Jill has a bag containing 3 1/2 cup of flour. She will use 1 1/4 cups of flour to make cookies and 1/3 Cup of flour to make candy. How many cups of flour will Jill have left after she has made the cookies and candy?

Using the subtraction operation, the baby gained a total weight of 3.25 pounds.

Subtraction operation is one of the four basic mathematical operations, including addition, division, and multiplication.

Subtraction involves the minuend, the subtrahend, and the difference.

The total weight of the baby during its first year of life = 11 pounds

The weight gained during the first four months = 4.25 pounds

The weight gained during the second four months = 3.5 pounds

The weight of the baby gained during the last four months = 3.25 pounds (11 - 4.25 - 3.5).

Thus, by subtraction, we can conclude that the baby gained 3.25 pounds in weight during the last four months of its life.

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The probability of at least 2 items being returned when an online retailer sells 20 items of clothing is approximately 0.6082.

Probability refers to the measure of the likelihood or chance of an event occurring. It quantifies the possibility of different outcomes in an uncertain or random situation. Probability is typically represented as a number between 0 and 1, where 0 indicates an impossible event and 1 indicates a certain event.

The concept of probability is based on the understanding that outcomes of certain events are not always predictable with certainty, but they can be described and analyzed using mathematical methods.

The probability of at least 2 items being returned can be calculated using the binomial probability formula. In this case, the probability of success (returning an item) is 10% or 0.1, and the probability of failure (not returning an item) is 90% or 0.9. The formula is:

P(X ≥ k) = 1 - P(X < k)

Where X is the number of items returned and k is the minimum number of items required.

To find the probability of at least 2 items being returned out of the 20 items sold, we can use the formula:

P(X ≥ 2) = 1 - P(X < 2)

P(X < 2) is the probability of 0 or 1 items being returned. Let's calculate it step by step.

P(X = 0) = (0.9)^(20) ≈ 0.1216
P(X = 1) = (20C1) * (0.1)^(1) * (0.9)^(19) ≈ 0.2702

P(X < 2) = P(X = 0) + P(X = 1) ≈ 0.1216 + 0.2702 ≈ 0.3918

Now, we can calculate P(X ≥ 2):

P(X ≥ 2) = 1 - P(X < 2) ≈ 1 - 0.3918 ≈ 0.6082

Therefore, the probability of at least 2 items being returned when an online retailer sells 20 items of clothing is approximately 0.6082.

It's important to note that this calculation assumes each item sold is independent of each other, and the probability of returning an item is consistent for all items. Also, this is a theoretical probability, and actual results may vary.

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Answer:

-3

Step-by-step explanation:

when you have a power to the - it creates a fraction instead of a whole number.

2^3 = 8

2^-3=1/8

The probability that the flight takes less than 42 minutes is approximately 0.0668, or 6.68%. The probability that the flight takes between 40 and 50 minutes is approximately 0.9876, or 98.76%.

To find the probability that the flight takes less than 42 minutes, we need to calculate the z-score and then use the standard normal distribution table or calculator. First, calculate the z-score: z = (42 - 45) / 2 = -1.5. Using the standard normal distribution table or calculator, we can find the probability corresponding to a z-score of -1.5. The table or calculator will give us the area under the standard normal curve to the left of -1.5. The probability that the flight takes less than 42 minutes is approximately 0.0668, or 6.68%. b. To find the probability that the flight takes between 40 and 50 minutes, we need to calculate the z-scores for both values and then find the difference in probabilities. First, calculate the z-scores: z1 = (40 - 45) / 2 = -2.5; z2 = (50 - 45) / 2 = 2.5. Using the standard normal distribution table or calculator, find the probabilities corresponding to z1 and z2. Then, subtract the probability for z1 from the probability for z2. The probability that the flight takes between 40 and 50 minutes is approximately 0.9876, or 98.76%.

c. To find the times that 5% of flights take longer than, we need to find the z-score that corresponds to the upper 5% tail of the standard normal distribution. Using the standard normal distribution table or calculator, find the z-score that corresponds to an area of 0.05 in the upper tail. This z-score represents the number of standard deviations above the mean.  The z-score is approximately 1.645. To find the corresponding time, we can use the formula: x = z * σ + μ. where x is the time, z is the z-score, σ is the standard deviation (2 minutes), and μ is the mean (45 minutes). Thus, 5% of flights take longer than 1.645 * 2 + 45 = 48.29 minutes (rounded to two decimal places).

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Answer: 7%

(Hope this is right.)

Step-by-step explanation:

Let's solve this using the information we have and an equation.

Shane: $32,000 - (Given)

Theresa: 18,000+14x, if x=1,160 - (Given)

---------------------------------------------------------------

Step two: (Theresa) 14(1,160) =16,240 (Algebra)

Step three: (Theresa) 18,000+16,240=34,240 (Algebra, given.) - cost of Theresa's car.

---------------------------------------------------------------

Finally,

They're asking for how much more she paid for her car as a percentage of what Shane paid.

34,240-32,000=2,240 and

2,240/32,000=0.07

0.07x100=7

Answer 7% more than what Shane paid.

Answer:

Option 3 and 5

Step-by-step explanation:

- 5, 5, - 5, 5, - 5, .....

5 - ( - 5 )

= 5 + 5

= 10

- 5 - 5

= - 10

Here, common difference is not same, so this sequence is not an A.P

96, 48, 24, 12, 6

48 - 96 = - 48

24 - 48 = - 24

Here, common difference is not same, so this sequence is not an A.P

18, 5.5, - 7, - 19.5, - 32, .....

5.5 - 18 = - 12.5

- 7 - 5.5 = - 12.5

Here, common difference is same, so this sequence is an A.P

- 1, 3, - 9, - 27, - 81, .....

- 3 - 1 = - 4

- 3 - 9 = - 12

Here, common difference is not same, so this sequence is not an A.P

16, 32, 48, 64, 80, .....

32 - 16 = 16

48 - 32 = 16

Here, common difference is same, so this sequence is an A.P

Answer:

1 in 5

Step-by-step explanation:

Answer: 4^3, and 5^2. This is the answer.

Step-by-step explanation:

Before school Ali ran 3/10 km, after school she ran 1/5 km. The total distance she ran is 1/2 km.

To add fractions, check whether they have common denominator or not. If they have common denominator, add the numerators.

Example:

2/5 + 1/5 = (2+1)/5 = 3/5

If the dominators are not the same, first find the common denominator.

Example:

1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2

Information available in the problem:

Before school, Ali ran 3/10 km

After school, Ali ran 1/5 km

Total distance that Ali ran = 3/10 + 1/5

                                           = 3/10 + 2/10

                                           = (3 + 2)/10

                                           = 5/10 = 1/2

Hence, total distance = 1/2 km

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The most appropriate choice for reflection will be given by-

After reflection over y-axis, coordinate of K will become K' (6, -1)

After reflection over y-axis, coordinate of L will become  L' (0, -1)

After reflection over y-axis, coordinate of M will become M' (0, -2)

After reflection over y-axis, coordinate of J will become  J' (6, -2)

What is reflection?

Reflection of a figure about a line is a transformation in which a mirror image of the figure can be obtained over the line.

The line is called the line of reflection.

Here,

After reflection over the y - axis, sign of x coordinate will be same.

Coordinate of K = (-6, -1)

After reflection over y-axis, coordinate of K will become K' (6, -1)

Coordinate of L = (0, -1)

After reflection over y-axis, coordinate of L will become L' (0, -1)

Coordinate of M = (0, -2)

After reflection over y-axis, coordinate of M will become M' (0, -2)

Coordinate of J = (-6, -2)

After reflection over y-axis, coordinate of J will become J' (6, -2)

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The 95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners is $72.50 to 77.50$.

The formula for a 95% confidence interval for the population mean is given by:

\($\bar{x} \pm t_{\frac{\alpha}{2},n-1} \frac{s}{\sqrt{n}}$\)

where \($\bar{x}$\) is the sample mean, \($t_{\frac{\alpha}{2},n-1}$\) is the critical value for a t-distribution with \($\frac{\alpha}{2} = 0.025$\) and n-1 = 63 degrees of freedom,

s is the sample standard deviation, and

sqrt{n} is the square root of the sample size.

Since the population standard deviation is given, we can use the sample mean as an estimate for the population mean and use s = 10 as an estimate for the population standard deviation.

So, the 95% confidence interval is:

\(75 \pm t_{0.025,63} * \frac{10}{\sqrt{64}}\\= 75 \pm 2.00 * \frac{10}{8}\\= 75 \pm 2.50$\)

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Answer:

x = 35     y = 45

Step-by-step explanation:

Total number of strings:  x + y = 80  ⇒  x = 80 - y

Substitute  x = 80 - y  into  4.5x + 1.5y = 225  to find y:

4.5(80 - y) + 1.5y = 225

360 - 4.5y + 1.5y = 225

                      3y = 135

                        y = 45

Substitute the found value of y into  x + y = 80  to find x:

x + 45 = 80

x = 80 - 45 = 35

To solve the problem we must know about the system of equations.

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

The number of premium and standard strings Kenny ordered are 35 and 45 respectively.

Given to us

Total Number of Strings

= number of premium strings + number of standard strings

80 = x+ y

Solving for y,

y = 80-x

Total Cost of all strings

($4.50)x + ($1.50y) = $225

4.50x + 1.50y = 225

Substitute the value of y,

\(4.50x + 1.50(80-x) = 225\\\\4.50x +120 -1.5x = 225\\\\4.50x-1.5x = 225-120\\\\3x = 105\\\\x=\dfrac{105}{3}\\\\x = 35\)

Thus, the number of premium strings Kenny ordered was 35.

Substitute the value of x in the equation of y,

y = 80 - x

y = 80 - 35

y = 45

Thus, the number of standard strings Kenny ordered was 45.

Hence, the number of premium and standard strings Kenny ordered are 35 and 45 respectively.

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Answer:

x=0   , x=8 , x = ±5i

Step-by-step explanation:

-x(x – 8)(x² + 25) = 0

Using the zero product property

-x =0   x-8 =0  x^2+25 =0

x =0    x= 8     x^2 = -25

x=0    x= 8    sqrt(x^2) = sqrt(-25)

                      x = ±5i

Answer:

The proper equation is, y = -5x + 35

The mistake Amy made, was that she used the x-intercept instead of the y intercept

(-5, -1)

Hope this helps! :)

P(X = 4, Y = 2) = 0.055131

P(X = Y) = 0.35607

From the information given:

X represent no of Canon SLR

The PMF is given as:

X   :    0         1        2           3        4

p(x) :  0.1       0.2   0.3     0.25   0.15

p = P(customers that purchase the camera & also purchase an extended warranty.

As a result, the conditional distribution Y provided X approaches a Binomial distribution with n = x and p = 0.55 as the parameter.

\(\frac{Y}{X}\) ~ Bin ( n= x , p =0.55) y

     = 0.1 ........ x and X = 0,1,2,3,4.

The condition probabilities Y given X is:

\(P (\frac{Y = 0}{X = 0} ) =1\)

\(P (\frac{Y = 0}{X = 1} ) = 0.45 and P (\frac{Y = 1}{X = 1} ) =0.55\)

\(P (\frac{Y = 0}{X = 2} ) = 0.2025 and P (\frac{Y = 1}{X = 2} ) =0.495, P (\frac{Y = 2}{X = 2} ) =0.3025\)

\(P (\frac{Y = 0}{X = 3} ) = 0.091125 and P (\frac{Y = 1}{X = 3} ) =0.334125, \\P (\frac{Y = 2}{X = 3} ) =0.408375 and P (\frac{Y = 3}{X = 3} ) = 0.166375\)

\(P (\frac{Y = 0}{X = 4} ) = 0.0.041006 and P (\frac{Y = 1}{X = 4} ) =0.0.200475, P (\frac{Y = 2}{X = 3} ) =0.367538\)

\(P (\frac{Y = 3}{X = 4} ) = 0.299475 and P (\frac{Y = 4}{X = 4} ) =0.091506\)

Now, the joint P.D (probability Dist.) of X & Y is expressed as:

\(P (\frac{Y = y}{X = x} ) = P (\frac{Y = y. X = x}{X = x} )\)

\(P( X = x , Y = y) = P(\frac{Y = y}{X =x} ) * P(X =x)\)

The Joint P.D is;

                      Y                                                                      Total

             0              1                    2             3          4

X     0     0.1            0                  0              0         0                  0.1

      1      0.09        0.11              0               0         0                 0.2

  2    0.06075  0.1485      0.09075          0         0                 0.3

  3    0.022781 0.083531 0.102094   0.041594  0                0.25

  4    0.006151  0.030071  0.055131  0.044921  0.013726    0.15

Total  0.279682 0.372103  0.247974  0.086515 0.013726       1

(a)

P(X=4,Y=2)

From the table above:

P(X=4,Y=2)

 = 0.055131

(b)

P(X= Y)

= (P = 0 , Y = 0) + P( X =1, Y =1) + P( X=2, Y=2) + P(X=3,Y=3) + P(X=4,Y=4)

= 0.1 + 0.11 + 0.09075 + 0.041594 + 0.013726

= 0.35607

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The samples of size n = 2 that can be drawn from this population is 28

From the question, we have the following parameters that can be used in our computation:

Population, N = 8

Sample, n = 2

The samples of size n = 2 that can be drawn from this population is calculated as

Sample = N!/(n! * (N - n)!)

substitute the known values in the above equation, so, we have the following representation

Sample = 8!/(2! * 6!)

Evaluate

Sample = 28

Hence, the number of samples is 28

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Complete question

A finite population consists of 8 elements.

10,10,10,10,10,12,18,40

How many samples of size n = 2 can be drawn this population?

Vector a = (3, 2), then;

Also, vector b = (-5, 6), then;

Then, -3a + 2b = (-9, -6) + (-10, 12)

The answer is (-19,6)

The revised mean is thus 20.8, which is consistent with choice (B).

How can you calculate the mean?

Simply dividing the total number of values in a data collection by the aggregate of all of the values yields it. The computation can be performed on unprocessed data or data that has been combined into a frequency chart.

We must first compute the average of the dataset such as the new number, then split by the overall number of data points in order to determine the innovative mean within a week of adding a count to the dataset.

Let's call the four original numbers in the dataset A, B, C, and D. We know that their mean is 19, so we can write:

(A + B + C + D)/4 = 19

Multiplying both sides by 4 gives us:

A + B + C + D = 76

Now, if we add the number 28 to the dataset, we get a new sum:

A + B + C + D + 28

To find the new mean, we need to divide this sum by the total number of values in the dataset, which is 5 now:

(A + B + C + D + 28)/5

Substituting in our earlier expression for A + B + C + D, we get:

(76 + 28)/5 = 104/5 = 20.8

Therefore, the new mean is 20.8, which corresponds to option (B).

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Answer:

10080

Step-by-step explanation:

Population to millionaires ratio of Los Angeles:

Expected number of millionaires in Berlin based on ratio above:

Answer:

0.5833333.......

Step-by-step explanation:

All you have to do is divide 7 by 12. The fraction 7/12 is equal to 7 ÷ 12.

7 ÷ 12 = 0.583... (repeating 3)

Or if you round, you have 0.58.

Answer:

first order

Step-by-step explanation:

they're basically a linear function. to make it easier you could just put the coordinates on the side of the table.

The value of ML = 3, using the mid-point theorem of triangles.

According to the midpoint theorem, "the line segment of a triangle crossing the midpoints of two sides of the triangle is said to be parallel to its third side and also half the length of the third side."

In the question, we are given that triangle ABC is an equilateral triangle, and L, M, and N are the midpoints of BC, AB, and CA respectively.

Thus, by the midpoint theorem, we can say that:

Assuming AB = BC = AC = x units, we get:

Thus, the triangle LMN is an equilateral triangle.

Thus, MN = ML = NL.

Given MN = 3, we can write the value of ML = 3.

Thus, the value of ML = 3, using the mid-point theorem of triangles.

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The given question is in Spanish. The question in English is:

"Triangle ABC is equilateral and L, M, and N are the midpoints of BC, AB, and CA respectively. If MN = 3, what is the value of ML?"

The relative atomic mass of Interactium is 290.14 amu.


We can calculate the relative atomic mass of Interactium using the following equation:

Ar = (Ab × Mb) + (Ac × Mc) + (Ad × Md) where Ar is the relative atomic mass, Ab is the abundance of Interactium-284, Mb is the mass of Interactium-284, Ac is the abundance of Interactium-289, Mc is the mass of Interactium-289, Ad is the abundance of Interactium-294, and Md is the mass of Interactium-294.  

Substituting the given values in the equation, we get:

Ar = (0.16 × 284) + (0.27 × 289) + (0.57 × 294)
Ar = 45.44 + 77.97 + 167.43
Ar = 290.14 amu

Therefore, the relative atomic mass of Interactium is 290.14 amu.

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The "correct" statement is that the odds ratio appears statistically significant when the whole 95% confidence interval is much less than 1.

In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values a predetermined percentage of the time.

Thus, the "correct" statement is that the odds ratio appears statistically significant when the whole 95% confidence interval is much less than 1.

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Answer:

What is 2x+1 is equal to

??!