Joe has an experiment with three different conditions (0mg, 50mg, & 100mg of caffeine). He is measuring how long a person then stays up. Why is a One-Way ANOVA preferable over doing three independent samples t tests? Your answer should clearly address alpha level.

Answer:

Step-by-step explanation:

if I’m correct please mark Brainalist

From the properties of a Rhombus;

Opposite angles of a rhombus are equal. The adjacent angles of a rhombus are supplementary, i.e. adds up to 180 degrees.

If one of the angles of a rhombus is 120 degrees, and sum of the adjacent angles is 180 degrees, then, the adjacent angle will be 60 degrees (180-120=60)

If one of the angles of a rhombus is 30 degrees, then, the adjacent angle will be 150 degrees (180-30 =150)

Thus, the sum of 120 and 130 is not supplementary and definitely can not be adjacent

Hence, it is not possible hope this helps !

No, it is not possible for a rhombus to have an angle of 120° and an angle of 30°.

" Rhombus is a quadrilateral whose opposite side are parallel and congruent. Opposite angles are congruent. Adjacent angles are supplementary."

According to the question,

Given,

Measure of the angle are 120° and 30°.

If we consider both the angles are opposite \(120 \neq 30\)

then as per property of congruent angle in rhombus,  it is not correct.

For adjacent angle, \(120 + 30 \neq 180\) they are not supplementary.

Again it is not true for rhombus.

Hence, it is not possible for a rhombus to have an angle of 120° and an angle of 30°.

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Answer:

p - 14.5 = 53

Step-by-step explanation:

The original price is p.

The discounted price is $14.50 less than p, or $14.50 subtracted from p. The discounted price is p - 14.5.

The discounted price is $53

Equation:

p - 14.5 = 53

(a) We have shown that there exists an element b ∈ B that is an upper bound for A.

(b) The statement in part (a) is not always the case if we only assume sup A ≤ sup B.

(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.

Proof:
1. By definition, sup A is the least upper bound for set A, and sup B is the least upper bound for set B.
2. Since sup A < sup B, there must be a value between sup A and sup B.
3. Let's call this value x, where sup A < x < sup B.
4. Now, since x < sup B and sup B is the least upper bound of set B, there must be an element b ∈ B such that b > x (otherwise, x would be the least upper bound for B, which contradicts the definition of sup B).
5. Since x > sup A and b > x, it follows that b > sup A.
6. As sup A is an upper bound for A, it implies that b is also an upper bound for A (b > sup A ≥ every element in A).

Thus, we have shown that there exists an element b ∈ B that is an upper bound for A.

(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.

Example:
Let A = {1, 2, 3} and B = {3, 4, 5}.
Here, sup A = 3 and sup B = 5. We can see that sup A ≤ sup B, but there is no element b ∈ B that is an upper bound for A, as the smallest element in B (3) is equal to the largest element in A, but not greater than it.

This example shows that the statement in part (a) is not always the case if we only assume sup A ≤ sup B.

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Answer:

37

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

You can use absolute value to solve this. l-12l+l25l=12+25=37

Absolute value is the distance from 0.

Answer:

By the math, x = 10°

Here's my issue though, the top angle is x - 15°. That would be an angle of -5° which is impossible.

Step-by-step explanation:

x - 15 + 2x + 25 + 180 - 4x = 180°

combine like terms:

3x - 4x + 190 = 180°

-x = -10°

x = 10°

Answer:

12 inches

Step-by-step explanation:

Hope this helps.. Sorry its late (There should be an attachment)

Answer: 240 miles in 2 hours

Step-by-step explanation:

we know the car is traveling 60 km per half hour (30 minutes)

so to find km per hour, multiply both by 2.

the rate of speed is 120 miles per 60 minutes (1 hour)

multiply 120 mph by the 2 hours given = 240 miles in 2 hours

Answer:

240 km in 2 hours

Step-by-step explanation:

If the car travels 60 km in 30 minutes, then its speed can be calculated as follows:

Speed = distance ÷ time

Speed = 60 km ÷ (30 minutes ÷ 60) = 120 km/hour

Since the car is traveling at a constant speed, we can use the formula:

Distance = Speed × Time

To find how far the car will travel in 2 hours, we can substitute the values we have found:

Distance = Speed × Time

Distance = 120 km/hour × 2 hours

Distance = 240 km

Therefore, the car will travel 240 km in 2 hours if it continues at the same constant speed.

Answer:

16.4

Step-by-step explanation:

If it is asking for the tenth it will be the 1st one after the point and you round it to the next one.

The expression that represents the correct translation of the phrase is 8x = x + 2

An equation is an expression that shows the relationship between two or more numbers and variables.

Independent variables represent function inputs that do not depend on other values, while dependent variables represent function outputs that depends on other values.

Let x represent the unknown number, the product of 8 and a number is equal to the number increased by 2, hence:

8 * x = x + 2

8x = x + 2

The expression that represents the correct translation of the phrase is 8x = x + 2

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Answer:

x = -2

-2(-2^2) + 4(-2)

-2(4) + -8

6 students can be seated in a row of 6 chairs in 121 ways.

Given,

Number of students = 6

Number of chairs = 6

We have to find the number of ways the students can be seated in a row.

Here,

Jack insists on sitting in the first chair.

So, 1 way of sitting for jack.

Next,

5 students and 5 chairs are there.

So they can sit in;

5! = 120 ways

Therefore,

Total number of way of sitting is 120 + 1 = 121 ways.

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The increase in the number of products is the same for each additional

employee in the plant.

Responses:

Part A:

Part B:

Part C:

The given data

Part A: From the given table, as the number of employees in the plant increases from 0 to 200, the number of products produced increases from 10 to 1,260

Therefore, an increase in the number of employees, increases the number of products produced, which indicates that there is a correlation between the number of employees in the plant and the number of produced yearly.

Part B:

The common difference between the number of products produced is a constant, which is 160 - 10 = 150

The slope of the line joining the first and last point is given as follows;

The y-intercept is given as the number of products produced when the number of employees is 0, which is 10.

The function of the data is a linear function.

Where;

y = The number of products produced yearly

x = The number of employees in the factory

Part C:

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Answer:

(x + 3)² + (y - 6)² = 9

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 3, 6 ) and r = 3 , then

(x - (- 3 )² + (y - 6)² = 3² , that is

(x + 3)² + (y - 6)² = 9

The probability of at least 33 male lambs is approximately 74.2%, which rounds to 25.9%  to the nearest tenth of a percent.

To solve this problem, we can use the binomial distribution formula:

P(X≥33) = 1 - P(X<33)

where X is the number of male lambs born out of 60, and P(X<33) is the probability that less than 33 male lambs are born.

The probability of getting a male lamb is 0.5, assuming that males and females are equally probable. So, the probability of getting exactly x male lambs out of 60 is:

P(X=x) = (60 choose x) * 0.5^60

where (60 choose x) is the number of ways to choose x items out of 60, which is calculated by the binomial coefficient formula:

(60 choose x) = 60! / (x! * (60-x)!)

Using a binomial distribution calculator or a spreadsheet program like Excel, we can find the probability of getting less than 33 male lambs:

P(X<33) = sum(P(X=x), x=0 to 32) ≈ 0.0459

Therefore, the probability of getting at least 33 male lambs is:

P(X≥33) = 1 - P(X<33) ≈ 1 - 0.0459 ≈ 0.9541

To convert this to a percentage, we can multiply by 100 and round to the nearest tenth:

P(X≥33) ≈ 95.4%

So, the answer is not one of the options given. The closest option is D) 25.9%, which is the probability of getting exactly 30 male lambs.

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Let's denote the ages of the two remaining men as x and x + 3 (since one is 3 years older than the other).

We know that the average age of 6 men is 35 years. So, the sum of their ages is 6 * 35 = 210 years.

We also know that the average age of four of them is 32 years. So, the sum of their ages is 4 * 32 = 128 years.

To find the sum of the ages of the two remaining men, we subtract the sum of the ages of the four men from the sum of the ages of all six men:

210 - 128 = 82 years.

Now, we can set up an equation to solve for the ages of the remaining two men:

x + (x + 3) = 82.

Combining like terms, we get:

2x + 3 = 82.

Subtracting 3 from both sides:

2x = 79.

Dividing both sides by 2:

x = 39.5.

So, one of the remaining men is 39.5 years old, and the other is 39.5 + 3 = 42.5 years old.

The moment of inertia of a cube with mass m = 0.500kg and side lengths s = 0. 030m about an axis which is both normal (perpendicular) to and through the center of a face of the cube is I = 2.205x10^-4 kg/m^2.

Here Given mass m = 0.5 kg

And side length = 0.03 m

Moment of inertia I = mass x radius of rotation squared

I = mr^2

In this case, the radius of rotation is about an axis which is both normal (perpendicular) to and through the center of a face of the cube.

Calculating from the dimensions of the the box, the radius of rotation r = 0.021 m

Therefore, I = 0.5 x 0.021^2 = 2.205x10^-4 kg/m^2

Hence the answer is the moment of inertia of a cube with mass m = 0.500kg and side lengths s = 0. 030m about an axis which is both normal (perpendicular) to and through the center of a face of the cube is I = 2.205x10^-4 kg/m^2.

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According to the graph:

There is a local minimum at (2,2)

Local maximum at (-1,4) and (5,5)

The function is decreasing in the interval:

The function is increasing in the interval:

Answer:

Local minimum: (2,2)

Local maximum: (-1,4) and (5,5)

Decreasing: [-1, 2] and [5, ∞]

Increasing: [ - ∞, - 1] and [2, 5]

Answer:

\(x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}\)

Step-by-step explanation:

Biquadratic Equations

Solve:

\(x^4 + 3x^2 - 18 = 0\)

The biquadratic equations are equations of degree 4 without the terms of degree 1 and 3.

Solving such equations requires to express the equation as a second-degree equation with \(x^2\) as the variable.

Rewriting the equation:

\((x^2)^2 + 3(x^2) - 18 = 0\)

The quadratic equation can be factored as:

\((x^2+6)(x^2-3)=0\)

It leads to two equations:

\(x^2+6=0\)

\(x^2-3=0\)

The first equation has imaginary roots. Solving for x:

\(x^2=-6\)

\(x=\pm\sqrt{-6}\)

\(x_1=\mathbf{i}\sqrt{6}\)

\(x_2=-\mathbf{i}\sqrt{6}\)

Where

\(\mathbf{i}=\sqrt{-1}\)

The second equation has two real roots:

\(x^2-3=0\)

\(x^2=3\)

\(x=\pm\sqrt{3}\)

\(x_3=\sqrt{3}\)

\(x_4=-\sqrt{3}\)

The roots are:

\(\mathbf{x_1=\mathbf{i}\sqrt{6},\ x_2=-\mathbf{i}\sqrt{6},\ x_3=\sqrt{3},\ x_4=-\sqrt{3}}\)

The answer is A. The normal distribution in its standardized form has a mean of 0 and a standard deviation of 1. This means that the distribution is centered around 0, and the spread of the data is determined by the standard deviation of 1. This is useful in statistical analysis because it allows us to compare data from different distributions on a standardized scale.

The normal distribution is a continuous probability distribution that is often used in statistical analysis. It is characterized by a bell-shaped curve and is symmetrical around its mean. In its standardized form, the normal distribution has been transformed to have a mean of 0 and a standard deviation of 1. This transformation is achieved by subtracting the mean of the distribution from each data point and dividing by the standard deviation. This standardization allows us to compare data from different normal distributions on a standardized scale.

The normal distribution has many properties that make it useful in statistical analysis. It is often used as a model for many real-world phenomena, such as the distribution of human height, IQ scores, and many others. The normal distribution is also useful because it is well understood and has many mathematical properties that make it easy to work with.

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The solution for the formula υ² = υ₀² + 2a(x - x₀) is x = (υ² - υ₀² + 2ax₀) / 2a

Given,

The formula ; υ² = υ₀² + 2a(x - x₀)

We have to solve this formula for getting the value of x.

That is,

υ² = υ₀² + 2a(x - x₀)

Then,

υ² = υ₀² + 2ax - 2ax₀

Here,

υ² - υ₀² = 2ax - 2ax₀

So,

υ² - υ₀² + 2ax₀ = 2ax

Therefore,

x = (υ² - υ₀² + 2ax₀) / 2a

That is,

The solution for the formula υ² = υ₀² + 2a(x - x₀) is x = (υ² - υ₀² + 2ax₀) / 2a

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Answer:

6m,8m,10m

Step-by-step explanation:

6m,8m,10m represent side lengths of a right triangle.

Proof :

for right angled triangle,

p^2 + b^2 = h ^ 2

6^2 + 8^2 = 10^2

36 + 64 = 100

100= 100{True}

proved

Answer:6m,8m,10m

Step-by-step explanation:

Answer: 2 + 0.7 + 0.06

Step-by-step explanation:

Expanded form is a method of writing numbers in such a way that the mathematics value of their individual digits would be shown.

Therefore, 2.76 inches in expanded form would be:

= 2 + 0.7 + 0.06

The above shows the units value, tenths value and the hundredths value of the number.

Answer:

Step-by-step explanation:

Given data:

Home price = $450,000

Down payment = 5%.

Mortgage time = 30 years.

Mortgage fixed rate = 7%.

Solution:

Down payments

= 5% x $450,000

= $22,500.

Amount to be financed

= Home price – down payment

= $450,000 – $22,500

= $427,500.

Monthly Mortgage payment

P* r * ( 1 + r ) ^n / [ ( 1 + r ) ^n ]

= $427,500 * 0.0058 * ( 1 + 0.0058 ) ^360 / [(1 + 0.0058 )^360 ]

= $2844.75

Answer:

b=312

g=396

you can use substitution or elimination

Step-by-step explanation:

(b+g=708)10

(15b+10g=8640)1

(10b+10g=7080)-

(15b+10g=8640)

10b-15b=-1560

-5b=-1560

divide both sides by -5

b=312

then substitute

b+g=708

312+g=708

g=708-312

g=396

so b=312

g=396

The Largest Positive Offset value  that can be used in the BR instruction is 255.

The Largest Negative Offset value  that can be used in the BR instruction is -256.

What is BR instruction?

The short form of BR instruction is termed as Branch instruction.  Instead of executing the instruction in a defined order depending on the  constraint, BR Instruction is used to begin executing different instructions

Here, in BR instruction

The range of the maximum values for the integers is -255 to 255, so the largest positive offset is 255 and the largest negative offset -256

The Largest Positive Offset value  that can be used in the BR instruction is 255.

The Largest Negative Offset value  that can be used in the BR instruction is -256.

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Answer:

23-22i

Step-by-step explanation:

The equivalent expression of (-45 - 22i) + 2(5 - 3i)(5 + 3i) is 23 - 22i

The complex expression is given as:

(-45 - 22i) + 2(5 - 3i)(5 + 3i)

Apply the difference of two squares on the expression

(-45 - 22i) + 2(5^2 - (3i)^2)

Evaluate the squares

(-45 - 22i) + 2(25 + 9)

Expand the bracket

-45 - 22i + 68

Evaluate the like terms

23 - 22i

Hence, the equivalent expression of (-45 - 22i) + 2(5 - 3i)(5 + 3i) is 23 - 22i

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Answer:

P = 8000\((1 + .04)^{t}\)   where t is the number of years

Step-by-step explanation:

Answer:

Question 1

The greatest number of treasure chest you can fill = 23

Step-by-step explanation:

Gold coins = 46

Diamonds = 115

Rubies = 184

To determine the greatest number of treasure chests you can fill, find the highest common factors of 46, 115 and 184

46 = 1, 2, 23, 46.

125 = 1, 5, 23, 115

184 = 1,2,4,8,23,46,92,184

The highest common factors of 46, 115 and 184 is 23

The greatest number of treasure chest you can fill = 23

Number of gold coins in each chest = 46/23

= 2

Number of diamonds in each chest = 115 / 23

= 5

Number of rubies in each chest = 184 /23

= 8

Question 2

Nickels = 246

Dimes = 312

Quarters = 204

Find the highest common factor of 246, 312, 204

246 = 1, 2, 3, 6, 41, 82, 123, 246

312 = 1, 2, 3, 4, 6, 8, 12, 13, 24, 26, 39, 52, 78, 104, 156, 312.

204 = 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102, 204

The highest common factor of 246, 312, 204 is 6

How many are in your group?

6 members

There are 6 members in your group that each person got the same exact amount of each coin with no coins remaining.

Number of nickels each person receive = 246 / 6

= 41

Number of dimes each person receive = 312 / 6

= 52

Number of quarters each person receive = 204 / 6

= 34