jack and jill ordered 2 identical pizzas one cheese one pepperoni. jack ate 5/6 and jill ate 1/2 of a pizza. How much pizza did they eat together?


PLS HELPPP

Answer:

0 and  -1

Step-by-step explanation:

Hello,

\(x^3+2x^2+x = x(x^2+2x+1)=x(x+1)^2\)

so the roots are

0 and -1 (to get x+1=0 )

do not hesitate if you need further explanation

hope this helps

Answer:

It's actually X = 0, X = - 1, with multiplicity 2, Option D, on Edge2020

Step-by-step explanation:

I just did it on edge :)

Answer:

X = 9

Step-by-step explanation:

Vertical angles equal to each other, the example shows vertical angles.

6x + 2 = 54

-2 -2

6x/6 = 54/6

X = 9

Hope this helps you have a nice day!

Answer: 4(20+9)+4(6) thats the first one

4(20)+4(9)+4( 6) thats the second one

80+36+24=140 that is the third

Step-by-step explanation:

Answer:

4(20+9)+4(6)

4(20)+4(9)+4( 6)

Step-by-step explanation:

Triangle ADC also has a right angle at D, making it a right-angled triangle.

The exact value of x be 2.25.

The hypotenuse's square is equal to the sum of its two other side squares of a right-angled triangle, according to the Pythagoras theorem.

Triangle ADB exists even a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADB = BD = 4,

Height of Triangle ADB = AD = 3,

Hypotenuse of Triangle ADB = AB

Using the Pythagoras Theorem, we get,

\($\left[(A D)^2+(B D)^2\right]=(A B)^2$\)

substitute the values in the above equation, we get

or,\($(A B)^2=\left[(3)^2+(4)^2\right]$\)

simplifying the equation, we get

or, \($(A B)^2=[9+16]$\)

or, \($(A B)^2=25$\)

or, \($\sqrt{(A B)^2}=\sqrt{25}$\)

or, AB = 25

Triangle ADC is also a right-angled triangle with right-angle at D.

Therefore, Base of Triangle ADC = DC = x

Height of Triangle ADC = AD = 3,

And, Hypotenuse of Triangle ADC = AC

Using the Pythagoras Theorem, we get,

\(& {\left[(D C)^2+(A D)^2\right]=(A C)^2} \\\)

simplifying the equation, we get

\(& \text { or },(A C)^2=\left[(3)^2+(x)^2\right] \\\)

\(& \text { or },(A C)^2=\left[9+x^2\right]\)

Triangle ABC is also a right-angled triangle with right-angle at A. Therefore, Base of Triangle ABC = AC,

Height of Triangle ABC = AB = 5,

And, Hypotenuse of Triangle ABC =  BC = (4 + x)

Using the Pythagoras Theorem, we get,

\(& {\left[(A C)^2+(A B)^2\right]=(B C)^2} \\\)

\(& \text { or, }(B C)^2=\left[(A C)^2+(A B)^2\right] \\\)

substitute the values in the above equation, we get

\(& \text { or, }(4+x)^2=\left[\left(9+x^2\right)+(5)^2\right] \\\)

simplifying the equation, we get

\(& \text { or, }\left[4^2+(2 \times 4 \times x)+x^2\right]=\left[9+x^2+25\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[(9+25)+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]=\left[34+x^2\right] \\\)

\(& \text { or, }\left[16+8 x+x^2\right]-\left[34+x^2\right]=0 \\\)

\(& \text { or, },(16-34)+8 x+\left(x^2-x^2\right)=0 \\\)

8x - 18 = 0

8x = 18

\(& \text { or, } x=\frac{18}{8} \\\)

\(& \text { or, } x=\frac{9 \times 2}{4 \times 2} \\\)

\(& \text { or, } x=\frac{9}{4} \\\)

Therefore, the value of x be 2.25.

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Answer:

---------------

Let the numbers be s and l.

We are given that:

Set up equations:

Eliminate l:

Solve for s:

Find l:

Answer:

Length = 7

Width = 15

Step-by-step explanation:

L= x

W= x-8

2x+2(x-8)=44

Answer:

your answer is A. the reason is because it has 2200 sqare units

The answer to this Question is A we can use basic knowledge from linear equations to find the answer

What is Linear Equation?

Linear Equation is a equation in which degree of variables is 1 only

Yes the given case is possible only under some conditions that we can define as follows and as given in Linear Equations from Options

together cole and maggie have won 30 games and we are also given that  out of those 30 maggie has won 4 games

we should closely see at Linear Equations given in Options.

therefore cole has won 26 games which is more than 13

Hence the answer to the Question is Yes

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Answer:

74 units squared

Step-by-step explanation:

we know that the area of a square or rectangle is A = L × w

so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.

so I'll start with the middle square its length is 8 and width is 8 too.

A = 8 × 8

A = 64

now we'll move on to the other small ones to the side.

the one on the right side it's length is 2 and width is 2.

A = 2 × 2

A = 4

and then the last one on the left, Length is 3, width is 2.

A = 2 × 3

A = 6

now we'll add up all of the areas to get the total area.

Total = 64 + 4 + 6

Total = 74 units squared

The fraction of the class that is sophomores is \(35/43\).

The fraction of the class that is sophomores, divide the number of sophomores by the total number of students in the class.

Number of sophomores = 35

Total number of students = 43

Fraction of sophomores = (Number of sophomores)/(Total number of students Fraction of sophomores)

Fraction of sophomores  \(= 35 / 43\)

Therefore, the fraction of the class that are sophomores is = \(35/43\).

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The length of cable in the coil that weighs 5 1/2 kilograms is 1/2 meter.

Let x be the length of cable in meters that weighs 5 1/2 kilograms.

Then, we can write:

1 meter / (75/1000) kilograms = x meters / 5.5 kilograms

Simplifying the left side, we get:

1 meter / (75/1000) kilograms = 1000 / 75 meters/kilogram

= 40/3 meters/kilogram

Substituting this into our proportion, we get:

40/3 meters/kilogram * x meters = 5.5 kilograms

Multiplying both sides by 3/40, we get:

x meters = (5.5 kilograms) * (3/40) * (40/3 meters/kilogram)

               = 1/2 meter

The length is 1/2 meter

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This DE has characteristic equation

\(4r^2 - 12r + 9r = (2r - 3)^2 = 0\)

with a repeated root at r = 3/2. Then the characteristic solution is

\(y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}\)

which has derivative

\({y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}\)

Use the given initial conditions to solve for the constants:

\(y(0) = 3 \implies 3 = C_1\)

\(y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2\)

and so the particular solution to the IVP is

\(\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}\)

The length of EB is approximately 14.6 units when rounded to the nearest tenth.

To find the length of EB, we can use the property of similar triangles in this diagram. By looking at triangle DFE and triangle CFB, we can see that they are similar triangles.

Using the similarity ratio, we can set up the proportion:

DF / CF = DE / EB

Plugging in the given values, we have:

13.1 / 10.9 = 17.5 / EB

To find EB, we can cross-multiply and solve for EB:

13.1 * EB = 10.9 * 17.5

EB = (10.9 * 17.5) / 13.1

EB ≈ 14.6

Therefore, the length of EB is approximately 14.6 units when rounded to the nearest tenth.

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Answer:

Step-by-step explanation:

Place the compass at one end of line segment, and taking it more than 1/2 of MN is its 1st step

Answer:

39

Step-by-step explanation:

\(\displaystyle A=\int^3_0(16-x^2)dx=16x-\frac{x^3}{3}\biggr|^3_0=16(3)-\frac{3^3}{3}=48-\frac{27}{3}=48-9=39\)

14. The trigonometric equation (sin47°/cos43°)² + (cos43°/sin47°)² - 4cos²45° = 4

15. In the trigonometric equation 2(cos²θ - sin²θ) = 1, θ = 15°

A trigonometric equation is an equation that contains a trigonometric ration.

14. To find the value of (sin47°/cos43°)² + (cos43°/sin47°)² - 4cos²45°, we proceed as follows

Since we have the trigonometric equation (sin47°/cos43°)² + (cos43°/sin47°)² - 4cos²45°,

We know that sin47° = sin(90 - 43°) = cos43°. So, substituting this into the equation, we have that

(sin47°/cos43°)² + (cos43°/sin47°)² - 4cos²45° = (cos43°/cos43°)² + (cos43°/cos43°)² - 4cos²45°

= 1² + 1² - 4cos²45°

We know that cos45° = 1/√2. So, we have

1² + 1² - 4cos²45° = 1² + 1² - 4(1/√2)²

= 1 + 1 + 4/2

= 2 + 2

= 4

So, (sin47°/cos43°)² + (cos43°/sin47°)² - 4cos²45° = 4

15. If 2(cos²θ - sin²θ) = 1 and θ is a positive acute angle, we need to find the value of θ. We proceed as follows

Since we have the trigonometric equation 2(cos²θ - sin²θ) = 1

We know that cos2θ = cos²θ - sin²θ. so, substituting this into the equation, we have that

2(cos²θ - sin²θ) = 1

2(cos2θ) = 1

cos2θ = 1/2

Taking inverse cosine, we have that

2θ = cos⁻¹(1/2)

2θ = 30°

θ = 30°/2

θ = 15°

So, θ = 15°

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Answer:

-22=22

Step-by-step explanation:

3,5-5,7=

-22/22

The equation of the line passing through R and PQ is 4(y - 6) = -x - 1/2.

To find the equation of the line passing through the midpoint R and the points P and Q, we first need to find the coordinates of the midpoint R. The midpoint coordinates can be found by taking the average of the x-coordinates and the average of the y-coordinates of P and Q.

The x-coordinate of the midpoint R is (3 + (-5)) / 2 = -1/2.

The y-coordinate of the midpoint R is (5 + 7) / 2 = 6.

So, the coordinates of the midpoint R are (-1/2, 6).

Next, we can use the two-point form of the equation of a line, which states that the equation of the line passing through points (x₁, y₁) and (x₂, y₂) is given by:

(y - y₁) = (y₂ - y₁) / (x₂ - x₁) \(\times\) (x - x₁)

Substituting the coordinates of R (-1/2, 6) and P (3, 5) into the equation, we have:

(y - 6) = (7 - 5) / (-5 - 3) \(\times\)(x - (-1/2))

Simplifying the equation:

(y - 6) = (2 / -8) \(\times\)(x + 1/2)

(y - 6) = -1/4 \(\times\)(x + 1/2)

4(y - 6) = -x - 1/2

Therefore, the equation of the line passing through R and PQ is 4(y - 6) = -x - 1/2.

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Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July

X pounds - 0.35 * X pounds = 9,500 pounds

Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.

To determine the number of pounds of raw materials that should be purchased in July, we need to calculate the raw materials production needs for August and then consider the inventory policies given in the information provided.

Each unit of finished goods requires 5 pounds of raw materials. The budgeted unit sales for August are 19,000 units. Therefore, the raw materials production needs for August would be 19,000 units multiplied by 5 pounds per unit, which equals 95,000 pounds.

The ending raw materials inventory equals 10% of the following month’s raw materials production needs. Therefore, the desired ending raw materials inventory for July would be 10% of 95,000 pounds, which is 9,500 pounds.

To calculate the raw materials purchases for July, we need to consider the payment terms provided. Thirty-five percent of raw materials purchases are paid for in the month of purchase and 65% in the following month.

Let's assume the raw materials purchases for July are X pounds. Then the payment for 35% of X pounds will be made in July, and the payment for 65% of X pounds will be made in August.

The payment for raw materials purchases in July (35% of X pounds) will be:

0.35 * X pounds

The payment for raw materials purchases in August (65% of X pounds) will be:

0.65 * X pounds

Since the raw materials purchases for July should cover the desired ending raw materials inventory for July (9,500 pounds), we can set up the following equation:

Raw materials purchases in July - Payment for raw materials purchases in July = Desired ending raw materials inventory for July

X pounds - 0.35 * X pounds = 9,500 pounds

Solving this equation will give us the value of X, which represents the pounds of raw materials that should be purchased in July.

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The correct statement is: She should calculate the ratio between the number of calories she burned versus the number of miles she ran.

The quantitative relation between two amounts shows the number of times one value contains or is contained within the other. for example-"the ratio of computers to students is now 2 to 1"

Given here: The table containing data calories vs miles run.

You can tell if a table shows a proportional relationship by calculating the ratio of each pair of values. If those ratios are all the same, the table shows a proportional relationship.

Thus calculating the ratio for each pair of entries we get

1) ratio=118/1.2

      =295:3a  or unit rate 98.33 calories per mile

2) 190/2= 95:1 or unit rate 95 calories per mile

3) 226/2.4=565:6 or unit rate94.1

clea,rly the ratios are different.

Hence, The table containing the data doesn't form a proportional relationship.

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Answer:

1850 cents or $18.50

Step-by-step explanation:

50*8=400

3*35=105

5*269=1345 ($2.69 can be converted to 269 cents)

400+105+1345=1850

Answer:(x + 1)(x - 1)(x + 5)(x - 3) is the fully factored form of the polynomial.

The zeros are (-1, 0), (1, 0), (-5, 0), and (3, 0).

x^4 + 2x^3 - 16x^2 - 2x + 15

We can use the rational roots theorem to find some of the possible roots, and after finding just one root, we can simplify this polynomial.

List factors of 15:

1, 3, 5, 15.

List factors of 1:

1.

Our possible rational factors are:

+/- 1, +/- 3, +/- 5, +/- 15.

To find factors, we can use the remainder theorem.

Replace all x values with 1.

1^4 + 2(1)^3 - 16(1)^2 - 2(1) + 15 = 0

Because the answer is zero, it means that 1 is a root.

We can divide this polynomial by x - 1 to find a simplified form.

After dividing, our quotient is: x^3 + 3x^2 - 13x - 15

We can continue finding factors by using the rational roots theorem. Once we have only three terms, we can try to factor using the AC method.

Our next possible root is -1.

(-1)^3 + 3(-1)^2 - 13(-1) - 15 = 0

We know that -1 is also a root, and so we can divide the polynomial by x + 1.

After diving we're left with x^2 + 2x - 15.

Now, we can try to factor using the AC method.

List factors of -15.

1 * -15

-1 * 15

3 * -5

-3 * 5 (these digits satisfy the criteria.)

Split the middle term.

x^2 - 3x + 5x - 15

Factor binomials.

x(x - 3) + 5(x - 3)

Rearrange binomials.

(x + 5)(x - 3)

Add in the two factors we already factored out.

(x - 1)(x + 1)(x + 5)(x - 3)

Step-by-step explanation:

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

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Answer:A

Step-by-step explanation:

Invested in each vehicle is $40,000 if the annual investment income is $944.25.

Let

CD's = x

Bonds = x + 60000

Stocks = y

x + x + 60000 + y = 140000 ----> 2x + y = 80000 .......(1)

Using I = Prt; t = 1; I = Pr

2x + 3.7(x + 60000) + 11.1y = 7800(100× )  × Since I used an exact proportion, the opposite side needs to be multiplied by 100.

5.7x + 11.1y = 558000 .......(2)

Either elimination or substitution;

x = 20000 y = 40000

So CD's = 20000, Bonds = 80000, Stocks = 40000

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Answer: right, left

Step-by-step explanation:

Answer:

34

Step-by-step explanation:

Given that the ages of a group of lifeguards are listed. 17, 17, 18, 19, 22, 23, 25, 27, 32, 38 If another age of 18 is added to the data, (d) The mean would decrease in value to about 23.3.

The mean is also called as the average or a measure of central tendency.  The mean can be calculated as the sum of observation divided by the number of observation.

Given in the question,

ages of lifeguard : 17, 17, 18, 19, 22, 23, 25, 27, 32, 38

Sum of ages = 238

Number of ages = 10

Mean = \(\frac{Sum\ of \ ages}{Number \ of \ ages } = \frac{238}{10} = 23.8\)

Given that an age of 18 is added to the data,

The sum of ages changes to = 238 + 18 = 256

Number of ages given changes to = 10+1 = 11

Mean becomes = \(\frac{Sum\ of \ ages}{Number \ of \ ages } = \frac{256}{11} = 23.27\)

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Answer:

4

Step-by-step explanation:

I'm going to assume you mean [ m + 2 = 6 ]

m + 2 = 6

~Subtract 2 to both sides

m = 4

Best of Luck!

The amount in year 6 is $1282.5.

What is simple interest?

Simple interest is a quick and easy method of calculating the interest charge on a loan. Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.

Given,

rate of interest = 7%

time = 1 year

Amount on first year = $950

First we will calculate simple interest for 5 years, because amount is available for 1 year.

SI =PRT

SI = 950(7/100)1

SI = $332.5

Therefore, the amount after 6 years = 950+332.5

=$1282.5

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