If it is known that ∠BAD ≅ ∠CAD, BD ≅ CD can be proved.
Given, that In ΔABC
AB = AC
we have to prove that, BD≅CD
Now we have,
AB = AC (Given)
AD = AD (Common)
if it can be known that
∠BAD ≅ ∠CAD
then, by SAS congruence property we can say
that, ΔABD ≅ ΔACD
as, AB = AC (Given)
∠BAD ≅ ∠CAD
AD = AD (Common)
Hence, By CPCT it can be proved that BD ≅ CD.
If it is known that ∠BAD ≅ ∠CAD, BD ≅ CD can be proved.
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6^3 multiplied by (1/2)^3
Step-by-step explanation:
6³×(½)³
=> 216÷8 = 27.
hope this helps you.
100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!
The scale factor and the value of x for each figure is given as follows:
A) Scale factor of 1/3, x = 7 m.
B) Scale factor 0.4747, x = 4.5 in.
How to obtain the scale factor and the value of x?For Figure A, we have that the ratio between the areas is given as follows:
510/4590 = 1/9.
As the area is measured in square units, while the side lengths are measured in units, the scale factor is the square root of 1/9, hence it is given as follows:
1/3.
Then the value of x is obtained as follows:
x = 21 x 1/3
x = 7 m.
For Figure B, we have that the ratio between the areas is given as follows:
16/71 = 0.22535.
The scale factor is then the square root of 0.22535, which is given as follows:
0.4747.
Then the value of x is given as follows:
x = 9.5 x 0.4747
x = 4.5 in.
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Simplify: (Algebra)
a. 2j-3o-5e+l-j+4o+6e
b. -7d+a+2v-i+8d-v+2i+d2
c. 4a+12r-i+a2-11r-3a+n+a3
d. r3-11a+12a-sh+2sh+i+d
e. t5+a-2a+2r-r+l-2l+a4+3n-2n
f. -11i2-r+2r+a3-4d+3d-a
g. -9r+10r+a-s3-2a+2s3+u-l
h. -4d+2a3-a3+5n+iz-4n
i. 16a5-2(l-y+y3)-a+d2-d3+in
j. -5z-e+2e-y5-n+2n-a5-l+l3-i3
k. m-3m-a+2a-m3-2m5-a3-d+l+i4
l. -4t3+5t3+3o-2o+2m-m-r3-is+2is
m. -5j+h-2h+4j-3a+6a-d3
n. r3-3u+2u-st+a3-2a3-5m+4m
o. -6b5-a+4h-3h+18a2+3a-d4+i2-2i2-4r4
p. 13s5-2o+5n3-12s5-6n3+3o+a5
q. -17m+16m-3u+r3+2u-2r3+a4+d4
Answer:
\(2j-3o-5e+l-j+4o+6e= e+j+l+o\)
\(-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v\)
\(4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r\)
\(r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d\)
\(t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n\)
\(-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a\)
\(-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l\)
\(-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz\)
\(16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in\)
\(-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3\)
\(-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4\)
\(-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is\)
\(-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3\)
\(r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m\)
\(-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4\)
\(13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5\)
\(-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4\)
Step-by-step explanation:
\(a.\ 2j-3o-5e+l-j+4o+6e\)
Collect Like Terms
\(-5e+6e+2j-j+l+4o-3o\)
\(e+j+l+o\)
Hence:
\(2j-3o-5e+l-j+4o+6e= e+j+l+o\)
\(b.\ -7d+a+2v-i+8d-v+2i+d^2\)
Collect Like Terms
\(d^2+a+8d-7d-i+2i+2v-v\)
\(d^2+a+d+i+v\)
Hence:
\(-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v\)
\(c.\ 4a+12r-i+a^2-11r-3a+n+a^3\)
Collect Like Terms
\(a^3+a^2+4a-3a-i+n+12r-11r\)
\(a^3+a^2+a-i+n+r\)
Hence:
\(4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r\)
\(d.\ r^3-11a+12a-sh+2sh+i+d\)
Evaluate like terms
\(r^3+a+sh+i+d\)
Hence:
\(r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d\)
\(e.\ t^5+a-2a+2r-r+l-2l+a^4+3n-2n\)
Evaluate like terms
\(t^5-a+r-l+a^4+n\)
Hence:
\(t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n\)
\(f.\ -11i^2-r+2r+a^3-4d+3d-a\)
Evaluate Like Terms
\(-11i^2+r+a^3-d-a\)
Hence:
\(-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a\)
\(g.\ -9r+10r+a-s^3-2a+2s^3+u-l\)
Collect Like Terms
\(-9r+10r+a-2a+2s^3-s^3+u-l\)
\(r-a+s^3+u-l\)
Hence:
\(-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l\)
\(h.\ -4d+2a^3-a^3+5n+iz-4n\)
Collect Like Terms
\(-4d+2a^3-a^3+5n-4n+iz\)
\(-4d+a^3+n+iz\)
Hence:
\(-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz\)
\(i.\ 16a^5-2(l-y+y3)-a+d^2-d^3+in\)
Open bracket
\(16a^5-2l-2y+2y3-a+d^2-d^3+in\)
Hence:
\(16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in\)
\(j.\ -5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3\)
Evaluate like terms
\(-5z+e-y^5+n-a^5-l+l^3-i^3\)
Hence:
\(-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3\)
\(k.\ m-3m-a+2a-m^3-2m^5-a^3-d+l+i^4\)
Evaluate like terms
\(-2m+a-m^3-2m^5-a^3-d+l+i^4\)
Hence:
\(-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4\)
\(l.\ -4t^3+5t^3+3o-2o+2m-m-r^3-is+2is\)
Evaluate like terms
\(t^3+o+m-r^3+is\)
Hence
\(-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is\)
\(m.\ -5j+h-2h+4j-3a+6a-d^3\)
Evaluate like terms
\(-5j-h+4j+3a-d^3\)
Hence:
\(-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3\)
\(n.\ r^3-3u+2u-st+a^3-2a^3-5m+4m\)
Evaluate like terms
\(r^3-u-st-a^3-m\)
Hence:
\(r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m\)
\(o.\ -6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4\)
Collect Like Terms
\(-6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4\)
\(-6b^5+2a+h+18a^2-d^4-i^2-4r^4\)
Hence:
\(-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4\)
\(p.\ 13s^5-2o+5n^3-12s^5-6n^3+3o+a^5\)
Collect Like Terms
\(13s^5-12s^5-2o+3o+5n^3-6n^3+a^5\)
\(s^5+o-n^3+a^5\)
Hence:
\(13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5\)
\(q.\ -17m+16m-3u+r^3+2u-2r^3+a^4+d^4\)
Collect Like Terms
\(-17m+16m+2u-3u+r^3-2r^3+a^4+d^4\)
\(-m+-u-r^3+a^4+d^4\)
Hence:
\(-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4\)
Sigue la secuencia 6,8,12,20
Answer:
28,38
Step-by-step explanation:
Answer:
6,8,12,20,36,68
esta multiplcando el siemprw por 2
comienza con 2 despues aumenta a 4 despues a 8 y sigues asi
Using the table, what is the average daily balance of the credit card for the October 1 - October 31 billing period? Round your answer to the nearest cent. Do not include a dollar sign or comma in your answer. For example, $5,678.00 should be entered as 5678.00. Day 1112131 Activity − Payment Purchase Purchase Adjustment −−2000+1500+1000 Closing Balance 100008000950010500
The balance based on the.data given in the table is shown below.
Balance from day 1 to 10 = 11000
Balance from day 11 to 21= 8000
Balance from day 21 to 30- 5500
Balance on day 31 7500
How to explain the balanceBalance from day 1 to 10= 11000
Balance from day 11 to 21= 8000 Balance from day 21 to 30 5500
Balance on day 31- 7500
The average daily balance of the credit card for the month of december is:
Average daily balance The ratio of total balance from each day in cycle to the total number of days in cycle.
Total balance from each day in cycle=
(11000 x 10)+(8000 × 10)+(5500 x 10) + (7500 x 1) = 104000
Average daily balance=104000 / 31
= 8145
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Why is it important to have high
quality audio files
Answer:
TO HEAR BETTER
Because as quality increases the tone increases
Which compare the end behavior of functions m and n?
M(x) = -8x + 10
N(x) = 5x²-9
Help me pls I will give u 5 stars
The end behavior of function M is a downward slope, while the end behavior of function N is an upward curve.
The end behavior of functions :The end behavior of a function describes the behavior of the function as the input (x) becomes very large in either the positive or negative direction. It is determined by the degree and leading coefficient of the function.
Here we have
M(x) = -8x + 10
N(x) = 5x²- 9
For function M(x) = -8x + 10, as x becomes very large in either the positive or negative direction, the output (y) becomes increasingly negative.
This is because the leading coefficient is negative, and the degree of the function is 1 (linear). Therefore, the end behavior is described as follows:
As x → ∞, M(x) → -∞
As x → -∞, M(x) → +∞
For function N(x) = 5x²-9, as x becomes very large in either the positive or negative direction, the output (y) becomes increasingly positive.
This is because the leading coefficient is positive, and the degree of the function is 2 (quadratic). Therefore, the end behavior is described as follows:
As x → ∞, N(x) → +∞
As x → -∞, N(x) → +∞
Therefore,
The end behavior of function M is a downward slope, while the end behavior of function N is an upward curve.
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An elevator is on the twelfth floor it goes down 11 floors and than up 5 floors what floor is the elevator on now
Answer:
The sixth floor
Step-by-step explanation:
Check whether the sequence is arithmetic. If so, find the common difference d.
1, 10, 19, 28,37
Answer: 9
Step-by-step explanation: 1+9 =10
10+9=19
19+9=28
28+9=37
Solve for x. I attached the question. Pls help me :(
Answer:
x = 16°
Step-by-step explanation:
What we know:
∠JML = 47°
∠JKL = (7x + 21)°
∠JML is an inscribed angle
∠JKL is an inscribed angle
Inscribed angles are half of the value of their intercepted arc
So if m∠JML = 47° then mArc JL is double that or 94°
And ∠JKL is intercepted by Arc JML which is the rest of the circle not intercepted by ∠JML so
mArc JL + Arc JML = 360°
94 + Arc JML = 360
Subtract 94 from both sides to isolate Arc JML
Arc JML = 266°
So if Arc JML = 266° then it's intercepted inscribed angle is half of that.
Arc JML ÷ 2 = ∠JKL
266 ÷ 2 = ∠JKL
133 °= ∠JKL
Now we can use this value and set it equal to the expression to find the value of x
(7x + 21) = 133
Subtract 21 from both sides to isolate the x
7x = 112
Divide both sides by 7
x = 16
Ramirez Company installs a computerized manufacturing machine in its factory at the beginning of the year at a cost of $45,300. The machine's useful life is estimated at 10 years, or 403,000 units of product, with a $5,000 salvage value During its second year, the machine produces 34,300 units of product. Determine the machine's second-year depreciation and year end book value under the straight-line method. Choose Denominator Annual Depreciation Expense Choose Numerator: Depreciation expense ear 2 Depreciation ear end book value (Year 2)
The machine's second-year depreciation is 37240 and year end book value under the straight-line method is 16308.
Straight-line depreciation can be calculated as follows: Cost minus salvage/Estimated useful life (years)= Depreciation expense
=40300/10
=4030
Year 2 depreciation = 4030
Year end book value (Year 2)=37240
Double-declining balance depreciation can be calculated as follows:
Beginning book value x Double the straight-line rate = Depreciation expense; First year's depreciation = 45300x 20%=9060 and Second year's depreciation = 36240x20%=7248
Thus, The annual year depreciation is 9060+7248=16308.
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Complete question:
Ramirez Company installs a computerized manufacturing machine in its factory at the beginning of the year at a cost of $45,300. The machine's useful life is estimated at 10 years, or 403,000 units of product, with a $5,000 salvage value During its second year, the machine produces 34,300 units of product. Determine the machine's second-year depreciation and year end book value under the straight-line method.
what is the name of this angle
Answer: Obtuse Angle
Step-by-step explanation:
Answer:
obtuse is a wide angle, a right angle is a 90 degree angle, and an acute angle is anything smaller than 90 degrees, so this is an obtuse angle! Hope this helped!
Step-by-step explanation:
A binomial experiment consists of 16 trials. The probability of success on trial 9 is 0.48. What is the probability of success on trial 13?
Answer:
p = 0.48
Step-by-step explanation:
A binomial experiment is and experiment with n trials, every trial is identical and independent and every trial has the same probability p of success and 1-p of fail.
Then, we have a binomial experiment of 16 trials. it means that every trial has the same conditions. So, if the probability of success on trial 9 is 0.48, the probability of success on trial 13 is also 0.48.
What is Y+4=-2(x-6) in standard form?
9514 1404 393
Answer:
2x +y = 8
Step-by-step explanation:
The standard form of a linear equation is ...
ax +by = c
where a, b, c are mutually prime and 'a' is positive.
__
Eliminating parentheses, we have ...
y +4 = -2x +12
2x +y +4 = 12 . . . . . . add 2x
2x +y = 8 . . . . . . . . . .subtract 4
A pound of rice has a mixture of two types of rice, each costing $10 and $30, if the average cost per is $24, what is the ratio of the different types of rice?
Answer:
3:7
Step-by-step explanation:
Let x = pounds of the $10 rice in the mixture
Let y = pounds of the $30 rice in the mixture
Total cost of the $10 rice = 10x
Total cost of the $30 rice = 30y
(10x + 30y) / (x + y) = 24
Solve this equation for y/x:
10x + 30y = 24(x + y)
10x + 30y = 24x + 24y
30y - 24y = 24x - 10x
6y = 14x
y/x = 6/14 simplify the fraction
y/x = 3/7
So, the ratio of the two different types of rice (y:x) is 3:7, meaning a pound of the rice mixture has 3 parts of the $30 rice to 7 parts of the $10 rice.
Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is the height of the particle. (a) What is tt when the particle has height 2020? t=t= (b) What is the velocity of the particle when its height is 2020? v⃗ =v→= (c) When the particle has height 2020, it leaves the helix and moves along the tangent line at the constant velocity found in part (b). Find a vector parametric equation for the position of the particle (in terms of the original parameter tt) as it moves along this tangent line.
Answer:
a) t = 4
b) v = pi j + 5 k
c) rt = 1i + (pi t) j + (20 +5t )k
Step-by-step explanation:
You have the following vector equation for the position of a particle:
\(r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}\) (1)
(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.
For a height of 20 you have:
\(5t=20\\\\t=\frac{20}{5}=4\)
(b) The velocity of the particle is the derivative, in time, of the vector position:
\(v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}\) (2)
and for t=4 (height = 20):
\(v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}\)
(c) The vector parametric equation of the tangent line is given by:
\(r_t(t)=r_o+vt\) (3)
ro: position of the particle for t=4
\(r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}\)
Then you replace ro and v in the equation (3):
\(r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}\)
Part(a): The value of \(t=4\)
Part(b): Required vector \(L(t)=(1\widehat{i}+0\widehat{j}+10\widehat{k})+(t-4)(0\widehat{i}+\pi \widehat{j}+5\widehat{k})\)
Given vector equation is,
\(r(t)=cos(\pi t)\widehat{i}+sin(\pi t)\widehat{j}+5t\widehat{j}\)
Vector equation:
A vector is an object that has both a magnitude and a direction. Geometrically, we can picture a vector as a directed line segment, whose length is the magnitude of the vector, and with an arrow indicating the direction.
Part(a):
When the particle has a height of 20
\(5t=20\\t=4\)
Part(b):
The point on the curve is \((cos(4\pi),sin(4\pi),20) =(1,0,20)\)
Differentiating the given equation with respect to \(t\).
\(r'(t)=- \pi sin(\pi t)\widehat{i}+\pi cos(\pi t)\widehat{j}+5\widehat{k}\\r'(t)=- \pi sin(4\pi t)\widehat{i}+\pi cos(4\pi t)\widehat{j}+5\widehat{k}\\r'(4)=0\widehat{i}+\pi \widehat{j}+5\widehat{k}\\L(t)=r(4)+(t-4)r'(4)\\L(t)=(1\widehat{i}+0\widehat{j}+10\widehat{k})+(t-4)(0\widehat{i}+\pi \widehat{j}+5\widehat{k})\)
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A line contains the point (-3,4). If the slope of the line is -2/3, write the equation of the line using slope intercept form
Answer:
y=-2/3x +2
Step-by-step explanation:
4tan(x)-7=0 for 0<=x<360
Answer:
x = 65.26 degrees or x = 245.26 degrees.
Step-by-step explanation:
To solve the equation 4tan(x)-7=0 for 0<=x<360, we can first isolate the tangent term by adding 7 to both sides:
4tan(x) = 7
Then, we can divide both sides by 4 to get:
tan(x) = 7/4
Now, we need to find the values of x that satisfy this equation. We can use the inverse tangent function (also known as arctan or tan^-1) to do this. Taking the inverse tangent of both sides, we get:
x = tan^-1(7/4)
Using a calculator or a table of trigonometric values, we can find the value of arctan(7/4) to be approximately 65.26 degrees (remember to use the appropriate units, either degrees or radians).
However, we need to be careful here, because the tangent function has a period of 180 degrees (or pi radians), which means that it repeats every 180 degrees. Therefore, there are actually two solutions to this equation in the given domain of 0<=x<360: one in the first quadrant (0 to 90 degrees) and one in the third quadrant (180 to 270 degrees).
To find the solution in the first quadrant, we can simply use the value we just calculated:
x = 65.26 degrees (rounded to two decimal places)
To find the solution in the third quadrant, we can add 180 degrees to the first quadrant solution:
x = 65.26 + 180 = 245.26 degrees (rounded to two decimal places)
So the solutions to the equation 4tan(x)-7=0 for 0<=x<360 are:
x = 65.26 degrees or x = 245.26 degrees.
A marketing research company records the consumer habits of a sample of 25 fam of gallons of milk consumed by these families during the last month. Number of families 7 9 Gallons of milk 3. 4 7 For these families, what is the mean number of gallons of milk consumed last month
4.61 gallons is the mean number of gallons of milk consumed last month.
What is the statistical term for the mean?The most typical or average value among a group of numbers is called the mean. It is a statistical measure of a probability distribution's central tendency along the median and mode. It also goes by the name "anticipated value."
What in arithmetic is a mean?The mean (also known as that of the arithmetic mean, which varies with respect to the geometric mean) of a data is calculated as the sum of all values divided by the total number of values. This indicator of the central tendency is usually referred to as the "average".
The total number of gallons of milk consumed is:
\((7 \times 3) + (9 \times 4) + (7 \times 7) \\= 21 + 36 + 49 = 106\)
The total number of families is \(7 + 9 + 7 = 23\)
Therefore, the mean number of gallons of milk consumed last month is:
\(106/23 = 4.61\) gallons
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Which of the following effects of a BAC of .2 percent does NOT relate to one’s driving ability?
A. lack of coordination
B. Breathalyzer test results indicating a high BAC
C. Impaired gross motor skills such as walking or gestures
D. Impaired reactions
It is either between B or C.
The effect that does NOT relate to one's driving ability is breathalyzer test results indicating a high BAC. Option B.
Breathalyzer testWhile the breathalyzer test measures the blood alcohol concentration (BAC), it is a method used to determine the level of alcohol in a person's system and is commonly used in assessing impairment for driving under the influence.
Therefore, it directly relates to one's driving ability and is not excluded from the effects on driving ability caused by a BAC of .2 percent.
On the other hand, options, lack of coordination, impaired gross motor skills, and impaired reactions all directly relate to one's driving ability as they affect the physical and cognitive abilities necessary for safe and efficient driving.
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marcels financial goal is to purchase a house to make Marcels financial goal of purchasing a house a specific goal he can
Marcel can set a goal of purchasing the house in 5 years. The timeframe Factor enables Marcel to work towards his financial goal within a specified period.
Marcel's financial goal is to purchase a house. To make Marcel's financial goal of purchasing a house a specific goal, he can identify the following factors:
Specificity: Marcel should specify the type of house he wants to purchase. This includes the size of the house, the number of rooms, the location, the neighborhood, and the amenities he wants in the house. For instance, Marcel can specify that he wants to purchase a 3-bedroom bungalow house located in a suburban area.
Measurability: Marcel should identify how much money he needs to purchase the house. This means that he should set a financial target that he wants to achieve to be able to purchase the house. For instance, Marcel can set a target of saving $100,000 in 3 years to purchase the house. The measurability factor enables Marcel to track his progress toward achieving his financial goal.
Attainability: Marcel should set a financial goal that is achievable based on his income and financial situation. For instance, if Marcel's current income cannot enable him to save $100,000 in 3 years, he can adjust his financial goal to suit his financial situation.
Realistic: Marcel should set a realistic financial goal that he can achieve given his resources and time frame. For instance, Marcel should not set a financial goal that is too high that he cannot achieve it or too low that it does not challenge him.
Time-bound: Marcel should set a timeframe within which he wants to achieve his financial goal. This means that Marcel should set a specific date by which he wants to purchase the house.
For instance, Marcel can set a goal of purchasing the house in 5 years. The timeframe factor enables Marcel to work towards his financial goal within a specified period.
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Select the correct answer.
29 points!! Kathy distributes jelly beans among her friends. Alia gets 42 fewer jelly beans than Kelly, who gets 33 jelly beans. How many jelly beans does Alia get?
A. 4^2 - 3^3
B. 3^3 + 4^2
C. 4 - 3^3
D. 3^3 - 4^2
E. 3^2 - 4^3
Answer:
Alia has 11 jelly beans.
Step-by-step explanation:
4^2= 163^3= 2727-16=11
I just need explanation or a sentence explaining question 6
Answer and Explanation:
From the question, we're asked to explain how the graph of 7x^2 will be narrower than the graph of 1/7x^2.
To explain this, we have to note that how narrow a parabola will be is determined by how large the coefficient of x^2 is. So the greater the coefficient of x^2, the narrower the graph will be.
We can see that the coefficient of x^2 in 7x^2(which is 7) is greater than the coefficient of x^2 in 1/7x^2( which is 1/7), so the graph of 7x^2 will be narrower than the graph of 1/7x^2.
The survey results of the towns favorite holiday were displayed in a newspaper as described37% of people enjoy Fourth of July•28% of people enjoy New Years Eve42% of people enjoy Memorial DayC5% of people enjoy all three12 % of people enjoy New Years Eve and Memorial Day•18 % of people enjoy Fourth of July and New Years Eve13% of people enjoy Memorial Day onlyWhat percentage of people enjoy New Years Eve only?
In order to calculate the percentage that enjoy New Years Eve only, we can use the diagram and formula below:
Using F to represent Fourth of July, N to represent New Years Eve and M to represent Memorial Day, the formula is:
\(P(N\text{ only})=P(N)-P(F\text{ and }N)-P(M\text{ and }N)+P(all\text{ }three)\)From the given data, we have:
P(N) = 28% = 0.28
P(F and N) = 18% = 0.18
P(M and N) = 12% = 0.12
P(all three) = 5% = 0.05
So P(N only) is:
\(\begin{gathered} P(N\text{ only})=0.28-0.18-0.12+0.05\\ \\ P(N\text{ only})=0.03=3\% \end{gathered}\)What Volume of silver metal will weigh exactly 2500.0g. The density of silver is 10.5g/cm³
The volume of silver metal which will weigh 2500.0g given the density of silver as 10.5 g/cm³ is; 238.095238 cm³.
What volume of silver metal will weigh 2500.0g?It follows from the task content that the volume of silver metal which will weigh 2500.0g is to be determined.
Since the density of a material as the ratio of mass to volume of such material.
Hence;
Density = Mass / Volume
Therefore, in this scenario;
10.5 = 2500 / Volume
Volume= 2500 / 10.5
Volume = 238.095238 cm³
Therefore, the volume of silver metal which will weigh exactly 2500.0g is; 238.095238 cm³.
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A Ferris wheel at a carnival has a radius of 38 feet. Suppose a passenger is traveling at 5 miles per hour. (A usual fact: 1 mi = 5280 ft).A) Find the angular speed of the wheel in radians per minute.B) Find the number of revolutions the wheel makes per hour.
Answer:
a
\(w = 11.58 \ rad/minutes\)
b
\(R_h = 111 \ revolution\ per \ hour\)
Step-by-step explanation:
From the question we told that
The radius of the wheel is \(r = 38 \ ft\)
The speed of the passenger is \(v = 5 \ miles /hr = \frac{26400}{3600} = 7.33 \ ft / s\)
Generally the angular speed is mathematically represented as
\(w = \frac{v}{r}\)
=> \(w = \frac{7.3}{ 38}\)
=> \(w = 0.193 \ rad/s\)
now converting the seconds to minutes
\(w = 0.193 *60\)
\(w = 11.58 \ rad/minutes\)
Generally number of revolutions the wheel makes per minutes is mathematically represented as
\(R = \frac{11.58 }{2 \pi}\)
\(R = 1.84 \ rpm\)
Generally number of revolutions the wheel makes per hour is mathematically represented as
\(R_h = R * 60\)
=> \(R_h = 1.84 * 60\)
=> \(R_h = 111 \ revolution\ per \ hour\)
Calculate slope using the slope formula
Answer:
m= -125/176
Step-by-step explanation:
First CORRECT answer get branliest Please help!
Answer:
36^6 or 2176782336
Step-by-step explanation: if you multiply 10^2 would equal because you would multiply 10 by 10 and 4^3 would equal 64 because you would have to multiply four 3 times (4 x 4 x 4) and you subtract 100 and 64 (100 - 64) and you get 36 BUT, the question says "Give your answer as APO 6, so you put your answer as 36^6 or 2,176,782,336
Find the equation of the line tangent to the graph of f(x)=(lnx)^(4)at x=10
Hello,
Step-by-step explanation:
\(f(x) = ln(x) {}^{4} \)
\((ln(u)') = \frac{u'}{u} \)
\(f'(x) = \frac{4ln {}^{} (x) {}^{3} }{x} \)
\(f'(10) = \frac{4ln {}^{} (10) {}^{3} }{10} = \frac{12ln(x)}{x} \)
\(f(10) = ln(10) {}^{4} \)
\(y = \frac{12ln(x)}{x} (x - 10) + 4ln(10)\)
\(y = f'(a)(x - a) + f(a)\)
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