It requires 55N force to ring the bell at a hammer swing carnival game. Donald Duck can generate 250W of power while swinging the hammer down in .85s, doe he produce enough force to ring the bell at a height of 7m? Donald doubled power to what happens to the force he generates ?

We have that Gravity a force acting down ward against any object and frictional force is a force acting a against  movement, Hence

Generally, Gravity a force acting down ward against any object on earth at an acceleration of about  9.8m/s

and frictional force is a force acting a against the movement based on contact with another surface

Therefore

Gravity is a field force acting downward on the couch:

This is True

Friction from the carpeted floor is a contact force acting against your push.

This is True

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Answer:

PAPER CLIPS ON NOSE OF A PAPER AIRPLANE

Purpose: To determine if the number of paperclips on the nose of a paper airplane affects the velocity and speed, measured in meters per seconds.

Make a Hypothesis Based on the Learning Thus Far: If the number of paperclips on the nose of a paper airplane increases, then the speed will _increase______ (increase, decrease, stay the same) in a __linear_______ (linear, exponential, logarithmic) mathematical relationship, and the velocity will (increase, decrease, stay the same) in a __exponential____ (linear, exponential, logarithmic) mathematical relationship. (Fill in the appropriate words for your hypothesis.)

Pictures: Insert at least 3 pictures of yourself conducting the experiment into this lab report. At least 2 pictures must show your face as you conduct the investigation. You may need to ask someone to help take these photos.

Explanation:

meters per seconds.

Make a Hypothesis Based on the Learning Thus Far: If the number of paperclips on the nose of a paper airplane increases, then the speed will _increase______ (increase, decrease, stay the same) in a __linear_______ (linear, exponential, logarithmic) mathematical relationship, and the velocity will (increase, decrease, stay the same) in a __exponential____ (linear, exponential, logarithmic) mathematical relationship. (Fill in the appropriate words for your hypothesis.)

Pictures: Insert at least 3 pictures of yourself conducting the experiment into this lab report. At least 2 pictures must show your face as you conduct the investigation. You may need to ask someone to help take these photos.

Data Table: Number of Paperclips on the Nose of a Paper Airplane versus Velocity and Speed

Trials

Time Aloft

(s)

Distance traveled (m)

Displacement traveled (m)

Speed

(m/s)

Velocity

(m/s)

1 clip

Trial 1

1 clip

Trial 2

1 clip

Trial 3

2 clips

Trial 1

2 clips

Trial 2

2 clips

Trial 3

3 clips

Trial 1

3 clips

Trial 2

3 clips

Trial 3

Graph: Make a line graph of average Speed and Velocity (as two different lines) on the y-axis and the number of paper clips on the x-axis. Do NOT connect the dots. Instead, make a line/curve of best fit for the speed and velocity to help determine if there is a relationship between the number of paperclips and speed/velocity.

Data Analysis: This section is also known as “Show Your Work”. Here is where you show how you performed the mathematics of the experiment. Be sure to include units in your measurements. This is also where you will find the slope of the line for your graph (in decimal form including units) as well as the equation of the line IF the relationship between the dots is in fact a line.

Based on your current understanding of physics, hypothesize what forces acted on the airplane and how did the addition of paperclips change those forces? How did those forces change from when the airplane was released to when it came to rest on the floor? Draw a FBD.

Conclusion: This is a series of several paragraphs written with correct grammar using a formal academic author voice that answers the following questions:

What was the independent variable? What was the dependent

variable? What were the controlled variables? How well was the purpose achieved? What was the relationship between variables? How accurate was the hypothesis?

Why was the hypothesis correct/incorrect? What events in the experiment were expected? What events in the experiment were not expected? What human error occurred (i.e. measurement errors, significant digit errors, mathematical errors, etc)? What equipment error occurred (i.e. friction, air resistance, improper calibration, broken equipment, etc)? How could the lab be improved? How could this lab apply to physics in the real world?

What similar experiment could be done next to further study this phenomenon? What would be the independent, dependent and control variables? What would the purpose be? What is the hypothesis concerning the relationship between the dependent and independent variables in this experiment?

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

Force = 0.145 × 9.81 = 1.42245

We have the final answer as

Hope this helps you

The  mass of the parent galaxy is 3.42 x 10^12 solar masses assuming H0 = 70 km/s/Mpc.

the equation for the mass of a galaxy is :

M = (v^2 * r) / G

H0 = 70 km/s/Mpc

v_satellite = 6450 km/s

v_parent = 6500 km/s

We apply the  equation for the Hubble law, in order to find the distances to the galaxies:

d_satellite = v_satellite / H0 = 92.1 Mpc

d_parent = v_parent / H0 = 92.9 Mpc

θ = 0.1∘

d = d_satellite * (θ/60) = 0.026 Mpc

We have the equation for the mass of the parent galaxy as :

M = (v^2 * r) / G

M = (6500 km/s)^2 * (0.026 Mpc) / G = 3.42 x 10^12 solar masses

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a plate with bread, grapes, a hard-boiled egg, cheese, cucumber slices, and carrot slices food groups are represented in this snack

According according to the Demographic Reference Intake report for macronutrients, a sedentary adult should consume 0.36 grammes of animal protein for every pound of weight of their body, or 0.8 grammes of proteins per kilogramme. As a result, the average inactive guy should take around 56 grammes of protein per day, whereas the average sedentary female should consume approximately 46 grammes.

A person can consume too much protein; if it accounts for more than 35% of their daily calories, they may suffer unfavourable repercussions.

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Answer:

answer is liquid just took the test on edge:)

Explanation:

MERICA YEE YEE

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The interaction between the Corn plants and milkweed plants demonstrates as competition.

Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.

In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.

As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and  milkweed plants demonstrates competition.

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Answer:

Choice E.

Amplitude: \(20\; {\rm cm}\).

Frequency: \(2\; {\rm Hz}\).

Explanation:

The amplitude of a simple harmonic motion (SHM) is the maximum displacement from equilibrium.

In this question, the equilibrium is in the center of the two extremes. With one extreme at \(x = 10\; {\rm cm}\) and the other at \(x = 50\; {\rm cm}\), the center will be at \((1/2)\, (10 + 50)\; {\rm cm} = 30\; {\rm cm}\).

The maximum displacement will be \((50\; {\rm cm} - 30\; {\rm cm}) = 20\; {\rm cm}\) (or equivalently, \((30\; {\rm cm} - 10\; {\rm cm}) = 20\; {\rm cm}\).

Frequency measures the number of cycles completed in unit time (e.g., one second.) In one full cycle of an SHM, the oscillator will travel from one extreme to another and then back to the original extreme. In this question:

In other words, one full cycle of this SHM will take \(0.25\; {\rm s} + 0.25\; {\rm s} = 0.50\; {\rm s}\). The period of this SHM will be \(0.50\; {\rm s}\). Hence, the frequency of this SHM will be:

\(\begin{aligned} (\text{frequency}) &= \frac{1}{(\text{period})} \\ &= \frac{1}{0.50\; {\rm s}} \\ &= 2\; {\rm Hz}\end{aligned}\).

Answer:

distance travelled= 12 x 3=36 m

Answer:no

Explanation: lol

Answer:

20.0086

Answer:

20.0086

Explanation:

Acellus

1. It is unethical for Demario to cheat

2. Demario should not engage in cheating himself

3. Demario should not turn in cheating classmates without careful consideration

4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.

A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.

By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.

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The electric potential at the fourth corner (point A) is E4 = kQ.[ 2/a2 + 1/a√2 ]

The electric potential is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field.

Number of point charges = 3

Using the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a2 + kQ/√(2a2) + kQ/a2

E4 = kQ.[ 1/a2 + 1/√(2a2) + 1/a2 ]

E4 = kQ.[ 2/a2 + 1/a√2 ]

Therefore the electric field at the fourth corner is  E4 = kQ.[ 2/a2 + 1/a√2 ].

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Complete question:

Three-point charges are arranged at the corner of a square of side l as shown in Fig. 17-39. what is the potential at the fourth corner (point A)?

When displaying sections of data, bar charts is used. As long as the number of categories to compare, vertical bar charts can be useful for comparing several category discrete data, like ages, classes, schools.

Charts and graphs are useful visual aids because they make information accessible and quick to understand. So, it is not unexpected that both print and digital media frequently use graphs. When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

Visual representations of data, such as tables and graphs, are used to arrange information and reveal patterns and correlations. To present the results of their research, scientists and researchers frequently employ tables and graphs.

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equal in magnitude but opposite in direction

Answer:

11.5

Explanation:

Answer:

Explanation: An astronaut on Jupiter will feel much heavier than on Earth due to the higher force of gravity. If the astronaut weighs 100 kg on Earth, he would weigh approximately 300 kg on Jupiter. This increased force of gravity can make it difficult to move around and perform physical tasks.

Answer:

Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.

Answer:

Explanation:

Given the following data;

Mass = 35 kg

Velocity = 3 m/s

To find the kinetic energy of the child;

K.E = ½mv²

Answer:

A. Insulator

Explanation:

Since there is no current passing through at all.

Let's see what to do buddy.....

_________________________________

\(Acceleration = 4 \: \: \frac{mile}{ h } p( min ) \)

Thus ;

The speed increases 4 units per minute.

The train has a speed of 25 mph now.

After a minute it has a speed of 29 mph.

After a minute it has a speed of 33 mph.

After a minute it has a speed of 37 mph.

Look ; 4 units per minute means 4 units per 60 seconds, thus the speed increases 1 unit per 15 seconds .

If the speed wants to increasing from 37 to 40 , needs 3 × 15 seconds = 45 sec.

So we have : 1 min + 1 min + 1 min + 45 sec .

3 minutes and 45 seconds or 225 seconds need to the speed increasing from 25 mph to 40 mph.

_________________________________

And we're done.....♥️♥️♥️♥️♥️

Hi there! :)

Reference the diagram below for clarification.

1.

We must begin by knowing the following rules for resistors in series and parallel.

In series:
\(R_T = R_1 + R_2 + ... + R_n\)

In parallel:
\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}\)

We can begin solving for the equivalent resistance of the two resistors in parallel using the parallel rules.

\(\frac{1}{R_{T, parallel}} = \frac{1}{10} + \frac{1}{10}\\\\\frac{1}{R_{T, parallel}} = \frac{2}{10} = \frac{1}{5}\\\\R_{T, parallel} = 5\Omega\)

Now that we have reduced the parallel resistors to a 'single' resistor, we can add their equivalent resistance with the other resistor in parallel (15 Ohm) using series rules:
\(R_T = 15 + 5\\\\\boxed{R_T = 20 \Omega}\)

2.

We can use Ohm's law to solve for the current in the circuit.

\(i = \frac{V}{R_T}\\\\i = \frac{120}{20} = \boxed{6 A}\)

3.

For resistors in series, both resistors receive the SAME current.

Therefore, the 15Ω resistor receives 6A, and the parallel COMBO (not each individual resistor, but the 5Ω equivalent when combined) receives 6A.

In this instance, since both of the resistors in parallel are equal, the current is SPLIT EQUALLY between the two. (Current in parallel ADDS UP). Therefore, an even split between 2 resistors of 6 A is 3A for each 10Ω resistor.

4.

Since the 15.0 Ω resistor receives 6A, we can use Ohm's Law to solve for voltage.

\(V = iR\\\\V = (6)(15) = \boxed{90 V}\)

Answer:

a

e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )

b

G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

    The  velocity  of transverse waves in a crystal of atomic separation is  

                  \(b_y  = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }\)

Generally the dispersion relation is mathematically represented as

            \(e(k) =  b_y  *  k\)

=>    \(e(k) = c  \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} }  *  k\)

=>    \(e(k) =   c *  \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }\)

=>    \(e(k) =  \frac{2a}{c}  *  sin (\frac{k*a}{2} )\)

Generally the group velocity is mathematically represented as

          \(G_{v} =  \frac{d e(k ) }{dk }  =  \frac{a^2}{c}  *  cos (\frac{k* a}{2} ) \)

Answer: The scenario violates the second law of thermodynamics.

Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.

Answer:

The electric field inside the conductor is zero.

Explanation:

In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.

I = 0

From the ohm's law

ΔV= IR = 0

⇒ΔV =0

Therefore, potential V is same through the conductor.

Also, E = -ΔV d = 0

Hence, The electric field inside the conductor is zero.

The error in her thinking is that oxygen has has six electrons and a negative charge is acquired by nitrogen when it gains two electrons.

Oxygen is a member of group 16. The elements in group 16 has six valence electrons. This means that they need an extra two electrons to complete their octet.

If an atom gains two electrons, it will have a charge of -2 and not +2, a positive charge means that the atom lost electrons. Nonmetals like oxygen do not loose electrons rather they gain electrons.

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The mechanical advantage of the crowbar is 3.1667.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane.

The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Input force by you= 12 N.

Output force from the crowbar = 38 N.

Then, the mechanical advantage of the crowbar = Output force from the crowbar / input force by you.

= 38N/12N.

=3.1667.

Hence, the mechanical advantage of the crowbar is 3.1667.

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