it takes 7/4 yd of a ribbon to make a hair bow. how much ribbon is needed to make 9 bows​

Answer:

A) MP(q) = -3q² + 440q - 13

B) 146.64 units.

Step-by-step explanation:

The profit function is given by the revenue minus the cost function:

\(P(q) = R(q) - C(q)\\P(q) = -q^3+220q^2-500-13q\)

A) The Marginal profit function is the derivate of the profit function as a function of the quantity sold:

\(P(q) = -q^3+220q^2-500-13q\\MP(q) = \frac{dP(q)}{dq} \\MP(q)=-3q^2+440q-13\)

B) The value of "q" for which the marginal profit function is zero is the number of items (in hundreds) that maximizes profit:

\(MP(q)=0=-3q^2+440q-13\\q=\frac{-440\pm \sqrt{440^2-(4*(-3)*(-13))} }{-6}\\q'=146.64\\q'' = - 0.03\)

Therefore, the only reasonable answer is that 146.64 hundred units must be sold in order to maximize profit.

Answer:

x≥ 6

Step-by-step explanation:

hope this helps loves x please make me brainlest

Answer: your answer would be D. x ≥ 6

x is greater or equal to 6

Step-by-step explanation:

200 pounds need to collect to earn the $50.00. Divide the cost per pound from the total amount needed, \(\frac{50.00}{0.25}\)= 200 pounds.

The official money of the U.k. and its regions is the GBP, or British pound sterling. The Pound is the earliest currency that is still accepted as legal tender in the entire world. The GBP, represented by pound sign (£), has one of the greatest trade volumes worldwide.

The development of the pounds sterling -The Latin word "libra," which means balance and weight, is where the name "pound sterling" comes from. During the years, the pound banknotes underwent various revisions before being initially printed by the Bank of England and over 300 years ago.

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Answer:

yyy

Step-by-step explanation:

Answer:Canst see

Step-by-step explanation:

sorry my guy

Answer + Step-by-step explanation:

Part A :

Let M(a , b) be a point where the graphs

of the equations y = 8ˣ and y = 2ˣ⁺² intersect.

M lies on both graphs

Then

the coordinates of M verify both equations (equation of graph1 and equation of graph 2)

Then

\(b=8^{a}\ \text{on the other hand} \ b=2^{a+2}\)

Then

\(8^{a}=2^{a+2}\)

Therefore ‘a’ (the x-coordinates of the points M where the two graphs intersect) is a solution to the equation :

\(8^{x}=2^{x+2}\)

Part B : check the attached table.

Part C :

Graphically, we try to spot the points of intersection of the two graphs ,the x-coordinates of those points are the solution to our equation.

In our case , obviously the two graphs intersect at only one point M(1 ,8)

Therefore 1 is the only solution to 8ˣ = 2ˣ⁺².

Also ,Check the attached graph.

Answer:

3/2y-5

Step-by-step explanation:

Answer:

\(\text{Midpoint of $AC$}=\left(-2,2\right)\)

\(\text{Midpoint of $AB$}=\left(\dfrac{5}{2},3\right)\)

\(\text{Slope of midsegment}=\dfrac{2}{9}\)

\(\text{Slope of $AC$}=3\)

\(\text{Slope of $BC$}=\dfrac{2}{9}\)

\(\text{Length of midsegment}=\dfrac{\sqrt{85}}2\)

\(\text{Length of $BC$}=\sqrt{85}\)

Step-by-step explanation:

Given points:

To determine the midpoints of AC and AB, substitute the given points into the midpoint formula.

\(\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint between two points}\\\\Midpoint $=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}\)

\(\begin{aligned}\text{Midpoint of $AC$}&=\left(\dfrac{x_C+x_A}{2},\dfrac{y_C+y_A}{2}\right)\\\\&=\left(\dfrac{-3-1}{2},\dfrac{-1+5}{2}\right)\\\\&=\left(\dfrac{-4}{2},\dfrac{4}{2}\right)\\\\&=\left(-2,2\right)\end{aligned}\)

\(\begin{aligned}\text{Midpoint of $AB$}&=\left(\dfrac{x_B+x_A}{2},\dfrac{y_B+y_A}{2}\right)\\\\&=\left(\dfrac{6-1}{2},\dfrac{1+5}{2}\right)\\\\&=\left(\dfrac{5}{2},\dfrac{6}{2}\right)\\\\&=\left(\dfrac{5}{2},3\right)\end{aligned}\)

\(\hrulefill\)

\(\boxed{\begin{minipage}{8cm}\underline{Slope Formula}\\\\Slope $(m)=\dfrac{y_2-y_1}{x_2-x_1}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.\\\end{minipage}}\)

To determine the slope of the midsegment, substitute the midpoints of AC and AB into the slope formula:

\(\begin{aligned}\text{Slope of midsegment}&=\dfrac{y_{AB}-y_{AC}}{x_{AB}-x_{AC}}\\\\&=\dfrac{2-3}{-2-\frac{5}{2}}\\\\&=\dfrac{-1}{-\frac{9}{2}}\\\\&=\dfrac{2}{9}\end{aligned}\)

Therefore, the slope of the midsegment is 2/9.

To find the slope of AC, substitute the points A and C into the slope formula:

\(\begin{aligned}\text{Slope of $AC$}&=\dfrac{y_{C}-y_{A}}{x_{C}-x_{A}}\\\\&=\dfrac{-1-5}{-3-(-1)}\\\\&=\dfrac{-6}{-2}\\\\&=3\end{aligned}\)

Therefore, the slope of the AC is 3.

**Note** There may be an error in the question. I think you are supposed to find the slope of BC (not AC) since there is no relationship between the slopes of the midsegment and AC, but there is a relationship between the slopes of the midsegment and BC.  

\(\begin{aligned}\text{Slope of $BC$}&=\dfrac{y_{C}-y_{B}}{x_{C}-x_{B}}\\\\&=\dfrac{-1-1}{-3-6}\\\\&=\dfrac{-2}{-9}\\\\&=\dfrac{2}{9}\end{aligned}\)

The slope of BC is 2/9, so the slopes of the midsegment and BC are the same. This implies that the midsegment and BC are parallel.

\(\hrulefill\)

\(\boxed{\begin{minipage}{7.4 cm}\underline{Distance Formula}\\\\$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$\\\\\\where:\\ \phantom{ww}$\bullet$ $d$ is the distance between two points. \\\phantom{ww}$\bullet$ $(x_1,y_1)$ and $(x_2,y_2)$ are the two points.\\\end{minipage}}\)

To find the length of the midsegment, substitute the endpoints (-2, 2) and (5/2, 3) into the distance formula:

\(\begin{aligned}\text{Length of midsegment}&=\sqrt{\left(\frac{5}{2}-(-2)\right)^2+(3-2)^2}\\\\&=\sqrt{\left(\frac{9}{2}\right)^2+(1)^2}\\\\&=\sqrt{\frac{81}{4}+1}\\\\&=\sqrt{\frac{85}{4}}\\\\&=\dfrac{\sqrt{85}}2\end{aligned}\)

To find the length of the BC, substitute points B and C into the distance formula:

\(\begin{aligned}\text{Length of $BC$}&=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\&=\sqrt{(-3-6)^2+(-1-1)^2}\\&=\sqrt{(-9)^2+(-2)^2}\\&=\sqrt{81+4}\\&=\sqrt{85}\end{aligned}\)

Therefore, the length of BC is twice the length of the midsegment.

since she already has 18 cups flour she needs 6 cups of sugar

Answer:

\(f(x) = ax(bx + a) \\ a = 1 \: b = 10 \: x = 1 \\ f(x) = ax(bx + a) \\ f(1) = 7(1)(10(1) + 7) \\ f(1)= 7(10 + 7) \\ f(1)= 70 + 49 \\ f(1)= 149\)

Answer:

A. c = 60 / p

Step-by-step explanation:

If p=2, the equation would read... c = 60 / 2, which mean c = 30. If c = 12, the equation would read... 12 = 60 / p, and p = 5, and so on, 20 = 60 / 3, and 15 = 60 / 4.

The item most likely to weigh 2 kilograms is a roast chicken.

The size, breed, and any other ingredients or stuffing used can all affect the weight of a roast chicken. Weights of roast chickens can range from petite ones weighing less than 1 kilogram to larger ones weighing more than 2 kilograms.

The other things that we have there would either weigh less than 2 Kg such as a tea bag or much more than 2 Kg such as a horse. The egg and the tea a very light and would be less than 2 Kg in weight while the bag and the horse would be above 2 Kg in weight.

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Robert can make a maximum of 8 milkshakes with the remaining chocolate syrup.

Converting the mixed number 2 2/5 to an improper fraction: 2 2/5 = 12/5

Subtracting the amount of chocolate syrup used per milkshake from the total amount of chocolate syrup:

12/5 - 1/4 = (48 - 5) / 20 = 43/20

Therefore, Robert has 43/20 cups of chocolate syrup left, which is the maximum amount he can use to make milkshakes.

For maximum number of milkshakes:

(43/20) / (1/4) = (43/20) x (4/1) = 172/20 = 8.6

Since Robert cannot make a fraction of a milkshake, he can make a maximum of 8 milkshakes with the remaining chocolate syrup.

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Answer:

Step-by-step explanation:

A function is defined so that for each input, there is no more than one output.

For the time period of  the projectile at least 192 feet above the ground is between 2 second and 6 second

Since s=128t-16t2, we want to know the 2 times where 128t-16t2=192, as those two values will be the begin and end times of the interval in question. We can rewrite that equation in standard quadratic equation form:

16t2-128t+192=0 or, simplified, 8t2-64t+96=0

or t2-8t+12=0

since it is now in quadratic form, we can solve using the quadratic formula:

t = 2 and 6

So the time period from approximately 2 second and 6 second has the projectile above 192 feet.

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Part (a)

\(g(x)=-3x^2 - 12x-11 \\ \\ =-3(x^2 + 4x)-11 \\ \\ =-3(x^2+4x+4)-11+12 \\ \\ =\boxed{-3(x+2)^2+1}\)

So, the vertex is at (-2, 1).

Part (b)

Plot the vertex, (-2,1).

Also, when x = -3, g(x) = -3(-1)² + 1 = -2. Since the graph is symmetric about x = -2, plot (-3, -2) and (-1, -2).

By similar logic, you can also plot (-4, -11) and (0, -11).

Answer:

b & c

Step-by-step explanation:

The smallest positive integer n such that t \($\sqrt[4]{56 \cdot n}$\)  is an integer is 686.

We have to find the smallest positive integer n such that \($\sqrt[4]{56 \cdot n}$\) is an integer

To find the smallest positive integer n such that  \($\sqrt[4]{56 \cdot n}$\)   is an integer, we need to determine the factors of 56 and find the smallest value of n that, when multiplied by 56, results in a perfect fourth power.

The prime factorization of 56 is:

56 = 2³ × 7

The prime factors of 56 need to be raised to multiples of 4.

Therefore, we need to determine the smallest value of n that includes additional factors of 2 and 7.

To make the expression a perfect fourth power, we need to raise 2 and 7 to the power of 4, which is 2⁴ × 7⁴

The smallest value of n that satisfies this condition is:

n = 2 × 7³ = 2× 343 = 686

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Answer:

9x

Step-by-step explanation:

the full answer is 9x+11=29

Answer:

X=2

Step-by-step explanation:

Add the numbers

4+5+5+6=29

4x+{\color{#c92786}{5}}+5x+{\color{#c92786}{6}}=29

4x+5+5x+6=294+11+5=29

4x+{\color{#c92786}{11}}+5x=29

4x+11+5x=29

Combine like terms

Subtract

1

1

11

11

from both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify

Solution

=

2

Answer:

Step-by-step explanation:

The probability Mrs. Walker will pick all 32 of the first round games correctly is given by:

0.56^32 = 1.56789e-10

To find the probability that Mrs. Walker will pick exactly 8 games correctly in the first round, we can use the binomial formula:

P(x=8) = 32 choose 8 * 0.56^8 * (1-0.56)^(32-8)

Where 32 choose 8 is the number of ways to choose 8 games out of 32.

To find the probability that Mrs. Walker will pick exactly 28 games incorrectly in the first round, we can use the same formula as in 2:

P(x=4) = 32 choose 4 * 0.56^4 * (1-0.56)^(32-4)

Answer:

Vectors \(p_{1} = 2+5\cdot x + 3\cdot x^{2}\), \(p_{2} = 4+11\cdot x +6\cdot x^{2}\) and \(p_{3} = 1+2\cdot x +x^{2}\) are linearly independent.

Step-by-step explanation:

From Linear Algebra, we must remember that a set of vectors is linearly independent if and only if coefficients of its linear combinations are all zeroes. That is:

\(\Sigma\limits_{i=1}^{n} \alpha_{i}\cdot p_{i}= 0\), where \(\alpha_{i} = 0\). (Eq. 1)

Where:

\(p_{i}\) - i-th Polynomial of the set of vectors, dimensionless.

\(\alpha_{i}\) - i-th coefficient associated with the i-ith polynomial of the set of vectors, dimensionless.

Let \(p_{1} = 2+5\cdot x + 3\cdot x^{2}\), \(p_{2} = 4+11\cdot x +6\cdot x^{2}\) and \(p_{3} = 1+2\cdot x +x^{2}\) elements of the set of vectors, whose linear combination is:

\(\alpha_{1}\cdot p_{1}+\alpha_{2}\cdot p_{2}+\alpha_{3}\cdot p_{3}= 0\)

\(\alpha_{1}\cdot (2+5\cdot x+3\cdot x^{2})+\alpha_{2}\cdot (4+11\cdot x +6\cdot x^{2})+\alpha_{3}\cdot (1+2\cdot x+x^{2}) = 0\)

\((2\cdot \alpha_{1}+4\cdot \alpha_{2}+\alpha_{3})+(5\cdot \alpha_{1}+11\cdot \alpha_{2}+2\cdot \alpha_{3})\cdot x+(3\cdot \alpha_{1}+6\cdot \alpha_{2}+\alpha_{3})\cdot x^{2} = 0\)

Values of coefficient are contained in the following homogeneous system of linear equations:

\(2\cdot \alpha_{1}+4\cdot \alpha_{2}+\alpha_{3} = 0\) (Eq. 2)

\(5\cdot \alpha_{1}+11\cdot \alpha_{2}+2\cdot \alpha_{3} = 0\) (Eq. 3)

\(3\cdot \alpha_{1}+6\cdot \alpha_{2}+\alpha_{3} = 0\) (Eq. 4)

The solution of this system is:

\(\alpha_{1} = 0\), \(\alpha_{2} = 0\), \(\alpha_{3} = 0\)

Which means that given set of vectors are linearly independent.

We can write the diameter and circumferance of base as -

D = 2√(750ρ/πh)

C = 2π√(750ρ/πh)

A function is a relation between a dependent and independent variable.

Mathematically, we can write → y = f(x) = ax + b.

Given is to find the diameter and height of the tin can.

Assume the density of coffee as {ρ}. We can write the volume of the tin can as -

Volume = mass x density

Volume = 750ρ

We can write -

πr²h = 750ρ

r = √(750ρ/πh)

D = 2r

D = 2√(750ρ/πh)

Now, we can write the circumferance as -

C = 2πr

C = 2π√(750ρ/πh)

Therefore, we can write the diameter and circumferance of base as -

D = 2√(750ρ/πh)

C = 2π√(750ρ/πh)

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To find the measure of the geometry-big circle, we need to sum up the measures of all the arcs around the circle.

We are given the following measures:

\(\sf\:m\angle AB = 56 \\\)

\(\sf\:m\angle BC = 59 \\\)

\(\sf\:m\angle CD = 63 \\\)

\(\sf\:m\angle DE = 63 \\\)

\(\sf\:m\angle EF = 31 \\\)

To find the measure of the geometry-big circle, we add up these measures:

\(\sf\:m\angle AB + m\angle BC + m\angle CD + m\angle DE + m\angle EF \\\)

Substituting the given values:

\(\sf\:56 + 59 + 63 + 63 + 31 \\\)

Simplifying the expression:

\(\sf\:272 \\\)

Therefore, the measure of the geometry-big circle is 272.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The angle of sinθ between the horizontal vector (1, 0) and the slant vector (15/17, -8/17) is sin⁻¹(8/17), which is approximately 29.11 degrees.

To find the angle of sinθ between a horizontal vector and a slant vector, we can use the dot product formula:

a · b = |a| |b| cos(θ)

where a and b are vectors, |a| and |b| are their magnitudes, and theta is the angle between them.

In this case, the horizontal vector is (1, 0) and the slant vector is (15/17, -8/17).

The magnitude of the horizontal vector is 1, and the magnitude of the slant vector is:

|b| = sqrt((15/17)² + (-8/17)²) = sqrt(225/289 + 64/289) = sqrt(289/289) = 1

The dot product of the two vectors is:

a · b = (1)(15/17) + (0)(-8/17) = 15/17

So we have:

15/17 = (1)(1) cos(θ)

cos(θ) = 15/17

To find sin(θ), we can use the trigonometric identity:

sin²(θ) + cos²(θ) = 1

sin²(θ) = 1 - cos²(θ) = 1 - (15/17)² = 64/289

Taking the square root of both sides, we get:

sin(theta) = sqrt(64/289) = 8/17

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An 86% confidence interval for the difference in age to leave mother is -3.10091

What is confidence Interval?

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. In statistics, confidence is another word for probability.

Given, Gorilla Baby sample

x means x bar here so, \(x_{1}\) = 3.21

\(s_{1}\) = 0.81

\(n_{1}\) = 64

Human Baby sample

x means x bar here so, \(x_{2}\) = 19.1

\(s_{2}\) = 2.16

\(n_{2}\) = 200

Confidence interval needs t score

t score = 1.18

86% confidence interval = \(x_{1}\) - \(x_{2}\) ± tc \(\sqrt{s^{2} {1} / n_{2} + s^{2} {2} / n_{2}\)

= 3.21 - 19.1 ± 1.18 √0.81²/64 +2.16²/200

= 3.21 - 19.1 ± 1.18 √0.033

= -3.10091

An 86% confidence interval for the difference in age to leave mother is -3.10091

The detail question is here,

A study based on the Association primate Ebmarah looked at the average age a baby gorilla leaves it’s mother versus the average age the human baby leaves it’s mother . Naturally they are different , so we don’t want a hypothesis test. Instead, find an  86% confidence interval  for the difference in age to leave mother.

Gorilla:

Sampled 64 babies

Stayed with mother on average 3.21 years

Standard deviation:  0.81

Human:

Sampled  200 babies

Stayed with mother on average 19.1 years

Standard deviation:  2.16

Matched  pairs  standard deviation :0.23

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Answer:

256x^2

Step-by-step explanation:

The square root of (16x)^4 is (16x)^2 because you divide the power by root and 16x squared is equal to 256x^2

Answer:

256x²

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Answer:

x=18.5

u gotta do 3x+2=x+49

combine the like terms and it becomes 2x=37 then divide by 2 u get 18.5

plug it in as x and check if it's right

Answer:

7/4

Step-by-step explanation:

1/2 x 2 = 1

3/4 + 1 = 7/4 or 1 3/4