jasmine broke the antenna k. her radio receiver how will this most likely affect jasmine radio?

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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Pretty sure the average speed of the bus is v = 1.55 m/s

Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

Answer:

Distance: 21km

Displacement: ~16.76km

We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is

\(X=58.96gal/day\)

From the Question we are told that

Pipe Drip\(=155 mL/min.\)

Generally

We have that for mL to gallons conversion

\(1mL=0.000264172\)

And

A minute to day con version is

\(1min=0.000694444\)

Therefore

\(X=155 mL/min.\)

\(X=155(\frac{0.000264172}{0.000694444})\)

\(X=58.96gal/day\)

In conclusion

The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)

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Complete Question

1 a A little girl pushes a 5.0 kg toy baby stroller at constant speed 7.0 m across the floor. She pushes on the handle with a force of 40 N at an angle of 30o with the horizontal.  How much work is done by the girl on the wagon?

1b  A farmhand pushes 20 ㎏ bale of hay 4m across the floor of the barn if she exerts a horizontal force of 60 N on the hay, how much work is done? (5 pts)

All parts are 4 points each

Answer:

1a

  \(W = 242.5 \ J\)

1b

    \(W = 240 \ J\)

Explanation:

Considering question a

From the question we are told that

       The mass of the toy baby stroller is  \(m = 5.0 \ kg\)

        The distance covered is    \(d = 7.0\ m\)

          The force the girl applies on the handle  is  \(F = 40 \ N\)

          The angle at which this force is applied is  \(\theta = 30^o\)

Generally the workdone is mathematically represented as

          \(W = F_x * d\)

Here  \(F_x\) is the force along the horizontal axis , this is mathematically represented as

           \(F_x = F cos (\theta )\)

=>         \(F_x = 40 * cos(30 )\)

=>         \(F_x = 34.64 \ N\)

So

              \(W = 34.64 * 7\)

=>           \(W = 242.5 \ J\)

Considering question b

From the question we are told that

       The mass of the toy baby stroller is  \(m = 20 \ kg\)

        The distance covered is    \(d = 4 \ m\)

          The force the girl applies on the handle  is  \(F = 60 \ N\)      

Generally the workdone is mathematically represented as

          \(W = F * d\)

=>     \(W = 60 * 4\)

=>     \(W = 240 \ J\)

The kinetic energy of an object with mass 5kg and a constant velocity of 15m/s is 562.5J.

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

The kinetic energy of an object can be calculated using the following formula:

K.E = ½ mv²

Kinetic energy = ½ × 5 × 15²

Kinetic energy = 562.5J

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604.8 kg

Hi there !

d = m/V => m = d×V

V = l×w×h = 10m×12m×4m = 480 m³

m = 1.26kg/m³×480m³ = 604.8 kg

Good luck !

Option. (B) The crest of one wave overlaps with the trough of another  is the best description of the destructive interference of light. The statement Option (B) Radio waves have longer wavelengths and lower frequencies than microwaves correctly compares radio waves and microwaves. Exposure to Option (A) infrared radiant energy is sensed by human skin as warmth. prism produces the colors of the rainbow from white light Option (C) by separating the light of different wavelengths. Option(C) Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

Question 2The best description of the destructive interference of light is when the crest of one wave overlaps with the trough of another wave.

Destructive interference occurs when two waves combine to form a wave of lower amplitude.

When this happens, the crest of one wave overlaps with the trough of another, reducing the overall amplitude of the wave.

Question 4Radio waves have longer wavelengths and lower frequencies than microwaves.

This implies that they also have lower energy and are less dangerous than microwaves.

Microwaves have shorter wavelengths, higher frequencies, and higher energy than radio waves.

Question 6Exposure to infrared radiant energy is sensed by human skin as warmth.

This is because the infrared wavelengths correspond to thermal energy, which means that they cause molecules to vibrate faster and generate heat when absorbed by objects.

The sun is a source of infrared radiation that is sensed by our skin as warmth.

Question 8A prism produces the colors of the rainbow from white light by separating the light of different wavelengths.

When white light enters a prism, it is refracted and separated into its component colors because each color has a different wavelength.

This is because each color bends differently as it passes through the prism, which causes them to separate and form a rainbow of colors.

Question 10Light moves in a straight line except at surfaces between different transparent materials, where its path bends.

This bending of light is known as refraction and occurs because light travels at different speeds through different materials.

When light moves from one material to another, such as from air to glass, it changes speed and direction, causing its path to bend.

This is why lenses and prisms can be used to bend and focus light in specific ways.

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The Root Mean Square (RMS) voltage measured across the secondary coil is 639.39 volts.

Given

Number of turns in the primary coil N1=400

Number of turns in the secondary coil N2=2000

Voltage across the primary coil V1max=180volts

Using ideal transformer voltage equation,

Maximum voltage across secondary coil

V2max= (N2/N1) x V1max

            = ( 2000/400) x 180v
            = 900 volts
Root Mean square (RMS) voltage across secondary coil

Vrms=  \(V2max/ \sqrt{2}\)                

          = \(900/\sqrt{2}\)

          = 636.39 volts

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The expression for the tension in the spring A is T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

The tension in spring A can be determined by resolving the forces into x and y components as shown below.

The angle spring A makes with horizontal is calculated as;

A = 90⁰ - θ

The horizontal component of the tension on spring A;

T(Aₓ) = -W cos(A)

T(Aₓ) = -W cos(90 - θ)

The vertical component of the tension of spring A is calculated as;

T(Ay) = W sin(A)

T(Ay) = W sin(90 - θ)

The expression for the tension in spring A is calculated as;

T(A) = √[(T(Aₓ)² + T(Ay)²]

T(A) = √[(-W cos(90 - θ))² + (W sin(90 - θ))²]

Thus, the expression for the tension in the spring A is determined through resolution of vector components.

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Answer:

P = 4.5 watts

Explanation:

Given that,

EMF of the circuit, E = 3 volt

The resistance  of the resistors, R = 2 ohms

We need to find the power of this circuit. The relation between power, emf and resistance is given by the formula as follows :

\(P=\dfrac{V^2}{R}\)

Substitute all the values,

\(P=\dfrac{3^2}{2}\\\\P=4.5\ W\)

So, the power of this circuit is equal to 4.5 watts.

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

false

Explanation:

Answer:

false

Explanation:

edge

Answer:

\(1140\:\mathrm{J}\)

Explanation:

Work is given by \(W=F\Delta x\), where \(F\) is force and \(\Delta x\) is displacement.

Plugging in given values, we get:

\(W=95\:\mathrm{N}\cdot12\:\mathrm{m}=\fbox{$1140\:\mathrm{J}$}\).

Answer:

the total distance is 5km and the displacement is 1km

Explanation:

The total distance would be the addition of John running both ways so 3 km, 2 km.

However since he only walked back from a distance of 3 km to 2 km, he would be displaced 1 km because displacement is more like the position from the original point.

Think about 2 km as a positive value for the first part of the question and a negative value for the second part.

1. b. electrical potential energy.

2. a. True. For electric potential energy, a reference position must be defined.

3. a. -4 J. The potential energy between two charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Since the potential energy is given as 2 J initially, and q2 is replaced by q3 (which is negative and twice the magnitude of q2), the potential energy becomes -4 J.

4. c. decreases. The potential energy between two charges decreases as they are moved closer together.

5. b. -3.24 J. The electric potential energy between two point charges is given by the equation U = k(q1q2)/r, where k is the electrostatic constant, q1 and q2 are the charges, and r is the separation between them. Substituting the values into the equation, we get U = (9x10^(-6) C)(-4x10^(-6) C)/(0.1 m) = -3.24 J.

6. a. B or D. Electric potential energy can never be negative if the charges repel each other.

7. c. measures energy per unit charge.

8. 12 J. The potential energy is given by the equation U = qV, where U is the potential energy, q is the charge, and V is the potential. Substituting the values into the equation, we get U = (6 C)(2 V) = 12 J.

9. b. 10 V. The electric potential is given by the equation V = U/q, where V is the potential, U is the potential energy, and q is the charge. Substituting the values into the equation, we get V = 50 J/5 C = 10 V.

10. c. 14 V. The electric potential is inversely proportional to the distance from a point charge. When the distance is doubled, the potential is halved. Therefore, the electric potential at the new position of q2 is 28 V/2 = 14 V.

11. c. increases. The potential at the position of q2 due to q1 increases when a negative test charge is substituted with twice the magnitude of the positive test charge.

12. By convention, the direction of a current is taken to be the direction of motion of negative charges. In reality, it is actually electrons that move in wires.

13. c. 0.25 A. The current is defined as the rate of flow of charge. Given that 15 C flows through the wire each minute, the current is 15 C/60 s = 0.25 A.

14. b. 1.2x10^6 C. The charge flowing through the wire is given by the equation Q = It, where Q is the charge, I is the current, and t is the time. Substituting the values into the equation, we get Q = (3x10^(-3) A)(1 hour)(3600 s/hour) = 1.2x10^6 C.

15. d. current. An ampere is a unit of electric current.

16. electrons. As current flows through a wire, it is actually electrons that move. The flow of electrons constitutes the electric current.

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The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

The given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:

The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:

Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26

Normalize the vector by dividing each component by the magnitude:

Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k

Multiply the normalized vector by the desired magnitude:

To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:

Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)

Simplifying the expression gives:

Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k

So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.

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There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.

A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.

The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.

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From the histogram given, there were at approximately 7 downloads between 3pm and 4pm . This can be derived by counting the rows in that time period.

A histogram is a graph that depicts the frequency distribution of a few data points from a single variable.

Histograms frequently divide data into "bins" or "range groups" and count the number of data points that belong to each of those bins.

Histograms are frequently used to depict the key properties of data distribution in a handy format. It is especially beneficial when working with huge data sets (more than 100 observations). It can aid in the detection of uncommon observations (outliers) or gaps in the data.2

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:25N/

Explanation:

Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?

Answer:

0.133 kg

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.

From the question,

Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s

Substitute these values into equation 2

(0.8*15)+(m'*20) = 10(0.8+m')

Solve for m'

12-20m' = 8+10m'

-20m'-10m' = 8-12

-30m' = -4

m' = -4/-30

m' = 0.133 kg

Answer: Fuel is burned in engines to make the motor move.

( Chemical to Mechanical )

Explanation:

during combustion of the diesel ( when the fuel is burnt in the engine of the vehicle, the diesel ( chemical energy ) is transformed or converted to Mechanical energy. This mechanical energy is what the truck uses in moving. Without the combustion of the fuel the vehicle won’t move and the combustion of diesel is achieved through compression unlike that of fuel.

Answer: Both A and B

Explanation:

The objects are in contact so it would depend on the amount of force that is pressing them as to the amount of friction and it would depend on the smoothness as too the amount of friction that is added

The ball left the bat at an angle of 45° from the horizontal, and then the ball was in the air for 4.51 seconds.

To calculate how long the ball was in the air, we can break down the motion of the ball into its horizontal and vertical components. Given that the ball was hit at an angle of 45° from the horizontal, we can determine the initial velocities in the horizontal and vertical directions.

The horizontal component of the initial velocity (Vx) remains constant throughout the motion because there is no horizontal acceleration. The vertical component of the initial velocity (Vy) can be calculated using trigonometry, knowing that the angle is 45° and the magnitude of the velocity is 125 m (450 ft).

Vy = V * sin(45°)

Vy = 125 m/s * sin(45°)

Vy = 125 m/s * √(2)/2

Vy ≈ 88.4 m/s

Next, we can analyze the vertical motion of the ball. The ball is subject to a constant acceleration due to gravity, which is approximately 9.8 m/s². Using this acceleration, we can calculate the time it takes for the ball to reach its maximum height and then fall back down to the ground.

Using the kinematic equation:

Vy = V0y + a * t

where Vy is the final vertical velocity (which is 0 m/s at the highest point), V0y is the initial vertical velocity, a is the acceleration due to gravity (-9.8 m/s²), and t is the time.

0 = 88.4 m/s - 9.8 m/s² * t

Solving for t:

t = 88.4 m/s / 9.8 m/s²

t ≈ 9.02 s

Since the time calculated is for the total time of the ball's flight (going up and coming back down), we can divide it by 2 to get the time the ball was in the air:

t_air = t / 2

t_air ≈ 4.51 s

Therefore, the ball was in the air for approximately 4.51 seconds.

It's important to note that this calculation assumes ideal conditions and neglects factors such as air resistance, variations in gravitational acceleration, and any other external factors that could affect the ball's flight.

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