Jeremiah is conducting an investigation about the water cycle. He is given the following
materials:
a lamp
a glass jar that contains water
plastic wrap
Describe how Jeremiah can arrange these materials to create a model that shows the
processes by which water is cycled from a lake into the atmosphere and back to the lake.
Be sure to identify what each material represents in the model.
Answers
The water cycle outlines the continuous water movement in liquid, solid and gaseous state between locations on the Earth's surface.
The glass jar represents the lake while the atmosphere is represented by the space above the water, and the sky is represented by the (clear) plastic wrapArrangement description and Processes;
The processes of the water cycle includes;
Evaporation;CondensationPrecipitationSublimationRunoffInfiltrationThe arrangement of the materials is as follows;
Place the glass jar (the lake) containing water and the lamp (the Sun) side by side, such that the lamp light shines on the water surfaceCover the glass jar by wrapping the plastic wrap (the sky) around it to prevent the escape of water vapor when the water is hot.Switch on the lamp so that it heats the water by radiation heat transferObserved processes;
The processes demonstrated by the above experiment includes;
1) Evaporation: As the water in the glass jar becomes warmer, the level of the water in the jar can be observed to decrease slightly due to evaporation
2) Condensation: Fog formation, Clouds
When hotter, the water surface as seen through the clear plastic wrap becomes less clearer due to evaporation, and condensation of the vapor while floating above the water surface, similar to the clouds seen in the sky.
3. Precipitation: Rain;
The clear plastic wrap covering the top of the glass jar, prevents the movement of the vapor further away, such that the tiny condensed vapor gather together, to form big droplets under the plastic wrap that falls back into the jar, which is similar to the process of rainfall
The above processes are repeated as more water evaporates from the jar condenses on the plastic wrap and falls back into the jar, showing the process by which water is recycled from the lake into the atmosphere and back to the lake.
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Related Questions
A 35 kg boy running at a velocity of 2 m/s to the right jumps onto a trolley at rest with a mass of 70 kg. What is the speed of the trolley and the boy after the boy has jumped in?
Use Gresa to answer the problem.
Answers
The speed of the trolley and the boy after the boy has jumped in is 0.7m/s to the right.
What is momentum?Momentum can be thought of as the power when a body is moving, meaning how much force it can have on another body.
Let v 1 and v 2 be the velocities of the boy and the trolley before the boy jumps in.
v 1=2 and v2=0
The momentum p of the system boy-trolley before the jump,
p = Momentum of Boy + Momentum of trolley
p=35×2+70×0=70 Kg m/sec
Let V be the velocity of trolley ( with the boy in it ), the momentum of the trolley is
p=(35+70)V
By conservation of momentum, momenta are equal before and after interaction.
70=(35+70)V
V=0.7 m/sec to the right
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g A wave on a string has a speed of 13.3 m/s and a period of 0.3 s. What is the frequency of the wave
Answers
Answer:
3.33 Hz
Explanation:
The first step is to calculate the wavelength
= speed × period
= 13.3 × 0.3
= 3.99
Therefore the frequency of the wave can be calculated as follows
= speed/wavelength
= 13.3/3.99
= 3.33 Hz
A charge +Q and a charge -2Q are a distance 3x apart. Point P is on the line joining the charges, at a distance x from +Q.
The magnitude of the electric field produced at P by the charge +Q alone is E.
What is the total electric field at P?
Answers
The total electric field at point P, taking into account both charges, +Q and -2Q, is given by:
E_total = k * |Q| * [(1 / x²) - (4 / (9x²)]).
To determine the total electric field at point P, we must consider the contributions of both charges, +Q and -2Q.
The electric field (E) at P due to a single charge can be calculated using Coulomb's law. An electric field is defined as the force per unit positive charge at a given point. Mathematically, it is expressed as follows:
E = k * (|q| / r²),
where k is the electrostatic constant, q is the charge, and r is the distance from the charge to the point where the electric field is measured.
In this case we have a charge +Q at a distance x from point P. The electric field at point P due to +Q alone can be calculated as:
E1 = k* (|Q|/x2).
Similarly, the electric field at P due to -2Q can be calculated as:
E₂ = k * (|-2Q| / (3x)²) = 4k * (|Q| / (9x²)).
The total electric field (E_total) at point P is the vector sum of the electric fields produced by +Q and -2Q. Because they have opposite charges, the electric fields will have opposite directions.
E_total = E1 - E₂.
By substituting the expressions for E₁ and E₂:
E_total = k * (|Q| / x²) - 4k * (|Q| / (9x²)).
Further simplification:
E_total = k * |Q| * [(1 / x²) - (4 / (9x²)]).
Please note that the direction of the electric field will depend on the signs of the charges (+Q and -2Q) and their relative positions with respect to point P.
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g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements
Answers
Answer:
m = \(\frac{k}{g}\) x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = \(\frac{k}{g}\) x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
Answers
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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A businessman reached is home by riding motorcycle with in 5 minutes by travelling 9 km distance. Then what is has average velocity?
Answers
We can use the formula:
average velocity = displacement / time
Here, the displacement is the distance travelled, which is 9 km, and the time taken is 5 minutes, or 5/60 = 1/12 hours (since there are 60 minutes in an hour). Therefore:
average velocity = 9 km / (1/12 hours)
= 108 km/h
So the average velocity of the businessman is 108 km/h.
C. Using the magnitude and phase response from 6.1A, determine the inductance L that satisfies the follow conditions, given R = 1 kQ. Vin = 1020 V f = 1.3 kHz Vout = 7.07445" V D. Using the magnitude and phase response from 6.1B, determine the inductance L that satisfies the follow conditions, given R = 1 kQ. Vin = 2020" V Vout = 11.22-56" V f = 4.8 kHz
Answers
C. The inductance L that satisfies the given conditions is 0.008472 H.
D. The inductance L that satisfies the given conditions is 0.000349 H.
For part C, we know that the circuit consists of an inductor L and a resistor R in series across a voltage source Vin, and the output is taken across the inductor. The magnitude and phase response can be expressed as,
\(|\dfrac{V_{out}}{V_{in}}| = \dfrac{\omega L}{\sqrt {(R^2 + \omega^2 L^2)}}\)
\(\phi = -tan^{-1}\dfrac {\omega L}{R}}\)
We are given Vin = 1020 V, f = 1.3 kHz, and Vout = 7.07445 V.
Using the given values, we can calculate the angular frequency ω as follows
\(\omega = 2\pi f\\= 2\pi (1.3 \times 10^3)\\ = 8.168\text{ rad/s}\)
Substituting the given values and the value of R = 1 kΩ, we get:
\(|\dfrac{V_{out}}{V_{in}}| = \dfrac{\omega L}{\sqrt {(R^2 + \omega^2 L^2)}}\)
\(\dfrac{7.07445}{1020} = \dfrac{(8.168)L}{\sqrt{1^2 + (8.168L)^2}}\)
Solving for L, we get:
L = 0.008472 H
For part D, we know that the circuit consists of an inductor L and a resistor R in series across a voltage source Vin, and the output is taken across the resistor. The magnitude and phase response can be expressed as,
\(|\dfrac{V_{out}}{V_{in}}| = \dfrac{\omega L}{\sqrt {(R^2 + \omega^2 L^2)}}\)
\(\phi = -tan^{-1}\dfrac {\omega L}{R}}\)
We are given Vin = 2020 V, f = 4.8 kHz, and Vout = 11.22-56 V.
Using the given values, we can calculate the angular frequency ω as follows
ω = 2πf = 30.144 rad/s
Substituting the given values and the value of R = 1 kΩ, we get:
\(|\dfrac{V_{out}}{V_{in}}| = \dfrac{\omega L}{\sqrt {(R^2 + \omega^2 L^2)}}\)
\(\dfrac{11.22-56}{2020} = \dfrac{ 1}{\sqrt{1^2 + (30.144L)^2}}\)
Solving for L, we get:
L = 0.000349 H
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You are moving into an apartment and take the elevator to the 6th floor suppose your weigh is 685N and that of your belongings is 915N. Determine the work done by the elevator is lifting you and your belongings up to the 6th floor 15.2m at acontant velocity
Answers
Basically answer is -1600(15.2)g
Why constant velocity dosnt matter is because the net work is 0 not the gravity work
Sounds are vibrations transmitted through the air or another medium. There are three
physical characteristics of a sound, each giving rise to a perceptual characteristic of
the sound. For example, one of these physical characteristics is frequency, which
gives rise to pitch perception. Define and describe all three characteristics of the
sound stimulus and the perceptions to which they give rise. Detail how each physical
characteristic relates to the associated perception.
Answers
Answer:
Explanation:
The three physical characteristics of a sound stimulus and their corresponding perceptual characteristics are as follows:
1. Frequency: Frequency refers to the number of vibrations or cycles per second that occur in a sound wave. It is measured in hertz (Hz). Frequency gives rise to the perception of pitch. Pitch is the subjective perception of how high or low a sound is. Higher frequencies are perceived as higher pitches, while lower frequencies are perceived as lower pitches. For example, a sound wave with a higher frequency would be perceived as a higher-pitched sound, like a whistle, whereas a sound wave with a lower frequency would be perceived as a lower-pitched sound, like a deep bass note.
2. Amplitude: Amplitude is the magnitude or intensity of a sound wave and is usually measured in decibels (dB). It represents the amount of energy carried by the sound wave. Amplitude gives rise to the perception of loudness. Loudness is the subjective perception of the strength or intensity of a sound. Greater amplitudes are perceived as louder sounds, while smaller amplitudes are perceived as quieter sounds. For instance, a sound wave with a higher amplitude would be perceived as a louder sound, like a thunderclap, whereas a sound wave with a lower amplitude would be perceived as a softer sound, like a whisper.
3. Timbre: Timbre refers to the quality or tone color of a sound. It is the characteristic that allows us to distinguish between sounds with the same pitch and loudness. Timbre is influenced by the complex combination of different frequencies, amplitudes, and waveforms present in a sound wave. It gives rise to the perception of the unique "sound signature" of an instrument or voice. For example, a guitar and a piano playing the same note at the same loudness would still sound different due to their distinct timbres. Timbre enables us to identify and differentiate between various musical instruments and voices.
In summary, frequency determines the pitch perception of a sound, amplitude influences the perception of loudness, and timbre defines the unique quality or tone color of a sound. These physical characteristics directly relate to the corresponding perceptual characteristics, providing us with a rich and diverse soundscape in our auditory experience.
A ray of light makes an angle of 35 with a plane mirror ,what is the reflection
Answers
When a ray of light strikes a plane mirror, the angle of reflection is equal to the angle of incidence.
In this case, the ray of light makes an angle of 35 degrees with the plane mirror. Therefore, the angle of reflection will also be 35 degrees. To understand why this happens, we need to consider the properties of reflection. When light interacts with a smooth surface like a mirror, it follows the law of reflection.
According to this law, the incident ray, the reflected ray, and the normal (a line perpendicular to the mirror's surface) all lie in the same plane. The angle of incidence is the angle between the incident ray and the normal, measured on the side of the normal where the light is coming from. In this case, the angle of incidence is 35 degrees.
According to the law of reflection, the angle of reflection is the angle between the reflected ray and the normal, also measured on the side of the normal where the light is coming from. Since the incident and reflected rays are on opposite sides of the normal, the angle of reflection is also 35 degrees.
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I WILL MARK YOU AS BRAINLIEST!!! An object is launched straight up into the air with an initial velocity of 40 meters per second, from a height 30 m above the ground. Assuming that gravity pulls it down, changing its position by about 4.9 /2, after how many seconds will the object hit the ground? Enter your answer as a number rounded to the nearest tenth, such as: 42.5
Answers
Answer:
8.9 seconds
Explanation:
The height of the object at time t is:
y = h + vt − 4.9t²
where h is the initial height, and v is the initial velocity.
Given h = 30 and v = 40:
y = 30 + 40t − 4.9t²
When y = 0:
0 = 30 + 40t − 4.9t²
4.9t² − 40t − 30 = 0
Solving with quadratic formula:
t = [ -(-40) ± √((-40)² − 4(4.9)(-30)) ] / 2(4.9)
t = [ 40 ± √(1600 + 588) ] / 9.8
t = 8.9
It takes 8.9 seconds for the object to land.
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally insulated chamber. For water L = 3.33 x 105 J/kg. The specific heat of ice is 2090 J/(kg°C) and of water 4186 J/(kg°C). How much does the ice heat up in order to bring the water down to 0°C?
A. 0.04°C
B. 0.4°C
C. 4°C
D. 10°C
E. 20°C
Answers
Answer:
Explanation:
heat lost by water will be used to increase the temperature of ice
heat gained by ice
= mass x specific heat x rise in temperature
1 x 2090 x t
heat lost by water in cooling to 0° C
= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .
= 1 x 2 x 4186
8372
heat lost = heat gained
1 x 2090 x t = 8372
t = 4°C
There will be a rise of 4 degree in the temperature of ice.
The increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
The given parameters;
mass of the ice, m₁ = 1 kgtemperature of the ice, t₁ = -20°Cmass of the water, m₂ = 1 kgtemperature of the water, t₂ = 2 °CApply the principle of conservation of energy to determine the increase in the temperature of the ice to bring the water to 0 °C.
Heat absorbed by the ice = Heat lost by water
\(Q_{ice} = Q_{w}\\\\mc\Delta t_{ice} = mc \Delta t_{w}\\\\1 \times 2090 \times \Delta t = 1 \times 4186 \times (2-0)\\\\2090\Delta t = 8372\\\\\Delta t = \frac{8372}{2090} \\\\\Delta t = 4 \ ^0C\)
Thus, the increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
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A bus has a speed of 1.3 m/s and a mass of 12,000 kg. A baseball has a
speed of 44.7 m/s and a mass of 0.145 kg. What is the kinetic energy of the
bus?
Answers
Answer:
find it yourself too lazy for math but here's the step
Explanation:
it's the object mass multiplied by the velocity.
1. The kinetic energy of a car is 8 106 J as it travels along a horizontal road. How much work is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J
Answers
The power to stop the car with kinetic energy of a car is \(8*10^{6} J\) as it travels along a horizontal road is \(8*10^{5} watt\), option B
What is Kinetic energy ?Kinetic energy can be seen as one that is been recorded when an object is able to move from a place , in a broad term we can say this is the energy that can be attributed to that of someone leaving a place and go to another place hence we can see it as the one in the motion.
The definition of energy as the "power to accomplish work" refers to the capacity to apply a force that moves an object. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. The two types can be attributed to the one we know which are kinetic and potential energy.
\(Power \frac{Energy}{time}\)
\(Energy = 8*10^{6} J\)
\(time = 10 s\)
\(Power = \frac{8*10^{6} J}{10}\)
\(power = 8*10^{5} watt\)
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proper question;
The kinetic energy of a car is 8 × 106 J as it travels along a horizontal road. How much power is required to stop the car in 10 s? (A) zero joules (B) 8 105 J (C) 8 107 J (D)8 104 J (E) 8 106 J
A cart is pushed ahead for 3.5 s with a force of 360 N. Determine the change in momentum of the cart.
Answers
advantage of compound pendulum
Answers
The known values are given in the table below them. Find the missing values.
Answers
The value of the missing resistance, R₃ = 10.35 ohms.
The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.
The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.
What is the value of missing component of the circuit?The values of the missing component of the circuit is calculated by applying the following formula.
The total resistance of the circuit;
For R₂, R₃, 1/R = 1/R₂ + 1/R₃
1/R = 1/12 + 1/R₃
1/R = (R₃ + 1)/(12R₃)
R = 12R₃ / (R₃ + 1)
For, R₁, R₂ and R₃, total resistance;
R = 12R₃ / (R₃ + 1) + R₁
R = [12R₃ / (R₃ + 1)] + 2
R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)
R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)
R = (14R₃ + 2 ) / (R₃ + 1)
The total current in circuit is calculated as;
I = V/R
I = 30 / R
I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)
I = (30R₃ + 30) / (14R₃ + 2) ------- (1)
The voltage in parallel circuit is the same
V₂ = V₃ = 24 V
V₃ = IR₃
24 = IR₃
I = 24/R₃ --------- (2)
Solve (1) and (2) together as follows;
24/R₃ = (30R₃ + 30) / (14R₃ + 2)
30R₃² - 306R - 48 = 0
Solve the quadratic equation, using formula method.
R₃ = 10.35 ohms
I₃ = V₃/R₃
I₃ = 24 V / 10.35
I₃ = 2.32 A
If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V
The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A
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an ac generator is connected across the terminals of a 3.25-µf capacitor. determine the frequency at which the capacitive reactance is 375 ω.
Answers
The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.
Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).
From the given,
The capacitive reactance (Xc) = 375ω
capacitance (C) = 3.25μF
capacitive reactance Xc = 1/(2π×f×C)
Frequency (f) = 1/(2π×Xc×C)
= 1/(2×3.14×375×3.25×10⁻⁶)
= 131 s⁻¹.
Thus, the frequency of the capacitive reactance is 131 s⁻¹.
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A car drove 200 km east on an interstate highway, then was finally able to make an
exit and drove for another 70 km to the north before reaching their destination.
What was the direction of car's resultant displacement?
Answers
Answer:
70.66°Explanation:
To find the direction of the displacement vector, we have to solve for the ratio of both displacements, and furthermore the inverse tangent of the ratio.
Given data
200km east represents the x axis
70 km north represents y axis
the direction of the resultant is given as
∅= tan-1x/y
∅=tan-1 200/70
∅= tan-120/7
∅= tan-12.85
∅= 70.66°
hence the direction of the resultant is 70.66°
what is sufficient condition for being alive?
Answers
The sufficient condition for being alive is growing, taking in nutrients and reproducing.
The biological point of being alive means being able to,
GrowTake in nutrientsReproduceThe physical point of being alive means being able to breathe. But philosophically being alive has a lot of different meanings such as consciousness, self awareness, activeness, alertness etc.
Therefore, the sufficient condition for being alive is growing, taking in nutrients and reproducing.
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You are holding a 200-g apple.
What is the force that you exert on the apple?
What is the force that the apple exerts on you? Support your answer with free
body diagrams.
Answers
On the apple, we apply "antigravitational force."
The apple exerts "gravitational force" on us.
The gravitational attraction, an attractive force whose magnitude is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another, draws all mass-containing things together.
You can never decrease the gravitational pull produced by adding mass. It is possible for gravitational forces acting in opposition to one another to cancel one another out and leave no net force. It would be conceivable for gravity to push objects instead of always dragging them if it weren't always additive.
A place or thing being free from the pull of gravity is the goal of the hypothetical phenomena known as anti-gravity. It doesn't mean balancing the force of gravity with another force, like electromagnetism or aerodynamic lift, or the lack of weight under gravity felt in free fall or orbit.
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person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
Answers
Let the circumference of the circle be 10L.
A moves at 10L/2 = 5L per hour
B moves at 10L/5 = 2L per hour
Therefore it takes 10L/(5L+2L) = 10/7 hours
Normal forces are applied uniformly over the surface of a spherical volume of water whose radius is 20.0 cm. If the pressure on the surface is increased by 200 MPa, by how much does the radius of the sphere decrease?
Answers
The radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.
To determine the decrease in radius of the spherical volume of water when the pressure on its surface is increased, we can use the equation relating pressure to the radius of a sphere:
ΔP = K/R
Where ΔP is the change in pressure, K is a constant, and R is the radius of the sphere.
In this case, we're given that ΔP (change in pressure) is 200 MPa and the initial radius R is 20.0 cm. We need to find the change in radius ΔR.
We can rearrange the equation to solve for ΔR:
ΔR = K/ΔP
Now, we need to determine the value of the constant K. The constant K depends on the bulk modulus of the material, which is a measure of its resistance to compression. For water, the bulk modulus is approximately 2.2 GPa (gigapascals).
Substituting the values into the equation, we have:
ΔR = (2.2 GPa) / (200 MPa)
To simplify the calculation, we need to convert the units so that they are consistent. Let's convert GPa to MPa:
ΔR = (2.2 GPa * 1000 MPa/GPa) / (200 MPa)
ΔR = 11 mm
Therefore, the radius of the sphere decreases by 11 mm when the pressure on its surface is increased by 200 MPa.
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x A
Which wave BEST represents a sound that a person and a dog can hear changing to a sound that only a dog can hear?
x
A A
BB
CC
D.
xD D
m
Answers
Explanation:
ultrasound wave have a frequency higher than the upper limit for human hearing
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s. What speed does it have when it slides back down to its starting point?
Answers
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s
What is Friction?The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.
using work energy theorem ,
change in kinetic energy = work done by frictional force
\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) = μmghcos30°
where mass is m=200g
x is speed with which it slides back
y is speed at top of metal ramp=3.8 m/s
μ is coefficient of kinetic friction=0.3
g is gravity = 9.8m/\(s^{2}\)
h is height to which hockey puck is reached on metal ramp=1.18m
Substituting the values and solving for speed x,
x=2.36m/s
speed it will have when it slides back down to its starting point is 2.36m/s
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I chose A. is it right?
If a particular cell is known to be round and incapable of producing its own food, which one of these organelles would you assume the cell must have?(1 point)
CENTRAL VACUOL
plasma membrane
cell wall
chloroplast
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Answer:
nice try but it's plasma membrane
The cell that is known to produce their own food should have a central vacuole. The correct option is A.
What is a vacuole?A vacuole is a cell organelle that is membrane-bound. Vacuoles are generally small in animal cells and help to sequester waste products.
Vacuoles in plant cells help to retain water balance. A solo vacuole can sometimes take up the maximum of the interior space of a plant cell.
Plant cells have much larger vacuoles than animal cells. When a plant cell stops growing, it usually has one very large vacuole.
That vacuole can sometimes take up more than half of the cell's volume. The vacuole can hold a lot of water or food.
The given cell is known to be round and incapable of producing its own food, so it must be having a central vacuole.
The correct option is A.
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An emf is induced by rotating a 1060 turn, 20.0 cm diameter coil in the Earth's 5.25 ✕ 10−5 T magnetic field. What average emf (in V) is induced, given the plane of the coil is originally perpendicular to the Earth's field and is rotated to be parallel to the field in 10.0 ms? V †
Answers
Answer:
The average emf induced in the coil is 175 mV
Explanation:
Given;
number of turns of the coil, N = 1060 turns
diameter of the coil, d = 20.0 cm = 0.2 m
magnitude of the magnetic field, B = 5.25 x 10⁻⁵ T
duration of change in field, t = 10 ms = 10 x 10⁻³ s
The average emf induced in the coil is given by;
\(E = N\frac{\delta \phi}{dt} \\\\E = N\frac{\delta B}{\delta t}A\)
where;
A is the area of the coil
A = πr²
r is the radius of the coil = 0.2 /2 = 0.1 m
A = π(0.1)² = 0.03142 m²
\(E = \frac{NBA}{t} \\\\E = \frac{1060*5.25*10^{-5}*0.03142}{10*10^{-3}} \\\\E = 0.175 \ V\\\\E = 175 \ mV\)
Therefore, the average emf induced in the coil is 175 mV
Larry the Rock was lonely for multiple years. The inertia that Larry possessed intimated those who walked past by it, therefore people never moved Larry.
Larry constantly watched people and cars accelerate past him but sadly he has never had the opportunity to experience acceleration.
But one day, David decides to let Larry experience acceleration and tried to push him. His friend Pancho heard about this and decided to help out. But
because Pancho was not listening in Physics class, he was pushing Larry from the opposite side of David with an equal amount of force and Larry was sad
he still did not get to move.
What type of Equilibrium is Larry going through?
O Static Equilibrium
O Kinetic Equilibrium
O Dynamic Equilibrium
O Geo Equilibrium
O Francesca Equilibrium
Answers
First option is correct.Larry the Rock is going through Static Equilibrium.
In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.
Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.
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The air in a room measuring 8 ft x 9 ft x 12 ft is at 80°F and 1 atm. Determine the mass of the air, in lb, and its weight, in lbf, if g = 32.0 ft/s2
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The air in a room measuring 8 ft x 9 ft x 12 ft is at 80°F and 1 atm. The mass of the air is 2.46 lb and its weight is 78.7 lbf.
Using the Ideal Gas Law, PV = nRT, Where:P = pressure, V = volume, R = universal gas constant,
T = temperature
n = number of moles of gas, m = mass of the gas
We can find the number of moles of gas as:
n = PV/RT
where,P = 1 atm, V = 864 ft3, T = 80 + 460 = 540 R (Temperature in Rankine scale)
R = 1545.3 ft·lbf/(lb·R)
Substituting the values:
n = (1 atm x 864 ft3) / (1545.3 ft·lbf/(lb·R) x 540 R)
n = 0.0847 lb-mole
To find the mass of the air,
m = n x M
where,M = molecular weight of air = 28.97 lb/lb-mole
m = 0.0847 lb-mole x 28.97 lb/lb-mole
m = 2.46 lb
The weight of the air is given by the formula,
W = mg
where,g = 32.0 ft/s2, m = 2.46 lb
W = 2.46 lb x 32.0 ft/s2
W = 78.7 lbf
Therefore, the mass of the air is 2.46 lb and its weight is 78.7 lbf.
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