Jenny is watching her favorite soccer team playing a match the odds against her favorite team winning are 7/10 what is the probability? Of her team winning

Correct option is A, The temperature started at 78°F and decreased by 6°F. Then the temperature decreased by 5°F.

An expression, often known as a mathematical expression, is a finite collection of symbols that are well-formed in accordance with context-dependent principles.

You must substitute a number for each variable and carry out the arithmetic operations in order to evaluate an algebraic expression. Since 6 + 6 equals 12, the variable x in the example above is equal to 6. If we are aware of the values of our variables, we can substitute those values for the original variables before evaluating the expression.

An expression is, for instance, 3x - 2. While an equation, on the other hand, denotes the connection between two separate expressions via an equal to sign, One such equation is 3x - 2 = 5 + x.

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The general solution to the differential equation is given by: y = C1e^(3t/4) + C2e^(-t/5), where C1 and C2 are constants to be determined.

To find the general solution of the given second-order differential equation:

20y'' - 11y' - 3y = 0

We can start by assuming a solution of the form y = e^(rt), where r is a constant to be determined.

First, let's find the derivatives of y with respect to t:

y' = re^(rt)

y'' = r^2e^(rt)

Now substitute these derivatives into the differential equation:

20(r^2e^(rt)) - 11(re^(rt)) - 3e^(rt) = 0

Factor out e^(rt):

e^(rt)(20r^2 - 11r - 3) = 0

Since e^(rt) is never equal to zero, we can set the expression inside the parentheses equal to zero:

20r^2 - 11r - 3 = 0

Now we can solve this quadratic equation for r. Factoring or using the quadratic formula, we find two roots:

r1 = 3/4

r2 = -1/5

This solution contains two arbitrary constants, representing the degrees of freedom in the general solution.

To obtain a particular solution, we need initial conditions or boundary conditions specified in the problem. By substituting specific values for t and y into the general solution, we can determine the values of the constants C1 and C2.

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The estimator is unbiased only when the true parameter value matches the mean of the sampling distribution; otherwise, it is biased.

In part (a), the estimator is biased because the mean of the sampling distribution is different from the true parameter value. In part (b), the estimator is unbiased as the mean matches the true parameter value. In part (c), the estimator is biased again because the mean does not align with the true parameter value.

Bias refers to the tendency of an estimator to consistently overestimate or underestimate the true parameter value. An unbiased estimator has a sampling distribution with a mean that equals the true parameter value. In this case, we observe that the estimator is only unbiased when the true parameter value matches the mean of the sampling distribution. When the true parameter value deviates from the mean, the estimator becomes biased.

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Answer:

C. x = 11/c

Step-by-step explanation

Add 4 to both sides

cx-4+4=7+4

Simplify

cx=11

Divide both sides by c

cx/c=11/c

11/c

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches has height of triangular base as 9√2 inches.

We are given that.

Length of equilateral triangle = a =18 inches

Base is an equilateral triangle.

height of the triangular base of the pyramid

h= a.cosθ

Each angle of equilateral triangle is equivalent to 60 degree

θ = 60/2

θ = 30 degree

Substitute the values,

Height of triangular base of the pyramid,

h=18.cos30

h = 18x √3/2 in

Using the value of

Cos30 = √3/2

Height of triangular base of the pyramid, h= 9√3 inches

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The original amount invested for certain sum was $23750.

Let's solve the given problem: Given that A certain sum is invested at 4% annual interest. If $1400 is added to the account, the annual interest will amount to $196.

We are to find how much was originally invested. Let's assume the original amount was "x". Then, Total amount after adding $1400 = x + 1400 Interest at 4% = 4/100 = 0.04

According to the question, we have ; 0.04x + 0.04(1400 + x) = 1960.04x + 0.04x + 56 = 1960.08x = 1900x = $23750

Therefore, the original amount invested was $23750.

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Answer:

i need help to

Step-by-step explanation:

lol

Constraints are simply the subjects of an objective function.

The inequality that represents the constraint is: \(12x + 6y \le 20\)

Represent the number of hats with x, and the number of scarves with y.

From the question, we have:

So, the equation of the total time spent is:

\(Time = 12x + 6y\)

This time spent is not more than 20 hours.

So, the inequality is

\(12x + 6y \le 20\)

Hence, the inequality that represents the constraint is: \(12x + 6y \le 20\)

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Answer:

2/3 probability or 66%

Step-by-step explanation:

hope this helps!!

Answer:

1. -5.5   2. 5   3.  5, 5.5

Step-by-step explanation:

For #1 just look at what point it would be towards the y- axis.

For #2 you want to kinda estimate what it would be between.

And lastly #3 they want to see the exact coordinates for Q so, look at the x axis first they the y axis. Remember Run then Jump

cause a dictionary contains all known words including dictionary..my turn!.look in the comments!

Answer:

f^-1 = 36

Step-by-step explanation:

\(f(x) = (\frac{x}{6} ) -5\\f^{-1} (1) = ?\\f^-^1= \\y = (\frac{x}{6} ) -5\\ y = \frac{x}{6}-5\\y+5 = x/6\\Multiply -through- by ; 6\\ 6(y+5) =x\\f^-^1(x) = 6(x+5)\\f^-^1(1) = 6(1+5)\\ = 6(6)\\f^-^1 (1) = 36\)

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

The expected value of a dice roll is the average outcome of all the possible results.

For example, if you roll a six-sided die, you can expect to get a 3.5 on average since there are an equal number of each of the six possible outcomes (1, 2, 3, 4, 5, 6). Mathematically, you can calculate the expected value of a dice roll by multiplying each possible outcome by its probability of occurring and then adding all of the values together. For example, if you roll a six-sided die, the expected value is (1/6) + (2/6) + (3/6) + (4/6) + (5/6) + (6/6) = 3.5. In other words, the expected value of a dice roll is 3.5.

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The domain of the function is negative infinity (-∞) to positive infinity (∞) because an exponent can be any real number.

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function is defined.

This ultimately implies that, a domain simply refers to the set of all possible input numerical values (x-values) to a function. Additionally, the domain of a graph consist of all the input numerical values (x-values) that are located on the x-coordinate.

By critically observing the graph of this function (see attachment), we can reasonably and logically deduce the following about its domain:

Domain = [-∞, ∞].

In conclusion, the range of this function is from zero (0) to positive infinity (∞) because 4^x is always positive.

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Complete Question:

Use the graph of the function y = 4x to answer the following questions. The domain of the function is _____ to _____ because an exponent can be any real number.

On a coordinate plane, an exponential function approaches the x-axis in quadrant 2 and increases exponentially in quadrant 1.

Answer:

\(\frac{-7}{24}\)=r

Step-by-step explanation:

3÷8=r+2÷3

\(\frac{3}{8}\)=r+\(\frac{2}{3}\)

\(\frac{3}{8}\)-\(\frac{2}{3}\)=r

(make the denominators same)(LCM of 8 and 3=24)

\(\frac{3}{8}\)(\(\frac{3}{3}\))+\(\frac{2}{3}\)(\(\frac{8}{8}\))=r

\(\frac{9}{24}\)-\(\frac{16}{24}\)=r

\(\frac{9-16}{24}\)=r

\(\frac{-7}{24}\)=r

the derivative of the function y = (ln(x + 4))x using logarithmic differentiation is given by y' = (ln(x + 4))x * [ln(ln(x + 4)) + (1/ln(x + 4)) * (1/(x + 4))].

To find the derivative of the function y = (ln(x + 4))x using logarithmic differentiation, we can follow these steps:

Step 1: Take the natural logarithm of both sides of the equation:

  ln(y) = ln((ln(x + 4))x)

Step 2: Use the logarithmic property ln(a^b) = b ln(a) to simplify the right-hand side of the equation:

  ln(y) = x ln(ln(x + 4))

Step 3: Differentiate both sides of the equation implicitly with respect to x:

  (1/y) * y' = ln(ln(x + 4)) + x * (1/ln(x + 4)) * (1/(x + 4))

Step 4: Simplify the expression on the right-hand side:

  y' = y * [ln(ln(x + 4)) + (1/ln(x + 4)) * (1/(x + 4))]

Step 5: Substitute the original expression of y = (ln(x + 4))x back into the equation:

  y' = (ln(x + 4))x * [ln(ln(x + 4)) + (1/ln(x + 4)) * (1/(x + 4))]

Therefore, the derivative of the function y = (ln(x + 4))x using logarithmic differentiation is given by y' = (ln(x + 4))x * [ln(ln(x + 4)) + (1/ln(x + 4)) * (1/(x + 4))].

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The limit of the given expression as x approaches 1 is 0.

To evaluate the limit of the given expression as x approaches 1, we can use L'Hopital's rule, which states that if the limit of a quotient of functions is of the form 0/0 or ±∞/±∞, then the limit can be found by taking the derivative of the numerator and denominator and evaluating the new quotient at the same point.

Using L'Hopital's rule on the given expression, we get:

lim x→1 [5x/(x-1) - 5/x] = lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)]

Plugging in x = 1 directly to this expression, we get:

lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)] = (5 - 10 + 5)/(1 - 1) = 0/0

Since the limit is still in an indeterminate form, we can apply L'Hopital's rule once again:

lim x→1 [(5x^2 - 10x + 5)/(x^2 - x)] = lim x→1 [(10x - 10)/(2x - 1)] = 0

Therefore, the limit of the given expression as x approaches 1 is 0.

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Check the picture below.

Answer:

No. It is not possible to construct a triangle with lengths of its sides 4cm, 5cm and 9cm because the sum of two sides is not greater than the third side:

5 + 4 is not greater than 9.

Step-by-step explanation:

May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 10 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

Answer:

Its 4 but ima just explain it :- )

Step-by-step explanation:

okay so what you gotta do is 60 - 47.50=12.5/3=4.166666

4.1666 you turn into 4

Maximum possible number of gigabytes 47.50+ 3x ≤ 60

The number of maximum gigabytes of data he can use would be 4.

Inequality is defined as the relation which makes a non-equal comparison between two given functions. It shows a relationship between two numbers or two expressions.

We have,Cost of flat per month = $47.50

Cost per gigabyte = $3

Maximum bill per month = $60

Maximum possible number of gigabytes as;

47.50 + 3x ≤ 60

Where x is the number of gigabytes.

Solve for x;

47.50 + 3x ≤ 60

3x ≤ 60 - 47.50

3x ≤ 12.5

x ≤ 47.50/3

x ≤ 4.1

x ≤ 4

This means that the number of maximum gigabytes of data he can use is 4.

We can cross-check.

47.50 + 3 x 5 ≤ 60

47.50 + 15 ≤ 60

61 ≤ 60 ( not possible )

So,

47.50+ 3 x 4 ≤ 60

47.50 + 12 ≤ 60

58 ≤ 60

Thus,

The number of maximum gigabytes of data he can use is; 4.

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Answer:

NMHGJMHBNKJ6T76 5745

Step-by-step explanation:

7657457657776767

The effect estimation requires more than simple regressions of "Quality of Care" on "Shift Hours" (Part 1) or with "Hospital Characteristics" (Part 2). Including "Tiredness" (Part 3) or using variable (Part 5) is necessary.

To estimate the causal effect of changing shift hours on quality of care, several factors must be considered. Regression analysis with just a constant and "Shift Hours" (Part 1) fails to account for confounding variables, leading to biased estimates. Including "Hospital Characteristics" (Part 2) still overlooks omitted variable bias and endogeneity issues.

However, by adding "Tiredness" to the regression (Part 3), the direct and indirect effects of shift hours on quality of care can be estimated. The coefficient of "Shift Hours" represents the direct causal effect, while the coefficient of "Tiredness" captures the mediating effect. Regressing "Quality of Care" solely on "Policy" (Part 4) neglects confounders.

When "Hospital Characteristics" are unobserved, instrumental variable estimation (Part 5) can address endogeneity by identifying an instrumental variable unrelated to quality of care but affecting shift hours.

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The distance between the Woozy Wheel and the Roller Rail is 13 units.

To determine the distance between the Woozy Wheel and the Roller Rail, we can use the distance formula in the coordinate plane.

The coordinates of the Woozy Wheel are (-14, 1), and the coordinates of the Roller Rail are (-2, -4).

Using the distance formula, the distance (d) between two points (x₁, y₁) and (x₂, y₂) is given by:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

Substituting the coordinates of the Woozy Wheel and the Roller Rail into the formula:

d = √((-2 - (-14))² + (-4 - 1)²)

= √(12² + (-5)²)

= √(144 + 25)

= √169

= 13

Therefore, the distance between the Woozy Wheel and the Roller Rail is 13 units.

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Answer:

$6.50

Step-by-step explanation:

25 - 6.25 = 18.75

18.75 - 3.75 = 15

15 - 8.50 = 6.50

The equation that could be used to find q is q = 110-0.15(110) where q equal the price of a quarter-page ad after the markdown.

According to the question,

We have the following information:

Cost of a quarter-page ad cost = $110

Mark down in the price = 15%

Now, q represents the price of a quarter-page ad after the markdown.

(Note that when we remove the sign of % means that the number has to be divided by 100.)

So, the equation will be the difference of the markdown price from the original price:

q = 110-(15/100)110

q = 110-0.15*110

q = 110-0.15(110)

Hence, the correct option is the third one.

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Answer:

all together there is 141 candies in all

The velocity of a particle = i + 2t j

The acceleration of a particle = 2 j

The speed of a particle = \(\sqrt{1 + 4t^{2} }\)

Here,

The position function is, \(r (t ) = ti + t^{2} j +2k\)

We have to find, the velocity, acceleration, and speed of a particle with the given position function.

What is Velocity of a particle with the given position function?

The instantaneous velocity v(t) of a particle is the derivative of the position with respect to time. That is, v(t)=dx/dt.

Now,

The position function is, \(r (t ) = ti + t^{2} j +2k\)

The velocity of a particle = \(\frac{d r(t)}{dt}\)

\(r (t ) = ti + t^{2} j +2k\)

\(\frac{d r(t)}{dt} = i + 2t j\)

The acceleration of a particle = \(\frac{d^{2} r(t)}{dt^{2} }\)

\(r (t ) = ti + t^{2} j +2k\)

\(\frac{d r(t)}{dt} = i + 2t j\)

\(\frac{d^{2} r(t)}{dt^{2} }= 2j\)

The speed of a particle = \(| \frac{d r(t)}{dt}| = |v(t)|\)

\(\frac{d r(t)}{dt} = i + 2t j\)

\(|v(t)|=\sqrt{1 + 4t^{2} }\)

Hence, The velocity of a particle = \(i + 2t j\)

The acceleration of a particle = \(2 j\)

The speed of a particle = \(\sqrt{1 + 4t^{2} }\)

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Answer:

23%

Step-by-step explanation:

Multiplying by 1.23 is the same as increasing by 23%. So, the number that should go in the space is 23.

percentage, a relative value indicating hundredth parts of any quantity.

Percentage increase = (New value - Old value) / Old value x 100%

If multiplying by 1.23 is the same as increasing by a certain percentage, then we can set the new value equal to 1.23 times the old value, and solve for the percentage increase.

Let x be the percentage increase we are looking for. Then we have:

1.23 x Old value = Old value + (x / 100%) x Old value

Simplifying this equation, we get:

0.23 × Old value = (x / 100%) x Old value

Dividing both sides by Old value, we get:

0.23 = x / 100%

Multiplying both sides by 100%, we get:

x = 23%

Therefore, multiplying by 1.23 is the same as increasing by 23%. So, the number that should go in the space is 23.

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The maximum value of the function is approximately 1.724 and the minimum value is approximately -1.724.

To find the maximum and minimum values of the function y = sin x + sin 2x, we can first take its derivative with respect to x:

y' = cos x + 2 cos 2x

Then, we can set y' equal to zero and solve for x:

cos x + 2 cos 2x = 0

We can use a graphing calculator to find the solutions to this equation, which are approximately x = 0.285 and x = 2.857. We can then evaluate the original function at these values to find the maximum and minimum values:

y(0.285) ≈ 1.724

y(2.857) ≈ -1.724

Therefore, the maximum value of the function is approximately 1.724 and the minimum value is approximately -1.724.

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The difference in the area of the square 'a' and 'b' as per given side-length is equal to 8 ( x + 1 ) square meters.

Side length of square 'a' = (2x + 1) meters

Side length of square 'b' = ( 2x + 1 + 2 ) meters

                                         = ( 2x + 3 ) meters

Area of a square 'a' = ( side length )²

                                = ( 2x + 1 )²

Area of a square 'b' = ( side length )²

                                = ( 2x +3 )²

Difference in the area of the squares = ( 2x +3 )² - ( 2x +1 )²

                                                             = ( 2x + 3 -2x -1 )( 2x + 3 + 2x + 1 )

                                                             = ( 2 ) ( 4x + 4 )

                                                             = 8 ( x + 1 )

Therefore, the difference in the area of the given squares is equal to    8 ( x + 1 ) square meters.

The side length of square 'a' is (2x + 1) meters. The side length of square 'b' is 2 meters longer than that of square a. find the difference in the area of the squares.

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