might stumble upon this substance one day and be curious about what it does.
Charlie wants to build a magnetic levitation train for his younger brother. Charlie has drawn a diagram of his train and has built the train. What should Charlie do next with his design?
A. Test the device, get feedback from other people, and revise the design if needed.
B. Show his design to other people and get feedback before selling his design.
C. Publish his design in a magazine as is and wait for investors.
D. Test the device and sell it to the local veterinarian.
Answer:
B
Explanation:
I can't explain right now, mabe later.
two point charges of 2.00 μc and -2.00 μc are 0.100 m apart. what is the electric field at the point midway between the two charges?
Two point charges of 2.00 μc and -2.00 μc are 0.100 m apart the electric field at the point midway between the two charges: 7.20 x 10⁵ N/C.
The electric field at the point midway between two point charges can be determined by calculating the electric fields produced by each charge and then summing them up as vectors.
In this case, we have two point charges, +2.00 μC and -2.00 μC, separated by a distance of 0.100 m. Since the charges have the same magnitude but opposite signs, the electric fields they produce at the midpoint will have equal magnitudes but point in opposite directions.
The electric field produced by a point charge is given by the equation: E = k × |q| / r²
where E is the electric field, k is the electrostatic constant, |q| is the magnitude of the charge, and r is the distance between the charge and the point where the field is being calculated.
For the midpoint, the distances from each charge are equal, i.e., r = 0.050 m. Therefore, the electric field produced by each charge is:
E₁ = k × |2.00 μC| / (0.050 m)²
E₂ = k × |-2.00 μC| / (0.050 m)²
Substituting the values and considering the opposite directions of the fields, we have: E = E₁ - E₂
Calculating the magnitudes and taking into account the values of k and the charges, we find:
E = (9.0 x 10⁹ N·m²/C²) × (2.00 μC) / (0.050 m)²
E ≈ 7.20 x 10⁵ N/C
Therefore, the electric field at the point midway between the two charges is approximately 7.20 x 10⁵ N/C.
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A , as recorded by a seismometer,will be a lot of vibration versus timeline
Answer:
Subscribe my Gaming channel Sameer Duos
Explanation:
Generally, a seismograph consists of a mass attached to a fixed base. During an earthquake, the base moves and the mass does not. The motion of the base with respect to the mass is commonly transformed into an electrical voltage. The electrical voltage is recorded on paper, magnetic tape, or another recording medium.
The ______________ is all the surroundings of a living organism.
genetics
environment
temperature
heredity
A light bulb radiates 20 J of energy as light for every 100 J of electrical energy supplied to it. Calculate: (2 marks)
a) The efficiency of the light bulb.
b) The energy wasted by the light bulb for every 100 J of electrical energy supplied to it
The efficiency of the light bulb is 20% (0.20) because it radiates 20 J of light energy for every 100 J of electrical energy supplied to it.
The energy wasted by the light bulb for every 100 J of electrical energy supplied to it is 80 J (100 J - 20 J), as the remaining energy is not converted into light but lost in the form of heat or other inefficiencies.
Efficiency is calculated by dividing the useful output energy by the input energy and multiplying by 100% to get a percentage. In this case, the useful output energy is 20 J, and the input energy is 100 J. So, the efficiency is (20 J / 100 J) * 100% = 20%.
To find the energy wasted, we subtract the useful output energy from the total input energy. In this case, the useful output energy is 20 J, and the total input energy is 100 J. Therefore, the energy wasted is 100 J - 20 J = 80 J. This represents the energy that is not converted into light but instead lost as heat or in other inefficiencies.
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Figure 13 shows a child’s toy . The toy hangs from a hook in the ceiling.
A child pulls the toy downwards and then releases it.
The toy oscillates up and down with the frequency of 1.25.
How many times each second will the toy oscillate up and down?
The number of oscillations of the toy in a second is 1.25.
What is frequency?This is the number of complete oscillation of an object is a given period.The given parameter:
Frequency of the toy, F = 1.25 HzThe frequency of an object is calculated as follows;
\(f = \frac{n}{t} \\\\\)
where;
n is the number of oscillationst is the time of motionThe number of oscillations of the toy in a second is calculated as follows;
\(1.25 = \frac{n}{1} \\\\n = 1.25\)
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lowest to the loudest: a. 63 hz at 30 db, b. 1,000 hz at 30 db, c. 8,000 hz at 30 db
The order of the given frequencies from lowest to loudest at 30 dB is: a. 63 Hz, b. 1,000 Hz, c. 8,000 Hz.
The loudness of a sound is measured in decibels (dB), while the pitch or frequency is measured in hertz (Hz). However, at the same dB level, not all frequencies are perceived as equally loud.
The human ear is more sensitive to frequencies around 1,000 Hz, so a sound at 1,000 Hz needs less intensity to be perceived as loud as sounds at other frequencies.
In this case, all the given frequencies have the same sound intensity level of 30 dB, so the order of loudness depends on their frequency. The frequency of 63 Hz is the lowest and is perceived as less loud than the other two frequencies.
The frequency of 8,000 Hz is the highest and is perceived as the loudest among the given frequencies. Finally, the frequency of 1,000 Hz is in the middle and is perceived as somewhat loud.
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hat is hard glass? Classify the components of glass based on formers, inter
Hard glass is a type of glass characterized by its high resistance to thermal and mechanical stress. It is commonly used in scientific and industrial applications. The components of glass can be classified into formers, intermediates, and modifiers.
Hard glass, also known as borosilicate glass, is a type of glass that possesses high resistance to thermal expansion and mechanical stress. It is composed mainly of silica (SiO2) and boron oxide (B2O3), which act as formers in the glass structure. The formers provide the basic framework of the glass and contribute to its high durability and thermal stability.
In addition to formers, glass can also contain intermediates and modifiers. Intermediates, such as alumina (Al2O3) and magnesia (MgO), help in reducing the melting point of the glass and improve its workability during the manufacturing process. Modifiers, such as sodium oxide (Na2O) and calcium oxide (CaO), alter the properties of the glass, such as its refractive index and chemical resistance.
By combining the right proportions of these components, glassmakers can produce glass with specific characteristics suitable for various applications, ranging from laboratory equipment and optical lenses to household items and industrial containers.
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A snail can move app approximately 0.30 inches per minute. How many meters can the snail cover in 15 minutes
Answer:
4.5 because just do the math and its 4.5
what is the answer?
"Choice-C" is the answer.
What are the magnitudes of the accelerations of the plastic bead and the glass bead?
The magnitudes of the accelerations of the plastic bead and the glass bead are 1.5 m/s² and 0.88 m/s² respectively.
How to calculate electrostatic force?Mathematically, the electrostatic force between two (2) charges can be calculated by using this formula:
\(F = k\frac{q_1q_2}{r^2}\)
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Since the two charges on the plastic bead and glass bead have opposite sign, the coulomb force between them will be attractive in nature. Thus, the electrostatic force would act along the line joining these two charges.
Substituting the given parameters into the formula, we have;
F = 9 × 10⁹ (-5 × 10⁻⁹ × 18 × 10⁻⁹)/(0.016)²
F = 3.164 × 10⁻³ Newton.
Note: The same electrostatic force would act on the two beads.
For the acceleration of plastic bead, we have:
Acceleration = Force/Mass
Acceleration = 3.164 × 10⁻³/2.1 × 10⁻³
Acceleration = 1.5 m/s².
For the acceleration of glass bead, we have:
Acceleration = Force/Mass
Acceleration = 3.164 × 10⁻³/3.6 × 10⁻³
Acceleration = 0.88 m/s².
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Complete Question:
A 2.1 g plastic bead charged to -5.0 nC and a 3.6 g glass bead charged to 18.0 nC is 1.6 cm apart (center to center). What are the magnitudes of the accelerations of the plastic bead and the glass bead?
the index of refraction for a certain material is 1.399 for red light and 1.432 for blue light. light containing both of these colors is traveling in vacuum and strikes a flat sheet of this material. find the angle separating the two colors in the refracted light in the sheet if the angle of incidence is 60.00°.
The angle separating the two colors in the refracted light can be found using Snell's Law.
Snell's Law states that n₁ * sin(θ₁) = n₂ * sin(θ₂), where n₁ and n₂ are the indices of refraction for the initial and final mediums, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
In this case, the index of refraction for red light is 1.399 and for blue light is 1.432. The angle of incidence is given as 60.00°.
To find the angle separating the two colors in the refracted light, we need to calculate the angle of refraction for each color.
For red light: n₁ * sin(θ₁) = n₂ * sin(θ₂)
1 * sin(60.00°) = 1.399 * sin(θ₂)
sin(θ₂) = (1 * sin(60.00°)) / 1.399
For blue light: n₁ * sin(θ₁) = n₂ * sin(θ₂)
1 * sin(60.00°) = 1.432 * sin(θ₂)
sin(θ₂) = (1 * sin(60.00°)) / 1.432
Using a scientific calculator, you can calculate the values of sin(θ₂) for both colors.
Finally, subtract the angle of refraction for red light from the angle of refraction for blue light to find the angle separating the two colors in the refracted light in the sheet.
To find the angle separating the two colors in the refracted light, we use Snell's Law. The index of refraction for red light is 1.399 and for blue light is 1.432. By calculating the angles of refraction for each color, we can subtract them to find the angle separating the two colors.
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A ball of mass 0.25 kg falls from a height of 50 m. Using energy
considerations, find the final velocity. Let g = 9.8 m/s
A . 2.97 m/s
B . 21.0 m/s
C . 33.3 m/s
D . 44.1 m/s
Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.
When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.
Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height
:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m
Eg = 122.625 J
This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy
.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)
Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)
We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s
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How much potential energy does a 75 kg diver have stepping off the edge of a 5 meter platform?
Answer:
3.678kJ
Explanation:
Given
mass= 75kg
height= 5 m
g= 9.81m/s^2
Required
Potential energy
PE= mgh
substitute
PE= 75*9.81*5
PE=3678.75J
PE= 3.678kJ
an optician uses a plane mirror to help him. suppse a patient sits in a chair 2.5m away from him. He views the image of a chart which faces the mirror and is located 30m behindd him. how far is the chart as viewed by his eyes
Answer:
I think 75 m
Explanation:
tell if it was correct
charlotte is driving at 70.3 mi/h and receives a text message. she looks down at her phone and takes her eyes off the road for 4.95 s. how far has charlotte traveled in feet during this time? g
The speed of the Charlotte is 70.3 miles per hour or mi/h. To find out how far she has traveled in feet, we will first convert 70.3 mi/h to feet per second (ft/s) and then multiply it by the time she looked down at her phone (4.95 seconds).
1 mile = 5280 feet
1 hour = 3600 seconds
Therefore, 1 mile per hour = 5280/3600 feet per second (ft/s)70.3 miles per hour
= (70.3 × 5280)/3600 ft/s
= 103.1 ft/s
Now, we can calculate the distance traveled by Charlotte in feet using the formula:
distance = speed × time distance
= 103.1 ft/s × 4.95 s
= 510.345 feet (rounded to three decimal places)
Therefore, Charlotte has traveled 510.345 feet in 4.95 seconds when she looked down at her phone.
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If the tank has a constant pressure of 40 kpa applied
on the surface of the water when the height of water from the
center of the orifice is 7 m, compute the discharge express in
kn/sec.
The discharge from the orifice is approximately 11.71 m/s.
To compute the discharge from an orifice, we can use Torricelli's law, which states that the velocity of efflux (V) is given by the equation:
V = √(2gh)
where g is the acceleration due to gravity (approximately 9.8 m/s²) and
h is the height of the water from the center of the orifice.
Given that h = 7 m, we can calculate the velocity of efflux:
V = √(2 * 9.8 * 7) = √(137.2) ≈ 11.71 m/s
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A race car is one lap behind the lead race car when the lead car has 52 laps to go in a race. If the speed of the lead car is 56.3 m/s, what must be the average speed of the second car to catch the lead car just before the end of the race, assume 1 lap is 1.34km
The speed of the car is 55.2 m/s.
What is the average speed?We can define speed as the ratio of distance to time. We know that the question states the car is one lap behind the lead race car when the lead car has 52 laps to go in a race.
If 1 lap = 1.34km or 1340 m
Distance covered = 1340 m * 52 = 69680 m
Time = 69680 m/ 56.3 m/s
= 1237.7 s
Given that the second car is one lap behind;
51 * 1340 m = 68340 m
Speed = 68340 m/1237.7 s
= 55.2 m/s
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A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) What was the photon's energy (in eV)? _________eV (b) Later, the atom returns to the ground state, emitting one or more photons in the process. Which of the following energies describes photons that might be emitted thus? (Select all that apply.) O 1.89 ev O 12.1 eV O 10.2 ev O 13.6 ev
A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.
To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:
E = -13.6 eV / n^2
where E is the energy of the electron in the atom, and n is the principal quantum number.
(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:
ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)
Calculating the value of ΔE:
ΔE = -13.6 eV / 9 + 13.6 eV
= -1.51 eV
Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).
(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.
ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV
ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV
ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV
ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV
ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV
ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV
ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV
Comparing the calculated energy differences with the given options:
(A) 1.89 eV: This energy difference does not match any of the calculated values.
(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.
(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.
(D) 13.6 eV: This energy difference does not match any of the calculated values.
Therefore option B and C are correct.
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a rigid tank is divided into two equal parts by a partition. one part of the tank contains 2.5 kg of compressed l
Complete question
A rigid tank is divided into two equal parts by a partition. One part of the tank contains 2.5 kg of compressed liquid water at 400 kPa and 60
60 ∘ C while the other part is evacuated. The partition is now removed, and the water expands to fill the entire tank. Determine the entropy change of water during this process, if the final pressure in the tank is 40 kPa.
Water expands to fill the entire tank. For a final pressure of 10 kPa, the final water temperature is 60°c and the tank volume is 2245.4.
The energy balance:
\(E_{in} -E_{out} =\) Δ\(E_{system}\)
So, therefore
0 = ΔU \(mm(u_{2} -u_{1} )\)
\(u_{1} =u_{2}\)
Water's characteristics are listed in tables A = 4 and A-6.
\(p_{1} = 600 kpa\)
\(T_{1}\) = 60°c
⇒ \(v_{1} = v_{f}\)
⇒ 60°c = 0.001017
⇒ \(u_{1} =u_{f}\)
⇒ 60°c = 251.16
Confirmed whether we receive quality between 0 and 1.
\(P_{2}\) = 10kpa
\((u_{2}-u_{1} )\)
We have \(v_{f}\) = 0.001010,
v = 14.670
\(u_{f}\) = 191.79,
\(v_{f}\) = 2245.4
So, therefore, water expands to fill the whole tank. For a final pressure of 10 kPa, the very last water temperature is 60°c and the tank quantity is 2245.4.
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1. A wooden wheel of mass M, consisting of a rim with spokes, rolls down a ramp that makes an angle q with the horizontal, as shown above. The ramp exerts a force of static friction on the wheel so that the wheel rolls without
slipping.
(a)
i. On the diagram below, draw and label the forces (not components) that act on the wheel as it rolls down the ramp, which is indicated by the dashed line. To clearly indicate at which point on the wheel each force is exerted, draw each force as a distinct arrow starting on, and pointing away from, the point at which the force is exerted. The lengths of the arrows need not indicate the relative magnitudes of the
forces.
1. A wooden wheel of mass M, consisting of a rim w
ii. As the wheel rolls down the ramp, which force causes a change in the angular velocity of the wheel
with respect to its center of mass?
Briefly explain your reasoning.
(b) For this ramp angle, the force of friction exerted on the wheel is less than the maximum possible static
friction force. Instead, the magnitude of the force of static friction exerted on the wheel is 40 percent of the
magnitude of the force or force component directed opposite to the force of friction. Derive an expression
for the linear acceleration of the wheel’s center of mass in terms of M, q, and physical constants, as
appropriate.
(c) In a second experiment on the same ramp, a block of ice, also with mass M, is released from rest at the same
instant the wheel is released from rest, and from the same height. The block slides down the ramp with
negligible friction.
i. Which object, if either, reaches the bottom of the ramp with the greatest speed?
_____Wheel ______Block _____Neither; both reach the bottom with the same speed.
Briefly explain your answer, reasoning in terms of forces.
ii. Briefly explain your answer again, now reasoning in terms of energy
The block, because there is no Force of Friction (Ffr) to slow it down.
-Normal Force (Fn) is perpendicular to ramp
- Force of Friction (Ffr) is going up the ramp
- Force of Gravity (Fg=w=mg) is going straight down
Force of Friction (Ffr) because it causes a rotation, therefore making the acceleration different if friction were negligible and it were slipping down the slope.
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which of the following factors determines the strength of the frictional force between two surfaces
Answer:
Explanation:
The strength of the force of friction depends on two factors: how hard the surfaces push together and the types of surfaces involved. What factors affect the gravitational force between two objects? Two factors affect the gravitational attraction between objects: mass and distance.
1. A 3 bladed fan is spinning at 16.7 revs/sec in a very dark room. If a flashing light (called a strobe light) flashes at just the right frequency, the spinning blades look motionless. What is the shortest time, in seconds, between flashes that will make the fan appear to be stopped?
Answer:
P = 1 / f = 1 / 16.7 = .06 sec period of 1 revolution
Period of 1/3 revolution = .06 s / 3 = .02 sec
If the light flashes every .02 sec the fan will appear motionless
You have two rocks made of the same material that are at the same
temperature. The first rock has three times the mass of the second rock. How
does the thermal energy of the two rocks compare?
A. The second rock has three times the thermal energy of the first rock
B. The first rick has six times the thermal energy of the second rock
C. The second rock has one-third as much thermal energy as the first rock
D. The rocks have the same amount of thermal energy
Answer:
the rocks have the same amount of thermal energy
i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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aYe PeEpS iF yOu GiVe Me A wEriD aNsWeR ImA rEeEeeEeEpOrT iT :D
Answer:
Tt tT
tT tt
Explanation:
the rest I pretty sure don't understand
The effectiveness of biofeedback has been a subject of controversy because biofeedback __________.
A.
has no reported side effects
B.
cannot be effectively tested
C.
has no reported negative effects
D.
requires uncomfortable electrodes
please help
Answer:
B
Explanation:
cannot be effectively tested
The effectiveness of biofeedback has been a subject of controversy because biofeedback cannot be effectively tested.
What is biofeedback therapy?
You can learn to control certain of your body's functions, like your heart rate, using a technique called biofeedback.You are connected to electrical sensors during biofeedback, which enables you to learn more about your body.An alternative medical strategy called biofeedback instructs patients on how to influence how their bodies work.Your physical and emotional health may be improved by this mind-body therapy.An expert monitors your body's processes using devices and monitoring equipment during a biofeedback session. With the aid of visual or aural feedback, people can learn to recognize the bodily manifestations of stress and anxiety, such as elevated heart rate, body temperature, and tense muscles.Sensors linked to your body are used in biofeedback therapy to track important bodily processes.You are supposed to learn more about how your body functions with the aid of biofeedback.You might be able to address health issues and gain better control over some bodily systems with the assistance of this knowledge.Biofeedback is generally safe, but it might not be appropriate for everyone. Biofeedback devices might not work properly on people with certain medical conditions, such as heart rhythm problems or certain skin conditionsTo learn more about biofeedback refer
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Para mover un cuerpo, se le ata una cuerda y tres personas tiran de ella, ejerciendo fuerza de 60 Kgf, 70 Kgf y 75 Kgf. ¿Cuál es la resultante del sistema? (resuelve analítica y gráficamente). 6. Sobre una barra de 4,5 m de longitud, se ejercen fuerzas paralelas de igual sentido, si la resultante del sistema es hacia arriba y de 450 N y la fuerza mayor es de 250 N ¿Cuál es la intensidad de la otra fuerza? ¿A qué distancia de la resultante se encuentra cada fuerza?
Answer:
Assuming that the first person pulls with 0° direction, the second person pulls with 90° direction and the third person pulls with 180° direction, the net force would be
\(F=(60-75)i+70j\\F=-15i+70j\)
It's module is
\(|F|=\sqrt{(-15)^{2} +(70)^{2} } =\sqrt{225+4900} \approx 71.6 \ KgF\)
Therefore, the net force is 71.6 Kgf
Now, in the second problem, if the forces are parallel and have the same direction and sense, that means those forces complement each other, that means if the major one is 250 Newtons, then the second one is 200 Newtons, because the net force is 250 N.
Therefore, the missing force is 200 N.
Has anybody seen the movie “Hidden Figures” that can help me with this assignment?
A conducting bar moves along a circuit with a constant velocity. A constant magnetic field is perpendicular to the bar and circuit. The bar covers 1.50 m2 of area in 1.00 second. An EMF of 3.57 V is induced in the circuit. What is the strength of the magnetic field in Tesla?
Answer:
2.38 T
Explanation:
Since the number of coils and the change in time are both 1, I set it up as 3.57=1.50(x) and then solved for x to be 2.38 T.