If there are 24 people and each of them will eat 2 cups of ice cream, then there will be 48 cups of ice cream in total.
We know that 1 gallon is equivalent to 16 cups, so we form the following proportion
\(\frac{1\text{gallon}}{x}=\frac{16\text{cups}}{48\text{cups}}\)Let's solve for x
\(\begin{gathered} x=\frac{48}{16}\text{gallons} \\ x=3\text{gallons} \end{gathered}\)Hence, he should buy 3 tubs of ice cream in total.Seven years ago, Grogg's dad was 6 times as old as Grogg, and 3 years ago, his dad was 4 times as old as Grogg. How old is Grogg's dad currently?
Answer:
Grogg's dad is 22
Step-by-step explanation:
Let D = dad's current age
Let g = Grogg's current age
6(d - 7) = g - 7 → 6d - 42 = g - 7 → 6d -35 = g
4(d - 3) = g - 3 → 4d -12 = g - 3 → 4d -9 = g
Set the two equations equal to each other and solve for d
6d - 35 = 4d - 9 Subtract 4d from both sides
2d -35 = -9 Add 35 to both sides
2d = 44 Divide both sides by 2
d = 22
Helping in the name of Jesus.
Answer:
Step-by-step explanation:
d = current dad age
g = current grogg age
d-7 = 6(g-7)
d-3 = 4(g-3)
Let's solve the first equation first:
Add 7 to both sides: d - 7 +7 = 6g - 42 + 7 so d = 6g - 35
Substitude d = 6g - 35 for d in d - 3 = 4g - 12
(6g-35)-3 = 4g-12 = 6g-38 = 4g-12
Subtract 4g from both sides: 2g - 38 = -12
Add 38 to both sides: 2g = 26
Easy: g = 13
And now substitude g in for any equations.
d-3 = 52-12
d = 43
A survey found that the American family generates an average of 17.2 pounds of glass garbage each year. Assume the standard deviation of the distribution is 2.5 pounds. Find the probability that the mean of a sample of 40 families will be between 17.1 and 18.1 pounds. Assume that the sample is taken from a large population and the correction factor can be ignored. Round your final
answer to four decimal places and intermediate z-value calculations to two decimal places
The probability that the mean of a sample of 40 families will be between 17.1 and 18.1 pounds is given as follows:
0.5874 = 58.74%.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by \(\mu\) and standard deviation symbolized by \(\sigma\) is obtained by the rule presented as follows:
\(Z = \frac{X - \mu}{\sigma}\)
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).The parameters for this problem are given as follows:
\(\mu = 17.2, \sigma = 2.5, n = 40, s = \frac{2.5}{\sqrt{40}} = 0.3953\)
The probability that the mean of a sample of 40 families will be between 17.1 and 18.1 pounds is the p-value of Z when X = 18.1 subtracted by the p-value of Z when X = 17.1, hence:
\(Z = \frac{X - \mu}{\sigma}\)
By the Central Limit Theorem:
\(Z = \frac{X - \mu}{s}\)
Z = (18.1 - 17.2)/0.3953
Z = 2.28
Z = 2.28 has a p-value of 0.9887.
Z = (17.1 - 17.2)/0.3953
Z = -0.25
Z = -0.25 has a p-value of 0.4013.
Hence:
0.9887 - 0.4013 = 0.5874 = 58.74%.
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Alana is 2 years younger than Tommy and the
sum of their ages is 16. How old is Alana?
Answer:
7
Step-by-step explanation:
9 - 2 = 7
7 + 9 = 16
Mark as Brainliest
simplify the equation
Answer:
\(a \sqrt[5]{b} \)
Step-by-step explanation:
solution Given:
\( \sqrt[5]{ {a}^{3} {b}^{2} } \times \sqrt[5]{ {a}^{2}{b }^{ - 1} } \)
since i indices rule if the power is same it can be multiplied or divided.
\( \sqrt[5]{ {a}^{3} {b}^{2} \times {a}^{2} {b}^{ - 1} } \)
since power is added of like terms in multiplication
\( \sqrt[5]{ {a}^{3 + 2} {b}^{2 - 1} } \)
again simplifying
\( \sqrt[5]{ {a}^{5} b} \)
by using indices formula
\( \sqrt[x]{ {a}^{y} } = {a}^{ \frac{y}{x} } \)
we get
\(a \sqrt[5]{b} \)
Answer:
\(a \sqrt[5]{b}\)
Step-by-step explanation:
Given expression:
\(\sqrt[5]{a^3b^2} \times \sqrt[5]{a^2b^{-1}}\)
\(\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:\)
\((a^3b^2)^{\frac{1}{5}} \times (a^2b^{-1})^{\frac{1}{5}}\)
As the exponents are the same,
\(\textsf{apply exponent rule} \quad a^n \cdot c^n=(a \cdot c)^n:\)
\((a^3b^2a^2b^{-1})^{\frac{1}{5}}\)
Collect like terms:
\((a^3a^2b^2b^{-1})^{\frac{1}{5}}\)
\(\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:\)
\((a^{(3+2)}b^{(2-1)})^{\frac{1}{5}}\)
Simplify the exponents:
\((a^5b^1)^{\frac{1}{5}}\)
\(\textsf{Apply exponent rule} \quad (a^bc^d)^n=(a^b)^n \cdot (c^d)^n:\)
\((a^5)^{\frac{1}{5}} \cdot (b^1)^{\frac{1}{5}}\)
\(\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:\)
\(a^{\frac{5}{5}} \cdot b^{\frac{1}{5}}\)
Simplify:
\(a^1 \cdot b^{\frac{1}{5}}\)
\(a \cdot b^{\frac{1}{5}}\)
\(\textsf{Apply exponent rule} \quad a^{\frac{1}{n}}=\sqrt[n]{a}:\)
\(a \sqrt[5]{b}\)
|3t – 9| = 3 Step by step
Answer:
t = {4, 2}
Step-by-step explanation:
|3t-9| = 3
Split into two parts,
3t-9 = 3, and -(3t-9) = 3
Solve
t-3 = 1, and -(t-3) = 1
t = 4, and -t+3 = 1
t = 4, and t=2
At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 21 knots. How fast (in knots) is the distance between the ships changing at 4 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
At \($5 \mathrm{pm}$\) the distance between the ships is changing at the speed of \($\mathbf{3 0 . 2 1}$\) knots
Firstly we need to an equation to represent both ships and the distance between each. A is moving \($25 \mathrm{knots}$\) west and \($B$\) is moving \($17 \mathrm{knot}$\) north. \($D$\)will be the distance between the two. Drawing it, you'll notice that it creates a right triangle.
So we use the Pythagorean Theorem:
\($$D^{\wedge} 2=A^{\wedge} 2+B^{\wedge} 2$$\)
Differentiate in relation to time:
\($$2 \mathrm{D}(\mathrm{dD} / \mathrm{dt})=2 \mathrm{~A}(\mathrm{dA} / \mathrm{dt})+2 \mathrm{~B}(\mathrm{~dB} / \mathrm{dt})$$\)
Now we must find all of our variables.
\(& A=\text { time(speed })+\text { original distance }=5(25)+10=135 \\\)
\(& B=5(17)+0=85 \\\)
\(& D=V\left(A^{\wedge} 2+B^{\wedge} 2\right)=159.53 \\\)
\(& d A / d t=25 \\\)
\(& d B / d t=17\)
Plug in all your variables and solve for
\($(\mathrm{dD} / \mathrm{dt})$ :\)
\(& 2 \mathrm{D}(\mathrm{dD} / \mathrm{dt})=2 \mathrm{~A}(\mathrm{dA} / \mathrm{dt})+2 \mathrm{~B}(\mathrm{~dB} / \mathrm{dt}) \\\)
\(& 2(159.53)(\mathrm{dD} / \mathrm{dt})=2(135)(25)+2(85)(17) \\\)
\(& 319.061(\mathrm{dD} / \mathrm{dt})=9640 \\\)
\(& \mathrm{dD} / \mathrm{dt}=9640 / 319.061 \\\)
\(& \mathrm{dD} / \mathrm{dt}=30.21 \text { knots }\end{aligned}\)
At \($5 \mathrm{pm}$\) the distance between the ships is changing at the speed of \($\mathbf{3 0 . 2 1}$\) knots
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How do you use different number systems and techniques to solve linear equations? (Give a couple of examples.)
Answer:
Step-by-step explanation:
You have two equations given and you want to solve all the couples (x; y) ∈ \(R^{2}\) that verifies both equations at the same time.
\(S:\left \{ {{2x-3y=5} \atop {-4x+5y=7}} \right.\)
First Method:
Substitution:
you need to give an expression of y in function of x or x in function of y in one of the two equations of the linear system, in order to replace the obtained expression in the other equation.
Example:
Take 2x-3y=5 <==> 2x = 5+3y <==> x = 5/2 + 3/2y
And now replace the obtained x in the other equation:
-4x + 5y = 7 <==> -4*(5/2+ 3/2*y) + 5y = 7 <==> -10 - 6y + 5y = 7
<==> -y = 17 <==> y = -17
and then you need to obtain x: 2x-3y=5
2x - 3*(-17) = 5 <==> 2x + 46= 0 <==> x = -23.
And the solutions are S = {(-23; -17)} ∈ \(R^{2}\)
Second Method:
Linear Combination:
You combine the two equations in order to have only one unknown value or variable an then you solve the set.
| 2x - 3y = 5 (*2)
| -4x + 5y = 7
| 4x -6y = 10
| -4x + 5y = 7
| 0 - y = 17 <==> y = -17
and then you need to obtain x: 2x-3y=5
2x - 3*(-17) = 5 <==> 2x + 46= 0 <==> x = -23.
So: S = {(-23; -17)} ∈ \(R^{2}\)
Question 2: Leilamade a one-time investment of $12 000.00 in a
registered retirement savings plan (RRSP) at 2.65%, compounded
semi-annually. She plans to withdraw the money when she retires in 30
years.
a) Determine the value of the investment when she retires. Show your
work.
I
b) Calculate the rate of return [note:] over the 30 years. Show your work.
the value of the investment when she retires is $26434.92.
What is the compound interest?Compound interest is when you earn interest on both the money you've saved and the interest you earn.
Formula:
A = P(1 + {r}/{n})^{n.t}
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
here, we have,
given that,
Leilamade a one-time investment of $12 000.00 in a
registered retirement savings plan (RRSP) at 2.65%, compounded
semi-annually.
She plans to withdraw the money when she retires in 30
years.
So, she get finally is,
using the formula we get,
$26434.92
hence, the value of the investment when she retires is $26434.92.
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Solve the system of
equation graphically, by
substitution, and by
elimination.
2x-5y = 34
y=3x-25
What is 2.5 × 15.625
Answer:
39.0625
Step-by-step explanation:
Answer:
39.0625
Step-by-step explanation:
On the boardwalk at the beach, there were beach towels for sale. They were $20.98 each. Marie’s mom bought 5 of them. About how much did he spend?
Answer:
$104.90
Step-by-step explanation:
Did the math for you.
Have a good day!
Answer:
104.90 or 105$ rounded
Step-by-step explanation:
you do 20.98 (how much they cost) x 5 (how much he bought) = 104.90 (total cost.
Hope this helps :P
Determine the equation of the circle graphed below
Answer:
(x-2)^2 + (y+3)^2 = 5.1^2
Step-by-step explanation:
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2, where h and k are the x and y values of the center of the circle respectively and r stands for the radius.
The center is given to us, at (2, -3) so we can plug that in:
(x-(2))^2 + (y- (-3))^2 = r^2
Simplify:
(x-2)^2 + (y+3)^2 = r^2
We can also solve for the radius by getting another point given to us: (3,2).
Using the pythagorean theorem, we can find how far the two points are away from each other:
a^2 + b^2 = c^2
1^2 + 5^2 = c^2
1 + 25 = c^2
26 = c^2
c ~ 5.1
Plug the radius we solved for in for r:
(x-2)^2 + (y+3)^2 = 5.1^2
Please find the Y for both of these equation
4x - y = 4
X-2y=-6
Answer:
1). y= -4+ 4x
2). y= 3+ x/2
Step-by-step explanation:
hope this helps !
What is the Product of 3.9 x 0.4
Answer:
1.56
Step-by-step explanation:
:)
Answer:
1.560
Step-by-step explanation:
3.9 x 0.4
A rectangular piece of metal is 5 in longer than it is wide. Squares with sides 1 in lòng are cut from the four corners
and the flaps are folded upward to form an open box. If the volume of the box is 234 in³, what were the original
dimensions of the piece of metal?
The original dimensions of the piece of metal were 15 inches by 20 inches.
To solve this problem, we can use the given information to set up an equation. Let's assume that the width of the rectangular piece of metal is x inches. According to the problem, the length of the piece of metal is 5 inches longer than its width, so the length would be (x+5) inches.
When squares with sides 1 inch long are cut from the four corners, the width and length of the resulting box will be reduced by 2 inches each. Therefore, the width of the box will be (x-2) inches and the length will be ((x+5)-2) inches, which simplifies to (x+3) inches.
The height of the box will be 1 inch since the flaps are folded upward.
Now, let's calculate the volume of the box using the formula Volume = length * width * height.
Substituting the values, we have:
234 = (x+3)(x-2)(1)
Simplifying the equation, we get:
234 = x^2 + x - 6
Rearranging the equation, we have:
x^2 + x - 240 = 0
Now, we can solve this quadratic equation either by factoring or by using the quadratic formula. Let's use factoring to find the values of x.
Factoring the equation, we have:
(x+16)(x-15) = 0
Setting each factor equal to zero, we get:
x+16 = 0 or x-15 = 0
Solving for x, we have:
x = -16 or x = 15
Since the width cannot be negative, we take x = 15 as the valid solution.
Therefore, the original dimensions of the piece of metal were 15 inches in width and (15+5) = 20 inches in length.
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Plz help this is due in an hour
Answer:
2X+3+X-6 =180
3X-3+3=180+3
3X=183
X=61
Answer:
x = 61
Step-by-step explanation:
The angles shown form a straight line
Angles that form a straight line add up to equal 180
Hence, 2x + 3 + x - 6 = 180
( note that we just created an equation that we can use to solve for x )
We now solve for x using the equation created
2x + 3 + x - 6 = 180
step 1 combine like terms
2x + x = 3x
3 - 6 = - 3
we now have 3x - 3 = 180
step 2 add 3 to each side
-3 + 3 cancels out
180 + 3 = 183
we now have 3x = 183
step 3 divide 3 from each side
3x / 3 = x
183 / 3 = 6
we're left with x = 61
If s(x) = 2x² and f(x) = 3x, which value is equivalent to (s-f)(-7)?
O-439
O-141
O 153
O 443
The value of expression (s - f) (- 7) would be,
⇒ (s - f) (- 7) = 119
We have to given that,
Functions are defined as,
⇒ s (x) = 2x²
⇒ f (x) = 3x
Now, We can find the value of (s - f) (- 7) is,
⇒ (s - f) (- 7)
⇒ s (- 7) - f (- 7)
⇒ 2 (- 7)² - (3 × - 7)
⇒ 2×49 + 21
⇒ 98 + 21
⇒ 119
Therefore, The value of expression (s - f) (- 7) would be,
⇒ (s - f) (- 7) = 119
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In the equation, the value of a is:
Answer:
Please check if the answer is a = 4 or not
Blank - 3/10 = 1/5 What is the blank number
Answer:
1/2
Step-by-step explanation:
Let's consider the number we want is x
x-3/10=1/5
On both sides of the equation, if we substract (or add) a certain number, say 3/10, the equality relation still exists.
That is x-3/10+3/10=1/5+3/10
Then x=1/5+3/10
You see 1/5+3/10=2/10+3/10=1/2
So x=1/2
the sum of nine consecutive positive integers is 99. what is the largest of these integers
Answer:
I believe it is 200. Forgive me if its wrong-
What is 5x6 + (5x5-5) to the 2nd power
Answer: 2500
Step-by-step explanation: If you calculate out 5x6 that equals 30 and 5x5-5 equals 20, when you do 30+20 that equals 50 and 50 to the 2nd power is 50x50 and that would equal 2500
Please help me I need help with algebra 2
Answer:If (x + 1) is a factor of the polynomial p(x), then p(x) can be written as:
p(x) = (x + 1) q(x)
for some polynomial q(x). By substituting x = -1 into this expression, we can find the value of c:
p(-1) = (-1 + 1) q(-1) = 0 q(-1) = 0
So,
0 = 5(-1)^4 + 7(-1)^3 - 2(-1)^2 - 3(-1) + c
= -5 + 7 - 2 + 3 + c
= c = 3
So, the value of c that makes (x + 1) a factor of the polynomial p(x) = 5x^4 + 7x^3 - 2x^2 - 3x + c is c = 3.
another question i need quickly:
what do you do if the median is 0 and 1?
What if the median is zero?
A variable that can in principle be only zero or positive can only have mean zero if all values in practice are zero. On the other hand, such a variable can and will have median zero if more than half of the values are zero.
Can you have a median of one number?
Median of one number = the number itself.
Please help me with the simplifying
The key here is to not worry too much and just follow PEMDAS.
Here we have the expression \((5\cdot 7)^2\). Following PEMDAS, we complete the expression inside the parentheses first, or \(5\cdot 7 = 35\). This gives us \((35)^2\) or just \(35^2.\)
Hope this helps.
What number decreased by 40 is 5 times that number?
Answer:
-10
Step-by-step explanation:
Let the number be x
x - 40 = 5x
⇒ -40 = 5x - x
⇒ 4x = -40
⇒ x = -40/4
⇒ x = -10
Answer:
-10
Step-by-step explanation:
Let the number be x
x - 40 = 5x
4x = -40
x = -10
How many ways can you make change for 60¢ using only nickels, dimes, and quarters?
There are 13 ways to make change for 60¢ using only nickels, dimes and quarters.
Determination of the number of combinations for a given amount of moneyIn the United States of America, a nickel equals 0.05 dollar, a dime equals 0.10 dollar and a quarter equals 0.25 dollar.
For 0.60 dollar we have the following expression in terms of nickels (\(n\)), dimes (\(d\)) and quarters (\(q\)):
\(0.25\cdot q + 0.10\cdot d + 0.05\cdot n = 0.60\), where \(q,\,d,\,n \in \mathbb{N}_{O}\) (1)
Since quarters are the money of greatest value, we assume arbitrary quantities and count corresponding solutions, whose representations are included below:
Case 1 (\(q = 0\))\(n = 12-2\cdot d\) (2)
According to the first graph, there are seven forms in this scenario.
Case 2 (\(q = 1\))
\(n = 7-2\cdot d\) (3)
According to the graph case_2, there are four forms in this scenario.
Case 3 (\(q = 2\))\(n = 2- 2\cdot d\)
According to the graph case_3, there are two forms in this scenario.
Hence, there are 13 forms to make change for 60¢ using only nickels, dimes and quarters. \(\blacksquare\)
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1. Which of the following expressions is equal to m3?
m. 3
m + m + m
3
m. m. m
Answer:
m +m+m is equal to M3. hope it helps
Answer:
m.m.m
Step-by-step explanation:
I'm going to assume m3 signifies m³. If this be the case, then;
m.3 = m×3 = 3mwhere as
m+m+m = 3mbut
m.m.m = m×m×m = m³A man wants to mesure the height of a nearby building. He places a 7ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building. The total length of the building’s shadow is 162ft, the pole casts a shadow that is 5.5ft long. How tall is the building? Round your answer to the nearest foot.
The height of the building is approximately 227 feet.
In the given question, a man wants to measure the height of a nearby building. He places a 7 ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building.
The total length of the building's shadow is 162 ft, and the pole casts a shadow that is 5.5 ft long. We have to determine the height of the building.The given situation can be explained with the help of a diagram.
As shown in the figure above, let AB be the building and CD be the 7 ft pole. The height of the building is represented by the line segment AE, which is to be determined. Let the length of the shadow of the pole be CD and that of the building be BD.
Therefore, the length of the total shadow will be BC or CD + BD.According to the question, the shadow of the pole is exactly covered by the shadow of the building. This implies that the two triangles AEF and CDF are similar. Hence, the corresponding sides are proportional. Therefore, we have:AE/EF = CD/DF
On substituting the values from the given data, we get:
AE/(EF + 5.5) = 7/5.5.... (1)
Similarly, we can write from the given data:
BD/DF = 162/5.5.... (2)
From equations (1) and (2), we can write:
AE/(EF + 5.5) = BD/DF => AE/(EF + 5.5) = 162/5.5.... (3)
On solving the above equation for AE, we get:
AE = (7/5.5) × (162/5.5 - 5.5)≈ 226.6 ft
Therefore, the height of the building is approximately 227 feet.
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as a sales person at Trending Card Unlimited, Justin receives a monthly base pay plus commission on all that he sells. If he sells $400 worth of merchandise in one month, he is paid $500. If he sells $700 worth of merchandise in one month, he is paid $575. Find justin's salary if he sells $2500 worth of merchandise
Answer:
$1025
Step-by-step explanation:
We can use the 2-point form of the equation of a line to write a function that gives Justin's salary as a function of his sales.
We start with (sales, salary) = (400, 500) and (700, 575)
__
The 2-point form of the equation of a line is ...
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
salary = (575 -500)/(700 -400)(sales -400) +500
salary = 75/300(sales -400) +500
For sales of 2500, this will be ...
salary = (1/4)(2500 -400) +500 = (2100/4) +500 = 1025
Justin's salary after selling $2500 in merchandise is $1025.
pls help
Given: △ABC, CM⊥ AB, BC = 5, AB = 7
CA = 4 sqrt(2)
Find: CM
Answer:
The general plan is to find BM and from that CM. You need 2 equations to do that.
Step One
Set up the two equations.
(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32
BM^2 + CM^2 = 5^2 = 25
Step Two
Subtract the two equations.
(7 - BM)^2 + CM^2 = 32
BM^2 + CM^2 = 25
(7 - BM)^2 - BM^2 = 7 (3)
Step three
Expand the left side of the new equation labeled (3)
49 - 14BM + BM^2 - BM^2 = 7
Step 4
Simplify And Solve
49 - 14BM = 7 Subtract 49 from both sides.
-49 - 14BM = 7 - 49
- 14BM = - 42 Divide by - 14
BM = -42 / - 14
BM = 3
Step Five
Find CM
CM^2 + BM^2 = 5^2
CM^2 + 3^2 = 5^2 Subtract 3^2 from both sides.
CM^2 = 25 - 9
CM^2 = 16 Take the square root of both sides.
sqrt(CM^2) = sqrt(16)
CM = 4 < Answer
Step-by-step explanation: