Explanation:
Density is an intensive property of matter.
It is the mass per unit volume of a substance and it is expressed mathematically below:
Density = \(\frac{mass}{volume}\)
Mass is the amount of matter present within a substance
Volume is the space a substance occupies
So, density is directly proportional to the mass of a body and inversely related to the volume it occupies.
The packing of a substance is very important for determining the density values .
If you travel from Tucson to Argentina, you will see some different constellations in the night sky. true or false
Answer:
its true!!
Explanation: have a nice day !!
branches of sicence
Answer: Natural science can be divided into two main branches
Explanation:
life science and physical science. Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science.
1. A 500 N force applied to a box at a 50 degree angle above the horizontal surface. Find the x and y
components. Use the cheat sheet located in your blue resource folder, and show all work.
Answer:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Explanation:
At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:
\(F_{x} = F\cdot \cos \alpha\) (1)
\(F_{y} = F\cdot \sin \alpha\) (2)
Where:
\(F\) - Magnitude of the force, measured in newtons.
\(\alpha\) - Direction of the force above the horizontal surface, measured in sexagesimal degrees.
If we know that \(F = 500\,N\) and \(\theta = 50^{\circ}\), then the components of the force is:
\(F_{x} = (500\,N)\cdot \cos 50^{\circ}\)
\(F_{x} = 321.394\,N\)
\(F_{y} = (500\,N)\cdot \sin 50^{\circ}\)
\(F_{y} = 383.023\,N\)
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Read the following poem by Lola Ridge. Then, respond to the prompt that follows.
Wild Ducks
By Lola Ridge
That was a great night we spied upon
See-sawing home,
Singing a hot sweet song to the super-stars
Shuffling off behind the smoke-haze …
Fog-horns sentimentalizing on the river …
Lights dwindling to shining slits
In the wet asphalt …
Purring lights …red and green and golden-whiskered …
Digging daintily pointed claws in the soft mud …
…But you did not know …
As the trains made golden augers
Boring in the darkness …
How my heart kept racing out along the rails,
As a spider runs along a thread
And hauls him in again
To some drawing point …
You did not know
How wild ducks' wings
Itch at dawn …
How at dawn the necks of wild ducks
Arch to the sun
And new-mown air
Trickles sweet in their gullets.
In a well-written paragraph of 5–7 sentences, analyze the ambiguous nature of "Wild Ducks." Your response should include:
an explanation of your interpretation of the poem's meaning
evidence from the poem (PReP) that supports your interpretation
an explanation of how another reader could interpret the poem differently
evidence from the poem to support an alternative interpretation
Due to the possibility of misinterpretation, the poem "Wild Duck" can be read as either the speaker leaving her lover or the lover leaving her.
What does the poem discuss?Lola Ridge's poem "Wild Duck" allows for more than one interpretation of the speaker's meaning. As a result, it is ambiguous. The ambiguity of the poem can be examined, and the following response to the prompt:
You could say that according to your interpretation of the poem, the speaker is telling us about a night when she bid her lover farewell.
You could argue that the metaphor comparing the speaker to wild ducks and the speaker's statement that her heart "races along the train rails" are examples from the poem that support your claim.
You could argue that a different reading would imply that the speaker is the one being dumped by her lover.
You could cite the second stanza, which is not included here, where the speaker claims that the "known you" have emptied her soul, as proof for your claim.
But it's crucial to remember that the first interpretation appears to be the most plausible one. The metaphor involving the wild duck and the personification of the heart that runs on rails are quite clear, even though the poem does leave some room for ambiguity. The person who wants to leave someone behind is the speaker.
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Jupiter's acceleration due to gravity is 26.2 m/s2. The amount of potential energy stored in a 300 g
object 1.75 m above Jupiter's surface would be
Answer: The amount of potential energy stored in 300g object is 1,75m.
The amount of potential energy stored in the object is 13.755 J.
To determine the potential energy stored in the object, we need to know about the gravitational potential energy and how is it calculated.
What is gravitational potential energy?The potential energy of a massive object has in relation to another massive object due to gravity is known as gravitational potential energy.What is the mathematical expression of gravitational potential energy?Mathematically, the gravitational potential energy is m×g×h.where, m=mass
g= gravitational field or acceleration due to gravity
h= height
Here, m= 300gm=0.3Kg , g=26.2 m/s², h=1.75mPotential energy = 0.3×26.2×1.75=13.755J.
Thus, we can conclude that the amount of potential energy stored in a 300g object 1.75 m above Jupiter's surface would be 13.755J.
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What determines whether a real or a virtual image is formed from a concave mirror?
Answer:
The distance of the object from the concave mirror determines if it is a virtual or real image
Explanation:
Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.
How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s²
Answer:
108 N
Explanation:
Use Newton's second law.
F = ma
F = (90 kg) (1.2 m/s²)
F = 108 N
The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Determina las componentes del siguiente vector:
C = 50N 60º
The components of vector C are: 25N in the horizontal direction and 43.30N in the vertical direction.
How to get the Components of Vector?The vector can be broken down into two rectangular components (horizontal and vertical) using trigonometry:
The horizontal component is:
C_horizontal = C * cos(θ) = 50N * cos(60°) = 25N
The vertical component is:
C_vertical = C * sin(θ) = 50N * sin(60°) = 43.30N
Therefore, the components of vector C are: 25N in the horizontal direction and 43.30N in the vertical direction.
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Explain how the net impact forces can be reduced for basketball players through the
application of scientific and engineering concepts in sneaker design.
Answer:
* If we increase the distance traveled before stopping, the forces decrease significantly,
* If we decrease the height of the fall by grabbing the net to slow down.
* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.
Explanation:
When basketball players jump to place the ball in the net they see from a good height, when they hit the ground, strong tensions are produced in the bones and bonds.
Applying science to this case of fall, we can suggest several processes to decrease the forces on impact.
* If we increase the distance traveled before stopping, the forces decrease significantly,
* If we decrease the height of the fall by grabbing the net to slow down.
* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.
By designing shoes that have some degree of force absorption, it is possible to significantly reduce the stress on the player.
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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4. Find the voltage across the capacitor, Vc, 0.15 second after theswitch is closed.
This is and RC circuit. We know that in this kind of circuits the potencial acroos the capacitor during the charging process is:
\(V_{}=E(1-e^{-\frac{t}{RC}})\)where E is the voltage on the battery, t is the time, R is the total resistance and C is the capacitance.
In this case we have two resistance in series, then the total resistance is the sum of each of them. Therefor the equivalent resistance in this case is 1100 Ohms.
Plugging the values given we have:
\(\begin{gathered} V=35(1-e^{-\frac{0.15}{(75\times10^{-6})(1100)}}) \\ V=29.32 \end{gathered}\)Therefore after 0.15 seconds the voltage in the capacitor is 29.32 V.
why does pure water increase in volume when heated
Answer:
Pure water increases in volume when heated due to the phenomenon of thermal expansion. When water is heated, the kinetic energy of its molecules increases, causing them to move faster and spread out. This increased molecular movement leads to an increase in the average distance between water molecules, resulting in an expansion of the water.
Explanation:
.......
A car is traveling at a constant speed on the highway. Its tires have a diameter of 68.0 cm and are rolling without sliding or slipping. If the angular speed of the tires is 55.0 rad/s , what is the speed of the car?
Answer:
37.4m/s
Explanation:
since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:
v=55*0.68
v=37.40
A student bought a 1.55-ounce chocolate bar and left it in
a car on a hot day.
How many ounces of chocolate are in the melted bar?
A. Exactly 1.55 ounces
B. At least 1.55 ounces
C. An unknown number of ounces
D. Less than 1.55 ounces
Answer:
a
Explanation:
A student bought a 1.55-ounce chocolate bar and left it in a car on a hot day. Exactly 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
The change caused by an applied force is smaller the more mass a body has. The kilogram serves as the unit of mass in the International System of Units (SI).
As mass does not depends on the state of the object, exactly same mass of chocolate are in the melted bar that it was in chocolate bar. So, 1.55 ounces of chocolate are in the melted bar. Hence, option (A) is correct.
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You are reading a book and decide to estimate the magnitude of the electric and magnetic fields of the light that is incident on the book from your desk lamp. You can treat the lamp as a point source that emits sinusoidal EM waves uniformly in all directions. The book is at 1 m from the 100 Watt light bulb. Assume that all the electric energy is transformed into visible light.
(Part a) Calculate I, the intensity of the light incident on your book?
(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.
Answer:
a. 7.96 W/m² b. i. 0.205 V/m ii. 0.68 nT
Explanation:
(Part a) Calculate I, the intensity of the light incident on your book?
Intensity, I = Power, P/Area,A
I = P/A where P = 100 W and A = 4πr² where r = distance of source from book = 1 m.
So, I = P/A
= 100 W/4π(1 m)²
= 25/π W/m²
= 7.96 W/m²
(Part b) Find Eo and Bo, the amplitude of the electric and the magnetic fields of the EM waves emitted by the lamp.
i. Eo the amplitude of the electric field
Intensity, I = E²/cμ₀ where E = r.m.s value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = permeability of free space = 4π × 10⁻⁷ H/m
Thus, E = √(I/cμ₀)
substituting the values of the variables into the equation, we have
E = √(I/cμ₀)
E = √(7.96 W/m²/[3 × 10⁸ m/s × 4π × 10⁻⁷ H/m])
E = √(7.96 W/m²/120π H/s)
E = √(0.0211 Ws/Hm²)
E = 0.145 V/m
Now E = E₀/√2 where E₀ = maximum value of electric field
So, E₀ = √2E
= √2 × 0.145 V/m
= 0.205 V/m
ii. Bo the amplitude of the magnetic field
Since c = E₀/B₀ where c = speed of light = 3 × 10⁸ m/s
B₀ = E₀/c
= 0.205 V/m ÷ 3 × 10⁸ m/s
= 0.068 × 10⁻⁸ T
= 0.68 × 10⁻⁹ T
= 0.68 nT
A 1700 kg car drives around a flat 170-m -diameter circular track at 27 m/s.
What is the magnitude of the net force on the car?
Answer:
the magnitude of the net force on the car is 144,270 N.
Explanation:
To solve this problem, we need to use the formula for centripetal force:
F = (m * v^2) / r
where F is the net force, m is the mass of the car, v is the speed of the car, and r is the radius of the circular track (which is half the diameter).
First, we need to find the radius of the track:
r = d/2 = 170 m / 2 = 85 m
Now we can plug in the values we know:
F = (1700 kg * (27 m/s)^2) / 85 m
F = 144,270 N
Therefore, the magnitude of the net force on the car is 144,270 N.
A circular ferris wheel that revolves at a constant rate once every 30 seconds. The
radius of the ferris wheel is 10 m. What is the normal force of the ferris wheel on a 10
kg toddler at the very bottom of the ferris wheel?
The normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
Centripetal force of the Ferris wheelThe normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is calculated as follows;
Fn = Fc + mg
Fn = mω²r + mg
where;
ω is the angular speed = 1 rev/30 s = 2π/30 s = 0.21 rad/sFn = 10(0.21²) 10 + 10(9.8)
Fn = 102.41 N
Thus, the normal force of the ferris wheel on a 10kg toddler at the very bottom of the ferris wheel is 102.41 N.
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Please help me i need this to pass :((
Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.
What is the height L of the light liquid in the column in the right arm of the U-tube?Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.
The pressure at point A is equal to the pressure at point B
Therefore:
P₀ + ρgh = P₀ + ρgh
where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.
Simplifying this equation, we get:
ρgh = ρgh
Canceling out the ρ and solving for h, we get:
h = h
In other words, the height of the heavy liquid is the same in both arms of the U-tube.
Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.
Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).
Therefore, we can write:
P₀ + ρgh = P₀ + ρg(L+h)
where L is the height of the light liquid in the right arm.
Simplifying this equation, we get:
ρgh = ρgL + ρgh
Canceling out the ρgh and solving for L, we get:
L = (ρ/ρ₀)h
where ρ₀ is the density of the light liquid.
Substituting the given values, we get:
L = (0.92 g/cm³ / 13 g/cm³)h
L = 0.070769h
Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.
The volume of the heavy liquid in the left arm is:
V₁ = Ah = (13.2 cm²)(h cm)
V₁ = 13.2h cm³
The volume of the heavy liquid plus the light liquid in the right arm is:
V₂ = A(L+h) = (2.11 cm²)(L+h cm)
V₂ = 2.11(L+h) cm³
Since these volumes are equal, we can set them equal to each other and solve for h:
13.2h = 2.11(L+h)
13.2h = 2.11L + 2.11h
11.09h = 2.11L
h = (2.11/11.09)L
Substituting this into our expression for L, we get:
L = 0.070769(2.11/11.09)L
L = 0.01345L
L = 0.01444h
Substituting the given value for the density of the heavy liquid, we get:
L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)
L = 0.203 cm
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Complete question:
A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.
Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.
A 3 kg model airplane is traveling at a speed of 33 m/s. The operator then increases the speed up to 45 m/s in 2 seconds. How much
force did the engine need in order to make this change?
Answer:
Force = 18N
Explanation:
Force = [ mass ( final velocity - initial velocity ) ] / time taken
using the formula, here mass is 3 kg, final velocity = 45 m/s , initial velocity = 45 m/s , time taken = 2 seconds
Force = [ 3 ( 45 - 33 ) ] / 2
Force = 18N
Answer: 33kms
Explanation:
fms/f=5m/s^6b
a=7
h=6
A truck is parked at the bottom of a hill it moves from the bottom of the hill and parks at the top compared to when it was parked at the bottom of the hill at its new position in the truck now has
A. more kinetic energy
B. more potential energy
C. Less kinetic energy
D. less potential energy
Which landscape feature can be caused by chemical
weathering?
OU-shaped valley
O Basalt columns
O Limestone caves
Answer: Limestone Caves
Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.
5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° away from the central maximum. At what angle does the 18th minimum occur? A) 26.0° B) 1.94° C) 5.05° D) 0.44°
For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as
theta=25.3
Option A is correct
What angle does the 18th minimum occur?Generally, the equation for the the angle is mathematically given as
\(\theta=n(\lambda/d)\)
Therefore
\(\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)\)
In conclusion
theta/7=16/5
theta=10*7/5
theta=25.3
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Suppose you observe a star orbiting the galactic center at a speed of 1400 km/s in a circular orbit with a radius of 26 light-days. Calculate the mass of the object that the star is orbiting. Express your answer in solar masses to two significant figures.
Answer:
M = 9.9 x 10⁶ Solar masses
Explanation:
Here the centripetal force is given by the gravitational force between star and the object:
\(Gravitational\ Force = Centripetal\ Force \\\frac{mv^2}{r} = \frac{GmM}{r^2}\\\\M = \frac{v^2r}{G}\)
where,
M = Mass of Object = ?
v = orbital speed of star = 1400 km/s = 1400000 m/s
G = Universal Gravittaional Constant = 6.67 x 10⁻¹¹ N.m²/kg²
r = distance between star and object = (26 light-days)(2.59 x 10¹³ m/1 light-day) = 6.735 x 10¹⁴ m
Therefore,
\(M = \frac{(1400000\ m/s)^2(6.735\ x\ 10^{14}\ m)}{6.67\ x \ 10^{-11}\ N.m^2/kg^2}\)
M = (1.97 x 10³⁷ kg)(1 solar mass/ 1.989 x 10³⁰ kg)
M = 9.9 x 10⁶ Solar masses
Sally puts on wool socks and rubs her feet on a nylon carpet. How does static electricity build up in Sally?
O When electrons from the wool socks move into the carpet, Sally and her socks gain a negative charge.
O The friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
O Electrons from the wool socks move into the carpet, giving Sally and her socks a positive charge.
Electrons from the carpet move into the wool socks, giving Sally and her socks a positive charge.
When Sally puts on wool socks and rubs her feet on a nylon carpet, static electricity builds up through a process involving the movement of electrons. The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge.
The correct answer would be the friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.
The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge. This is due to the phenomenon known as the triboelectric effect.
The triboelectric effect occurs when two materials come into contact and then separate. During the rubbing process, the atoms in the two materials interact, causing the transfer of electrons between them. In this case, the wool socks have a greater affinity for electrons compared to the nylon carpet. As a result, electrons from the socks are transferred to the carpet, leaving the socks with a positive charge and the carpet with a negative charge.
Sally, wearing the wool socks, experiences an accumulation of excess electrons on her feet, giving her a negative charge. This excess negative charge on her body can lead to static electricity-related phenomena, such as experiencing a shock when touching a metal object or seeing her hair stand on end when near certain surfaces.
It's important to note that the movement of electrons determines the charge distribution during the triboelectric effect. In this scenario, electrons move from the wool socks to the nylon carpet, resulting in Sally and her socks gaining a negative charge.
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which are the four major components of the compression refrigeration cycle in order
Answer:
Compression, Condensation, Expansion, Evaporation
13. An 80.0 kg climber with a 20.0 kg pack climbs 8848 m to the top of Mount Everest. What is the climber's
potential energy?
a 6.94 x 106
2.47 106
b. 4.16 x 106
d. 1.00 X 106
The potential energy of the climber is 6.94 × 10⁶. It is the energy which is present in the body of an object which is at rest. Thus, the correct option is A.
What is Potential energy?Potential energy is the energy which is present in the body of an object which is at rest. This energy is transformed into kinetic energy when the body experiences any force and undergo motion. The SI unit of potential energy is Joule (J).
PE = m × g × h
where, PE = Potential energy,
m = mass of the object,
g = acceleration due to gravity,
h = height
PE = 80 × 9.8 × 8848
PE = 80 × 9.8 × 8848
PE = 784 × 8848
PE = 6936832
PE = 6.94 × 10⁶
Therefore, the potential energy of the climber is 6.94 × 10⁶.
Therefore, the correct option is A.
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Two tiny, spherical water drops, with identical charges of -6.19 × 10-16 C, have a center-to-center separation of 1.22 cm. (a) What is the magnitude of the electrostatic force acting between them? (b) How many excess electrons are on each drop, giving it its charge imbalance?
Answer:
a
\(F = 2.32*10^{-17} \ N\)
b
\(n =3869 \ electrons\)
Explanation:
From the question we are told that
The charge on each water drop is \(q_1=q_2=q = - 6.19*10^{-16} \ C\)
The distance of separation is \(d = 1.22\ cm = 0.0122 \ m\)
Generally the electrostatic force between the water drops is mathematically represented as
\(F = \frac{k * q_1 * q_2 }{ d^ 2}\)
Here k is the coulombs constant with value \(k = 9*10^9 \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.\)
So
\(F = \frac{9*10^9 * -6.19 *10^{-16} * (-6.19*10^{-16}) }{ 0.0122^ 2}\)
\(F = 2.32*10^{-17} \ N\)
Generally the quantity of charge is mathematically represented as
\(q = n * e\)
Here n is the number of electron present
and e is the charge on one electron with value \(e = 1.60*10^{-19} \ C\)
So
\(n = \frac{6.19 *10^{-16}}{1.60*10^{-19}}\)
\(n =3869 \ electrons\)
Conceptual Example 14 provides useful background for this problem. A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carousel itself (without riders) has a moment of inertia of 105 kg·m2. When one person is standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s. However, as this person moves inward to a point located 0.507 m from the center, the angular velocity increases to 0.795 rad/s. What is the person's mass?
For one person standing at a distance of 1.57 m from the center, the carousel has an angular velocity of 0.512 rad/s, the person's mass is mathematically given as
m = 24.2 kg
What is the person's mass?Generally, the equation for the conservation angular momentum is mathematically given as
(I + m * r0^2) * w0 = (I + m * r^2) * w^2
Therefore
(105 + m * 1.78^2) * 0.517 = (105 + m * 0.524^2) * 0.841
m = 24.2 kg
In conclusion, the mass
m = 24.2 kg
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