is, 2 multiplied by the p-value of z = -0.62.

Looking at the z-table, z = -0.62 has a p-value of 0.2676.

2*0.2676 = 0.5352.

The p-value of the test is 0.5352 > 0.05, which means that the difference in driving is not statistically significant at the .05 significance level, and thus the answer is False.

In the image below, the inscribed angles of T and S intercept the same arc.

If arc YZ has a measure of 70 degrees, what is the sum of measures of the inscribed angles at T and S?

In the image below, the inscribed angles of T and S intercept the same arc.If arc YZ has a measure of

Answers

The measure of each inscribed angle at T and S is 72.5 degrees, and the sum of their measures is: 145 degrees

What is inscribed angle ?

An inscribed angle is an angle formed by two chords of a circle that have a common endpoint on the circle. The vertex of the inscribed angle is on the circle, and the sides of the angle intersect the circle at two distinct points.

There are some important properties of inscribed angles:

The measure of an inscribed angle is half the measure of the arc it intercepts. This is called the inscribed angle theorem.Two inscribed angles that intercept the same arc are equal in measure.If one side of an inscribed angle is a diameter of the circle, then the angle is a right angle.

According to the question:
If the inscribed angles of T and S intercept the same arc, then they must be equal in measure. Let's call the measure of each angle x.

Since the sum of the measures of the angles in a triangle is 180 degrees, we can set up an equation to find the measure of the third angle in triangle TSY:

x + x + measure of angle YTS = 180 degrees

Simplifying the equation, we get:

2x + measure of angle YTS = 180 degrees

But we know that the measure of angle YTS is equal to half the measure of arc YZ, since it is an inscribed angle intercepting the same arc. So:

measure of angle YTS = 1/2 * measure of arc YZ = 1/2 * 70 degrees = 35 degrees

Substituting this value into our equation, we get:

2x + 35 degrees = 180 degrees

Solving for x, we get:

2x = 145 degrees

x = 72.5 degrees

Therefore, the measure of each inscribed angle at T and S is 72.5 degrees, and the sum of their measures is:

72.5 degrees + 72.5 degrees = 145 degrees

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There is a straight road between town A and town B of length 130 km.
Maxi travels from town A to town B.
Pippa travels from town B to town A.
Both travel at a constant speed of 40 km/h.
Maxi leaves 30 minutes before Pippa.
Work out how far from town A they will be when they pass each other

Answers

They will be when they pass each other at 44 4/9 mins.

This is a classic question on Speed, time, & distance.

1. When time traveled in each segment is constant, then average speed is simple mean of speeds.

2. When distance traveled in each segment is constant, then average speed is reciprocal of simple mean of reciprocal of speeds. It is basically called Harmonic mean.

So this question falls in the category of 2.

=> So, average speed = Reciprocal of mean of reciprocals of 40 & 50.

=> Average speed = Reciprocal of mean of 1/40 & 1/50.

=> Average speed = Reciprocal of (1/40 + 1/50)/2

= Reciprocal of (5+4)/400

= 44 4/9 mins

Hence, they will be when they pass each other at 44 4/9 mins.

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5- 2 4/5 what's the answer mates and it's not middle school it's forth grade(4th grade)​

Answers

Answer:

2 1/5

Step-by-step explanation:

First you make both fractions into 5 becomes 25/5. 2 4/5 becomes 14/5. Then you would just subtract 25/5 - 14/5 = 11/5 then make it a mixed number 2 1/5.

Answer:

It would be 2.2 as a decimal, or 11/5 (2 1/5)

Step-by-step explanation:

It's quite simple.

Start by turning 2 4/5 into an improper fraction, then turn 5 into a fraction. By doing that you should get 25/5 - 14/5. Subtract to get 11/5.

hope this helped!

What is the following quotient? ^3sqrt60/^3sqrt20

Answers

The quotient ^3√60 / ^3√20 simplifies to 2.

To simplify the quotient ^3√60 / ^3√20, we can apply the rules of exponents for radicals.

Let's start by simplifying the individual cube roots:

^3√60 = ^3√(2^2 × 3 × 5) = 2^2 × ^3√(3 × 5) = 2^2 × ^3√(15).

Similarly,

^3√20 = ^3√(2^2 × 5) = 2 × ^3√5.

Now we can rewrite the original quotient using these simplified forms:

^3√60 / ^3√20 = (2^2 × ^3√15) / (2 × ^3√5).

Since we have the same cube root in the numerator and denominator, we can cancel them out:

^3√60 / ^3√20 = (2^2 × ^3√15) / (2 × ^3√5) = 2^2 / 2 = 4 / 2 = 2.

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The difference between the complement of 63 
degree and supplement of 72 degree is​

Answers

Answer:

9

Step-by-step explanation:

27 is the compliment of 63

108 is the suppliment of 72

72 - 63 is the difference aka 9

Algebra Question
Let v = (-7,6,-6) and w = (-5,-3,-6) be vectors in R^3. Find the orthogonal projection of v onto w.
Answer:
Projection on w: (-54/14, -159/70, -159/35)

I have the correct answer but I don't know how they got it.

Answers

The orthogonal projection of vector v onto vector w in R^3 is (-54/14, -159/70, -159/35).

To find the orthogonal projection of v onto w, we need to calculate the scalar projection of v onto w and multiply it by the unit vector of w. The scalar projection of v onto w is given by the formula:

proj_w(v) = (v⋅w) / (w⋅w) * w

where ⋅ denotes the dot product.

Calculating the dot product of v and w:

v⋅w = (-7)(-5) + (6)(-3) + (-6)(-6) = 35 + (-18) + 36 = 53

Calculating the dot product of w with itself:

w⋅w = (-5)(-5) + (-3)(-3) + (-6)(-6) = 25 + 9 + 36 = 70

Now, substituting these values into the formula, we have:

proj_w(v) = (53/70) * (-5,-3,-6) = (-54/14, -159/70, -159/35)

Therefore, the orthogonal projection of v onto w is (-54/14, -159/70, -159/35).

In simpler terms, the orthogonal projection of v onto w can be thought of as the vector that represents the shadow of v when it is cast onto the line defined by w. It is calculated by finding the component of v that aligns with w and multiplying it by the direction of w. The resulting vector (-54/14, -159/70, -159/35) lies on the line defined by w and represents the closest point to v along that line.

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Use the magnitudes​ (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the​ range, variance, and standard deviation. If another​ value, 7.50​, is added to those listed in the data​ set, do the measures of variation change​ much?3.28
2.78.
2.20
2.76
2.47
2.70
3.62
2.84
2.78
3.29
1.76
4.65
3.23
2.35
2.00
3.90
2.41
2.90
2.65
2.30
2.82
2.79
2.42
3.42
2.32
1.49
2.41
2.46
2.46
2.67
2.42
2.79
2.66
2.73
2.44

2.82
1.96
1.69
2.54

2.44
3.42
3.94
1.61
2.86
1.61
2.58
3.97
2.48
2.44
1.81
2.19
2.43
3.01
2.93
2.34
2.01
3.02
2.77
3.83
2.93
2.09
1.83
2.36
2.38
3.48
3.45
1.55
2.52
1.48
2.22
3.08
2.27
3.25
1.99
1.90
2.39
2.96
2.56
1.50
2.17
2.33
1.91
2.72
2.92
1.82
3.61
2.71
1.43
3.59
3.15
2.55
1.52
1.42
2.84
2.84
2.17
1.67
3.19
1.39
1.71
2.39
1.13
2.33
2.46
1.79
1.98
3.00
1.92
2.44
1.85
2.25
2.34
3.19
4.00
2.09
1.49
2.31
2.30
2.56
2.54

Answers

Answer:

2.90

Step-by-step explanation:

im not completly shous though

helppp need aswer soon
A cylinder has a radius of 3 cm and a height of 6 cm. Use the formula V cylinder. Round your answer to the nearest whole number (cubic centimeter). = Tr² h and Show 3.14 all work for to estimate the volume of the for credit.​

Answers

Answer:

170 cm³

Step-by-step explanation:

V = πr²h

= 3.14 * (3)² * 6

= 3.14 * 9 * 6

= 169.56 cm³

= 170 cm³

The map shows an obstacle course at a school fair. The units are given in yards.
What is the total distance of
the obstacle course?
? yards
Start
(-40, -10)
Tire
Race
(-40, -30)
Finish
(10, 20)
Monkey
Bars
(40,20)
Rope
Climb
(40,-30)

Answers

The total distance of the obstacle course can be calculated by finding the distance between each pair of consecutive points and adding them up. The distance between two points (x1, y1) and (x2, y2) can be calculated using the formula: distance = sqrt((x2 - x1)^2 + (y2 - y1)^2).

Using this formula, we can calculate the distances between each pair of consecutive points as follows:

Start to Tire Race: distance = sqrt((-40 - (-40))^2 + (-30 - (-10))^2) = 20 yards

Tire Race to Rope Climb: distance = sqrt((40 - (-40))^2 + (-30 - (-30))^2) = 80 yards

Rope Climb to Monkey Bars: distance = sqrt((40 - 40)^2 + (20 - (-30))^2) = 50 yards

Monkey Bars to Finish: distance = sqrt((10 - 40)^2 + (20 - 20)^2) = 30 yards

Adding up all these distances, we get a total distance of 20 + 80 + 50 + 30 = 180 yards for the obstacle course.

A local talent is selling underground CD’s to get his rap career off the ground.

Each crate contains 60 blank CD’s.

Each crate cost $35.

How much should he sell his CD’s to make a profit of $85?

Answers

Answer:

He should sell his CD's for $2.

Step-by-step explanation:

Each crate contains 60 blank CD’s and each crate cost $35.

This means that he will pay $35 for 60 CD's.

How much should he sell his CD’s to make a profit of $85?

He will sell each of the 60 CD's for x, which means that his earnings will be of 60x.

Profit: Earnings - Cost = 60x - 35

To make a profit of $85

\(60x - 35 = 85\)

\(60x = 120\)

\(x = \frac{120}{60}\)

\(x = 2\)

He should sell his CD's for $2.

Mr. Smith has a maximum of $50 to spend at a museum. A ticket to the museum costs $7. He
can spend p dollars to buy other things at the museum. Which inequality can be used to find
the possible values for p?

Answers

Answer:

Step-by-step explanation:

After buying the ticket, the amount with him = 50 - 7 = 43

p ≤ 50 - 7

p ≤ 43

Answer:

p≤ 43

Step-by-step explanation:

50-7=43

so now Mr.smith will have $43 to spend

p is less than or equal to 43

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