Jessica is on a the swim team. Each day she swims 8000m. Use the the fact to find how much this is in kilometers

Answer:

-2<=y<=-7

Step-by-step explanation:

9514 1404 393

Answer:

  1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 30, 33, 35, 42,

  55, 66, 70, 77, 105, 110, 154, 165, 210, 231, 330, 385, 462, 770, 1155, 2310

Step-by-step explanation:

The trailing digit is 0, and the sum of digits is 6, so we know the number is divisible by 2, 3, 5. Dividing out those factors, we get a quotient of 77, which is 7×11. This means the prime factorization is ...

  2×3×5×7×11 = 2310

There are 5 prime factors, each with an exponent of 1, so the total number of divisors is 2^5 = 32. We will have found them all when all 32 are listed.

  1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 21, 22, 30, 33, 35, 42,

  55, 66, 70, 77, 105, 110, 154, 165, 210, 231, 330, 385, 462, 770, 1155, 2310

Of course, the pairwise products working toward the center from the ends of the list are all 2310.

Answer:

B: (-6, -1)

Step-by-step explanation:

6+x/2 = 0

6+x = 0

x = -6

-5+y/2 = -3

-5 + y = -6

y = -1

Answer:

(-6,-1)

Step-by-step explanation:

We can use the midpoint formula here to find the coordinates of B . Given data :-

Let B be B(p , q) . Then ,

=> M = ( x₁ + x₂/2 , y₁ + y ₂ /2 )

=> (0 ,-3) = ( 6 + p/2 , -5+q/2)

=> 0 = 6 + p/2

=> 6 + p = 0

=> p = (-6)

=> -3 = -5+q/2

=> -5+q = -6

=> q = 5-6

=> q = (-1)

Answer:

Step-by-step explanation:

AB=√[(4+2)²+(6-11)²]=√61

BC=√[(-1-4)²+(0-6)²]=√61

AC=√[(-1+2)²+(0-11)²]=√122

AC²=AB²+BC²

So it is a right angled triangle.

The area of the triangle is (8/5)sqrt(1199) square units.

We are given that;

Coordinates= A=(-2,11) B = (4.6) C=(-1,0)

Now,

we can plug in one point on line AB, such as A(-2, 11), and solve for b:

y = mx + b 11 = (-5/6)(-2) + b 11 = (5/3) + b b = 11 - (5/3) b = (28/3)

Hence, the equation of line AB is:

y = (-5/6)x + (28/3)

Now we can set y equal to 0 (the y-coordinate of C) and solve for x:

y = (-5/6)x + (28/3)

0 = (-5/6)x + (28/3) (-5/6)

x = -(28/3)

x = -(28/3)/(-5/6)

x = (56/15)

Therefore, point D has coordinates (56/15, 0). To find the height of the triangle, we need to find the distance between points A and D using the distance formula:

\(h = AD = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2) h = sqrt((56/15 - (-2))^2 + (0 - 11)^2) h = sqrt((136/15)^2 + 121) h = sqrt(18496/225 + 121) h = sqrt(45121/225) h = (3/15)sqrt(5024)\)

Now we can plug in the values of b and h into the area formula and simplify:

\(A = (1/2)bh A = (1/2)(sqrt(61))((3/15)sqrt(5024)) A = (1/10)sqrt(61)sqrt(5024) A = (1/10)sqrt(307584) A = (1/10)(16)sqrt(1199) A = (8/5)sqrt(1199)\)

Therefore, by the given triangle answer will be (8/5)sqrt(1199) square units.

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Solving for h in the given equation; 3 g h = f + 3 gives; h = f/3g + 1/g.

The given equation is; 3 g h = f + 3

To solve for h; we must divide both sides of the equation by 3g as follows;

Hence, we have;

The correct answer is Choice C; StartFraction f Over 3 g EndFraction + StartFraction 1 Over g EndFraction

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Answer:

C if you want a short answer :)

Step-by-step explanation:

Good luck

Answer:

54x

Step-by-step explanation:

The equation y = 45 models the saving.

If m is the slope of the line that passes through the point (x₁, y₁), then the equation of the line is y - y₁ = m (x - x₁).

Given the graph of the equation.

Note that the graph passes through points (0,0) and (2,90).

The slope of the line is:

m = (90 - 0)/(2 - 0)

m = 45

The equation of the line with a slope of m = 45 and passes through (0,0) is:

y -0 = 45(x - 0)

y = 45x

Hence, the equation y = 45 models the saving.

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Answer: D

Step-by-step explanation:

Answer:

Kindly check explanation

Step-by-step explanation:

Waiting times collected over a one month period:

2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3

A)

Class(x) - - frequency(f)

0-4 - - - - - 4

5-9 - - - - - - 8

10-14 - - - - - 5

15-19 - - - - - 2

20-24 - - - - 1

B)

Class(x) - - frequency(f)- - relative frequency(rf)

0-4 - - - - - 4 - - - - - - - - - - 4/20 = 0.20

5-9 - - - - - - 8 - - - - - - - - - - 8/20 = 0.40

10-14 - - - - - 5 - - - - - - - - - - 5/20 = 0.25

15-19 - - - - - 2 - - - - - - - - - - 2/20 = 0.10

20-24 - - - - 1 - - - - - - - - - - - 1/20 = 0.05

C)

Class(x) - - frequency(f) - - cumulative frequency

0-4 - - - - - 4 - - - - - - - - - - - 4

5-9 - - - - - - 8 - - - - - - - - - - - 12

10-14 - - - - - 5 - - - - - - - - - - - 17

15-19 - - - - - 2 - - - - - - - - - - - 19

20-24 - - - - 1 - - - - - - - - - - - - 20

D)

Class(x) - - f - - cf - - - - rf - - - - - - crf

0-4 - - - - 4 - -- 4 - - - 0.20 - - - 0.20

5-9 - - - - - 8 - - 12 - - - 0.40 - - - 0.60

10-14 - - - 5 - - -17 - - - 0.25 - - - 0.85

15-19 - - - 2 - - - 19 - - - 0.10 - - - 0.95

20-24 - - 1 - - - 20 - - 0.05 - - - 1.00

crf - cumulative relative frequency

rf - relative frequency

cf - cumulative frequency

E) 0.6 (from the cumulative relative frequency column)

9 minutes or less :

Frequency = 12, total frequency = 20

12 / 20 = 0.6

The frequency distribution of the given data and frequency table for them would be presented as mentioned below.

Frequency Distribution

Given that,

Data

2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3

a). The use of classes to create a frequency distribution through classes would be as follows:

Class(X)                             frequency(f)

0-4                                          4

5-9                                          8

10-14                                        5

15-19                                        2

20-24                                       1

b). The relative frequency distribution would be as follows:

Class(X)                             frequency(f)              relative frequency(rf)

0-4                                          4                                  4/20 = 0.20

5-9                                          8                                 8/20 = 0.40

10-14                                        5                                 5/20 = 0.25

15-19                                        2                                 2/20 = 0.10

20-24                                       1                                 1/20 = 0.05

c). The cumulative frequency distribution would be as follows:

Class(X)                             frequency(f)              cumulative frequency(cf)

0-4                                          4                                  4

5-9                                          8                                 12

10-14                                        5                                 17

15-19                                        2                                 19

20-24                                       1                                 21

d). The cumulative frequency distribution employing classes in part a would be as follows:

Class(X)           (f)                           (cf)               rf                 crf

                    Frequency      Cumulative     Relative   Cumulative Relative

                                                  Frequency   Frequency   Frequency

0-4                    4                               4              0.20               0.20

5-9                    8                               12            0.40                0.60

10-14                 5                                17             0.25                0.85

15-19                 2                                19             0.10               0.95

20-24               1                                 21             0.05                  1

e). The proportion of customers requiring an oil change wait 9 minutes would be:

Frequency \(= 12\)

Total Frequency \(= 20\)

The Proportion of customers requiring an oil change wait 9 minutes or less

\(= 12/20\\= 0.6\)

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The probability of rolling an odd number or a number less than 4 is 2/3.

What is probability?

The degree to which something is likely; the probability that something will occur or will be the case.

Here, we have

Given

A single die is rolled.

Sample space = {1, 2, 3, 4, 5, 6}

Let P(A) be the probability of getting an odd number, where A = {1, 3, 5}

Let P(B) be the probability of getting a number less than 4,

where B = {1,2,3}

A ⋂ B ={1, 3}

P(A) = 3/6 = 1/2

P(B) = 3/6 = 1/2

P(A ⋂ B) = 2/6 = 1/3

Let P be the required probability of getting an odd number or a number less than 4

P = P( A ⋃ B ) = P(A) + P(B) - P(A ⋂ B)

P( A ⋃ B ) = 1/2 + 1/2 - 1/3

P( A ⋃ B ) = 1 - 1/3

P( A ⋃ B ) = 2/3

Hence, the probability of rolling an odd number or a number less than 4 is 2/3.

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Answer:

look at the picture.......................

Answer:

it will take him 30 weeks

Step-by-step explanation:

2 weeks = 1 kilogram lost

105-90=15

1 x 15 = 15

2 x 15 = 30

Answer:

you have to add them together

The values of the unknown angles are ∠1 = 92°, ∠2 = 24°, ∠3 = 64°, ∠4 = 35°, ∠5 = 81°

Corresponding angles are the angles which are formed in matching corners or corresponding corners with the transversal when two parallel lines are intersected by any other line (i.e. the transversal). For example, in the below-given figure, angle p and angle w are the corresponding angles.

∠1 + 88 = 180°( angles on a straight line)

∠1 = 180 - 88 which is 92°

∠3 = 64°( corresponding angles are equal)

∠2 + ∠1 + ∠3 = 180( sum of angles in a triangle)

∠2 + 92° + 64° = 180

∠2 = 180 - 92 - 64

∠2 = 24°

∠4 + 81 + ∠3 = 180 ( angles on a straight line)

∠4 + 81 + 64 = 180

∠4 = 180 - 64 -81

∠4 = 35°

∠5 = 81°( alternate angles are equal)

In conclusion the values of ∠1, ∠2, ∠3, ∠4, ∠5 are 92°, 24°, 64°, 35° and 81° respectively.

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Answer:

a

Step-by-step explanation:

The order of operations (PEMDAS) states that we should perform multiplication and division before addition and subtraction. Using this order, we get:

244 - (33456 / 3456) * 345 + 13.55 - 2

= 244 - 97.02 * 345 + 13.55 - 2

= 244 - 33494.1 + 13.55 - 2

= -33238.55

Therefore, 244-33456/3456*345+13.55-2 = -33238.55.

Answer:

b & c

Step-by-step explanation:

Answer:

5.4

Step-by-step explanation:

square of 29 = 5.385164807

5.385164807 estimated is 5.4

Answer:

I think answer is B

B.10x+150=180

Answer: 16j^3+2

Step-by-step explanation:

Answer:

slope = 2 / 3

Step-by-step explanation:

slope = rise / run

rise = 2

run = 3

slope = 2 / 3

Answer:

22 + x = 43

Step-by-step explanation:

let x = vanessa's savings

22 + x = 43

Answer: b = 11.62

Step-by-step explanation:

We can use this formula to solve for b:

\(b^{2} =\) \(\sqrt{c^{2}-a^{2} }\)

\(b^{2} =\) \(\sqrt{12^{2}-3^2 }\)

\(b^2= \sqrt{144-9}\)

= 11.61895004

We can round that to 11.62.

Hope this helped!

Answer:

11700

Step-by-step explanation:

I'm not sure if that is a fraction or if you're trying to divide it. That is the answer if you're trying to divide. Hope it helps.

Answer:

a is positive, and b is negative

Answer:

The b is negative

Step-by-step explanation:

As u can see the b which is the y intercept..If the b is positive the point should have be at the top, but it's not

Answer:

85%

Step-by-step explanation:

The students who read less than six magazines would be placed in the intervals: 0-1, 2-3, and 4-5 on the graph. Adding up the total amount in those intervals gives us:

2 + 15 = 17

So, using the answer from b, we can say that 17/20 kids read magazines. Now, we need to convert it into a percent by multiplying by 100:

17/20 *100

17 * 5

85%

Answer:

\(T_7 = 11\)

\(T_n = 2n- 3\)

Step-by-step explanation:

Given

\(S_n = n^2 -2n\)

\(T_n = S_n - S_{n-1}\)

Solving (a): T7

Substitute 7 for n in \(T_n = S_n - S_{n-1}\)

\(T_7 = S_7 - S_{7-1}\)

\(T_7 = S_7 - S_6\)

Calculate S7 and S6

\(S_n = n^2 -2n\)

\(S_7 = 7^2 - 2 * 7 = 35\)

\(S_6 = 6^2 - 2 * 6 = 24\)

So:

\(T_7 = 35 -24\)

\(T_7 = 11\)

Solving (b): Tn

\(T_n = S_n - S_{n-1}\)

Where \(S_n = n^2 -2n\)

Calculate\(S_{n-1}\)

We have:

\(S_{n-1} =(n-1)^2 - 2(n-1)\)

Open brackets

\(S_{n-1} = n^2 -2n + 1 -2n +2\)

\(S_{n-1} = n^2 -2n-2n + 1 +2\)

\(S_{n-1} = n^2 -4n + 3\)

So:

\(T_n = S_n - S_{n-1}\)

\(T_n = n^2 - 2n - (n^2 -4n + 3)\)

\(T_n = n^2 - 2n - n^2 +4n - 3\)

Collect Like Terms

\(T_n = n^2 - n^2- 2n +4n - 3\)

\(T_n = 2n- 3\)

The misleading about the data shown on the figure is the clas width

From the question, we have the following parameters that can be used in our computation:

The histogram

On the histogram, we have the following readings

From the above, we can see that

The above readings are not consistent i.e. the class widths are not equal

Hence, the misleading about the data shown on the figure is the clas width

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Using relations in a right triangle, the secant of angle θ is given by:

D. 5/4.

The relations in a right triangle are given as follows:

Using the Pythagorean Theorem, the hypotenuse of the triangle is given as follows:

h² = 9² + 12²

h = sqrt(9² + 12²)

h = 15.

The secant of an angle is 1 divided by the cosine, hence:

Which means that option D is correct.

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