Answer:
permanent set
.............
Johann squeezes a bagel too hard that it is not able to return to its original shape. The bagel has Plastic deformation.
What is Plastic Deformation?Plasticity, also referred to as plastic deformation, is the property of a solid material to undergo permanent deformation, a non-reversible change in shape in response to applied forces.
It is a concept used in physics and materials science. For instance, plasticity is demonstrated when a solid piece of metal is bent or pounded into a new shape because the material itself undergoes lasting modifications. Engineering professionals use the term yield to describe the change from elastic to plastic behavior.
Most materials, especially metals, soils, rocks, concrete, and foams, show signs of plastic deformation.
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Camden is in the business of manufacturing phones. He must pay a daily fixed cost to
rent the building and equipment, and also pays a cost per phone produced for
materials and labor. The labor and materials cost $125 for each phone manufactured,
and the total cost of producing 4 phones in a day would be $1100. Write an equation
for the function C(p), representing total cost, in dollars, of producing p phones in a
given day.
The function of the cost would be Cp = 600 + 125N.
Camden is having a fixed cost that needs to be paid, an that is
rent to building and equipment's + cost per phone produced for materials and labor cost
Also the labor and material cost is $125
so, we can write that
Total cost (Cp) = R + N x 125
where N is the number of phone produced and R is the rent per day
Also,
1100 = R + 4 x 125
so we can get,
R = 1100 - 500
R = 600
Now we can put this value in the first equation, we can get
Cp = 600 + N x 125
hence the cost function is Cp = 600 + 125N.
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The sides of a rectangle are 6.01 meters and 12 meters. Taking the significant figures into account, what is the area of the rectangle? A. 70 square meters B. 72 square meters C. 72.00 square meters D. 72.1 square meters
Answer:
D. 72.1 m^2
Explanation:
6.01m x 12m = 72.12 m^2
A . 2 m/s^2
B . 30 m/s^2
C . 30 m/s
D . 0.5 m/s
Answer:
C-30m/s that my answer
Could someone please help me with this project?? I would greatly appreciate it!!
In this experiment, use the steps of the scientific method to explore using a “coffee cup” calorimeter to measure the rate of heat loss for several substances and determine which of the substances is the best insulator. You will be testing the insulating capabilities of three types of fabric and the control will be air. The three types of fabric are:
Test Sample 1: 52% cotton/48% poly fabric
Test Sample 2: 100% acrylic fabric
Test Sample 3: 80% cotton/20% poly fabric
For the control, and each test sample, you will be measuring the amount of heat lost by the water in the calorimeter over 6 minutes, taking the temperature every 30 seconds. Be sure to record your data on your data sheet . View the animation to complete this experiment.
Answering the following questions will help you to focus on the outcomes of these experiments:
1. Construct a graph of temperature versus time. Put temperature on the y-axis and time on the x-axis.
2. Graph all three sets of data on the same graph. Use a different colored pencil for each test material. Provide a key on the graph relating the pencil color to the test material.
3. Calculate the change in temperature from start to finish for the air and each of the samples and record on your data sheet.
4. Which water sample lost the least amount of heat energy over the 6-minute time interval?
5. Was the rate of heat loss constant during each experiment? How can you tell?
6. Which material was the best insulator? Which material was the least effective insulator?
Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.
1. According to your data, was your hypothesis correct? (Be sure to refer to your data and graphs when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to guide your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
4. Explain why the design of the bird's nest in the picture provides good insulation for the eggs.
Submit your data sheet, graph, and answers to all of the questions in the essay box below.
Answer:Sure, I can help you with this project. Here is an outline for your experiment report:
I. Introduction
Briefly describe the purpose and goals of the experiment, which is to determine the insulating capabilities of three types of fabric and air using a coffee cup calorimeter.
Explain the scientific method and how it will be used to conduct the experiment.
II. Materials and Methods
List the materials used in the experiment, including the coffee cup calorimeter, water, thermometer, and the three types of fabric.
Describe the procedure used to test each material, including the control of air.
Explain how the data was collected and recorded, including the measurement of temperature at 30-second intervals over a 6-minute time interval.
III. Results
Present the data in a graph of temperature versus time, with temperature on the y-axis and time on the x-axis.
Graph all three sets of data on the same graph and use a different color for each test material, with a key on the graph relating the color to the test material.
Calculate the change in temperature from start to finish for each material, and record the data on the data sheet.
Analyze the data and answer the questions posed in the experiment prompt, including which water sample lost the least amount of heat energy over the 6-minute time interval and which material was the best insulator.
IV. Discussion
Discuss the findings of the experiment and summarize the conclusions that can be drawn from the data.
Answer the questions posed in the experiment prompt, including whether the hypothesis was correct and whether the rate of heat loss was constant during each experiment.
Summarize any difficulties or problems encountered during the experiment and suggest modifications to the procedure to avoid these problems.
Explain why the design of the bird's nest in the picture provides good insulation for the eggs.
V. Conclusion
Summarize the key findings and conclusions of the experiment.
Discuss the implications of the results and suggest possible applications or further research.
Conclude with a final statement that reflects on the importance of the experiment and what was learned.
VI. Data Sheet and Graph
Attach the data sheet and graph as appendices to the report.
I hope this outline helps you in writing your experiment report. Let me know if you need any further assistance!
Explanation:
On Earth, an average person's vertical jump is 0.40 m. What is it on the Moon? The gravitational acceleration near the surface of the Moon is 1.62 m/s2. Assume that the person leaves the surfaces at the same speed.
The average person's vertical jump on the Moon would be 0.65 m.
The gravitational acceleration near the surface of the Moon is 1.62 m/s2, which is about one sixth the gravitational acceleration on Earth.
As a result, an average person's vertical jump on the Moon would be less than on Earth.
To calculate the vertical jump on the Moon, we need to use the formula h = 1/2 x g x t2.
This equation is used to calculate the height h (in meters) that an object will reach when thrown into the air, given the gravitational acceleration g (in m/s2) and the time t (in seconds) it takes to reach the peak of the jump.
Since the gravitational acceleration on the Moon is 1.62 m/s2, and the time taken to reach the peak of the jump is the same (assume 0.5 s), then h = 0.5 x 1.62 x (0.5)2, which is 0.65 m.
Therefore, an average person's vertical jump on the Moon would be 0.65 m.
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A dog sleigh driver prepared for her race. Her sleigh was loaded with equipment, but on snow and ice, the dogs moved the heavy sled. Each dog pulled with a force of 600 N.
During the race, she came to an area of grass and dirt instead snow. The sled slowed to a stop.
The driver said, "There must be something wrong with one of the dogs. One of them is pulling with a force of less than 600 N.
How would you respond to the dog sled driver?
The dog slowed down and stop because of the high magnitude of friction opposing the motion due to the nature of the grass and dirt.
What is Friction ?Friction is a force that opposes motion. It depends on the nature of the surface in contact with the moving object.
Given that a dog sleigh driver prepared for her race. Her sleigh was loaded with equipment, but on snow and ice, the dogs moved the heavy sled with a force of 600 N each. On the snow and ice, the opposing force known as friction is small.
During the race, she came to an area of grass and dirt instead snow. The sled slowed to a stop because of the high magnitude of the opposing force or frictional force due to the nature of the grass and dirt.
Therefore, there is nothing wrong with one of the dogs. One of them is pulling with a net force of less than 600 N because of drastic increase in frictional force due to the nature of grass and dirt.
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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
Answer:
Explanation:
is this marked??
(a). The car's average velocity between t = 1.0s to t = 1.5s will be - \(1\;m/s\)
(b). The car's acceleration at t = 1.5s will be - \(0.4\;m/s^{2}\)
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
The car's average velocity (in m/s) in the interval between -t = 1.0 s to t = 1.5 s.
The car's acceleration at t = 1.5 s.Determining whether car's speed increasing or decreasing with time.What is Acceleration?The rate of change of velocity with respect to time is called Acceleration. Mathematically -
\($a=\frac{dv}{dt}\)
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
\($v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s\)
PART - B
Velocity at t = 1.5 s will be -
\($v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s\)
The car's acceleration at t = 1.5s will be -
\($a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}\)
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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Is it possible for both the pressure and volume of a monatomic ideal gas to change without causing the internal energy of the gas to change?
Explain how this could occur.
Yes, it is possible for both the pressure and volume of a monatomic ideal gas to change without causing the internal energy of the gas to change. This occurs when the gas undergoes an adiabatic process, meaning there is no heat transfer between the gas and its surroundings.
In an adiabatic process, the change in internal energy (ΔU) is solely dependent on the work done on or by the gas (W). According to the first law of thermodynamics, ΔU = Q + W, where Q is the heat transfer. Since Q = 0 in an adiabatic process, ΔU = W.
For the internal energy of the gas to remain constant (ΔU = 0), the work done on or by the gas must also be zero. This can be achieved through a specific path in the pressure-volume (PV) diagram, where the gas expands and does work on its surroundings, followed by compression, with the surroundings doing an equal amount of work on the gas. The net work done over this process will be zero, ensuring the internal energy remains unchanged.
In summary, it is possible for both the pressure and volume of a monatomic ideal gas to change without affecting its internal energy by undergoing an adiabatic process with zero net work done.
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An object of mass 10 kg has a momentum of 15 kg m/s. Find the average force required to accelerate the object to 10 m/s over 20 seconds.
Answer:
Force = 4.25 Newton
Explanation:
Given the following data;
Mass = 10 kg
Momentum = 15 Kgm/s
Time, t = 20 seconds
Final velocity, V = 10 m/s
To find the average force required;
First of all, we would determine the initial velocity of the object.
Momentum = mass * velocity
15 = 10 * velocity
Velocity = 15/10
Velocity = 1.5 m/s
Next, we would determine the acceleration of the object by using the first equation of motion;
V = U + at
10 = 1.5 + a*20
10 - 1.5 = 20a
8.5 = 20a
Acceleration, a = 8.5/20
Acceleration, a = 0.425 m/s²
Lastly, we would find the average force by using the formula;
Force = mass * acceleration
Force = 10 * 0.425
Force = 4.25 Newton
5.) The classical model of the hydrogen atom has the electron revolving in a circular orbit of radius and kinetic energy 1 (e) 2 41€r a) Calculate the fractional energy radiated per revolution, t/T,
Given:The radius of the circular orbit of the electron is r.The kinetic energy of the electron is 1/2mv². The kinetic energy of the electron is 1/2(9.109 × 10⁻³¹)(2.18 × 10⁶)².The classical model of the hydrogen atom has the electron revolving in a circular orbit of radius and kinetic energy 1(e)2 41€r.
Formula used: The fractional energy radiated per revolution is t/T where T is the period of revolution of the electron around the nucleus. T is given by T = 2πr/v, where v is the speed of the electron which is given by v = (2KE/m)¹/².The radius of the circular orbit of the electron is:r = (4πε₀ℏ²/mee²) × n²= (4π × 8.85 × 10⁻¹² × (6.626 × 10⁻³⁴/2π)²/(9.109 × 10⁻³¹) × (1.602 × 10⁻¹⁹)²) × 1²r = 5.292 × 10⁻¹¹m.
The kinetic energy of the electron is:KE = (1/2)mv²= (1/2)(9.109 × 10⁻³¹)(2.18 × 10⁶)²KE = 9.11 × 10⁻¹⁹J.t = 1/3.In this problem, the main answer is:Fractional energy radiated per revolution is t/T = 1/3.The explanation is:We know that the kinetic energy of the electron is 9.11 × 10⁻¹⁹J. The radius of the circular orbit of the electron is 5.292 × 10⁻¹¹m.t = Fractional energy radiated per revolution = ΔE/E0 = ΔKE/KE = 9.11 × 10⁻¹⁹/27.2 × 1.6 × 10⁻¹⁹ = 1/3.T = 2πr/v = 2π × 5.292 × 10⁻¹¹/(2.18 × 10⁶) = 7.5 × 10⁻¹⁶s.t/T = 1/3.
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how then does a light turn on almost instantly when the switch is flipped?
Light travels at the speed of 186,000 miles a second.
How does information travel during transcription?
a) RNA to amino acid
b) DNA to amino acid
c) DNA to RNA
d) RNA to DNA
5. In which image below is the most work being wasted as heat?
A. Image A
B. Image B
C. Image C
D. Image d
Answer:
C
Explanation:
The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
What will be the speed of the rock?Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference. The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
Nuclear energy is a useful source of power but has disadvantages. The disadvantage of nuclear energy is it produces dangerous waste.
Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference
From the second equation of motion:
solving above we get:
t = 0s or t = 8.16s, t =0 seconds is neglected since it represents the initial position which is the same as the final position at t = 8.16s
So, the rock takes 8.16 seconds to return to the release point.
Therefore, The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
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a claim is a set of interacting parts forming a complex whole true or fasle.
Answer:
false
Explanation i have none
are same side exterior angles congruent or supplementary?
The same-side exterior angles are not congruent, they are supplementary. The same side exterior angles are formed and they have a sum of 180 degrees.
What is meant by congruence?Congruent refers to having the same precise size and shape. Even if we flip, turn, or rotate the forms, their shape and size need to remain constant. If it is possible to superimpose one geometric figure onto the other such that they correspond throughout, then the two are said to be congruent, or to be in the relation of congruence.
In general relativity, a congruence (more precisely, a congruence of curves) is the collection of integral curves of a (never vanishing) vector field in a four-dimensional Lorentzian manifold that is used to physically represent spacetime.
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The equipment releases a balloon from a point that is a small distance above the surface of the planet. The atmosphere at the surface of this planet has a density of
Make an appropriate calculation and then predict and explain the direction of any motion of the balloon. Show your working.
The inflated balloon has a mass of 80 g and a volume of 0.3m ^ 3 .
0.35kg / (m ^ 3)
The balloon will go upward with acceleration of 3.1 m/s².
What is buoyant force?The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force. Upthrust is another name for this upward thrust. A body submerged partially or completely in a fluid appears to lose weight, or to be lighter, due to the buoyant force.
Given that
Mass of the balloon = 80 g = 0.080 kg.
Volume of the balloon = 0.3 m³.
So, weight of the balloon = 0.080 × 9.8 N = 0.784 N.
Buoyant force acting on the balloon = 0.3 × 0.35 × 9.8 N = 1.029 N.
Hence, net upward force acting on the balloon is = 1.029 N - 0.784 N = 0.248 N.
So, upward acceleration of the balloon = 0.248/0.080 m/s² = 3.1 m/s².
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The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radius of 1.30 m. The toroid has 900 turns of largediameter wire, each of which carries a current of 14.0 kA. Find the magnitude of the magnetic field inside the toroid along (a) the inner radius and (b) the outer radius.
Answer:
(a) 11.3 T
(b) 6.09 T
Explanation:
Current, I = 14 kA = 14000 A
number of turns, N = 900
inner radius, r = 0.7 m
outer radius, R = 1.3 m
The magnetic field due to a circular coil is given by
\(B = \frac{\mu o}{4\pi}\times \frac{2 N\pi I}{R}\)
(a) The magnetic field due to the inner radius is
\(B = 10^{-7}\times \frac{2\times 900\times 3.14\times 14000}{0.7}\\\\B = 11.3 T\)
(b) The magnetic field due to the outer radius is
\(B = 10^{-7}\times \frac{2\times 900\times 3.14\times 14000}{1.3}\\\\B = 6.09 T\)
Austin kicks a soccer ball with an initial velocity of 18.0 m/s at an angle of 35.0°. What are the horizontal and vertical components of the initial velocity? Round your answers to the nearest tenth. vix = m/s viy = m/s
Answer:
(vix, viy) = (14.7 m/s, 10.3 m/s)
Explanation:
The velocities of interest are ...
(vix, viy) = (vi)(cos(35°), sin(35°)) = (18 m/s)(cos(35°), sin(35°))
(vix, viy) = (14.7 m/s, 10.3 m/s)
Answer:
First one = 14.7
Second one = 10.3
Explanation:
EDGE
Calculate the density of so3 gas at 25oc and 715 torr?.
The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.
We want to calculate the density of SO₃ gas at 25 °C and 715 Torr.
What is density?Density (ρ) is the ratio of the mass to the volume of a substance.
If we assume ideal behavior, we can calculate the density of SO₃ using the following expression.
ρ = P × M / R × T
where,
P is the pressure of SO₃.M is the molar mass of SO₃.R is the ideal gas constant.T is the absolute temperature of SO₃.To apply this formula, we need to convert 25 °C to Kelvin using the following expression.
K = °C + 273.15 = 25 °C + 273.15 = 298 K
The density of SO₃ is:
ρ = P × M / R × T
ρ = 715 Torr × (80.06 g/mol) / (62.4 mmHg.L/mol.K) × 298 K = 3.08 g/L
The density of SO₃ gas at 25 °C and 715 Torr is 3.08 g/L.
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For the mirror configuration below, the angle of incidence for the going towards the mirror on the right is 15 degrees. What is the angle of reflection for the light ray leaving the mirror on the bottom
Answer:
Thus, the angle of reflection is 15 degrees.
Explanation:
Angle of incidence, i = 15 degrees
The angle of incidence is the angle between the normal to the mirror and the incident ray, the angle of reflection is the angle between the reflected ray and the normal to the mirror.
According to the laws of reflection, the angle of incidence is equal to the angle of reflection.
Thus, the angle of reflection = angle of incidence = 15 degrees
Which form of radiation has the longest wavelength.
Answer:
Radio Waves
Explanation:
It's all about the Electromagnetic Spectrum.
From longest to smallest Wavelength :
Radio waves, microwave, infrared, visible, ultraviolet, x-ray, and lastly gamma-ray radiation.
Additional :
since Wavelength is inversely proportional to frequency, the highest Wavelength will have the lowest frequency.
How much force is necessary to stretch a spring 0. 5 m when the spring constant is 190 N/m? N.
Statement:
A force is necessary to stretch a spring 0.5 m when the spring constant is 190 N/m.
To find out:
The force required to stretch the spring.
Solution:
Spring constant (k) = 190 N/m.Displacement (x) = 0.5 mLet the force necessary to stretch the spring be F.We know the formula of spring force, i.e., F = kx.Putting the values in the above formula, we getF = 190 N/m × 0.5 mor, F = 95 NSo, the force required to stretch the spring is 95 N.Answer:
95 N
Hope you could understand.
If you have any query, feel free to ask.
an object is placed 42 cm in front of a lens. the lens creates an image 10 cm from the lens on the same side as the object. find the following:a. the focal lengthb. the type of lensc. the magnification of the imaged.indicate whether the image is real or virtual and upright or invertede. the power of this lens
An object is placed 42 cm in front of a lens. the lens creates an image 10 cm from the lens on the same side as the object. a) f = 21 cm, b) the lens is a convex lens and the image is virtual.
a. The focal length of the lens can be found using the lens equation, 1/f = 1/d0 + 1/di, where f is the focal length of the lens, d0 is the distance between the object and the lens, and di is the distance between the image and the lens. Plugging in the given values, we get:
1/f = 1/42 cm + 1/10 cm
1/f = 0.0476 cm^-1
f = 21 cm
b. Since the focal length is positive, the lens is a convex lens.
c. The magnification of the image can be found using the equation m = -di/d0, where m is the magnification of the image. Plugging in the given values, we get:
m = -di/d0 = -10 cm/42 cm = -0.238
Since the magnification is negative, the image is inverted.
d. Since the image is on the same side of the lens as the object, the image is virtual. Since the image is inverted, it is also upright.
e. The power of the lens can be found using the formula P = 1/f, where P is the power of the lens in diopters (D). Plugging in the value of focal length we obtained earlier, we get:
P = 1/f = 1/21 cm = 0.048 D
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Ohm's Law relates the following:
A) current, mass, and time
B) volts, amperes and resistance
C) resistivity, area and length
D) resistance, current, and power
Ohm's Law relates the following: volts, amperes, and resistance. Ohm's Law relates the following: volts, amperes, and resistance.
Ohm's Law states that the current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor. The formula for Ohm's Law is: V = IR.
In simpler terms, this means that if you increase the voltage, the current will also increase, but if you increase the resistance, the current will decrease. It can be mathematically expressed as I = V/R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms. This relationship is extremely important in understanding and designing electrical circuits. I hope this long answer helps to explain Ohm's Law!
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A catapult is a device that throws heavy stones. The stone sits in a basket at the end of an arm. The arm moves fast, and the stone is launched toward the target. What type of force does the catapult apply to the stone
Elastic force is the type of force which the catapult applies to the stone.
What is a Catapult?This is a launching device which is composed of rubber and used in the study of projectile motion.
The type of force present in a rubber is elastic force which is applied as a result of pressure on it when the individual launches the stone towards the required target.
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The catapult applies elastic force to the stone which is converted to kinetic energy of the flying stone.
What Elastic potential energy?Elastic potential energy is the type of energy that is stored in an elastic material.
The catapult is an elastic material that converts elastic energy into kinetic energy of flying stone.
Thus, the catapult applies elastic force to the stone which is converted to kinetic energy of the flying stone.
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The sun produces energy from matter in its core through the process of
Answer here
Answer:
Explanation:
nuclear fusion?
PLEASE HELP Due Soon!
When the motion energy of an object changes, energy is being transferred. How do you know that's true?
Answer:
Explanation:
When objects collide, energy can be transferred from one object to another, thereby changing their motion. In such collisions, some energy is typically also transferred to the surrounding air; as a result, the air gets heated and sound is produced.
What is the resistance of resistor R1?
(1 point)
3.00 Ω
200 Ω
7.50 Ω
5.00 Ω
Answer: The answer is 3.00 Ω
Explanation:you join R1 up with R2.
if jupiter was about the size of a basketball, which planet(s) would be about the size of a baseball?
If Jupiter was about the size of a basketball, Venus would be about the size of a baseball.
If Jupiter was about the size of a basketball (approximately 9.4 inches or 24 centimeters in diameter), then a planet about the size of a baseball (approximately 2.9 inches or 7.4 centimeters in diameter) would be roughly 1/3 the diameter of Jupiter.
There are four planets in our solar system that are smaller than Jupiter and roughly 1/3 its diameter: Saturn, Uranus, Neptune, and Venus. Of these, Venus is the closest in size to a baseball, with a diameter of approximately 7,520 miles (12,104 kilometers), making it slightly larger than a baseball but still in the same size range.
So, if Jupiter was the size of a basketball, Venus would be the planet in our solar system that is closest in size to a baseball. Saturn, Uranus, and Neptune would be slightly larger, but still much smaller than Jupiter.
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vectors ????⃗ and ????⃗ lie in the xy ‑plane. vector ????⃗ has a magnitude of 19.6 and is at an angle of 125.5∘ counterclockwise from the x ‑axis. vector ????⃗ has a magnitude of 29.1 and is 235.3∘ from the x ‑axis. resolve ????⃗ and ????⃗ into components, and express using ???????????? unit vectors,
(a) The x and y component of the vectors is -11.38 units and 15.96 units respectively.
(b) The x and y component of the vectors is 29.1 units and -23.92 units respectively.
What is the x and y component of the vectors?(a) The x and y component of the vectors is calculated as follows;
vector = 19.6 units and angle = 125.5⁰
x = 19.6 x cos(125.5)
x = -11.38 units
y = 19.6 x sin(125.5)
y = 15.96 units
(b) The x and y component of the vectors is calculated as follows;
vector = 29.1 units and angle = 235.3⁰
x = 29.1 x cos(235.3)
x = -16.57 units
y = 29.1 x sin(235.3)
y = -23.92 units
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