Javier's deli packs lunches for a school field trip by randomly selecting sandwich, side, and drink options. each lunch includes a sandwich (pb&j, turkey or ham and cheese), a side (cheese stick or chips), and a drink (water or apple juice)

1. what is the probability that a student gets a lunch that includes chips and apple juice?

2. what is the probability that a student gets a lunch that does not include chips?​

Answer:

CAN $1590

Step-by-step explanation:

Below is the given values:

Tourist has money = TT $7875

Spending = TT $2310

Remaining money = 7875 - 2310 = TT $5565

The Canadian currency she has =  TT $5565 / TT $ 3.5

The Canadian currency she has =CAN $1590

The amount of money she will receive after converting into Canadian dollars = CAN $1590

Answer:

96 pizzas

Step-by-step explanation:

Allan can make 8 pizzas in 15 minutes at the pizza restaurant where he works.

We are told that;

If the number of pizzas varies directly with minutes,

P ∝ M

P = kM

Hence:

8 = 15k

k = 8/15

How many pizzas can Allan make in 3 hours?

Convert 3 hours to minutes

1 hour = 60 minutes

3 hours = x

x = 3 × 60

x = 180 minutes

Hence,

M = 180 minutes

k = 8/15

P = kM

P = 8/15 × 180

P = 96 pizzas

Therefore, Allan can make 96 pizzas in 3 hours

The probability of observing the experiment result, a sample mean, for example, or something more unusual just by chance if the null hypothesis is true is the definition of "P-Value."

A null hypothesis is a sort of statistical hypothesis which asserts that there is no statistical significance in a particular set of observations.

Using sample data, hypothesis testing is performed to determine the believability of a theory. It really is expressed as H0 and is also known to simply as "null."

Some key features regarding null hypothesis are-

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Answer:

25%

Step-by-step explanation:

\(percentage \: increase = \frac{30 - 24}{24} \times 100 \\ \\ = \frac{6}{24} \times 100 \\ \\ = \frac{1}{4} \times 100 \\ \\ = 25\%\)

Answer:

It would be D

because you need to multiple 3x3 to get 9 so the answer to your problem is D

Answer:

B

Step-by-step explanation:

So we are trying to find the number that is not between \(\frac{\sqrt{16}}{2}\) and 3π on the number line. To do this, lets try to find roughly (exactly if possible) that \(\frac{\sqrt{16}}{2}\) and 3π are. Lets start with \(\frac{\sqrt{16}}{2}\).

\(\frac{\sqrt{16}}{2}=\frac{4}{2}=2\)

So now, by looking at the number line, we can see that the values must be greater than 2. Now lets find 3π. Lets use 3.14 for π (3.14 is actually smaller than the actual value of π):

3(3.14) = 9.42

So we know that the value must be less than 9.42.

We can rewrite answer choice A as 2.08, with is more than 2 and less than 9.42. Therefore, it is between the two numbers on the number line.

While I do not know the exact value of √0.4, I know that it will be less than 1, making it less than 2. Therefore, it is not between the two numbers on the number line, and therefore is our answer.

Lets go through the other two answer choices though.

For C, while 9.37 is close to 9.42, it is still less than 9.42 and greater than 2, and therefore is between the two numbers on the number line.

For D, √9 can be rewritten as 3, which is between the two numbers on the number line.

Even if you did not know that answer choice B, √0.4, was less than 1, you still would have been able to find that B was the correct answer by the process of elimination.

I hope you find my answer helpful.

The long-run probabilities of each state as follows:T1 = limn→∞T1(n) = limn→∞0.7229012 = 0.7229T2 = limn→∞T2(n) = limn→∞0.3121788 = 0.3122 . Therefore, the long-run probabilities of each state are T1 = 0.7229 and T2 = 0.3122.

The table showing the probability of each state in future periods is given below:

State Probability 0 1 2 3 4 5 6 7 8 9 10 1 0.5 0.58 0.624 0.6608 0.68512 0.700672 0.710403 0.716241 0.719744 0.721846 0.7229012(n) 0.5 0.42 0.376 0.3592 0.34488 0.333408 0.324677 0.318839 0.315336 0.313234 0.3121788

The probabilities of state 1 and state 2 are approaching long-run probabilities of each state.

As we see in the above table, the probabilities of states 1 and 2 are approaching long-run probabilities of each state.

The long-run probabilities are calculated by using the following formulas: limn→∞T1(n) = T1(n−1)limn→∞T2(n) = T2(n−1)

By using these formulas, we get the long-run probabilities of each state as follows: T1 = limn→∞T1(n) = limn→∞0.7229012 = 0.7229T2 = limn→∞T2(n) = limn→∞0.3121788 = 0.3122 .

Therefore, the long-run probabilities of each state are T1 = 0.7229 and T2 = 0.3122.

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Answer:

-4

Step-by-step explanation:

3+1 = 4 so just put a dash at the start and you ger -4

Answer:

15, 18, 21

Step-by-step explanation:

3, 6, 9, 12, 15, 18, 21...

3 x 5 = 15

3 x 6 = 18

3 x 7 = 21

Hope this helps! :)

Answer:

The answer is 3.18 miles/runner.

Step-by-step explanation:

To solve this problem, we need to find the distance that each member of the team runs. To do this, we have to divide the total distance of the race (12.72 miles) by the number of runners on the team (4 runners).

If we perform this operation, we get:

12.72 miles/4 runners

= 3.18 miles/runner

Therefore, the correct answer is that each team member runs 3.18 miles during the race.

Hope this helps!

Answer:

1) 90

2) 38

Step-by-step explanation:

1) look at the attached diagram

As you can see, the floor and the wall must meet at a 90° angle.

2) Perimeter of office: 10 + 12 + 10 + 12 = 44

Subtract the door and windows' lengths:

44 - 3 - 3 = 38 ft.

The BN structure model with more than 10 nodes can be established. The structure refers to the way the variables are related.

A Bayesian Network (BN) is a probabilistic graphical model that illustrates a set of variables and their probabilistic dependencies. A BN structure is made up of nodes and edges. Nodes represent variables, and edges represent the connections between the variables. The BN structure model can be established by using various algorithms, including structure learning and parameter learning.The BN structure with more than 10 nodes is a complex model with numerous variables and their dependencies. The structure's meaning is how the variables are interrelated, allowing us to estimate the probabilities of certain events or scenarios. The nodes in the structure represent various factors that affect the outcome of an event, and the edges between them demonstrate how these factors are related.The BN structure model is used in many fields, including medical diagnosis, fault diagnosis, and decision making.

The Bayesian Network structure model with more than 10 nodes is a powerful tool for analyzing complex systems. It helps to understand the interrelationships between variables and estimate the probabilities of different events or scenarios. This model is useful in various fields and provides insights into many complex phenomena.

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To calculate cumulative cash surplus/ deficit we need to consider cash flows during quarter, including sales, purchases, accounts receivable, accounts payable, cash expenses, taxes,  initial cash,loan balances.

Calculate the total cash inflows from sales for Q1: $46,000 (Q1 sales) * 71% (purchases as a percentage of next quarter's sales) = $32,660.

Calculate the total cash outflows for Q1: $1,500 (monthly cash expenses) * 3 months + $400 (monthly taxes) * 3 months = $5,700 + $1,200 = $6,900.

Calculate the net cash flow from accounts receivable: $32,660 (total cash inflows from sales) - $12,200 (accounts receivable balance at the beginning of Q1) = $20,460.

Calculate the net cash flow from accounts payable: $48,000 (Q2 sales projection) * 45 days / 30 days = $72,000 (purchases for Q2) - $14,800 (accounts payable balance at the beginning of Q1) = $57,200.

Calculate the net cash flow from short-term borrowing: Since the short-term loan balance is zero at the beginning of Q1 and there is no mention of additional borrowing, the net cash flow from short-term borrowing is zero.

Calculate the net cash flow for Q1: Net cash flow = Cash inflows - Cash outflows = $20,460 (net cash flow from accounts receivable) - $6,900 (total cash outflows) + $57,200 (net cash flow from accounts payable) = $70,760.

Calculate the cumulative cash surplus/deficit at the end of Q1: Cumulative cash surplus/deficit = Initial cash balance + Net cash flow - Minimum cash balance = $280 (initial cash balance) + $70,760 (net cash flow) - $250 (minimum cash balance) = $71,790.

Therefore, the cumulative cash surplus (deficit) at the end of Q1, prior to any short-term borrowing, is $71,790.

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Answer:

the answer is 312

Step-by-step explanation:

I used my calculator and i multiplied 6 by 52 and got 312

Answer:

no if the diameter was 7.2 inches the circumstance would be 22.62 :)

3,686 seats were empty. This  number indicates that the stadium was not full to capacity.

1. Subtract the number of people in  from the number of people the stadium can hold:

62,005 - 58,319 = 3,686

2. The answer is 3,686 seats were empty.

The football stadium was able to accommodate up to 62,005 people, but only 58,319 were in attendance at the game. This means that 3,686 seats were left empty. To calculate this, subtract the number of people in attendance from the number of people the stadium can hold. 62,005 - 58,319 = 3,686. Therefore, 3,686 seats were empty. This number indicates that the stadium was not full to capacity.

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Answer: On the first day, Shelly rode 10 miles on first day.

On the second day, Shelly rode 8 miles.

On the third day, Shelly rode 12 miles.

Step-by-step explanation:

Let x = distance rod eon first day.

Shelly rode her bike a total of 30 miles over a three-day period.

Then as per given,

Distance rode on second day = \(\dfrac45x\)

Distance rode on third day \(=\dfrac32\times\text{ Distance rode on second day}\)

\(=\dfrac32\times\dfrac45x=\dfrac{6}{5}x\)

Total distance rode = \(x+\dfrac45 x+\dfrac65x=30\)

\(\Rightarrow\ \dfrac{5x+4x+6x}{5}=30\\\\\Rightarrow\ \dfrac{15x}{5}=30\\\\\Rightarrow\ 3x=30\\\\\Rightarrow\ x=\dfrac{30}{3}\\\\\Rightarrow\ x=10\)

Hence, She rode 10 miles on first day.

Distance rode on second day = \(\dfrac45\times10=4\times2=8\text{ miles}\)

Distance rode on third day \(=\dfrac{3}{2}\times8=3\times4=12\text{ miles}\)

She needs 14 cups of fertiliser.

What is the area?

A two-dimensional figure's area is the amount of space it takes up. In other terms, it is the amount that counts the number of unit squares that span a closed figure's surface.

Area = length * width

Find the area of the garden:

Area = 9 1/3 * 12

       = 28/3 * 12

       = 112  yards²

Find the amount of the fertiliser needed:

1   yards² = 1/8 cup

112  yards² = 1/8 * 112 = 14 cups

She needs 14 cups of fertiliser.

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Answer:x=25

Step-by-step explanation:

19=x-6

+6 +6

25=x

x=25

The correct option is Option D: the approximate loudness of a dinner conversation will be 50Db with a sound intensity 10⁻⁷.

The loudness L, ( which is measured in decibels (Db)), of the sound of the intensity I, can be calculated in watts per square meter,

L = 10 log(I/I₀)  

where I₀ = 10⁻¹²  which is the least intensity that a human can hear.

The sound intensity of a dinner conversation= I= 10⁻⁷

Loudness L of that conversation = 10 log (10⁻⁷/10⁻¹²)

= 10 log(10⁻⁷⁻⁽⁻¹²⁾)

= 10 log(10⁻⁷⁺¹²)

= 10 log(10⁵)

= 10*5

= 50 Db

Therefore the correct option is Option D: the approximate loudness of a dinner conversation will be 50Db with a sound intensity 10⁻⁷.

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a) The distance covered after traveling ²/₅ of the total distance is (iv) 0.500km.

b) The distance Ronak needs to travel to reach the market is (iii) 0.750km.

c) The amount Ronak paid for the 12.5 kg of rice is (ii) Rs. 706.25.

d) The total amount paid for the autorickshaw and rice is (i) Rs. 721.25.

The distance being walked to reach the market = 1,250 m (1.25 km)

a) The distance covered after traveling ²/₅ of the total distance = 0.500km (1.25 x ²/₅)

b) The distance Ronak needs to travel to reach the market is 0.750km (1.25 - 0.5).

c) Rice bought = 12.5 kg at Rs 56.50 per kg

The amount he paid for the 12.5 kg of rice is Rs 706.25 (12.5 x Rs 56.50).

d) Return taxi cost = Rs 15

The total amount paid for the autorickshaw and rice is Rs. 721.25 (Rs 706.25 + Rs 15).

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Answer: Yes, round it to the nearest tenth

Answer:

5 (4x+3) (4x-3)

Step-by-step explanation:

Both terms are perfect squares, so factor using the difference of squares formula

a^2 - b^2 = (a+b)(a-b)

a will be 4x, and b will be 3

Further solve and you will have your answer

Answer: \(5(4x+3)(4x-3)\)

Step-by-step explanation: Whenever dealing with a factoring problem, always take the GCF which in this case is five. Once in simplest form with the GCF taken out, it will be easy to factor.

Work :

Start by Factoring out the 5 as it is the GCF

\(5(16x^2-9)\)

Use the \(a^2-b^2 = (a+b)(a-b)\) in order to completly factor

\(5(4x+3)(4x-3)\)

That's it!

Answer:

Therefore, the approximate monthly payment is $548.85

Step-by-step explanation:

The amount of student loans Erica currently has = $34,006.00

The duration over which Erica is to pay back the loan = 7 years

The annual interest rate for the loan = 9.1%

Therefore, we have the geometric sequence formula is given as follows;

\(A_n = P( 1 + r)^n - M \times \left [ \dfrac{(1 + r)^n-1}{r} \right ]\)

Where;

M = The monthly payment

P = The initial loan balance = $34,006.00

r = The annual interest rate = 9.1%

n = The number of monthly payment = 7 × 12 = 84

Aₙ = The amount remaining= 0 at the end of the given time for payment

Substituting the values into the above formula, , we get;

\(0 = 34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} - M \times \left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]\)

\(M = \dfrac{34006 \times \left ( 1 + \dfrac{0.091}{12} \right )^{84} }{\left [ \dfrac{\left (1 + \dfrac{0.091}{12} \right )^{84}-1}{\dfrac{0.091}{12} } \right ]} \approx 548.85\)

Therefore, the approximate monthly payment = $548.85

The distance between your house and school is 4.1 miles.

According to the given question.

Point c represents your house.

Point d represents post office which is directly west to the point c i.e from house.

And point e represents school which is west of the post office.

Also, it is given that the distance between house and post office, cd is 1.7 miles.

And the distance between the post office and school,de is 2.4 miles.

Now, if we see the attached figure we can say that

cd + de = ce

⇒ 1.7miles  + 2.4miles  = 4.1 miles

Hence, the distance between your house and school is 4.1 miles.

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For the function f(x) = ⌊x²/3⌋, the values of f(s) for different sets s are as follows: a) f(s) = {1, 0, 0, 0, 1, 3}, b) f(s) = {0, 0, 1, 3, 5, 8}, c) f(s) = {0, 8, 16, 40}, d) f(s) = {1, 12, 33, 77}

The function f(x) = ⌊x²/3⌋ represents the floor of x²/3. To find f(s) for different sets s, let's evaluate it for each case:

a) For s = {-2, -1, 0, 1, 2, 3}:

  - For -2, (-2)²/3 = 4/3, and ⌊4/3⌋ = 1.

  - For -1, (-1)²/3 = 1/3, and ⌊1/3⌋ = 0.

  - For 0, (0)²/3 = 0/3 = 0.

  - For 1, (1)²/3 = 1/3, and ⌊1/3⌋ = 0.

  - For 2, (2)²/3 = 4/3, and ⌊4/3⌋ = 1.

  - For 3, (3)²/3 = 9/3 = 3.

  Therefore, f(s) = {1, 0, 0, 0, 1, 3}.

b) For s = {0, 1, 2, 3, 4, 5}:

  - For 0, (0)²/3 = 0/3 = 0.

  - For 1, (1)²/3 = 1/3, and ⌊1/3⌋ = 0.

  - For 2, (2)²/3 = 4/3, and ⌊4/3⌋ = 1.

  - For 3, (3)²/3 = 9/3 = 3.

  - For 4, (4)²/3 = 16/3, and ⌊16/3⌋ = 5.

  - For 5, (5)²/3 = 25/3, and ⌊25/3⌋ = 8.

  Therefore, f(s) = {0, 0, 1, 3, 5, 8}.

c) For s = {1, 5, 7, 11}:

  - For 1, (1)²/3 = 1/3, and ⌊1/3⌋ = 0.

  - For 5, (5)²/3 = 25/3, and ⌊25/3⌋ = 8.

  - For 7, (7)²/3 = 49/3, and ⌊49/3⌋ = 16.

  - For 11, (11)²/3 = 121/3, and ⌊121/3⌋ = 40.

  Therefore, f(s) = {0, 8, 16, 40}.

d) For s = {2, 6, 10, 14}:

  - For 2, (2)²/3 = 4/3, and ⌊4/3⌋ = 1.

  - For 6, (6)²/3 = 36/3 = 12.

  - For 10, (10)²/3 = 100/3, and ⌊100/3⌋ = 33.

  - For 14, (14)²/3 = 196

The values of f(s) for the given sets show how the function ⌊x²/3⌋, which represents the floor of x²/3, behaves for different inputs.

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By using the concept of testing of hypothesis, it can be calculated that

The required test statistic is t = 0.918

What is testing of hypothesis?

Suppose, there is a hypothesis and there is a data at hand. Testing of hypothesis is a method of inferencing which is used to decide whether the given hypothesis is true or not based on the statistical data given

From the table attached here, it can be calculated that

\(\bar{x}_{2012}=365.4667\\s^{2}_{2012}=27133.66364\\\bar{x}_{2013}=331.775\\s^{2}_{2013}=29750.53782\\n_{2012}=45\\n_{2013}=40\\\)

So the test statistic t is

\(\large t=\frac{\bar{x}_{2012}-\bar{x}_{2013}}{\sqrt{\frac{s^{2}_{2012}}{n_{2012}}+\frac{s^{2}_{2013}}{n_{2013}}}}\)

\(t=\frac{365.4667-331.775}{\sqrt{\frac{27133.66364}{45}+\frac{29750.53782}{40}}}\)

\(t \large =\frac{33.6917}{36.6978711}\)

t = 0.918

The value of the test statistic is 0.918

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Answer:

Prime numbers are those that only have two factors, the number itself and 1. The two factors cannot be the same. E.g. 2 is a prime number but 1 is not.A prime factor is when a prime number is a factor of another number e.g. 2 is a prime factor of 12. So when told to write a number as a product of its prime factors, you need to show all the prime numbers that can multiply together to make that particular number.So 40 as product of prime factors:2x2x2x5 or 2^3 x5 -----> diagram

Answer:

x-(x times 33%)  or x times (100-33)%

Step-by-step explanation:

A group contains n men and n women. 2n! number of ways are there to arrange these people in a row if the men and women alternate. Arrangement is known as permutation.

A permutation of a set in mathematics is, broadly speaking, the rearrangement of its elements if the set already has an ordered structure into a sequence or linear order. The act or procedure of altering the linear order of an ordered set is referred to as a "permutation."

When the order of the arrangements counts, a permutation is a mathematical technique that establishes the total number of alternative arrangements in a collection. Choosing only a few items from a collection of options in a specific sequence is a common task in arithmetic problems.

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