it rains in Yakutsk but it's always dry after why?

Answer:

The new temperature is 527.15 ºC.

Explanation:

Charles’s law states that the volume of a fixed  amount of gas maintained at constant pressure is directly proportional to the absolute  temperature of the gas (the absolute temperature is the Kelvin temperature).

We need to calculate the temperature after the expansion, that is T₂. For that, we use Charles' law:

\( V₁ ÷ T₁ = V₂ ÷ T₂ \)

Because we have to use the absolute temperature, we convert ºC to K adding 273.15:

T₁ = 127 ºC + 273.15 ºC = 400.15 K

\( T₂ = V₂ × T₁ ÷ V₁ \)

\( T₂ = 20. 0 L × 400.15 K ÷ 10.0 L \)

T₂ = 800.3 K

We substract 273.15 to the result to convert it back to ºC:

T₂ = 800.3 - 273.15  = 527.15 ºC.

Answer:

Sodium - malleable, soft, and shiny

Silicon - has properties of both metals and nonmetals

Bromine - highly reactive gas

Argon - non-reactive gas

Explanation:

Sodium is an alkaline metal. Just like other alkaline metals, it's malleable, soft, and shiny.

Silicon is a metalloid. Metalloids are elements that have properties of both metals and nonmetals.

Bromine a highly reactive chemical element. It is a fuming red-brown liquid at room temperature that evaporates to form a similarly coloured gas.

Argon is a noble gas. Just like other noble gases, it's non-reactive.

Answer:

Products

Explanation:

Answer:

Reaction time tests can be used to assess an individual's hand-eye coordination. One test involves catching a 1 metre ruler and measuring the distance, d in metres, that the ruler travelled before being caught. The reaction time t seconds is then calculated using the formula: = √2d/9.8

If you draw the table of the Hess law, you can use that table to obtain the enthalpy of reaction

A table called the "Hess's law table" can be created to depict how Hess's law is used. The reactants, intermediates, products, and related enthalpy changes (H) of each reaction that takes place during a chemical reaction are listed in the table.

Hess's law indicates that you can add the enthalpy changes of the separate reactions to get the total reaction's enthalpy change (H). By eliminating common species between neighboring reactions in the table, the overall reaction is achieved.

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Answer: Since the vials are filled the same, and are placed on the same hot pad, all the water will evaporate at the same time

Explanation:

The source of error in the experiment  is the vials  being filled the same, and  placed on the same hot pad, all the water evaporating at the same time .

Errors in chemical analysis result when there is a difference between observed value and the true value.If the magnitude of errors is large , it results in decrease in accuracy, reproducibility, and precision.

There are three types of errors:1) random error 2) systematic error 3) human error.The cause of random errors are difficult to quantify while the human errors can be minimized by taking a range of readings to reduce the error.

Errors while measuring boiling point may be human errors while noting down the boiling temperature or instrumental or systematic error if there is a fault in the thermometer.

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The mass number of an atom is equal to the number of protons plus the number of neutrons that it contains. In other words, the number of neutrons in any atom is its mass number minus its atomic number.

hope this helps, if not, your free to give me 1 star

Answer:

milliliter

Explanation:

Answer:

B milliliter

Explanation:

Answer:

30=2

31=1

32=4

Explanation:

the answer is below the answer

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\ \)

So we have

\(volume = \frac{220}{11} \\ \)

We have the final answer as

Hope this helps you

Answer:

1.08 M

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 mL

Initial concentration (C₁) = 6 M

Final volume (V₂) = 250 mL

Final concentration (C₂) =?

The final concentration of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

6 × 45 = C₂ × 250

270 = C₂ × 250

Divide both side by 250

C₂ = 270 / 250

C₂ = 1.08 M

Therefore, the final concentration of the solution is 1.08 M.

When NH₄OH and CaS are mixed the following reaction occurs:

NH₄OH + CaS ---> Ca(OH)₂ + (NH₄)₂S

Ca(OH)₂ is a poorly soluble base in water. So the formula of the precipitade formed is Ca(OH)₂ and its name is calcium hydroxide.

Bases with cations of the group II of the periodic table are generally poorly soluble in water.

Therefore, the mass fraction of calcium bicarbonate is 16.2%.

Calcium bicarbonate, which is represented by the formula Ca(HCO3)2, is a white crystalline powder that is highly soluble in water. When dissolved in water, calcium bicarbonate produces a weakly alkaline solution.

The solubility of this salt in water is increased by increasing the pressure. The hardness of the water is measured in mg/L as CaCO3, and in this case, it is measured to be 162 mg/L.

The molar concentration of HCO3- ions is calculated using the following formula:

Molarity = (mg/L × 1000)/(MW × V)

Lets substitute the given values in the above equation and calculate the molar concentration of HCO3- ions.

Molarity = (162 mg/L × 1000)/(162.11 g/mol × 1 L)

Molarity = 0.999 M

Consequently, the molar concentration of HCO3- ions in the water is 0.999 M.

The normality of Ca2+ ions is given by the formula:

Normality = Molarity × Equivalence factor

Since the equivalence factor of Ca2+ is 2,

let's substitute the above value and calculate the normality of Ca2+ ions.

Normality = 0.999 M × 2

Normality = 1.998 N

Thus, the normality of Ca2+ ions is 1.998 N.

The mass fraction of calcium bicarbonate is calculated as follows:

Mass fraction = (Mass of Ca(HCO3)2 in 100 g of water) × 100%

Let's substitute the given values and calculate the mass fraction of calcium bicarbonate.

Mass of Ca(HCO3)2 in 100 g of water = (162 mg/L × 100 g)/1000 g

Mass of Ca(HCO3)2 in 100 g of water = 16.2 g/100 g of water

Now, substituting the above value in the formula for mass fraction,

Mass fraction = (16.2 g/100 g of water) × 100%

Mass fraction = 16.2%.

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To determine ∆g° for a reaction,

when ∆g = -123.5 kJ/mol, q = 0.035, and T = 223 K,

follow these steps:

Step 1: Convert ∆g from kJ/mol to J/mol
∆g = -123.5 kJ/mol * 1000 J/kJ = -123500 J/mol

Step 2: Use the formula ∆g = ∆g° + RT ln q, where R = 8.314 J/mol･K, to find ∆g°.

Rearrange the formula to solve for ∆g°:
∆g° = ∆g - RT ln q

Step 3: Plug in the values:
∆g° = -123500 J/mol - (8.314 J/mol･K * 223 K * ln(0.035))

Step 4: Perform the calculations:
∆g° ≈ -123500 J/mol + 12933.86 J/mol

Step 5: Add the values to find ∆g°:
∆g° ≈ -110566.14 J/mol

So, the ∆g° for this reaction is approximately -110566.14 J/mol.

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Answer:

\(M_{base}=0.0311M\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

\(n_{acid}=n_{base}\)

Which in terms of molarities and volumes is:

\(M_{acid}V_{acid}=M_{base}V_{base}\)

Thus, we solve for the molarity of the base (KOH) to obtain:

\(M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M\)

Regards!

Sea surface temperatures will rise. More heat energy will emerge from this, increasing the likelihood that tropical cyclones may form. Floods and cyclones worsen as a result of increased evaporation and heavy precipitation brought on by warming are the short term effects of climate change

Short-term climatic changes also include those brought on by the ocean and atmosphere interacting. Seasons. Because the amount of solar energy received by Earth at various latitudes varies throughout the year, seasons develop. Climate all throughout the world are impacted by these changes in wind, current, and ocean temperature. Changes often last a year or two, while climate refers to the area's typical long-term weather patterns. The average weather for a specific area and time period, often averaged over a 30-year period, is how some scientists describe climate. Sea surface temperatures will rise. More heat energy will emerge from this, increasing the likelihood that tropical cyclones may form. Warming also causes increased evaporation, which increases the frequency of heavy rain and snowfalls and causes floods.

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Short term of effects of climate change includes the rise in temperature, increased warmth of Water, expansion of ocean, heavy rains, floods and severe storms.

A relatively brief occurrence or its repercussions are referred to as short term effects. The short term effects of climate change includes the following,

The waters will warm as the temperature rises. More heat energy will be produced as a result, which will boost the likelihood that tropical cyclones will form. The global surface temperature increases along together the concentrations of greenhouse gas.

Most of the temperature from global warming is absorbed by the ocean. All ocean depths have experienced a significant increase in ocean warming during the past 20 years. Water expands as it becomes warmer, therefore as the ocean warms, so does its volume.

In many areas, destructive storms have increased in ferocity and frequency. More moisture evaporates as temperatures rise, aggravating extremely heavy rains and flooding and resulting in more severe storms.

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The rate of diffusion of carbon dioxide (CO2) and ozone (O3) at the same temperature can be compared based on their molar mass and their respective diffusion coefficients. Generally, lighter molecules diffuse faster than heavier molecules due to their higher average velocity and kinetic energy.

In terms of molar mass, carbon dioxide (CO2) has a molar mass of approximately 44 g/mol, while ozone (O3) has a molar mass of approximately 48 g/mol. Since carbon dioxide has a slightly lower molar mass compared to ozone, it is expected to diffuse slightly faster. However, molar mass alone is not the only factor affecting the rate of diffusion. The diffusion coefficient, which is a measure of how easily a substance can diffuse through a medium, also plays a significant role. The diffusion coefficient depends on various factors, including molecular size, shape, and interactions with the surrounding medium. In the case of carbon dioxide and ozone, the diffusion coefficient of carbon dioxide is generally higher than that of ozone. This can be attributed to the smaller molecular size of carbon dioxide, allowing it to move more freely through a medium and diffuse at a faster rate compared to ozone. Overall, considering both molar mass and diffusion coefficient, carbon dioxide tends to have a higher rate of diffusion compared to ozone at the same temperature.

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Answer: blowing a balloon is a physical change as when you blow a balloon the balloon expands but the balloon remains a balloon .there is change in Blowing a balloon is a physical change because only the size of the balloon changes , no change in chemical properties of the balloon occurs (no new substance is formed).

Explanation:

The gas that has particles that move at a greater speed is O₂ with a mass of 32 amu at 15 degrees.

The molar mass of gas and the speed of the particles of the gas are inversely proportional. This means that the higher the molar mass of a gas, the lower will be the speed of the particles of the gas

This is in accordance with Graham's law of diffusion which states that the rate of diffusion of a gas is inversely proportional to the square of the density of the gas.

Also, an increase in the temperature of a gas will result in an increase in the speed of the particles of the gas.

However, for two gases at the same temperature, the molar mass of the gases will determine the speed of the particles of the gas.

The heavier gas will have particles that move at a lower speed.

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(a) Diagram of characteristic X-ray generation in an atom:

[Note: Due to the limitations of text-based communication, I'm unable to provide a visual diagram. However, I'll explain the process in the following text.]

(b) Explanation of characteristic X-ray generation:

When high-energy electrons collide with an atom, they can knock out inner shell electrons, creating vacancies. Outer shell electrons then transition to fill these vacancies, releasing energy in the form of X-rays. These X-rays are called characteristic X-rays and have specific energies corresponding to the energy differences between different electron shells.

(c) X-ray production in an X-ray tube:

An X-ray tube consists of a cathode and an anode enclosed in a vacuum. The cathode emits a stream of high-speed electrons through a process called thermionic emission. These electrons are accelerated by a high voltage and directed towards the anode. As the fast-moving electrons collide with the anode, X-rays are produced through two main processes: bremsstrahlung radiation (braking radiation) and characteristic X-ray emission.

In bremsstrahlung radiation, the electrons are decelerated by the positively charged anode, causing them to emit X-rays with a continuous spectrum of energies. Characteristic X-ray emission occurs when the high-speed electrons displace inner shell electrons in the anode, leading to the generation of characteristic X-rays specific to the anode material.

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In general, the arming time of a munition refers to the time required for the munition's fuse to become active and enable the explosive charge to detonate. The arming time can vary depending on several factors, including the type of fuse used, the specific munition model.

Tail fuzes like the M905 tail fuze are designed to be used with certain types of munitions, such as bombs, and are typically armed by the motion or rotation of the munition during its descent or trajectory. The arming time of a tail fuze can depend on several factors, including the munition's velocity, the altitude of the munition, and the specific settings on the fuze.

It's important to note that discussing specific arming times of military munitions is not recommended, as it can be considered sensitive information that should only be handled by authorized personnel with the proper clearance and training to ensure public safety and security.

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According  to stoichiometry and concept of Avogadro's number there are 3.61×10²⁴ particles for 4 moles of KClO₃.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.As 2 moles of potassium chlorate gives 3 moles of oxygen , thus 4 moles of potassium chlorate will give 4×3/2=6 moles , 6 moles have 6×6.023×10²³=3.61×10²⁴ particles.

Thus,  there are 3.61×10²⁴ particles for 4 moles of KClO₃.

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Answer:

Water moves through the hydrosphere in a cycle. Water collects in clouds, then falls to Earth in the form of rain or snow.

Answer:

Water moves through the hydrosphere in a cycle.

Explanation:

Hope it helps.

A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed. (a) The balanced chemical equation is BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl. (b) The limiting reagent is Na₂CO₃.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl

To calculate number of moles when molarity and volume are given as:

Number of moles = Molarity × Volume

Now,

Number of moles of BaCl₂ = Molarity  × Volume

                                             = 0.50 M  × 0.05 L         [1 ml = 0.001 L]

                                             = 0.025 moles

Number of moles of Na₂CO₃ = Molarity  × Volume

                                                = 0.75 M × 0.075 L     [1 ml = 0.001 L]

                                                = 0.05625 moles

The limiting reagent is Na₂CO₃ here.

Thus from the above conclusion we can say that A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed. (a) The balanced chemical equation is BaCl₂ + Na₂CO₃ → BaCO₃ + 2NaCl. (b) The limiting reagent is Na₂CO₃.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: A precipitation reaction occurs when 50. 0 mL of 0. 50 M BaCl₂ is mixed with 75. 0 mL of 0. 75 M Na₂CO₃ (aq). The only precipitate is the BaCO₃ (s) formed.

a) Write the balanced equation that describes this reaction.

b) Which chemical is the limiting reactant

He discovered that plants could produce oxygen during the process of photosynthesis. Therefore, it could be said that plants require CO2 for photosynthesis, which produces O2. Both plants and animals require O2 for survival. Hence, the given statement is true.

Joseph Priestly’s experiments explained that plants require CO2, and they are associated with O2. Plants require O2, while animals also require O2. The given statement is true.In 1771, Joseph Priestly conducted a significant experiment, where he placed a mouse and a sprig of mint plant in a closed container. He noticed that the mouse in the closed container struggled and died, whereas the sprig of mint remained healthy. Priestly concluded that plants were able to remove CO2 from the air, which helped in the survival of the mouse. He discovered that plants could produce oxygen during the process of photosynthesis. Therefore, it could be said that plants require CO2 for photosynthesis, which produces O2. Both plants and animals require O2 for survival. Hence, the given statement is true.

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Answer:

D 2.8.6 is the electron configuration

Visible and infrared light do not cause sunburn and they are not known to directly be a skin cancer risk.