Jayce goes on a bike ride to Luc’s house. What will be his velocity if he is traveling at 31 km/h for 12.5 minutes?

Answer:If the masses are different, the lighter ice skater will accelerate faster than the ice skater with more mass.

Explanation:

The lighter skater will accelerate more quickly than the heavier skater if there are mass discrepancies.

According to Newton's third law, the action and reaction forces in any force interaction must be equal and moving in the opposite directions. These pressures, nevertheless, affect a variety of items. In this case, each skater will experience the same amount of force, and if any other horizontal forces, such as friction, operating on each skater in the opposite direction from the pushing force are less than the pushing force, each will accelerate in that direction. The two skater system's center of mass will remain where it is if there is little to no friction to prevent the skaters from moving.

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Answer:

6.78 m/s

Explanation:

We can use the law of conservation of momentum to solve this problem. According to this law, the total momentum of a system is conserved in the absence of external forces. In this case, the system consists of the truck and the parked car.

Before the collision, the momentum of the truck is given by:

p1 = m1 * v1 = 130 kg * 12 m/s = 1560 kg*m/s

The momentum of the parked car is zero since it is not moving.

The total momentum of the system before the collision is therefore:

p1_total = p1 + p2 = 1560 kg*m/s

After the collision, the two objects stick together and move with a common velocity, which we will call v_final. The total mass of the system is:

m_total = m1 + m2 = 130 kg + 100 kg = 230 kg

The total momentum of the system after the collision is:

p2_total = m_total * v_final

According to the law of conservation of momentum, p1_total = p2_total. Therefore:

1560 kg*m/s = 230 kg * v_final

Solving for v_final, we get:

v_final = 1560 kg*m/s / 230 kg = 6.78 m/s

Therefore, the final velocity of the two objects after the collision is 6.78 m/s.

Explanation:

m1 of the truck: 130 kg

m2 of the car: 100 kg

v1 of the truck: 12 m/s

vf?

use the formula:

(m1×v1) + (m2×v2) = (m1+m2)vf

so

\(vf = \frac{(m1 \times v1) + (m2 \times v2)}{(m1 + m2)} \)

\(vf = \frac{(130 \times 12) + (100 \times 0)}{(130 + 100)} \)

vf = 1560 ÷ 230 = 6,7 m/s

Answer:

I don't know sorry' please

Answer:

K.E=1/2m*v^2

2*K.E/v^2=m

Mass=32×2/(4)^2

Mass=64/16

Mass=4kg

Explanation:

Answer:

Light travels at 3.0 x 108 m/s in a vacuum.

Explanation:

Light travels at 3.0 x 108 m/s in a vacuum.

The airspeed of the plane for this flight would be 240 miles per hour (mph) and the wind rate is 35 mph.

The plane is accounting for the 2,100-mile flight in 8.75 hours, so it must travel at a speed of 240 mph in order to make the journey in that time. This means that if the wind is blowing from Los Angeles to Atlanta, it must be blowing at a speed of 35 mph, in the opposite direction of the plane.

This is calculated by subtracting the airspeed of the plane from the average return trip speed of the plane and wind combined of 325 mph (accounting for the 5 hour return flight).

In conclusion, if the wind were blowing from Los Angeles to Atlanta at a constant rate during the return trip for the plane, the airspeed of the plane is 240 mph and the wind rate is 35 mph.

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Following are the answers:- (a)speed of an airplane is continuous.

(b)age of a college professor chosen at random is continuous.

(c)number of books in the college bookstore is discrete.

(d) weight of a football player chosen at random is continuous.

(e) number of lightning strikes in rocky mountain national park on a given day is discrete.

Discrete variables are ones with a finite number of possible values.

A continuous variable is a variable that can take either an infinite or an uncountable number of values.

Discrete variables are ones with a finite number of possible values. This is not true of an airplane's speed, which varies constantly. As a result, an airplane moves at a constant speed.

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a. The cost per hour of producing 1000 gumballs is the sum of the hourly cost of using two gumball presses and the hourly wage paid to the worker who operates the presses. Thus, the cost is 2v + w, where v is the hourly rent for gumball presses and w is the hourly wage.

b. The cost function for producing q thousand gumballs per hour can be expressed as TC = q(2v + w), where TC is the total cost. The reason for this is that the fixed proportions production function means that the only way to increase output is to increase the number of gumball presses and workers in fixed proportions. As a result, the cost of producing q thousand gumballs per hour is simply q times the cost of producing 1000 gumballs per hour.

c. The average cost (AC) of producing q thousand gumballs per hour is TC/q, which simplifies to AC = 2v + w. The marginal cost (MC) of producing q thousand gumballs per hour is the derivative of the cost function with respect to q, which is MC = 2v + w.

d. When v = 3 and w = 5, the average cost and marginal cost curves are shown in the graph below:

e. When v = 6 and w = 5, the average cost and marginal cost curves shift upwards, as shown in the graph below:

This is because the cost of using the gumball presses has increased, which increases the total cost of producing each unit of output. As a result, both the average and marginal cost curves shift upwards by the same amount

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Answer:

sound waves

Explanation:

The kinetic energy of the meatball is transferred into the surroundings through sound waves.

When the meatball hits the wall, the kinetic energy of the meatball causes vibrations in the wall and the surrounding air. These vibrations create sound waves which transfers the kinetic energy to sound energy until it runs out of energy.

When an object / medium vibrates, the particle of the object / medium starts to move. This movement of particles is called as sound waves. It is a type of mechanical wave.

Therefore, the kinetic energy of the meatball is transferred into the surroundings through sound waves.

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The shortest chain sling ACB for a movable bin is  1.228 m.

The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works

Triangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.

According to Newton's first law, in the y-axis

∑ F = 0

w - T₁y - T₂y = 0

T₁y + T₂y = 2,100

T₁ sin θ + T₂ sin θ = 2,100

5,000 sin θ + 5,000 sin θ = 2,100

10,000 sin θ = 2,100

sin θ = 2,100 ÷ 10,000

sin θ = 0.21

θ = sin⁻¹ (0.21)

θ = 12.12°

Look at AOC

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Answer:

Someone who writes software or programs for computers is called a programmer.

Explanation:

Yes, it is possible for an object to experience a net zero external unbalanced force. This means that the forces acting on the object are balanced, resulting in no overall force acting on it. An object can be in a state of rest or continue moving with a constant velocity when it experiences a net zero external unbalanced force.

When an object experiences a net zero external unbalanced force, it can be in different states:
If the object is at rest and experiences a net zero external unbalanced force, it will remain at rest. This occurs when the forces pushing or pulling on the object in different directions cancel each other out. For example, if you push an object with a force of 50 N to the right, and someone else pulls it with an equal force of 50 N to the left, the object will not move.
If the object is in motion and experiences a net zero external unbalanced force, it will continue to move with a constant velocity. This happens when the forces pushing or pulling on the object are equal in magnitude and opposite in direction. For instance, if a car is traveling at a constant speed of 60 km/h and experiences an equal resistance force due to air resistance, the net force on the car is zero, and it will continue moving at the same speed.
It's important to note that even though the net external unbalanced force is zero, the object may still experience internal forces, such as gravitational or frictional forces, which do not cancel out.

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The changes in height of the mercury column for a temperature change of 28 ◦C is approximately 548.6 cm.

The change in height of the mercury column can be calculated using the formula:

Δh = V/A

The change in volume of the mercury can be calculated using the formula:

ΔV = V₀βΔT

where V₀ is the initial volume of the mercury, β is the volume expansion coefficient of mercury, and ΔT is the change in temperature.

The initial volume of the mercury can be approximated as the volume of a cylinder with height h and radius r, where h is the height of the capillary tube and r is the radius of the bulb:

V₀ = πr²h = π(0.29/2)²(15) = 5.76 cm³

The cross-sectional area of the capillary tube can be calculated as:

A = πr² = π(0.0041/2)² = 5.27 × 10⁻⁵ cm²

Substituting the values into the equations, we get:

ΔV = V₀βΔT = (5.76 cm³)(0.000182 (◦C)⁻¹)(28 ◦C) = 0.0289 cm³

Δh = V/A = (0.0289 cm³)/(5.27 × 10⁻⁵ cm²) ≈ 548.6 cm

Therefore, the change in height of the mercury column for a temperature change of 28 ◦C is approximately 548.6 cm.

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Answer:

glycolysis is the answer to the question

Answer:

water process?

Explanation:

Always wash your hands, hand washing skills. By the way you spelt thanks* improperly.

The energy required to move one elementary charge (e) through a potential difference (V) can be calculated using the formula:E = qV the answer is (d) 8.0 x 10^-19 J.

In physics, potential refers to the energy per unit of charge associated with a physical system. It is often used in the context of electric potential, which is the potential energy per unit of charge associated with a static electric field. Electric potential is measured in units of volts (V) and is defined as the work done per unit charge in moving a test charge from infinity to a point in the electric field.The electric potential difference, or voltage, between two points in an electric field is defined as the work done per unit charge in moving a test charge from one point to the other.

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Answer:

800 m/s

Explanation:

v = fλ

v = 200 x 4  = 800 m/s

Answer:

O N

Explanation:

Upthrust = Volume of object * density of fluid * acceleration due to gravity

Upthrust = 4.0 m3 *  1000 kg/m3 * 10 m/^2

Upthrust = 40, 000 N

Upthrust = Weight in air - Weight in water

Weight in air = 40,000 N

Weight in water = Weight in air - Upthrust

Weight in water = 40,000 N - 40,000 N

Weight in water = 0 N

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 3

We have the final answer as

Hope this helps you

Answer:

See below

Explanation:

12 125 lbs  *  .4536 kg/lb = 5499.9 kg      =   5 .4999 x 10 ^3 kg

A wheel undergoing rolling motion means that the wheel is moving forward while rotating on its axis. The motion of the wheel can be analyzed using the concept of rotational motion and translational motion.

One of the fundamental truths about a wheel undergoing rolling motion is that the point of contact between the wheel and the surface is stationary. This means that the wheel's velocity at the point of contact is zero, and this is true for any point on the wheel's circumference that is in contact with the surface.
Another truth about a wheel undergoing rolling motion is that it has less friction than a sliding object. This is because the rolling motion allows the wheel to distribute its weight over a larger area, reducing the pressure on any particular point of contact between the wheel and the surface. Additionally, the shape of the wheel allows it to change direction easily, making it an excellent tool for transportation and movement.
In summary, a wheel undergoing rolling motion has a stationary point of contact with the surface, less friction than a sliding object, and is an excellent tool for transportation and movement.

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Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

28.8 cm/7.2 cm = 4

Answer: 2.5 m

Explanation: 1/2(1s)(5m/s)

=2.5.

Got it from Khan Academy

Answer:

Tiny particles in solids, liquids and gases are always in motion. It is the motion of particles that creates a form of energy called thermal (heat) energy that is present in all matter. The particles in solids are tightly packed and can only vibrate. Matter in its solid state has the lowest amount of thermal energy (for that type of matter). Because solids have less thermal energy than liquids or gasses, the atoms in their solid state move very little.

Explanation:

So yes, chocolate has VERY low thermal energy

Frequency of the rarest genotype in the population The frequency of the minor allele at the first locus is 0.3, the minor allele at the second locus is 0.2, and the minor allele at the third locus is 0.1.

A population of size p will have p × 0.3 major alleles and p × 0.7 minor alleles at the first locus. A population of size p will have p × 0.2 major alleles and p × 0.8 minor alleles at the second locus. Similarly, at the third locus, a population of size p will have p × 0.9 major alleles and p × 0.1 minor alleles.

There are 2 alleles per locus, hence the total number of genotypes for the 3 loci is 2³ = 8.Rarest genotype is the one with minimum frequency, which is obtained as the product of the frequency of each of the minor alleles at the three loci.

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I'm going to assume you mean

\(y = 14t^2 - \dfrac{t^2}{2+5t} - 3\)

Taking the derivative with respect to t on both sides gives

\(\dfrac{\mathrm dy}{\mathrm dt} = 2\cdot14t - \dfrac{(2+5t)(2t)-t^2(5)}{(2+5t)^2} - 0 \\\\ \dfrac{\mathrm dy}{\mathrm dt} = \boxed{28t - \dfrac{4t+5t^2}{(2+5t)^2}}\)

You could go on to expand the rational expression into partial fractions. One way to do this:

\(\dfrac{5t^2 + 4t}{(2 + 5t)^2} = \dfrac{t(5t+2) + 2t}{(2+5t)^2} \\\\= \dfrac{t}{2+5t} + \dfrac{2t}{(2+5t)^2} \\\\= \dfrac15 \cdot \dfrac{t}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \cdot \dfrac{t+\frac25-\frac25}{\frac25+t} + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 \left(1 - \dfrac{2}{2+5t}\right) + \dfrac{2t}{(2+5t)^2} \\\\ = \dfrac15 - \dfrac{2}{10+25t}+ \dfrac{2t}{(2+5t)^2}\)

and this would give

\(\dfrac{\mathrm dy}{\mathrm dt} = 28t - \dfrac15 + \dfrac2{10+25t} - \dfrac{2t}{(2+5t)^2}\)

To solve this problem, we need to use the conservation of mechanical energy principle, which states that the total mechanical energy of a system remains constant if the only forces acting on the system are conservative forces.

We can start by calculating the total mechanical energy of the system at point A and point B, and then use the conservation of mechanical energy principle to determine the work done by the force of friction and the average force of friction.

(a) Calculation of work done by the force of friction:

At point A, the total mechanical energy of the system is given by:

E_A = mgh_A + 1/2 mv_A²

where m is the mass of the object, g is the acceleration due to gravity, h_A is the height of point A above a reference level, and v_A is the speed of the object at point A.

At point A, the object is at the highest point of the circular track, so its height above the reference level is given by h_A = R. Thus, we can write:

E_A = mgR + 1/2 mv_A²

E_A = (1.2 kg)(9.81 m/s²)(0.90 m) + 1/2 (1.2 kg)(9.5 m/s)²

E_A = 62.19 J

At point B, the total mechanical energy of the system is given by:

E_B = mgh_B + 1/2 mv_B²

where h_B is the height of point B above the reference level and v_B is the speed of the object at point B.

At point B, the object is at the lowest point of the circular track, so its height above the reference level is given by h_B = 0. Thus, we can write:

E_B = 1/2 mv_B²

E_B = 1/2 (1.2 kg)(3.1 m/s)²

E_B = 5.70 J

Since the total mechanical energy of the system is conserved, we have:

E_A = E_B + W_friction

where W_friction is the work done by the force of friction between points A and B.

Thus, we can solve for W_friction:

W_friction = E_A - E_B

W_friction = 62.19 J - 5.70 J

W_friction = 56.49 J

Therefore, the work done by the force of friction between points A and B is 56.49 J.

(b) Calculation of the average force of friction:

We know that the work done by a force is equal to the force times the distance over which it acts. In this case, the force of friction acts over the distance between points A and B, which is equal to the circumference of the circular track.

The circumference of the circular track is given by:

C = 2πR

C = 2π(0.90 m)

C = 5.65 m

Thus, the average force of friction is given by:

F_friction = W_friction / C

F_friction = 56.49 J / 5.65 m

F_friction = 9.99 N

Therefore, the magnitude of the average force of friction for this motion between points A and B is 9.99 N.

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Answer:

To write 50000 in scientific notation, we will have to move the decimal point four points to left, which literally means dividing by 104 . Hence in scientific notation 50000=5×104 (note that as we have moved decimal four points to left and thus divided by 104 , we are multiplying by 104 to compensate.

Explanation:

Metaphysics. According to Epicurus, the fundamental building blocks of the universe are atoms, which are indestructible, minute pieces of matter, moving in space. Conglomerations of atoms make up everyday items.

Following the Cyrenaic philosopher Aristippus, Epicurus held that the greatest good was to seek modest, lasting pleasure in the form of a state of ataraxia (tranquility and freedom from fear) and aponia (the absence of bodily pain) through knowledge of the workings of the world and restraint of desires. Being an empiricist, Epicurus held that the only reliable way to learn about the universe is through the senses. He took inspiration from the ancient philosopher Democritus for a lot of his physics and cosmology.

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