It costs $20 to enter an amusement park and $0.50 to go on each ride. You have $24. How many rides are you able to go on?
Answer:
8 rides
Step-by-step explanation:
20 + .50x = 24
-20 -20
.50x = 4
/.50 /.50
x = 8
Answer:
8
Step-by-step explanation:
If you have $24 and you buy a $20 ticket to get in, you are left with four dollars.
Since each ride is $0.50 and that is half a dollar, you can multiply four times two. This gives you eight.
Therefore, you can ride 8 rides :)
i need some help please
Which three ordered pairs describe points that are 5 units away from P(-1,2)?
A. (1,5)
B. (-6,7)
C. (-1,-3)
D. (4,2)
E. (2,-2)
The ordered pair that is 5 units away is (-1, -3)
What is a line?
A line is a distance between two points.
Analysis:
see attached file.
In conclusion, the ordered pair is (-1, -3)
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no links or files, worth 25 points, please help!
Answer:
6
Step-by-step explanation:
2 to the power of 1 is 2, anything to the power of one is the original number itself. 3*2=6
Answer:
3x2^1 is equivalent to 6
Step-by-step explanation:
3x2^1=
3x(2)=
6
A small hotel in central London has 8 rooms. Based on data collected over the last five years, it was estimated that the probability a room is occupied on any particular "weekend" night (Saturday and Sunday) is 0.75. This is the probability of success. On any particular "weekend" night, a hotel is only occupied (Success) or not occupied (Failure). There are no other possibilities. Required: What is the probability that at least 4 of the 7 hotel rooms are occupied on any weekend night? Note: Show all your calculations in well laid-out Excel spreadsheet tables with clear headings and include formulas. Give your answers correct to 3 decimal places.
Based on the given data, the probability of a room being occupied on any particular weekend night is 0.75. To calculate the probability that at least 4 out of the 7 rooms are occupied on a weekend night, we can use the binomial probability formula. By summing up the probabilities for 4, 5, 6, and 7 occupied rooms, we find that the probability is approximately 0.923.
To calculate the probability, we can use the binomial probability formula, which states that the probability of getting exactly k successes in n independent Bernoulli trials, each with a probability p of success, is given by the formula:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
In this case, we want to find the probability of at least 4 out of 7 rooms being occupied on a weekend night. We can calculate this by summing up the probabilities of getting 4, 5, 6, and 7 occupied rooms.
For 4 occupied rooms:
P(X = 4) = (7 choose 4) * 0.75^4 * (1 - 0.75)^(7 - 4) = 0.339
For 5 occupied rooms:
P(X = 5) = (7 choose 5) * 0.75^5 * (1 - 0.75)^(7 - 5) = 0.395
For 6 occupied rooms:
P(X = 6) = (7 choose 6) * 0.75^6 * (1 - 0.75)^(7 - 6) = 0.266
For 7 occupied rooms:
P(X = 7) = (7 choose 7) * 0.75^7 * (1 - 0.75)^(7 - 7) = 0.122
To find the probability of at least 4 occupied rooms, we sum up the probabilities for 4, 5, 6, and 7 occupied rooms:
P(X >= 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.339 + 0.395 + 0.266 + 0.122 = 0.923
Therefore, the probability that at least 4 out of the 7 hotel rooms are occupied on any weekend night is approximately 0.923, or 92.3% when rounded to three decimal places.
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Based on the given data, the probability of a room being occupied on any particular weekend night is 0.75.
To calculate the probability that at least 4 out of the 7 rooms are occupied on a weekend night, we can use the binomial probability formula. By summing up the probabilities for 4, 5, 6, and 7 occupied rooms, we find that the probability is approximately 0.923.
To calculate the probability, we can use the binomial probability formula, which states that the probability of getting exactly k successes in n independent Bernoulli trials, each with a probability p of success, is given by the formula:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
In this case, we want to find the probability of at least 4 out of 7 rooms being occupied on a weekend night. We can calculate this by summing up the probabilities of getting 4, 5, 6, and 7 occupied rooms. For 4 occupied rooms:
P(X = 4) = (7 choose 4) * 0.75^4 * (1 - 0.75)^(7 - 4) = 0.339
For 5 occupied rooms:
P(X = 5) = (7 choose 5) * 0.75^5 * (1 - 0.75)^(7 - 5) = 0.395
For 6 occupied rooms:
P(X = 6) = (7 choose 6) * 0.75^6 * (1 - 0.75)^(7 - 6) = 0.266
For 7 occupied rooms:
P(X = 7) = (7 choose 7) * 0.75^7 * (1 - 0.75)^(7 - 7) = 0.122
To find the probability of at least 4 occupied rooms, we sum up the probabilities for 4, 5, 6, and 7 occupied rooms:
P(X >= 4) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.339 + 0.395 + 0.266 + 0.122 = 0.923. Therefore, the probability that at least 4 out of the 7 hotel rooms are occupied on any weekend night is approximately 0.923, or 92.3% when rounded to three decimal places.
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14/3 = 7y solve for y and simplify your answer as much as possible
Answer:
2/3 = y
Step-by-step explanation:
to solve you got to cancel out the 7
so 7y/7.
whatever you do to one side, you do to the other.
14/3 ÷ 7 = 7y/7
14/3 ÷ 7 = 0.6666... = 2/3 = y
The following tree heights were recorded on a school campus:
61, 72, 84, 88, 77, 67, 76, 79, 63, 79, 69, 70, 86, 78, 82, 82, 80, 73, 87, 90, 73, 76, 79, 71, 75, 79, 76, 83, 84, 87, 72, 81, 89, 74, 77, 78, 81, 84
A science teacher wants to choose a data display that will highlight every height. Which display will present the information in this way?
Box plot
Circle graph
Histogram
Line plot
A line plot would be the best data display to highlight every height.
A line plot, also known as a dot plot, is a type of graph that displays data as a series of dots on a number line. Each dot represents a single data point, and the dots are placed above the corresponding value on the number line.
Line plots are useful for displaying small data sets because they provide a simple visual representation of the data. They can quickly show the range of values in the data set, as well as any outliers or clusters of data points. Line plots are commonly used in elementary and middle school classrooms to teach basic data analysis and graphing skills. They are also used in scientific research and statistical analysis to visualize small data sets and identify patterns in the data.
A line plot, also known as a dot plot, displays the data as points on a number line. Each data point is represented by a dot, making it easy to see every height in the data set. Here is an example of a line plot for the given data:
A display that will highlight every height would be a line plot, which would show each individual height as a dot along a number line.
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Maine has a cold climate in the winter. Which statement about the probability of
temperatures falling below 32 F in Maine during the month of January is most likely
true?
A. The probability is 100.
B. The probability cannot be determined before February.
C. The probability is closer to 1 than to 0.
D. The probability could be -1.
Option B is inaccurate since historical data and weather trends may be expressions used to determine the chance. Since probabilities are always between 0 and 1, option D is erroneous.
what is expression ?An expression in mathematics is a collection of numbers, variables, and mathematical operations (such as addition, subtraction, multiplication, division, exponentiation, and so on) that express a quantity or value. Expressions might be as basic as "3 + 4" or as complex as They may also contain functions like "sin(x)" or "log(y)". Expressions can be evaluated by substituting values for the variables and performing the mathematical operations in the order specified. If x = 2, for example, the formula "3x + 5" equals . Expressions are commonly used in mathematics to describe real-world situations, construct equations, and simplify complex mathematical issues.
The following statement is most likely correct concerning the likelihood of temperatures falling below 32 degrees Fahrenheit in Maine during the month of January:
D. The probability is greater than one.
Maine is noted for its frigid winters, with temperatures often falling below freezing in January. Yet, it is not certain that temperatures would never fall below 32 degrees Fahrenheit in January. As a result, it is safe to state that the likelihood of temperatures falling below 32 degrees Fahrenheit is high, but not absolutely 100%. Option B is inaccurate since historical data and weather trends may be used to determine the chance. Since probabilities are always between 0 and 1, option D is erroneous.
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geometry solve for X
Please help..... TvT
Answer:
1/3 -- 33.3%
37/100 -- 0.37
1/4 -- 25%
19/50 -- 30%
3/20 -- 15%
Step-by-step explanation:
Compute the flux of F⃗ =3(x+z)i⃗ +2j⃗ +3zk⃗ through the surface S given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0, oriented toward the xz-plane
It seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.
To compute the flux of the vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ through the surface S given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0, oriented toward the xz-plane, we can use the surface integral.
The surface integral of a vector field F⃗ over a surface S is given by the formula:
∬S F⃗ · dS = ∬S F⃗ · (n⃗ dS)
where F⃗ is the vector field, dS is the differential area vector, and n⃗ is the unit normal vector to the surface.
In this case, the surface S is given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0. We can parameterize this surface as:
r(x, z) = xi⃗ + yj⃗ + zk⃗ = xi⃗ + (x^2+z^2)j⃗ + zk⃗
To find the normal vector n⃗ to the surface, we can take the cross product of the partial derivatives of r(x, z) with respect to x and z:
n⃗ = ∂r/∂x × ∂r/∂z
= (1i⃗ + 2xj⃗) × (0i⃗ + 2zj⃗)
= -2xz i⃗ + 2zj⃗ + 2xk⃗
Now, we can calculate the flux:
∬S F⃗ · (n⃗ dS) = ∬S (3(x+z)i⃗ + 2j⃗ + 3zk⃗) · (-2xz i⃗ + 2zj⃗ + 2xk⃗) dS
= ∬S (-6x^2z - 4xz + 6xz^2 + 6xz) dS
= ∬S (-6x^2z + 2xz + 6xz^2) dS
To evaluate this integral, we need to determine the limits of integration for x, y, and z.
Since the surface is defined by 0≤y≤16, x≥0, z≥0, we have:
0 ≤ y = x^2 + z^2 ≤ 16
Simplifying the inequality, we get:
0 ≤ x^2 + z^2 ≤ 16
From this, we can see that x and z both range from 0 to 4.
Now, we can evaluate the flux:
∬S (-6x^2z + 2xz + 6xz^2) dS = ∫∫ (-6x^2z + 2xz + 6xz^2) dA
where dA is the differential area.
Integrating over the limits 0 ≤ x ≤ 4 and 0 ≤ z ≤ 4, we can calculate the flux.
However, it seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.
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what is the expected number of sixes appearing on three die rolls
To find the expected number of sixes appearing on three die rolls, we can calculate the probability of rolling a six on each individual roll and then multiply it by the number of rolls.
The probability of rolling a six on a single roll of a fair die is 1/6, since there are six equally likely outcomes (numbers 1 to 6) and only one of them is a six.
Since the rolls are independent events, we can multiply the probabilities together to find the probability of rolling a six on all three rolls:
(1/6) * (1/6) * (1/6) = 1/216
Therefore, the probability of rolling a six on all three rolls is 1/216.
To find the expected number of sixes, we multiply the probability by the number of rolls:
Expected number of sixes = (1/216) * 3 = 1/72
So, the expected number of sixes appearing on three die rolls is 1/72.
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Select the correct answer.
M(3, 2) and N(9, 2) are the endpoints of the segment MN on the coordinate plane. What is the length of MN?
A.
4 units
B.
6 units
C.
7 units
D.
12 units
The length of segment MN is 6 units. Option B.
To find the length of segment MN, we can use the distance formula, which is derived from the Pythagorean theorem. The formula is:
Distance = √[(x2 - x1)² + (y2 - y1)²]
In this case, the coordinates of point M are (3, 2), and the coordinates of point N are (9, 2). Plugging these values into the distance formula, we have:
Distance = √[(9 - 3)² + (2 - 2)²]
= √[6² + 0²]
= √[36 + 0]
= √36
= 6 units
The length of a segment on the coordinate plane can be found using the distance formula. Applying the formula to points M(3, 2) and N(9, 2), we calculate the distance as √[(9 - 3)² + (2 - 2)²], which simplifies to √[36], resulting in a length of 6 units. Hence, the correct answer is B.
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Please help ASAP!!!!!!!!!!
Graph y= 2/7x helpppppppp
The graph of the given equation is plotted below.
The given equation is y=2/7 x.
What is the graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points. A graph consists of some points and lines between them. The length of the lines and position of the points do not matter.
Graph the line using the slope and y-intercept, or two points.
Slope: 2/7
y-intercept: (0, 0)
Plot the points (0, 0) and (7, 2) on the graph
Hence, the graph of the given equation is plotted below.
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Pls help me this is my homework
Answer:
C) 840
C) 87
D) 3000-150n
Step-by-step explanation:
Answer:
c
c
d
Step-by-step explanation:
2 Find the vertex of the function and identify it as a maximum or a minimum
y-5=(1/3)(x + 2)²
O (-2,5) Maximum
(-2, 5) Minimum
O (2,-5) Maximum
O (2,-5) Minimum
2 of 10
(-2, 5) Minimum
Step-by-step explanation:
y-5=(1/3)(x + 2)²
y-5=(1/3)(x²+4x+4))
y-5=1/3x²+4/3x+4/3
y=1/3x²+4/3x+4/3+5
y=1/3x²+4/3x+4/3+15/3
y=1/3x²+4/3x+19/3
graph is attached
x= -b/2a
x= (-4/3)/2(1/3)
x= (-4/3)/(2/3)
x= (-4/3)*(3/2)
3's cancel
x= (-4/1)*(1/2)
x = -4/2
x = -2
plug -2 back into
y=1/3x²+4/3x+19/3
y=1/3*4+4/3*-2+19/3
y=4/3-8/3+19/3
y=15/3
y=5
(-2,5)
if a is positive
graph looks like a smile
so minimum
if a is negative
graph looks like a frown
so maximum
quadraticswbi.weebly.com
Pleaseeee help asap
What type of quadrilateral is formed by the points a (0,4) b (4,0) c (0,-3) d (-4,0)
A isosceles trapezoid
B kite
C parallelogram
D Rhombus
Which values from the set -6, -4, -3, -1, 0, 2 satisfy this inequality?
−12x + 3≥ 5
-6, -4 , -3 , and - 1 only
-6 and -4 only
- 1 , 0, and 2 only
-4, -3, -1, 0, and 2 only
I REALLY NEED HELP THIS IS A TEST
Answer:
-6, -4 , -3 , and - 1 only.
Step-by-step explanation:
−12x + 3 ≥ 5
-12x ≥ 5 - 3
-12x ≥ 2
Divide both sides by -12:
x ≤ -1/6 (Note the inequality sign flips because we are dividing by a negative value).
So considering the given set, all the values except 0 and 2 fit this inequality.
A rectangle has a length of 6 inches, and a width
of 4 inches. What is the area of this rectangle
Answer:
length times width so.... 24
A person hikes 4 miles in 2.5 hours. Find the unit rate in miles per hour.
mi/h
h/mi
How is each unit rate useful in a real-life situation
Answer:
1.6 mi / hr
0.625 hr / mi
Step-by-step explanation:
4/2.5 = x / 1
2.5/2.5 = 1
So, 4 / 2.5 = 1.6
1.6 mi / hr
4= m
2.5 = hr
4 / 4 = 1
2.5 / 4 = 0.625
0.625 hours / mile
If my answer is incorrect, pls correct me!
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A forester shows the accompanying histogram of tree diameters he used in analyzing 27 trees in a large woods that was for sale. Was he justified in using a Normal model to analyze the woods? Explain, citing some specific concerns
Choose the correct answer below
A. Yes, because the histogram is unimodal and symmetric.
B. No, because while the histogram is unimodal, it is not symmetric
C. No, because the histogram is not unimodal or symmetric.
D. No, because while the histogram is symmetric, it is not unimodal
Yes, the forester was justified in using a Normal model to analyze the woods, because the histogram is unimodal and symmetric. So option A is correct.
A histogram is a type of graph that uses vertical bars to show the distribution of a set of data. This particular histogram is unimodal, meaning that it has one peak which is an indication that the data is distributed normally. Additionally, the histogram is symmetric, which is another indication that the data is normally distributed.
Using a Normal model to analyze the woods is a valid approach because it allows the forester to identify the average diameter of the trees, as well as the spread of the data. It also allows him to check for any outliers, or points that fall outside the normal range. With this information, the forester can determine if the woods is suitable for sale, or if the buyer should be aware of any unexpected features.
Overall, the histogram is an effective way for the forester to analyze the data and determine if a Normal model is appropriate. By noting the unimodal and symmetric nature of the histogram, the forester can be sure that a Normal model will accurately represent the data, allowing him to make an informed decision about the woods.
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Estimate the limit numerically. HINT (If you need to use infinity or –infinity, enter INFINITY or –INFINITY, respectively. If an answer does not exist, enter DNE.)
A)
lim
x→0 x − 14 / x − 2
B)
lim
x→4 x^2 − 5 / x − 4
C)lim
x→−5 x^2 + 10x + 25 / x + 5
D) lim x→+[infinity] 8x^2 + 4x + 80 / 4x^2 − 8
If you need to use infinity or –infinity, enter INFINITY or –INFINITY, respectively. If an answer does not exist, enter DNE. The limit numerically of:- A) 7, B) DNE, C) DNE and D) 2.
A) lim x→0 (x − 14) / (x − 2)
As x approaches 0, the numerator (x-14) approaches -14, and the denominator (x-2) approaches -2. Therefore, the limit is -14/-2 = 7.
Answer: 7
B) lim x→4 (x^2 − 5) / (x − 4)
As x approaches 4, the numerator (x^2-5) approaches 11, and the denominator (x-4) approaches 0. Therefore, the limit does not exist.
Answer: DNE
C) lim x→−5 (x^2 + 10x + 25) / (x + 5)
As x approaches -5, the numerator (x^2+10x+25) approaches 0, and the denominator (x+5) approaches 0. Therefore, the limit does not exist.
Answer: DNE
D) lim x→+[infinity] (8x^2 + 4x + 80) / (4x^2 − 8)
As x approaches infinity, the numerator (8x^2+4x+80) and the denominator (4x^2-8) both approach infinity. However, the leading term in the numerator is 8x^2, and the leading term in the denominator is 4x^2. Therefore, the limit is 8/4 = 2.
Answer: 2
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William says that 15 years from now, his age will be 3 times his age 5 years ago. If x represents Williams present age,
Answer:
Step-by-step explanation:
William's present age = x
William 15 years from now = x + 15
William 5 years ago = x - 5
William says that 15 years from now, his age will be 3 times his age 5 years ago.
x + 15 = 3(x-5) ← equation formed
x + 15 = 3x - 15
3x - x = 15 + 15
2x = 30
x = 15 . ← William's current age
William is 15 now
HELP 10 POINTS + BRAINLIEST Determine the equation of the line shown in the graph:
y=0
x=0
y=5
X=5
Answer:
y=0
Step-by-step explanation:
the x coordinate is 5 and the y coordinate is 0 because the line does not move up the y axis
Answer:
your question is a little messed up.
the equation for the blue line is x = 5
y=x if you're looking for an equation that satisfies (0,0) and (5,5)
Two sides of an isosceles triangle measure 3 inches and 7 inches. Which could be the length of the third side?
due today----- 25 points
What's More State whether each of the following sets is well-defined or not. Write your answer in the space provided before the number. 1. The set of young politicians. 2. The set of types of matter. 3. The set of versatile actress. 4. The set of all oceans of the earth. 5. The set of months containing 31 days. 6. The set of tasty food. 7. The set of planets in our solar system. 8. The set of durable bags. 9. The set of consonants in the English Alphabet 10. The set of even counting numbers.
Answer:
1. well defined
2. not
3. well defined
4. well defined
5. well defined
6. not
7. well defined
8. not
9. well defined
10. not
Step-by-step explanation:
Montraie drove 220 miles in 5 hours. If he continued at the same rate, how long would it take to travel 88 miles?
The time taken for Montraie to travel a distance of 88 miles is 2 hours.
How long would it take for Montraie to travel 88 miles?Speed is simply referred to as distance traveled per unit time.
It expressed mathematically as;
Speed = Distance ÷ time.
Given the data in the question;
Distance covered = 220 milesTime elapsed = 5 hoursSpeed = ?First, we determine the speed of Montraie.
Speed = Distance ÷ time.
Speed = 220 miles ÷ 5 hours
Speed = 44 miles per hour.
Now, time spent in traveling a distance of 88 miles will be;
Speed = Distance ÷ time
Time = Distance / Speed
Time = 88 miles / 44 miles per hour
Time = 2 hours
Therefore, the elapsed time is 2 hours.
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If Montraie drove 220 miles in 5 hours. If he continued at the same rate, then it takes 2 hours to travel 88 miles.
What is Ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.
Given that,
Montraie drove 220 miles in 5 hours.
We need to find how long it would take to reach 88 miles.
Let us form a equation based on given data.
Let x be the time to reach 88 miles.
We need to find value of x.
220/5=88/x
Apply cross multiplication
220x=440
x=440/220
x=2
Hence it takes 2 hours to travel 88 miles with same rate.
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Gianna wants to ride her bicycle 48.5 miles this week. She has already ridden 18 miles. If she rides for 5 more days, which equation could be used to determine x, the average number of miles she would have to ride to meet her goal?
Answer:
8.1 miles per day
Step-by-step explanation:
18 + 5x = 48.5 >> subtract 18 to both sides
5x= 40.5 >> divide by 5 to both sides
x= 8.1 miles
f possible, find the first three nonzero terms in the power series expansion for the product f(x)g(x). f(x)=e56 - 2 (5x)" g(x) = sin 8x= -11(8x)2k + 1 The power series approximation of f(x)g(x) is (Type an expression that includes all terms up to order 3.)
The power series approximation of f(x)g(x) up to order 3 is:
\(e^56 sin 8x - 22(5x)sin 8x - 2e^56(5x) + 22(5x)^2 sin 8x\)
To find the power series expansion of the product f(x)g(x), we need to multiply the power series expansions of f(x) and g(x) and collect like terms.
First, let's find the power series expansion of f(x):
\(f(x) = e^56 - 2(5x)^"\)
Using the formula for the power series expansion of e^x:
\(e^x = 1 + x + (x^2)/2! + (x^3)/3! + ...\)
We can write the power series expansion of f(x) as:
\(f(x) = e^56 - 2(5x)^"\)
\(= (1 + 56 + (56^2)/2! + (56^3)/3! + ...) - 2(5x)^(1)\)
= \(1 - 5x + (56 - 25x^2) +\)...
Now let's find the power series expansion of g(x):
g(x) = sin 8x
= (8x) - (8x)^3/3! + (8x)^5/5! - ...
Finally, we can multiply the power series expansions of f(x) and g(x) to get the power series expansion of f(x)g(x):
\(f(x)g(x) = (1 - 5x + (56 - 25x^2) + ...) * ((8x) - (8x)^3/3! + (8x)^5/5! - ...)\)
\(= (8x) - (40x^2) + (568x^2)/2! + ((56-8*8)/2!)x^4 + ...\)
Collecting like terms up to order 3, we get:
\(f(x)g(x) = (8x) - (40x^2) + (224x^3)/3! + ...\)
Therefore, the power series approximation of f(x)g(x) up to order 3 is:
\(e^56 sin 8x - 22(5x)sin 8x - 2e^56(5x) + 22(5x)^2 sin 8x\)
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