James weighs 120 pounds. He ran up the steps which rose 12 feet. John weighs 91 pounds. He ran up the same steps as James. How much more work did James do than John? (In ft-Ibs)

Number οf phοtοns per cubic millimeter = Number οf phοtοns / (Vοlume in cubic millimetres)

Tο find the physical length οf the pulse as it travels thrοugh space, we can use the equatiοn:

Length = (Speed οf light) x (Time)

(a) First, let's cοnvert the pulse duratiοn frοm picοsecοnds (ps) tο secοnds (s):

14.0 ps = 14.0 × \(10^{(-12)} s\)

The speed οf light is apprοximately 3 × \(10^8\) m/s, but we need tο cοnvert it tο the apprοpriate units tο match the pulse duratiοn. Sο, the speed οf light in picοmeters per secοnd (pm/s) is:

3 × \(10^8\) m/s = 3 × \(10^{14\) pm/s

Nοw we can calculate the length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 ×\(10^{(-12)} s\) )

(b) Tο find the number οf phοtοns in the pulse, we can use the equatiοn:

Energy οf the pulse = Number οf phοtοns × Energy per phοtοn

Given that the energy οf the pulse is 3.00 J and the wavelength οf the laser is 694.3 nm, we can calculate the energy per phοtοn using the equatiοn:

Energy per phοtοn = (Planck's cοnstant) × (Speed οf light) / (Wavelength)

Planck's cοnstant is apprοximately 6.626 × \(10^{(-34)\) J·s.

Nοw we can calculate the energy per phοtοn:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 × \(10^{(-9)\)m)

The number οf phοtοns in the pulse can be fοund by rearranging the equatiοn:

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) Tο find the number οf phοtοns per cubic millimeter, we need tο knοw the vοlume οf the beam. The vοlume οf a cylinder is given by the equatiοn:

Vοlume = π × (Radius)² × Length

The radius οf the circular crοss sectiοn is half the diameter, sο it is 0.300 cm (οr 0.003 m).

The number οf phοtοns per cubic millimeter can be calculated by dividing the number οf phοtοns by the vοlume οf the beam in cubic millimeters:

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimeters)

Let's calculate the results:

(a) The physical length οf the pulse:

Length = (3 × \(10^{14\) pm/s) × (14.0 × \(10^{(-12)\) s)

(b) The number οf phοtοns in the pulse:

Energy per phοtοn = (6.626 × \(10^{(-34)\) J·s) × (3 × \(10^8\) m/s) / (694.3 ×\(10^{(-9)\)m)

Number οf phοtοns = Energy οf the pulse / Energy per phοtοn

(c) The number οf phοtοns per cubic millimeter:

Vοlume = π × (0.003 m)² × Length

Number οf phοtοns per cubic millimetre = Number οf phοtοns / (Vοlume in cubic millimetres)

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Answer:

a=845.07 m/s2

Explanation:

m=0.142kg

F=120N

a=?

F=m*a /:m

a=F/m

a=120N/0.142kg

a=845,07m/s2

Answer:

a = 845.07 m/s²

Explanation:

As we know ,

as per newton's 2nd law:-

F = ma

therefore

a = F/m

given:

a = ?

F = 120N

m = 0.142 kg

procedure:-

a = 120/0.142

therefore :

a = 845.07 m/s²

Answer:

An article written by a scientist .

Explanation:

Primary sources information are those that contain first  hand information probably from the place of the activities or by the original contact of the information (source ) .

So primary information is normally contained in artifact , journals , letter , dissertations manuscripts  , videos and audio recordings .

The fact that the article is written by the scientist means he is the one who has the original information hence he is the first person to access the information , meaning he is the original owner .

Answer:

The not alligator side.

Obviously the middle, both sides will be shallow, so the middle will most likely  be the deepest part.

Explanation:

Answer:

\(\mu= 0.25\)

Explanation:

Given data

Force= 10N

mass= 4kg

r= 4*9.81

r= 39.24N

The expression for the force acting is expressed as

\(F=\mu*r\)

substitute

\(\mu=F/r\)

\(\mu= 10/39.24\)

\(\mu= 0.25\)

The minimum value of the coefficient of static friction in order for the block to remain motionless is 0.26.

Given the following data:

Scientific data:

To determine the minimum value of the coefficient of static friction in order for the block to remain motionless:

Note: The force that is required to make the block motionless must be lesser than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

\(Fs = uFn = umg\)

Where;

Making u the subject of formula, we have:

\(u=\frac{F_s}{mg}\)

Substituting the given parameters into the formula, we have;

\(u=\frac{10}{4.0 \times 9.8} \\\\u=\frac{10}{39.2}\)

u = 0.26

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The work done by the force of 50 N  on an object opposite to the direction of motion is equal to  -150 J. Therefore, option (D) is correct.

Work done on an object can be defined as the energy utilized when a force is applied in order to move the object through a definite displacement.

When the 'F' is the applied force and 'd' is the displacement by an object and W is work done will be equal to:

W= F × d

If the body is moving in the opposite direction of the applied force then the work done will be negative.

Given, the applied force, F = 50 N

The displacement of the object, d = 3.0 m

The work done is equal to W = F.d

W = 50 × 3

W = 150 J

As the object is moving in the opposite direction of the applied force so the work done will be - 150 J.

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Using the Standard population for region, the proportionate mortality for old people in region Y is 80%. The correct answer is option  (c).

To calculate the proportionate mortality, we need to determine the number of deaths among old people in region Y and divide it by the standard population for region Y.

According to the given options, option c is the correct answer, which states that the proportionate mortality is 48/60 = 80%.

This means that out of the standard population of 60 in region Y, 48 deaths occurred among old people. This indicates a high proportionate mortality rate for the elderly population in region Y, reflecting the impact on that age group's mortality in the region.

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The time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

Given information: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. One astronomical unit is the distance from the Earth to the Sun or about 150 million km.

Calculation: To find how many km was New Horizons from Earth, we need to multiply the distance in AU by the conversion factor. 1 AU = 150 million km 50 AU = 50 x 150 million km = 7.5 billion km Thus, the New Horizons spacecraft was 7.5 billion km from Earth in the spring of 2021. Now, let's move on to the second question. The planet Mars completes one orbit of the Sun in 687 days. We need to express this time in seconds using scientific notation.

To convert days to seconds, we need to multiply the number of days by the conversion factor. 1 day = 86400 seconds 687 days = 687 x 86400 seconds= 5.94 x 10⁷ seconds (using scientific notation) Therefore, the time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

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Answer:

hey mate your answer is here

Answer:

c

Explanation:

i think

Answer: B

Explanation:

Answer:

The chemical and physical processes that change objects on Earth's surface over time are called weathering .  Over thousands of years, weathering breaks up rocks into smaller pieces.

b. Mechanical weathering,Chemical makeup,Surface area,clay,ice wedging expands, abrasion

   there all in order btw

The angle θ0 at which the electron is incident between the two plates, we can use the relationship θ0 = arctan(E * L / (2d)).

determine the angle θ0 at which the electron is incident between the two plates, we can consider the forces acting on the electron due to the electric field.

The electric field between the plates is directed from left to right. The force experienced by the electron due to the electric field is given by the equation:

F = q * E

where F is the force, q is the charge of the electron, and E is the electric field strength.

Since the electron is negatively charged, it experiences a force in the opposite direction to the electric field. This force will cause the electron to accelerate in the opposite direction.

When the electron enters the region between the plates:

The force due to the electric field will act on the electron in the opposite direction to its initial motion, causing it to decelerate. The electron will follow a curved path due to this deceleration.

When the electron exits the region between the plates:

The force due to the electric field will act on the electron in the same direction as its final motion, causing it to accelerate. The electron will follow a curved path due to this acceleration.

Since the situation is symmetrical, the angle at which the electron exits the region between the plates will be the same as the angle at which it enters.

We need to determine the angle θ0 at which the electron enters the region between the plates.

Consider a small portion of the path between the plates and assume that the electric field is constant within this small region.

In this small region, the net force acting on the electron can be expressed as:

F_net = F_electric - F_centrifugal

where F_electric is the force due to the electric field, and F_centrifugal is the centrifugal force.

The force due to the electric field can be calculated as:

F_electric = q * E

The centrifugal force can be calculated as:

F_centrifugal = m * \(v^2 / r\)

where m is the mass of the electron, v is its velocity, and r is the radius of the curved path.

The electron is moving in a curved path, the net force acting on it is responsible for the centripetal force required to maintain this curved path.

Setting the net force equal to the centripetal force, we have:

F_electric - F_centrifugal = m * \(v^2 / r\)

Substituting the expressions for F_electric and F_centrifugal, we get:

q * E - m * v^2 / r = m * \(v^2 / r\)

Simplifying the equation, we have:

q * E = 2 * m * \(v^2 / r\)

Since the electron enters and exits the region between the plates with the same speed v, we can simplify further:

q * E = 2 * m *\(v^2 / r\)

The forces acting on the electron when it enters the region between the plates:

The force due to the electric field is acting in the opposite direction to the initial motion, causing deceleration.

The centrifugal force is acting in the same direction as the initial motion, opposing the deceleration.

For the electron to enter the region between the plates, the force due to the electric field must be greater than the centrifugal force.

We have:

q * E > m * \(v^2 / r\)

Since the electron is moving perpendicular to the electric field, the electric force can be expressed as:

q * E = q * (V/d)

where V is the voltage between the plates, and d is the spacing between the plates

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Answer:

b. they move in convection currents.

Explanation:

i learned this in 4th grade

Answer:

55.56%

Explanation:

We'll begin by calculating the work done in pushing the wedge. This can be obtained as follow:

Force (F) = 900 N

Distance (s) = 0.1 m

Workdone (Wd) =..?

Wd = F × s

Wd = 900 × 0.1

Wd = 90 J

Finally, we shall determine the efficiency. This can be obtained as follow:

Work output = 50 J

Work input = 90 J

Efficiency =?

Efficiency = work output / work input

Efficiency = 50 / 90 × 100

Efficiency = 55.56%

Thus, the efficiency is 55.56%

Answer:

KI

Explanation:

Based on the given surface temperature and luminosity, Arcturus is classified as a K-type star.

The classification of stars is based on their spectral characteristics, which are determined by their surface temperature. The spectral classification system uses letters to denote the temperature, ranging from the hottest O-type stars (over 30,000 K) to the coolest M-type stars (below 3,500 K), with intermediate types B, A, F, G, and K in between.

The luminosity of a star is a measure of its total energy output, and it is related to the star's mass and size. Higher luminosity stars are generally more massive and larger than lower luminosity stars.

Arcturus has a surface temperature of 4560 K, which corresponds to a spectral type of K. Its luminosity is 170 times that of the Sun, which means that it is a relatively bright star. Overall, Arcturus is classified as a K-type giant star, which is a type of evolved star that has exhausted the hydrogen fuel in its core and is now fusing helium.

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Answer:

5

Explanation:

Venus has relatively few impact craters and these craters are distributed fairly evenly over the entire planet.

-This suggests that older impact craters were covered over everywhere on the planet.

The solar system is an arrangement of the sun and the planets. The sun is at the focus of the solar system and it is surrounded by the planets moving radially outwards from the focus. This is the heliocentric model of the solar system.

Now, the magnitude of gravity on a planet determines the weight of a body on that planet. The greater the gravitational pull, the greater the weight of the object on that planet.

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The old farm house had been wrapped in insulation and sided.

refrigerator may be considered to be a heat engine operated in reverse.

The warmed water may become a thermal pollution problem in terms of the receiving body of water.

First, compare two balls from the heavier group to Group A. There must be two weighings; lower bound because there are three options per weighing.

a) Follow these steps to determine which ball is heavier in just two weighings:

1. nine balls should be divided into three groups of three balls each—Group A, Group B, and Group C.

2. Using the balanced scale, weigh Group A in comparison to Group B:

3. Using just two weighings, you can determine which ball is heavier by following these steps.

4.  Compare those two balls to one another:

Using just two weighings, you can determine which ball is heavier by following these steps.

(b) The decision tree lower bound demonstrates that fewer than two weighings are required to identify the defective ball. This is due to the fact that there are nine balls, and each one can only tell you how much each group weighs. We can only reduce the number of possibilities by a factor of three with each weighing.

We would need to compare all possible ball combinations, which would require more than two weighings, in order to distinguish between all nine balls in a single weigh. Therefore, the minimum required to determine which of the nine balls with identical appearances is the heavier is two weighings.

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Answer:

588 J

Explanation:

P.E = mgh

      = 6 * 9.8 * 10

     = 588 J

if g value is rounded and taken as 10 then answer is 600 J.

Magma is called for the dense mix of dry hot rock fragments and hot gas erupting from volcanic vent at high speed.

Magma is the extremely hot liquid and flows under the surface of the earth. When this liquid comes out to the surface of earth, then called as lava.

Gas bubble, making up to lave are energetic in nature, because they keep on expanding in all directions, they will go all out to the only open are of a volcano, the vent, in an upward direction.

Hence Magma is called for the dense mix of dry hot rock fragments and hot gas erupting from volcanic vent at high speed.

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The negative plate is the one facing us because the electric field between the plates is zero, which can only happen if the two plates have the same magnitude and opposite sign of charge density.

Charge density is the amount of electric charge per unit area or per unit volume of a material or object. It is usually denoted by the symbol ρ and is measured in units of coulombs per square meter (C/m²) or coulombs per cubic meter (C/m³).

In the case of a charged plate, the charge density is the total charge on the plate divided by its surface area. For example, if a plate has a charge of 60 µC and an area of 2 m², then the charge density is:

Charge density = 60 µC / 2 m² = 30 µC/m²

Charge density is an important concept in electrostatics, as it is used to describe the distribution of electric charge over a surface or within a volume. It is also used in the calculation of electric fields and forces in electrostatics, as the electric field depends on the charge density of the objects producing the field.

Two large, charged plates with charge density ±30µC/m² facing each other with a separation of 5.0 mm.

One of the plates has a negative charge density.

We want to find out which plate is negative

1. Calculate the total charge on one of the plates using the charge density and the area of the plate:

Q = ±30 µC/m² * A

Here, A is the area of one of the plates.

2. Calculate the electric field due to each plate using Coulomb's law:

E = (1/4πε₀) * (Q / r²)

Here, r is the distance between the plates, which is 5.0 mm or 0.005 m.

ε₀ is the permittivity of free space, which is a constant and has a value of 8.85 x 10⁻¹² F/m.

Since there are two plates, calculate the electric field due to each plate and then take the difference between them to get the net electric field between the plates.

3. Substitute the values and calculate the electric field due to each plate:

E1 = (1/4πε₀) * (Q / r²)

E2 = (1/4πε₀) * (Q / r²)

Here, E1 is the electric field due to one plate, and E2 is the electric field due to the other plate. Since the plates have the same magnitude of charge density, their charges will have the same magnitude too, so we can drop the absolute value sign in Coulomb's law.

4. Subtract the electric field due to one plate from the electric field due to the other plate to get the net electric field:

E = E1 - E2

E = 0

Since, the net electric field is zero, this means that the electric field due to one plate is equal in magnitude and opposite in direction to the electric field due to the other plate. Therefore, the plates must have the same magnitude of charge and opposite signs of charge density.

5. Since, one of the plates has a negative charge density is known, this means that the negative plate is the one facing us. Therefore, the negative plate is the one that we were asked to identify.

Therefore, the negative plate is the one facing us.

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Answer:

Choice 2

Explanation:

Formula for Momentum is change in velocity * mass

The **process** most responsible for shaping the large-scale structure of the universe is **gravitational instability**.

Gravitational instability is the driving force behind the formation of cosmic structures, such as galaxies, clusters, and superclusters. It originates from the initial density fluctuations present in the early universe. These fluctuations arise from quantum mechanical processes during the inflationary phase of the universe and are imprinted on the cosmic microwave background radiation. Over time, under the influence of gravity, these density variations grow and amplify, causing matter to collapse and form structures.

The gravitational attraction between matter leads to the clumping of regions with higher density, while less dense regions expand. This process creates an intricate web-like structure known as the cosmic web, consisting of filaments, voids, and clusters. The cosmic microwave background radiation, as observed by satellite missions like the Planck spacecraft, provides valuable insights into the initial conditions of these density fluctuations and helps us understand the evolution of the universe's large-scale structure.

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Answer: The answer is 222.8

Answer:

-17.5 nC

Explanation:

charge A = -30 nC

charge B = -5 nC

After adding them it would be the average of the two charges because of the getting same voltage difference. so

c = (-30+(-5)) / 2 nC

c= -17.5 nC

answer is -17.5 nC

ANSWER

EXPLANATION

Parameters given:

Speed of electron, v = 4.10 * 10^3 m/s

Magnetic field, B = 1.45 T

Magnetic force, F = 1.40 * 10^(-16) N

To find the angle that the velocity of the electron makes with the magnetic field, apply the formula for magnetic force:

where θ = angle

q = electric charge = 1.6 * 10^(-19) C

Make θ the subject of the formula:

Therefore, the angle that the velocity makes is:

To find the second angle, subtract the angle from 180 degrees:

The angles are: